Solve 6x + ( 14x - 5 ) + ( 17 - 3x ) , - ( 2 - x ) -3 ( 6 + 8x ) -12, ( 4x - 9 ) + 8 ( 2x + 3 ) -7x

Jesse's ranking is 25th percentile.

Jesse's ranking can be calculated using the following formula:

Percentile = (Jesse's ranking / Total number of students in class) x 100

In this case, Percentile = (45/180) x 100 = 25th Percentile

Therefore, Jesse's ranking is 25th percentile.

To calculate percentile, we divide the rank of the student with the total number of students in the class and then multiply the result with 100. In this case, Jesse was ranked 45th in a class of 180 students and so his percentile is 25%. Percentile is a measure that helps us to compare individuals in a group. It helps us to know the relative performance of a person in a given group of people. Generally, a higher percentile indicates better performance than the other students in the group.

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The numerical value of x in the two congruent alternate exterior angles is 20.

Alternate exterior angle theorem states that "if a transversal intersects two parallel lines, the alternate angle s formed are congruent.

From the diagram, the two angles forms an alternate exterior angle , the two angles are congruent.

( 5x - 8 ) = ( 3x + 32 )

Solve for x

5x - 8 = 3x + 32

Collect like terms by moving all terms containing variable x to left and the constant terms to the right side of the equation.

5x - 8 = 3x + 32

5x - 3x = 32 + 8

2x = 40

Divide both sides by 2

2x/2 = 40/2

x = 40/2

x = 20

Therefore, the numerical value of x is 20.

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Answer:

Yes they are same shape but different size

Step-by-step explanation:

Answer:

Question 1:

1. - 4

2. 4

3. - 15

4. 15

Question 2:

1. - 6

2. 6

3. - 6

Hope this helps :)

Answer:

0.00656

Step-by-step explanation:

Answer:

B.

Step-by-step explanation:

Unit rate is $4.04 per oz

Answer:

900

Step-by-step explanation:

4500/5

Answer: (-4,-2)

Step-by-step explanation:

Looking at the graph, if you move from the zoo downwards for 7 units, you will arrive at point B which is also 2 units from the park.

Point B is therefore the doctor's office and its coordinates are, (-4, -2)

Determining the probability of repayment is not solely determined by the interest rate spread, but also relies on factors such as borrower creditworthiness, loan terms, and the lender's risk assessment methods.

To determine the loan company's expected probability of repayment, we can analyze the interest rate spread between what they charge (15%) and what they borrow at (10%).

The interest rate spread represents the lender's profit margin and accounts for various factors such as default risk, operating costs, and desired return on investment.

In this case, with an interest rate spread of 5% (15% - 10%), the loan company expects to cover its costs and generate profit by lending money to consumers. The wider the interest rate spread, the greater the lender's expected profit.

However, the exact probability of repayment cannot be determined solely based on the interest rate spread. It also depends on other factors like the creditworthiness of borrowers, loan terms, and risk assessment methods employed by the lender.

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The scalar projection is 42/13, and the vector projection is 42/169⟨-5,12⟩.

The scalar projection of b onto a can be calculated using the formula \(\frac{a.b}{|a|}\), and the vector projection of b onto a can be calculated using the formula \(\frac{a.b}{|a|^{2} } .a\). The formula for finding the magnitude of a is |a| = √c²+d² if a = ⟨c,d⟩.

a = ⟨−5, 12⟩, b = ⟨4, 6⟩

a⋅b = ⟨−5, 12⟩⟨4, 6⟩

= -20 + 72

= 42

|a| = √[(-5)² + (12)²]

= √25 + 144

= √169

= 13

The scalar projection is

\(\frac{a.b}{|a|}\) = [⟨−5, 12⟩⟨4, 6⟩]/√[(-5)² + (12)²]

= [-20 + 72]/√25 + 144

= 42/√169

= 42/13

The vector projection is

\(\frac{a.b}{|a|^{2} } .a\) = [42/(13)²] ⟨−5, 12⟩

= 42/169⟨−5, 12⟩

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If we sample the function x(t) = cos(75t) at the Nyquist frequency, the resulting discrete frequency would be half of the Nyquist frequency, which is equal to half of the highest frequency component in the continuous signal.

In this case, the highest frequency component in x(t) is 75 Hz, as determined by the coefficient of t in the cosine function. According to the Nyquist-Shannon sampling theorem, to accurately represent a signal, the sampling frequency must be at least twice the highest frequency component. Therefore, the Nyquist frequency in this scenario would be 2 * 75 Hz = 150 Hz.

Since we are sampling at the Nyquist frequency, the resulting discrete frequency would be half of the Nyquist frequency, which is 150 Hz / 2 = 75 Hz. Hence, when sampling x(t) at the Nyquist frequency, the resulting discrete frequency would be 75 Hz.

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Answer:

8

Step-by-step explanation:

Even though we don't know the number yet, let's name this number "n".

8n + 3 = 6n + 19

8n + 3 - 6n = 6n + 19 - 6n

2n + 3 = 19

2n = 16

n = 16/2

n = 8

Our number is 8.

Note: This answer is 100% correct.  

Answer:

Looks like (0,32)

Step-by-step explanation:

Hard to tell since there is no other data but it appears to be (0,32)

To determine if the linear system corresponding to an augmented matrix [a1 a2 a3 b] has a solution, we can check whether the vector b is in the span of the vectors {a1, a2, a3}.

In linear algebra, the augmented matrix represents a system of linear equations. The columns a1, a2, and a3 correspond to the coefficients of the variables in the system, while the column b represents the constants on the right-hand side of the equations. To check if the system has a solution, we need to determine if the vector b is a linear combination of the vectors a1, a2, and a3.

If the vector b lies in the span of the vectors {a1, a2, a3}, it means that b can be expressed as a linear combination of a1, a2, and a3. In other words, there exist scalars (coefficients) that can be multiplied with a1, a2, and a3 to obtain the vector b. This indicates that there is a solution to the linear system.

On the other hand, if b is not in the span of {a1, a2, a3}, it implies that there is no linear combination of a1, a2, and a3 that can yield the vector b. In this case, the linear system does not have a solution.

Therefore, determining whether the vector b is in the span of {a1, a2, a3} allows us to determine if the linear system corresponding to the augmented matrix [a1 a2 a3 b] has a solution or not.

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Answer:

yes u picked C thats the correct answer

Step-by-step explanation:

Answer:n=-2 or n=4

Step-by-step explanation:

Q is not inversible if det(Q)=0

\(\left|\begin{array}{ccc}6&7&-1\\3&n&5\\9&11&n\end{array}\right| =0\\\\\\\\6(n^2-55)-3(7n+11)+9(35+n)=0\\\\n^2-2n-8=0\\\\\Delta=36=6^2\\\\n=\dfrac{2-6}{2} =-2\ or\ n=\dfrac{2+6}{2}=4\\\)

The height of the box is 2 inches.

Given: A package of gift cards has a length of 8 inches, a width of 4 inches, and a volume of 64 inches cubed.

To Find: The height of the box.

Solution: We can use the volume of a rectangular prism formula to compute the height of the box.

V = l x w x h.

Where V denotes volume,

l denotes length,

w denotes width,

and h denotes height.

It is given that the volume is 64 inches cubed and the length and breadth of the box are 8 and 4 inches, respectively.

Now, the formula becomes h = Volume / (length x width)height

Here, we get,

64 / (8 x 4)h

Now, after solving the above equation with the given formula we get the height of the box = 2 inches.  As a result, the box's height is 2 inches.

Thus, the height of the box is 2 inches.

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Answer:

8

Step-by-step explanation:

Kari has 2 choices for jackets and 4 choices for jumpsuits. We'll multiply those together to find the number of options she has.

Since the numbers are very small, we can grind out this same number (but be organized):

Jean/white

Jean/tan

Jean/green

Jean/black

Leather/white

Leather/tan

Leather/green

Leather/black

These are the eight choices.

Answer:

why don't you copy and paste it

Answer:

--------------------

Area is the product of two dimensions, so the ratio of areas of similar figures is equal to the square of the scale factor k.

Hence the scale factor is:

Therefore the ratio of corresponding parts is:

The Values of (a+b)ab are undefined.

Given that, a = 3an and db = -2We need to find the values of (a+b)

Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1

From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),

we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0

Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined

Therefore, the values of (a+b)ab are undefined.

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\(\stackrel{ \textit{Partial Variation} }{V=aD+bD^2}\qquad \impliedby \begin{array}{llll} \textit{V\textit{ varies partly}}\\ \textit{with D and partly with }D^2 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \textit{we also know that} \begin{cases} V=5\\ D=2\\[-0.5em] \hrulefill\\ V=9\\ D=3 \end{cases}\implies \begin{array}{llll} 5=a2+b2^2&\qquad &5=2a+4b\\\\ 9=a3+b3^2&&9=3a+9b \end{array} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{\textit{using the 1st equation}}{5=2a+4b}\implies 5-2a=4b\implies \cfrac{5-2a}{4}=b \\\\\\ \stackrel{\textit{using the 2nd equation}}{9=3a+9b}\implies \stackrel{\textit{substituting from above}}{9=3a+9\left( \cfrac{5-2a}{4} \right)}\implies 9=3a+\cfrac{45-18a}{4} \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{4}}{4(9)=4\left( 3a+\cfrac{45-18a}{4} \right)}\implies 36=12a+45-18a\implies -9=-6a\)

\(\cfrac{-9}{-6}=a\implies \boxed{\cfrac{3}{2}=a}\hspace{5em}b=\cfrac{5-2\left( \frac{3}{2} \right)}{4}\implies \boxed{b=\cfrac{1}{2}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill V=\cfrac{3}{2}D+\cfrac{1}{2}D^2~\hfill\)

Answer:

Part A: School A Interquartile range = 9.5. School B Interquartile range = 7.5

Part B: There are no outliers present for either data set.

Step-by-step explanation:

For Part A, school A interquantile range is 9.5. Five number summary of school A is minimum = 6, quarantine q1= 6.5, median = 14, quarantine q3 = 16, and maximum = 17. Calculate Q3-Q1 = 16 - 6.5 which gives you 9.5

For School B, the interquartile range is 7.5. Five number of summary of school B is minimum = 5, quarantine q1 = 8, median = 12, quarantine q3= 15.5, maximum = 19. IQR Range = Q3-Q1 = 15.5 - 8. Which gives you 7.5

For Part B: All the outcomes of school A in between the values of -7.75 and 30.25. So this means there is no outliers in school A. For school B, all the outcomes of school B in between the values of -3.25 and 26.75. So there are no outlines in school B.

The measure of angles are

The length of the hypotenuse of the right triangle = 11 inches

The length of the one leg = 10 inches

Then the length of the other leg is the square root of the sum of the hypotenuse square and one leg square

Then the equation will be

The length of the other leg = \(\sqrt{11^2-10^2}\)

= \(\sqrt{121-100}\)

= 4.58 inches

Therefore AC = 11 inches

AB = 10 inches

BC = 4.58 inches

The angle B = 90 degrees

Consider the angle A

cos θ = Adjacent side / hypotenuse

cos θ = 10 /11

θ = 24.61 degrees

Consider the angle C

cos θ = Adjacent side / Hypotenuse

cos θ = 4.58 / 11

θ = 65.39 degrees

Hence, the measure of angles are

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Answer:

Corn Beef = x

Creamed Chipped beef = y

Jan:

2x + 3y = 4.95

Wayne:

3x +2y = 5.95

Graph two equation and find the point where two lines cross and that will be solution.

Point where two lines cross: (1.29, 0.79)

Corn Beef = $1.29

Creamed Chipped Beef = $0.79

Step-by-step explanation:

Greetings from Brasil...

Here we don't have much to go

∛Y = A.(C + 1/X)

∛Y = (AC + A/X)

raising both members to the cube.....

(∛Y)³ = (AC + A/X)³

from Notable Products: (a + b)³ = a³ + 3a²b + 3ab² + b³

Y = (AC)³ + 3(AC)².(A/X) + 3AC(A/X)² + (A/X)³

Y = A³[C³ + (3C²/X) + (3C/X²) + (1/X³)]

Answer:

see below

Step-by-step explanation:

sqrt(20)

sqrt(4*5)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(4) sqrt(5)

2 sqrt(5)

Answer:

We can factor down 20 with it's greatest prime GCF, which is 5. We get a 4. When we factor that down the same way, we get 2. If we repeat that process, we get 5, 2, and 2, which turns into \(2\sqrt{5}\).

Answer:

at least 87

\( \geqslant 87\)

Step-by-step explanation:

danny has at least $15 more than his brother and his brother has $72 that means Danny has at least 15 + 72(his brothers money) it can be 87 or more than 87

Danny's money is

\( \geqslant 87\)

Answer:

3.8

Step-by-step explanation:

delta math gave up