Solve for the measure of arc CH.

For this data set, the equation for the line of greatest fit is provided as y = 10x + 60.

The formula for a linear function's slope-intercept is provided as y = mx + b.

It contains the following coefficients:

The slope, or m, indicates how quickly the output of the function changes in relation to the input.

The value that the function assumes is represented by the y-intercept, or b, where the input value is zero.

The line of fit's intercept b is represented as b = 60 because the function passes through the point (0,60).

The slope m is calculated as follows: m = 20/2 = 10 when x increases by 2, from 0 to 2, and y increases by 20, from 60 to 80.

As a result, the line of best fit is presented as y = 10x + 60.

indicating that the third choice is the best one.

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Answer: \(\frac{1}{3}\) gallon of milk

Step-by-step explanation:

       We will divide 2/3 by 2 to find the answer to this problem.

   Given:

2/3 / 2

   "Keep, change, flip"

2/3 * 1/2

   Multiply and simplify

2/6 = 1/3 gallon of milk

   Another way to this of this is that we have 2 third gallons of milk. If there are two students, then 2 / 2 = 1. Each student will get one-third, or 1/3 gallon of milk.

The Quadratic equation -x² = 8x + 20 does not have real roots.

Given that:

Quadratic equation, -x² = 8x + 20

The quadratic equation is ax² + bx + c = 0. Then the discriminant is given as,

D = b² - 4ac

If D > 0, then the roots are real and distinct root.

If D = 0, then the roots are real and equal roots.

If D < 0, then the roots are imaginary roots.

Simplify the equation, then we have

-x² = 8x + 20

x² + 8x + 20 = 0

The discriminant is calculated as,

D = 8² - 4 × 1 × 20

D = 64 - 80

D = - 16

D < 0

The Quadratic equation -x² = 8x + 20 does not have real roots.

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Answer:

p-(-Q)

Step-by-step explanation:

Because the thing goes down and i got it correct for that answer your welcome

Step-by-step explanation:

\( = \frac{ \frac{3}{x - 2} - 5 }{2 - \frac{4}{x - 2} } \)

\( = \frac{ \frac{3 - 5.(x - 2)}{x - 2} }{ \frac{2.(x - 2) - 4}{x - 2} } \)

\( = \frac{ \frac{3 - 5.(x - 2)}{ \cancel{x - 2}} }{ \frac{2.(x - 2) - 4}{ \cancel{x - 2} }} \)

\( = \frac{3 - 5.(x - 2)}{2.(x - 2) - 4} \)

\( = \frac{3 - 5x + 10}{2x - 4 - 4} \)

\( = \frac{ - 5x + 13}{2x - 8} \)

\( = \frac{13 - 5x}{2x - 8} \)

The answer is D.

The equivalent value of the expression is A = ( 13 - 5x ) / ( 2x - 8 )

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

In an equation, the expressions on either side of the equals sign are called the left-hand side (LHS) and the right-hand side (RHS), respectively. The equals sign (=) indicates that the two expressions have the same value, and that the equation is true for certain values of the variables involved.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. It typically consists mathematical operations, such as addition, subtraction, multiplication, division, and exponentiation.

Given data ,

Let the equation be represented as A

Now , the value of A is

\(A = \frac{\frac{3}{x-2}-5}{2\:-\:\frac{4}{x-2}}\)

On simplifying , we get

\(A = =\frac{\frac{-5x+13}{x-2}}{2-\frac{4}{x-2}}\)

On further simplification , we get

\(A = =\frac{\frac{-5x+13}{x-2}}{\frac{2x-8}{x-2}}\)

Therefore , the value of A is A = ( 13 - 5x ) / ( 2x - 8 )

Hence , the equation is A = ( 13 - 5x ) / ( 2x - 8 )

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Answer:

D.

Step-by-step explanation:

The line will be a straight line and will go through AB in the center. Therefore, it will be the perpendicular bisector.

As per the concept of fraction, the amount time spend for each test is 1.67 hours

In math the term called fraction is known as  the number is expressed as a quotient in which the numerator is divided by the denominator.

Here we have know that Jordan spent 5 hours over the weekend studying for 3 tests.

In order to find the amount of time spend for each test, we have to divide the total number of subject by the time spend by him.

Here the value of total subjects = 5 and the amount of time spend by him is 3.

Then the amount of time time spend for each test is calculated as,

=> 5/3

=> 1.67 hours

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Josephine can choose three books (one chemistry, one history, and one statistics) in 60 ways using the multiplication principle.

To calculate the number of ways Josephine can choose one book of each type to study, we can use the multiplication principle, which states that the total number of outcomes for a sequence of events is the product of the number of outcomes for each event.

So, to solve this problem, we need to multiply the number of ways Josephine can choose one chemistry book, one history book, and one statistics book.

The number of ways to choose one chemistry book from two is 2 (since there are only two options).

The number of ways to choose one history book from three is 3.

The number of ways to choose one statistics book from ten is 10.

Therefore, the total number of ways Josephine can choose one book of each type to study is:

2 x 3 x 10 = 60

So there are 60 ways for Josephine to choose the three books she wants to study.

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Answer:

She is struggling with addition of double-digit numbers

Step-by-step explanation:

She could benefit from a written explanation of vertical addition

Answer:

1 and 7

Step-by-step explanation:

(x+4)(x-2) = x²+2x-8

set up proportion:

2x-3/ x²+2x-8 = 1/5

cross-multiply:

5(2x-3) = x²+2x-8

10x-15 = x²+2x-8

Combine Like Terms:

x²-8x+7

Factor:

(x-7)(x-1)

set each factor equal to zero and solve:  x = 1, x = 7

Answer:

\( \frac{(2x - 3)}{(x + 4)(x - 2)} = \frac{1}{5} \\ \frac{2x - 3}{x {}^{2} - 2x + 4x - 8} = \frac{1}{5} \\ x {}^{2} - 2x + 4x - 8 = 5(2x - 3) \\ x {}^{2} + 2x - 8 = 10x - 15 \\ x {}^{2} + 2x - 10x = - 15 + 8 \\ x { }^{2} - 8x = - 7 \\ x {}^{2} - 8x + 7 = 0 \\ x {}^{2} - x - 7x + 7 = 0 \\ x(x - 1) + 7(x - 1) \\ x + 7 = 0 \\ x = - 7or \\ x - 1 = 0 \\ x = 1\)

Step-by-step explanation:

x=7 or x=1

True. The O-H stretch of a concentrated solution of an alcohol occurs at a lower frequency than the O-H stretch of a dilute solution due to increased hydrogen bonding in the concentrated solution.

The O-H stretch of a concentrated solution of an alcohol occurs at a lower frequency than the O-H stretch of a dilute solution due to intermolecular interactions in the concentrated solution that affect the bonding vibrations.

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False.

The O-H stretch of a concentrated solution of an alcohol occurs at a higher frequency than the O-H stretch of a dilute solution.

In a concentrated solution, the presence of more alcohol molecules results in stronger hydrogen bonding interactions between the alcohol molecules. These stronger interactions lead to a higher bond strength and a higher vibrational frequency, resulting in a higher frequency for the O-H stretch. In a dilute solution, there are fewer alcohol molecules and weaker hydrogen bonding interactions, resulting in a lower bond strength and a lower vibrational frequency, leading to a lower frequency for the O-H stretch.

what is frequency?

Frequency refers to the number of occurrences of a repeating event per unit of time. In the context of waves and vibrations, frequency specifically refers to the number of complete cycles or oscillations of a wave that occur in one second. It is measured in units of hertz (Hz), where one hertz represents one cycle per second.

In simpler terms, frequency describes how often a wave or oscillation repeats within a given time period. A higher frequency means more cycles occur in a given time, while a lower frequency means fewer cycles occur within the same time frame. Frequency is an important property in various fields, including physics, engineering, telecommunications, and music, as it helps characterize and differentiate different types of waves and vibrations.

