Answers
Answer:
6.2
Step-by-step explanation:
can i hae brailiezt plzz
Related Questions
Which one of the following best describes the notion of "the significance level of a hypothesis test?"A. The probability of a type I error.
B. Type one
C. Type I error because the principal rejected the null hypothesis when it was true.
Answers
The best describes the notion of "the significance level of a hypothesis test"is A. The probability of a type I error.
About hypothesisA hypothesis is a proposition whose nature has not been scientifically proven. So that this proposition must be proven empirically with a research process that is in accordance with the appropriate methodology.
Usually, a researcher formulates a hypothesis based on his subjective observations of a problem that is contextual with the issues raised in the research.
Sometimes, researchers also refer to previous research with appropriate problem topics to be proven further in the research process.
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If f'(c) < 0 then f(x) is decreasing and the graph of f(x) is concave down when x = c. True False Question 4 (1 point). A local extreme point of a polynomial function f(x) can only occur when f'(x) = 0. True False Question 5 (1 point) If f'(x) > 0 when x < c and f'(x) < 0 when x > c, then f(x) has a maximum value when x = C. True False
Answers
Question 3: True
Question 4: False
Question 5: True
If the derivative of a function, f'(x), is positive for values of x less than c and negative for values of x greater than c, then it indicates a change in the slope of the function. This change from positive slope to negative slope suggests that the function has a maximum value at x = c.
This is because the function is increasing before x = c and decreasing after x = c, indicating a peak or maximum at x = c.
Question 3: If f'(c) < 0 then f(x) is decreasing and the graph of f(x) is concave down when x = c.
True
When the derivative of a function, f'(x), is negative at a point c, it indicates that the function is decreasing at that point. Additionally, if the second derivative, f''(x), exists and is negative at x = c, it implies that the graph of f(x) is concave down at that point.
Question 4: A local extreme point of a polynomial function f(x) can only occur when f'(x) = 0.
False
A local extreme point of a polynomial function can occur when f'(x) = 0, but it is not the only condition. A local extreme point can also occur when f'(x) does not exist (such as at a sharp corner or cusp) or when f'(x) is undefined. Therefore, f'(x) being equal to zero is not the sole requirement for a local extreme point to exist.
Question 5: If f'(x) > 0 when x < c and f'(x) < 0 when x > c, then f(x) has a maximum value when x = c.
True
If the derivative of a function, f'(x), is positive for values of x less than c and negative for values of x greater than c, then it indicates a change in the slope of the function. This change from positive slope to negative slope suggests that the function has a maximum value at x = c. This is because the function is increasing before x = c and decreasing after x = c, indicating a peak or maximum at x = c.
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If I took any two distinct prime numbers, and the number "1", would these numbers always be pairwise relatively prime? True O False
Answers
The statement is true. If we take any two distinct prime numbers, and the number "1", these numbers will always be pairwise relatively prime.
Two numbers are said to be pairwise relatively prime if their greatest common divisor (GCD) is equal to 1. In this case, since we are considering distinct prime numbers, their GCD will always be 1 since prime numbers have no common factors other than 1 and themselves. Therefore, any two distinct prime numbers will be relatively prime.
Similarly, when we consider the number "1", it is relatively prime to any other number because its only divisor is 1. Hence, when "1" is paired with any prime number, the GCD will be 1.
In summary, whether we consider two distinct prime numbers or pair them with the number "1", the resulting numbers will always be pairwise relatively prime.
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let x1, x2 ..., x100 all be independent bernoulli variables, which take a value of 1 with probability 0.5
Answers
Using the normal approximation to the binomial, there is a 0.9713 = 97.13% probability that the sum of these variables is less than 60.
What is the missing information?This problem is incomplete, but researching it on a search engine, it asks the probability that the sum of these Bernoulli variables is of less than 60.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with \(\mu = np, \sigma = \sqrt{np(1-p)}\).The binomial distribution is a series of n Bernoulli trials with p probability of a success on each trial, hence the parameters for the binomial distribution are given as follows:
n = 100, p = 0.5.
