Select the best answer for the question.
3. Aside from representing the circuit components and the way they're connected to each other, the electrical symbols used in schematic diagrams also represent the
OA. physical location of the circuit.
OB. functions of the circuit.
O C. size of the circuit.
OD. actual shapes of the circuit components.

Answers

Answer 1

The electrical symbols used in schematic diagrams also represent the physical location of the circuit.

What is schematic diagram in electrical?

A schematic diagram is a basic, two-dimensional representation of an electrical system that shows the connectivity and operation of various electrical components.

A simplified drawing that uses symbols and lines to represent key information is called a schematic diagram. For instance, if you're taking the subway, you might see a "map" that shows all the stations along the route, but it won't show all the streets and structures you might pass.

Symbol used :

The most typical symbols used in circuit diagramming are electrical symbols. In your circuit, amplifiers (represented by triangle shapes) boost the output signal. Your system's capacitors (parallel lines) store energy, whereas resistors (zigzag lines) lower current flow.

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Related Questions

Which option identifies the major method scientists use to share their research findings with other scientists?
a) conference presentations
b) peer-reviewed journals
c) newspaper articles
d) Internet videos ​

Answers

The major method scientists use to share their research findings with other scientists is (b) peer-reviewed journals.

What is peer-reviewed journals?

The primary means through which scientists disseminate the results of their study to other scientists is through peer-reviewed publications. Research articles are submitted by scientists in this method to respectable scientific publications.

The papers are next subjected to a thorough examination by a group of subject-matter specialists known as peers or referees. Prior to being approved for publication, these experts evaluate the research's quality, validity, and importance.

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a device is defined as a unit of an electrical system, other than a conductor, that carries or ? electric energy as its principal function.

Answers

A device is defined as a unit of an electrical system, other than a conductor, that carries or transfers electric energy as its principal function.

 In electrical engineering, a device refers to a component or unit within an electrical system that performs a specific function.

Devices can be classified based on their function, behavior, or physical characteristics. This definition can be applied to a variety of devices commonly used in electrical systems such as transformers, generators, motors, switches, and more. These devices are designed to convert and transfer electrical energy in various ways to power different systems and devices.

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A 30.0 kg rock falls from a 35.0 m cliff. What is the kinetic and potential energy when the rock has fallen 12.0 m?

Answers

Answer:

When the rock has fallen 12.0 m;

The kinetic energy of the rock is approximately 3,531.6 J

The potential energy of the rock is approximately 6,768.9 J

Explanation:

The question relates to the characteristic constant total mechanical energy of a body

The mass of the rock that falls, m = 30.0 kg

The height of the cliff from which the rock falls, h₁ = 35.0 m

The required information = The kinetic and potential energy when the rock has falling 12.0 m

The kinetic energy is given by the formula, K.E. = 1/2×m×v²

The potential energy is given by the formula, P.E. = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

The velocity of the rock after falling through a given height, h is given by the formula, v² = 2·g·Δh

The total mechanical energy of the rock, M.E. = K.E. + P.E. = Constant

At the height of the cliff before falling, Δh =0, therefore v₁ = 0, therefore, K.E. = 1/2×m×v₁² = 0 J

The potential energy at the cliff before the rock begins to fall, P.E. is goven as follows;

P.E. = 30.0 kg × 35.0 m × 9.81 m/s² = 10,300.5 J

At the top of the cliff, M.E. = K.E. + P.E. = 0 J+ 10,300.5 J = 10,300.5 J

∴ M.E. = 10,300.5 J

When the rock has fallen, 12.0 m, Δh = 12.0 m, the speed of the rock, v₂, is given as follows;

v₂² = 2 × 9.81 m/s² × 12.0 m = 235.44 m²/s²

v₂ = √(235.44 m²/s²) ≈ 15.344 m/s

∴ When the rock has fallen 12.0 m, K.E., is given as follows;

K.E. = 1/2×m×v₂²

K.E. = 1/2 × 30.0 kg × 235.44 m²/s² = 3,531.6 J

When the rock has fallen 12.0 m the kinetic energy, K.E. = 3,531.6 J

When the rock has fallen 12.0 m, M.E. = P.E. + K.E.

