Answer:
\( {x}^{4} - {x}^{2} {y}^{2} + {y}^{4} \\ {x}^{4} + {y}^{4} - {(xy)}^{2} \)
You would like to have $20,000 to use a down payment for a home in five years by making regular, end-of-month deposits into an annuity that pays 6% interest compounded monthly.
How much should you deposit each month?
Round your answer to the nearest cent. Do not include the dollar sign in the answer box below.
The calculation of this can be done by first determining the future value of the monthly payments of $327.50
The future value of an annuity can be determined using a financial calculator, mathematical formula, or spreadsheet software. The future value of an annuity is calculated by multiplying the periodic payment amount by the future value factor,
which is based on the number of payments and the interest rate.For example, suppose we want to know the future value of a $500 end-of-month deposit into an annuity that pays 6% interest compounded monthly for five years.
The future value factor for 60 periods at 0.5 percent per month is 80.9747, which can be multiplied by the monthly deposit amount to find the future value of the annuity.500 × 80.9747 = 40,487.35
This means that a $500 end-of-month deposit into an annuity paying 6% interest compounded monthly for five years will have a future value of $40,487.35.
Therefore, to accumulate a $20,000 down payment for a home in five years, you would need to deposit $327.50 per month into the annuity.
for 60 months using the formula and then solving for the monthly payment amount where FV = $20,000 and n = 60, r = 0.5%.FV = PMT [(1 + r)n – 1] / r$20,000 = PMT [(1 + 0.005)60 – 1] / 0.005PMT = $327.50 (rounded to the nearest cent).
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I need help with this problem Harry made 4 hits in 9 times at-bat. If she keeps the same success level, how many hits should she make in 18 timesat-bat?
We need to find the expected value, first:
\(E(x)=p(x)\cdot n\)Where:
\(\begin{gathered} p(x)=\frac{4}{9} \\ n=18 \end{gathered}\)Therefore:
\(\begin{gathered} E(x)=\frac{4}{9}\cdot18 \\ E(x)=8 \end{gathered}\)Answer:
8 hits
Seth spent a total of $28.40 over 4 days. He spent $1.40 more each day than the day before. How much did Seth spend on the first day?
Help with the linear equations
Answer:
\(y \: intercept = - 1 \frac{1}{2} \)
Step-by-step explanation:
The y intercept form for the equation of a line is
\(y = mx + c\)
You should note that c represents the y-intercept of the line (where the line touches the y-axis)
\(y = mx + c \\ \\ we \:were\: given \:the \:equation \:y = x - \frac{3}{2} \\ \\ therefore \: the\: value \:of \:c \:is\: - \frac{3}{2} \:or -1 \frac {1}{2}\)
Suppose an account pays 2.5% interest that is compounded annually. At the beginning of each year, $10,000 is deposited into the account
(starting with $10,000 for the first year).
Assuming no withdrawals or other deposits are made and that the interest rate is fixed, the balance of the account (rounded to the
nearest dollar) after the seventh deposit is_
O $74,581
O $77,201
O $75,474
O $76,816
Answer:
The answer is 75,474
Step-by-step explanation:
5h-6-8+7h what’s the answer ?
express each set using the roster method.
a. the set of the natural odd numbers greater than 2, but less than 11
b.
{x|x (N and 4
In set-builder notation, the same set can be expressed as {x|x (N and 4<x<10)}, which reads as "the set of all x such that x is a natural number and 4 < x < 10."
How to solve the question?
a. The set of natural odd numbers greater than 2, but less than 11 can be expressed using the roster method as {3, 5, 7, 9}. The set includes all the odd natural numbers between 2 and 11, excluding the endpoints, since 2 is not odd, and 11 is not less than 11.
b. The set {x|x (N and 4<x<10)} can be expressed using the roster method as {5, 6, 7, 8, 9}. The set includes all the natural numbers greater than 4 and less than 10, since x is a natural number (N) and satisfies the condition 4 < x < 10.
