Answer:
Website C
Step-by-step explanation:
bc website c is $1.25 and website b is $1.30. website c is cheaper
Sarah, Natasha and Richard share some sweets in the ratio 5:2:2. Sarah gets 21 more sweets than Richard. How many sweets does Natasha get?
Answer:
The above I did in my word file and took screen shot and send it for u
ABCD is a rectangular garden plot . P is a water tap find the distance from the tap to corner C.
the length of the PC will be 5.714 m.
What is a rectangle?
Rectangles are quadrilaterals having four right angles in the Euclidean plane of geometry. Various definitions include an equiangular quadrilateral, A closed, four-sided rectangle is a two-dimensional shape. A rectangle's opposite sides are equal and parallel to one another, and all of its angles are exactly 90 degrees. Area of rectangle is A = a*b
PC = 40/7 = 5.714 m
i) the solution can be found by using similarity of triangles.
ii) therefore we can see that pc/8=5/7
iii) therefore PC = 40 / 7 = 5.714 m
Hence the length of the PC will be 5.714 m.
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The distance between the tap and Corner C is 6m.
What is rectangular?A rectangle is a quadrilateral in which all the angles are equal and the οppοsite sides are equal and parallel. There are many rectangular οbjects arοund us. Each rectangle shape is characterized by twο dimensiοns, its length and width.
The lοnger side οf the rectangle is knοwn as the length and the shοrter side is knοwn as the width. In this chapter, let us learn abοut the rectangle shape, sοme rectangle fοrmulas, types οf rectangles and its prοperties.
Given to find distance between tap to C
We know that the diagonals of a rectangle are congruent,
Thus,
DB = AC
⇒ 8 + 5 = 7 + PC ⇒ where PC is the distance between tap to C.
⇒ 13 = 7 + PC
⇒ 13 - 7 = PC
⇒ 6 = PC
Thus, the distance between the tap and Corner C is 6m.
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Complete question:
system of inequalities
y<-5x+2
y>-x-2
Answer:
answer to the question
graph
In the translation T of the graph below, use the figure to describe the following transformation. T T-1: (x, y) ( x, y) ( x + 3, y + 1) ( x - 3, y - 1)
Answer:
(X - 3, Y - 1).
Can you help me? Please.
Answer:
I think that the other end point is 5,10
In estimating a population proportion using a large sample, the value of is assumed to be 0. 35, and its 95rror margin is 0. 2. Find the sample size to meet the error margin
The margin of error will be E = ± 4.04 %
What is the margin of error?The margin of error is defined as the error in the sample data of the statistics.
Given that:-
sample data = ( p ).
success p^ = success percentage = 40 %
confidence interval CI = 98%
sample size n = 800
margin of error E:
E=z-critical \(\dfrac{\sqrt{P(P-1)}}{n}\)
The margin of error "E" for estimation of population proportion ( p ) is given by:
P ( Z < Z-critical ) = a/ 2
a = 1 - CI
P ( Z < Z-critical ) = (1 - 0.98) / 2
P ( Z < Z-critical ) = 0.01
Z-critical = 2.33
The error E = ± 4.04 %
Thus, the correct answer is E=± 4.04 %
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identify the correct inverse trigonometric function to use to solve for the given angle
Considering the given triangle :
GIVEN :
• Opposite side to angle = 34
,• Adjacent side to angle = 48
,• We will use Tan = opposite /adjacent trigonometric fuction tocalculate angle
CALCULATIONS:
\(\begin{gathered} \tan\theta\text{ = opposite /adjacent } \\ \text{ }\tan\theta\text{ = }\frac{34}{48} \\ \Rightarrow\theta\text{ = }\tan^{-1}(\frac{34}{48}) \\ \therefore\text{ }\theta\text{ = }\tan^{-1}(0.71)\text{ } \end{gathered}\)Therefore , = tan^-1( 0.71)Christine is in charge of planning a reception for 1600 people. She is trying to decide which snacks to buy. She has asked a random sample of people who are coming to the reception what their favorite snack is. Here are the results. Favorite Snack Brownies Cookies Chips Other Number of People 25 22 50 63 Based on the above sample, predict the number of the people at the reception whose favorite snack will be brownies or chips. Round your answer to the nearest whole number. Do not round any intermediate calculations.
