Answer:
Explanation:
F = ma
Assuming the 20° is angle θ measured to the horizontal
mgsinθ - μmgcosθ = ma
g(sinθ - μcosθ) = a
at constant velocity, a = 0
g(sinθ - μcosθ) = 0
sinθ - μcosθ = 0
sinθ = μcosθ
μ = sinθ/cosθ
μ = tanθ
μ = tan20
μ = 0.3639702342...
μ = 0.36
Why was the geocentric model of our solar system widely accepted until the 16th century?
A.
The model was considered to work in tandem with the ancient Aztec calendar.
B.
Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
C.
The star catalogue matched the movement of constellations.
D.
No one had yet sailed entirely around Earth to disprove the geocentric model.
The correct answer is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
The geocentric model, which placed Earth at the center of the universe with the Sun, Moon, and stars revolving around it, was widely accepted until the 16th century for several reasons. One of the primary reasons was that observations seemed to support this view. For example, it was observed that the stars appeared to move across the sky in a circular path, and it was assumed that this was due to their motion around Earth. Similarly, the Sun and Moon appeared to rise and set each day, which was consistent with their motion around Earth.
The geocentric model was consistent with the prevailing philosophical and religious beliefs of the time, which held that Earth was a special and unique place at the center of the universe. It was not until the development of the heliocentric model, which placed the Sun at the center of the solar system, and the refinement of astronomical observations, that the geocentric model was gradually abandoned.
The correct option is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
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Find the equivalent capacitance of the
following combination as shown in figure. C₁
In which C₁ = C₂2 = C3 = C4 = C5 = 100 μF
=C4
C3
C₂
The effective capacitance of the following combination with capacitors C₁, C₂, C₃, C₄, C₅ = 100μF is 350 μF.
Capacitors are the energy storage device in the form of electrical energy. The amount of charge (Q) stored in the capacitors is linearly proportional to the applied Voltage (V). Capacitance equals the ratio of charge and voltage. The unit of capacitance is Farad (F). Capacitors are connected in series and parallel connections. In series connections, the capacitance is 1/C(eff) = 1/C₁ + 1/C₂. In parallel connections, the effective capacitance C(eff) = C₁ + C₂.
From the figure,
The capacitances, C₁, C₄, C₂ are parallelly connected whereas C₃ and C₅ are in series connections.
C(eff) = C₁ + C₂ + C₄ = 100 + 100 + 100 = 300 μF
The capacitance C₅ and C₃ are in series connections, then
1/C(eff) = 1/C₅ + 1/C₃ = 1/100 + 1/100 = 2/100 = 1/50
C(eff) = 50 μF
The effective capacitance = 300 + 50 = 350 μF.
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what is the force acting on point O? Check picture for diagram! please and thank you
The magnitude of the force acting at point O is determined as 240 N.
What is the magnitude of the force at point O?The magnitude of the force at point O is calculated by applying the principles of moment as shown below.
sum of the clockwise moment = sum of the anticlockwise moment
F₀(2 m + 2m + 2m) = 260 N (2m + 2 m ) + 200 N ( 2 m )
where;
F₀( is the force at point O6F₀ = 260 (4) + 200(2)
6F₀ = 1,440
F₀ = 1440 / 6
F₀ = 240 N
Thus, the magnitude of the force acting at point O is determined as 240 N.
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what were your preparetion before going the different physical fitness test?
Answer:
Avoid heavy strenuous exercise for the 24 hours prior to testing. Do not exercise at all on the day of testing to ensure you are well rested. Wear appropriate clothing for the conditions (e.g. shorts/track pants and t-shirt/singlet/sports top) and non-slip athletic footwear with laces securely fastened
A car advertisement states that a certain car can accelerate from rest to
27m/s in 4.9 seconds at a temperature of 75F. What is the acceleration of
the car?
Answer:
Acceleration of the car = 5.51 m/s²
Explanation:
Given:
Initial speed of car = 0 m/s
Final speed of car = 27 m/s
Time taken by car = 4.9 seconds
Find:
Acceleration of the car
Computation:
Using first equation of motion
v = u + at
Where
v = Final velocity
u = Initial velocity
t = Time taken
a = Acceleration
So,
v = u + at
27 = 0 + a(4.9)
a(4.9) = 27
a = 5.51 m/s²
Acceleration of the car = 5.51 m/s²
Diffrence between MeV and meV?
Answer:
Difference between MeV and meV?
1 MV = 1000000 volts. 1 MeV stands for million electron volts. It is a unit of energy. 1 MeV = 1.60217653 x 10 13
Explanation:
hope this helps <3
what is a circit pls tell me
Answer:
A closed loop that electrons can travel in.
Explanation:
Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their potential energies due to their interactions with Q?
Charge q1 is distance s from the negative plate of a parallel-plate capacitor. Charge q2=q1/3 is distance 2s from the negative plate. What is the ratio U1/U2 of their potential energies?
We have that The ratio U1/U2 of their potential energies due to their interactions with Q is
\(U1/U2=6\)\(U1/U2=6\)From the question we are told that
Question 1
Charge q1 is distance r from a positive point charge Q.
Question 2
Charge q2=q1/3 is distance 2r from Q.
Charge q1 is distance s from the negative plate of a parallel-plate capacitor.
Charge q2=q1/3 is distance 2s from the negative plate.
Generally the equation for the potential energy is mathematically given as
\(U=\frac{-k*qQ}{r}\)
Therefore
The Equations of U1 and U2 is
For U1
\(U1=\frac{-k*q_1Q}{r}\)
For U2
\(U2=\frac{-k*q_1Q}{3*2r}\)
Since
U is a function of q and q2=q1/3
Therefore
\(U1/U2=6\)
For Question 2
For U1
\(U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}\)
Therefore
\(U1/U2=6\)
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Which vector is the sum of vectors à and b?
The vectors addition permits locating the perfect result for the sum of the two vectors in option B). See attached and the vector is directed to the right and up.
Vector addition is the operation of adding or extra vectors together into a vector sum. The so-known as parallelogram regulation gives the rule for vector addition of or greater vectors. for two vectors and, the vector sum is received via placing them head to tail and drawing the vector from the loose tail to the unfastened head.
A vector is an amount or phenomenon that has impartial residences: importance and direction. The time period also denotes the mathematical or geometrical representation of the sort of quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.
Vectors are used in technological know-how to describe something that has a direction and a magnitude. they're commonly drawn as pointed arrows, the length of which represents the vector's importance
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Which vector is the sum of vectors à and b?
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find acceleration for force 2N acting on 2 Kg?
Answer:
1 m/s^2
Explanation:
F=ma
2 Newtons=2 Kg * a
a=1 m/s^2
A cannonball is shot from the top of a
47.8 m high hill at a speed of 53.7 m/s.
How fast is it going when it reaches
the plain below?
Answer:
61.8
Explanation:
It must be going at a speed of 61.81 m/s when it reaches the plain below
What are kinematic equations?
The kinematic equations are a set of equations that describe the motion of an object with constant acceleration. Kinematics equations require knowledge of derivatives, rate of change, and integrals.
using Kinematics equations
\(v^{2}\) = \(u^{2}\) + 2gs ( a = g)
= \((53.7)^{2}\) + 2 * 9.8 * 47.8 m
v = 61.81 m/s
It must be going at a speed of 61.81 m/s when it reaches the plain below
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An object of mass m starts motion at a velocity of V1 , and accelerates to have a final velocity of V2 that equals 2 V1 , Find the difference in its Kinetic energy.
The difference in its Kinetic energy of the mass is 3 (¹/₂mV₁² ).
What is the difference in the kinetic energy of the mass?
The difference in the kinetic energy of the mass is calculated by applying the following formula as shown below.
ΔK.E = K.Ef - K.Ei
where;
K.Ef is the final kinetic energyK.Ei is the initial kinetic energyThe difference in its Kinetic energy of the mass is calculated as;
ΔK.E = ¹/₂m [ (2V₁²) - ( V₁²) ]
ΔK.E = ¹/₂m[ (4V₁²) - ( V₁²) ]
ΔK.E = ¹/₂mV₁²[4 - 1]
ΔK.E = 3 (¹/₂mV₁² )
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I’ve been struggling with this question, help!
The masses of the two objects MA and MB in the binary system are 4 Mo respectively.
How can the masses of the binary systems be calculated?The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.
Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:
MA + MB = 8 Mo
We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:
d(A to B) / d(Binary System) = 1/3
We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:
d(A to B) + d(B to binary system) = d(Binary system)
Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):
d(A to B) + 1/3d = d(Binary system)
3d(A to B) + d = 3d(Binary system)
Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:
3d(A to B) + d = 3(d(A to B) + d(B to binary system))
2d(A to B) = 2d(B to binary system)
d(A to B) / d(B to binary system) = 1
So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:
MA = MB
Substituting this into the first equation, we get:
2MA = 8 Mo
MA = MB = 4 Mo
Therefore, the mass of each object is 4 Mo.
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How far back into the universe are we able to see? Explain.
Answer:
About 46 billion light years Because space expands so what we didn’t see before is what we could see now. An example could be how everyone thought Pluto was a regular sized planet but once you get a look at the bigger picture and compare it to other thing in space we now know Pluto is a dwarf planet.
suppose the plates of a parallel-plate capacitor move closer together by an infinitesimal distance , as a result of their mutual attraction. (a) use eq. 2.52 to express the work done by electrostatic forces, in terms of the field e, and the area of the plates, a. (b) use eq. 2.46 to express the energy lost by the field in this process.
As a result, the energy lost by the field in this operation equals ε_0 * A * dd^2 / d.
What is electrostatic force?Non-contact forces, such as electrostatic forces, pull or push on things without touching them. When certain materials are rubbed together, a phenomenon known as 'charge' is transferred from one surface to the other. Charged items pull on uncharged things and can push or pull on charged objects.
Here,
(a) The work done by electrostatic forces when the plates move closer together by an infinitesimal distance is given by:
W = - dQV = - dQ * (V2 - V1)
where dQ is the change in charge on the plates, and V is the voltage across the plates. The voltage can be related to the electric field between the plates and the plate separation by:
V = Ed
where d is the plate separation. Substituting this into the equation for work, we get:
W = - dQ * (Ed2 - Ed1) = - dQ * E * dd
Since the change in charge on the plates is proportional to the change in separation, we can write:
dQ = C * dd
where C is the capacitance of the parallel-plate capacitor. Substituting this into the expression for work, we get:
W = - C * E * dd^2
Finally, using the relationship between the electric field and capacitance for a parallel-plate capacitor:
E = ε_0 * A / d
where ε_0 is the vacuum permittivity and A is the area of the plates, we can rewrite the expression for work as:
W = - C * ε_0 * A * dd^2 / d^2 = - ε_0 * A * dd^2 / d
(b) The energy lost by the field in this process can be calculated as the work done by the electric forces, which is given by:
ΔU = -W = ε_0 * A * dd^2 / d
So, the energy lost by the field in this process is equal to ε_0 * A * dd^2 / d.
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The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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Atoms of which two elements could combine with atoms of carbon (C) to
form covalent bonds?
A. S
B. Na
C. N
D. K
E. Ca
Answer:
Correct answer is letter E.Ca
SOMEONE PLEASE HELP ASAP?!
A neutron and a proton combine to form a nucleus. How does the sum of the masses of the nucleons that make up the nucleus compare with the mass of the nucleus itself?
The nucleons have less mass, because matter is converted into binding energy. Option D is correct.
During the process of combining a neutron and a proton to form a nucleus, a small amount of mass is converted into binding energy. This is due to the strong nuclear force that holds the nucleus together. The mass of the nucleus is slightly less than the sum of the masses of the individual nucleons, and the difference in mass is referred to as the mass defect.
This mass defect is related to the binding energy of the nucleus through Einstein's famous equation E=mc², where E is energy, m is mass, and c is the speed of light. The mass defect represents the amount of mass that is converted into binding energy to hold the nucleus together. Option D is correct.
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A scale measures the weight of a light object to be 11.000 lbs ± 0.034 lbs. what is the uncertainty if this same scale is use to measure an object that weights 78.000 lbs? Assume that the percent uncertainty of the scale remains constant
1)0.034lbs
2)0.044lbs
3)0.310lbs
4)0.240Ibls
The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.
What is uncertainty in measurement?This is the error associated in an attempt measure the object accurately.The percent uncertainty in measuring the light weight object is calculated as follows;
\(= \frac{0.034}{11} \times 100\%\\\\= 0.309\%\)
The uncertainty of the heavy object if the scale remains constant is calculated as follows;
\(= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs\)
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You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 2.1 m/s. The
ball has ____
energy. Calculate it.
Answer:
4.6 Joules
Explanation:
K=1/2*MV^2
1/2 * 2.1kg * 2.1^2m/s
==4.6305 Joules
simplified to 4.6 Joules
7. Apply Concepts: suppose the dog walked at a constant speed the whole way. What
would the graph look like then? Explain.
If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.
What is the speed about?A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.
If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.
In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.
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3. Observe: An organelle is a cell structure that performs a specific function. Observe the samples below under the highest magnification. Click the Show labels checkbox to label the organelles. List the organelles and approximate size of the cells in each sample.
Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.
Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.
The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.
In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.
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The table shows the relationship between the masses of two objects, the distance between the two objects, and the gravitational force between the objects. A 4-column table with 5 rows. The first column labeled Mass of Object 1 (kilograms) has entries 1, 2, 2, 3, 9. The second column labeled Mass of Object 2 (kilograms) has entries 1, 1, 2, 3, 3. The third column labeled Distance between Objects 1 and 2 (meters) has entries 1, 1, 2, 1, 3. The fourth column labeled Gravitational Force Objects 1 and 2 (Newtons) has entries 1 G, 2 G, 1 G, 9 G, 3G. Which conclusion is supported by the data in the table? An increase in the mass of an object causes the same decrease in the gravitational force. An increase in the distance between the objects causes the same decrease in the gravitational force. An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass. An increase in the mass causes a greater change in the gravitational force than the same increase in the distance between the objects. Brainlyest for correct answer!
Answer:
C
Explanation:
edge 2020... Using elimination it's the only one that makes sense.
The statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.
What is gravitational force?The gravitational force is a force that attracts all mass-bearing objects. The gravitational force is referred to as attractive because it always strives to pull masses together rather than pushing them apart.
As we know, the gravitational force is given by:
\(\rm F = \dfrac{Gm_1m_2}{r^2}\)
Where, G is the gravitational constant.
m1 and m2 are masses.
r is the distance between the masses.
From the data given in the table, shows that:
The gravitational force is indirectly proportional to the square of the distance.
Thus, the statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.
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A sprinter with a mass of 70 kg accelerates at a rate of 5 m/s2. What force is the sprinter exerting?
Answer:
The force exerted by the sprinter can be calculated using Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration:
F = m * a
where:
F is the force
m is the mass of the object (70 kg)
a is the acceleration (5 m/s^2)
Plugging in the values, we get:
F = 70 kg * 5 m/s^2
F = 350 N
So, the sprinter is exerting a force of 350 N. This is the force that the sprinter's legs are applying to the ground, propelling them forward and producing the acceleration.
Three equal positive charges 'q' are at the corners of an equilateral triangle of side 'a'.
a. Assuming that the three charges together create an electric field, find the location of a point other than the obvious one where the electric field is zero.
b. What is the magnitude and direction of the electric field at the top corner due to the two charges at the base?
(a) The location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.
(b) The magnitude and direction of the electric field at the top corner due to the two charges at the base is 1.732 kq/a².
Position where the electric field is zero
The electric field is zero at the center of the equilateral triangle whose magnitude is equal to √3a/6.
Electric field at top corner due to two charges at the baseE = E₁ + E₂
where;
E₁ is electric field at the left base cornerE₂ is electric field at the right base cornerE = kq/a²[(cos 60i + sin 60j) + (-cos 60i + sin 60j)]
E = kq/a²[2(sin 60j)] = 1.732 kq/a²
Thus, the location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.
The magnitude and direction of the electric field at the top corner due to the two charges at the base is 1.732 kq/a².
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why do astronauts weigh less on the moon than on earth
Answer:
Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.
Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.
(round to 3 significant figures pls) A block of iron at 415 degrees C is put into a 0.625 kg tub of water at 15.0 degrees C. They come to equilibrium at 100 degrees C, and 0.144 kg of the water boils off to steam. What was the mass of the iron block?
Temperature of iron (Ti) = 415 °C Temperature of water (Tw) = 15.0 °CTemperature at equilibrium (Te) = 100 °CMass of water (m) = 0.625 kgMass of steam evaporated (ms) = 0.144 kgHeat lost by iron (Q1) = Heat gained by water (Q2) + Heat required to evaporate steam .
Heat lost by iron = (mass of iron (m) x specific heat capacity of iron (c) x change in temperature of iron (ΔT1))Heat gained by water = (mass of water (m) x specific heat capacity of water (c) x change in temperature of water (ΔT2))Heat required to evaporate steam = (mass of steam (ms) x specific latent heat of vaporization of water (L))Now, using the above formula we can calculate the mass of the iron block as:
Q3m x c x ΔT1 = m x c x ΔT2 + ms x L
Let's calculate the value of Q1 first.
Q1 = m x c x ΔT1m = Q1 / (c x ΔT1)
We know that
c = 450 J/kg °C and ΔT1 = Ti - Te = 415 - 100 = 315°CQ1 = m x c x ΔT1= m x 450 J/kg
°C x 315°C= 141750 m Jm = Q1 / (c x ΔT1)= 141750 / (450 x 315)= 1.002 kg
Now, let's calculate the value of Q3.Q3 = ms x L= 0.144 kg x 2.26 x 10^6 J/kg= 325440 J
Now, let's calculate the value of Q2
.Q2 = m x c x ΔT2m = (Q2 + Q3) / (c x ΔT2)
We know that ΔT2 = Te - Tw = 100 - 15 = 85°CQ2 = m x c x ΔT2= 0.625 kg x 4186 J/kg °C x 85°C= 276981.25 JNow, let's calculate the mass of the iron block.m =
(Q2 + Q3) / (c x ΔT2)= (276981.25 + 325440) / (450 x 85)= 1.003 kg
Hence, the mass of the iron block is 1.003 kg rounded off to 3 significant figures.
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In what way dose ocean water move globally
Answer: Letter A. Along cold water currents from the poles to the equator. Apex
Explanation:
Explanation:
The great ocean conveyor moves water around the globe. ... There is constant motion in the ocean in the form of a global ocean conveyor belt. This motion is caused by a combination of thermohaline currents (thermo = temperature; haline = salinity) in the deep ocean and wind-driven currents on the surface.
An airplane accelerates down a runway at 4.3 m/s2 for 48 s until it finally lifts off the ground. Determine the distance traveled before takeoff.
I
Answer:
x=4953.6m
Explanation:
used formula x=xo+vot+1/2at^2
a positively-charged particle ( q) is at rest in the plane between two fixed bar magnets, as shown. the magnet on the left is three times as strong as the magnet on the right. which choice below best represents the resultant magnetic force exerted by the magnets on the charge?
The resultant force exerted by the magnets on the charge will be zero.
According to the Lorentz force equation, only moving charges experience magnetic forces. Therefore, a charge at rest experiences no force and does not move. Only moving charges can experience a magnetic force, so the force on a stationary charge is zero. The magnetic force is always perpendicular to the velocity of the charged particles, so the particles move in a circular motion. The positive charges above move vertically through the magnetic field and are deflected. The correct rule below predicts the direction in which positive charges are deflected. A similar left-hand rule predicts the deflection of negative charges.
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