The mean and the standard deviation are given by:
\(\mu = np = 100(0.5) = 50\).\(\sigma = \sqrt{np(1-p)} = \sqrt{100(0.5)(0.5)} = 5\)Using continuity correction, the probability that the sum is less than 60 is P(X < 59.5), which is the p-value of Z when X = 59.5, hence:
\(Z = \frac{X - \mu}{\sigma}\)
Z = (59.5 - 50)/5
Z = 1.9
Z = 1.9 has a p-value of 0.9713.
Hence there is a 0.9713 = 97.13% probability that the sum of these variables is less than 60.
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Please help. This will be worth 20 points.
Answers
7.) The function that can be used to represent the store's discount would be price(X) - discounted price.
8.) The amount of money that Andy will pay when the manufacturer's coupon is applied first would be = $480
What is a discount sales?A discount sales is the cost of a product by a manufacturer after a certain amount of money has been deducted from its actual cost price in order to favour the customers.
For a refrigerator with a discount percentage of 20, the new price is calculated as follows:
= 20/100 × 600/1
= 12000/100
= $120
The discounted price = 600-120 = $480.
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Write the point-slope form of an equation of the line through the points (-1, 4) and (-2, 2)
A. y + 2 = 2(x - 2)
B. y 4 20 + 1)
c. y + 1 = 2(3-4)
D. y 2 233 - 2)
Answers
Answer:
The answer is option BStep-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find an equation of a line given two points first find the slope / gradient
Slope of the line using points (-1,4) and (-2,2) is
\(m = \frac{2 - 4}{ - 2 + 1} = \frac{ - 2}{ - 1} = 2\)
So the equation of the line using point (-1,4) is
y - 4 = 2( x + 1)Hope this helps you
perform the necessary questions -5 -(-3) + (-8)
Answers
the answer is 0 because -5 -(-3) equals 8 which cancels out when u add negative 8 :)
f(x)= 3x-2 g(x)= x-1
Answers
By using the general formula for the composition of two functions, we will get:
How to find the compositions of functions?For two functions f(x) and g(x), we define the composition as:
f o g (x) = f( g(x))
So we are evaluating a function in another function.
In this case, the functions are:
f(x) = 3x - 2
g(x) =x - 1
Then the compositions, evaluated in the correspondent values are:
f o g (2) = f( g(2)) = f( 2 - 1) = f(1) = 3*1 - 2 = 1
g o f (-1) = g( f(-1) ) = g( 3*-1 - 2) = g(-5) = -5 - 1 = -6
g o g (-2) = g( g(-2)) = g( -2 - 1) = g(-3) = -3 - 1 = -4
f o g (-3) = f( g(-3)) = f( -3 - 1) = f(-4) = 3*-4 - 2 = -14
Then we conclude that the compositions are equal to:
f o g (2) = 1g o f (-1) = -6g o g (-2) = -4f o g (-3) = -14If you want to learn more about composition of functions:
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Find the solution to the initial-value problem 6 dx
dy
=(2x+1)(y 2
−2y−8) with y(0)=−3 using the method of separation of variables. 16. Solve the equation xdx+secxsinydy=0. 17. A bacterial culture contains 100 cells at a certain point in time. Sixty minutes later, there are 450 cells. Assuming exponential growth, determine the number of cells present at time t. 18. Solve the following Initial Value Problem xy dx
dy
=lnx,y(1)=2.
Answers
1. The initial-value problem 6dx/dy=(2x+1)(y^2-2y-8) with y(0)=-3 can be solved using the method of separation of variables. We separate the variables by writing the equation as 6dy=(2x+1)(y^2-2y-8)dx, then integrate both sides with respect to their respective variables to find the solution.
