SOCCER Four soccer players are practicing a drill. Goalie A is facing Player B
to receive the ball. Goalie Athen turns tº to face Player A to pass her the ball. If
Goalie B is facing Player A to receive the ball, then through what angle
measure should Goalie B turn to pass the ball to Player B?

Answer:

a= −1/9y+64/9

Answer:  approximately 24 square units in the shaded areas

Step-by-step explanation:  

The area of the entire dark circles will be for each πr², then divided by 2 to get the area of the semicircles created on the sides of the triangles:

16π + 9π = 25π   Half that times value for pi

≈ 39.2699  is the area of the dark semicircles. Round to 39.27

Now the fun! Find the area of the parts subtracted by the light semicircle:

The area of the entire circle is 25π  or about 78.54. The triangle is half of an inscribed rectangle, 6×8, so 48.  Subtracted from the circle leaves about 30.54 in the four slices between the arcs of the circumference and the perimeter of the rectangle. We are concerned with only half of the slices, so we will subtract 15.27

Area of the dark semicircles minus the area of the light slices will leave the area of the shaded crescents:

34

Step-by-step explanation:

 122

This is a lengthy question ill go through all the formulas

This is a right triangle which means u can use pythagorean theorem to find QP

formula :

\(a^{2} +b^{2} =c^{2}\)

Note that \(c^{2}\) is always the hypotenuse(the hyp is always opposite to ninety degrees)

so lets substitute

=> \(a^{2} +17^{2} =28^{2}\)

=> \(a^{2} +289 =784\)

subtract 289 both sides

\(= > a^{2}=495\)

Now square root both

\(\sqrt{ a}^{2}=\sqrt{495}\)

==> \(3\sqrt{55}\) or 22.2 (answer)

But for the other three u have to use another formula any of sin, tan,cos while using For example angle Q and then use any and do inverse it will be very easy after u know all the formulas of Sin,cos, tan

SOHCAHTOA

^

Thats an acronym   for the formula

Sin= Opposite/ hyp

Cos= Adjustent/Hyp

Tan= Opposite/Adjustent

Answer:

Option D

Step-by-step explanation:

8 ÷ 0 = Undefined

Answer:

D

Step-by-step explanation:

The statement is false because adding a vector to a set of vectors can increase its span, but the new span is not necessarily the same as the original span.

The statement is false. To prove this, consider three vectors u1, u2 and u3 that span R3, and a vector u4 that is not a linear combination of

u1, u2 and u3.

The span of

{u1, u2, u3, u4}

will be a subset of the span of

{u1, u2, u3}.

This means that the span of

{u1, u2, u3, u4}

will contain all the vectors that the span of {u1, u2, u3} contains, plus the vector u4. However, it does not necessarily mean that the span of

{u1, u2, u3, u4} will be the same as the span of {u1, u2, u3},

as there may be other vectors that are in the span of

{u1, u2, u3, u4}

but not in the span of {u1, u2, u3}. Hence, the statement is false.

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The complete question is

Determine if the statement is true or false, and justify your answer. If (u1, u2, u3) spans R3, then so does (u1, u2, uz, u). O False. Consider u4 =0 True, the span of a set of vectors can only increase (with respect to set containment) when adding a vector to the set. O True, since the span of {ul, u2, u3, u4} is a subset of the span of {u1, u2, us), O False. Consider u4 = 0. The span of {u1, u2, u3, u4} is a subset of the span of {u1, u2, us}, but the span of {u1, u2, u3, u4} is not the same as the span of {u1, u2, us}.

The probability that Bentley selects a striped egg and Johnny selects a polka dotted egg is 35/132.

The probability of Bentley selecting a striped egg on the first pick is 7/12

After Bentley selects an egg, there are 11 eggs remaining in the basket, of which 5 are polka dotted.

So the probability of Johnny selecting a polka dotted egg on the second pick = 5/11.

To find the probability of both events happening, we multiply the probabilities:

P(Bentley selects striped and Johnny selects polka dotted) = (7/12) * (5/11)

P(Bentley selects striped and Johnny selects polka dotted) = 35/132

Therefore, the probability that Bentley selects a striped egg and Johnny selects a polka dotted egg is 35/132.

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Answer:B.Sample space

Step-by-step explanation:

Answer:

It is moved 8 units left and 5 units down

y = \(\sqrt[3]{x+8}\) - 5

So vertical translation 5 units down and horizontal translation 8 units left

Answer:

\(\boxed{\boxed{\sf s=\frac{1}{3}}\sf \:or\:\boxed{\sf s=0.33...}}\)

Step-by-step explanation:

\(\sf 3\left(s+1\right)-8=6s\left(2-4\right)\)

Expand ( Apply the Distributive Property):-

\(\sf 3s-5=-12s\)

Add 5 to both sides:-

\(\sf 3s-5+5=-12s+5\)

Simplify:-

\(\sf 3s=-12s+5\)

Add 12s to both sides:-

\(\sf 3s+12s=-12s+5+12s\)

Simplify:-

\(\sf 15s=5\)

Divide both sides by 15:-

\(\sf \cfrac{15s}{15}=\cfrac{5}{15}\)

Simplify:-

\(\sf s=\cfrac{1}{3}\)

___________________

Hope this helps!

Have a great day! :)

The answer of the integral f(t) = cos(t) + t0 + e−τf(t − τ) dτ using laplace transformation is f(t)=cost+sint.

What is Laplace Transformation?

Laplace Transfrom is a part of integration where the integration is done with respect to the real variable. And this real variable is converted into a complex form.

In order to solve the given equations, we need to take two functions f(t) and g(t) and L and t as laplace transformers.

Given that:

F(t) = cos(t) + t0 + e−τf(t − τ) dτ

Use Laplace transformation both sides

L{f(t)} = L{cos(t)} + L{ t0 + e−τf(t − τ) dτ}

L{f(t)}=s÷s²+1+L{e−t∗f(t)}

L{f(t)}=s÷s²+1+L{e−t} L{f(t)}

F(s)=s÷s²+1+1÷s+1 F(s)

F(s)(1−1s+1)=s÷s2+1

F(s)(1−1÷s+1)=s÷s²+1

F(s)(s÷s+1)=s÷s²+1

F(s)(1s+1)=1s2+1

F(s)=s+1÷s²+1

F(s)=s÷s²+1+1÷s²+1.

Take Inverse Laplace

L−1{F(s)}=L−1{s÷s²+1+1÷s²+1}

f(t)=L−1{s÷s²+1}+L−1{1÷s²+1}

f(t)=cost+sint

Therefore the  answer of the integral f(t) = cos(t) + t0 + e−τf(t − τ) dτ using laplace transformation is f(t)=cost+sint.

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To evaluate the limit of the improper integral, we have:

lim┬(x→0)⁡〖(sin⁡(2x))/(3x)〗

We can rewrite the limit as an improper integral:

lim┬(x→0)⁡〖∫[0]^[x] (sin⁡(2t))/(3t) dt〗

where the integral is taken from 0 to x.

Now, let's evaluate this improper integral. Since the integrand approaches a well-defined value as t approaches 0, we can evaluate the integral directly:

∫[0]^[x] (sin⁡(2t))/(3t) dt = [(-1/3)cos(2t)]|[0]^[x] = (-1/3)cos(2x) - (-1/3)cos(0) = (-1/3)cos(2x) - (-1/3)

Taking the limit as x approaches 0:

lim┬(x→0)⁡(-1/3)cos(2x) - (-1/3) = -1/3 - (-1/3) = -1/3 + 1/3 = 0

Therefore, the given limit is equal to 0.

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The size of the angle marked y in the triangle is 50 degrees

The complete question is added as an attachment

Given that the triangle is an isosceles triangle

An isosceles triangle is a triangle with two sides of equal length. This means that two of the angles opposite to those sides are congruent.

Using the above definition, we have the following equation

y + 2 * 65 = 180

So, we have

y + 130 = 180

Evaluate the like terms

y = 50

Hence. the value of y is 50 degrees

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Answer:

Check pdf

Step-by-step explanation:

The best estimate for the deer population on the island is 500.

1. The veterinary doctors marked 30 deer on the island.

2. Later on, they counted 150 deer in total.

3. Out of the 150 deer, 12 had marks.

4. To find the best estimate for the deer population on the island, we can set up a proportion.

5. Let "x" represent the total deer population.

6. The proportion can be set up as: 30/x = 12/150.

7. Cross-multiplying gives us: 12x = 30 * 150.

8. Solving for x, we get: x = (30 * 150) / 12.

9. Evaluating the expression, we find: x = 375.

10. Rounding to the nearest whole number, the best estimate for the deer population on the island is 500.

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Answer:5.97

Step-by-step explanation.  

you have to look at the question.

you have to look around the question

The very last step is you have to answer it  

Answer:

The total grams of fat that were in both servings based on the information is 27.625 grams.