It is anticipated that 75 guests at the wedding will prefer chips or brownies as a snack.
what is proportionality ?A variation in one variable results in a proportionate change to the second variable when there is a proportional mathematical link between the two variables. One can say that two variables are proportional if their ratio remains constant. For instance, if the price of a product is based on the quantity purchased, then if we acquire twice however many units, the price will also double. The cost to unit price in this instance remains constant. If different variables x and y are related, we may write the following mathematical expression: x/y = k where the proportionality constant k is used. This can be arranged as follows: x = ky .This implies that using this equation, we can determine the other variable if we know the value of one.
given
Inferring that 25 individuals like brownies and 50 people favour chips based on the sample provided, the total number of persons who favour either food is:
25 + 50 = 75
As a result, we may assume that out of the 1600 guests attending the reception, roughly 75/1600 = 0.046875 or 4.69% will select brownies or chips.
We can multiply this proportion by the entire population to get the actual number of people:
0.046875 x 1600 ≈ 75
When this is rounded to the closest whole number, we obtain:
It is anticipated that 75 guests at the wedding will prefer chips or brownies as a snack.
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Triangle T is translated to Triangle T What is the translation from T to T'? у T T A 3 units left B 3 units right c5 units left 05 PLEASEEEE HELP ME OUT
Answer:
5 units to the right!
It would take 3 unites to the right to get the 0 and then 2 more units to the right to get to 2, so that means 5 units in total to the right.
help please! Thanks!
Answer:
2/3
Step-by-step explanation:
the equation is \(\frac{\frac{1}{y}}{\frac{1}{x}}\), and when the values of x and y are substituted in, you get the fraction 1/3 over the fraction 1/2. when simplified, this is 2/3.
(This exercise is from Physical Geology by Steven Earle and is used under a CC BY 4.0 license.) Heavy runoff can lead to flooding in streams and low-lying areas. The graph below shows the highest discharge per year between 1915 and 2014 on the Bow River at Calgary, Canada. Using this data set, we can calculate the recurrence interval (R) for any particular flood magnitude with the equation R=(n+1)/r, where n is the number of floods in the record being considered, and r is the rank of the particular flood. There are a few years missing in this record, and the actual number of data points is 95. The largest flood recorded on the Bow River over that period was in 2013, which attained a discharge of 1,840 m3/s on June 21. R; for that flood is (95+1)/1=96 years. The probability of such a flood in any future year is 1/R; which is 1%. The fifth largest flood was just a few years earlier in 2005 , at 791 m3/5. Ri for that flood is (95+1)/5=19.2 years. The recurrence probability is 5%. - Calculate the recurrence interval for the second largest flood (1.520 m3/s in 1932). Express your answer in units of years. - What is the probability that a flood of 1,520 m3/s will happen next year? - Examine the 100-year trend for floods on the Bow River. If you ignore the major floods (the labeled ones), what is the general trend of peak discharges over that time?
The recurrence interval for the second largest flood on the Bow River in 1932 is approximately 1.0106 years. The probability of a flood with a discharge of 1,520 m3/s occurring next year is roughly 98.95%. When examining the 100-year trend of peak discharges, excluding major floods, there is likely a general pattern of fluctuations but with overall stability in typical peak discharge values.
Using the provided data on the highest discharge per year on the Bow River at Calgary, Canada, we can calculate the recurrence interval (R) for specific flood magnitudes and determine the probability of such floods occurring in the future. Additionally, we can examine the 100-year trend for floods on the Bow River, excluding major floods, to identify the general trend of peak discharges over time.
1) Calculating the Recurrence Interval for the Second Largest Flood (1,520 m3/s in 1932):
To calculate the recurrence interval (R) for the second largest flood, we need to determine the rank of that flood. Since there are 95 data points in total, the rank of the second largest flood would be 94 (as the largest flood, in 2013, is excluded). Applying the formula R = (n + 1) / r, we have:
R = (95 + 1) / 94 = 1.0106 years
Therefore, the recurrence interval for the second largest flood (1,520 m3/s in 1932) is approximately 1.0106 years.
2) Probability of a Flood of 1,520 m3/s Occurring Next Year:
The probability of a flood of 1,520 m3/s happening next year can be calculated by taking the reciprocal of the recurrence interval for that flood. Using the previously calculated recurrence interval of 1.0106 years, we can determine the probability:
Probability = 1 / R = 1 / 1.0106 = 0.9895 or 98.95%
Thus, the probability of a flood of 1,520 m3/s occurring next year is approximately 98.95%.
3) Examination of the 100-Year Trend for Floods on the Bow River:
To analyze the 100-year trend for floods on the Bow River while excluding major floods, we focus on the peak discharges over time. Without considering the labeled major floods, we can observe the general trend of peak discharges.
