Answer:
-12
Step-by-step explanation:
-10x+1+7x =37
-10x+7x+1 =37 (-10x+7x = -3x)
-3x+1 =37
-3x =37 -1
-3x =36
-3x / -3 = 36 / -3
x = -12
Answer:
x = -12
Step-by-step explanation:
\( \sf - 10x+1+7x=37\)
Combine like terms.
\(\sf - 3x+1=37\)
Subtract 1 from both sides.
\(\sf - 3x=37−1\)
\(\sf - 3x=36\)
Divide both sides by -3.
\(\sf \cfrac{ - 3x}{3} = \cfrac{36}{3} \)
\(\sf x = - 12\)
2. Create a portfolio composed of two independent bets of $5 each, both on 3 numbers. (a) Construct the probability distribution of the portfolio, beginning with the sample points. (b) Find the expected value, the variance, and the standard deviation of the portfolio bet, on 3 numbers. (c) By what multipliers do the results change when switching from a single $10 bet to the portfolio bet, again on 3 numbers
The expected value remains at $15, the variance remains at 0, and the standard.
The multipliers for the results remain the same.
Probability Distribution of the Portfolio Bet: There are a total of 9 sample points, and each sample point has a probability of 1/9.
To construct the probability distribution of the portfolio bet, we first need to define the sample points. Since the portfolio is composed of two independent bets on 3 numbers, let's denote the bets as Bet 1 and Bet 2, respectively.
For Bet 1, let's assume the numbers chosen are 1, 2, and 3. The sample points for Bet 1 would be the three individual numbers: {1}, {2}, and {3}.
For Bet 2, let's assume the numbers chosen are 4, 5, and 6. The sample points for Bet 2 would be: {4}, {5}, and {6}.
Now, let's combine the sample points of both bets to create the sample points for the portfolio bet:
Sample points for the portfolio bet: {1, 4}, {1, 5}, {1, 6}, {2, 4}, {2, 5}, {2, 6}, {3, 4}, {3, 5}, {3, 6}.
(a) Probability Distribution of the Portfolio Bet:
To construct the probability distribution, we need to assign probabilities to each of the sample points. Since each bet is independent, we assume that each number has an equal chance of being chosen.
There are a total of 9 sample points, and each sample point has a probability of 1/9.
The probability distribution of the portfolio bet is as follows:
{1, 4}: 1/9
{1, 5}: 1/9
{1, 6}: 1/9
{2, 4}: 1/9
{2, 5}: 1/9
{2, 6}: 1/9
{3, 4}: 1/9
{3, 5}: 1/9
{3, 6}: 1/9
(b) Expected Value, Variance, and Standard Deviation of the Portfolio Bet:
To calculate the expected value (E), variance (Var), and standard deviation (SD) of the portfolio bet, we need to assign a payoff or outcome for each sample point.
Let's assume the payoff for each winning sample point is $15 (which would include the return of the initial $5 bet).
The expected value (E) is calculated as follows:
E = Σ(P * X),
where P is the probability and X is the payoff. Summing up the products of the probabilities and payoffs for all sample points, we get:
E = (1/9 * $15) + (1/9 * $15) + ... + (1/9 * $15) (9 times) = 9/9 * $15 = $15.
The variance (Var) is calculated as:
\(Var = Σ(P * (X - E)^2).\)
For each sample point, we calculate\((X - E)^2\) and multiply it by the probability. Summing up these values, we get:
\(Var = (1/9 * ($15 - $15)^2) + (1/9 * ($15 - $15)^2)\) + ... + (\(1/9 * ($15 - $15)^2\)) (9 times) = 0.
The standard deviation (SD) is the square root of the variance, so in this case, SD = sqrt(0) = 0.
(c) Multipliers when switching from a $10 single bet to the portfolio bet:
When switching from a single $10 bet to the portfolio bet, the multipliers for the results remain the same. The expected value remains at $15, the variance remains at 0, and the standard.