Step-by-step explanation:

From the information, Lara bought Philly soft pretzels. Each serving has 1.7 grams of fat. She ate 15 servings of the pretzels at lunch and 1.25 servings of the pretzels as a snack.

Therefore, the total grams will be:

Therefore, the total grams of fat that were in both servings based on the information is 27.625 grams.

= (15 × 1.7) + (1.25 × 1.7)

= 25.5 + 2.125

= 27.625 grams

b. 4

....................

3x =24

or, x= 24/3

or, x =8

Answer:

the vertex of a quadratic equation:

a*x^2 + b*x + c = y

Is located at:

x = -b/2a.

In this case, x = -2

Then:

-b/2a = -2.

And we also have that:

a*(-2)^2 + b*-2 + c  = 3

Then we have two equations:

-b/2a = -2

a*(-2)^2 + b*-2 + c  = 3

We have only 2 equations and 3 variables, so we can just give the variable c different values and we will find different quadratic equations that are not equivalent.

Let's begin with c = 0, our equations are:

-b/2a = -2

a*(-2)^2 + b*-2 + 0  = 3

In the first equation we can isolate b and get:

b = 4*a

Now we can replace this in the other equation and solve this for a.

a*4 + 4*a*-2 = 3

-4*a = 3

a = -3/4

then:

b = 4*a = 4*-3/4 = -3

The first quadratic equation is:

(-3/4)*x^2  - 3*x = y.

Now, to find the second let's use a different value of c.

c = 1

b = 4*a

a*(-2)^2 + b*-2 + 1  = 3

Let's solve in the same way as before:

a*4 + (4*a)*-2 + 1 = 3

-4*a = 2

a = 2/-4 = -1/2

b = 4*-1/2 = -2.

Then our equation is:

(-1/2)*x^2 - 2*x + 1 = y

For the last equation, let's use c = 2.

then our equations are:

b = 4*a

a*(-2)^2 + b*-2 + 2  = 3

Same as before, replace the first equation in the second.

a*4 + (4*a)*-2 + 2 = 3

-4*a + 2 = 3

-4*a = 1

a = -1/4

Then:

b = 4*(-1/4) = -1

Our third equation is:

(-1/4)*x^2 - 1*x + 2 = y

Now, below you can see all of them graphed.

Where red is the first one, blue the second and green the third one. (and as you can see, all of them share the vertex (-2,3) )

Answer:

-5.4

Step-by-step explanation:

Euclid receives 20 shares of common stock as a nontaxable stock dividend.The basis of the common stock remains the same as in scenario a, which is $96.15 per share.

To calculate the per share basis, we divide the original purchase cost by the total number of shares (including the dividend shares).  In scenario b, Euclid receives a nontaxable preferred stock dividend of 20 shares. The preferred stock has a fair market value of $5,000, and the common stock, on which the preferred is distributed, has a fair market value of $75,000.

The tax consequences involve determining the new basis of the preferred stock and the common stock after the dividend. a. To find the per share basis of Euclid's common stock after receiving the stock dividend, we divide the original purchase cost by the total number of shares. The original purchase cost was $50,000 for 500 shares, which means the per share basis was $50,000/500 = $100. After receiving 20 additional shares as a dividend, the total number of shares becomes 500 + 20 = 520.

Therefore, the new per share basis is $50,000/520 = $96.15. b. In this scenario, Euclid receives a preferred stock dividend of 20 shares. The preferred stock has a fair market value of $5,000, and the common stock has a fair market value of $75,000. To determine the new basis of the preferred stock, we consider its fair market value.

Since the preferred stock dividend is nontaxable, its basis is equal to the fair market value, which is $5,000.

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Answer:

55 (approx.)

Step-by-step explanation:

30% of 186 students joined the band

(30/100) × 186

5580/100

55.8

= 55 students (approx.)

(the answer will come approximate as final is in decimal)

Answer: D

Step-by-step explanation: If you plug in the formula, it works.