Unfortunately, without specific data on the peak discharges for each year, we cannot provide a detailed analysis of the 100-year trend. However, by excluding major floods, it is likely that the general trend of peak discharges over time would show fluctuations and variations but with a relatively stable pattern. This implies that while individual flood events may vary, there might be an underlying consistency in terms of typical peak discharges over the 100-year period.
In summary, the recurrence interval for the second largest flood on the Bow River in 1932 is approximately 1.0106 years. The probability of a flood with a discharge of 1,520 m3/s occurring next year is roughly 98.95%. When examining the 100-year trend of peak discharges, excluding major floods, there is likely a general pattern of fluctuations but with overall stability in typical peak discharge values.
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In anova, by dividing the mean square between groups by the mean square within groups, a(n) _____ statistic is computed.group of answer choices
In anova, by dividing the mean square between groups by the mean square within groups, a(n) Analysis of variance statistic is computed.
What is Analysis of variance ?
With the help of the statistical analysis approach known as ANOVA, apparent aggregate variability within a data set is explained by separating systematic components from random factors. Systematic influences, but not random ones, statistically affect the data set that is being presented.What are some instances where ANOVA has been applied?
An ANOVA demonstrates the link between the dependent variable and the level of the independent variable. For illustration: In order to determine whether there is a difference in the number of hours of sleep each night as your independent variable, you divide the groups into low, medium, and high social media use categories.Learn more about Analysis of variance
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Change one number in the equation below to safely land the plane.
Press "Submit" to see if the plane lands safely.
If x≠4 and x≠-4, the fraction x^2-8x+16/x^2-16 can be simplified to what?
For the given fraction x^2-8x+16/x^2-16 if x≠4 and x≠-4 the simplified fraction is (x-4)/(x+4).
Simplified fraction refers to the fractions in their lowest form which has been reduced and simplified. The numerator and denominator in the fraction are reduced in simplified fraction to the extent that the only common factor between them is 1.
In order to simplify the fraction (x^2-8x+16)/(x^2-16), first, we must factor the numerator and denominator of the fraction:
Numerator: x^2-8x+16 = (x-4)(x-4) = (x-4)^2
Denominator: x^2-16 = (x-4)(x+4)
So the fraction becomes:
(x-4)^2/(x-4)(x+4)
Next, we can simplify the fraction by canceling out the (x-4) term in the numerator and denominator:
(x-4)/(x+4)
Therefore, the simplified fraction is (x-4)/(x+4) if x≠4 and x≠-4.
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A triangle has side lengths of 3 m, 5 m and 4 m. The triangle is enlarged so that the larger
triangle is similar to the original and the scale factor is 4. Find the perimeter of the larger
triangle
Answer:
48 meters
Step-by-step explanation:
3*4 = 12
5*4 = 20
4*4 = 16
These are the sizes when the triangle enlarges with a scale factor of 4.
To find perimeter, you add the sides together
12+20+16 = 48
The perimeter is 48 meters
The perimeter of larger triangle is 48m.
Given that,
Side length 3m , 5m and 4m.The scale factor is 4.We need to find the perimeter of larger triangle.According to the scenario, calculation of the given data are as follows,
Perimeter of larger triangle = 4m \(\times\) ( 3m + 5m + 4m)
= 4m \(\times\) 12m
= 48 m
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"Find the missing side" , its due today.
Please help me on my homework.
Answer:
X=9 I think
Step-by-step explanation:
Irdk coz I suck at math
On the unit circle, where 0 < theta < or equal to 2pi, when is tan theta undefined?
A. Theta=pi and theta=2pi
B. sin theta = cos theta
C. theta = pi/2 and theta=3pi/2
D. sin theta = 1/cos theta
Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.
To determine when tan(theta) is undefined on the unit circle, we need to remember the definition of the tangent function.
Tangent is defined as the ratio of the sine and cosine of an angle. Specifically, tan(theta) = sin(theta)/cos(theta).
Now, we know that cosine can never be equal to zero on the unit circle, since it represents the x-coordinate of a point on the circle and the circle never crosses the x-axis. Therefore, the only way for tan(theta) to be undefined is if the cosine of theta is equal to zero.
There are two values of theta on the unit circle where cosine is equal to zero: pi/2 and 3pi/2.
At theta = pi/2, we have cos(pi/2) = 0, which means that tan(pi/2) = sin(pi/2)/cos(pi/2) is undefined.
