The true statement concerning racemic mixtures is that racemic mixtures are optically inactive (statement c). Racemic mixtures contain equal amounts of both enantiomers, resulting in no net rotation of plane-polarized light. The other statements (a, b, and d) are either false or have exceptions.
Racemic mixtures are mixtures that contain equal amounts of both enantiomers, which are mirror images of each other. Let's evaluate each statement to determine which ones are true.
a. Melting points between both enantiomers will vary:
This statement is false. Enantiomers have the same chemical composition, and their melting points are usually very similar or even identical. The only difference between enantiomers is their spatial arrangement.
b. Two enantiomers rotate plane-polarized light to an equal extent in the same directions, so the rotation doubles:
This statement is false. Enantiomers rotate plane-polarized light in equal amounts but in opposite directions. When a racemic mixture is formed, the rotations of the two enantiomers cancel each other out, resulting in no net rotation. As a result, racemic mixtures are optically inactive.
c. Racemic mixtures are optically inactive:
This statement is true. Racemic mixtures do not rotate plane-polarized light because the rotations of the two enantiomers cancel each other out. This is why racemic mixtures are considered optically inactive.
d. The boiling points between the enantiomers are identical:
This statement is generally true. Enantiomers have the same boiling points since their chemical compositions are the same. However, there can be some minor differences in boiling points due to factors like impurities or interactions with the surrounding environment.
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The correct number of atoms of each element present in the formula Cu3(PO4) 2 is:
1) Write the formula
\(Cu_3(PO_4)_2\)2) The subscripts show us the number of each atom in the formula. In this case, we also have to make sure to count the parenthesis subscript.
There are
3 Cu
2 P
8 O
Why water beads on a freshly washed or freshly waxed car. What characteristics of water and the car's finish or wax cause this
Water beads on a freshly washed or waxed car due to the interplay between the properties of water and the car's finish or wax. The two main characteristics of water and the car's finish or wax cause this incident are
Surface Tension and Hydrophobicity.
There are two main factors at play:
Surface Tension: Water molecules are cohesive and exhibit a property known as surface tension. Surface tension is the force that allows water molecules to stick together and form droplets. When water is applied to a smooth surface, such as a freshly washed or waxed car, the cohesive forces of water molecules cause them to minimize their contact with the surface and form droplets.
Hydrophobicity: The car's finish or wax can have hydrophobic properties. Hydrophobic substances repel or resist water. When the car's surface is treated with wax or a hydrophobic coating, it creates a barrier between the water droplets and the surface. The hydrophobic nature of the wax or coating causes water to bead up and roll off the surface instead of spreading out and wetting it.
In summary, the combination of water's surface tension and the hydrophobic properties of the car's finish or wax lead to water beading up on the surface, rather than spreading out. This effect enhances the aesthetic appearance of the car and also helps to prevent water spots and potential damage from contaminants dissolved in the water.
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why are so many products made from plastic ?
Explanation:
Plastic takes time to degrade which means it has great longevity. Plastic does not break as easily as glass or other materials. It lasts long and offers great service. Plastic storage containers offer greater flexibility than any other packaging materials.
(Please Help)
1.What is the most common isotope for element X
2.Calculate the average atomic mass or element X
Answer:
1. Isotope 2 occurs most commonly
2. 39.02amu
Explanation:
1. Isotope 2 has a relative abundance of 78.68% i.e. 78.68 out of 100, hence, it is the isotope that occurs most commonly.
2. Isotope 1 = 9.67%, mass no: 38
Isotope 2 = 78.68%, mass no: 39
Isotope 3 = 11.34%, mass no: 40
Isotope 4 = 0.31%, mass no: 41
To find the average atomic mass of element X, we multiply each isotopes' relative abundance by its mass no and find the sum as follows:
We convert each percentage to decimal abundance:
Isotope 1 = 9.67% = 0.0967
Isotope 2 = 78.68% = 0.7868
Isotope 3 = 11.34% = 0.1134
Isotope 4 = 0.31% = 0.0031
(0.0967 × 38) + (0.7868 × 39) + (0.1134 × 40) + (0.0031 × 41)
3.6746 + 30.6852 + 4.536 + 0.1271
Average atomic mass = 39.02amu
What two factors influence the effectiveness of molecular collisions in producing chemical change? 1) The concentration of the reactants. 2) The activation energy. 3) The pressure. 4) The orientation of the reactants.