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The calculated value of the integral \(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx\) is \(\frac{2\ln(k) + 1}{4}\)

From the question, we have the following parameters that can be used in our computation:

\(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx\)

The above expression can be integrated using integration by parts method which states that

∫uv' = uv - ∫u'v

Where

u = ln(kx) and v' = 1/x³ d(x)

This gives

u' = 1/x and g = -1/2x²

So, we have

\(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx = -\frac{\ln(kx)}{2x^2} - \int\limits^{\infty}_1 -\frac{1}{2x^3} \, dx\)

Factor out -1/2

\(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx = -\frac{\ln(kx)}{2x^2} + \frac{1}{2}\int\limits^{\infty}_1 \frac{1}{x^3} \, dx\)

Integrate

\(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx = -\frac{\ln(kx)}{2x^2} - \frac{1}{4x^2}|\limits^{\infty}_1\)

Recall that the x values are from 1 to ∝

This means that

\(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx = 0 -(-\frac{\ln(k * 1}{2(1)^2} - \frac{1}{4 * 1^2})\)

So, we have

\(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx = \frac{\ln(k)}{2} + \frac{1}{4}\)

Express as a single fraction

\(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx = \frac{2\ln(k) + 1}{4}\)

Hence, the value of the integral \(\int\limits^{\infty}_1 {\frac{\ln(kx)}{x^3} \, dx\) is \(\frac{2\ln(k) + 1}{4}\)

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The month for the same plan to be the same for Settle City and Text Turf is 3 months.

It should be noted that Settle city charges $15 plus 5 per month for unlimited text messages text turf. This will be represented as 15 + 5m

It should be noted that when they charge $30 plus $10 per month for the same plan, this will be represented as 30 - 10m

It should be noted that m = number of months.

It should be noted that the number of months that you can take from here to company and pay the same price will be:

15 + 5m = 30 + 10m

15 - 30 = 10m - 5m

-15 = 5m

m = -15 / 5

m = -3

The value can't be negative. The information isn't properly written. It should give a positive value of 3.

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Answer:

s=5

Step-by-step explanation:

72=27+9s

Subtract 27 from both sides.

72-27=9s+27-27

45=9s

Divide 9 from both sides.

5=s

Answer:

(x - 10)² + (y + 4)² = 121

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (10, - 4 ) and r = 11 , then

(x - 10)² + (y - (- 4) )² = 11² , that is

(x - 10)² + (y + 4)² = 121

\(\text{Yesterday} = \$9.80\)

\(\text{Today} = \$9.71\)

\(\% \ \text{Increase} = ((9.71 - 9.80) \div 9.80) \times 100\%\)

                    \(= (-0.09\div9.80) \times 100%\)

                    \(\thickapprox -0.0092 \times 100%\)

                   \(\thickapprox -0.92\%\)

                  \(\thickapprox \bold{-0.9 \%}\)   \(\bold{to \ the \ nearest \ tenth.}\)

Therefore, The density of air enclosed in a sphere with a radius halved will be 9.6 kg/m3. This is because the volume reduces by a factor of 8, resulting in an increase in density by a factor of 8.

When the radius of the sphere is halved, the volume of the sphere reduces by a factor of 8. Since the mass of the air enclosed remains constant, the density of the air within the sphere will increase by a factor of 8. Therefore, the density of the air within the sphere will be 9.6 kg/m3 after compression.
The density of the air enclosed within a sphere is given as 1.2 kg/m3. When the radius of the sphere is halved, the volume of the sphere reduces by a factor of 8 (since volume is proportional to the cube of radius). However, the mass of the air enclosed remains constant. Therefore, the density of the air within the sphere will increase by a factor of 8, resulting in a new density of 9.6 kg/m3.


Therefore, The density of air enclosed in a sphere with a radius halved will be 9.6 kg/m3. This is because the volume reduces by a factor of 8, resulting in an increase in density by a factor of 8.