Answer:

D

Step-by-step explanation:

The unit circle is the circle centered at with radius The unit circle is a circle centered at the origin with a radius of 1 unit. It plays a fundamental role in trigonometry, providing a geometric representation of the trigonometric functions

The unit circle is a circle that is centered at the origin (0, 0) of a coordinate plane and has a radius of 1 unit. In other words, it is a circle with a diameter of 2 units.

The unit circle is particularly significant in mathematics, especially in trigonometry. Its properties and relationships with angles are extensively used in various mathematical applications.

One of the main reasons the unit circle is so important is due to its connection with the trigonometric functions sine and cosine. As an angle rotates around the origin,

the coordinates of the point on the unit circle where the terminal side of the angle intersects the circle correspond to the values of sine and cosine of that angle.

For example, if an angle of 30 degrees is measured counterclockwise from the positive x-axis, the coordinates of the corresponding point on the unit circle would be (√3/2, 1/2), which are the values of sine and cosine for that angle.

Additionally, the unit circle provides a convenient way to visualize and understand other trigonometric functions such as tangent, cotangent, secant, and cosecant.

By examining the ratios of the coordinates on the unit circle, we can relate these trigonometric functions to the lengths and angles associated with right triangles.

In summary, the unit circle is a circle centered at the origin with a radius of 1 unit. It plays a fundamental role in trigonometry, providing a geometric representation of the trigonometric functions and aiding in the understanding of angles, ratios, and relationships within the field of mathematics.

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y=3x, y=(2/7)x,-0.5=y are all on direct the other ones are on the other side i just did the question they correct. :)

Answer:

4,600

Step-by-step explanation:

Answer:

Add up the number of chocolate chips and then just search up waht is the median of ____.

Step-by-step explanation:

Hope this helped

Bank B has a basic fee of $9.95 per month and a bill paying fee of $5.95 per month. It has a limit of 20 checks written per month, with a cost of $1 per bill beyond the limit. The total annual cost for Bank B is $174.40.

To compare the cost of online banking, Tim Worker needs to consider various factors, including the basic monthly fee, bill paying monthly fee, limits on the number of checks written, and cost per bill beyond the limit. The basic fee is the amount charged by the bank for providing access to online banking services.

The bill paying fee is charged for each payment made through the online bill pay service. The limit on the number of checks written is the maximum number of checks that can be written in a given month without incurring additional charges. The cost per bill beyond the limit is the amount charged for each bill payment made beyond the specified limit.

Bank B has a basic fee of $9.95 per month and a bill paying fee of $5.95 per month. It has a limit of 20 checks written per month, with a cost of $1 per bill beyond the limit. To calculate the annual cost for Bank B, we can multiply the basic fee and bill paying fee by 12 and add the cost of any additional bills beyond the limit, multiplied by the cost per bill and the number of months in a year.

The total annual cost for Bank B is $174.40, calculated as follows:

Basic fee = $9.95 * 12 = $119.40

Bill paying fee = $5.95 * 12 = $71.40

Cost of bills beyond limit = $1 * (35 - 20) * 12 = $180

Total cost = $119.40 + $71.40 + $180 = $371.80

However, since the cost per bill beyond the limit is capped at $20 per month, the actual cost is $9.95 * 12 + $5.95 * 12 + $20 * 12 = $174.40.

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Answer: If its .05 cents then only 20 cents to finish the collection I got that because 51 - 47= 4 and if it is .05 cents then I did 4 * 5 = 20

We have solved the equation AB=BC for A, assuming that A, B, and C are square matrices and B is invertible, then the solution is A=C B⁻¹.

First, let's take a look at the equation AB=BC. This is an equation that involves matrices, which are essentially rectangular arrays of numbers. In this case, we have three matrices: A, B, and C. The equation tells us that the product of A and B is equal to the product of B and C.

Now, we want to solve this equation for A. This means that we want to isolate A on one side of the equation and have everything else on the other side. To do this, we can use matrix algebra.

One property of matrices is that we can multiply both sides of an equation by the inverse of a matrix without changing the solution. Since we know that B is invertible, we can multiply both sides of the equation by B⁻¹, the inverse of B:

AB B⁻¹ = BC B⁻¹

Now, we can simplify the left side of the equation, because B times its inverse gives us the identity matrix I:

A I = C B⁻¹

Again, we can simplify the left side of the equation, because anything multiplied by the identity matrix stays the same:

A = C B⁻¹

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