The following two factors affect the efficacy of molecular collisions in producing chemical change: The activation energy and The orientation of the reactants.
The correct answers are option 2 and 4.
The activation energy is the bare minimum of energy necessary for a reaction to take place. The higher the activation energy, the less probable the reactants will have enough energy to break through this energy barrier and react.
The orientation of the reactants: In order for a reaction to occur, the reacting molecules must collide in the proper orientation. If the molecules collide in the incorrect direction, the reaction may not occur or will occur in a less effective manner.
While reactant concentration and pressure can impact reaction pace, they have no direct effect on the efficacy of molecular collisions in creating chemical change.
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If the DISTANCE traveled for the PURPLE line is 3.5m and it traveled for 1.75 seconds, what was it's speed?
5.25 m/s
2m/s
6.125 m/s
0.5 m/s
Help!
Answer:0.5 m/s
Explanation: Divide D: distance To L: line 3.5 divided by 1.75 gives you 0.5 m/s
distance/time
Name organs and is the tissues found in them.
Answer:
epithelial tissue, connective tissue, muscle tissue, and nervous tissue.
I think its right
brainiest pls
Explanation:
Which TWO of the following changes can be classified as physical
A. Ice melting on a warm day
B. Fireworks going off on July 4th
C. Baking soda reacting with vinegar
D. Glass shattering as it hits the floor
The two changes that can be classified as physical are as follows:
Ice melting on a warm day (option A)Glass shattering as it hits the floor (option D).What is a physical change?A physical change in chemistry is a change affecting the form of a chemical substance, but not its chemical composition.
When matter changes its observable properties, we can say it has undergone a physical change.
Physical change is a type of change where the physical properties of matter change. Physical changes include;
State of matterchange in colourchange in odoursolubilityTherefore, melting of ice, which is a change of state and shattering of glass are examples of physical change.
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What eats a FawnsFoot Mussel?
Answer:
I have no Idea please give more context to your question.
Explanation:
which of the following is not a colligative property? group of answer choices freezing point depression increasing solubility vapor pressure lowering boiling point elevation
Freezing point. The known colligative properties of a solution are freezing point depression, osmotic pressure, vapor pressure lowering, and boiling point elevation.
What do you mean by freezing explain?Freezing refers to the phase change of a substance from the liquid state to a solid-state. This is a phase change phenomenon which means that a substance is transformed from one state of matter to another state.
What is freezing give an example?The change in the liquid to the solid phase at a constant temperature is called freezing. The temperature at which liquid changes to solid is called the freezing point. Example: water-filled in an ice cube tray, when kept in the freezer, changes into solid, so here the water freezes to form ice cubes.
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Zn+2KOH+2H2O = Zn(OH)4 2+K+2H2 is an example of what type of reaction?
A. neutralization
B. dissociation
C. oxidation of metals by acid other than water
D. reaction of a base with a metal
The given reaction,\(Zn + 2KOH + 2H_2O - > Zn(OH)_4^2- + K^+ + 2H_2\), is an example of a reaction between a metal and a base, known as a reaction of a base with a metal.
The reaction involves the metal zinc (Zn) reacting with potassium hydroxide (KOH), which is a strong base, in the presence of water. The reactants combine to form zinc hydroxide \((Zn(OH)_2)\) as an intermediate product, which then further reacts with water to form zinc tetrahydroxide \((Zn(OH)4^2-)\). Simultaneously, potassium ions (K+) and hydrogen gas (H2) are also produced.
This reaction is categorized as a reaction of a base with a metal because a metal (Zn) reacts with a base (KOH) to form a salt (K+) and hydrogen gas (H2). The presence of water in the reaction allows for the formation of hydroxide ions (OH-) and the subsequent formation of zinc hydroxide and zinc tetrahydroxide. The overall reaction can be represented as follows:
\(Zn + 2KOH + 2H_2O\) → \(Zn(OH)_4^2- + K+ + 2H_2\)
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In the project schedule, the duration of the project isGroup of answer choicesa. equal to or less than the total of the durations for all the individual activities.b. more than the total of the durations for all the individual activities.c. always equal to the total of the durations for all the individual activities.d. always less than the total of the durations for all the individual activities
The correct answer is (b) more than the total of the durations for all the individual activities.
