Solve for x!!! Help please this is urgent!!!

Answer:12

Step-by-step explanation:

ez

Answer:

$1,350

Step-by-step explanation:

Simple interest formula

I = Prt

where:

Given:

⇒ Total interest earned = 1000 × 0.1 × 5 = $500

If you have to pay 30% income tax on the interest earned annually, then you will keep 70% of your earned interest.

⇒ 70% of $500 = 0.7 × $500 = $350

Account balance = principal + interest earned after tax

                             = $1,000 + $350

                             = $1,350

Answer: 47.5

Step-by-step explanation:

Answer:

y=4x-8 hope this helps:)

Step-by-step explanation:

Hey there!!

You can find the equation of a st.line passing through points using one point formula if only one point is given and slope is given , else find it by using two point formula (if 2 points are given).

Here, the points are, (4,8) and (-1,-12).

Using two point formula,

\((y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)\)

Keep all values,

\((y - 8) = \frac{ - 12 - 8}{ - 1 - 4} (x - 4)\)

Now, simplify them.

\((y - 8) = 5(x - 4)\)

y - 8 = 5x -20

5x -y -20+8 = 0

Therefore, 5x - y -12 = 0 is the required equation.

Hope it helps...

Answer:

a. 7(x+2)

b. 9(x-3)

c. 5(2y-5)

d. 4(2n+7)

e. -3(x+9)

f. -6(x-5)

Step-by-step explanation:

hope this helped <3

Answer:

a. 7(x + 2)

b. 9(x - 3)

c. 5(2y - 5)

d. 2(4n + 7)

e. -3(x + 9)

f. 6(-x + 5)

Step-by-step explanation:

Use distribution for all questions

a. Factor by 7, the greatest common factor.

7x + 14 = 7(x + 2)

b. Factor by 9

9x - 27 = 9(x - 3)

c. Factor by 5

10y - 25 = 5(2y - 5)

d. Factor by 4

8n + 28 = 2(4n + 7)

e. Factor by -3

-3x - 27 = -3(x + 9)

f. Factor by 6

-6x + 30 = 6(-x + 5)

Hope this helps!!

Please mark me brainliest if it is correct :)

The measure of angle ABP from the given circle is 90°.

From the given figure,

11) Measure of angle ABP is 90°.

12) Measure of angle BAK is 180°-(90°+25°)

= 180°-115°

= 65°

13) Measure of angle AQP is 90°.

14) Measure of angle QAK is 180°-(90°+25°) (Because ∠BPA=∠QPA=25°)

15) Measure of Arc BK = Measure of angle BAK = 65°

16) Measure of Arc BQ = Measure of angle BAQ = 65°×2

= 130°

17) m∠CAD=m∠BAK=65°

Therefore, the measure of angle ABP from the given circle is 90°.

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The number of ways to order the first, second and third place finishers is simply the number of permutations of 8 runners taken 3 at a time. This can be calculated using the formula for permutations

The formula for permutations, P(n,r), gives the number of ways to choose r items from a set of n items, where order matters. This formula is calculated as:

P(n,r) = n! / (n-r)!

where n! represents the factorial of n (i.e. n multiplied by n-1 multiplied by n-2, etc. down to 1).

In this problem, n = 8 and r = 3, so the number of permutations is:

P(8,3) = 8! / (8-3)! = 8! / 5! = 40320 / 120 = 336

So there are 336 different arrangements of first, second, and third place finishers in the 100-meter sprint.

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Answer:

This gives us a square with an area of 225 square units.

Step-by-step explanation:

To find the dimensions of the rectangle with the largest area for a given perimeter of 60, we need to use the formula for the perimeter of a rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.

In this case, we know that P = 60, so we can write:

60 = 2l + 2w

Simplifying this equation, we get:

30 = l + w

To find the largest area of the rectangle, we need to maximize the product of the length and the width, which is the formula for the area of a rectangle, A = lw.