M.E. = Constant = 10,300.5 J

K.E. = 3,531.6 J

∴ 10,300.5 J = P.E. + 3,531.6 J

P.E. = 10,300.5 J - 3,531.6 J = 6,768.9 J

∴ When the rock has fallen 12.0 m, the potential energy, P.E. = 6,768.9 J.

Complete the following hypothesis the pressure lncrease as

Answers

Temperature is increased the pressure also increases due to fast movement of molecules because of more energy.

How temperature is related to pressure?

The temperature of the gas is directly proportional to the pressure. Faster moving particles will collide with the walls of the container that put force on the wall which leads to increase in pressure.

So we can conclude that temperature is increased the pressure also increases due to fast movement of molecules because of more energy.

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Tyrell is holding a cup of hot cholate in his hands which cause his hand to feel
warmer. What is happening to the particles in his hands?

Answers

Answer:

When Tyrell's hands get warm the particles in his hands are moving faster or more rapidly.

Explanation:

you toss a ball in the air. what is the work done by gravity as the ball goes up?

Answers

Answer: Gravity slows the ball down as it goes up and eventually stops it from going up and starts to pull it back down to earth.

Explanation:

What is the removal of anxiety-provoking ideas from awareness called?
a. Catalysis.
b. Reaction formation.
c. Repression.
d. Regression.

Answers

The removal of anxiety-provoking ideas from awareness is called "c. repression".

It is a defense mechanism in which individuals unconsciously push unwanted thoughts or feelings out of their consciousness and into their subconscious mind.

This process is done to protect oneself from experiencing uncomfortable or painful emotions.

Repression is often used as a coping mechanism, especially in situations where individuals feel overwhelmed by emotions that they cannot handle.

It is important to note that repression is not a healthy long-term solution, as it can lead to psychological issues in the future.

Therapy can be beneficial in helping individuals confront and process their repressed emotions and ideas in a safe and healthy environment.

In conclusion, the answer to the question is c. Repression.

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Answer all questions
1. You’re in a race and you pass the person in second place. What place are you in now?
2. A girl fell off a 20-foot ladder. She wasn’t hurt. How?
3. Mississippi has four S’s and four I’s. Can you spell that without using S or I?
4. I called my dog from the opposite side of the river. The dog crossed the river without getting wet, and without using a bridge, a boat, or a raft. How is that possible?
5. A girl throws a ball as hard as she can. It comes back to her, even though nothing and nobody touches it. How?
6. When is “L” greater than “XL”?
7. How can you physically stand behind your father while he is standing behind you?

Answers

Answer:

nope the dog jumped over the river

Explanation:

If an object is acted upon by a net force, the change in velocity will be?

Answers

Answer:

posetive

Explanation:

an object with a force exerted on it will move forwards

if one cell is 3v what are the others​

if one cell is 3v what are the others

Answers

Answer:

The chemistries and technologies behind coin cells vary. Some are alkaline, others are lithium. Alkaline coin cell batteries have a nominal voltage of 1.5V. Lithium coin cell batteries, on the other hand, have a nominal voltage of 3V.

For a particular nonlinear spring, the relationship between the magnitude of the applied force f and the resultant displacement x from equilibrium is given by the equation f = kx2. What is the amount of work done by stretching the spring a distance x0?.

Answers

By extending the spring to the specified distance, work is \(W = \frac{Kx0}{3}\).

What exactly does science work on?

The output of a force is equal to the product of the component acting in the displacement's direction and the displacement's magnitude.

The details provided are:

F is the applied force to the spring.

Spring extension is equal to x0.

Following is a calculation of the work involved in stretching the spring to the specified distance;

\(w=\int\limits^x {F} \, dx\)

\(\int\limits^i_i {Kx^2} \, dx\)

\(w= k\int\limits^i_i {x^2} \, dx\)

\(w=K\frac{x^3}{3}\)

\(w= \frac{Kx0}{3}\)

Stretching the spring to the specified distance does the following work:  w= \frac{Kx0}{3} .

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Can ya pls answer dis rq!

Can ya pls answer dis rq!