2. The equation xdx+sec(xsiny)dy=0 can be solved by separating the variables. We can write the equation as xdx=-sec(xsiny)dy, then integrate both sides to find the solution.
3. Assuming exponential growth, the number of cells in a bacterial culture can be determined using the formula N(t) = N0 * e^(kt), where N(t) is the number of cells at time t, N0 is the initial number of cells, k is the growth rate, and e is the base of natural logarithm. By substituting the given values of N0 and t, we can solve for the growth rate k and then find N(t).
4. The initial value problem xydx/dy = lnx with y(1) = 2 can be solved by separating the variables and integrating both sides. We separate the variables by writing the equation as xydx = lnx dy, then integrate both sides to find the solution.
1. To solve the initial-value problem 6dx/dy=(2x+1)(y^2-2y-8) with y(0)=-3, we can separate the variables by writing the equation as 6dy=(2x+1)(y^2-2y-8)dx. Next, we integrate both sides with respect to their respective variables. Integrating the left side gives 6y, and integrating the right side involves factoring the quadratic term and using partial fraction decomposition. After integrating, we obtain the solution in the form of an implicit equation for y(x).
2. To solve the equation xdx+sec(xsiny)dy=0, we can separate the variables by writing it as xdx=-sec(xsiny)dy. Integrating both sides involves integrating xdx and integrating sec(xsiny)dy, which can be challenging. However, we can use a trigonometric substitution and algebraic manipulation to simplify the integral and find the solution.
3. Assuming exponential growth, the number of cells in a bacterial culture can be described by the formula N(t) = N0 * e^(kt), where N(t) is the number of cells at time t, N0 is the initial number of cells, k is the growth rate, and e is the base of natural logarithm. By substituting the given values of N0 and t (N(0)=100, N(60)=450), we can form two equations and solve for the growth rate k. Once k is determined, we can use the formula N(t) = N0 * e^(kt) to find the number of cells at any given time t.
4. To solve the initial value problem xydx/dy = lnx with y(1) = 2, we separate the variables by writing it as xydx = lnx dy. Integrating both sides involves integrating xydx and integrating lnx dy. After integration, we obtain the solution in the form of an implicit equation for y(x). To find the specific solution with the initial condition y(1) = 2, we substitute the values into the implicit equation and solve for the constant of integration.
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16. The solution to the equation xdx+secxsinydy=0 is given by x^2 + 2ln|cosx| + c = 0, where c is the constant of integration.
The number of cells present at time t in the bacterial culture can be determined using the formula N(t) = N₀ * e^(kt), where N₀ is the initial number of cells, N(t) is the number of cells at time t, and k is the growth rate constant.
The solution to the initial value problem xydx/dy = lnx, y(1) = 2 is given by y = x^2lnx.
16. To solve the equation xdx+secxsinydy=0, we can use separation of variables. By separating the variables and integrating, we obtain the solution x^2 + 2ln|cosx| + c = 0, where c is the constant of integration.
The growth of the bacterial culture can be modeled by exponential growth. The formula N(t) = N₀ * e^(kt) relates the number of cells at time t, N(t), to the initial number of cells, N₀, and the growth rate constant, k. By substituting the given values N₀ = 100, N(t) = 450, and t = 60, we can solve for the value of k. Once we have the value of k, we can use the formula to determine the number of cells at any given time t.
To solve the initial value problem xydx/dy = lnx, y(1) = 2, we can use separation of variables. By separating the variables and integrating, we obtain the solution y = x^2lnx. The initial condition y(1) = 2 can be satisfied by substituting x = 1 into the solution equation.
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Where is each answer
Answers
Answer:
1.(D)
2.(A)
3.(C)
4.(B)
Question 10 of 28
Which of the following expressions are equivalent to
2. ? Choose all that apply.
ھر - 20
A.
B.
c.