In project management, the duration of the project refers to the total time it takes to complete the entire project, from start to finish. This duration is typically longer than the sum of the durations for all the individual activities within the project. There are various factors that contribute to the project duration being longer than the sum of individual activity durations. These factors include dependencies between activities, resource constraints, and other project-specific considerations. Activities may need to be sequenced in a specific order.
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Seawater is a solution, and the concentration of dissolved solids in it is referred to as its __________. The term __________ is applied to water that exceeds the average of 35 percent, whereas __________ is the term used to describe water that is less than 35 percent.
The concentration of dissolved solids in seawater is referred to as its salinity. The term hypersaline is applied to water that exceeds the average of 35%, whereas hyposaline is the term used to describe water that is less than 35%.
Salinity is the measure of the amount of dissolved solids in seawater, usually expressed in parts per thousand (ppt) or as a percentage (%). The average salinity of seawater is approximately 35 ppt or 3.5%, which means that 35 grams of dissolved solids are present in 1 liter of seawater. However, salinity can vary in different regions of the ocean due to factors such as temperature, evaporation, and precipitation.
If the salinity of seawater is greater than 35 ppt, it is referred to as hypersaline. Hypersaline water can occur in areas such as salt pans, lagoons, and isolated seas where evaporation exceeds precipitation and the inflow of freshwater.
Conversely, if the salinity of seawater is less than 35 ppt, it is referred to as hyposaline. Hyposaline water can occur in areas such as estuaries, where freshwater from rivers and streams mixes with seawater.
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Changes in the total amount of thermal energy provide evidence that chemical reactions have taken place. A chemical reaction in which energy has been absorbed is known as a(n):
Select one:
physical reaction.
endothermic reaction.
reversible reaction.
exothermic reaction.
Answer:
B. endothermic reaction
Explanation:
Given the balanced equation:
2 Al + 6 NaOH --------> 2 Na3AlO3 + 3 H2
What mass, in grams, of Na3AlO3 is produced when 6 x 10^23 molecules of NaOH is consumed?
explain
a) 240 b) 80 c) 64 d) 9.6 e) 48
47.78 grams of Na₃ AlO₃ is produced when 6 × 10²³ molecules of NaOH are consumed.
An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and the total charge for each component of the reaction.
The balanced equation:
2 Al + 6 NaOH --------> 2 Na₃ AlO₃ + 3 H₂
We have 6 × 10²³ molecules of NaOH.
So, the mass of Na₃ AlO₃ will be:
= 6 × 10²³ molecules NaOH × ( 1 mol NaOH / 6.023 × 10²³ molecules NaOH ) × ( 2 mol Na₃ AlO₃ / 6 mol NaOH) × ( 143.9 g Na₃AlO₃ / 1 mol Na₃ AlO₃ )
= 47.78 g Na₃ AlO₃
The mass of Na₃ AlO₃ produced when 6 × 10²³ molecules of NaOH are consumed is 47.78 grams.
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What is force? Why?
At about what temperature does the sample change phase? Justify your
answer based on the cooling curve shown above.
A student states, “When the alcohol sample was at a temperature of 500 K, all the particles were moving faster than any of the particles were moving at
400 K" Do you agree or disagree with this student's statement? Justify your
answer.
porque a las vacunas los cientificos las llaman reactivos.
Answer:
Because scientists call vaccines reagents.
Describe the particles of a solid, liquid, and gas. For each, be sure to tell how far apart they are and how fast or slowly they move.
Answer:
Solid
A solid is a state of matter where the particles are tightly packed together, they are very close togetherThey vibrate, they move very slowlyLiquid
A liquid has free-flowing particles, but they may not leave the containerThey move at medium speedGas
A gas moves very freely, they leave the container, and they may not be captured in its entiretyIt moves very fast because it is heatedHope this helps :)
- jp524
calculate the amount of heat released from combustion of 2 g of wood. the heat capacity of the bomb calorimeter is 9.96 kj/°c .
If the heat capacity of the bomb calorimeter is 9.96 kj/°c, then the amount of heat released from combustion of 2 g of wood is 39.84 kJ.
To determine the amount of heat released from combustion of 2 g of wood, you need to use the formula
Q = C × ΔT Where:Q is the heat released or absorbed in joules (J)C is the heat capacity of the bomb calorimeter (given as 9.96 kJ/°C)ΔT is the change in temperature in degrees Celsius (°C)We can assume that all the heat released from the combustion of the wood is absorbed by the calorimeter, so we can use the heat capacity of the calorimeter to calculate the heat released. Since the calorimeter absorbs the heat, the value of Q will be negative (i.e. the heat is released).