Answers

Answer:

Below

Explanation:

Recommended protein sources

1. Lean meat such as chicken or fish

Advantages : they are high quality sources of protein, and contain all 8 essential amino acids, which is why they are considered a complete protein

2. Animal products like eggs and greek yogurt

Advantages : these foods also contain all 8 essential amino acids, making them a complete protein

3. Pulses like beans and lentils

Advantages : tends to be lower in calories and fat than animal-based protein sources, as well as being higher in fiber and essential nutrients

Hope this helps!

The best leaper in the animal kingdom is the puma, which can jump to a height of 12. 0 feet when leaving the ground at an angle of 45°. With what speed must the animal leave the ground to reach that height?.

Answers

To reach a height of 12.0 feet with an angle of 45° the animal must leave the ground with a velocity of: 39.295 ft/s

The formulas for projectile motion that we will use to solve this exercise is:

h max = [vi² * (sinθ)²] / (2*g)

Where:

h max = maximum heightg = gravityvi = initial velocity

Information about the problem:

vi = ?θ= 45ºg = 32.17 ft/s²h max = 12.00 ft

Applying the maximum height formula an clearing the initial velocity we have:

h max = (vi² * (senθ)²) / (2*g)

vi= √ [(h max * 2 * g) / (senθ)²]

vi= √ [12 ft * 2 * 32.17 ft/s² ) / (sen 45º)²]

vi= √ [772.08 ft²/s² / 0.5]

vi= √1544.16 ft²/s²

vi = 39.295 ft/s

What is projectile motion?

The projectile motion is the motion whose trajectory describes a parabola having a horizontal and a vertical component of motion.

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The best leaper in the animal kingdom is the puma, which can jump to a height of 12. 0 feet when leaving

How much heat is required to be removed from a 8kg liquid water at 33 °C to be transformed into ice at 0 °C?

Answers

The Total heat required to transform 8 kg of liquid water at 33 °C to the ice at 0 °C is 13,019 J.

The heat required to be removed from a liquid to transform it into a solid is called the heat of fusion. For water, the heat of fusion is approximately 334 J/g. To calculate the amount of heat required to transform 8 kg of liquid water at 33 °C to the ice at 0 °C, we'll need to take into account both the heat of fusion and the heat required to lower the temperature of the water from 33 °C to 0 °C.

First, we'll calculate the heat required to lower the temperature of the water from 33 °C to 0 °C. This can be calculated using the formula:

Q = mcΔT

where Q is the heat required, m is the mass of the water (8 kg), c is the specific heat capacity of water (4.186 J/g·°C), and ΔT is the change in temperature (3temperature change

Q = (8 kg)(4.186 J/g·°C)(33 °C) = 10,347 J

Next, we'll calculate the heat of fusion by multiplying the heat of fusion of water (334 J/g) by the mass of the water (8 kg).

Q = (334 J/g)(8 kg) = 2672 J

To sum up, the total heat required to transform 8 kg of liquid water at 33 °C to ice at 0 °C, is equal to the heat required to lower the temperature + heat of fusion which is 10,347 J + 2672 J = 13,019 J

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a satellite is to orbit the earth so that its period is 2.5 hours. a. what velocity is required to maintain this orbit? b. what will be the altitude of this orbit?

Answers

a) the velocity required to maintain this orbit is 7,423 meters per second and

b) the altitude of this orbit will be 8,390 kilometers.

By calculating the below steps

Time period of satellite orbit = 2.5 hours = 2.5 x 3600 seconds = 9000 s

Radius of satellite orbit = r

Velocity of satellite = v

Let's use the relation between orbital period and velocity of satellite,

V = 2πr/T

Putting the given values, v = 2πr/T …(1)

Also, gravitational force acting on the satellite is given by:

F = (mv²)/r

Here, m = mass of the satellite and g = acceleration due to gravity on the earth at altitude h.

mass of the satellite m = 1000 kg and

g = 9.8 m/s².

