Answer:
This question appears incomplete
Explanation:
This question appears incomplete. However, the type of observation done by Silvia at this football game is Qualitative observation. This is because she determined who wants the home team to win based on how they were dressed.
Qualitative observation describes observations that can be characerized based on our senses (sight, smell, feel e.t.c) and cannot be counted or numbered. Silvia knew the sides not by the numbers but by there visible dressing (sight).
Four model rockets are launched in a field. The mass of each rocket and the net force acting on it when it launches are given in the table below. (1. 4.25kg 120N) (2. 3.25kg 120N) (3. 5.50kg 120N) (4. 4.50kg 120N), Which rocket has the lowest acceleration?
The correct answer is option 3 i.e., 5.50 Kg and 120 N had lowest acceleration among all options given.
What connection exists between force and mass of acceleration?
Mass times acceleration, or F=m x a, equals force. This means that in order to move an object at the same speed as an object with smaller mass, a stronger force is required. Newton's Second Law of Motion is this.
Acceleration = Force / Mass
Given, as per question in all the 4 options Force = 120 N same for all
So as per formula if we assume Force is constant
Then, if mass is increased then acceleration will be lowest as both are inversely proportional.
1. Acceleration= 120 / 4.25 = 28.23 m/s²
2. Acceleration= 120 / 3.25 = 34.28 m/s²
3. Acceleration= 120 / 5.50 = 21.81 m/s²
4. Acceleration= 120 / 4.50 = 26.66 m/s²
Hence answer is option number 3.
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A car moves with a constant speed of 220 km/h. Express this speed in m/s and calculate the distance covered in 20 seconds
Hello..!
We first apply the data to the problem.
Data:
V = 220km/hT = 20sD = ?Now, we convert the "km/h" to "m/s".
Conversion:
220km/h • (1000m/1km) • (1h/3600s)V = 61.1m/sThen, we apply the formula that is.
Formula:
D = V • TFinally we develop the problem.
Developing:
D = (61.1m/s) • (20s)D = 1222mThe distance covered is 1222 meters.
Answer:
Formula:
D = v • tResolver:D = (61.1m/s) • (20s)D = 1222mHope this helped
A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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Which of these has 28 protons and 26 electrons?
O Fe
O Fe2+
Ο Ni
O Ni2+
Answer:
here, if you have an iron which has 28 protons and 26 electrons, and we have to find the charge on the iron, the element and the symbol of the iron. So For 28 protons charge is 28 e. And for 26 electrons, charge will be -26 E. So total charges 28 E minus 26 E. Equal to two E. On I N S, plus two. No, we have to find the element. So atomic number is equal to Number of protons, which is 28, and this is atomic number four nickels. So the element is nickel and we have to find the symbol of iron. So the iron has to positive child. So the symbol will be and I took place So this completes the solution. Thank you.
Explanation:
Can someone please help!!!
Answer:
W = F • ∆x
so for work to be done, a force and displacement has to be in the same direction. (Ex: a box is being pushed forward and it's also moving forward.)
Why do the parts of the blades
farthest away from where
they connect to the helicopter
spin the fastest?
A. They contain much more mass.
B. They have to travel a greater distance in
the same amount of time.
C. They are made of a material that is more
dense than the inner part of the blade.
Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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A metal cube has a surface area of
64x10^-4 m2. Calculate the quantity of
heat flow through the cube in 600s
with -1x10^-3K m' temperature
gradient.
Answer:
A metal cube has a surface area of
64x10^-4 m2. Calculate the quantity of
heat flow through the cube in 600s
with -1x10^-3K m' temperature
gradient.
Question 8 of 20
What identifies your skills and interests to help you plan out your career
goals?
A. A self-examination
B. A self-assessment
O C. A self-help book
O D. A bit of self-knowledge
Answer:
c
Explanation: because i took it and got it correct
what is the electric force between 2 forces .0042c and -0.0050c and are .0030m apart
To calculate the electric force between two charges, we can use Coulomb's law:
F = k * |q1 * q2| / r^2
where F is the electric force, k is the electrostatic constant (k ≈ 8.99 × 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
In this case, q1 = 0.0042 C, q2 = -0.0050 C, and r = 0.0030 m.
Substituting these values into the equation:
F = (8.99 × 10^9 N m^2/C^2) * |0.0042 C * (-0.0050 C)| / (0.0030 m)^2
F = (8.99 × 10^9 N m^2/C^2) * 0.000021 C^2 / 0.000009 m^2
F ≈ 1977.78 N
Therefore, the electric force between the two charges is approximately 1977.78 Newtons.
A textbook of mass 2.10 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.100 m , to a hanging book with mass 3.10 kg . The system is released from rest, and the books are observed to move a distance 1.29 m over a time interval of 0.850 s . Part A What is the tension in the part of the cord attached to the textbook
Answer:
the tension in the part of the cord attached to the textbook is 7.4989 N
Explanation:
Given the data in the question;
As illustrated in the image below;
first we determine the value of the acceleration,
along vertical direction; we use the second equation of motion;
y = ut + \(\frac{1}{2}\)a\(_y\)t²
we substitute;
0 m/s for u, 1.29 m for y, 0.850 s for t,
1.29 = 0×0.850 + \(\frac{1}{2}\)×a\(_y\)×(0.850)²
1.29 = 0.36125a\(_y\)
a\(_y\) = 1.29 / 0.36125
a\(_y\) = 3.5709 m/s²
Now when the text book is moving with acceleration , the dynamic equation will be;
T₁ = m₁a\(_y\)
where m₁ is the mass of the text book ( 2.10 kg )
a\(_y\) is the vertical acceleration ( 3.5709 m/s² )
so we substitute
T₁ = 2.10 × 3.5709
T₁ = 7.4989 N
Therefore, the tension in the part of the cord attached to the textbook is 7.4989 N
How fast is a 30 kg child runnning if her kinetic energy is 500 J?
\(\displaystyle v = 5.7735 \ m/s\)
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Physics
SI Units
Speed is m/s (meters per second)Energy is J (Joules), equal to 1 N/m (newton per meter)Mass is kg (kilograms)Energy
Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2} mv^2\)
KE is Kinetic Energy (in J)m is mass (in kg)v is velocity (in m/s)Explanation:Step 1: Define
Mass m = 30 kg
Kinetic Energy KE = 500 J
Step 2: Solve for v
Substitute [KEF]: \(\displaystyle 500 = \frac{1}{2}(30)v^2\)Multiply: \(\displaystyle 500 = 15v^2\)Isolate v term: \(\displaystyle \frac{100}{3} = v^2\) Isolate v: \(\displaystyle \frac{10\sqrt{3} }{3} = v\)Rewrite: \(\displaystyle v = \frac{10\sqrt{3} }{3} \ m/s\)Evaluate: \(\displaystyle v = 5.7735 \ m/s\)How is the biopsychological approach different from the medical model?
Answer:
Similar to a lock and key, the biomedical model seeks to find a solution that fits the respective problem. Biopsychosocial. The biopsychosocial model is aptly named because of its three essential components: biological, psychological and social ideologies. As a result, the concept of health is viewed as a balance between these three sectors.
Explanation:
hope it helps
have a great day
:)
I need the answer asap everyone have a good day bye
Im pretty sure its A cuz is closer to the earth.
Three 70-kg deer are standing on a flat 200-kg rock that is on an ice-covered pond. A gunshot goes off and the deer scatter, with deer A running at (15m/s)iˆ+(5.0m/s)jˆ , deer B running at (−12m/s)iˆ+(8.0m/s)jˆ , and deer C running at (1.2m/s)iˆ−(18.0m/s)jˆ . What is the velocity of the rock on which they were standing?
Explanation:
Add all of the velocities together....then the rock will be moving in the OPPOSITE direction according to conservation of momentum
(15 + -12 + 1.2) m/s i = -1.8 m/s i
(5 + 8 + -18 ) m/s j = -5 m/s j These are the resultant force components on 210 kg of deer meat
-1.8 (210) i - 5 (210) j = 200 x i + 200 y j m/s
results in rock velocities: 1.89 i m/s + 5.25 j m/s
Please tell me if this is incorrect and I will re-evaluate ......
5. A single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen. The 5th minimum occurs at 7.00° away from the central maximum. At what angle does the 18th minimum occur? A) 26.0° B) 1.94° C) 5.05° D) 0.44°
For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle is mathematically given as
theta=25.3
Option A is correct
What angle does the 18th minimum occur?Generally, the equation for the the angle is mathematically given as
\(\theta=n(\lambda/d)\)
Therefore
\(\theta 1/ \theta 2=n1(\lambda/d)/ n2(\lambda/d)\)
In conclusion
theta/7=16/5
theta=10*7/5
theta=25.3
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WILL GIVE BRAINLESS IF U ANSER ALL CORECTLY
1 What does wind do as it goes up and over a mountain range?
2 What is the climate on the windward side of a mountain range like?
3 What is the climate on the leeward side of a mountain like?
4 What are rain shadow deserts?
5 What are the characteristics (wind, precipitation, vegetation) seen on the windward side of the Sierra Nevada Mountains?
6 What are the characteristics (wind, precipitation, vegetation) seen on the leeward side of the Sierra Nevada Mountains?
Answer:
1-As winds rise up the windward side of a mountain range, the air cools and precipitation falls.
2-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls.
3-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks.
4-Rain shadow deserts are formed because tall mountain ranges prevent moisture-rich clouds from reaching areas on the lee, or protected side, of the range.
5-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.
6-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.
Explanation:
#6 and 5 are the same
100 Points !!!!!!!! I WILL GIVE BRAINLIEST
Answer: 1. 0.25 m/s squared
2. A = 0.4 m/s^2
3.=20kg. I did this before.
Explanation:
Answer:
Answer: 1. 0.25 m/s squared
2. A = 0.4 m/s^2
3.=20kg.
Explanation:
brainliest? ill answer more of your recent questions!!
Most of the bending of light in the eye is done at the air-cornea interface. By what angle (θcornea) is the beam of light shown in Figure deviated as it passes from air to the cornea if the incident angle is θi = 23.6°? The refractive index of air is nair = 1.00, the refractive index of the cornea is ncornea = 1.38. Explain why θcornea< θi?
The angle (θcornea) when light passes from air to cornea is 16.86°
What is Snell's law?It states that the ratio of sine of angle of incidence and angle of refraction is equal to the refractive index of second medium to the first medium.
sini/sinr =n₂ / n₁
Most of the bending of light in the eye is done at the air-cornea interface. The beam of light deviated as it passes from air to the cornea if the incident angle is θi = 23.6°.
Given the angle of incidence i = 23.6°, refractive index of air n₁ =1, refractive index of cornea n₂ = 1.38, then the angle of refraction at cornea is
sinr = sini x (n₁/n₂)
Plug the values, we get
sinr = sin23.6 x (1/1.38)
sinr = 16.86°
The angle of refraction is less than angle of incidence due to refraction.
Thus, the angle (θcornea) when light passes from air to cornea is 16.86°
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How do bumper cars at an amusement pack demonstrate Newton’s third law?
Answer:
If two bumper cars collide with a certain force, then they will move away from each other in opposite directions with the same force. This demonstrates Newton's third law, which states that for every action, there is an equal and opposite reaction.
Explanation:
Most people can throw a baseball farther than a bowling ball, and most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball. Explain these two situations in terms of
Newton’s First Law of Motion
Newton’s Second Law of Motion
Based on Newton's first and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
What is Newton's first law of motion?
Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.
Newton's first law of motion is also called law of inertia because it depends on mass of the object.
An object with a greater mass will require greater force to be stopped or get moving.
Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.
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An experiment is set up to test the angular resolution of an optical device when red light (wavelength ????r ) shines on an aperture of diameter D . Which aperture diameter gives the best resolution? D=(1/2)????r D=????r D=2????r
Explanation:
As per Rayleigh criterion, the angular resolution is given as follows:
\(\theta=\frac{1.22 \lambda}{D}\)
From this expression larger the size of aperture, smaller will be the value of angular resolution and hence, better will be the device i.e. precision for distinguishing two points at very high angular difference is higher.
A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is ___ Newton.
A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is 298.44__ Newton.
The problem describes a Tesla that is stuck in the mud and needs to be pulled out using a rope. the guy pulls a force F⊥ of 300N and that the angle between the rope and the horizontal plane is θ = 4.2°. The goal is to find the tension force T exerted by the rope.To solve for T, we'll need to use trigonometry. We can break the force vector into its horizontal and vertical components as follows:
Fx = F⊥ cosθ and Fy = F⊥ sinθ.
Since the rope is pulling the Tesla horizontally, the horizontal component of the force will be the tension force T. So we have:
T = Fx = F⊥ cosθ = (300 N) cos(4.2°) ≈ 298.44 N
Taking the cosine of the angle is necessary since it's the adjacent side that we're interested in, which is the horizontal component of the force. Therefore, the tension force exerted by the rope is approximately 298.44 N.
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A car accelerates to a speed of 55 m/s within the span of 8 seconds. If its acceleration
was 4 m/s2, what was its initial velocity? Show all work and units for full credit.
The initial velocity of a car that accelerates to a speed of 55 m/s within the span of 8 seconds is 23m/s.
How to calculate initial velocity?The initial velocity of a moving body can be calculated using the following formula:
a = v - u/t
Where;
a = acceleration (m/s²)v = final velocity (m/s)u = initial velocity (m/s?t = time (seconds)According to this question, a car accelerates to a speed of 55 m/s within the span of 8 seconds. If its acceleration was 4 m/s², the initial velocity is calculated as follows:
4 = 55 - u/8
32 = 55 - u
u = 55 - 32
u = 23m/s
Therefore, the initial velocity of a car that accelerates to a speed of 55 m/s within the span of 8 seconds is 23m/s.
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a. If the frequency of light is increased above the threshold frequency, the
energy of the electrons emitted will _________________.
b. If the frequency of light is decreased to below the threshold frequency, the
rate at which electrons are emitted will _______________.
c. If the intensity of light is decreased, the energy of the electrons emitted will ____________________.
d. If the intensity of light is decreased, the rate at which electrons are emitted will ________________.
Answer:
a. If the frequency of light is increased above the threshold frequency, the energy of the electrons emitted will increase.
b. If the frequency of light is decreased to below the threshold frequency, the rate at which electrons are emitted will decrease.
c. If the intensity of light is decreased, the energy of the electrons emitted will remain the same, but fewer electrons will be emitted.
d. If the intensity of light is decreased, the rate at which electrons are emitted will decrease.
An object begins at position x = 0 and moves one-dimensionally along the x-axis witļi a velocity v
expressed as a function of time t according to the graph above. At what time does the object pass
through x = 0 again?
Answer:
The answer is "between 20 s and 30 s".
Explanation:
Calculating the value of positive displacement:
\(\ (x_{+ve}) = \frac{1}{2} \times 15 \times 20 \\\\\)
\(= \frac{1}{2} \times 300 \\\\= 150 \\\\\)
Calculating the value of negative displacement upon the time t:
\((x_{-ve}) = \frac{1}{2} \times 5 \times 20- 20(t-20) \\\\\)
\(= \frac{1}{2} \times 100- 20t+ 400 \\\\= 50- 20t+ 400 \\\\\)
\(\to X= X_{+ve} + X_{-ve} \\\\\)
\(\to 150 - 50 -20t+400 =0\\\\\to 100 -20t+400 =0 \\\\\to 500 -20t =0\\\\\to 20t =500 \\\\\to t=\frac{500}{20}\\\\\to t=\frac{50}{2}\\\\\to t= 25\)
That's why its value lie in "between 20 s and 30 s".
PLEASE HELP
Question 4 of 10
Which statement is true of a piece of ice at 0°C that is put into a freezer at
-18°C?
A. The ice cube will remain unchanged.
B. The ice cube will gain mass from the surroundings.
C. The ice cube will lose thermal energy to the surroundings.
D. The ice cube will gain thermal energy from the surroundings.
The ice cube will lose thermal energy to the surroundings. The given statement is true of a piece of ice at 0°C that is put into a freezer at -18°C. Thus, the correct option is C.
What is thermal energy?The term thermal energy is used loosely in various different contexts in physics and engineering mainly. Thermal energy can refer to several different well-defined physical concepts. These concepts include the internal energy or the enthalpy of a body of matter and the radiation energy, the heat energy, which is defined as a type of energy transfer and it is the characteristic energy of a degree of freedom.
If a piece of ice at 0°C that is put into a freezer at -18°C then it can be said that the ice cube will lose thermal energy to the surroundings.
Therefore, the correct option is C.
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Work is done on a wooden crate by pushing it across a floor. The work done is equal to the force applied parallel to the floor multiplied by the
A. force of friction
B. distance moved
C. mass of the crate
D. crate's direction
The work done is equal to the force applied parallel to the floor multiplied by the distance moves. Hence, option B is correct.
When a wooden crate is pushed across a floor, the work done on it is given by the product of the force applied parallel to the floor and the distance moved by the crate.
This is because work is defined as the product of force and displacement in the direction of the force, which in this case is the distance moved by the crate. The force of friction and the mass of the crate are not relevant to the calculation of work done in this scenario
It is important to understand the concept of work and the factors that influence it, as it is a fundamental concept in physics and is used in many real-world applications.
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A body of mass 5 kg is moved by a horizontal force of 0.5 N on a smooth frictionless table for 20 seconds. Calculate the change in kinetic energy.
A. 5 J
B. 20 J
C. 10 J
D. 30 J
Answer: 10 J
Explanation:
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a car is moving at 12 m/s and has a mass of 600 kg what is the. kinetic energy of the car?
Answer:
43200 J
Explanation:
(1/2(mass)) (speed)^2