Simplify: 3/4y - 2/4y + 7 = 2/4y - 1. Show your work.
help please

Answer:answer what

Step-by-step explanation:

Answer:

\(\left( 3-2i\right) \left( 3+2i\right) =13\)

Step-by-step explanation:

Note :

i² = −1

(a - b)(a + b) = a² - b²

________________

\(\left( 3-2i\right) \left( 3+2i\right) =3^{2} - (2i)^2\)

                         \(=9 - (2)^2\times i^2\)

                         \(=9 - 4(i)^2\)

                         \(=9-4\times(-1)\)

                         \(=9+4\)

                         \(=13\)

Answer: (3 – 2i)(3 2i)=13

Step-by-step explanation:

edge2020

As per the given triangle RT = AS, RS = AT, the statement < TSA = < STR is proved.

Given two triangles, if the length of one side is proportional to the length of a corresponding side in another triangle, then the two triangles are similar.

This relationship is expressed as "RT = AS," where R and S are corresponding vertices in the two triangles and T is the point where the two sides intersect.

To prove that < TSA = < STR, we need to show that corresponding angles in the two triangles are equal.

This is because corresponding angles in similar triangles are equal, and this is one of the ways to prove that two triangles are similar.

To prove that RT = AS and RS = AT, we can use the function of proportionality. This function states that if two sides are proportional, then the ratio of corresponding lengths will be equal.

Therefore, if RT = AS and RS = AT, then we can conclude that < TSA = < STR and the two triangles are similar.

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Answer:

1,300 lb.

Step-by-step explanation:

V = 9 × 12 × 14.5 = 1566 ft³

1,566 × 0.83 = 1,299.78 ≈ 1,300 lb.

The match can be scheduled in 900 different ways with the help of permutations and combinations.

Given,

Number of players from each school = 3.

Let, the players of the first school be A, B, and C.

Let, the players of the second school be X, Y, and Z.

The problem can be solved in two cases,

Case-1

According to the question,

Each player from the first school has to play twice with each player from the second school.

We can organize the schedule into six different rounds, i.e.,

Round 1 : AX BY CZ

Round 2 : AX BZ CY

Round 3 : AY BX CZ

Round 4 : AY BZ CX

Round 5 : AZ BX CY

Round 6 : AZ BY CX

In other words, we have to permutate these 6 rounds, i.e., 6! = 720 ways.

Case-2

Given,

Three rounds are played simultaneously in each round.

(a)

Round 1 : AX BZ CY

Round 2 : AX BZ CY

Round 3 : AY BX CZ

Round 4 : AY BX CZ

Round 5 : AZ BY CX

Round 6 : AZ BY CX

(b)

Round 1 : AX BY CZ

Round 2 : AX BY CZ

Round 3 : AY BZ CX

Round 4 : AY BZ CX

Round 5 : AZ BX CY

Round 6 : AZ BX CY

The total number of permutations for Case-2 will be twice of 6! / (2! 2! 2!), which is equal to 90+ 90 = 180.

Thus, the total number of ways in which the match can be scheduled is 720 + 180 = 900.

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(4, 1) is the solution for the given inequalities

Given,

The system of inequalities;

3x + y ≤ 14

3x + 5y < 19

We have to find that (4, 1) is a solution to the given system of inequalities;

So,

(x, y) = (4, 1)

Then,

Substitute the values of x and y in the equation;

3x + y ≤ 14

3 x 4 + 1 ≤ 14

12 + 1 ≤ 14

13 ≤ 14

Next,

3x + 5y < 19

3 x 4 + 5 x 1 < 19

12 + 5 < 19

17 < 19

Here,

(4, 1) is the solution for the given inequalities

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Hey there!

Assuming:

(3^2 * 4^2)^5

If so,

(3^2 * 4^2)^5

= (3 * 3 * 4 * 4)^5

= (9 * 16)^5

= (144)^5

= 144^5

= 144 * 144 * 144 * 144 * 144

= 20,736 * 20,736 * 144

= 429,981,696 * 144

= 61,917,364,224

Therefore, your answer should be:

61,917,364,224

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

In summary, given a simple dataset with 30 points, the following steps were performed: (a) OLS estimation was used to calculate the coefficients β^0 and β^1 for the regression of Y on X.

(b) the predicted value of Y was calculated for each observation; (c) the residuals were calculated for each observation; (d) the Explained Sum of Squares (ESS), Total Sum of Squares (TSS), and Residual Sum of Squares (RSS) were calculated separately; (e) the coefficient of determination R^2 was calculated; (f) the predicted value of Y was determined when X equals the last digit of the CUNY ID plus one; and (g) the interpretation of β^0 and β^1 was provided.

In detail, to calculate the OLS estimates of coefficients β^0 and β^1, a regression model of Y on X was fitted using the given dataset. β^0 represents the intercept term, which indicates the value of Y when X is zero. β^1 represents the slope of the regression line, indicating the change in Y corresponding to a unit change in X.

The predicted value of Y for each observation was obtained by plugging the corresponding X value into the regression equation. The residuals were then calculated as the difference between the observed Y values and the predicted Y values. ESS represents the sum of squared differences between the predicted Y values and the mean of Y, indicating the variation explained by the regression model.

TSS represents the total sum of squared differences between the observed Y values and the mean of Y, representing the total variation in Y. RSS represents the sum of squared residuals, indicating the unexplained variation in Y by the regression model. R^2, also known as the coefficient of determination, was calculated as ESS divided by TSS, indicating the proportion of total variation in Y explained by the regression model. Finally, the predicted value of Y was determined when X equals the last digit of the CUNY ID plus one, allowing for an estimation of Y based on the given information.

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The hypothesis test to determine if two teams have significantly different weights can be formulated as follows:

H0: The weights of team 1 (Team B) and team 2 (Team A) are not significantly different.

H1: The weights of team 1 (Team B) and team 2 (Team A) are significantly different.

To conduct this hypothesis test, we can use a two-sample t-test. This test allows us to compare the means of two independent samples, in this case, the weights of the two teams. The steps to solve this problem are as follows:

1. Collect the data: Obtain the weights of the players from both Team A and Team B.

2. Set up the hypotheses: State the null hypothesis (H0) and the alternative hypothesis (H1) as mentioned earlier.

3. Choose the significance level: Determine the desired level of significance (e.g., α = 0.05) to assess the strength of evidence against the null hypothesis.

4. Calculate the test statistic: Use the appropriate formula to calculate the t-test statistic, which measures the difference between the sample means relative to the variation within the samples.

5. Determine the critical region: Determine the critical value or the rejection region based on the chosen significance level and degrees of freedom.

6. Make a decision: Compare the test statistic to the critical value or rejection region. If the test statistic falls within the critical region, reject the null hypothesis. If it falls outside the critical region, fail to reject the null hypothesis.

7. Draw conclusions: Based on the decision made in the previous step, draw conclusions about the weights of the two teams. If the null hypothesis is rejected, it suggests that the weights of Team A and Team B are significantly different. If the null hypothesis is not rejected, there is not enough evidence to conclude a significant difference in weights between the two teams.

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Answer:

The difference between the two values is -9

Answer:

12 and 30

Step-by-step explanation:

so they could be 2×2×3 = 12 and 2×3×5 = 30

Answer:

x>13 (C)

Step-by-step explanation:

1) simplify -> 2x+7>33

2) subtract 7 from both sides -> 2x+7-7>33-7 = 2x>26

3) divide both sides by 2 -> 2x/2>26/2

x>13

Answer:

Step-by-step explanation:

x + 6 = 0

x = -6

-x + 1 = 0

-x = -1

x = 1

x = -6, 1

True. A sampling distribution is a probability distribution that describes the behavior of a statistic across repeated samples drawn from a population.

It is used to make inferences about a population parameter based on the sample statistics.

The key feature of a sampling distribution is that it is formed by taking repeated samples from a population and calculating a statistic (such as the mean or standard deviation) for each sample. The distribution of these statistics is then studied to determine the properties of the statistic under repeated sampling.

For example, if we repeatedly sample from a normal population and calculate the mean of each sample, the distribution of these means will follow a normal distribution. This distribution is known as the sampling distribution of the mean. The properties of this distribution can be used to estimate the population mean and to test hypotheses about the population mean based on sample means.

Overall, understanding sampling distributions is important in statistics, as they allow us to make inferences about population parameters based on samples, which is often more practical and feasible than trying to study entire populations.

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Answer:

B 9

Step-by-step explanation:

We have 6 green socks, 18 purple socks, and 12 orange socks.

Adding more purple sock means 6 green socks, 18+x purple socks, and 12 orange socks.

We have a  probability of 60% of getting a purple sock.

P( purple) = number of purple socks / total

.60 = (18+x) / (6+18+x+12)

.60 = (18+x) / (36+x)

Multiply each side by 36+x

21.6 +.6x = 18+x

Subtract 18 from each side

3.6x +.6x = x

Subtract .6x from each side

3.6x = .4x

Divide each side by .4

9 =x

Jamal added 9 purple socks

Answer:

\(8x - 5 + 2x \\ 10x - 5 \\When x=-1 ; \\ 10( - 1) - 5 \\ - 10 - 5 = - 15\)

I hope I helped you^_^

a.  The probability that the driver is incorrectly classified as being over the limit is 0.03

b. The probability that th driver is correctly classified as being over limit  is 0.10

c. The probability that the driver gives a breathalyser test reading that is over the limit is 0.16

d. The probability that the driver is under the legal limit, given the breathalyser reading is below the limit is 0.9779

Part a) The probability that the driver is incorrectly classified as being over the limit can be calculated as the probability of a false positive. This is given by the percentage of drivers who have not consumed an excess of alcohol but still give a reading above the legal limit, which is 3%.

Therefore, the probability is 0.03 (or 0.03 in decimal form) to four decimal places.

Part b) The probability that the driver is correctly classified as being over the limit is given by the percentage of drivers who are actually above the legal limit and give a reading above the limit. This is given as 10%.

Therefore, the probability is 0.10 (or 0.10 in decimal form) to four decimal places.

Part c) The probability that the driver gives a breathalyser test reading that is over the limit can be calculated as the sum of the probabilities of correctly and incorrectly classified drivers being over the limit. This is given by the percentage of drivers above the legal limit (13%) plus the percentage of drivers not above the limit but incorrectly classified as over the limit (3%).

Therefore, the probability is 0.13 + 0.03 = 0.16 (or 0.16 in decimal form) to four decimal places.

Part d) The probability that the driver is under the legal limit, given the breathalyser reading is below the limit, can be calculated using Bayes' theorem. It is the probability of the driver being below the limit and giving a reading below the limit divided by the probability of giving a reading below the limit.

The probability of the driver being below the limit and giving a reading below the limit is given by the percentage of drivers below the limit (87%) multiplied by the probability of giving a reading below the limit given that they are below the limit (100%). This gives 0.87 * 1 = 0.87.

The probability of giving a reading below the limit is given by the sum of the probabilities of drivers below the limit giving a reading below the limit (87%) and drivers above the limit giving a reading below the limit (10%). This gives 0.87 + 0.10 = 0.97.

Therefore, the probability is 0.87 / 0.97 = 0.9779 (or 0.9779 in decimal form) to four decimal places.

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Answer:

dividend

Step-by-step explanation:

The comparison between the Puritan governments of Massachusetts and Connecticut is that both were theocracies. Meanwhile, the contrast between the two is the government. The effectiveness of each form of government and its impact on American democracy are different.

Compare and contrast the Puritan governments of Massachusetts and Connecticut:

The Puritan governments of Massachusetts and Connecticut were both theocracies, meaning that they were governed by religious leaders. However, there were some key differences between the two. In Massachusetts, the government was more authoritarian, with strict laws and punishments for those who did not follow the Puritan faith. In contrast, Connecticut had a more democratic government, with elected officials and a system of checks and balances.

Evaluate the effectiveness of each form of government:

The authoritarian government of Massachusetts was effective in maintaining strict adherence to the Puritan faith, but it also led to the persecution of those who did not conform. On the other hand, the democratic government of Connecticut allowed for more religious freedom and was able to adapt to changing circumstances.

Impact on American democracy:

The Puritan governments of Massachusetts and Connecticut had a lasting impact on American democracy. The authoritarian government of Massachusetts influenced the development of strong central governments, while the democratic government of Connecticut influenced the development of representative democracy and the separation of powers.