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For the linear regression y = ẞ1 + ẞ2x + e, assuming that the sum of squared errors (SSE) takes the following form:
SSE = 382 +681 +382 + 18ẞ1ẞ2
Derive the partial derivatives of SSE with respect to B1 and B2 and solve the optimal values of these parameters.
a. B₁ = B1
b. B₂ =
The optimal values of these parameters are:
a. β₁ = 0
b. β₂ = 0
The linear regression y = β1 + β2x + e, assuming that the sum of squared errors (SSE) takes the following form:
SSE = 382 + 681 + 382 + 18β1β2
Derive the partial derivatives of SSE with respect to β1 and β2 and solve the optimal values of these parameters.
Given that SSE = 382 + 681 + 382 + 18β1β2 ∂SSE/∂β1 = 0 ∂SSE/∂β2 = 0
Now, we need to find the partial derivative of SSE with respect to β1.
∂SSE/∂β1 = 0 + 0 + 0 + 18β2 ⇒ 18β2 = 0 ⇒ β2 = 0
Therefore, we obtain the optimal value of β2 as 0.
Now, we need to find the partial derivative of SSE with respect to β2. ∂SSE/∂β2 = 0 + 0 + 0 + 18β1 ⇒ 18β1 = 0 ⇒ β1 = 0
Therefore, we obtain the optimal value of β1 as 0. Hence, the partial derivative of SSE with respect to β1 is 18β2 and the partial derivative of SSE with respect to β2 is 18β1.
Thus, the optimal values of β1 and β2 are 0 and 0, respectively.
Therefore, the answers are: a. β₁ = 0 b. β₂ = 0
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what is the maximum number of points of intersection of 4 rectangles
The maximum number of points of intersection for four rectangles is 16.
1. Start by considering two rectangles. The maximum number of points of intersection between these two rectangles is 8.
- Each rectangle has 4 corners, resulting in a total of 8 corners for both rectangles combined.
- The corners can intersect with each other, resulting in points of intersection.
2. Now, add a third rectangle to the configuration. Each corner of the third rectangle can intersect with the existing 8 corners, resulting in an additional 8 points of intersection. However, we also need to consider the intersections among the three rectangles' sides.
- There are 4 sides for each rectangle, resulting in a total of 12 sides for three rectangles.
- The sides can intersect at their endpoints or at other points along their length, potentially adding more points of intersection.
- The maximum number of intersections among the sides of three rectangles is 4.
3. Finally, add a fourth rectangle to the configuration. Each corner of the fourth rectangle can intersect with the existing 16 corners, resulting in an additional 16 points of intersection. We also need to consider the intersections among the sides of the fourth rectangle with the existing sides of the other three rectangles.
- There are 4 sides for the fourth rectangle, resulting in a total of 16 sides for all four rectangles.
- The maximum number of intersections among the sides of four rectangles is 0, as all four rectangles are already intersecting.
Adding up the points of intersection, we have 8 (corners) + 4 (intersections among sides) + 16 (new corners) = 28. However, we must consider that the intersections among the sides of four rectangles are already counted as corners, so we need to subtract 4 from the total.
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the figure above shows the graph of the twice-differentiable function g and the line tangent to the graph of g at the point (0,3). the value of limx→0g(x)e−x−3x2−2x is
Using L'Hopital's rule, we can find that the limit is equal to (g(0) - 3)/2.
Since the line tangent to g at (0,3) has slope 2, we know that g(0) - 3 = 2(0) = 0. Therefore, the limit is 0/2 = 0. Based on the given information, we have a twice-differentiable function g(x) and its tangent line at the point (0,3). To find the value of the limit as x approaches 0 for g(x)e^(-x) - 3x^2 - 2x, we can use L'Hopital's rule since it involves indeterminate forms of the type 0/0 or ∞/∞. Apply L'Hopital's rule twice on the given expression. Then, evaluate the resulting expression at x=0. This will give you the value of the limit for the given expression. Make sure to check if the conditions for using L'Hopital's rule are met before applying it.
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A diver is standing on a platform 29 ft above the pool. He jumps from the platform with an initial upward velocity of 9 f(t)/(s). Write an equation that shows he hits the water.
This equation 16t² - 9t - 29 = 0 he hits the water.
