Solve for unknown.14Y-2 = 2Y + 140

Answers

Answer 1

14Y-2 = 2Y + 140

\(\begin{gathered} 14y-2y=140+2 \\ 12y=142 \\ y=\frac{142}{12} \\ =11.83 \end{gathered}\)

Thus, the value of unknown y is 11.83.


Related Questions

A roller coaster car is released from rest as shown in the image below. If
friction is neglected, the car will oscillate back and forth across the "dip" in
the roller coaster. What is the approximate velocity of the roller coaster car
each time it reaches the bottom of the roller coaster in the image? (Recall
that g = 9.8 m/s2.)
TAS
81 m
O A. 40 m/s
B. 25 m/s
C. 30 m/s
D. 15 m/s

A roller coaster car is released from rest as shown in the image below. Iffriction is neglected, the

Answers

Answer:

40m/s

Explanation:

a=g

u=0

s=81

v²=u²+2as

v²=2(9.81)(81)

v=√1587.6=39.8446985181≈40m/s

The velocity of the roller coaster car each time it reaches the bottom is 40 ms⁻¹. The correct option is (A).

The rate at which the position of an object changes with respect to time is described by the physical quantity known as velocity. It has both magnitude and direction because it is a vector quantity.

Given:

Initial velocity, u = 0 m/s

Acceleration, a = -9.8 ms⁻²

Distance, d = 81 m

From the third equation of motion:

v² = u² - 2as

v² = 0 - 2×(-9.8)×81

v = 40 ms⁻¹

Hence, the velocity of the roller coaster car is 40 ms⁻¹. The correct option is (A).

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Where is the potential energy equal to zero?

Where is the potential energy equal to zero?

Answers

Answer:

im sure your already past this but it's E.

Explanation:

This is because in this case potential energy is linear to height, which means that the higher the more potential energy.

A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. How long until the cannonball hits the ground?
96.7 s
55.3 s
65.3 s
45.5 s

Answers

Answer:

96.7 s

Explanation:

Time of flight in projectile can be calculated thus:

T = 2 × u × sin ϴ/ g

Where;

T = time of flight (s)

u = initial velocity (m/s)

ϴ = Angle of projectile (°)

g = acceleration due to gravity (9.8m/s²)

Based on the provided information; u = 670m/s, ϴ = 45°

Hence, using T = 2.u.sin ϴ/ g

T = 2 × 670 × sin 45° ÷ 9.8

T = 1340 × 0.7071 ÷ 9.8

T = 947.52 ÷ 9.8

T = 96.68

T = 96.7s

a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direct with a speed of 1.3 m/s whats the mass of the cannon.

Answers

The mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.

What is velocity?

When anything is moving, its velocity tells us how rapidly that something's location is changing from a certain vantage point and as measured by a particular unit of time.

If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.

Given:

The mass of the cannonball, m = 5 kg,

The velocity of the cannon, v = 550 m/s,

The recoil speed of the cannon, vₐ = 1.3 m / s,

Then by using momentum conservation calculate the mass of the cannon,

\(m \times v = m_{a} \times v_{a}\)

Here mₐ is the mass of the cannon,

Substitute the values,

5 × 550 = mₐ × 1.3

mₐ = 2115.4 kg

Therefore, the mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.

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In the EXPLORE section of your lesson 4.08 on Potential energy there were several animations to watch that provided a graphic illustrating how the PE and KE in a system changed as a skateboarder rides a halfpipe or a pendulum moves, why did the bar for the total energy remain constant?

Question 8 options:

all answers given are correct

Energy is converted from kinetic to potential and potential to kinetic, but the total amount of energy is conserved

This is because no energy is being created or destroyed in this system

Because these models do not take into account the impact of friction and air resistance and are helping to solidify the concept of energy conservation and that the total mechanical energy remains constant in that model

Answers

Answer:

Answer:B Or the second one

Explanation:

it all stayed consistant.

