Answer:
the answer to this certain question is 5
Pretty please helppplp!!!!!!
Since the x's both are to a power and have exponents outside of the parenthesis, we multiply the inner exponent by the outer exponent.
x^-150 / x^-144
Then, we need to move the bottom term to the top so that we have no negative exponents. Now, we are technically subtracting, but subtracting a negative is the same thing as adding.
x^(-150 + 144)
x^-6
Hope this helps!
Answer:
so your answer is -6
Step-by-step explanation:
\(\frac{(x^2^5)^-^6}{(x^-^3)^4^8}\) Did i write the equation right? If so you would multiply the exponents
x^-150 x^144
---------- so you then flip the two and get ----------
x^-144 x^150
then you would subtract the exponents like this 144-150= -6
y
10
6
8
7
6
5
4
3
2
1
-10
-9-8
-7
-6
-5
-4
-3
1
2
3
4
5
9
4
9
8
10
-5
-6
-7
-8
-9
-10
write an exponential function that includes the following given pair of points.
(-3,16) and (-2,8)
In testing for differences between the means of 2 independent populations the null hypothesis is?
In testing for differences between the means of two independent populations, the null hypothesis states that the difference between the two population means is not significantly different from zero or is H₀: µ₁ - µ₂ = 0
Given: To state the null hypothesis between the difference of means for 2 independent populations.
What is a hypothesis?
A hypothesis is a proposed assumption or supposition which acts as an initial point for starting research work and it is based on just a few observations from the past that are based on a limited shred of evidence and is needed more evidence to prove to be true later in the future.
What is the null hypothesis?
In statistics, a null hypothesis is a proposition or explanation that says that for a given set of observations there is no significance or there is no difference for a certain characteristic of a population or a given data set under observation. It is denoted as H0
What is mean?
Mean is defined as the average for a given data set.
Hence in testing for differences between the means of two independent populations, the null hypothesis states that the difference between the two population means is not significantly different from zero or is H₀: µ₁ - µ₂ = 0
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It takes 2 yards of material to
make 6 scarves, how many yards of material are needed to make 24
scarves?
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 44 ft./s the balls height in feet after two seconds is given by the following find all values of tea for which the balls high is 22 feet
How does the graph of g(x) = (x − 2)3 + 6 compare to the parent function of f(x) = x3?
The graph of g(x) is the graph of f(x) translated 2 units to the right and 6 units up.
How does the graph of g(x) compare to the one of f(x)?
Here we have:
\(f(x) = x^3\\\\g(x) = (x - 2)^3 + 6\)
You can notice that if we take f(x), and we shift it 2 units to the right, we have:
g(x) = f(x - 2)
Then if we apply a shift upwards of 6 units, then we have:
g(x) = f(x - 2) + 3
Replacing f(x) by the cubic parent function, we have:
\(g(x) = (x - 2)^3 + 6\)
So we conclude that the graph of g(x) is the graph of f(x) translated 2 units to the right and 6 units up.
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in scientific literature, when a value is given as 461.17 /- 0.31 ma, the standard deviation is assumed to be the 2-sigma. if the orginial measurements are repeated, how likely will the new values fall within 2 standard deviations of the given mean value?
If the original measurements are repeated, there is a 95.4% chance that the new values will fall within 2 standard deviations of the given mean value.
The given value of 461.17 /- 0.31 mA represents a range of values that are within two standard deviations of the mean. Since the standard deviation is assumed to be the 2-sigma, this means that the range of values is equal to the mean value plus or minus two times the standard deviation. In other words, the range of values is from 460.55 mA to 461.79 mA.
If the original measurements are repeated, we can assume that the new values will follow a normal distribution with the same mean and standard deviation as the original measurements. Since 95.4% of the data falls within two standard deviations of the mean on either side, we can say that there is a 95.4% chance that the new values will fall within the range of 460.55 mA to 461.79 mA.
Therefore, we can conclude that if the original measurements are repeated, there is a 95.4% chance that the new values will fall within 2 standard deviations of the given mean value.
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PLEASE HELP IF YOU KNOW ALGEBRA AND SPANISH
I don't know Spanish but I'm reasonably sure I know what the questions are asking. Please correct me if I'm wrong.
a. f(2) = -2^2+4(2)-10 = -4+8-10 = -6.
b. g(6) = 5(6)+1 = 30+1 = 31.
c. f(-1) = -(-1)^2+4(-1)-10 = -1-4-10 = -15.
d. This is saying to solve g(x)=16:
5x+1=16Subtract 1 from each side: 5x=15Divide both sides by 5: x=3.The answer is x=3.
5a squared - 6ab
i need help
Answer:
a (5a - 6b)
Step-by-step explanation:
Factor a
5a^2 - 6ab
a (5a - 6b)
⚠️Pythagorean Theorem⚠️
‼️Urgent Help‼️
another good answer and another brainlist
Answer:
not
Step-by-step explanation:
9y=72? :D one last question this is such a struggling doing algebra in such an early grade: (
Answer:
y=8
Step-by-step explanation:
Answer:
y = 8
Step-by-step explanation:
Divide each term by 9 and simplify.
estimate the error that is made by approximating the sum of the given series by the series the fitst 5 terms 1/k^3
The error involved in approximating the sum of the given series by the sum of the first five terms of the series is `R5 = 1/6³ + 1/7³ + ...`.
To estimate the error that is made by approximating the sum of the given series by the series the first 5 terms 1/k³, we can use the remainder term of a convergent series.
The given series is ∑ 1/k³ from k = 1 to infinity.We have to find the error involved in approximating the sum of the given series by the sum of the first five terms of the series.
That is, we need to find the difference between the actual sum of the series and the sum of the first five terms of the series.
The sum of the series is given by: `S = 1/1³ + 1/2³ + 1/3³ + 1/4³ + ... + 1/n³ + ...` We can use the remainder term of the series to find the error in approximation.
The remainder term `Rn` is given by: `Rn = Sn - S` where `Sn` is the sum of the first `n` terms of the series. Thus, we have to find the remainder term for `n = 5`.
The remainder term `Rn` is given by: `Rn = S - Sn = 1/6³ + 1/7³ + ...` Since the given series is convergent, the remainder term `Rn` tends to zero as `n` tends to infinity.
So, if we take the sum of the first five terms of the series, the error involved in approximation is given by the remainder term `R5`.
The error involved in this approximation is very small and can be neglected.
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An independent set in a graph is a set of vertices S⊆V that contains no edge (so no pair of neighboring vertices is included). The max independent set problem is to find an independent set of maximum size in a graph G. (a) Write the max independent set problem as an integer linear program. (b) Write an LP relaxation for the max independent set problem. (c) Construct an example (a family of graphs) to show that the ratio LP-OPT / OPT can be at least cn where c>0 is some absolute constant and n is the number of vertices of the graph. (d) What is the (exact) relation between the size of a max independent set and the size of min vertex cover of a graph? (e) Using this relation, what does the 2-approximation algorithm for vertex cover imply for an approximation algorithm for max independent set?
The independent set in a graph is a set of vertices that contain no edges. So, no neighboring vertices are included. The max independent set problem is to get an independent set of maximum size in graph G.
The solution for this question is discussed below:
a) The integer linear program for the max independent set problem is as follows:
maximize ∑x_i Subject to: x_i+x_j ≤ 1 {i,j} ∈ E;x_i ∈ {0, 1} ∀i. The variable x_i can represent whether the ith vertex is in the independent set. It can take on two values, either 0 or 1.
b) The LP relaxation for the max independent set problem is as follows:
Maximize ∑x_iSubject to:
xi+xj ≤ 1 ∀ {i, j} ∈ E;xi ≥ 0 ∀i. The variable xi can take on fractional values in the LP relaxation.
c) The family of graphs is as follows:
Consider a family of graphs G = (V, E) defined as follows. The vertex set V has n = 2^k vertices, where k is a positive integer. The set of edges E is defined as {uv:u, v ∈ {0, 1}^k and u≠v and u, v differ in precisely one coordinate}. It can be shown that the size of the max independent set is n/2. Using LP, the value can be determined. LP provides a value of approximately n/4. Therefore, the ratio LP-OPT/OPT is at least c/4. Therefore, the ratio is in for a constant c>0.
d) The size of a max-independent set is equivalent to the number of vertices minus the minimum vertex cover size.
e) The 2-approximation algorithm for vertex cover implies a 2-approximation algorithm for the max independent set.
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Hello, please help me with Question B in this question :)
Given: The vectors u, v, and w as-
\(\begin{gathered} u=\begin{bmatrix}{2} & {} \\ {3} & {}\end{bmatrix} \\ v=\begin{bmatrix}{0} & {} \\ {1} & {}\end{bmatrix} \\ w=\begin{bmatrix}{4} & {} \\ {3} & {}\end{bmatrix} \end{gathered}\)Required: To determine the value of c such that u+cw is orthogonal to u.
Explanation: Two vectors are said to be orthogonal if their dot product is zero.
The vector u+cw is-
\(\begin{gathered} u+cw=\begin{bmatrix}{2} & {} \\ {3} & {}\end{bmatrix}+c\begin{bmatrix}{4} & {} \\ {3} & {}\end{bmatrix} \\ =\begin{bmatrix}2+{4}c & {} \\ 3+{3}c & {}\end{bmatrix} \end{gathered}\)The dot product of two vectors of the form-
Now, taking the dot product of (u+cw) with u as follows-
\(\begin{gathered} (u+cw)\cdot u=\begin{bmatrix}2+{4}c & {} \\ 3+{3}c & {}\end{bmatrix}\cdot\begin{bmatrix}{2} & {} \\ {3} & {}\end{bmatrix} \\ =4+8c+9+9c \end{gathered}\)Now, the product will be zero if the vectors are orthogonal.
\(\begin{gathered} 17c+13=0 \\ c=-\frac{13}{17} \end{gathered}\)Final Answer: The value of c is-
\(c=-\frac{13}{17}\)the purchasing agent at a local hardware store noticed a sale on hammers. the original price of the hammers was $12 each. with the discount, he could get each hammer for $9.50. what percentage was the discount (rounded to nearest whole percentage)?
The percentage discount on the hammers is about 21%.
The discount is the difference between the original price and the discounted price.
Discount = $12 - $9.50
subtract the numbers
= $2.50
To find the percentage discount, we divide the discount by the original price and multiply by 100
Percentage discount = ( Discount / Original price ) x 100
Substitute the values in the equation and find the percentage discount
Percentage discount = ( $2.50 / $12 ) x 100
Do the arithmetic operation
Percentage discount = 20.83%
Rounding to the nearest whole percentage, the discount is approximately equal to 21%.
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Let A be a 4X5 matrix. If a1,a2,a4 are linearly independent and a3=a1+2a2 a5=2a1-a2+3a4 determine the reduced row echelon form of A.
As per the given 4 x 5 matrix, the reduced row echelon form of A is \(\left[\begin{array}{ccc}1&2&0\\0&0&1\\0&0&0\end{array}\right]\)
The term matrix in math refers a set of numbers arranged in rows and columns so as to form a rectangular array.
Here we have the 4 x 5 matrix.
And here we also know that a1,a2,a4 are linearly independent and the value of a3=a1+2a² and a5=2a1-a²+3a⁴.
Now, we have to apply the value of
a1 = 1, a2 = 0, a3 = 0, a4 = 0, a5 = 1, a6 = 0, a7 = 0, a8 = 0, and a9 = 1.
Then we get the matrix of 3 x 3 looks like the following,
\(\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]\)
Now, we have to do the following steps in order to get the reduced row echelon form of A,
The first and foremost steps is to take the non-zero number in the first row is the number 1.
Then we have to place any non-zero rows are placed at the bottom of the matrix.
This steps are repeated until the final row becomes zero.
Then we get the resulting matrix as \(\left[\begin{array}{ccc}1&2&0\\0&0&1\\0&0&0\end{array}\right]\)
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A local little league ha a total of 60 player, of whom 20% are right-handed. How many right-handed player are there?
There are 12 players of right handed, according to the question.
What do you mean by percentage?
A percentage in mathematics is a number or ratio that is expressed as a fraction of 100. The abbreviations "pct.", "pct.", and occasionally "pc" are also used to indicate it, though the percent sign, "%," is most frequently used. A percentage has no dimensions and no standard measurement.
According to data in the given question,
We have given data:
A local little league has a total of 60 players of whom 20% are right-handed.
Let x be the total number of players that are right-handed.
The value of x can be found as follow:
x = 20% of 60
x = (20/100)60
x = 0.2(60)
x = 12
Therefore, the total number of players that are right-handed is 12, if the local little league has a total of 60 players of whom 20% are right-handed.
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find the work in ft-lb done by winding up a hanging cable of length 100 ft and weight-density 5 lb/ft
the work done is equal to the force applied (500 lb) multiplied by the distance (100 ft), resulting in 500 ft-lb of work done.
A force applied across a distance is what is referred to as work.
In this problem,
the force applied is the weight of the cable (5 lb/ft) multiplied by the length of the cable (100 ft).
Therefore, the work done is equal to the force applied (500 lb) multiplied by the distance (100 ft), resulting in 500 ft-lb of work done.Work is a force applied across a distance, and it is measured in a unit of energy called foot-pounds. In this problem, the force applied is the weight of the cable (5 lb/ft) multiplied by the length of the cable (100 ft). Therefore, the work done is equal to the force applied (500 lb) multiplied by the distance (100 ft), resulting in 500 ft-lb of work done. This means that 500 ft-lb of energy must be expended in order to move the cable 100 ft. This energy can be provided by a variety of sources, such as human labor, a motor, or some other mechanism.
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Help with number one a-f is all part of number one
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
carnival game:
spinner: 1 to 8
Step 02:
simple probability:
p = favorable outcomes / total outcomes
1. probability of an event:
a. p (odds):
p (odds) = 4 / 8 = 1 / 2
b. p (evens):
p (evens) = 4 / 8 = 1 / 2
c. p (3):
p (3) = 1 / 8
d. p (4 or 6):
p (4 or 6) = 2 / 8 = 1 / 4
e. p (7'):
p (7') = 7 / 8
f. p (1):
p (1) = 1 / 8
That is the full solution.
Office Supplies: The Office Supplies account started the year with a $4,000 debit balance. During the year, the company purchased supplies for $13,400, which added to the Office Supplies Account. The inventory of supplies available at the end of the year totaled $2,554.1. The beginning balance of Office Supplies: 2. The amount to be adjusted (show your calculation): 3. The ending balance of the account after the adjustment (show your calculation):4. Adjusting Journal Entry (please include description): Date Account Debit Credit
1.The beginning balance should be $4,000
2.The amount to be adjusted is $2554
3.The ending balance of the account after the adjustment $2554
4. Office Supplies Account is $14846
Adjusting entry:An adjusting entry is an additional journal entry that is made at the end of the month or year. When any financial transaction is incurred for which the amount is not accrued yet or no financial transaction incurred for the accrued amount and in such case the adjusting entry is made to know the actual amount accrued in the month or year.
The adjustment entries are the additional entries to the recorded journal entries.
"Information available from the question"
The Office Supplies account started the year with a $4,000 debit balance
The company purchased supplies for $13,400,
The inventory of supplies available at the end of the year totaled $2,554.
Now, According to the question:
1. The beginning balance should be $4,000
2.The adjusted amount is
Opening balance = 4000
Add: New purchases = 13400
Balance after Purchase = 17400
Less: Year end balance = 2554
3. The ending balance is $2,554
4. The adjusting journal entry is
Dr. Supplies Expense Account is 14846
Adjustment in the year = Cr. 14846 (subtracted from the balance)
Office Supplies Account is 14846
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Bag A contains 5x coins.
Bag B contains 3x coins.
8 coins are taken from Bag B and put into Bag A
The ratio of coins in Bag A to Bag B is now 11:5
Work out the total number of coins.
Answer:
given ,
number of coins in bag A = 5x
number of coins in bag B = 3x
_____________________________________
According to Question ,
8 coins are taken from Bag B and put into Bag A
The ratio of coins in Bag A to Bag B is now 11 : 5
therefore ,
\( \frac{5x + 8}{3x - 8} = \frac{11}{5} \\ \\ 5(5x + 8) = 11(3x - 8) \\ \\ 25x + 40 = 33x - 88 \\ \\ 33x - 25x = 40 + 88 \\ \\ 8x = 128 \\ \\ x = \cancel\frac{128}{8} \\ \\ \fbox{x =16} \)
now ,
\(no. \: of \: coins \: in \: bag \: A = 5x \\ \dashrightarrow{5 \times 16 = 80 \: coins}\)
\(number \: of \: coins \: in \: bag \: B = 3x \\ \dashrightarrow{3 \times 16 = 48 \: coins}\)
\(total \: number \: of \:coins = 80 + 48 \\ \dashrightarrow{ 128 \: coins}\)
hope helpful :D
Pls answer, will give brainliest...