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A multiple of 2 is any number that can be divided evenly by 2, meaning that its remainder when divided by 2 is 0.

When we have a number ending in 1, such as 11, 21, 31, 41, 51, and so on, we can see that when we divide these numbers by 2, we get a remainder of 1. For example:

11 divided by 2 is 5 with a remainder of 1

21 divided by 2 is 10 with a remainder of 1

31 divided by 2 is 15 with a remainder of 1

This means that these numbers are not divisible by 2 and therefore are not multiples of 2. So any number ending in 1 cannot be a multiple of 2.

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The statement " Rate of college enrollment immediately after completing high school was 67% by 1997" is an example of (a) Descriptive Statistics.

The Descriptive statistics involves the use of measures, such as averages, proportions, and frequencies, to summarize and describe the main features of a set of data.

In this statement, the rate of 67% is a summary statistic that describes the proportion of high school graduates who enrolled in college immediately after completing high school in 1997.

Whereas; the inferential statistics involves making inferences or predictions about a population based on a sample of data.

The statement provides a summary statistic for the rate of college enrollment for a specific year, 1997, but it does not provide any inferences or predictions about the rate of college enrollment for other years or other populations , so it denoted a Descriptive Statistics .

The given question is incomplete , the complete question is

What type of Statistics does the statement "the rate of college enrollment immediately after high school completion was 67" represents ?

(a) Descriptive

(b) Inferential

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Answer:

x=38

Step-by-step explanation:

(2x+5)=(3x-33)

2x-3x=-33-5

-x=-38

x=38

First you will get 4dz

An inequality to determine the rate of temperature decrease in degrees Celsius per day d, from Monday to Thursday is 30°c - 3d \(\leq\) 20°c

Let's assume the constant rate of decreasing the temperature be d degree Celsius.

So, the total decrease in temperature in three days is 3d degree Celsius.

Given,

The temperature on Monday is 30° c

Then,

The temperature on Thursday (which is 3 days later) will be 30°c - 3d

Since the pool opens when the temperature is higher than 20°c,

The equation to determine the rate of temperature decrease in degrees Celsius per day will be 30°c - 3d \(\leq\) 20°c

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Answer:24-25a

Step-by-step explanation:

Answer:

Step-by-step explanation:

a). Ratio of OP and RT = \(\frac{OP}{RT}\)

                                     = \(\frac{12}{3.6}\)

                                     = \(\frac{10}{3}\)

b). Since ΔOPQ ~ ΔRTS, their corresponding sides will be proportional.

    \(\frac{OQ}{RS}=\frac{OP}{RT}\)

    \(\frac{OQ}{4.5}=\frac{10}{3}\)

    OQ = \(\frac{10\times 4.5}{3}\)

    OQ = 15 cm

c). m∠P = m∠T = 60°

d). m∠Q = m∠S

    By applying angle sum theorem in ΔRST,

    m∠R + m∠S + m∠T = 180°

    26° + m∠S + 60° = 180°

    m∠S = 180° - 86°

             = 94°

    Therefore, m∠Q = m∠S = 94°

Answer:

Pythagorean Theorem : a²+b²=c²

a²+38²=42² => a²=1764+1444 => a²=3,208 inch => a=√3,208

=> a=56.64 inch

Step-by-step explanation:

Answer:

Step-by-step explanation:

18 – 21 ft.

Answer:

12+9q−9p

Step-by-step explanation:

−7p+15−2q+11q−2p−3

Combine −2q and 11q to get 9q.

−7p+15+9q−2p−3

Combine −7p and −2p to get −9p.

−9p+15+9q−3

Subtract 3 from 15 to get 12.

−9p+12+9q

Answer: −9p+9q+12

Step-by-step explanation:

the contstants of the p and q variable will add up to 9 and the number will add to 12

Answer:

y + 1 = 3(x + 8)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 3 and (a, b) = (- 8, - 1) , thus

y - (- 1) = 3(x - (- 8)), that is

y + 1 = 3(x + 8)