Answer:

Because these models do not take into account the impact of friction and air resistance and are helping to solidify the concept of energy conservation and that the total mechanical energy remains constant in that model

Explanation:

Im doing the same quiz 0v0

Two charges are repelling each other with a force magnitude F. If each charge doubled and the distance between the charges became four times the original distance, determine the new magnitude of the force. (1/2)F 4F 2F 16 F (1/4)F

Answers

Answer:

(1/4)F

Explanation:

Let F be the force on charges q and q' separated by a distance, d

F = kqq'/d²

Now, if q and q' are doubled, our new charges are 2q and 2q' respectively and, if the distnace is increased by four times, then our new distance is 4d. So our new force F' = k (2q)(2q')/(4d)²

= 4kqq'/16d²

= kqq'/4d²

= F/4

So, the magnitude of our new force is F/4

A 50 kg mass is placed 2 meters from the fulcrum. To balance the lever, a second object is placed 4 meters
from the fulcrum. What is the mass of the second object?

Answers

Answer:

mass =25 kg

using clockwise moment = anticlockwise moment

(a) Calculate the force (in N) the woman in the figure below exerts to do a push-up at constant speed, taking all data to be known to three digits. (You may need to use torque methods from a later chapter.) 401.15
(b)How much work (in J) does she do if her center of mass rises 0.260 m?

(c) What is her useful power output (in W) if she does 30 push-ups in 1 min? (Should work done lowering her body be included? See the discussion of useful work in Work, Energy, and Power in Humans.)

(a) Calculate the force (in N) the woman in the figure below exerts to do a push-up at constant speed,

Answers

the force the woman exerts to do a push-up at constant speed is 333 N.

the work the woman does is 152 J.

her useful power output is 76 W.

(a) To calculate the force the woman exerts to do a push-up, we need to use torque methods. The woman is doing a push-up at constant speed, which means that the net torque on her body is zero. The only torque acting on her body is due to her weight W, which acts at the center of mass of her body. The distance between her center of mass and her hands is 0.76 m, and the angle between her body and the horizontal is 45 degrees.

The torque due to her weight about her hands is given by:

τ = r x W = (0.76 m) x (cos 45°)(W)

where r is the distance between her hands and her center of mass and cos 45° is the component of the distance perpendicular to the weight vector. Since the woman is at constant speed, the torque she exerts about her hands must be equal and opposite to the torque due to her weight. Therefore:

τ = (0.76 m)(cos 45°)(W) = (1/2)(W)(0.76 m)

Solving for W, we get:

W = 2(τ/0.76 m) = 2[(0.5)(mg)(0.76 m)/(0.76 m cos 45°)] = 333 N

Therefore, the force the woman exerts to do a push-up at constant speed is 333 N.

(b) The work the woman does is equal to the change in her potential energy as her center of mass rises. The woman's mass is not given, so we will assume a value of 60 kg. The gravitational potential energy of the woman is given by:

U = mgh

where m is the mass of the woman, g is the acceleration due to gravity (9.81 m/s^2), and h is the height her center of mass rises (0.26 m). Therefore:

U = (60 kg)(9.81 m/s^2)(0.26 m) = 152 J

Therefore, the work the woman does is 152 J.

(c) The useful power output of the woman is the work she does per unit time, taking into account the work done in lowering her body. Each push-up involves two phases: lifting her body and lowering her body. When she lowers her body, the work done is negative, as the force she exerts is in the opposite direction to the displacement. The work done in lowering her body is equal to the work done in lifting her body, so the total work done in one push-up is zero.

The woman does 30 push-ups in 1 minute, which means she does one push-up every 2 seconds. Therefore, the useful power output of the woman is:

P = (152 J)/(2 s) = 76 W

Therefore, her useful power output is 76 W.

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Plot a graph of the pendulum period, T, vs. mass, m, using LabQuest App or graph paper. Scale each axis from the origin (0,0). Does the period appear to depend on mass? Do you have enough data to answer this conclusively?