Substituting the value of force in equation (2),

mv²/r = F= GMm/r²

Here, M = mass of the earth = 5.98 × 10²⁴ kg and G = gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg². Hence,

v² = GM/r…(2)

On substituting equation (1) into equation (2),

v² = (4π²r²)/T² …(3)

From equations (2) and (3),

GM/r = (4π²r²)/T²

GM = (4π²r³)/T²…(4)

Substituting the given value of T = 9000 s and solving equation (4) for r,

We get,

r³ = (GM × T²)/(4π²) = (6.67 × 10⁻¹¹ × 5.98 × 10²⁴ × 9000²) / (4π²)

r³ = 4.46 × 10²³r = 8,390 km

Using equation (2),

v² = GM/rv² = (6.67 × 10⁻¹¹ × 5.98 × 10²⁴) / 8.39 × 10⁶

v² = 47,07,21,290v = 7,423 m/s

So, the velocity required to maintain this orbit is 7,423 meters per second and the altitude of this orbit will be 8,390 kilometers.

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The ability of a telescope to separate two closely spaced stars is called _____.

Answers

The ability of a telescope to separate two closely spaced stars is called (angular) resolution.

What is a telescope ?

Astronomers use a telescope to observe distant things. Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from the night sky. The original telescopes employed lenses, which are simply curved pieces of clear glass, to focus light.

The capacity of a telescope to distinguish two point sources into distinct pictures is known as resolution. The resolving power is constrained by diffraction effects in ideal circumstances, such as above the atmosphere where there is no turbulence (seeing).

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a boat ended up with a velocity of 30.m/s [N30.E] after it experienced an acceleration of 3.0m/s^2 [S] for a period of 4.0s what displacement did the boat cover

Answers

Answer:

  96 m

Explanation:

The average velocity over those 4 seconds is the velocity after 2 seconds:

  30 m/s -(2 s)(3.0 m/s^2) = 24 m/s

The displacement is the product of this average velocity and the duration of the acceleration:

  d = (24 m/s)(4 s) = 96 m

The boat covered 96 m while being accelerated.

Which best describes the motion of the object between 1 and 4 seconds?

Answers

Answer:The object has negative acceleration and eventually stops.

Explanation:

Answer:not sure

Explanation:

Sorry:(

can a person run at a speed of 20 meters per second

Answers

Answer:

No

Explanation:

The fastest recorded time for a person to run 100 metres is 9.58 seconds, which is the equivalent of 10.4 metres per second

Answer:

No

Explanation:

Humans can run as fast as 19.3m/s, using their full possible energy.

if red light of wavelength 700 nmnm in air enters glass with index of refraction 1.5, what is the wavelength λλlambda of the light in the glass?
Express your answer in nanometers tothree significant figures.
λ = ___ nm

Answers

To calculate the wavelength (λ) of red light in the glass, you need to use the formula: λ_glass = λ_air / index of refraction where λ_air is the wavelength of red light in air (700 nm), and the index of refraction for the glass is 1.5.
λ_glass = 700 nm / 1.5, λ_glass ≈ 467 nm So, the wavelength of red light in the glass is approximately 467 nm.

When light travels from one medium to another, such as from air to glass, its speed and direction change, causing the light to bend or refract. The amount of bending depends on the properties of the two media and is quantified by the index of refraction, which is a ratio of the speed of light in a vacuum to the speed of light in the medium. In this case, we are given the wavelength of red light in air, which is 700 nm. To find the wavelength of red light in the glass, we use the formula λ_glass = λ_air / index of refraction, where the index of refraction for the glass is 1.5. When we substitute these values into the formula, we get a wavelength of approximately 467 nm in the glass. This means that red light in the glass has a shorter wavelength than in air because its speed is slower in the glass. This effect is known as dispersion and causes different colours of light to bend at different angles when passing through a prism, resulting in the rainbow spectrum.

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Put the major layers of Earth's atmosphere in to the correct order from the ground upward.Drag the layers into place in the correct order from lowest altitude at left to highest altitude at right.-troposphere-stratosphere-thermosphere-exosphere

Answers

The Earth's atmosphere consists of several distinct layers, each with its own unique characteristics. From the ground up, these layers are organized in the following order: troposphere, stratosphere, mesosphere, thermosphere, and exosphere.

The troposphere is the lowest layer of the atmosphere, extending from the Earth's surface up to approximately 8 to 15 kilometers in altitude. This layer contains most of the Earth's weather phenomena, such as clouds, rain, and snow. Temperature decreases with altitude in the troposphere. Above the troposphere is the stratosphere, which extends from around 15 to 50 kilometers above the Earth's surface. The ozone layer, which absorbs and scatters ultraviolet solar radiation, is located in this layer. Temperature increases with altitude in the stratosphere due to the absorption of UV radiation by the ozone. The mesosphere is not mentioned in the original question but is the next layer above the stratosphere, extending from approximately 50 to 85 kilometers in altitude. In this layer, temperature decreases with altitude, and meteors often burn up upon entering the mesosphere.

Above the mesosphere is the thermosphere, extending from around 85 to 600 kilometers above the Earth's surface. This layer contains the ionosphere, which is important for radio communications. The temperature increases with altitude in the thermosphere due to the absorption of solar radiation by the few gas particles present. Finally, the exosphere is the outermost layer of the Earth's atmosphere, extending from about 600 kilometers to the edge of space. In this layer, gas particles are widely dispersed, and the boundary between the exosphere and outer space is indistinct.

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A 20.8 m long string is clamped at both ends and under 9.4 N of tension. It supports consecutive standing waves at 40 Hz and 50 Hz. What is the string mass density in g/m

Answers

Main answer:The string mass density in g/m is 3.02 × 10⁻³:In the given problem,The length of the string, L = 20.8 mThe tension on the string, T = 9.4 NThe frequency of the standing waves, f₁ = 40 Hz and f₂ = 50 HzTo find the string mass density, we need to use the formula;`v = √(T/µ)

`Where, v is the velocity of the wave, T is the tension on the string, and µ is the mass density of the string.Then we will use the formula for the frequency of the standing wave in a string;`f = nv/(2L)`Where, f is the frequency of the standing wave, n is the harmonic number (1, 2, 3, 4, ...), L is the length of the string, and v is the velocity of the wave.Here, n = 1 for the first harmonic and n = 2 for the second harmonic.For the first harmonic,`f₁ = v/(2L)`For the second harmonic,`f₂ = 2v/(2L) = v/L`Dividing f₂ by f₁, we get;`f₂/f₁ = L/2L = 1/2`

Therefore,`f₁ = 40 Hz` and `f₂ = 50 Hz` such that `f₂/f₁ = 1/2`We can find the velocity v by using the formula`v = f₁(2L)`and`v = f₂L`We can then equate both the expressions for v, and get,`f₁(2L) = f₂L`Simplifying,`L = v/(2f₁) = v/(2f₂)`Then,`v = f₁L × 2`We can use this value of v in the formula for mass density;`µ = T/v²`Substituting the given values,`µ = (9.4 N)/(f₁L × 2)²`For f₁ = 40 Hz,`L = v/(2f₁) = (v/80) m``µ = (9.4 N)/((v/80) × 2)²``µ = (9.4 N)/(v²/6400)`For f₂ = 50 Hz,`L = v/(2f₂) = (v/100) m``µ = (9.4 N)/((v/100))²``µ = (9.4 N)/(v²/10000)`Since `f₂/f₁ = 1/2`, the values of `v` are the same for both frequencies.Substituting the value of `v`, we get;`µ = (9.4 N)/(v²/6400) = (9.4 N)/(v²/10000)`Simplifying,`µ = 0.012 kg/m`or`µ = 1.2 × 10⁻² kg/m`Converting to grams per meter,`µ = 1.2 × 10⁻² kg/m × (1000 g/1 kg)`Therefore,`µ = 3.02 × 10⁻³ g/m`

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If a metal has a mass of 78.2 g and a volume of 11.4 mL, what is its density?

Answers

Answer:

6.86g/mL

Explanation:

The density of the metal would be approximately 6.859 grams per milliliter (g/mL).

Given that the mass (m) is 78.2 g and the volume (V) is 11.4 mL, we can plug these values into the formula:

Density is a physical property that quantitatively expresses how much mass is contained within a given volume of a substance. In other words, it is a measure of how tightly packed the particles or molecules of a material are. Mathematically, density is defined as the mass of an object (or substance) divided by its volume. It is often denoted by the Greek letter "ρ" (rho).