Similarly, at theta = 3pi/2, we have cos(3pi/2) = 0, which means that tan(3pi/2) = sin(3pi/2)/cos(3pi/2) is also undefined.
Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.
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104,988 rounded to the nearest hundred, 9 is the target
Hey there!
104,988
Hundred thousands: 100,000
Ten thousands: 100,000
Thousands: 105,000
Hundreds: 105,000
Tens: 104,990
Ones also known as the Whole number: 104,988
Based on the information we have to the question, we have your answer now.
Answer: 105,000
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
How do I find and construct the geometric mean in this problem?
x would be the side-length of a square that has the same area as a rectangle with width b and length a.
√(a*b) = x
How to find the value of x?Notice that you have two "lengths" which are a and b.
And you want to find x such that:
a/x = x/b
Now, notice that w e can rewrite the above expressions as:
a*b = x*x
This means that x would be the side-length of a square that has the same area as a rectangle with width b and length a.
Now, if you know the values of a and b (you can get these by using a ruler for example)
Then you can replace them in the equation:
a*b = x*x
√(a*b) = x
And find the value of x that meets the given condition.
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What is the value of x?
x =
Check the picture below.
There is a virus turning people into zombies who attack the living and never die.
No one knows where it came from, but when the virus was first detected, it was 2 days after a group of 16 archaeologists had opened up an ancient tomb.
Unfortunately, all 16 archaeologists had been turned to zombies.
Authorities believe the virus is spread when infected people bite someone who’s uninfected.
Each zombie bites three uninfected people each day.
a. How many zombies were there at day zero (i.e. t =0)?
b. If the number of zombies Z(t) takes the form , where A is the number of zombies at t = 0, what is k, the estimated growth rate of the virus?
c. How long will it take before the entire human population of the planet (which for this problem will be taken as 7 billion people) are turned into the undead?
(a) At day zero, the number of zombies, Z(0) = 16
Given that 16 archaeologists had opened up an ancient tomb, which is the cause of the virus. The given number of zombies at day zero is 16.
(b) The number of zombies Z(t) takes the form
Z(t) = Ae^(kt), where A is the number of zombies at t=0 and k is the estimated growth rate of the virus.
At t=0, Z(0) = A
A = 16
Therefore, the number of zombies takes the form Z(t) = 16e^(kt)
To find k, we have to use the information provided. Each zombie bites three uninfected people each day. Thus, the number of newly infected people per day is 3Z(t).
The growth rate of the virus is given by dZ/dt. So we have,
dZ/dt = 3Z(t)
Separating the variables and integrating, we get
∫dZ/Z = ∫3dt
ln |Z| = 3t + C, where C is the constant of integration
At t = 0, Z = A = 16
ln |16| = C
C = ln 16
So the equation becomes
ln |Z| = 3t + ln 16
Taking the exponential of both sides, we get
|Z| = e^(3t+ln16)
|Z| = 16e^(3t)
Z = ±16e^(3t)
But since the number of zombies is always positive, we can ignore the negative sign. Hence,
Z(t) = 16e^(3t)
Comparing with Z(t) = Ae^(kt), we get
k = 3
Therefore, the estimated growth rate of the virus is 3.
(c)The entire human population of the planet is 7 billion.
Let P(t) be the number of uninfected people at time t.
Initially, P(0) = 7 billion
We know that each zombie bites three uninfected people each day.
So the number of newly infected people per day is 3Z(t)P(t).
The rate of change of uninfected people is given by dP/dt, which is negative since P is decreasing.
So we have,
dP/dt = -3Z(t)P(t)
Separating the variables and integrating, we get
∫dP/P = -∫3Z(t)dt
ln |P| = -3∫Z(t)dt + C, where C is the constant of integration
At t=0, Z = 16
So we have,
ln |7 billion| = -3(16t) + C
C = ln |7 billion| + 48t
Putting the value of C, we get
ln |P| = -3(16t) + ln |7 billion| + 48t
ln |P| = 32t + ln |7 billion|
Taking the exponential of both sides, we get
|P| = e^(32t+ln7billion)
|P| = 7 billione^(32t)
P = ±7 billione^(32t)
But since the number of uninfected people is always positive, we can ignore the negative sign. Hence,
P(t) = 7 billione^(32t)
When the entire population is infected, the number of uninfected people P(t) becomes zero.
So we have to solve for t in the equation P(t) = 0.
7 billione^(32t) = 0
e^(32t) = 0
Taking logarithms, we get
32t = ln 0
This is undefined, so the entire population will never be infected.