Given: Mass of wood = 2 g Heat capacity of the bomb calorimeter = 9.96 kJ/°C First, we need to calculate the change in temperature. This can be done by measuring the temperature of the calorimeter before and after combustion. Let's assume that the temperature increases by 4.0 °C.ΔT = 4.0 °C Now, we can calculate the heat released: Q = C × ΔTQ = (9.96 kJ/°C) × (4.0 °C)Q = 39.84 kJ
Therefore, the amount of heat released from combustion of 2 g of wood is 39.84 kJ.
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Classify the statements based on whether they describe a weak or strong mobile phase in affinity chromatography. a. referred to as the elution buffer b. referred to as the application buffer c. mimics the pH, ionic strength, and polarity of the affinity ligand's natural environment d. readily removes the analyte from the affinity ligand e. a competing agent is used to displace the analyte from the affinity ligand f. The pH, ionic strength, or polarity is changed to decrease the association equilibrium constant between the analyte and affinity ligand g. promotes strong binding between the analyte and affinity ligand
Statements about weak and strong mobile phase in affinity chromatography include,
Weak mobile phase:
(d) Enables efficient dissociation of the analyte from the affinity ligand.
(e) Utilizes a competing agent to displace the analyte from the affinity ligand.
(f) Involves modifying the pH, ionic strength, or polarity to reduce the association equilibrium constant between the analyte and affinity ligand.
Strong mobile phase:
(a) Referred to as the elution buffer, it facilitates the release of the analyte from the affinity ligand.
(b) Known as the application buffer, it promotes the initial binding of the analyte to the affinity ligand.
(c) Mimics the pH, ionic strength, and polarity of the affinity ligand's natural environment, enhancing favorable interactions.
(g) Fosters robust binding between the analyte and affinity ligand, ensuring strong affinity interactions.
In affinity chromatography, the choice between a weak or strong mobile phase depends on the desired outcome.
A weak mobile phase is employed to remove the analyte from the affinity ligand or decrease binding strength, achieved through efficient dissociation, displacement, or modification of relevant factors.
Conversely, a strong mobile phase is used to facilitate binding interactions, encompassing initial application, mimicking the natural environment, and promoting robust binding between the analyte and affinity ligand.
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Why should we not were
synthetic clothes while working
in kitchen ?
Answer:
Synthetic clothes can easily build up static electricity. It also easily can catch up on fire and when it does, it melts and can fuse to your skin.
Explanation:
Answer:
Explanation:
Synthetic fibres like Polyester catches fire very easily and melts. After melting It sticks to the body of the person wearing it causing severe burns. Hence it is advised not wear synthetic clothes while working in the Kitchen. Its advised to wear Apron or cotton clothes while cooking in Kitchen.
When moving across a row in the Periodic Table, which of the following increases?
what is action force?
Answer:
is force acting in one direction
Answer:
hope this helps!
as described by the third of Newton's law of motion of classical mechanics, offices occurs in pairs such that is one object exerts a force on another object, then the second object exerts an equal and opposite reaction Force on the first.
what is the expected major product from the reaction of 2-bromo-2-methylbutane with sodium methoxide in methanol?
The expected major product from the reaction of 2-bromo-2-methylbutane with sodium methoxide in methanol will be (C) 2-Methylbut-2-ene
In the first step, dissociation occurs by which 2-bromo-2-methylbutane removes bromide, and a carbocation results in 2-bromo-2-methylbutane.
C₅H₁₁Br → C₄C⁺H₁₁ + Br⁻
This carbocation then reacts with sodium methoxide. By this reaction two products, 2-methyl-but-2-ene and 2-methyl-but-1-ene will produce. Among these 2-methyl-but-2-ene will be the major product. In this reaction, methanol is used as a solvent.
C₄C⁺H₁₁ + C₂H₅O⁻Na⁺ → CH₃-CCH₃=CH-CH₃ + CH₂=CCH₃-CH₂-CH₃
So, by the given reaction (C) 2-Methylbut-2-ene will produce a major product.
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Determine the phase of the substances at the given state using Thermodynamic Properties Tables (in Appendix B) a) water: 60∘C,60kPa b) water: 100∘C,60kPa− c) water: 100∘C,500kPa d) Water: 25∘C,120kPa
e) Ammonia: −25∘C,120kPa f) Ammonia: 25∘C,120kPa g) R-134a: −25∘C,120kPa h) R−134a:25∘C,120kPa
a) vapor, b) saturated liquid, c) saturated liquid, d) compressed liquid, e) compressed liquid, f) compressed liquid, g) compressed liquid, h) compressed liquid.
The phase of substances in different states using Thermodynamic Properties Tables (in Appendix B) is given below:
a) The phase of water at 60∘C and 60kPa is vapor.
b) The phase of water at 100∘C and 60kPa is saturated liquid.
c) The phase of water at 100∘C and 500kPa is saturated liquid.
d) The phase of water at 25∘C and 120kPa is compressed liquid.
e) The phase of ammonia at -25∘C and 120kPa is compressed liquid.
f) The phase of ammonia at 25∘C and 120kPa is compressed liquid.
g) The phase of R-134a at -25∘C and 120kPa is compressed liquid.
h) The phase of R-134a at 25∘C and 120kPa is compressed liquid.
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Describe the sludge generation process and propose safe methods
of disposing it.
The sludge generation process refers to the production of sewage treatment residue during wastewater treatment. Sludge contains solid and semi-solid materials that must be handled and disposed of properly to protect human health and the environment.
The following are some methods for sewage disposal:
Wastewater Treatment: Initial treatment involves the physical removal of large solids, whereas secondary treatment uses biological processes to break down organic matter and remove dissolved pollutants.
Sludge Treatment: The separated sludge is under further treatment, which may include stabilization, dewatering, and, in some cases, additional processes to reduce contaminants.
Land Application: Treated sludge can be applied to agricultural land as a fertilizer or soil conditioner if it meets regulatory guidelines and has been properly treated.
Landfills: If sludge cannot be reused or recycled, it can be disposed of in a designated landfill that meets regulatory requirements, ensuring proper containment and preventing soil and water contamination.
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Time Limit: 0:25:00
Kelly Espinoza Gonzalez: Attempt 1
Question 5 (1 point)
Time Left: Time Exceeded
How many moles of iron (Fe) are in 279 g of iron?
O 0.2 mol Fe
15, 568 mol Fe
O 1 mol Fe
O 5 mol Fe
Iron has a molar mass of 55.84 grams/mole. So, five grams divided by 55.84 grams/mole gives us 0.089 moles of iron
How do you calculate moles?The unit is denoted by mol.The formula for the number of moles formula is expressed as.Number of moles formula is.Number of moles = Mass of substance / Mass of one mole.Number of moles = 95 / 86.94.1 mole is a number equal to. 022 x 10 23 particles, also known as the Avogadro's constant. To calculate the number of moles of any substance in the sample, we simply divide the given weight of the substance by its molar mass.One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions).To learn more about moles refers to:
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explain why is energy input required to add an electron to zinc
Answer: When you add an electron to zinc, it needs some extra energy. This is because zinc atoms naturally don't like having an extra electron. The extra electron and the electrons already present in zinc repel each other due to their negative charges. So, you have to give some energy to the zinc atom to overcome this repulsion and make it accept the additional electron. Basically, energy input is required to make zinc accept an extra electron because the electron doesn't fit easily and needs some force to be added.
Explanation: hope this helps
a sample of contains 2.02 g of hydrogen, 32.07 g of sulfur, and 64.00 g of oxygen. how many grams of sulfur and grams of oxygen are present in a second sample of containing 6.71 g of hydrogen?
In the second sample containing 6.71 g of hydrogen, there are 44.85 g of sulfur and 89.71 g of oxygen present.
In a sample containing 2.02 g of hydrogen, 32.07 g of sulfur, and 64.00 g of oxygen, there are 32.07 g of sulfur and 64.00 g of oxygen present.
If we have a second sample containing 6.71 g of hydrogen, we can calculate the amount of sulfur and oxygen present using the following equations:
Sulfur: 32.07 g / 2.02 g x 6.71 g = 44.85 g
Oxygen: 64.00 g / 2.02 g x 6.71 g = 89.71 g
Therefore, in the second sample containing 6.71 g of hydrogen, there are 44.85 g of sulfur and 89.71 g of oxygen present.
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