Plot a graph of the pendulum period, T, vs. mass, m, using LabQuest App or graph paper. Scale each axis

Answers

Given a graph of the period versus the mass.

From the graph, the plot of the period versus mass is almost a horizontal line. That is as the mass of the pendulum increases, its period remains constant. The period of the pendulum is unaffected by the change in the mass. Thus the period of the pendulum does not depend on its mass.

This is also consistent with the formula of the period which is,

\(T=2\pi\sqrt[]{\frac{L}{g}}\)

Where L is the length of the pendulum and g is the acceleration due to gravity.

As seen from the formula the period of the pendulum does not depend on the mass of the pendulum.

Therefore the period of the pendulum does not depend on its mass, this is conclusive from the given data.

at the time a cup of chili is served, its temperature is 170 degrees fahrenheit. the chili's temperature is modeled by the function c, where c(t) is measured in degrees fahrenheit and t is measured in minutes. the rate at which the temperature of the chili is decreasing is given by c(t)

Answers

The rate at which the temperature of the chili is decreasing is given by

c(t)=\(22e^{-0.05t^{2} }\) is 77.267⁰ F.

What do you mean by rate of change of temperature?

The rate of change of temperature, also known as the temperature gradient, is a measure of how quickly the temperature of a system is changing at a given point in space and time. It is typically measured in units of degrees Celsius per second or degrees Fahrenheit per second. The temperature gradient is a vector quantity, with the direction of the gradient pointing in the direction of the greatest temperature change. The magnitude of the gradient is a measure of how quickly the temperature is changing in that direction. The rate of change of temperature can be positive, negative, or zero. A positive rate of change of temperature means that the temperature is increasing, a negative rate of change of temperature means that the temperature is decreasing

Rate of change of temperature over 0 \(\leq\) t \(\leq\) 5.

\(\int\limits^5_0 {c(t)} \, dt = 22\int\limits^5_0 {e^{0.05t^{2} } } \, dt\)

using numerical integration we get value of

\(\int\limits^5_0 {e^{0.05t^{2} } } \, dt=3.51211\\\int\limits^5_0 {c(t)} \, dt= 22* 3.51211=77.26657= 77.267^{0} F\)

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at the time a cup of chili is served, its temperature is 170 degrees fahrenheit. the chili's temperature

What is the answer can you explain it to me

What is the answer can you explain it to me

Answers

Answer:

C) 300 Ohm.

Explanation:

In a series circuit, total resistance is just adding all the resistance together. So R (total) = 75 +75 +75+ 75 = 300 ohms

Parallel circuit are different because you add the inverses of resistance and you flip the final answer.

You can confirm your answers using the tools below:

https://www.omnicalculator.com/physics/series-resistor

https://www.omnicalculator.com/physics/parallel-resistor

In the Skycoaster amusement park ride, riders are suspended from a tower by a long cable. A second cable then lifts them until they reach the starting position indicated in (Figure 1). The lifting cable is then released, and the riders swing down the circular arc shown. If the four riders have a total mass of 330 kg

, what is the tension in the left cable just before release?

Answers

Tension in the left cable is 4395.9 N.

What is meant by tension ?

Tension is defined as a pulling force that acts along the length of a flexible medium like rope or cables.

Here,

The total mass of the riders is given, m = 330 kg

Let the tension in the left cable be T₁ and that in the right cable be T₂.

From the figure,

T₁ cos 15 = T₂ cos 26

T₁ = T₂ cos 26/cos 15

Also,

T₁ sin15 + T₂ sin 26 = mg

Substituting values,

(T₂ cos 26/cos 15) sin 15 + T₂ sin 26 = 330x 9.8

0.241 T₂ + 0.438 T₂ = 3234

0.679 T₂ = 3234

T₂ = 4762.8 N

Therefore, Tension in the left cable, T₁ = 0.930x 4762.8

         T₁ = 4395.9 N

Hence, The tension in the left cable is 4395.9 N

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Your question was incomplete. Attaching the image here.

In the Skycoaster amusement park ride, riders are suspended from a tower by a long cable. A second cable

Melanie gets out of her car at the park. She walks 25 m to the trail entrance.
She jogs around the trail until she reaches a pond, where she stops briefly.
She then continues to follow the trail around the pond. Which reference point
should be used to describe her motion?
A. Her car
B. The trail entrance
C. The pond
D. The trail

Answers

The reference point that should be used to describe Melanie motion is the pond (option C).

What is reference point?

Reference point is a particular point in space which is used as an endpoint to measure a distance from or chart a map from.

According to this question, Melanie gets out of her car at the park and walks 25 m to the trail entrance. She jogs around the trail until she reaches a pond, where she stops briefly.

However, she then continues to follow the trail around the pond. This suggests that the pond should serve as the reference point for Melanie's motion.

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importance of states of matter​

Answers

Answer:

STATES OF MATTER The three important states of the matter are (i) Solid state (ii) Liquid state (iii) Gaseous state, which can exist together at a particular temperature and pressure e.g. water has three states in equilibrium at 4.58 mm and 0.0098ºC.

Explanation:

The Moon is responsible for what % of the tides that we experience?

Answers

Answer: High tides and low tides are caused by the Moon. The Moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the Moon and the side farthest from the Moon. These bulges of water are high tides.

Explanation:

3) A 10 ohm resistor and a 5 ohm resistor are connected in a series. A 2 A current
runs through the 10 ohm resistor. What is the potential difference in the 5 ohm resistor?
a) 10 V
c) 30 V
b) 20V
d) 40 V

Answers

To find the potential difference (V) across a resistor, you can use Ohm's Law, which states that V = I * R, where I is the current and R is the resistance.

In this case, the 10 ohm resistor has a current of 2 A passing through it. Therefore, the potential difference across the 10 ohm resistor is V = 2 A * 10 ohms = 20 V.

Since the 5 ohm resistor is connected in series with the 10 ohm resistor, the potential difference across both resistors will be the same. Thus, the potential difference across the 5 ohm resistor is also 20 V.

Therefore, the correct answer is b) 20 V.
The correct answer is the a) 10V

Explanation:
You know that 10 ohm resistor and 5 ohm resistor are connected in series so the potential difference between the two resistors is different
So you had to do:
∆V2= R2 • I(tot)= 5•2= 10V

Tell me if you need the explanation

Calculate the amount Electrical energy consumed by Electrical motor rated 1.5hp if operated for 7 hours?​

Answers

Answer:

2.82 x 10⁷J

Explanation:

Given parameters:

Power rating of the motor = 1.5hp

Time taken  = 7hrs

Unknown:

Amount of electrical energy consumed  = ?

Solution:

To solve this problem, we need to convert first to standard unit.

              1 hp  =  746 Watts

               1.5hp  =   746 x 1.5  = 1119Watts

Also;

        7hrs to Seconds;

            1 hr  = 3600s

            7hr = 7 x 3600 = 25200s

So;

  Electrical energy = Power x time  = 1119 x 25200 = 2.82 x 10⁷J

Câu 9. Một dây dẫn đồng chất, tiết diện đều 20mm2 có dòng điện không đổi 12A đi qua. Tính trị trung bình mật độ dòng điện j ?

Answers

Answer:

Sorry I can't understand you



O Object A: -2
Object B: -2

Object A: +3
Object B: +4

O Object A: -6
Object B: -4

O Object A: -3
Object B: 0

When the objects interact, which option indicates a possible net charge for each object?

O Object A: -2Object B: -2Object A: +3Object B: +4O Object A: -6Object B: -4O Object A: -3Object B: 0When

Answers

The Judas is at work with a masterpiece the maths of circumference of 98

Discuss the relationship between size and wieght of an object and the amount

Answers

The wieght is the measure of the force of gravity on an object's mass, while mass is the measure of how much matter there is in an object. An object's weight is calculated as the mass of an object in kilograms multiplied by the acceleration of gravity exerted in meters per second squared.

Two 17cm -long thin glass rods uniformly charged to +16nC are placed side by side, 4.0 cm apart. What are the electric field strengths E1, E2, and E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm to the right of the rod on the left, along the line connecting the midpoints of the two rods?

Answers

The required electric field strengths are calculated to be E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.

Length of the two glass rods is given as, L = 17 cm = 0.17 m

Charge on them = 16 nc = 16 × 10⁻⁹ C

Distance between the rods is given as 4 cm = 0.04 m.

Electric charge due to a single glass rod can be given by,

E = Q/ (2π ε₀ r L) ----(1)

(1) can be used to determine E₁, E₂, E₃ because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced.

E₁ = Q/ (2π ε₀ r L) × [1/0.01 - 1/0.03]

⇒ (16 × 10⁻⁹)/(2× 3.14× 8.85 × 10⁻¹² × 0.17) × (66.67)

⇒  (16× 66.67 × 10³)/(9.45) = 112.88 × 10³ N/C

Let us find E₂,

E₂ = Q/ (2π ε₀ r L) × [1/0.02 - 1/0.02] = 0

And E₁ = E₃.

Thus, E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.

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Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!


Here is a function machine.



Input : multiply by 6. Subtract 80: output



The input is the same as the output. Find the input.


Also can you please show me an easy to work out these type of questions

Answers

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

A 10.0 N package of whole wheat flour is suddenly placed on the pan of a scale such as you find in grocery stores. The pan is supported from below by a vertical spring of force constant 395 N/m. If the pan has negligible weight, find the maximum distance the spring will be compressed if no energy is dissipated by friction.

Answers

Answer:

0.025 m

Explanation:

From the question,

Applying Hook's law

F = ke................... Equation 1

Where F = Force, k = spring constant of the scale, e = maximum distance at which the spring will compress.

make e the subject of the equation

e = F/k....................... Equation 2

Given: F = 10 N, e = 395 N/m

Substitute these values into equation 2

e = 10/395

e = 0.025 m

What do you think will happen to the Lunar phases if the moon was hit by an asteroid?

Answers

The Moon is very big, and any small object hitting it would have very little effect on its motion around the Earth, because the Moon's own momentum would overwhelm that of the impact. Most asteroid collisions would result in large craters and little else; even the largest asteroid known, Ceres, wouldn't budge the Moon.

While Kepler supported the Copernican model of the universe Kepler concluded the following

A the circular orbits of the copernican model weren’t correct paths of planets were elliptical

B all other bodies in the universe move around the earth in circular paths

C all other bodies in the universe move around the moon in triangular paths

D the circular orbits of the Copernican model weren’t correct paths of planets were rectangular

Answers

Kepler came to the conclusion that the orbit of earth around the sub is elliptical not circular so it should be A. Good luck and hope this helps

Answer:

Explanation: because Keller concluded that the circular obits of the Copernican model weren't correct paths of planets were elleptical

person pulls a toboggan for a distance of 35.0 m along the snow with a rope directed 32.0o above the snow. The tension in the rope is 105.0 N. How much work is done on the toboggan by the tension force?

Answers

The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ

W = F d cos θ

W = Work done

F = Force

d = Distance

θ = Angle between force and displacement vector

d = 35 m

F = 105 N

θ = 32°

W = 105 * 35 * cos 35°

W = 105 * 35 * 0.85

W = 3123.75 N m

W = 3.12 KJ

Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.

Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ

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Using a coil of wire and a permanent magnet, a student performed an experiment with these steps:Push the magnet into the coil.Let the magnet remain within the coil.Pull the magnet out of the coil.During which steps does an electric current flow through the coil?A. A, B, and CB. Both A and BC. Both A and CD. Both B and C

Answers

Answer:

Both A and C

Explanation:

The current is induced when the magnet is moving in and out of the coil or when the coil is moving back and forth. In this case, the magnet is moving in and out during steps A and C, so there is current in those steps.

What is the acceleration of a 4,000 kg car pushed with a
force of 12,000 N?

Answers

Answer:

3 m/s

Explanation:

A= F/m

12,000/ 4000 = 3

Answer:

3 m/s^2

Explanation:

The equation you have to use is F=ma because the problem is a Newton's 2nd law problem.

Our known values are:

F ( Force ) = 12,000 N

m ( mass ) = 4,000 kg

a ( acceleration ) = ?

Now we plug in the known values into the equation and solve

F=ma

12,000=4,000a

We have to divide 4,000 by both sides to isolate the a value

12,000/4,000=4,000/4,000a

The 4,000s on the right of the equation cancel.

And 12,000 divided by 4,000 equals 3

The acceleration (a) is 3 meters per second squared (m/s^2)

Next, check to make sure 3 does work by plugging it back into the equation.

12,000=4,000*3

12,000=12,000 ✔

As you can see, the acceleration will be 3 m/s^2

A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400Joules of work is done, how much force must have been applied?

4000 N
1600 N
800 N
100 N

Answers

The amount of force that must have been applied is 100 N.

option D is the correct answer.

What is the amount force applied to overcome the load?

The amount of force applied to overcome the load is calculated by applying the formula for work done as shown below.

Mathematically, the formula for work done is given as;

W = Fd

where;

F is the applied forced is the distance moved by the force or effort

If the distance moved by the effort arm is 10 meters, the amount of effort or force applied to overcome the load is calculated as follows;

F = W / d

F = ( 400 J ) / 4 m

F = 100 N

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Determine the kinetic energy of a 2000 kg roller coaster car that is moving at the speed of 10 ms

Answers

Answer:

\(\boxed {\boxed {\sf 100,000 \ Joules}}\)

Explanation:

Kinetic energy is energy due to motion. The formula is half the product of mass and velocity squared.

\(E_k= \frac{1}{2} mv^2\)

The mass of the roller coaster car is 2000 kilograms and the car is moving 10 meters per second.

m= 2000 kg s= 10 m/s

Substitute these values into the formula.

\(E_k= \frac{1}{2} (2000 \ kg ) \times (10 \ m/s)^2\)

Solve the exponent.

(10 m/s)²= 10 m/s * 10 m/s= 100 m²/s²

\(E_k= \frac{1}{2} (2000 \ kg ) \times (100 \ m^2/s^2)\)

Multiply the first two numbers together.

\(E_k= 1000 \ kg \times (100 \ m^2/s^2)\)

Multiply again.

\(E_k= 100,000 \ kg*m^2/s^2\)

1 kilogram square meter per square second is equal to 1 Joule. Our answer of 100,000 kg*m²/s² is equal to 100,000 Joules.

\(E_k= 100,000 \ J\)

The roller coaster car has 100,000 Joules of kinetic energy.

Other Questions
Simplify the below given Boolean equation by K-map method and draw the circuit for minimized equation. Y = A.B(BC) + A.B + A.B.C Parth created a Box-and-Whisker Plot to show the average weight of the fish he caught over the weekend. What information from the 1st Quartile does the graph give you? A. Three fourths of the fish he caught were larger than 22 pounds. B. The average weight of the fish he caught was 40 pounds. C. Three fourths of the fish he caught were less than 22 pounds. D. The largest fish he caught was 63 pounds. Preparingjoumal entries 3 03, 35 Progare jourtal entrist for the folowing thinsericas that ocestred during 2020 . Q5 2.13 Preparingjounal entries O 203,0,05 + Purchsed afice supplics en crefin for 5140 . I5 Prid 5300 regarding tic office suppies perchas of lanary 4. 16 Purchad 5700 of ofice supliss oc acount. Evercise 2.7 Analyzing and journalizing revenue transacions (.03, [Q. 5 Examine the folloming transections and identify those that created rectues for TII Sericing, a sole proprietonhip onted by Todd [rer. Prepare genera journal entries to record those transactions and expin atw the ocher transuctions did not creste revenues. a. Inessed 576,500 cash in the business. b. Prorided $2,700 of serrices on eredit. c. Received 53,150 cash for services provided to a cient. d. Received $18,300 from a client in pusment for services to be powided nect jear. e. Received $9,000 from a client in partial puyment of an account reckiable. 1. Borrowed 5300,000 from the bank by signing a promissony note. Evercise 2. Analyzing and journalizing expense transactions 00 33, 95 Myra Sharma owns and operates a yoga studio, Green Yoga. Eunine the followiag transactions and ilentify those that crested expenses for Green Yoga. Prepart journal entries to record those transuctions and explin why the other rransuctions did not create expenses. 2. Paid 514.100 cash for office supplics purchased 30 dyys prosivesty. b. Piid the 51,125 salary of the receptionis. c. Paid S45,000 cash for yoge stodio equipment. d. Paid utility bill with 5930 cash. e. Withdrew 55,000 from the business 2500 unt for personal Use. Use Excel to nd the z-scores that bound the middle 82% of thearea under the standard normal curve. Enter the answers inascending order. Round the answers to two decimal places. Thez-scores for t Attribution for a desired event (e.g., a click) should be given to: 5Select the correct answerWhich system of equations is represented by this graph? How are the lenses of 3-D glasses polarized?Both lenses are polarized horizontally.Both lenses are polarized vertically.They are not polarized.One lens is polarized horizontally, and one is polarized vertically. Most of the significant decisions in contemporary organizations are made under which decision-making condition? ANSWER PLEASE 15 POINTS!!!!!Point D is the center of the given circle. What is the measure of Ac?A. 4848B. 96BoC. 84D. 24 two 4.6 cmcm 4.6 cmcm metal plates are separated by a 0.22-mmmm-thick piece of teflon. part a what is the capacitance? express your answer with the appropriate units. solve the differential equation. (2 + t) du/dt + u = 2 + t, t > 0. A. u = 2t + t2 + C/t + 2 B. u = t2 + C/t + 2 C. u = 2t + 1/2t2/3/2t + 2 + C D. u = 2t + t2/2 + C/t + 2 E. u = 2t + t2/2 + C during the latter part of the 20th century, several groups recognized that eating too much of specific foods led to chronic diseases. which groups were these? What is meant by solution which has high concentration of water ? what did sherman land and the establishment of the bureau of refugees, freedmen, and abandoned lands demonstrate to southerners about reconstruction Translate the following latin sentence without using google translateDxit eum Rm crs discessrum esse. Salmonella, shigella, yersinia, and serratia are all. How would you describe the Northern Cheyenne in "A Brief History of the Northern Cheyenne"? Use evidence from the selection to support your answer.(Counts as 10% of your Lesson grade.) PLS HELP WILL GIVE BRAINLEST 100Pts!!!ANSWER ALL QUESTIONS!21. The value of a new car can depreciate (loses value) in many ways. First, a new car can depreciate in value up to 25% once it is purchased and driven off the car lot. After that the value of the car depreciates each year because it is one year older let's consider two different new cars.What is the value of car A and car B immediately after they are purchased and driven off the car lot?22. Complete the table and find the value of each vehicle at the end of the indicated year.23. Find the constant rate of change in the value of car A and in the value of car B after the initial depreciation.24. Based on the data in the table and the constant rate of changes for each vehicle, write an equation to predict the vaule of Car A and Car B at the end of t years. how do pollution and disease affect your population? do either of them change the carrying capacity? For a fixed baseline, at what point does parallax cease to be an accurate technique for measuring distance? (Do not say 10 kiloparsecs.) What are two ways that you could more accurately measure the distance to an object using parallax?