six is more than the difference of a number d and 1.

Answer:

c=6
d=10

Step-by-step explanation:

d+4=14 and c+5=11

The solution set of the given system of equations is {(4, 0), (2, 4)}.

The given system of equations is: y = x² – 6x + 8 and y = –x + 4

To solve the given system of equations, we need to solve both the equations simultaneously.

We can solve the equations by the following method:

First Equation:

y = x² – 6x + 8

Rewriting in vertex form, we get:

y = (x – 3)² – 1

This is a parabola that opens upward and its vertex is at (3, –1).

Second Equation:

y = –x + 4

This is a line that passes through (0, 4) and (4, 0).

Now, we can find the solution of the given system of equations by plotting the graph of both the equations on the same graph.

We can observe from the graph that the two graphs intersect at (4, 0) and (2, 4).

Therefore, the solution of the given system of equations is: x = 4, y = 0, x = 2, y = 4

So, the solution set of the given system of equations is {(4, 0), (2, 4)}.

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Answer:

david was. 9 seconds faster than Justin.

Step-by-step explanation:

8.1-7.2= .9

Answer:

0.9 seconds

Step-by-step explanation:

Since Justin came in slower, you would put his time first:

8.1 - 7.2

Doing that gets you 0.9

Answer:

Step-by-step explanation:

it is

Cost of a bag of chips is $ 2.49.

The number of juice bottles is 12

The total cost is $ 27.57.

Let x be the cost of a juice bottle. Therefore we have,

On solving, x can be calculated as,

Thus, the cost of each juice bottle is $2.09.

Answer:

239

Step-by-step explanation:

239 because do the answers in the parenthesis first then do the rest.

IF THE SLOPE IS 0 IT MEANS THAT THERE IS NO CHANGE IN THE Y COORDINATE OF THE LINE.FOR ANY VALUE OF X GIVEN

THEREFORE THE EQUATION WILL BE

\(y = (0)( - 6) - 2 \\ y = - 2\)

THE EQUATION IS

\(y = - 2\)

HOPE THIS HELPS

Answer:

The slope-intercept form would be: y = 0x - 2

Answer:

A. Cylinder, Shpere, Cone

Step-by-step explanation:

a cylander can be made by rotating a square.

for a sphere, a semi-circle.

for a cone, a right triangle.

hope this helped you

Answer:

102

Step-by-step explanation:

The mode is the number that appears the most in the data set. 102 appears 3 times while the others only once

Answer:

1558.9 feet.

Explanation:

We can model the situation as follows:

Where we want to know the distance x and we know the angle of 15.8° and the horizontal distance of 1500 ft.

Therefore, we can relate these values as follows:

So, solving for x, we get:

Then, the answer is 1558.9 feet.

The control limits for the mean chart are 7.76821 (LCL) and 8.34595 (UCL), while the control limits for the range chart are 0 (LCL) and 0.86566 (UCL).

To calculate the exact control limits for the mean and range charts, we will use the formulas provided:

Calculate the mean and range for each sample:

Sample 1:

Mean = (7.98 + 8.34 + 8.02 + 7.94 + 8.44 + 7.68 + 7.81 + 8.11) / 8 = 8.055

Range = 8.44 - 7.68 = 0.76

Sample 2:

Mean = (8.33 + 8.22 + 8.08 + 8.51 + 8.41 + 8.28 + 8.09 + 8.16) / 8 = 8.275

Range = 8.51 - 8.08 = 0.43

Sample 3:

Mean = (7.89 + 7.77 + 7.91 + 8.04 + 8.00 + 7.89 + 7.93 + 8.09) / 8 = 7.9475

Range = 8.09 - 7.77 = 0.32

Sample 4:

Mean = (8.24 + 8.18 + 7.83 + 8.05 + 7.90 + 8.16 + 7.97 + 8.07) / 8 = 8.055

Range = 8.24 - 7.83 = 0.41

Sample 5:

Mean = (7.87 + 8.13 + 7.92 + 7.99 + 8.10 + 7.81 + 8.14 + 7.88) / 8 = 7.9925

Range = 8.14 - 7.81 = 0.33

Sample 6:

Mean = (8.13 + 8.14 + 8.11 + 8.13 + 8.14 + 8.12 + 8.13 + 8.14) / 8 = 8.1325

Range = 8.14 - 8.11 = 0.03

Calculate the overall mean and overall average range:

Overall Mean = (8.055 + 8.275 + 7.9475 + 8.055 + 7.9925 + 8.1325) / 6 = 8.05708

Overall Average Range = (0.76 + 0.43 + 0.32 + 0.41 + 0.33 + 0.03) / 6 = 0.37833

Construct the control charts:

Mean Chart:

Upper Control Limit (UCL) = Overall Mean + (A2 * Overall Average Range)

Lower Control Limit (LCL) = Overall Mean - (A2 * Overall Average Range)

For a sample size of 8, A2 = 0.729.