In set-builder notation, the same set can be expressed as {x|x (N and 4<x<10)}, which reads as "the set of all x such that x is a natural number and 4 < x < 10." The vertical bar separates the description of the elements of the set (the condition) from the set itself.
The roster method and set-builder notation are both ways of describing sets, but the roster method lists all the elements of a set, while the set-builder notation describes the properties or conditions that define the set. Both methods are useful in different situations and depend on the specific context and the purpose of the set description.
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Your complete question is :-
express each set using the roster method.
a. the set of the natural odd numbers greater than 2, but less than 11
b.{x|x (N and 4
the graph below is a translated reflection of the graph of the parent function. Write the quadratic function to model the graph.
Answer: \(y=-\dfrac{16}{9}(x+3)^2+4\)
Step-by-step explanation:
Use the vertex formula: y = a(x - h)² + k where
a is the vertical stretch-a is a reflection over the x-axis(h, k) is the vertexWe can see that the vertex of the curve is (-3, 4) --> h = -3, k = 4
and it is a reflection over the x-axis --> a-value is negative
We need to find the a-value. Choose another point on the curve and plug it into the vertex formula for (x, y) and then solve for a.
I will choose (x, y) = (-3/2, 0)
\(0=a\bigg(\dfrac{-3}{2}+3\bigg)^2+4\\\\\\-4=a\bigg(\dfrac{3}{2}\bigg)^2\\\\\\-4\bigg(\dfrac{2}{3}\bigg)^2=a\\\\\\-\dfrac{16}{9}=a\)
Now that we know the vertex and the a-value, we can input them into the vertex formula:
\(\large\boxed{y=-\dfrac{16}{9}(x+3)^2+4}\)
Answer:
Answer:
Step-by-step explanation:
Use the vertex formula: y = a(x - h)² + k where
a is the vertical stretch
-a is a reflection over the x-axis
(h, k) is the vertex
We can see that the vertex of the curve is (-3, 4) --> h = -3, k = 4
and it is a reflection over the x-axis --> a-value is negative
We need to find the a-value. Choose another point on the curve and plug it into the vertex formula for (x, y) and then solve for a.
I will choose (x, y) = (-3/2, 0)
Now that we know the vertex and the a-value, we can input them into the vertex formula:
Newly purchased automobile tires of a certain type are supposed to be filled to a pressure of 30 psi. Let μ denote the true average pressure. Find the P-value associated with each of the following given z statistic values for testing H0: μ = 30 versus Ha: μ 30 when σ is known. (Give the answers to four decimal places.)
Complete Question
Newly purchased automobile tires of a certain type are supposed to be filled to a pressure of 30 psi. Let μ denote the true average pressure. Find the P-value associated with each of the following given z statistic values for testing H0: μ = 30 versus Ha: μ 30 when σ is known. (Give the answers to four decimal places.)
calculate for each
(a) z = 2.30
(b) z = -1.7
Answer:
a
\(p-value = 0.021448\)
b
\(p-value = 0.08913\)
Step-by-step explanation:
From the question we are told that
The population mean is \(\mu = 30 \ psi\)
The null hypothesis \(H_o : \mu = 30\)
The alternative hypothesis is \(H_a : \mu \ne 30\)
Considering question a
Here the test statistics is (a) z = 2.30
From the z table the probability of (Z > 2.30) is
\(P(Z > 2.30 ) = 0.010724\)
Generally the p-value is mathematically represented as
\(p-value = 2 * P(Z > 2.30 )\)
=> \(p-value = 2 * 0.010724\)
=> \(p-value = 0.021448\)
Considering question b
Here the test statistics is (a) z = -1.7
From the z table the probability of (Z < -1.7) is
\(P(Z < -1.7 ) = 0.044565\)
Generally the p-value is mathematically represented as
\(p-value = 2 * P(Z < -1.70 )\)
=> \(p-value = 2 * 0.044565\)
=> \(p-value = 0.08913\)
What will be the price of gas if there is a 27% increase from $2.67 per gallon?