To write an equation describing when the diver hits the water, we need to consider the vertical motion of the diver. We can use the equation:
y = y₀ + v₀t + (1/2)gt²
where:
y is the vertical position at time t
y₀ is the initial vertical position
v₀ is the initial vertical velocity
g is the acceleration due to gravity
t is the time
Given the information:
y₀ = 29 ft (height of the platform above the water)
v₀ = 9 ft/s (initial upward velocity)
g = 32 ft/s² (acceleration due to gravity, assuming downward is positive)
Plugging in these values, we have:
y = 29 + 9t - (1/2)(32)t²
To find when the diver hits the water, we set y equal to zero:
0 = 29 + 9t - (1/2)(32)t²
Simplifying the equation, we get:
16t² - 9t - 29 = 0
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A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of 84648464 with a mean life of 886886 minutes. If the claim is true, in a sample of 145145 batteries, what is the probability that the mean battery life would be greater than 904.8904.8 minutes
We can conclude that it is extremely unlikely to obtain a sample mean greater than 904.8 minutes if the design engineer's claim about the population variance and mean is true.
We can use the Central Limit Theorem to approximate the distribution of the sample means.
Under the given assumptions, the mean of the sampling distribution of the sample means is equal to the population mean, which is 886886 minutes, and the standard deviation of the sampling distribution of the sample means is equal to the population standard deviation divided by the square root of the sample size, which is\(\sqrt{84648464/145145} = 41.77\) minutes.
Therefore, we can standardize the sample mean using the formula:
\(z = (\bar{x} - \mu) / (\sigma / \sqrt{n } )\)
where \(\bar{x}\) is the sample mean, \(\mu\) is the population mean, sigma is the population standard deviation, and n is the sample size.
Plugging in the values we get:
z = (904.8 - 886886) / (41.77) = -21115.47
The probability of getting a sample mean greater than 904.8 minutes can be calculated as the area under the standard normal curve to the right of z = -21115.47.
This probability is essentially zero, since the standard normal distribution is symmetric and nearly all of its area is to the left of -6.
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The art club had an election to select a president. 25% of the 80 members of the club voted in the election. How many members voted?
Answer:
20, the answer is 20 members
Answer:
3) On a test of 25 questions, a student 4) Alisa earned $30 raking leaves. She ... 80% horror. 6Sn-sdo 1800 ... How many tickets were a) What percent of her weight did sold? ... b) Atlantic Auditorium has 850 seats. b) At the next visit, we were happy to see ... members of the art club voted in the more students joined. election.
Step-by-step explanation:
place these numbers from least to greatest. ( PLS HELP!)
Answer: second option
Step-by-step explanation:
Sqrt 3= 1.73
Sqrt 6= 2.45
pi= 3.14
9.17% to the nearest degree
Answer:
33°
Step-by-step explanation:
9.17% = 9.17/100
\(\dfrac{9.17}{100}*360=0.917*36=33.012\)
= 33°
Answer:
33
Step-by-step explanation:
9.17÷100=0.0917/0.9170.917×36=33.012
You received an unknown that was negative for Lucas reagent, positive for iodoform, and positive for 2,4-DNP. Which one of these compounds could be your unknown? a. Formaldehyde (H2C=0) b. 1-butanol O c2-methyl-2-propanol d. Acetone (2-propanone)
Based on the results of the tests, the unknown compound could be Acetone (2-propanone). Option d. Acetone (2-propanone).
If you received an unknown that was negative for Lucas reagent, positive for iodoform, and positive for 2,4-DNP, then acetone would be the unknown compound. This is because Acetone is known to be negative for Lucas reagent, positive for iodoform, and positive for 2,4-DNP. Based on the provided information, your unknown compound is negative for Lucas reagent, positive for iodoform, and positive for 2,4-DNP. These results indicate that the unknown compound is d. Acetone (2-propanone).
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A painted water tower is shown. What percent of the surface area of the water tower (not including the surface underneath the tower) is green? Round your answer to the nearest tenth of a percent.