UCL = 8.05708 + (0.729 * 0.37833) = 8.34595

LCL = 8.05708 - (0.729 * 0.37833) = 7.76821

Range Chart:

Upper Control Limit (UCL) = D4 * Overall Average Range

Lower Control Limit (LCL) = D3 * Overall Average Range

For a sample size of 8, D3 = 0 and D4 = 2.282.

UCL = 2.282 * 0.37833 = 0.86566

LCL = 0 * 0.37833 = 0

Therefore, the control limits for the mean chart are 7.76821 (LCL) and 8.34595 (UCL), and the control limits for the range chart are 0 (LCL) and 0.86566 (UCL).

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--The given question is incomplete, the complete question is given below " Webster Chemical Company produces mastics and caulking for the construction industry. The product is blended in large mixers and then pumped into tubes and capped. Management is concerned about whether the filling process for tubes of caulking is in statistical control. Several samples of eight tubes were taken, each tube was weighted, and the weights in the following table were obtained.

Assume that only six samples are sufficient and develop the control charts for the mean and the range. "--

Answer:

105

Step-by-step explanation:

2x17=34

17x2.5=42.5

1.5x17=25.5

1/2x2x2x1.5=3

34+42.5+25.5+3=105

Answer Po Ba Ay 11.33?

Step-by-step explanation:

Calc

Answer: D. Matthew’s, Rhoda’s, and Ming’s

Step-by-step explanation:

√0.89 ≈ 0.94

Anyah is incorrect because both of her decimals are smaller than √0.89.

Matthew is correct because 0 is less than 0.89 but 1 is still greater than 0.89.

Rhoda is correct because 0.9² is 0.81 is less than 0.89 but 1.0² is 1 which is still greater than 0.89.

Ming is correct because 0.93² is about 0.87 which is less than 0.89 but 0.95² is about 0.9 which is still greater than 0.89.

I hope this helps!

Answer:

Hi how are you doing today Jasmine

Answer:

5,166,000

Step-by-step explanation:

grown population after 1 year=2.5/100×5040000

which is 126,000

total population after 1year=5040000+126000

which is 5166000

Yes, given explanation is correct.if the calculated test statistic is less than -1.645 then the null hypothesis can be rejected.

For test the claim that the proportion of people who smoke is less than 22.5%.

A one-tailed test of hypothesis can be used. Specifically, a one-sample z-test for a proportion can be used where:

Null hypothesis: p ≥ 0.225 (the proportion of people who smoke is equal to or greater than 22.5%)

Alternative hypothesis: p < 0.225 (the proportion of people who smoke is less than 22.5%)

The test statistic for the one-sample z-test for a proportion is calculated as:

z = (p - P0) / √[(P0 × (1 - P0)) / n]

where p is the sample proportion, P0 = the hypothesized proportion under the null hypothesis and n = The sample size.

If the calculated test statistic falls in the rejection region which is determined by the chosen significance level (e.g., alpha = 0.05) then the null hypothesis can be rejected and it can be concluded that there is evidence to support the claim that the proportion of people who smoke is less than 22.5%.

For a one-tailed test with alpha = 0.05, the critical value is -1.645.

Hence, if the calculated test statistic is less than -1.645 then the null hypothesis can be rejected.

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Volume of paint used by each boy is equal to Liam : 2 + (13/4)x and

Evan :  1/2 + (11/2)y. Equation to represent equal volume is

2 + (13/4)x = 1/2 + (11/2)y.

As given in the question,

Let jar used by Liam is having x quarts of paint

And let jar used by Evam is having y quarts of paint

Paint mix by Liam is equal to

2 quarts of yellow paint + (3 1/4)x of blue paint

= 2 + (13/4)x

Paint mix by Evan is equal to

1/2 quarts of yellow paint + (5 1/2)y of blue paint

= 1/2 + (11/2)y

Volume of the paint used by both Liam and Evan is same

2 + (13/4)x = 1/2 + (11/2)y

Therefore, equation to represent the same volume of paint used by Liam and Evan is  2 + (13/4)x = 1/2 + (11/2)y and volume of paint mixed by each boy is given by :

Liam : 2 + (13/4)x

Evan :  1/2 + (11/2)y

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Answer:

B: 3,0,-3,-6

Step-by-step explanation:

An arithmetic sequence has constant adding or subtracting. In this case, 3 is being subtracted as a constant.

Answer:

x =37/96 or x = 0.385416

Step-by-step explanation:

12 (16x - 6) = 2

6 (16x - 6) = 1

96x - 36 = 1

96x = 1 + 36

96x = 37

Answer:

a. 43 + 72x ≤ 1,128

Step-by-step explanation:

Answer:

$14.85

Step-by-step explanation:

8.98 + 3.27 + 1.5 = 13.75

13.75 x .08 = 1.1

13.75 + 1.1 = 14.85

Answer:

$14.85

Step-by-step explanation:

8.98 x.08= 0.7184

3.27 x .08= 0.2616

1.50 x .08= 0.12

8.98 + 0.72=  9.70

3.27 + .26= 3.53

1.50 + 12 =1.62

9.70+ 3.53 +1.62 = 14.85

An expression for the amount of money that Alicia earns in a day is 40y-3g.