2
(3)2 - (13 )2
1
1
(x3 - 3 ) ( + 13 )
2
1
(3 - 13) (3 - 13)
مردم زمرے
2
1
D. (x3 - 3 ) ( + 13 )
Answers
Answer: A, D
Step-by-step explanation:
A) Correct. \((x^3)^2=x^{(3)(2)}=x^6\). Similar logic for y.
B) Incorrect. The numerators are different.
C. Incorrect. The denominators are not the same.
D. Correct. The denominators are the same by difference of squares.
10. A piece of cardboard is 12 x 15 inches. What is the max volume of an open-roof box that can be formed by folding up the sides to create a height of x? ROUND ANSWER TO THE NEAREST WHOLE NUMBER
Answers
Answer:
180 fr
Step-by-step explanation:
its too hard
Stefan's rectangular bedroom is 12 feet by 9 feet. What is the diagonal distance from one
corner to the opposite corner?
NO LINKS I NEED A REAL ANSWER!!!!!!
Answers
Answer:
the diagonal distance from one corner to the opposite is 15 feet.
Step-by-step explanation:
using the pythagorean theorem, we know that a^2 + b^2 = c^2. if a=9 and b=12 we can set up our equation as follows:
9^2 + 12^2 = c^2
81 + 144 = c^2
225 = c^2
the square root of 225 is 15 therefore:
15 = c
b. A family of four went to see a live concert in Vancouver. Each family member bought
a commemorative concert T-shirt, which cost 1/5 of the price of a ticket. The total bill
for 4 tickets and 4 T-shirts was $384. How much did each ticket and each T-shirt cost?
Answers
The cost of 1 ticket is $80 and the cost of 1 T-Shirt is $16 .
In the question ,
it is given that ,
a family of four people went to see a live concert in Vancouver ,
and the price of T-shirt is 1/5 of the price of the ticket .
let the price of 1 ticket be = x ,
so , the price of 1 T-Shirt be = x/5 .
also given that the bill for 4 tickets and 4 T-Shirts was $384 ,
that means
4x + 4x/5 = 384
taking LCM as 20 and solving further ,
we get,
20x/5 + 4x/5 = 384
24x/5 = 384
24x = 384*5
24x = 1920
x = 1920/24
x = 80
the cost for T-Shirt = 80/5 = 16
Therefore , The cost of 1 ticket is $80 and the cost of 1 T-Shirt is $16 .
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10. Find the area of the shaded region.
17 yd
5 yd
7 yd
6 yd
7 yd
4 yd
Answers
Answer:
176 yd
Step-by-step explanation:
UNSHADED REGION (white rhombus): A=(s1+s2)/2 * H
s1=7
s2=1+7=8
H=6
A=(7+8)/2*6=45
SHADED + UNSHADED REGION (big parallelogram): area of parallelogram A=B*H
B=17
H=7+6 = 13
A=17*13=221
SHADED REGION: big parallelogram area - rhombus area
221 - 45 =176 yd
Use the data set to answer the question.
{22,26,28,35,45,63,91}
What is the mean absolute deviation (MAD) of the data set?
Answers
Answer:
your answer will be 18.9
Step-by-step explanation:
hope this helps you have a nice day :)
step by step is in the picture
Brainliest if correct
Answers
Answer: a > -1
Explanation is in the image.
Answer:
\(a > -1\)
Step-by-step explanation:
1) Write the equation
\(-2a+14 < 5a+21\\\)
2) Collect like terms on their corresponding side
\(-7a < 7\)
3) Divide -7 from both sides and flip the sign
\(a > -1\)
A county reported the following data on breast cancer for the past year. what is the prevalence rate per 100,000? number of new cases: 1,774; number of total cases: 4,192; population: 5,977,906
Answers
The prevalence rate per 100,000 is 99.8%
We know that the prevalence rate is the proportion of persons in a population who have a particular disease over a specified period of time.