Density is defined as mass per unit volume. The formula for density is:

Density (ρ) = Mass (m) / Volume (V)

Density (ρ) = 78.2 g / 11.4 mL

Now, let's calculate the density:

Density (ρ) = 6.859 g/mL

So, the density of the metal is approximately 6.859 grams per milliliter (g/mL).

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The gravitational field of the Moon is weaker than that of the Earth. It
pulls on each kilogram of mass with a force of 1.6N. What will be the
weight of a 50kg mass on the Moon? [4]

Answers

The weight will be 80N.

Given :- Weak Gravitational field of moon relative to earth ,

F=1.6N

To find : Weight of a 50Kg mass on Moon .

Principle - Weight and mass although sounding same has different roles in Physics . Mass is the amount of matter that is utilized to build a material while talking about weight means its inclusive of an exertion of earth with the application of mass. Mathematically weight w= mg [Product of mass and gravity ]

Now in this question using basic unitary method we can resolve the ask of question. For example cost of one pen is 2rupee then cost of 2 pens is 4 rupees.

Reasoning- As per question , weight of 1 kg = 1.6N

so weight of 50Kg= 1.6 x 50⇒80N

Hence the amount of 80N equivalent weight is computed.

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A roadrunner at rest suddenly spots a rattlesnake slithering directly away at a constant speed of 0.75 m/s. At the moment the snake is 10. Meters from the bird, the roadrunner starts chasing it with a constant acceleration of 1.0 m/s^2. How long will it take the roadrunner to catch up to the snake?

Answers

Answer:

The roadrunner will take approximately 5.285 seconds to catch up to the rattlesnake.

Explanation:

From the statement we notice that:

1) Rattlesnake moves a constant speed (\(v_{S} = 0.75\,\frac{m}{s}\)), whereas the roadrunner accelerates uniformly from rest. (\(v_{o, R} = 0\,\frac{m}{s}\), \(a = 1\,\frac{m}{s^{2}}\))

2) Initial distance between the roadrunner and rattlesnake is 10 meters. (\(x_{o, R} = 0\,m\), \(x_{o,S} = 10\,m\))

3) The roadrunner catches up to the snake at the end. (\(x_{S} = x_{R}\))

Now we construct kinematic expression for each animal:

Rattlesnake

\(x_{S} = x_{o,S}+v_{S}\cdot t\)

Where:

\(x_{o, S}\) - Initial position of the rattlesnake, measured in meters.

\(x_{S}\) - Final position of the rattlesnake, measured in meters.

\(v_{S}\) - Speed of the rattlesnake, measured in meters per second.

\(t\) - Time, measured in seconds.

Roadrunner

\(x_{R} = x_{o,R} +v_{o,R}\cdot t +\frac{1}{2}\cdot a\cdot t^{2}\)

Where:

\(x_{o, R}\) - Initial position of the roadrunner, measured in meters.

\(x_{R}\) - Final position of the roadrunner, measured in meters.

\(v_{o,R}\) - Initial speed of the roadrunner, measured in meters per second.

\(a\) - Acceleration of the roadrunner, measured in meters per square second.

\(t\) - Time, measured in seconds.

By eliminating the final positions of both creatures, we get the resulting quadratic function:

\(x_{o,S}+v_{S}\cdot t = x_{o,R}+v_{o,R}\cdot t +\frac{1}{2}\cdot a \cdot t^{2}\)

\(\frac{1}{2}\cdot a \cdot t^{2} + (v_{o,R}-v_{S})\cdot t + (x_{o,R}-x_{o,S}) = 0\)

If we know that \(a = 1\,\frac{m}{s^{2}}\), \(v_{o, R} = 0\,\frac{m}{s}\), \(v_{S} = 0.75\,\frac{m}{s}\), \(x_{o, R} = 0\,m\) and \(x_{o,S} = 10\,m\), the resulting expression is:

\(0.5\cdot t^{2}-0.75\cdot t -10=0\)

We can find its root via Quadratic Formula:

\(t_{1,2} = \frac{-(-0.75)\pm \sqrt{(-0.75)^{2}-4\cdot (0.5)\cdot (-10)}}{2\cdot (0.5)}\)

\(t_{1,2} = \frac{3}{4}\pm \frac{\sqrt{329}}{4}\)

Roots are \(t_{1} \approx 5.285\,s\) and \(t_{2}\approx -3.785\,s\), respectively. Both are valid mathematically, but only the first one is valid physically. Hence, the roadrunner will take approximately 5.285 seconds to catch up to the rattlesnake.

Firecrackers A and B are apart. You are standing exactly halfway between them. Your lab partner is on the other side of firecracker A. You see two flashes of light, from the two explosions, at exactly the same instant of time. Define event 1 to be "firecracker A explodes" and event 2 to be "firecracker B explodes." According to your lab partner, based on measurements he or she makes, does event 1 occur before, after, or at the same time as event 2? Explain

Answers

Based on the scenario described, if you see the two flashes of light from the two explosions at exactly the same instant, then according to your lab partner, event 1 (firecracker A explodes) and event 2 (firecracker B explodes) also occur at the same time.

This is because your lab partner is on the other side of Firecracker A and can observe the explosion at the same time as you observe the explosion of Firecracker B.

This is an example of the relativity of simultaneity, which means that the timing of events is relative to the observer's frame of reference. Since you and your lab partner are in different positions relative to the explosions, you will observe the timing of the events differently. However, according to the measurements made by your lab partner, who is located on the opposite side of Firecracker A, event 1 and event 2 occur at the same time.

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When a liquid changes into a solid it is ________.

Answers

Answer:Freezing

Explanation:

if a liquid becomes a solid it freezes because it is left in a cold temp and freezes over time.

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If Argon's melting point is -309 degrees then what is its freezing point?

Answers

The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

A 2.0 kg cart has a momentum of 10.0 kg m/s. What is its velocity?


A.)22 m/s

B.) 2.0 m/s

C.) 5.0 m/s

D.) 20. m/s

Answers

Answer:

\(\boxed {\boxed {\sf C. \ 5.0 \ m/s}}\)

Explanation:

Momentum is the product of mass and velocity. The formula is:

\(p=mv\)

The mass of the cart is 2.0 kilograms. The momentum is 10.0 kg m/s. The velocity is unknown.

\(m= 2.0 \ kg \\p= 10.0 \ kg \ m/s\)

Substitute the values into the formula.

\(10.0 \ kg \ m/s= (2.0 \ kg ) v\)

We want to solve for the velocity (v). Therefore we must isolate the variable. It is being multiplied and the inverse of multiplication is division. Divide both sides of the equation by 2.0 kg.

\(\frac { 10.0 \ kg \ m/s}{2.0 \ kg}=\frac{(2.0 \ kg )v}{2.0 \ kg}\)

The kilograms will cancel each other out.

\(\frac { 10.0 \ m/s}{2.0}=v\)

\(5.0 \ m/s=v\)

The velocity is 5 meters per second.

What is the name of the album that is most frequently cited as the beginning of fusion?

Answers

The album that is most frequently cited as the beginning of fusion is "In a Silent Way" by Miles Davis. Released in 1969, it is often regarded as a groundbreaking and influential work that marked a significant shift in jazz and the emergence of fusion music.

"In a Silent Way" showcased a departure from Davis' previous acoustic jazz sound and incorporated elements of electric instruments, studio production techniques, and improvisational freedom. The album blended jazz with elements of rock, funk, and electronic music, creating a unique and experimental sonic landscape. The musicians involved in the recording, including Wayne Shorter, Herbie Hancock, and John McLaughlin, went on to become key figures in the fusion genre. This album laid the foundation for future fusion developments, influencing artists across various genres. Its atmospheric, ethereal, and exploratory nature set the stage for the fusion movement of the 1970s, which further integrated jazz with elements of rock, funk, and other genres. "In a Silent Way" remains a pivotal work in the history of fusion, symbolizing the fusion of diverse musical styles and the limitless possibilities of blending genres in innovative and creative ways.

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