We can solve for one variable in terms of the other using the equation above. For example, we can write:

w = 30 - l

Substituting this expression for w into the formula for the area, we get:

A = l(30 - l)

Expanding and simplifying this expression, we get:

A = 30l - l^2

This is a quadratic equation in l, which has a maximum value when l is halfway between the roots. We can find the roots using the quadratic formula:

l = (-b ± sqrt(b^2 - 4ac)) / 2a

In this case, a = -1, b = 30, and c = 0, so we get:

l = (-30 ± sqrt(30^2 - 4(-1)(0))) / 2(-1)

Simplifying, we get:

l = (-30 ± sqrt(900)) / -2

l = (-30 ± 30) / -2

So the roots are l = 0 and l = 30. We want the smaller value first, so we take l = 0 and find w = 30. This would give us a rectangle with zero area, so it is not a valid solution.

The other root is l = 30, which gives us w = 0. Again, this is not a valid solution because we need both dimensions to be positive.

Therefore, the dimensions of the rectangle with the largest area for a perimeter of 60 are:

l = 15 and w = 15

This gives us a square with an area of 225 square units.

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Answer:

a3) x= 83

y= 180-71 = 109

a4) x=53

w= 180-53...

y=x=53

z= 180-y

Step-by-step explanation:

post the whole q for understanding the question

Answer:

3x+13

Step-by-step explanation:

Perimeter of square = 4 * length

Length = Perimeter/4

Length = (12x + 52)/4

Length = 3x+13

Answer:

has a factor of 13 where it should have a 12

does not apply the order of operations correctly

determines

245

Step-by-step explanation:

I took the iready test

Answer: has a factor of 13 where it should have a 12.

does not apply the order of operations correctly.

determines.

245 sqaure inches.

Step-by-step explanation:

I took the i ready diagnostic.

The null hypothesis for this test is that the mean ECLSE test score for the university is equal to 1200. The alternative hypothesis is that the mean is not equal to 1200.

To perform the test, you will need to calculate the t-statistic and the p-value. The t-statistic is calculated by:

t = (sample mean - hypothesized mean) / (sample standard deviation/sqrt (sample size))

In this case, the sample mean is 1180, the hypothesized mean is 1200, the sample standard deviation is 100, and the sample size is 100. Plugging these values into the equation gives:

t = (1180 - 1200) / (100 / sqrt(100)) = -20 / 10 = -2

Next, you will need to calculate the p-value. The p-value is the probability of observing a t-statistic as extreme as the one calculated, given that the null hypothesis is true.

To calculate the p-value, you will need to use a t-distribution table or a software package to find the t-critical value for a one-tailed test with 99 degrees of freedom (since you have a sample size of 100) and a significance level of 0.05. The t-critical value is the value that defines the rejection region for the test. If the t-statistic falls in the rejection region, you can reject the null hypothesis.

If the p-value is less than the significance level of 0.05, you can reject the null hypothesis and conclude that the mean ECLSE test score for the university is not equal to 1200 at the 95% significance level. If the p-value is greater than or equal to 0.05, you cannot reject the null hypothesis and cannot conclude that the mean is different from 1200.

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Answer:

The shortest path to take is \(20\sqrt{3}\ cm\) or \(34.64\ cm\)

Step-by-step explanation:

This question requires an attachment (See attachment 1 for question)

Given

Cube Dimension: 20cm * 20cm

Required

Shortest path from A to B

For proper explanation, I'll support my answer with an additional attachment (See attachment 2)

The shortest path from A to B is Line labeled 2

But first, the length of line labeled 1 has to be calculated;

This is done as follows;

Since, the cube is 20 cm by 20 cm

\(Line1^2 = 20^2 + 20^2\) (Pythagoras Theorem)

\(Line1^2 = 2(20^2)\)

Take square root of both sides

\(Line1 = \sqrt{2(20)^2}\)

Split square root

\(Line1 = \sqrt{2} * \sqrt{20^2}\)

\(Line1 = \sqrt{2} * 20\)

\(Line1 = 20\sqrt{20}\)

Next is to calculate the length of Line labeled 2

\(Line2^2 = Line1^2 + 20^2\) (Pythagoras Theorem)

Substitute \(Line1 = 20\sqrt{20}\)

\(Line2^2 = (20\sqrt{2})^2 + 20^2\)

Expand the expression

\(Line2^2 = (20\sqrt{2})*(20\sqrt{2}) + 20 * 20\)

\(Line2^2 = 400*2 + 400\)

Factorize

\(Line2^2 = 400(2+1)\)

\(Line2^2 = 400(3)\)

Take square root of both sides

\(Line2 = \sqrt{400(3)}\)

Split square root

\(Line2 = \sqrt{400} * \sqrt{3}\)

\(Line2 = 20 * \sqrt{3}\)

\(Line2 = 20 \sqrt{3}\)

The answer can be left in this form of solve further as follows;

\(Line2 = 20 * 1.73205080757\)

\(Line2 = 34.6410161514\)

\(Line2 = 34.64 cm\) (Approximated)

Hence, the shortest path to take is \(20\sqrt{3}\ cm\) or \(34.64\ cm\)

Answer:

44.72 cm

Step-by-step explanation:

1. This was marked correct by RSM

2. Unfold the cube, so that points A and B and on points diagonal from each other on a 40 cm x 20 cm rectangle. Now draw a line connecting points A to B. That is the hypotenuse of both triangles. Now according to the pythagorean theorem, the hypotenuse is √2000, which is equal to 5√20.

3. The answer is 44.72 cm

Answer:

x = 67

Step-by-step explanation:

∠ CRQ = ∠ BQR = 113° ( Alternate angles )

∠ CRQ and ∠ CRS are adjacent angles and supplementary, that is

x + 113 = 180 ( subtract 113 from both sides )

x = 67

The range of the function represented by y = 15x + 20, where y is Kim's daily earnings and x is the number of bikes she assembles, is $20 ≤ y ≤ $110.

The range of a function is the set of values of y possible values of the dependent variable after substituting values for the independent variable(domain).

The total amount she earns can be represented by

y = 15x + 20

where y is her daily earnings and x is the number of bikes she assembles

If Kim's boss daily goal is to assemble no more than 6 bicycles a day, then the value of x will only range from 0 to 6(whole number).

domain : {x| 0 ≤ x ≤ 6}

where x is a whole number

Substituting the minimum and maximum value of x in the function.

y = 15(0) + 20     when x = 0

y = 20

y = 15(6) + 20     when x = 6

y = 110

range : $20 ≤ y ≤ $110

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Answer:

(7, 11)

Step-by-step explanation:

If a line segment has endpoints at A(\(x_1,y_1\)) and B(\(x_2,y_2\)), the coordinates of the midpoint O(x, y) of the segment AB is given by the formula:

\(x=\frac{x_1+x_2}{2}\\\\y=\frac{y_1+y_2}{2}\)

Given the midpoint M(3, 5) of the segment CD with the coordinates of C at (-1, -1). Let the coordinates of D be at (\(x_2,y_2\)). Hence:

\(x=\frac{x_1+x_2}{2}\\\\ 3=\frac{-1+x_2}{2} \\\\6=-1+x_2\\\\x_2=6+1\\\\x_2=7\\\\y=\frac{y_1+y_2}{2}\\\\ 5=\frac{-1+y_2}{2} \\\\10=-1+y_2\\\\y_2=10+1\\\\y_2=11\)

Hence the coordinates of D is at (7, 11)

A single ticket's estimated earnings are around -$0.9442, which indicates that a consumer may expect to lose approximately $0.9442 for each ticket purchased.

To find the expected winnings of a single ticket, we need to calculate the weighted average of the winnings based on the probabilities of winning each prize.

The probabilities of winning each prize are as follows:

1st prize: 1 winner out of 10,000 tickets sold (probability = 1/10,000 = 0.0001)

2nd prize: 3 winners out of 10,000 tickets sold (probability = 3/10,000 = 0.0003)

3rd prize: 5 winners out of 10,000 tickets sold (probability = 5/10,000 = 0.0005)

Consolation prize: 20 winners out of 10,000 tickets sold (probability = 20/10,000 = 0.0020)

No prize: (1 - (probability of winning any prize)) = 1 - (0.0001 + 0.0003 + 0.0005 + 0.0020) = 0.9971

Now, let's calculate the expected winnings:

Expected winnings = (Probability of 1st prize × $3000) + (Probability of 2nd prize × $1000) + (Probability of 3rd prize × $500) + (Probability of consolation prize × $100) + (Probability of no prize × -$2)

Expected winnings = (0.0001 × $3000) + (0.0003 × $1000) + (0.0005 × $500) + (0.0020 × $100) + (0.9971 × -$2)

Expected winnings ≈ -$-0.9442

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The complete question:

A club is holding a raffle. Ten thousand tickets have been sold for $2 each. There will be a 1st prize of $3000, 3 second prizes of $1000 each, 5 third prizes of $500 each and 20 consolation prizes of $100 each. Find the expected winnings of a single ticket.

x  -2        98        498      998     2998

p  .9971  .0020  .0005  .0003   .0001

The domain are all of the x-values that are located on the x-axis of a cartesian coordinate while the range all of the y-values that are located on the y-axis of a cartesian coordinate.

In Mathematics, a domain is the set of all real numbers for which a particular function is defined.

In Mathematics, the horizontal extent of any graph of a function represents all domain values and they are read and written from smaller to larger numerical values, and from the left of a graph to the right.

Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

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Answer:

the domain is continuous

Step-by-step explanation:

hope this helps :)

Answer:

-1

Step-by-step explanation:

\(i^1\cdot i^2\cdot i^3\cdot i^4= \\\\i^{1+2+3+4}= \\\\i^{10}= \\\\-1\)

Hope this helps!

The vertices of the triangle after reflection over y=x are (-1, 5), (-4, 1) and (-1, 0).

The vertices of the triangle from the given graph are (-5, -1), (-1, -4) and (0, -1).

Reflection across line y=x.

Reflect over the y = x, when you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed).

After reflection over y=x, we get vertices has

(-5, -1)→(-1, 5)

(-1, -4)→(-4, 1)

(0, -1)→(-1, 0)

Therefore, the vertices of the triangle after reflection over y=x are (-1, 5), (-4, 1) and (-1, 0).

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Answer:

$220

Step-by-step explanation:

use the I = Prt simple interest formula

Answer

$850.50

I think

Step-by-step explanation:

Answer:

874

Step-by-step explanation:

Couches: 2 × 677 = 1,354

Beds: 4 × 465 = 1,860

Lamps: 3 × 94 = 282

1,354 + 1,860 + 282 = 3496

Four equal payments: 3496 ÷ 4 = 874

The correct answer to the question is (D) 2, indicating that the expansion contains terms up to the second power of \((x - 1)\).

The expansion you have provided for \(f(x) = \ln(x)\) at \(x_0 = 1\) is incorrect. The correct expansion for \(\ln(x)\) using the Maclaurin series is:

\(\ln(x) = (x - 1) - \frac{(x - 1)^2}{2} + \frac{(x - 1)^3}{3} - \frac{(x - 1)^4}{4} + \dots\)

This expansion is obtained by substituting \(x - 1\) for \(x\) in the series expansion of \(\ln(x)\) around \(x_0 = 0\).

From the given expansion, we can see that there are terms involving powers of \((x - 1)\) up to the fourth power. Therefore, the correct answer to the question is (D) 2, indicating that the expansion contains terms up to the second power of \((x - 1)\).

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Answer:

4/3<x<7

Step-by-step explanation:

Given the inequalities

3 < 3 x − 1 < 2 x + 6

Add 1 to all sides

3+1 < 3x-1+1<2x+6+1

4 < 3x < 2x + 7

Split

4 < 3x

3x > 4

x > 4/3

4/3 <x

Also

3x < 2x + 7

3x-2x < 7

x <7

Combine

4/3<x<7

Hence the required solution is 4/3<x<7

Answer: D) -20.99

Step-by-step explanation:

-4.97-2.36+-5.19-8.47 = -20.99

To dilate a point at a point, you start by selecting a center of dilation and a scale factor.

Then, for each point that you want to dilate, you do the following:

For example, if you wanted to dilate point P by a scale factor of 2, with the center of dilation at O, you would draw a line segment from O to P, double its length, and then draw a new line segment from O to the new point, using the new length that you calculated. The new point would be the point that you arrive at when you complete this line segment.

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Answer:

35x ≤ 1000

Step-by-step explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!