Answer:
The answer is $3.39
Step-by-step explanation:
the question states an increase in price. this means that we need to multiply the current prince ($2.67) by 127%.
drop the percent and put 127 over 100
\(\frac{127}{100}\)
multiply
\(\frac{127}{100} *\frac{2.67}{1}\\\\ \frac{339.09}{100} \\\\3.39\)
we are dealing with currency so rounding to the hundredths place will suffice.
hope this helps :)
A curve has equation y = 2x + 1/(x-1)² Verify that the curve has a stationary point at x=2 and determine its nature.
There is no stationary point at x = 2. The nature of the curve at x = 2 cannot be determined since there is no stationary point.
To verify that the curve has a stationary point at x = 2, we need to find the derivative of the equation and set it equal to zero.
Given the equation:
y = 2x + 1/(x-1)²
Let's find the derivative dy/dx:
dy/dx = d/dx [2x + 1/(x-1)²]
To find the derivative, we can use the power rule and the chain rule. Let's differentiate each term separately:
For the first term, 2x, the derivative is 2.
For the second term, 1/(x-1)², we can rewrite it as (x-1)^(-2) to apply the power rule. The derivative is then:
d/dx [(x-1)^(-2)] = -2(x-1)^(-3) * d/dx (x-1)
Using the chain rule, d/dx (x-1) = 1, so the derivative becomes:
-2(x-1)^(-3) * 1 = -2/(x-1)^3
Now, let's set dy/dx equal to zero and solve for x:
-2/(x-1)^3 = 0
This equation is satisfied when the numerator is equal to zero:
-2 = 0
However, -2 is not equal to zero, which means there is no x value that makes dy/dx equal to zero.
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Classify each system of equations as having a single solution, no solution, or infinite solutions. y = 11 − 2x 4x − y = 7 x = 12 − 3y 3x + 9y = 24 2x + y = 7 -6x = 3y − 21 x + y = 15 2x − y = 15 2x + y = 7 -4x = 2y + 14 x + 4y = 6 2x = 12 − 8y
Answer:
Let's analyze each system of equations and classify them based on the number of solutions they have:
1) y = 11 − 2x
4x − y = 7
This system of equations represents two lines. The first equation is in slope-intercept form, and the second equation is in standard form. Since the equations have different slopes and different y-intercepts, they intersect at a single point. Thus, the system has a single solution.
2) x = 12 − 3y
3x + 9y = 24
The first equation represents a line, and the second equation is a linear equation. Since the first equation can be rewritten as 3y = 12 - x or y = 4 - (1/3)x, it indicates that the slope-intercept form can't be satisfied. Both equations are equivalent and represent the same line. Therefore, the system has infinitely many solutions.
3) 2x + y = 7
-4x = 2y + 14
The first equation represents a line, and the second equation is also a linear equation. If we simplify the second equation, we get y = -2x - 7, which is equivalent to the first equation. Thus, the system has infinitely many solutions.
4) x + y = 15
2x − y = 15
Both equations are in standard form. By adding the equations, we eliminate y and get 3x = 30, which simplifies to x = 10. Substituting x = 10 into either equation, we find y = 5. Therefore, the system has a single solution.
5) x + 4y = 6
2x = 12 − 8y
The first equation represents a line, and the second equation is a linear equation. By simplifying the second equation, we get x = 6 - 8y, which is equivalent to the first equation. Therefore, the system has infinitely many solutions.
To summarize:
- System 1: Single solution.
- System 2: Infinitely many solutions.
- System 3: Infinitely many solutions.
- System 4: Single solution.
- System 5: Infinitely many solutions.