In this question, we have been given a data on breast cancer for the past year:
number of new cases: 1,774;
number of total cases: 4,192;
population: 5,977,906
We need to find the prevalence rate per 100,000
The total number of infected people = 1,774 + 4192
= 5966
Chance of infection in the whole population would be,
5,977,906/ 5966 ≈ 1002
This means, chances of having breast cancer is 1 in every 1002 people.
A prevalence rate is calculated by dividing total number of infected people by the total population. The result is then multiplied by 100,000
Now we calculate the prevalence rate per 100,000
= (5966 / 5,977,906) × 100,000
= 0.000998 × 100,000
= 99.8 %
Therefore, the prevalence rate per 100,000 is 99.8%
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1. Find the midpoint for each segment with the given endpoints.
a. C(-2, 5) and D(8, -12) b. E(2.5, -7) and F(-6.2, -3.8)
Answers
Answer:
a.(3,-7/2) b.(-1.85,-5.4) will the midpoints
Step-by-step explanation:
let mid point be x,y
apply mid point formula
x=(x1+x2)/2 y=(y1+y2)/2
plz mark as brainliest
The midpoint of the given line is (3,-3.5)
What is midpoint of a line ?The midpoint of a line is a point which divides the line segment into two equal parts.We can also say that a midpoint bisects a line segment.
We know when two end points of a line segment are given we can find midpoint by
M(x) = (x₁ + x₂)/2 and M(y) = (y₁ + y₂)/2.
Given points C(-2, 5) and D(8, -12)
M(x) = ( - 2 + 8 )/2
M(x) = 6/2
M(x) = 3.
M(y) = ( 5 - 12 )/2
M(y) = -7/2
M(y) = -3.5.
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Which angle is the included angle for sides ABand BC?
A
C
O Angle B
Angle C
O Angle A
B
Answers
For the given sides AB and BC the angle included would always be Angle B
When we form a triangle we name the vertex as A, B and C. So, the sides AB and BC will always have an Angle B regardless of the naming convention we use.
A triangle is a polygon with three vertices and three edges that has three sides. It is a basic geometric shape. The term "abc" refers to a triangle containing the vertices a, b, and c. Any three non-collinear points in Euclidean geometry combine to create a singular triangle and a singular plane.
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A rectangular playing field is 70 yards long. Its area is 3,150 yards what is the width of the feild
Answers
Answer:
45 yards
Step-by-step explanation:
Formula to find area of rectangle: Length * Width
Given:
Length = 70 yards
Area = 3,150 yards
Width = 3,150/70
==> 45 yards
Width = 45 yards
illustrate. Then solve the
1.) A car is able to travel 210 km in 3 hours. How far can it
travel in 5 hours?
Answers
Answer:
350 km
Step-by-step explanation:
210/x=3/5
x=350
tadaaa
Coras multiply and divide
Melanie had two $10 bills, one $5 bill, four dimes, and six pennies. Then she bought a fruit cup for $2.19. How much money did Melanie have after she bought the fruit cup
Answers
10+10+5+0.4+0.06= $25.46-$2.19= $23.27.
Estimate the correlation coefficient for each of the above scatter plots?
Answers
Answer:
Negative Correlation
Step-by-step explanation:
We see that the overall trend is going from up to down. If you were to draw a best line of fit, it would have a negative slope. Therefore, our correlation is negative.
Find a cofunction with the same value as the given expression. tan {v/4}
Answers
The cofunction with the same value as the expression tan(v/4) is cot(π/4 - v/4).
1. Recall that the cofunction identities relate the trigonometric functions of complementary angles. The complementary angle of a given angle is the angle that, when added to the given angle, forms a right angle (90 degrees or π/2 radians).
2. The cofunction of tan(x) is cot(x) because tangent and cotangent are complementary functions.
3. To find the cofunction with the same value as tan(v/4), we need to determine the complementary angle of v/4.
4. The complementary angle of v/4 is π/4 - v/4. This can be understood by considering that the sum of the angles v/4 and π/4 - v/4 should equal π/2 (90 degrees).