Given that, Alicia runs a small business mowing yards in the summer. For every yard she mows, she earns $40. However, she spends part of this money on gasoline for her lawnmower. Each gallon of gasoline costs $3.

We need to find an expression for the given situation.

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Now, expression =40y-3g

Therefore, an expression for the amount of money that Alicia earns in a day is 40y-3g.

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Answer: $40y − $3g

Step-by-step explanation:

On the basis of birthday problem or scenario, the number of people should be selected to guarantee that at least 4 were born on the same day, not considering the year is equals to the 1096.

The worst case scenario is one of the many possible cases where the desired outcome comes after every other probable outcome has already occurred. The number of people who ensure that at least 7 people have a birthday on a single day of a non-leap year (365 days) can be determined by ensuring that in the number of people selected in each trial, two people do not have a birthday on a day. the same day. There are 365 days in a year.

Assuming everyone was born on a different day, then you could have 365 people where no one was born on the same day, but those 366 people would have to be born on the same day as someone else in the group. So the minimum number of people in a group would have to be 366 to guarantee that at least 2 people were born on the same day. But we wanted to guarantee that at least 4 people were born on the same day.

So, assuming we had 3 × 365 people together, with every 3 of them being born on the same day. Then would have a total of 365× 3 = 1095 people, with no more than 3 people being born on the same day. Now as we select one more person, the number of people born on a day for one of the days in the year will increase to 4. Hence the number of people that should be selected to guarantee that at least 4 were born on the same day are 1095 +1 = 1096. Hence, required value is 1096.

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The statement that best proves that <XWY ≅ <ZYW is that two parallel lines are cut by a transversal, then the alternate interior angles are congruent

To determine the correct statement, we need to know the properties of a parallelogram.

These properties includes;

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A number that represents the property of the sample is the statistics.

Statistics refer to that number that describes a particular property of a sample set of numbers. It is the common property shared by all the numbers of the sample set. It involves the collection of data and information and then categorizing them according to their properties and inferences.

'Mean and proportion' is mathematical calculations that can be carried out on statistic number sets.

Mean refers to the average of the number set that is provided to us. It is calculated by adding the numbers and dividing them by the number of terms.

Proportion refers to the fraction of the number set according to some characteristics shared by the numbers.

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can you be more clear? what is the question

the probability distribution governing y is a Gaussian distribution with mean wx (deterministic linear function of x) and variance σ^2, given by P(y | x) = N(wx, σ^2).

The probability distribution governing y can be represented using the concept of conditional probability. Given x, the distribution of y can be expressed as the conditional distribution of y given x.

Since the noise term € follows a Gaussian distribution with mean 0 and standard deviation σ (represented as N(0,σ^2)), we can write the conditional distribution of y given x as:

P(y | x) = N(wx, σ^2)

Here, N(wx, σ^2) represents the Gaussian distribution with mean wx (deterministic linear function of x) and variance σ^2.

In summary, the probability distribution governing y is a Gaussian distribution with mean wx (deterministic linear function of x) and variance σ^2, given by P(y | x) = N(wx, σ^2).

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Answer:

d

Step-by-step explanation:

Answer: a = 9 +b + c

Steps: a - b - c = 9

Subtract -b and -c from both sides:  a - b - c - (-b -c) = 9 - (-b -c)

Simplify: a = 9 +b + c

Plz mark brainliest:)

increasing the sample size and the difference between the null and alternative hypotheses reduces the probability of committing a type II error, while increasing the type I error level increases the probability of committing a type II error.

As the value of n (the sample size) increases, the probability of committing a type II error decreases. This is because as the sample size increases, the standard error of the mean decreases, which leads to a narrower confidence interval around the sample mean. As a result, it becomes easier to detect a true difference between the null hypothesis and the alternative hypothesis, which reduces the probability of a type II error.

As delta (the difference from the null hypothesis to detect) increases, the probability of committing a type II error decreases. This is because as the difference between the null and alternative hypotheses becomes larger, it becomes easier to detect a true difference between them. Therefore, the probability of failing to reject the null hypothesis when it is actually false (i.e., committing a type II error) decreases.

As the type I error level (alpha) increases, the probability of committing a type II error also increases. This is because the type I error level is the maximum allowable probability of rejecting the null hypothesis when it is actually true. When alpha is set at a high level (e.g., 0.10 or 0.20), the probability of committing a type I error increases, which reduces the power of the test to detect a true difference (i.e., increases the probability of committing a type II error).

Overall, increasing the sample size and the difference between the null and alternative hypotheses reduces the probability of committing a type II error, while increasing the type I error level increases the probability of committing a type II error. It is important to balance these factors in order to design a hypothesis test with appropriate power and error rates.

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