Answer:
43.6%
Step-by-step explanation:
curved surface area (green) is found by circumference multiply by height
\(\pi\) x d x h = \(\pi\) x (15 x 2) x 12 = 360\(\pi\)
total surface area is
blue circle + total curved surface area (blue + green)
= \(\pi\)\(r^{2}\) + 15(2)(8)\(\pi\) + 360\(\pi\)
= \(15^{2}\)\(\pi\) + 240\(\pi\) + 360\(\pi\)
= 825\(\pi\)
percentage = 360\(\pi\)/825\(\pi\) x 100%= 22/55 x 100% = 43.63
12aª²b²+ llab-5 with the solutions
Answer:
5127658756789587;'70
MHS Student Bookmarks Kami Export - How10.4 ReviewA group of 80 trees in a forest aren't growing properly. A botanist determines:• 68 of the trees have a disease or are being damaged by insects• 54 of the trees have a disease• 30 of the trees are being damaged by insectsWhat is the probability that a randomly selected tree has both a disease and is being damaged by insects?0꾧00 %0o1720ΟΟΟRE10123 9 5
Let the event that a tree has disease be D and the event that tree is being damaged by insects be I.
Therefore,
\(\begin{gathered} |D|=54 \\ |I|=30 \\ |D\cup I|=68 \\ \end{gathered}\)Recall that:
\(\begin{gathered} |D\cup I|=|D|+|I|-|D\cap I| \\ 68=54+30-|D\cap I| \\ \text{ Therefore,} \\ |D\cap I|=84-68=16 \end{gathered}\)The required probability is given by:
\(\frac{|D\cap I|}{80}=\frac{16}{80}=20\%\)Hence, the required probability is 20%=0.2
Direction: Read each statement and decide whether the answer is correct or not. If the statement is correct write true, if the statement is incorrect write false and write the correct statement (5 X 2 Mark= 10 Marks)
1. PESTLE framework categorizes environmental influences into six main types.
2. PESTLE framework analysis the micro-environment of organizations.
3. Economic forces are one of the types included in PESTLE framework.
4. An organization’s strength is part of the types studied in PESTLE framework.
5. PESTLE framework provides a comprehensive list of influences on the possible success or failure of strategies.
1. True. The PESTLE framework categorizes environmental influences into six main types: Political, Economic, Sociocultural, Technological, Legal, and Environmental factors.
These factors help analyze the external macro-environmental forces that can impact an organization's strategies and operations. 2. False. The PESTLE framework analyzes the macro-environmental factors and not the micro-environment of organizations. The micro-environment is examined through other frameworks like Porter's Five Forces, which focus on specific industry dynamics and competitive factors.
3. True. Economic forces, such as inflation, interest rates, exchange rates, and economic growth, are one of the types included in the PESTLE framework. Economic factors play a significant role in shaping business decisions and strategies.
4. False. An organization's strengths are not part of the types studied in the PESTLE framework. Strengths, weaknesses, opportunities, and threats (SWOT) analysis is a separate framework used to assess internal strengths and weaknesses of an organization.
5. True. The PESTLE framework provides a comprehensive list of influences on the possible success or failure of strategies. By considering the political, economic, sociocultural, technological, legal, and environmental factors, organizations can gain insights into the external forces that may impact their strategies and make informed decisions.
The PESTLE framework categorizes environmental influences into six main types, including political, economic, sociocultural, technological, legal, and environmental factors. It analyzes the macro-environmental forces, not the micro-environment of organizations. Economic forces are one of the types studied in the framework, while an organization's strengths are not included. The framework provides a comprehensive list of influences on the success or failure of strategies, allowing organizations to consider various external factors in their decision-making process.
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When a buh wa firt planted in a garden,it wa 12 inche tall. After two week, it wa 120% a tall a when it wa firt planted. How tall wa the buh after the two week
When a buh wa firt planted in a garden,it wa 12 inche tall. After two week, it wa 120% a tall a when it wa firt planted. Tall wa the buh after the two week is \(\\26 \frac{2}{5}\).
What is improper fractions?
An improper fraction is a fraction whose numerator is equal to or greater than its denominator. 3/4, 2/11, and 7/19 are proper fractions, while 5/2, 8/5, and 12/11 are improper fractions.
12 times 120% + 12
12*120%+12
\($$\begin{aligned}& 120 \% \text { in fractions: } \frac{6}{5} \\& =12 \times \frac{6}{5}+12\end{aligned}$$\)
Follow the PEMDAS order of operations
Multiply and divide (left to right) \($12 \times \frac{6}{5}: \frac{72}{5}$\)
\(=\frac{72}{5}+12$$\)
Add and subtract (left to right) \($\frac{72}{5}+12: \frac{132}{5}$\)
\(=\frac{132}{5}$$\)
Convert improper fractions to mixed numbers: \($\frac{132}{5}=26 \frac{2}{5}$\)
\(=26 \frac{2}{5}$$\)
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Which statement is the correct interpretation of the inequality −4 > −5?
On a number line, −4 is located to the left of 0 and −5 is located to the right of 0.
On a number line, −4 is located to the right of 0 and −5 is located to the left of 0.
On a number line, −4 is located to the right of −5.
On a number line, −4 is located to the left of −5.
Answer:
On a number line, −4 is located to the right of −5Step-by-step explanation:
We know that numbers increase from left to right on the number line.
- 4 > - 5 means:
- 4 is greater than -5 and therefore is located to the right of -5Correct choice is:
On a number line, −4 is located to the right of −5Answer:
On a number line, -4 is located to the right of 5!
Step-by-step explanation:
It is closer to the 0 therefore it is greater than 5 if you want more information...
<><><><<><><><><><><><><><><><><><><><><>
if you were to right a number line leading up to -8 - -7 - -6 etc..
then you would see and understand the value better! :D
Have a great week every one!!! / ( ` o w `o ) \
If f(x)=-9x-2, find f(7)
Answer:
x= -1/5
Let me know if you need an explanation :)
what is the difference between the critical value of z and the observed value of z (test statistic)?
The critical value of z separates the rejection region from the nonrejection region while observed value of z is the value calculated for a sample statistic such as x.
A critical value of z is used when the sampling distribution is normal, or close to normal. The critical value of z refers to the point that cuts off area under graph for the standard normal distribution separating the rejection and nonrejection region of the data. The Critical value of z can indicate what probability any particular variable will have. These values are typically obtained from a table such as the standard normal distribution table. The observed value of z is a value determined for a sample statistic x. It is a test statistic for Z-tests that measures the difference between an observed statistic and its hypothesized population parameter in units of the standard deviation.
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if mJK=(7x-39) and mML=87, find x
Answer:
https://brainly.com/question/9016553
Step-by-step explanation:
You can see the answers from the exact same question. In the link I pasted.
Not my answer but hope this helps
The average grade Jared received on 4 tests was 94. If he drops his lowest test grade of 85, what will his new average be?
A.72.75
B.76
C.89.5
D.97
Pls help TT
Answer:
total points on the 4 tests- 94x4= 376
376- 85= 291
291/3= D. 97
Answer:
D. 97
Step-by-step explanation:
x = sum of 4 test grades Jared received
\(\frac{x}{4} = 94\)
x = 376
If he drops lowest test grade of 85, then subtract 85 from Jared's sum of all test grades:
x - 85 --> 376 - 85
= 291
Now that one of his test grades are not considered, this means there are only 3 test grades to consider.
291 must be divided by 3 to get the average:
\(\frac{291}{3}\) = 97
The answer is D) 97
Solve. x/4 + ½ = 1/8
x = ____ (Simplify your answer.)
Answer:
\( \frac{x}{4} + \frac{1}{2} = \frac{1}{8} \)
\( \frac{x}{4} = - \frac{3}{8} \)
\(x = - \frac{3}{2} = - 1 \frac{1}{2} \)
The solution to the equation x/4 + 1/2 = 1/8 is x = -3/2.
Consider the equation, we have only one x term, so taking all the terms without x to the other side and terms with x on one side.
x/4 + 1/2 = 1/8
Take the 1/2 term on the other side,
x/4=1/8 - 1/2
Taking the LCM on the Right side,
x/4 = (1-4) / 8
x/4 = -3/8
Now, we have x/4 so what we can do is, shift the 4 to the other side too, we get,
x = ( -3/8) * 4
x = -3/2
The solution to the equation x/4 + 1/2 = 1/8 is x = -3/2.
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What is the factor of x³ 5x² 2x 24?
The factor of x3 5x2 2x 24 is (x - 4)(x + 2)(x + 6), which can be expanded as x3 + 2x2 - 4x2 + 6x - 8x - 24.