Answer:
a = 5
b = 4
c = 2
Step-by-step explanation:
5 - 0 = 5
8 + 4 = 12 and 4 + 8 = 12
6 + 8 and 12 + 2 is 14
From the following categories of variables, which of them are mutually exclusive and exhaustive?
a. Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday
b. Days: Weekday and Weekend
c. Letters: Vowels and Consonants
d. Letters: Alphabets and Consonants
The given categories of variables that are mutually exclusive and exhaustive are weekdays and weekend and vowels and consonants.
Mutually exclusive and exhaustive variables: A variable is mutually exclusive and exhaustive if it includes all possible outcomes and each outcome can only be assigned to one variable category.a. Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday - Mutually exclusive and exhaustiveb. Days: Weekday and Weekend - Mutually exclusive and exhaustive c. Letters: Vowels and Consonants - Mutually exclusive and exhaustive. Letters: Alphabets and Consonants - Not mutually exclusive and exhaustiveThe given categories of variables that are mutually exclusive and exhaustive are weekdays and weekend and vowels and consonants. Hence, the options a and c are correct.
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PLZZZZ HELP ME.A person riding in an elevator travels 180 feet in 30 seconds. What equation represents this relationship? How many feet will the person travel in
10 seconds?
y=6x;60 feet
y=8x; 80 feet
y=1/6x;60 feet
y=6x=6 feet
Answer: is A y=6x;60 feet
Which of the following pairs of numbers has 16 as their greatest common factor?
32, 48
32, 48
32, 62
32, 62
48, 36
48, 36
42, 16
42, 16
Answer:
32, and 48. This is the greatest factor of 16
Given: triangle WIN is similar to triangle TRY
Solve for x and y
Identify whether the following numbers are rational or irrational i) 0.11011001100011...........
ii) 2.56565656...........
Answer:
i) is irrational and ii) is rational
Step-by-step explanation:
i) does not keep a consistent pattern. If it was .11011011011.... it would be a rational number, but since it keeps changing its pattern it would be considered irrational. ii) is rational because it has a consistent pattern that doesn't change.
Step-by-step explanation:
0.11011001100011...............is your answer right answer
Solve the system: x + 3y - 2z = 1 2x + y + 3z = 20 2x - 2y + z = 6 Write the values for x, y, and z as a three-digit number without spacing for your answer.
The values for x, y, and z are 95, -9, and -21, respectively, resulting in a three-digit number: 95-9-21 = 95921.
To solve the system of equations:
x + 3y - 2z = 1
2x + y + 3z = 20
2x - 2y + z = 6
By the use of the method of Gaussian elimination or matrix algebra. Here, the Gaussian elimination:
1. Multiply equation 1 by 2 and subtract equation 3:
2(x + 3y - 2z) - (2x - 2y + z) = 2 - 6
2x + 6y - 4z - 2x + 2y - z = -4
8y - 5z = -4
2. Multiply equation 1 by 2 and subtract equation 2:
2(x + 3y - 2z) - (2x + y + 3z) = 2 - 20
2x + 6y - 4z - 2x - y - 3z = -18
5y + z = -18
3. Rearrange equation 2:
2x + y + 3z = 20
2x + 2y + 6z = 40
4. Subtract equation 3 from equation 2:
(2x + 2y + 6z) - (5y + z) = 40 - (-18)
2x + y + 5y + 6z - z = 58
2x + 6y + 5z = 58
Now we have a new system of equations:
8y - 5z = -4
5y + z = -18
2x + 6y + 5z = 58
We can solve this system using any method of our choice. In this case, solving the system yields:
x = 95
y = -9
z = -21
Therefore, the values for x, y, and z are 95, -9, and -21, respectively, resulting in a three-digit number: 95-9-21 = 95921.
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