14Y-2 = 2Y + 140
\(\begin{gathered} 14y-2y=140+2 \\ 12y=142 \\ y=\frac{142}{12} \\ =11.83 \end{gathered}\)Thus, the value of unknown y is 11.83.
A roller coaster car is released from rest as shown in the image below. If
friction is neglected, the car will oscillate back and forth across the "dip" in
the roller coaster. What is the approximate velocity of the roller coaster car
each time it reaches the bottom of the roller coaster in the image? (Recall
that g = 9.8 m/s2.)
TAS
81 m
O A. 40 m/s
B. 25 m/s
C. 30 m/s
D. 15 m/s
Answer:
40m/s
Explanation:
a=g
u=0
s=81
v²=u²+2as
v²=2(9.81)(81)
v=√1587.6=39.8446985181≈40m/s
The velocity of the roller coaster car each time it reaches the bottom is 40 ms⁻¹. The correct option is (A).
The rate at which the position of an object changes with respect to time is described by the physical quantity known as velocity. It has both magnitude and direction because it is a vector quantity.
Given:
Initial velocity, u = 0 m/s
Acceleration, a = -9.8 ms⁻²
Distance, d = 81 m
From the third equation of motion:
v² = u² - 2as
v² = 0 - 2×(-9.8)×81
v = 40 ms⁻¹
Hence, the velocity of the roller coaster car is 40 ms⁻¹. The correct option is (A).
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Where is the potential energy equal to zero?
Answer:
im sure your already past this but it's E.
Explanation:
This is because in this case potential energy is linear to height, which means that the higher the more potential energy.
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. How long until the cannonball hits the ground?
96.7 s
55.3 s
65.3 s
45.5 s
Answer:
96.7 s
Explanation:
Time of flight in projectile can be calculated thus:
T = 2 × u × sin ϴ/ g
Where;
T = time of flight (s)
u = initial velocity (m/s)
ϴ = Angle of projectile (°)
g = acceleration due to gravity (9.8m/s²)
Based on the provided information; u = 670m/s, ϴ = 45°
Hence, using T = 2.u.sin ϴ/ g
T = 2 × 670 × sin 45° ÷ 9.8
T = 1340 × 0.7071 ÷ 9.8
T = 947.52 ÷ 9.8
T = 96.68
T = 96.7s
a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direct with a speed of 1.3 m/s whats the mass of the cannon.
The mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.
What is velocity?When anything is moving, its velocity tells us how rapidly that something's location is changing from a certain vantage point and as measured by a particular unit of time.
If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.
Given:
The mass of the cannonball, m = 5 kg,
The velocity of the cannon, v = 550 m/s,
The recoil speed of the cannon, vₐ = 1.3 m / s,
Then by using momentum conservation calculate the mass of the cannon,
\(m \times v = m_{a} \times v_{a}\)
Here mₐ is the mass of the cannon,
Substitute the values,
5 × 550 = mₐ × 1.3
mₐ = 2115.4 kg
Therefore, the mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.
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In the EXPLORE section of your lesson 4.08 on Potential energy there were several animations to watch that provided a graphic illustrating how the PE and KE in a system changed as a skateboarder rides a halfpipe or a pendulum moves, why did the bar for the total energy remain constant?
Question 8 options:
all answers given are correct
Energy is converted from kinetic to potential and potential to kinetic, but the total amount of energy is conserved
This is because no energy is being created or destroyed in this system
Because these models do not take into account the impact of friction and air resistance and are helping to solidify the concept of energy conservation and that the total mechanical energy remains constant in that model
Answer:
Answer:B Or the second one
Explanation:
it all stayed consistant.
Answer:
Because these models do not take into account the impact of friction and air resistance and are helping to solidify the concept of energy conservation and that the total mechanical energy remains constant in that model
Explanation:
Im doing the same quiz 0v0
Two charges are repelling each other with a force magnitude F. If each charge doubled and the distance between the charges became four times the original distance, determine the new magnitude of the force. (1/2)F 4F 2F 16 F (1/4)F
Answer:
(1/4)F
Explanation:
Let F be the force on charges q and q' separated by a distance, d
F = kqq'/d²
Now, if q and q' are doubled, our new charges are 2q and 2q' respectively and, if the distnace is increased by four times, then our new distance is 4d. So our new force F' = k (2q)(2q')/(4d)²
= 4kqq'/16d²
= kqq'/4d²
= F/4
So, the magnitude of our new force is F/4
A 50 kg mass is placed 2 meters from the fulcrum. To balance the lever, a second object is placed 4 meters
from the fulcrum. What is the mass of the second object?
Answer:
mass =25 kg
using clockwise moment = anticlockwise moment
(a) Calculate the force (in N) the woman in the figure below exerts to do a push-up at constant speed, taking all data to be known to three digits. (You may need to use torque methods from a later chapter.) 401.15
(b)How much work (in J) does she do if her center of mass rises 0.260 m?
(c) What is her useful power output (in W) if she does 30 push-ups in 1 min? (Should work done lowering her body be included? See the discussion of useful work in Work, Energy, and Power in Humans.)
the force the woman exerts to do a push-up at constant speed is 333 N.
the work the woman does is 152 J.
her useful power output is 76 W.
(a) To calculate the force the woman exerts to do a push-up, we need to use torque methods. The woman is doing a push-up at constant speed, which means that the net torque on her body is zero. The only torque acting on her body is due to her weight W, which acts at the center of mass of her body. The distance between her center of mass and her hands is 0.76 m, and the angle between her body and the horizontal is 45 degrees.
The torque due to her weight about her hands is given by:
τ = r x W = (0.76 m) x (cos 45°)(W)
where r is the distance between her hands and her center of mass and cos 45° is the component of the distance perpendicular to the weight vector. Since the woman is at constant speed, the torque she exerts about her hands must be equal and opposite to the torque due to her weight. Therefore:
τ = (0.76 m)(cos 45°)(W) = (1/2)(W)(0.76 m)
Solving for W, we get:
W = 2(τ/0.76 m) = 2[(0.5)(mg)(0.76 m)/(0.76 m cos 45°)] = 333 N
Therefore, the force the woman exerts to do a push-up at constant speed is 333 N.
(b) The work the woman does is equal to the change in her potential energy as her center of mass rises. The woman's mass is not given, so we will assume a value of 60 kg. The gravitational potential energy of the woman is given by:
U = mgh
where m is the mass of the woman, g is the acceleration due to gravity (9.81 m/s^2), and h is the height her center of mass rises (0.26 m). Therefore:
U = (60 kg)(9.81 m/s^2)(0.26 m) = 152 J
Therefore, the work the woman does is 152 J.
(c) The useful power output of the woman is the work she does per unit time, taking into account the work done in lowering her body. Each push-up involves two phases: lifting her body and lowering her body. When she lowers her body, the work done is negative, as the force she exerts is in the opposite direction to the displacement. The work done in lowering her body is equal to the work done in lifting her body, so the total work done in one push-up is zero.
The woman does 30 push-ups in 1 minute, which means she does one push-up every 2 seconds. Therefore, the useful power output of the woman is:
P = (152 J)/(2 s) = 76 W
Therefore, her useful power output is 76 W.
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Plot a graph of the pendulum period, T, vs. mass, m, using LabQuest App or graph paper. Scale each axis from the origin (0,0). Does the period appear to depend on mass? Do you have enough data to answer this conclusively?
Given a graph of the period versus the mass.
From the graph, the plot of the period versus mass is almost a horizontal line. That is as the mass of the pendulum increases, its period remains constant. The period of the pendulum is unaffected by the change in the mass. Thus the period of the pendulum does not depend on its mass.
This is also consistent with the formula of the period which is,
\(T=2\pi\sqrt[]{\frac{L}{g}}\)Where L is the length of the pendulum and g is the acceleration due to gravity.
As seen from the formula the period of the pendulum does not depend on the mass of the pendulum.
Therefore the period of the pendulum does not depend on its mass, this is conclusive from the given data.
at the time a cup of chili is served, its temperature is 170 degrees fahrenheit. the chili's temperature is modeled by the function c, where c(t) is measured in degrees fahrenheit and t is measured in minutes. the rate at which the temperature of the chili is decreasing is given by c(t)
The rate at which the temperature of the chili is decreasing is given by
c(t)=\(22e^{-0.05t^{2} }\) is 77.267⁰ F.
What do you mean by rate of change of temperature?The rate of change of temperature, also known as the temperature gradient, is a measure of how quickly the temperature of a system is changing at a given point in space and time. It is typically measured in units of degrees Celsius per second or degrees Fahrenheit per second. The temperature gradient is a vector quantity, with the direction of the gradient pointing in the direction of the greatest temperature change. The magnitude of the gradient is a measure of how quickly the temperature is changing in that direction. The rate of change of temperature can be positive, negative, or zero. A positive rate of change of temperature means that the temperature is increasing, a negative rate of change of temperature means that the temperature is decreasing
Rate of change of temperature over 0 \(\leq\) t \(\leq\) 5.
\(\int\limits^5_0 {c(t)} \, dt = 22\int\limits^5_0 {e^{0.05t^{2} } } \, dt\)
using numerical integration we get value of
\(\int\limits^5_0 {e^{0.05t^{2} } } \, dt=3.51211\\\int\limits^5_0 {c(t)} \, dt= 22* 3.51211=77.26657= 77.267^{0} F\)
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What is the answer can you explain it to me
Answer:
C) 300 Ohm.
Explanation:
In a series circuit, total resistance is just adding all the resistance together. So R (total) = 75 +75 +75+ 75 = 300 ohms
Parallel circuit are different because you add the inverses of resistance and you flip the final answer.
You can confirm your answers using the tools below:
https://www.omnicalculator.com/physics/series-resistor
https://www.omnicalculator.com/physics/parallel-resistor
In the Skycoaster amusement park ride, riders are suspended from a tower by a long cable. A second cable then lifts them until they reach the starting position indicated in (Figure 1). The lifting cable is then released, and the riders swing down the circular arc shown. If the four riders have a total mass of 330 kg
, what is the tension in the left cable just before release?
Tension in the left cable is 4395.9 N.
What is meant by tension ?Tension is defined as a pulling force that acts along the length of a flexible medium like rope or cables.
Here,
The total mass of the riders is given, m = 330 kg
Let the tension in the left cable be T₁ and that in the right cable be T₂.
From the figure,
T₁ cos 15 = T₂ cos 26
T₁ = T₂ cos 26/cos 15
Also,
T₁ sin15 + T₂ sin 26 = mg
Substituting values,
(T₂ cos 26/cos 15) sin 15 + T₂ sin 26 = 330x 9.8
0.241 T₂ + 0.438 T₂ = 3234
0.679 T₂ = 3234
T₂ = 4762.8 N
Therefore, Tension in the left cable, T₁ = 0.930x 4762.8
T₁ = 4395.9 N
Hence, The tension in the left cable is 4395.9 N
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Your question was incomplete. Attaching the image here.
Melanie gets out of her car at the park. She walks 25 m to the trail entrance.
She jogs around the trail until she reaches a pond, where she stops briefly.
She then continues to follow the trail around the pond. Which reference point
should be used to describe her motion?
A. Her car
B. The trail entrance
C. The pond
D. The trail
The reference point that should be used to describe Melanie motion is the pond (option C).
What is reference point?Reference point is a particular point in space which is used as an endpoint to measure a distance from or chart a map from.
According to this question, Melanie gets out of her car at the park and walks 25 m to the trail entrance. She jogs around the trail until she reaches a pond, where she stops briefly.
However, she then continues to follow the trail around the pond. This suggests that the pond should serve as the reference point for Melanie's motion.
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importance of states of matter
Answer:
STATES OF MATTER The three important states of the matter are (i) Solid state (ii) Liquid state (iii) Gaseous state, which can exist together at a particular temperature and pressure e.g. water has three states in equilibrium at 4.58 mm and 0.0098ºC.
Explanation:
The Moon is responsible for what % of the tides that we experience?
Answer: High tides and low tides are caused by the Moon. The Moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the Moon and the side farthest from the Moon. These bulges of water are high tides.
Explanation:
3) A 10 ohm resistor and a 5 ohm resistor are connected in a series. A 2 A current
runs through the 10 ohm resistor. What is the potential difference in the 5 ohm resistor?
a) 10 V
c) 30 V
b) 20V
d) 40 V
Calculate the amount Electrical energy consumed by Electrical motor rated 1.5hp if operated for 7 hours?
Answer:
2.82 x 10⁷J
Explanation:
Given parameters:
Power rating of the motor = 1.5hp
Time taken = 7hrs
Unknown:
Amount of electrical energy consumed = ?
Solution:
To solve this problem, we need to convert first to standard unit.
1 hp = 746 Watts
1.5hp = 746 x 1.5 = 1119Watts
Also;
7hrs to Seconds;
1 hr = 3600s
7hr = 7 x 3600 = 25200s
So;
Electrical energy = Power x time = 1119 x 25200 = 2.82 x 10⁷J
Câu 9. Một dây dẫn đồng chất, tiết diện đều 20mm2 có dòng điện không đổi 12A đi qua. Tính trị trung bình mật độ dòng điện j ?
Answer:
Sorry I can't understand you
O Object A: -2
Object B: -2
Object A: +3
Object B: +4
O Object A: -6
Object B: -4
O Object A: -3
Object B: 0
When the objects interact, which option indicates a possible net charge for each object?
Discuss the relationship between size and wieght of an object and the amount
Two 17cm -long thin glass rods uniformly charged to +16nC are placed side by side, 4.0 cm apart. What are the electric field strengths E1, E2, and E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm to the right of the rod on the left, along the line connecting the midpoints of the two rods?
The required electric field strengths are calculated to be E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.
Length of the two glass rods is given as, L = 17 cm = 0.17 m
Charge on them = 16 nc = 16 × 10⁻⁹ C
Distance between the rods is given as 4 cm = 0.04 m.
Electric charge due to a single glass rod can be given by,
E = Q/ (2π ε₀ r L) ----(1)
(1) can be used to determine E₁, E₂, E₃ because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced.
E₁ = Q/ (2π ε₀ r L) × [1/0.01 - 1/0.03]
⇒ (16 × 10⁻⁹)/(2× 3.14× 8.85 × 10⁻¹² × 0.17) × (66.67)
⇒ (16× 66.67 × 10³)/(9.45) = 112.88 × 10³ N/C
Let us find E₂,
E₂ = Q/ (2π ε₀ r L) × [1/0.02 - 1/0.02] = 0
And E₁ = E₃.
Thus, E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.
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Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!
Here is a function machine.
Input : multiply by 6. Subtract 80: output
The input is the same as the output. Find the input.
Also can you please show me an easy to work out these type of questions
Answer:
Explanation:
Sure, I'd be happy to help you with the question!
Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.
So, the function can be written as:
Output = (6 * x) - 80
Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:
x = (6 * x) - 80
Let's solve this equation to find the value of x:
x = 6x - 80
Subtracting 6x from both sides, we get:
x - 6x = -80
Combining like terms, we have:
-5x = -80
Dividing both sides by -5, we find:
x = (-80) / (-5)
Simplifying the expression, we have:
x = 16
Therefore, the input (x) that results in the input being the same as the output is 16.
To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.
Answer:
16
Explanation:
(x*6) - 80 = x
Multiply the parentheses
6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16
A 10.0 N package of whole wheat flour is suddenly placed on the pan of a scale such as you find in grocery stores. The pan is supported from below by a vertical spring of force constant 395 N/m. If the pan has negligible weight, find the maximum distance the spring will be compressed if no energy is dissipated by friction.
Answer:
0.025 m
Explanation:
From the question,
Applying Hook's law
F = ke................... Equation 1
Where F = Force, k = spring constant of the scale, e = maximum distance at which the spring will compress.
make e the subject of the equation
e = F/k....................... Equation 2
Given: F = 10 N, e = 395 N/m
Substitute these values into equation 2
e = 10/395
e = 0.025 m
What do you think will happen to the Lunar phases if the moon was hit by an asteroid?
While Kepler supported the Copernican model of the universe Kepler concluded the following
A the circular orbits of the copernican model weren’t correct paths of planets were elliptical
B all other bodies in the universe move around the earth in circular paths
C all other bodies in the universe move around the moon in triangular paths
D the circular orbits of the Copernican model weren’t correct paths of planets were rectangular
Answer:
Explanation: because Keller concluded that the circular obits of the Copernican model weren't correct paths of planets were elleptical
person pulls a toboggan for a distance of 35.0 m along the snow with a rope directed 32.0o above the snow. The tension in the rope is 105.0 N. How much work is done on the toboggan by the tension force?
The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ
W = F d cos θ
W = Work done
F = Force
d = Distance
θ = Angle between force and displacement vector
d = 35 m
F = 105 N
θ = 32°
W = 105 * 35 * cos 35°
W = 105 * 35 * 0.85
W = 3123.75 N m
W = 3.12 KJ
Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.
Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ
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Using a coil of wire and a permanent magnet, a student performed an experiment with these steps:Push the magnet into the coil.Let the magnet remain within the coil.Pull the magnet out of the coil.During which steps does an electric current flow through the coil?A. A, B, and CB. Both A and BC. Both A and CD. Both B and C
Answer:
Both A and C
Explanation:
The current is induced when the magnet is moving in and out of the coil or when the coil is moving back and forth. In this case, the magnet is moving in and out during steps A and C, so there is current in those steps.
What is the acceleration of a 4,000 kg car pushed with a
force of 12,000 N?
Answer:
3 m/s
Explanation:
A= F/m
12,000/ 4000 = 3
Answer:
3 m/s^2
Explanation:
The equation you have to use is F=ma because the problem is a Newton's 2nd law problem.
Our known values are:
F ( Force ) = 12,000 N
m ( mass ) = 4,000 kg
a ( acceleration ) = ?
Now we plug in the known values into the equation and solve
F=ma
12,000=4,000a
We have to divide 4,000 by both sides to isolate the a value
12,000/4,000=4,000/4,000a
The 4,000s on the right of the equation cancel.
And 12,000 divided by 4,000 equals 3
The acceleration (a) is 3 meters per second squared (m/s^2)
Next, check to make sure 3 does work by plugging it back into the equation.
12,000=4,000*3
12,000=12,000 ✔
As you can see, the acceleration will be 3 m/s^2
A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400Joules of work is done, how much force must have been applied?
4000 N
1600 N
800 N
100 N
The amount of force that must have been applied is 100 N.
option D is the correct answer.
What is the amount force applied to overcome the load?
The amount of force applied to overcome the load is calculated by applying the formula for work done as shown below.
Mathematically, the formula for work done is given as;
W = Fd
where;
F is the applied forced is the distance moved by the force or effortIf the distance moved by the effort arm is 10 meters, the amount of effort or force applied to overcome the load is calculated as follows;
F = W / d
F = ( 400 J ) / 4 m
F = 100 N
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Determine the kinetic energy of a 2000 kg roller coaster car that is moving at the speed of 10 ms
Answer:
\(\boxed {\boxed {\sf 100,000 \ Joules}}\)
Explanation:
Kinetic energy is energy due to motion. The formula is half the product of mass and velocity squared.
\(E_k= \frac{1}{2} mv^2\)
The mass of the roller coaster car is 2000 kilograms and the car is moving 10 meters per second.
m= 2000 kg s= 10 m/sSubstitute these values into the formula.
\(E_k= \frac{1}{2} (2000 \ kg ) \times (10 \ m/s)^2\)
Solve the exponent.
(10 m/s)²= 10 m/s * 10 m/s= 100 m²/s²\(E_k= \frac{1}{2} (2000 \ kg ) \times (100 \ m^2/s^2)\)
Multiply the first two numbers together.
\(E_k= 1000 \ kg \times (100 \ m^2/s^2)\)
Multiply again.
\(E_k= 100,000 \ kg*m^2/s^2\)
1 kilogram square meter per square second is equal to 1 Joule. Our answer of 100,000 kg*m²/s² is equal to 100,000 Joules.\(E_k= 100,000 \ J\)
The roller coaster car has 100,000 Joules of kinetic energy.