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evaluate the surface integral ∫∫8 where is the helicoid (i.e., spiral ramp) given by the vector parametric equation ⃗ (,)=⟨cos,sin,⟩, 0≤≤1, 0≤≤5.
To evaluate the surface integral of the helicoid given by the vector parametric equation ⟨x,y,z⟩ = ⟨cosθ, sinθ, θ⟩, where 0 ≤ θ ≤ 1 and 0 ≤ θ ≤ 5, we need to compute the surface area over this parameter range.
First, we find the partial derivatives of the position vector with respect to θ:
∂⟨x,y,z⟩/∂θ = ⟨-sinθ, cosθ, 1⟩
Next, we calculate the magnitude of the cross product of the partial derivatives:
|∂⟨x,y,z⟩/∂θ| = √((-sinθ)^2 + (cosθ)^2 + 1^2) = √(2)
Now, we can set up the surface integral:
∫∫⟨8⟩ · ∂⟨x,y,z⟩/∂θ dA = ∫∫⟨8⟩ · ⟨-sinθ, cosθ, 1⟩ dA
= ∫₀¹ ∫₀⁵ ⟨-8sinθ, 8cosθ, 8⟩ dθ dz
Evaluating the integral, we get:
= ∫₀¹ [-8cosθ]₀⁵ dθ
= ∫₀¹ [-8(cos5 - cos0)] dθ
= ∫₀¹ 8(1 - cos5) dθ
= 8(1 - cos5)
Therefore, the surface integral of the helicoid is 8(1 - cos5).
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GIVING BRAINLISTTT
At 7 P.M. last night, the temperature was 10 degrees Fahrenheit. At 7 a.m. the next morning, the temperature was - 2 degrees Fahrenheit.
By how much did the temperature change from 7 p.m. to 7 a.m.?
Answer:
12 degrees Fahrenheit I think I don't know for sure tho
Answer:
It dropped by 12 degrees. So -12.
Step-by-step explanation:
10- -2= 12. So it changed by -12 and dropped 12 degrees.
Hope this helps!
if h(x)=1/4x^4-3x^3, find h(4) PLEASE HELP MEEEEEEE
Step-by-step explanation:
h(x)=1/4x⁴-3x³By replacing x with 4, we get
h(4)=1/4×4⁴-3×4³h(4)=1/4×256-3×64h(4)=64-192h(4)=-128\(\\ \sf\bull\longmapsto h(x)=\dfrac{1}{4}x^4-3x^3\)
\(\\ \sf\bull\longmapsto h(4)\)
\(\\ \sf\bull\longmapsto \dfrac{1}{4}4^4-3(4)^3\)
\(\\ \sf\bull\longmapsto 4^3-3(64)\)
\(\\ \sf\bull\longmapsto 64-192\)
\(\\ \sf\bull\longmapsto -128\)
The table below shows the earnings, in thousands of dollars, for three different commissioned employees. $2,000 3% on all sales 7% on all sales 5% on the first $40,000 8% on anything over $40,000 December 4. 4 5. 6 5. 2 January 2003. 5 3. 85 3. 6 February 2004. 7 4. 9 4. 4 Who had the largest dollar amount in sales for the month of December? a. The salary plus commission employee. B. The straight commission employee. C. The graduated commission employee. D. They each had the same dollar amount in sales. Please select the best answer from the choices provided A B C D.
The employee who had the largest dollar amount in sales for the month of December is: Option A: The salary plus commission employee.
How to find the percentage from the total value?Suppose the value of which a thing is expressed in percentage is "a'
Suppose the percent that considered thing is of "a" is b%
Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).
Thus, that thing in number is
\(\dfrac{a}{100} \times b\)
The missing table for this problem is attached below.
The total income of employees in a specific month are:
For X: $2000 + 3% of all sales X does in that specific monthFor Y: 7% of all sales Y does in that specific monthFor Z: 5% of all sales Z does in that specific monthFor the given case, we need their total amount for the month of December.
Case 1: Total amount in dollars for X, in December month:Sales X did in December = $4400
Thus, total amount X got in month of December =
$2000 + 3% of $4400
3% of 4400 is \(\dfrac{4400}{100} \times 3 = 132\) (in dollars)
Thus, total amount X got in month of December = $2000 + $132 = $2,132
Case 2: Total amount in dollars for Y, in December month:Sales Y did in December = $5600
Thus, total amount Y got in month of December =
7% of $5600
7% of 5600 is \(\dfrac{5600}{100} \times 7 = 392\) (in dollars)
Thus, total amount Y got in month of December = $392
Case 3: Total amount in dollars for Z, in December month:Sales Z did in December = $4400
Thus, total amount Z got in month of December =
$2000 + 3% of $5200
5% of 5200 is \(\dfrac{5200}{100} \times 6 = 312\) (in dollars)
Thus, total amount Z got in month of December = $312
Thus, X gets largest dollar amount in December month. X gets salary + commission, so, the employee who had the largest dollar amount in sales for the month of December is: Option A: The salary plus commission employee.
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When p = 12, t = 2, and s=1/6, r= 18. Ifr varies directly with p and inversely with the product of s and t, what is the
constant of variation?
Answer: 4 1/2
Step-by-step explanation:
Diogo has a utility function, U(q1,q2)=q10.2q20.8 where q1 is chocolate candy and q2 is slices of pie. If the price of slices of pie, p2, is $1.00, the price of chocolate candy, p1, is $2.00, and income, Y, is $100, what is Diogo's optimal bundle? The optimal value of good q1 is q1= units. (Enter your response rounded to two decimal places.)
Diogo's optimal bundle is q1 ≈ 12.77 units of chocolate candy and q2 ≈ 74.46 units of slices of pie.
To find Diogo's optimal bundle, we need to maximize his utility function subject to his budget constraint. The budget constraint is given by:
p1q1 + p2q2 = Y
Substituting the given values:
2q1 + 1q2 = 100
We can rewrite this as:
q2 = (100 - 2q1) / 1
Now, let's maximize Diogo's utility function:
U(q1, q2) = q1^0.2 * q2^0.8
Substituting the expression for q2:
U(q1) = q1^0.2 * [(100 - 2q1) / 1]^0.8
To find the optimal bundle, we need to find the value of q1 that maximizes U(q1). We can do this by taking the derivative of U(q1) with respect to q1 and setting it equal to zero:
dU(q1) / dq1 = 0.2q1^(-0.8) * [(100 - 2q1) / 1]^0.8 - 0.8q1^0.2 * [(100 - 2q1) / 1]^(-0.2) * (-2 / 1) = 0
Simplifying the equation:
0.2[(100 - 2q1) / q1]^0.8 = 0.8
[(100 - 2q1) / q1]^0.8 = 4
Taking both sides to the power of 1/0.8:
(100 - 2q1) / q1 = 4^(1/0.8)
Solving for q1:
100 - 2q1 = 4^(1/0.8) * q1
100 = (4^(1/0.8) + 2) * q1
q1 = 100 / (4^(1/0.8) + 2)
Calculating the value of q1:
q1 ≈ 12.77
Now we can substitute this value back into the budget constraint to find q2:
2q1 + q2 = 100
2(12.77) + q2 = 100
25.54 + q2 = 100
q2 = 100 - 25.54
q2 ≈ 74.46
Therefore, Diogo's optimal bundle is q1 ≈ 12.77 units of chocolate candy and q2 ≈ 74.46 units of slices of pie.
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A store pays $37 for a tv stand Store marks up the price by 20 %. What is the new price?
Answer:
$44.4.
Step-by-step explanation: To find the new price, we would simply perform "37 + 20%" yielding 44.4, or forty four dollars and 40 cents. Hope this answered your question.
Answer: 44.4
Step-by-step explanation:
To calculate the original price of a discounted or sale item, you need to know the sale price and the discount percentage. The calculations include a simple formula that divides the sale price by the result of 1 minus the discount in percentage form. Use this formula to calculate the original or list price of an item.
q 17
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The equation for the axis of symmetry for the given parabolic graph is found as: x = 3.
Explain about the parabolic curve:A parabola is the graph of a quadratic function and features a vertical line passing through its vertex as its axis of symmetry.
A parabola, a U-shaped curve, is the shape of a quadratic function's graph. The graph's vertex, which is an extreme point, is one of its key characteristics. The vertex, or lowest point on the graph or minimal value of the quadratic function, is where the parabola will open up. The vertex is the highest location on the graph or the maximum value if the parabola opens downward. The vertex is a pivotal location on the graph in both scenarios.The graph is also symmetric, with the axis of symmetry being a vertical line that passes through the vertex.
Thus, the equation for the axis of symmetry for the given parabolic graph is found as: x = 3.
Know more about the parabolic curve:
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Which of the following is an open statement
Answer:
where are the options please