This is the question
Check the picture below, so the lines look more or less like so, so the shape that we'll be getting will be the shape of a bowl with a hole in it, thus we'll use the washer method.
the way I use to get the larger Radius is simply using the "area under the curve" method, namely f(x) - g(x), where g(x) in this case is the axis of rotation.
so to get "R" and "r" we can get it by
\(\stackrel{y = 1}{(1)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies 1+3\implies \stackrel{R}{4} \\\\\\ \stackrel{y = \ln(x)}{\ln(x)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies \stackrel{r}{ln(x)+3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{R^2}{(4)^2}~~ - ~~\stackrel{r^2}{[\ln(x)+3]^2}\implies 16~~ - ~~[\ln^2(x)+6\ln(x)+9] \\\\\\ \ln^2(x)+6\ln(x)+7~\hfill \boxed{\displaystyle\int~[\ln^2(x)+6\ln(x)+7]dx}\)
The factory receives an order for more than 1,100 boxes. Machine B has already packed 55 boxes. Write and solve an inequality to find the amount of time it will take Machine B to pack the additional boxes that are needed for the order, assuming none of the boxes are defective.
Answer:
no lo sé pero te ayudaría si lo supieraGiven: 1 yard = 3 feet
yards = 4 feet
Answer:
12
Step-by-step explanation:
4 times 3 = 12
Angle B has a measure of 60∘ and is reflected across the line y=x and translated left 14 units to angle B′.
What is the measure of angle B′?
Answer:
\(B' = 60^\circ\)
Step-by-step explanation:
Given
\(B = 60^\circ\)
Reflected and translated to B'
Required
Find the measure of B'
When an angle is reflected and/or translated (irrespective of the number of units of reflection and translation), the resulting angle always equal the initial angle.
This is so because, reflection and translation are rigid transformations and as such, they do not alter the length of measurements.
Hence:
\(B' = 60^\circ\)
Subsidized Stafford Loan
Unsubsidized Stafford Loan
Federal Perkins Loan
Private Loans
Stafford Loan
*
a. These are subsidized loans that are for students who surely need the financial assistance
and they have a fixed interest rate of 5%.
b. These are loans that accrue interest from the day you get them and they have a fixed
interest rate of 6.8%.
c. These are loans that don't accrue interest until you graduate or fall below part-time
attendance and they have a fixed interest rate between 3.4% and 6.8%.
d. These are loans you can get through banks, credit unions, or other institutions and they
have a variable interest rate.
e. These are loans you automatically get if you submit FAFSA, but the amounts depend on
Matching the descriptions with the various student loans is as follows:
Subsidized Stafford Loan: c. These are loans that don't accrue interest ... and they have a fixed interest rate between 3.4% and 6.8%.
Unsubsidized Stafford Loan: b. These are loans that accrue interest ... and they have a fixed interest rate of 6.8%.
Federal Perkins Loan: a. These are subsidized loans that are for students who ... and they have a fixed interest rate of 5%.
Private Loans: d. These are loans you can get through banks, credit unions, or ...and they have a variable interest rate.
Stafford Loan: e. These are loans you automatically get if you submit to a FAFSA (Free Application for Federal Student Aid), but the amounts depend on your financial needs.
What are student loans?Student loans refer to the financial assistance offered to students for the payment of tuition, housing, or other schooling expenses.
A student loan differs from grants, scholarships, and other student aids to fund their post-secondary education and training.
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y2-8+7
2x - y >4
Yes
No
Luct sold 8 cups of lemonade abbie sold 6 times as many cups of lemonade
The amount of cups of lemonade sold by Abbie is 6 x 8 = a.
Hence, option A is correct.
Use the concept of multiplication defined as:
To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that,
Number of lemonade cups sold by Lust = 8
Number of lemonade cups sold by Abbie = 6 times of lust
Let 'a' represents the number of cups sold by Abbie,
Therefore,
6 x 8 = a
Hence,
The correct expression is 6 x 8 = a which is option A.
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The complete question is:
Luct sold 8 cups of lemonade Abbie sold 6 times as many cups of lemonade. Which equation helps us find how many cups Abbie sold if the number of cups sold by Abbie is 'a'.
A. 6x8 = a
B. 8xa = 6
C. 6xa = 8
Function c
is defined by the equation c(n)=50+4n
. It gives the monthly cost, in dollars, of visiting a gym as a function of the number of visits, n
.
True or False? The inverse function is as follows:
n=(c(n) − 50)×4
Responses
Answer:
False
Step-by-step explanation:
1. The inverse function should have c(n) isolated
2. When finding the inverse of a function, the variables c(n) and n are interchanged (and then c(n) is isolated).
It would look like this --->c(n)=50+4n--->n=50+4(c(n)) ---> c(n)=(n-50)/4
Triangles WILL GIVE BRAINLIEST
Answer:
A
Step-by-step explanation:
A
Answer:
Q9 - Option 1---- A - 15.6 Square Units
Q10 --Option --- (B) RECTANGLE
Step-by-step explanation:
Q9 --
Analyze:we know area of triangle = 1/2 ab sin theta
Where theta is the angle included between sides A and side B
Calculate:A = 5.2
B = 7
theta = 121 degrees
Area:1/2 * 5.2 * 7 * sin 121 degrees = 15.6 Square Units
Conclusion
The area of the triangle is 15.6 Square Units
Q10 - The cross-section of a right cylinder which is perpendicular to its base is a RECTANGLEOption --- (B) RECTANGLE
Hope this helps!
What is 4/9 - 1/12 least common moltiple
Answer:
36
Step-by-step explanation:
The LCM of 4, 9, and 12 is the product of all prime numbers on the left, i.e. LCM(4, 9, 12) by division method = 2 × 2 × 3 × 3 = 36.
\(\frac{4}{9} -\frac{1}{12} = \frac{4.4}{9.4} - \frac{1.3}{12.3} = \frac{16}{36}- \frac{3}{36} = \frac{13}{36}\)
ok done. Thank to me :>
You walking against the wind. Your normal speed without the wind is 5mph. How long will it takes you to cover a distance of 5miles if the wind slow you down to 4/5 of your normal speed?
Answer:
1.25 hours
Step-by-step explanation:
So if you walk at 5 mph without wind, it takes you 1 hour to cover a 5 mile distance since you travel at a speed of 5 every hour. (5 mph). with the wind, your speed is 4 miles per hour because the wind slows you down to 4/5ths of your normal speed. 4/5ths of 5 is 4. It takes 1.25 hours to walk with the wind because 5(miles)/4(mph) is 1.25 hours. Hope this helps bud!
ssume all information in example 1 above and the following additional information: Actual data for job 201 is give is given belowActual shirts completed for job 201………………2,000 shirtsActual direct material cost used………………...$30,000Actual direct cost incurred……………………...$20,000Actual direct labor hours used…………………. 400 hoursActual machine hours…………………………. 240 hoursInstruction: compute the applied factory overhead and determine the total cost of job 201 under each of the five bases. A) Physical output as allocation baseDirect materials cost as allocation base Direct labor cost as allocation base Direct labor hours as allocation baseMachine hours as allocation base
The applied overhead cost for job 201 is $36,000 and total cost for job 201 under direct materials cost as allocation base is $86,000.
Allocation base is a technique utilized in accounting to designate the cost of something to its use or product to recognize the price of the finished product.
Example provides the total overhead cost at $120,000 for the period, the base data of $100,000 direct material cost and 500 direct labor hours. The base data are used to calculate the predetermined factory overhead rate, which is used to apply overhead costs to work in progress.
The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the base data. The predetermined factory overhead rate is multiplied by the actual activity in the allocation base to obtain the applied overhead cost.
Direct materials cost as allocation base $30,000 is the actual direct material cost used in job 201. The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct material cost, which is $120,000/$100,000=120%.
The applied overhead cost for job 201 is $30,000*120% = $36,000.
Total cost for job 201 under direct materials cost as allocation base is $30,000+$20,000+$36,000 = $86,000.
-Direct labor cost as allocation base:
The actual direct labor cost used in job 201 is $20,000. The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct labor cost, which is $120,000/$100,000=120%.
The applied overhead cost for job 201 is $20,000*120% = $24,000.
Total cost for job 201 under direct labor cost as allocation base is $30,000+$20,000+$24,000 = $74,000.
-Direct labor hours as allocation base:
The actual direct labor hours used in job 201 is 400 hours.
The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct labor hours, which is $120,000/500 hours = $240 per hour.The applied overhead cost for job 201 is $240*400 hours = $96,000.
Total cost for job 201 under direct labor hours as allocation base is $30,000+$20,000+$96,000 = $146,000.
-Physical output as allocation base: The actual output in units completed for job 201 is 2,000 shirts.
The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the output in units, which is $120,000/10,000 units = $12 per unit.
The applied overhead cost for job 201 is $12*2,000 units = $24,000.Total cost for job 201 under physical output as allocation base is $30,000+$20,000+$24,000 = $74,000.
-Machine hours as allocation base: The actual machine hours used in job 201 is 240 hours.
The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the machine hours, which is $120,000/5,000 hours = $24 per hour.
The applied overhead cost for job 201 is $24*240 hours = $5,760.
Total cost for job 201 under machine hours as allocation base is $30,000+$20,000+$5,760 = $55,760.
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75 POINTS IF U GET THIS RIGHT !!!!!Every June 1, an ecologist takes a census of the number of wrens in a state park. She noticed that the number is decreasing by $40\%$ each year. If this trend continues, in what year will the census show that the number of wrens is less than $10\%$ of what it was on June 1, 2004?
Answer:
In 2009
Step-by-step explanation:
If the wren population is going down by 40% each year, that means the following year's population is just 60% of what was in the previous year. This means that what we have to do is multiply the previous year's number by 0.6 to get the current year's population. If we take the data from 2004 as 100%, we have the following numbers:
2004 = 100%
2005 = 60 % (100 * .6)
2006 = 36 % (60 * .6)
2007 = 21.6 % (36 * .6)
2008 = 12.96 % (21.6 * .6)
2009 = 7.776% (12.96 * .6)
This means that 2009 will show that the wren population is less than 10% (7.776%) than what it was in the year 2004.
I hope this helps! :D
Answer:
2009
Step-by-step explanation:
On June 1, 2004 we can say that there were 100% of the wrens.
If the number decreases by 40% each year, then each year there will be 60% of the previous years number. To find 60%, multiply by 0.6 (since 60% = 60/100 = 0.6)
June 1, 2004 = 100%
June 1, 2005 = 100% x 0.6 = 60%
June 1, 2006 = 60% x 0.6 = 36%
June 1, 2007 = 36% x 0.6 = 21.6%
June 1, 2008 = 21.6% x 0.6 = 12.96%
June 1, 2009 = 12.96% x 0.6 = 7.776%
Therefore, the census shows that the number of wrens is less than 10% in the year 2009.
Graph the circle (x - 3)^2 + (y + 3)^2= 36.
The circle on a graph by drawing the center point and then drawing a circle around it with a radius of 6.
To graph the circle with the equation (x - 3)² + (y + 3)² = 36, we can start by finding the center and radius of the circle.
The equation of a circle in standard form is (x - h)² + (y - k)² = r² (h, k) represents the center of the circle and r represents the radius.
Comparing the given equation with the standard form, we can see that the center of the circle is (3, -3) and the radius is √36 = 6.
Using this information, we can proceed to plot the circle on a graph:
Plot the center point: (3, -3).
From the center point, move 6 units in each direction (up, down, left, and right) to determine the points on the circle.
Up: (3, -3 + 6) = (3, 3)
Down: (3, -3 - 6) = (3, -9)
Left: (3 - 6, -3) = (-3, -3)
Right: (3 + 6, -3) = (9, -3)
Connect the plotted points to form a circle.
The resulting graph should look like this:
| • (3, 3)
|
| •
| •
__|_____________________________
|
|
|
|
| • (3, -3)
The center of the circle is denoted by a solid dot (•) in the graph and the other points lie on the circumference of the circle.
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Calc II Question
The base of s is an elliptical region with boundary curve 9x^2 + 4y^2 = 36
Cross sections perpendicular to the x axis are isoscelees right triangle with hypotension in the base.
Correct answer is 24 but I don't know how they go that
Answer:
See below for explanation
Step-by-step explanation:
The area of an isosceles triangle is \(A=\frac{1}{2}bh\), so let's write the base as an equation of y:
\(\displaystyle 9x^2+4y^2=36\\\\4y^2=36-9x^2\\\\y^2=9-\frac{9}{4}x^2\\\\y=\pm\sqrt{9-\frac{9}{4}x^2\)
As you can see, our ellipse consists of two parts, so the hypotenuse of each cross-section will be \(\displaystyle 2\sqrt{9-\frac{9}{4}x^2\), and each height will be \(\displaystyle \sqrt{9-\frac{9}{4}x^2}\).
Hence, the area function for our cross-sections are:
\(\displaystyle A(x)=\frac{1}{2}bh=\frac{1}{2}\cdot2\sqrt{9-\frac{9}{4}x^2}\cdot\sqrt{9-\frac{9}{4}x^2}=9-\frac{9}{4}x^2\)
Since we'll be integrating with respect to x because the cross-sections are perpendicular to the x-axis, then our bounds will be from -2 to 2 to find the volume:
\(\displaystyle V=\int^2_{-2}\biggr(9-\frac{9}{4}x^2\biggr)\,dx\\\\V=9x-\frac{3}{4}x^3\biggr|^2_{-2}\\\\V=\biggr(9(2)-\frac{3}{4}(2)^3\biggr)-\biggr(9(-2)-\frac{3}{4}(-2)^3\biggr)\\\\V=\biggr(18-\frac{3}{4}(8)\biggr)-\biggr(-18-\frac{3}{4}(-8)\biggr)\\\\V=(18-6)-(-18+6)\\\\V=12-(-12)\\\\V=12+12\\\\V=24\)
Therefore, this explanation confirms that the correct volume is 24!
Determine the 9th term of the geometric sequence 3,6,12,24
The solution is 768 is the correct answer, is the 9th term of the geometric sequence 3,6,12,24.
Given:
The geometric sequence 3,6,12,24.
Required:
Find the 6th term of the geometric sequence.
Explanation:
The given sequence is 3,6,12,24.
The nth term of the sequence is given by the formula:
an = a* r^n-1
Where a = first term and r = common ratio
From the given sequence
a = 3, r = 6/3 = 2
Then 9th term is:
a9 = 3 * 2^9-1
= 3* 2^8
=768
Final answer:
The solution is 768 is the correct answer, is the 9th term of the geometric sequence 3,6,12,24.
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What is the slope of the following line y=5x - 2
Answer:
m = 5 is the answer
Step-by-step explanation:
use symbolab I use it all the time
Answer:
the slope is 5
Step-by-step explanation:
the formula is y=mx+b and in this case 5 is m which stands for the slope
20. Which of the following is the function for the graph below?
The quadratic function that represents the given graph is:
y = ¹/₂(x − 4)² - 1
How to write a quadratic equation in vertex form?The general form of a quadratic equation in Vertex Form is expressed as:
y = a(x − h)² + k,
where
(h, k) is the vertex.
From the given graph, we can see that the coordinates of the vertex is (4, -1). Thus, we have:
y = a(x − 4)² - 1
Looking at the four given options from Option A to Option D, we can deduce that only given option that gives us the coordinates of the quadratic curve vertex is option D.
Thus, we can conclude that the quadratic function that truly represents the given parabolic graph curve is:
y = ¹/₂(x − 4)² - 1
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