Solid to Liquid A particular refrigerator cools by evaporating liquefied dichlorodifluoromethane, CC1,F2. How many kilograms of this liquid must be evaporated to freeze a tray of water at 0°C to ice at 0°C? The mass of the water is 572 g, the heat of fusion of ice is 6.02 kJ/mol, and the heat of vaporization of dichlorodifluoromethane is 17.4 kJ/mol. HOW DO WE GET THERE? The cooling effect as CCI2F2 liquid evaporates is used to freeze water at 0°C to ice. What is the quantity of heat removed from the water to freeze it? KJ Check Next (2 of 3) Submit Answer Try Another Version 10 item attempts remaining

Answer:

Products would be on the right. Reactants would be on the left

Explanation:

If 3580 g of manganomanganic oxide is consumed, 2.01 of moles aluminum oxide produced can be determined using the molar ratios of the balanced chemical equation.

To find the number of moles of aluminum oxide produced, we need to use the molar ratio between manganomanganic oxide and aluminum oxide from the balanced chemical equation. The balanced equation is necessary to establish the stoichiometric relationship between the reactants and products.

Let's assume the balanced equation for the reaction is:

3 Mn₃O₄ + 8 Al → 9 Mn + 4 Al₂O₃

From the balanced equation, we can see that for every 3 moles of Mn₃O₄ consumed, 4 moles of Al₂O₃ are produced.

To calculate the number of moles of Al₂O₃ produced, we can use the following equation:

moles of Al₂O₃  = (mass of Mn₃O₄ consumed / molar mass of Mn₃O₄) * (moles of Al₂O₃  / moles of Mn₃O₄)

=2.01 moles of  Al₂O₃

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The molarity of the hydrogen peroxide solution is calculated to be 0.367875 M.

To determine the molarity of the hydrogen peroxide solution, we can use the balanced chemical equation for the reaction between hydrogen peroxide and permanganate ion:

2MnO4– + 5H2O2 + 6H+ → 2Mn2+ + 5O2 + 8H2O

From the equation, we can see that the ratio of MnO4– to H2O2 is 2:5. Since it takes 13.5 mL of 0.109 M MnO4– to reach the equivalence point, we can calculate the moles of MnO4– used:

moles MnO4– = volume (L) × molarity (mol/L)

= 0.0135 L × 0.109 mol/L

= 0.0014715 mol

Using the ratio, we can calculate the moles of H2O2:

moles H2O2 = (moles MnO4–) × (5/2)

= 0.0014715 mol × (5/2)

= 0.00367875 mol

To find the molarity of the H2O2 solution, we divide the moles of H2O2 by the volume (in L) of the solution titrated:

molarity H2O2 = moles H2O2 / volume (L) = 0.00367875 mol / 0.010 L = 0.367875 M

Therefore, the molarity of the hydrogen peroxide solution is 0.367875 M.

In this question, we are given the volume and molarity of the permanganate ion solution used in the titration of hydrogen peroxide. We can use stoichiometry and the balanced chemical equation to determine the moles of hydrogen peroxide. By dividing the moles of hydrogen peroxide by the volume of the solution titrated, we can find the molarity of the hydrogen peroxide solution.

To begin, we calculate the moles of permanganate ion used by multiplying the volume (in L) of the solution titrated by its molarity. Next, we use the stoichiometric ratio from the balanced chemical equation to calculate the moles of hydrogen peroxide. The ratio shows that for every 2 moles of permanganate ion, there are 5 moles of hydrogen peroxide.

By multiplying the moles of permanganate ion by (5/2), we obtain the moles of hydrogen peroxide. Finally, we divide the moles of hydrogen peroxide by the volume (in L) of the hydrogen peroxide solution titrated to determine its molarity.

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Answer:

Large Cargo Ship

Explanation:

Hope it helped!

The variable that is unknown until the experiment is performed is the dependent variable.

In a scientific experiment, variables are classified into two main categories: independent variables and dependent variables. The independent variable is the variable that is intentionally manipulated or changed by the experimenter. It is under the control of the experimenter and is deliberately altered to observe its effect on the dependent variable.

On the other hand, the dependent variable is the variable that is measured or observed as the outcome or response in the experiment. It is the variable that is expected to change in response to the manipulation of the independent variable. The value or behavior of the dependent variable depends on the value or behavior of the independent variable.

Typically, before conducting an experiment, researchers have a hypothesis or an expectation about how the independent variable will affect the dependent variable. However, the actual outcome or result of the experiment, which is observed through the measurement of the dependent variable, remains unknown until the experiment is performed.

The purpose of conducting the experiment is to gather empirical data and observe the changes in the dependent variable to analyze the relationship between the independent and dependent variables.

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An s w e r:

Explanation:

Explanation:

A substance that breaks apart in water is either an ionic or covalent bond. However, elements of an ionic bond do not dissolve in water. Rather they react with water. Therefore, the correct answer is covalent compound.

Answer:

The correct answer is A.

Answer:

It's the elements atomic mass and the number of neutrons and protons in an atom.

Explanation:

Two-thirds of a bone's weight is composed of calcium phosphate which interacts with calcium hydroxide to form crystals of hydroxyapatite

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We would look at the liquid's solubility as well as boiling point to establish the kind of liquid based on its physical and chemical qualities.

One of the four main states of matter is liquid, the others who were solid, gas, and plasma. A liquid is a form of fluid. In contrast to a solid, those molecules found in a liquid possess significantly more flexibility to move.

The forces that hold molecules together within a solid are really only transient in a liquid, permitting it to flow while still being a solid. We would look at the liquid's solubility as well as boiling point to establish the kind of liquid based on its physical and chemical qualities.

Therefore, we would look at the liquid's solubility as well as boiling point to establish the kind of liquid based on its physical and chemical qualities.

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Your question is incomplete but most probably your full question was,

Describe how you could use the liquid's physical and chemical properties to determine what liquid it might be? solubility, melting point, boiling point

Explanation:

Lithium is an electropositive element that readily loses electrons.

Oxygen is electronegative and it will readily accept electrons.

 Due to this significant electronegativity differences between the two species they form electrovalent or ionic bonds between them.

  2atoms of Li lose two electrons:

      Li  →  Li²⁺ + e⁻

             Lithium isoelectronic with helium

 For oxygen;

      O + 2e⁻   →  O²⁻

                          Oxygen is isoelectronic with Neon

Two ions of the lithium combines with the oxygen to form the bond;

                   4Li + O₂  →  2Li₂O

The electrostatic attraction between the two ions forms the ionic bond

Answer:

d

Explanation:

stop answering people questions and not actually helping them typing random stuff like i just did here

It describes DNA passed from parent to offspring as the driving force of evolution.

What is evolution?

therefore option D is the correct answer.

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The false statement below is B. If ?G < 0, the reaction is spontaneous.

The statement is incomplete and not entirely correct. The Gibbs free energy change (?G) of a reaction determines the spontaneity of a reaction at constant temperature and pressure. A negative? G indicates that the reaction is thermodynamically favorable and spontaneous under standard conditions. However, the value of? G can be affected by changes in temperature, pressure, and concentration of reactants and products.

Regarding statement A, NaI is indeed the reducing agent in this reaction. In this reaction, NaI is oxidized to NaIO3, while HOCl is reduced to HCl.

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The total time to collect a 2D COSY experiment is 3 hours.

A COSY experiment is a correlation spectroscopy experiment that uses two frequency dimensions and two time dimensions.

The time taken to collect a 2D COSY experiment is given by:Total acquisition time = (nr of scans * acquisition time per scan) + relaxation delays + preparation timeThus, the number of scans = 16 per t1 increment.The total number of increments = 51 msec / 0.2 msec = 255.The FID is collected for 1.0 sec.Relaxation delays are typically 1.5 times the repetition delay, which is 2 times the acquisition time per scan. Therefore, relaxation delays = 1.5 × 2 × (2 * 0.2 msec) = 1.2 msecPreparation time = 4 sec. 

Acquisition time per scan = 2 * 0.2 msec = 0.4 msec. Therefore, the total acquisition time = (16 * 0.4 msec * 255) + (1.2 msec * 255) + 4 sec + 1 sec = 58.32 min = 0.972 hoursThus, the total time taken to collect a 2D COSY experiment is 3 hours.

Summary:The total time to collect a 2D COSY experiment is 3 hours.

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The number of hydrogen atoms in a 90.0g sample of camphor C₁₀H₁₆O is 5.68 X 10²⁴.

The mass of 1 mole of a chemical is indicated by its molar mass. It provides you with the amount of grams per mole of a substance, to put it another way.

Given,

Mass of sample of camphor (C₁₀H₁₆O), m = 90.0g

To find: No. of hydrogen atom in given sample.

Molecular mass of camphor is:

M = 152 g/mol

Moles of camphor,

n = m/M

n = 90/152 = 0.59

1 mole of camphor contains 16 moles of Hydrogen

so, 0.59 moles of camphor contains 9.44 moles of hydrogen

1 mole of any substance contain 6.022 X 10²³ no. of atoms/molecule

So, no. of atoms in 9.44 moles of hydrogen is

N = 6.022 X 10²³ X 9.44

N = 56.84 X  10²³

N = 5.68 X 10²⁴

Hence, The number of hydrogen atoms in a 90.0g sample of camphor C₁₀H₁₆O is 5.68 X 10²⁴.

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A block has a density of 1.73 g/mL has a density of  1.73 * 10⁶ mg/L.

The density of a substance is the ratio of the mass of a a given volume of a substance and the volume of that substance.

Mathematically, the density of a substance is given by the formula shown below:

Depending on the units in which the mass and volume of the substance is given, the unit of density can be given as follows:

kilogram per cubic meter; kg/m³

gram per cubic centimeter; g/cm³

gram per liter; g/L

milligram per liter; mg/L

The given block  has a density of 1.73 g/mL.

To convert from gram to mg, we multiply by 1000

1.73 g = 1.73 * 1000 = 1730 mg

to convert from mL to L, we divide by 1000

1 mL = 0.001 L

Density of the block in mg/L = 1730 mg/ 0.001 L

Density of the block in mg/L = 1.73 * 10⁶ mg/L

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Answer:

I think its sun but I'm not sure

Answer - The substance that is produced from a chemical reaction....

REACTANTS

Answer: Remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. Let the TA inspect his wrist to see if it is okay.

Explanation:

The question is incomplete, the choices are:

a. Take him to the safety shower, and make sure he stands under it for at least 15 minutes to be sure all hazardous material has been washed away. b. Remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. c. Let the TA inspect his wrist to see if it is okay.

d. Rinse the watch band before allowing him to put it back on.

An acid is traditionally considered to be any chemical compound that, when dissolved in water, produces a solution with greater hydronium cation activity than pure water, i.e., a pH less than 7. Both corrosive acids (and also corrosive bases) are capable of destroying skin by catalyzing the hydrolysis of fats, which are chemically esters. Also, when acids attack metals, hydrogen gas is often released.

This is why your lab partner should remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. This ensures that the acid is can not damage the skin. And also the person should make sure that someone qualified checks it to see if it is okay.

To solve this problem, we can use the combined gas law equation: P₁V₁/T₁ = P₂V₂/T₂

Where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, and P₂, V₂, and T₂ are the final pressure, volume, and temperature. We are given V₁ = 325 cm³, T₁ = 20°C = 293 K, P₁ = 723 mmHg, and V₂ = 975 cm³ at the same temperature T₂ = 293 K. We need to find P₂. First, we need to convert the initial pressure from mmHg to atm: P₁ = 723 mmHg × 1 atm/760 mmHg = 0.9513 atm. Now we can plug in the values and solve for P₂: P₁V₁/T₁ = P₂V₂/T₂. 0.9513 atm × 325 cm³/293 K = P₂ × 975 cm³/293 K. P₂ = 0.9513 atm × 325 cm³ × 293 K / (975 cm³ × 293 K). P₂ = 0.3164 atm. Therefore, the pressure that must be applied to the neon gas to permit its expansion to a volume of 975 cm³ is approximately 0.3164 atm.

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In Tollen's test, the reaction of aldehydes with silver(i) ions in basic solution results in the formation of silver metal and carboxylate.

Specifically, the reaction involves the oxidation of the aldehyde and the reduction of the silver(i) ion. This can be seen in the reaction of 2 silver 1 ions with a generic aldehyde and 3 hydroxide ions, which produces 2 silver atoms, a generic carboxylate, and 2 water molecules. The species being oxidized in the reaction is the aldehyde, while the species being reduced is the silver(i) ion. The visual indicator of a positive test is the formation of silver metal, which indicates the presence of an aldehyde in the sample.

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In this Tollen's test, the species being oxidized is the aldehyde (RCHO), while the species being reduced is the silver(I) ion (Ag+). The visual indicator of a positive test is the formation of silver metal (Ag), which appears as a shiny silver mirror on the inner surface of the test tube.

In the Tollen's test, the reaction involves aldehydes reacting with silver(I) ions in a basic solution to form silver metal and a carboxylate. The generic equation for this reaction is:

2 Ag+ + RCHO + 3 OH- → 2 Ag + RCOO- + 2 H2O

In the Tollen's test, aldehydes react with silver(i) ions in basic solution to form silver metal and a carboxylate. The reaction involves the oxidation of the aldehyde and reduction of the silver(i) ion. Specifically, in the presence of 2 silver(i) ions and 3 hydroxide ions, a generic aldehyde is oxidized to form a generic carboxylate and 2 water molecules, while the silver(i) ions are reduced to form 2 silver atoms. The visual indicator of a positive test is the formation of silver metal, which indicates the presence of an aldehyde. Therefore, in this reaction, the aldehyde species is being oxidized.

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Answer:

a

Explanation:

A molecular ingredient that could be used in a wall-filling material is C₂₇H₃₆N₂O₁₀, is not a good thermal insulator, hence option A is correct.

The big molecule C₂₇H₃₆N₂O₁₀ is a poor thermal insulator. Since NeNa is a relatively reactive chemical, it would probably dissolve in water far too quickly. The acidic molecule HCl would dissolve far too quickly in water.

Not a good thermal insulator is C₂₇H₃₆N₂O₁₀. It is a big molecule composed of a lot of hydrogen atoms. Since hydrogen atoms are excellent heat conductors, they would be ineffective in stopping heat from passing through a material used to fill a wall.

Thus, the option (A) C₂₇H₃₆N₂O₁₀ is correct.

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A factor which helped to first drive plants to live on land is: A. greater access to sunlight on land.

In Science, photosynthesis is a light-dependent process and it is typically represented by the following chemical reaction:

Carbon dioxide + water + light energy ⇒ sugar + oxygen

Based on the chemical reaction above, we can infer and logically deduce that light energy (sunlight) obtained from the Sun is a very important factor for photosynthesis.

Consequently, greater access to sunlight on land became a factor which helped to first drive plants to live on land.

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Answer:

it is A step by step

Explanation:

The factor that should be calculated to estimate the ability of a specific chemical to enter lipid-rich tissue is the octanol-water partition coefficient (Kow). Kow is a measure of the relative solubility of a compound in octanol (lipid-like) compared to water.

The higher the Kow value, the more likely a chemical is to accumulate in lipid-rich tissue, such as adipose tissue in animals. This is because the chemical has a greater affinity for lipids than for water, and lipid-rich tissues provide a larger reservoir for storage of lipophilic chemicals.

Kow can be used to estimate the bioaccumulation potential of a chemical and its potential for biomagnification in food chains. Chemicals with high Kow values are more likely to accumulate in the fatty tissues of animals and biomagnify up the food chain, potentially causing adverse effects in top predators.

Other factors such as the octanol-air partition coefficient (Koa), the soil-organic carbon partition coefficient (Koc), and the dissolved organic carbon partition coefficient (Kd) may also be relevant for estimating the fate and transport of toxic compounds, depending on the specific environmental compartment of interest. However, for estimating the potential for accumulation in lipid-rich tissue, Kow is typically the most relevant parameter.

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The volume of water added to dissolve potassium hydrogen phthalate (KHP) does not matter because the mass of KHP used is known and it will dissolve completely in any volume of water.

In volumetric analysis, the primary objective is to find the exact concentration of an analyte in a given solution. Analyte refers to the substance whose concentration is to be determined.In order to measure the analyte concentration, the known volume of the titrant of known concentration is added to the analyte until the endpoint is reached.Endpoint refers to the point in a titration where the reaction between the analyte and titrant is complete. The endpoint can be detected by observing a physical change in the system.In the case of KHP, it dissolves completely in any volume of water.

Therefore, the mass of KHP used can be accurately measured and dissolved in any volume of water. As a result, the volume of water added to dissolve the KHP does not affect the accuracy of the experiment.In summary, the volume of water added to dissolve KHP does not matter because the mass of KHP used is known and it will dissolve completely in any volume of water.

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Answer:

A. hydrolysis reaction.

Explanation:

Chemical Reactions.

First, let's review each concept of the group of answer choices:

- hydrolysis: is a reaction in which the net reaction is an organic compound reacting with water to give either two molar equivalents of a single product or more than one product.

- redox: is a type of chemical reaction that involves a transfer of electrons between two species.

- combustion: is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.

- neutralization: is a reaction that occurs when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water.

The problem is asking for the reaction that removes a phosphate group from ATP, so let's see the structure of ATP with one phosphate group:

What is enclosed in the red box is the phosphate group.

The reaction that removes this phosphate group represents a rupture of the structure and based on the logic of the definitions of the given concepts, the answer would be that the reaction to remove one phosphate group from ATP is A. hydrolysis reaction. This reaction looks like this:

ATP + water (H2O) -> ADP + Pi,

where ADP is the same molecule of ATP but it has two phosphate groups and Pi is the phosphate group removed.

Answer:

VSEPR molecular shapes are the substances from the laboratory operation that have more than one central atom.

Explanation:

Molecular shapes from VSEPR

Explanation:

The reason is VSEPR theory, it considers electrons, involved in bond formation as the key part. The pairs of electrons around a central atom, they may be in  sigma bonds, pi bonds, or lone pairs, are always in proximity with the positive nucleus and  as far as possible from each other. Therefore, only the lone pairs on the central atom are taken into consideration when predicting molecular shape.

H2O2 , C2O4,  CH3OH, CH3NH2

substances from the lab activity have more than one central atom

If the reaction is first order with respect to x and second order with respect to y, the rate law can be written as rate = k[X]⁻¹[Y]⁻².

Starting with known concentrations of x and y in experiment 1, the initial rate of formation of z was measured. The initial rate of formation of z in experiment 2 would depend on the new concentrations of x and y. If the new concentrations are different from the initial concentrations used in experiment 1, the initial rate of formation of z in experiment 2 will also be different.

To determine the initial rate of formation of z in experiment 2, the rate law equation would need to be used with the new concentrations of x and y. The units of k, the rate constant, determine the units of the rate.

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--The given question is incomplete, the complete question is

"738; (1,45)(0.042 T Jath) 8518,314(308) 4 OO (3.O0)L85) Ttn (0.0821)(35.0) Enic snele Initial Rate of (Ylo Formation of (moLL- sec 0.101 9l 0.20 Experiment (Xlo 0.40 0.20 The table above shows the results from rate study of the reaction X+Y 2. Starting with known concentrations of X and Y in experiment 1,the rate of formation of Z was measured. If the reaction was first order with respect to( X and second order with respect t0_Y! the initial rate of formation of 2 experiment 2 would be (A) R (B) 2 Cx]" [Y]' 2R Y 1 = 2 1 4R."--

Answer: It is not balanced

Explanation:

lets balance it:

H2SO4+2Na+NO2->2HNO2+Na2SO4

if you count number of elements you'll see they are equal at both sides of equation