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The building is 19.078 feet tall.

Given:

A 20-foot ladder is leaning against a building in order to reach the roof. the foot of the ladder is 6 feet from the building.

Let x be the building height.

here it forms a right angled triangle,

ladder length (hypotenuse) = 20 feet.

base length = 6 feet

According to pythagorean theorem,

\(hypotenuse^{2} = side^{2} +side^{2}\)

\(20^{2} =6^{2} +x^{2}\)

400 = 36 + \(x^{2}\)

\(x^{2}\) = 400 - 36

\(x^{2}\) = 364

x = \(\sqrt{364}\)

x = 19.078 feet.

Therefore the height of the building is 19.078 feet.

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The derivative of the function g(x) = (x² - x + 1\()^1^0\) * (tan(x))³ is g'(x) = 10(x² - x + 1)⁹ * (2x - 1) * (tan(x))³ + 3(x² - x + 1\()^1^0\) * (tan(x))² * sec²(x).

To find the derivative of the given function g(x), we can apply the product rule and the chain rule. Let's break down the function into its constituent parts: f(x) = (x² - x + 1\()^1^0\) and h(x) = (tan(x))³.

Using the product rule, the derivative of g(x) can be calculated as g'(x) = f'(x) * h(x) + f(x) * h'(x).

First, let's find f'(x). We have f(x) = (x² - x + 1\()^1^0\), which is a composite function. Applying the chain rule, f'(x) = 10(x² - x + 1\()^9\) * (2x - 1).

Next, let's determine h'(x). We have h(x) = (tan(x))³. Applying the chain rule, h'(x) = 3(tan(x))² * sec²(x).

Now, we substitute these derivatives back into the product rule formula:

g'(x) = f'(x) * h(x) + f(x) * h'(x)

       = 10(x² - x + 1)² * (2x - 1) * (tan(x))³ + 3(x² - x + 1\()^1^0\)* (tan(x))² * sec²(x).

In summary, the derivative of the function g(x) = (x² - x + 1\()^1^0\) * (tan(x))³ is g'(x) = 10(x² - x + 1)⁹  * (2x - 1) * (tan(x))³ + 3(x² - x + 1\()^1^0\) * (tan(x))² * sec²(x).

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Answer:

i think its D

f(x) = x-3 and g(x) = x+11

f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33

hope this helped :3

Answer:

D

Step-by-step explanation:

(x-3)(x+11)=x^2+11x-3x-33=x^2+8x-33

I think it is 6. It may be because we can see the intersect of line is in (1,6) and (-1,-6). So I think that it is 6.

Answer:

19.625 cm²

Step-by-step explanation:

Diameter = 5 cm

So Radius = 5/2 cm = 2.5 cm

Area of a circle = πr²

So

3.14×2.5² cm²

3.14×6.25 cm²

19.625 cm²

For a function, f(x) = 1 + 3x , the computed value of lim h→0 [f(5 + h) − f(5)]/h is equals to the three.

In Mathematics, the limit of a function is a value of the function as the input of the function tries approaches some number. Function limits are used to define continuity, integrals, and derivatives. Mathematically, let f(x) be a function and L be limit of function, f(x) at x a exist if and only if lim f(x) = lim f(x) = L

x→a⁻ x→a⁺

We have, f(x) = 1+3x and will compute lim h→0 [f(5 + h) − f(5)]/h . Firstly, determine the value of function at x = 5 , x = 5+h.

So, f(5) = 1+ 3×5 = 16 and f(5+ h) = 1+3(5+h)

= 16+ 3h

Now, lim [ f(5 + h) − f(5)]/ h

h→0

= lim [(16 + 3h) − (16) ]/ h

h→0

= lim [ 16 + 3h - 16 ]/ h

h→0

= lim [ 3h/ h ] = lim [ 3h¹h⁻¹ ]

h→0 h→0

= lim [ 3h¹⁻¹ ] = lim [ 3h⁰ ]

h→0 h→0

= lim 3 (1) = 3 ( since, x⁰ = 1 )

h→0

Hence, the required limit value is 3.

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Answer:

Step-by-step explanation:

Count the number of letters

Change integers to strings and put them

Hence answer is 3