1. Factor out the greatest common factor (GCF) from the coefficients of the terms.
x3 5x2 2x 24
2. Factor out the GCF from each term:
x3 = x•x•x
5x2 = 5•x•x
2x = 2•x
24 = 24
3. Our factors are now:
x•x•x 5•x•x 2•x 24
4. Group the terms with common factors:
(x•x•x) (5•x•x) (2•x) (24)
5. Factor out the common factor from each group:
x•x (x•5) (2•x) (24)
6. Our factors are now:
x (x•5) (2•x) (24)
7. Factor out the common factor from each group:
x (x•5) (2•x) (24)
8. Our factors are now:
x (x + 2)(x + 6) (24)
9. Our final answer is:
(x - 4)(x + 2)(x + 6)
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The polynomial which results from the expansion of $(x^2+5x+6)^2+(px+q)(x^3+7x^2+3x)$ has degree $2$. Find $p+q$.
The value of p + q is 0.
To determine the degree of the polynomial resulting from the given expansion, we need to multiply the terms within the parentheses and add their exponents. Let's expand the expression step by step:
First, expand (x^2 + 5x + 6)^2:
(x^2 + 5x + 6)^2 = (x^2 + 5x + 6)(x^2 + 5x + 6)
Expanding this using the distributive property:
= x^2(x^2 + 5x + 6) + 5x(x^2 + 5x + 6) + 6(x^2 + 5x + 6)
= x^4 + 5x^3 + 6x^2 + 5x^3 + 25x^2 + 30x + 6x^2 + 30x + 36
= x^4 + 10x^3 + 37x^2 + 60x + 36
Next, expand (px + q)(x^3 + 7x^2 + 3x):
(px + q)(x^3 + 7x^2 + 3x) = px(x^3 + 7x^2 + 3x) + q(x^3 + 7x^2 + 3x)
= p(x^4 + 7x^3 + 3x^2) + q(x^3 + 7x^2 + 3x)
= px^4 + 7px^3 + 3px^2 + qx^3 + 7qx^2 + 3qx
Adding the two expanded expressions together:
x^4 + 10x^3 + 37x^2 + 60x + 36 + px^4 + 7px^3 + 3px^2 + qx^3 + 7qx^2 + 3qx
To have a resulting polynomial of degree 2, the terms with x^4, x^3, and higher powers must cancel out. This means that px^4 and qx^3 terms must be zero. Therefore, p = 0 and q = 0.
Finally, p + q = 0 + 0 = 0.
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A group of students is arranging squares into layers to create a project. The first layer has 5 squares. The second layer has 10 squares. Which formula represents an arithmetic explicit formula to determine the number of squares in each layer ?
Answer: Its B i just took the test
Step-by-step explanation:
Find the value of x that makes the statement true.
3/5x-5+x-4 =-1
A. -5
B. 5
C. 7
D. -7
Step-by-step explanation:
I guess the equation is
(3/5)x - 5 + x - 4 = -1
or is it
(3/5)(x - 5) + x - 4 = -1 ?
or is it
3/(5x) - 5 + x - 4 = -1 ?
or is it
3/(5x - 5) + x - 4 = -1 ?
or even something else ?
the way you wrote it, following the rules strictly, it would be the first option I listed.
so, it is
(3/5)x - 5 + x - 4 = -1
3x/5 - 5 + x - 4 = -1
3x/5 -9 + x = -1
3x/5 + x = 8
3x + 5x = 40
8x = 40
x = 5, and B would be the right answer.
Answer:
B
Step-by-step explanation:
5
61 randomly selected students were asked the number of pairs of shoes they have. Let X represent the number of pairs of shoes. The results are as follows:
Complete question :
61 randomly selected students were asked the number of pairs of shoes they have. Let X represent the number of pairs of shoes. The results are as follows:
Pairs of Shoes4__5__6__7 __8 __9 __10 __11
Frequency : _ 8 _ 8 __5 _ 5 _ 9 __11 __7 ___8
Answer:
Mean = 7.64 ;
Median = 8
Q1 = 5
Q3 = 9
Atleast 10 pairs = 24.6
76% is equivalent to
Step-by-step explanation:
Round all your answers to 4 decimal places where possible.
10
The mean is:
Σfx /Σf
((8*4)+(5*8)+(6*5)+(7*5)+(8*9)+(9*11)+(10*7)+11*8)) ÷ (8+8+5+5+9+11+7+8) = 7.64
The median is:
0.5(n+1)th observation
n = frequency = 61
0.5(61 +1) = 1/2 * 62 = 31st observation
= 8
First quartile:
0.25(n+1)th observation
n = frequency = 61
0.25(61 +1) = 1/4 * 62 = 15.5
(15 + 16)th observation ÷ 2 = (5 + 5) / 2 = 5
The sample standard deviation is:
The third quartile is:
0.75(n+1)th observation
n = frequency = 61
0.75(61 +1) = 1/4 * 62 = 46.5
(46 + 47)th observation ÷ 2 = (5 + 5) / 2 = 9
What percent of the respondents have at least 10 pairs of Shoes? %
(7 + 8) / 61 = 15 / 61 = 0.246
76% of all respondents have fewer than how many pairs of Shoes?
(76 / 100) * 61
0.76 * 61
= 46.36
(46th + 47th)
(9 + 10) = 19 /2 = 9.5 = 10
what is a translation graph
Answer:A TRANSLATION OF A GRAPH
Step-by-step explanation:is its rigid movement, vertically or horizontally. On the left is the graph of the absolute value function.
test the claim about the population mean μ at the level of significance α. assume the population is normally distributed. claim: μ>29; α=0.05; σ=1.2 sample statistics: x=29.3, n=50
Based on the sample data and the hypothesis test, there is sufficient evidence to support the claim that the population mean μ is greater than 29 at the significance level of 0.05.
What is the mean and standard deviation?
The standard deviation is a summary measure of the differences of each observation from the mean. If the differences themselves were added up, the positive would exactly balance the negative and so their sum would be zero. Consequently, the squares of the differences are added.
To test the claim about the population mean μ at the level of significance α, we can perform a one-sample t-test.
Given:
Claim: μ > 29 (right-tailed test)
α = 0.05
σ = 1.2 (population standard deviation)
Sample statistics: x = 29.3 (sample mean), n = 50 (sample size)
We can follow these steps to conduct the hypothesis test:
Step 1: Formulate the null and alternative hypotheses.
The null hypothesis (H₀): μ ≤ 29
The alternative hypothesis (Hₐ): μ > 29
Step 2: Determine the significance level.
The significance level α is given as 0.05. This represents the maximum probability of rejecting the null hypothesis when it is actually true.
Step 3: Calculate the test statistic.
For a one-sample t-test, the test statistic is given by:
t = (x - μ) / (σ / √(n))
In this case, x = 29.3, μ = 29, σ = 1.2, and n = 50. Plugging in the values, we get:
t = (29.3 - 29) / (1.2 / √(50))
= 0.3 / (1.2 / 7.07)
= 0.3 / 0.17
≈ 1.76
Step 4: Determine the critical value.
Since it is a right-tailed test, we need to find the critical value that corresponds to the given significance level α and the degrees of freedom (df = n - 1).
Looking up the critical value in a t-table with df = 49 and α = 0.05, we find the critical value to be approximately 1.684.
Step 5: Make a decision and interpret the results.
If the test statistic (t-value) is greater than the critical value, we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.
In this case, the calculated t-value is approximately 1.76, which is greater than the critical value of 1.684. Therefore, we reject the null hypothesis.
hence, Based on the sample data and the hypothesis test, there is sufficient evidence to support the claim that the population mean μ is greater than 29 at the significance level of 0.05.
To learn more about the mean and standard deviation visit:
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{ (3,7), (-3,5), (0,4), (-1,5), (6,-2)}
what is the domain:
what is the range:
is this a function?
Answer:
domain -3<x<6
range -2<y<7
it is a function
Answer:
Domain:{3,-3,0,-1,6}
Range:{7,5,4,5,-2}
Since there is one value of y for every value of x , this relation is a function.
The relation is a function.
Step-by-step explanation:
What is the absolute value of −1 1/3?
Use this number line to determine the absolute value.
Answer:
the answer is a
Step-by-step explanation:
i did the quiz
Answer:
The answer is 1 1/3
Step-by-step explanation:
I took the test but reviewed my test and it said this was the correct answer