5. Therefore, the cofunction with the same value as tan(v/4) is cot(π/4 - v/4).
The cofunction with the same value as tan(v/4) is cot(π/4 - v/4).
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if the temperature is -5 degrees. and if another city it's four less degrees. what is the temperature in the other city?
Answers
If the temperature is -5 degrees in one city and it is four degrees less in another city, the temperature in the other city would be -9 degrees.
This is because subtracting four from -5 results in a decrease of four units, giving us -9 degrees.
In the given scenario, the temperature in the other city is four degrees less than the temperature in the first city. When we subtract four from the original temperature of -5 degrees, we obtain -9 degrees.
Thus, the temperature in the other city is -9 degrees, indicating that it is colder by four degrees compared to the first city.
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to calculate the center line of a control chart you compute the ________ of the mean for every period.
Answers
The centre line of a control chart is calculated by computing the average (mean) of the data for every period.
In control chart analysis, the centre line represents the central tendency or average value of the process being monitored. It is typically obtained by calculating the mean of the data points collected over a specific period. The purpose of the centre line is to provide a reference point against which the process performance can be compared. Any data points falling within acceptable limits around the centre line indicate that the process is stable and under control.
The calculation of the centre line involves summing up the values of the data points and dividing it by the number of data points. This average is then plotted on the control chart as the centre line. By monitoring subsequent data points and their distance from the centre line, deviations and trends in the process can be identified. Deviations beyond the control limits may indicate special causes of variation that require investigation and corrective action. Therefore, the centre line is a critical element in control chart analysis for understanding the baseline performance of a process and detecting any shifts or changes over time.
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Find the area and perimeter of a polygon with vertices located at A(-4,-8), B(4, -8), C(4, 0), D(0, 3), and E(-4,0).
Area =
Perimeter =
Answers
Answer:
76 and 34
Step-by-step explanation:
See attached
As we see this is a polygon with sides of AB=BC=AE and CD=DE
Sides AB=BC=AE equal to 8Sides CD=DE = \(\sqrt{3^2 + 4^2}\) = 5Area is the sum of areas of a square ABCE with side 8 and a triangle CDE with base of 8 and height of 3:
Area = 8*8 + 1/2*8*3 = 64 + 12 = 76Perimeter = 8*3 + 5*2 = 24 + 10 = 34
How many positive integers can be expressed as a product of two or more of the prime numbers 5, 7, 11, and 13 if no one product is to include the same prime factor more than once
Answers
There are 15 positive integers that can be expressed as a product of two or more of the prime numbers 5, 7, 11, and 13 if no one product is to include the same prime factor more than once.The prime numbers are:5, 7, 11, 13Product of two of the prime numbers are:35, 55, 65, 77, 85, 91, 115, 143, 165, 385
Product of three of the prime numbers is:385 Product of all the prime numbers is: 5005There are 15 positive integers that can be expressed as a product of two or more of the prime numbers 5, 7, 11, and 13 if no one product is to include the same prime factor more than once. Prime numbers are numbers that are only divisible by 1 and itself. 5, 7, 11, and 13 are prime numbers.
The question is asking to find the number of positive integers that can be expressed as a product of two or more of these prime numbers without including the same prime factor more than once. The products of two prime numbers are: 5 x 7 = 35, 5 x 11 = 55, 5 x 13 = 65, 7 x 11 = 77, 7 x 13 = 91, 11 x 13 = 143. There are six of these products. The products of three prime numbers is 5 x 7 x 11 = 385. There is only one of this product. There are fifteen possible positive integers that can be expressed as a product of two or more of the prime numbers 5, 7, 11, and 13 if no one product is to include the same prime factor more than once.
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PLS HELP HDJSJDJSJDJ
Answers
Answer:
your answers are correct
Step-by-step explanation: