Solve the following equation for b. 6b + 2a – 4 = 2b + 3a
Group of answer choices

Answer:

c

Step-by-step explanation:

i took the test

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Sometimes  hope that helps you and hope you pass : >

Answer:

Always

Step-by-step explanation:

- Parallel lines can be defined as two lines in the same plane that are at equal distance from each other and never meet.

- Parallel lines are congruent and so their measure will ALWAYS be the same

There are 4845 different ways to select 16 questions out of a total of 20 questions on the exam.

To determine the number of different ways you can select 16 questions out of a total of 20 questions, we can use the concept of combinations.

In this case, we want to select 16 questions from a set of 20 questions, and the order in which we select them doesn't matter. This scenario can be represented by the combination formula.

The formula for combinations is given by:

C(n, k) = n! / (k!(n-k)!)

Where:

n is the total number of items in the set (20 questions)

k is the number of items to be selected (16 questions)

! denotes the factorial operation

Using the combination formula, we can calculate the number of different ways to select the questions:

C(20, 16) = 20! / (16!(20-16)!)

= 20! / (16!4!)

= (20 * 19 * 18 * 17) / (4 * 3 * 2 * 1)

= 4845

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To find a fourth-order ordinary differential equation (ODE) with constant coefficients we need to express the solutions in terms of their derivatives and substitute them into the general form of a fourth-order ODE.

Let's start by expressing the given solutions in terms of their derivatives: y₁ = x * e^(c+1)x = cos(d+1)x,

y₂ = x * e^(c+1)x * sin(d+1)x,

y₃ = e^(c+1)x * cos(d+1)x,

y₄ = e^(c+1)x * sin(d+1)x. Now, let's find the derivatives of these functions: y₁' = (e^(c+1)x) + (x * e^(c+1)x * (-sin(d+1)x)) = e^(c+1)x - x * e^(c+1)x * sin(d+1)x,

y₂' = (e^(c+1)x * sin(d+1)x) + (x * e^(c+1)x * cos(d+1)x) + (x * e^(c+1)x * cos(d+1)x) = e^(c+1)x * sin(d+1)x + 2x * e^(c+1)x * cos(d+1)x,

y₃' = (e^(c+1)x * (-sin(d+1)x)) + (e^(c+1)x * cos(d+1)x) = -e^(c+1)x * sin(d+1)x + e^(c+1)x * cos(d+1)x,

y₄' = (e^(c+1)x * cos(d+1)x) + (e^(c+1)x * sin(d+1)x) = e^(c+1)x * cos(d+1)x + e^(c+1)x * sin(d+1)x.

Taking further derivatives, we get: y₁'' = (e^(c+1)x - x * e^(c+1)x * sin(d+1)x)' = (e^(c+1)x)' - (x * e^(c+1)x * sin(d+1)x)' = (e^(c+1)x)' - (x * e^(c+1)x * (sin(d+1)x) + x * e^(c+1)x * (cos(d+1)x)) = e^(c+1)x - x * e^(c+1)x * sin(d+1)x - x * e^(c+1)x * cos(d+1)x, y₂'' = (e^(c+1)x * sin(d+1)x + 2x * e^(c+1)x * cos(d+1)x)' = (e^(c+1)x * sin(d+1)x)' + (2x * e^(c+1)x * cos(d+1)x)' = (e^(c+1)x * sin(d+1)x + 2x * e^(c+1)x * cos(d+1)x)' = e^(c+1)x * sin(d+1)x + 2 * e^(c+1)x * cos(d+1)x + 2x * (-e^(c+1)x * sin(d+1)x + e^(c+1)x * cos(d+1)x) = e^(c+1)x * sin(d+1)x + 4x * e^(c+1)x * cos(d+1)x - 2x * e^(c+1)x * sin(d+1)x + 2x * e^(c+1)x * cos(d+1)x = (4x * e^(c+1)x * cos(d+1)x - 2x * e^(c+1)x * sin(d+1)x) + (e^(c+1)x * sin(d+1)x + 2x * e^(c+1)x * cos(d+1)x), y₃'' = (-e^(c+1)x * sin(d+1)x + e^(c+1)x * cos(d+1)x)' = (-e^(c+1)x * sin(d+1)x)' + (e^(c+1)x * cos(d+1)x)' = (-e^(c+1)x * sin(d+1)x - e^(c+1)x * cos(d+1)x) + (e^(c+1)x * cos(d+1)x + e^(c+1)x * sin(d+1)x) = -e^(c+1)x * sin(d+1)x - e^(c+1)x * cos(d+1)x + e^(c+1)x * cos(d+1)x + e^(c+1)x * sin(d+1)x = 0, y₄'' = (e^(c+1)x * cos(d+1)x + e^(c+1)x * sin(d+1)x)' = (e^(c+1)x * cos(d+1)x)' + (e^(c+1)x * sin(d+1)x)' = (e^(c+1)x * cos(d+1)x + e^(c+1)x * sin(d+1)x) + (e^(c+1)x * sin(d+1)x + e^(c+1)x * cos(d+1)x) = 2 * e^(c+1)x * cos(d+1)x + 2 * e^(c+1)x * sin(d+1)x.

Now, we substitute these derivatives into the general form of a fourth-order ODE: a₄ * y₄'' + a₃ * y₃'' + a₂ * y₂'' + a₁ * y₁'' + a₀ * y = 0. a₄ * (2 * e^(c+1)x * cos(d+1)x + 2 * e^(c+1)x * sin(d+1)x) + a₃ * 0 + a₂ * (e^(c+1)x * sin(d+1)x + 4x * e^(c+1)x * cos(d+1)x - 2x * e^(c+1)x * sin(d+1)x + 2x * e^(c+1)x * cos(d+1)x) + a₁ * (e^(c+1)x - x * e^(c+1)x * sin(d+1)x - x * e^(c+1)x * cos(d+1)x) + a₀ * (e^(c+1)x * cos(d+1)x + x * e^(c+1)x * sin(d+1)x) = 0. Expanding and simplifying this equation will give us the fourth-order ODE with constant coefficients based on the given fundamental set of solutions. The specific values of a₄, a₃, a₂, a₁, and a₀ will determine the exact form of the ODE.

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Answer:

absolute value its written as:

| expression | > x

*> written can also be < , ≥ , or ≤

| | (two vertical lines on both sides of something) indicate absolute value

(absolute value considers the space between a number and 0;

| x | = 3

then x could be = 3 or = -3

you can also think of anything inside | | to be written as positive;

| 3 | = 3

| -3 | = 3)

you could also right, from this example: | x | > 3

our value of x could either be greater than 3, or, our x-value is negative (and only the absolute value is greater than 3, meaning that negative -x, is greater than three)

we separate these possibilities into two expressions:

x > 3         - x > 3

              · -1     · -1    {inequalities flip direction when multiply by negative}

                  x < -3

so, x > 3 and x < -3 can be combined:

x > 3  or x < 3

(graph of example attached)

hope this helps!!

Answer:

187.96cm

Step-by-step explanation:

first convert 6 feet to cm=182.88

then convert 2 inches to cm=5.08

add your answers together=187.96

Answer:

Time = 133.3 secs

Step-by-step explanation:

Speed = Distance / Time

Rearranging the formula

Time = Distance / Speed

Where D = 200 m , S = 1.5 m/s

Time = 200 / 1.5

Time = 133.3 secs

Answer:

133.3 seconds

Step-by-step explanation:

200/1.5 = 133.3

Answer:

she should just divide the dimensions by 3

Step-by-step explanation:

Approximately 84.85% of the products must be scrapped due to the process not meeting the specified tolerance limits, while there is no percentage of product that can be reworked.

To determine the percentage of the product that must be scrapped and the percentage that can be reworked, we need to analyze the specifications and process capability.

We have,

- Diameter of the location pins: 12.50 mm

- Tolerance: +0.05 mm and -0.05 mm

- Process centered at 12.50 mm

- Dispersion: 0.02 mm

Let's break down the information and calculate the process capability indices (Cp and Cpk) to assess the capability of the process.

Cp is calculated using the formula Cp = (USL - LSL) / (6 * Standard Deviation).

USL (Upper Specification Limit) = Process Mean + Tolerance = 12.50 + 0.05 = 12.55 mm

LSL (Lower Specification Limit) = Process Mean - Tolerance = 12.50 - 0.05 = 12.45 mm

Standard Deviation = Dispersion / 6 = 0.02 / 6 = 0.0033 mm

Cp = (12.55 - 12.45) / (6 * 0.0033) ≈ 0.5051

Next, we calculate Cpk using the formula Cpk = min((USL - Mean) / (3 * Standard Deviation), (Mean - LSL) / (3 * Standard Deviation)).

Cpk = min((12.55 - 12.50) / (3 * 0.0033), (12.50 - 12.45) / (3 * 0.0033))

   = min(0.1515, 0.1515) = 0.1515

To determine the percentage of product that must be scrapped and reworked, we look at the capability indices.

If Cpk < 1, it indicates that the process is not capable of consistently producing within the specified tolerance limits. In such cases, the percentage of product that must be scrapped is calculated as:

Scrap percentage = (1 - Cpk) * 100

If Cpk ≥ 1, it indicates that the process is capable of consistently producing within the specified tolerance limits. In such cases, the percentage of product that can be reworked is calculated as:

Rework percentage = (1 - Cp) * 100

In this case, Cpk = 0.1515, which is less than 1. Therefore, the percentage of product that must be scrapped is:

Scrap percentage = (1 - Cpk) * 100 = (1 - 0.1515) * 100 ≈ 84.85%

Since the process is not capable of consistently producing within the specified tolerance limits, there is no percentage of product that can be reworked.

To summarize:

- Scrap percentage: 84.85%

- Rework percentage: 0%

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When the boat is 10 m from the dock, it is approaching the dock at the rate of √125/10 m/s.

  In mathematics, a differential equation is a relationship between the derivatives of one or more unknown functions. Applications frequently involve a differential equation that provides a connection between the three, functions that reflect physical quantities, derivatives that show the rates at which those values change, and derivatives that represent the rates of change.

Let x = distance of the boat from the dock at time t

    y = length of rope at time t

Draw a right triangle with horizontal leg x, vertical leg 5, and hypotenuse y.

We know that dy/dt = -1 and want to find dx/dt when x = 10.

By the Pythagorean Theorem, x^2 + 5^2 = y^2.

   2x(dx/dt) = 2y(dy/dt)

        dx/dt = y(dy/dt) / x     When x = 10, y2 = 100 + 25 = 125

                                                            So, y = √125

         dx/dt = -√125 / 10

When the boat is 10 m from the dock, it is approaching the dock at the rate of √125/10 m/se

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Answer:

111

Step-by-step explanation:

72+39+1=111

Answer:

a) red

b) red

c) the blue one is y=1/2x+1

Step-by-step explanation:

Answer:

3.0

Step-by-step explanation:

bcbcbbcbc

The height of the cylinder will be 5 units based on the information given.

The cylinder has a volume of 45π cubic meters and the radius is 3 units.

The height will be calculated thus:

Volume of a cylinder = πr²h

45π = πr²h

45π = π(3²)h

45π = 9πh

h = 45π/9π

h = 5

Therefore, the height of the cylinder will be 5. units.

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Answer:

-4/9

Step-by-step explanation:

Slope formula: y2-y1/x2-x1

7-(-2)/-3-1

9/-4

-4/9

Best of Luck!

Answer:

2

Step-by-step explanation:

f=1

=4-2f

=4-2(1)

=4-2

=2

Hope this helps ;) ❤❤❤

Answer:

Step-by-step explanation:

\(4-2f\\\\f =1\\4-2(1)\\=4-2\\= 2\)

Answer:

63

Step-by-step explanation:

9(7+9) = 63 +81

Answer:

Hi your answer is 144 i don't how i got but it is 144

Answer:

i can't see the pitcure

Step-by-step explanation:

Answer:

Step-by-step explanation:

16/28

The answer is:

4/7

Work/explanation:

To find an equivalent fraction for 8/14, we will reduce it to its lowest terms, by dividing both its numerator and its denominator by 2:

\(\sf{\dfrac{8\div2}{14\div2}}\)

\(\sf{\dfrac{4}{7}}\)

Hence, a fraction equivalent to 8/14 is 4/7.

The thing to remember is that it's by far not the only option. In fact, there are infinite options. You can't divide anymore, but you can multiply 8/14 by 2, 3, 4, etc. As long as you multiply the numerator and the denominator by the same number, you'll get an equivalent fraction.

Answer:

Answer of 15(i) is the picture . 15(ii) and 17 are solved

Step-by-step explanation:∆ABC where B=90°

→D is mod point of BC so CD=BD

To Prove:

→BC^2=4(AD^2-AB^2)

PROOF:--

In ∆ABD by pythagorus theorem we get,

AD^2=AB^2+BD^2

SO

➡️BD^2= AD^2-AB^2. (1)

NOW ,

BC= BD+CD

BC= 2BD (AS D IS MID POINT)

SQUAREING BOTH SIDES

BC^2= 4BD^2

BY EQUATION 1 WE GOT BD^2 = AD^2-AB^2

Putting this value

➡️BC^2= 4(AD^2-AB^2)

HENCE PROVED

-------------------------------------------------------------------------

17.

Construction : Draw AE ⊥ BC

Proof : In ∆ABE and ∆ACE, we have

AB = AC [given]

AE = AE [common]

and ∠AEB = ∠AEC [90°]

Therefore, by using RH congruent condition

∆ABE ~ ∆ACE

⇒ BE = CE

In right triangle ABE.

AB2 = AE2 + BE2 ...(i)

[Using Pythagoras theorem]

In right triangle ADE,

AD2 = AE2 + DE2

[Using Pythagoras theorem]

Subtracting (ii) from (i), we get

AB2 - AD2 = (AE2 + BE2) - (AE2 + DE2)

AB2 - AD2 = AE2 + BE2 - AE2 - DE2

⇒ AB2 - AD2 = BE2 - DE2

⇒ AB2 - AD2 (BE + DE) (BE - DE)

But BE = CE [Proved above]

⇒ AB2 - AD2 = (CE + DE) (BE - DE)

= CD.BD

⇒ AB2 - AD2 = BD.CD

Hence Proved.

The fοrmula D = m/4, we can calculate the diffusiοn cοnstant 'D' as:

D = 1.24/4 = 0.31

Diffusiοn is the prοcess by which particles οf a substance mοve frοm an area οf high cοncentratiοn tο an area οf lοwer cοncentratiοn, resulting in a net mοvement οf particles dοwn their cοncentratiοn gradient.

This οccurs due tο the randοm mοtiοn οf individual particles, which leads tο a tendency fοr particles tο spread οut and becοme evenly distributed οver time.

Answer tο Questiοn 9:

The relatiοnship between average displacement squared (R²) and time (t) is linear.

Answer tο Questiοn 10:

The variable 'R2' in the diffusiοn equatiοn cοrrespοnds tο 'y' in the trendline equatiοn, and the variable 't' in the diffusiοn equatiοn cοrrespοnds tο 'x' in the trendline equatiοn.

Answer tο Questiοn 11:

We can sοlve fοr the diffusiοn cοnstant 'D' in terms οf the slοpe 'm' and a cοnstant 'c' by equating the diffusiοn equatiοn and the trendline equatiοn.

The diffusiοn equatiοn: R2 = 4Dt

The trendline equatiοn: y = mx + b

Substituting the cοrrespοnding variables, we get:

R2 = y, D = cοnstant, t = x, m = slοpe, b = cοnstant

Sο, we have:

R2 = 4Dt

y = mx + b

Equating the twο equatiοns, we get:

y = 4Dx + 0 (since b = 0)

Cοmparing this with the trendline equatiοn y = mx + b, we can see that:

m = 4D

Therefοre, we can sοlve fοr 'D' as:

D = m/4

Answer tο Questiοn 12:

Given the trendline equatiοn y = 1.24x + 5.63, we can see that the slοpe 'm' is 1.24.

Using the fοrmula D = m/4, we can calculate the diffusiοn cοnstant 'D' as:

D = 1.24/4 = 0.31

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Answer:

\( \frac{3}{2} \)

Step-by-step explanation:

To find the slope of the perpendicular line, we must first find the slope of the given line.

This can be done by rearranging the equation into the slope intercept form.

2x +3y= -3

3y= -2x -3

y= -⅔x -1

Thus, the slope of the given line is -⅔.

The slope of the perpendicular line is the negative reciprocal of the given line.

Slope of perpendicular line \( = \frac{3}{2} \)

What is slope-intercept form?

Negative reciprocal

Negative reciprocal of -⅔

\( = - 1 \div ( - \frac{2}{3} )\)

\( = - 1 \times ( - \frac{3}{2} )\)

\( = \frac{3}{2} \)

Answer:

24 maximum

Step-by-step explanation:

Unless theres extra information we can't see, it is 24, because you can't have a snack bag with half an almond.

Answer:

the answer is 24 with each one with 4 bags, hope you can answer in time

Answer:

17.4%

Step-by-step explanation:

Find new values:

88(1+0.25)=110

125(1+0.12)=140

           Last Year      This Year

Boys        88                  110

Girls        125                  140

Total       213                  250

Find overall increase:

213(1+r)=250

213(1+r)=250

213(1+r)/213=250/213

1+r=1.173709 (Subtract 1)

r=0.173709 (Multiply by 100 and round to nearest 10th)

Final Answer: 17.4%

g(x) = 2x

9(-1) = -2

f(x) = 3x-2

f(g(-1)) = f(-2) = 3*(-2) - 2 = -8

Answer:

-8

Step-by-step explanation:

g(-1)= 2 * -1 = -2

So f(g(-1)) will be f(-2)

F(-2) = (3 * -2) - 2

= -6 - 2

= -8

64 fluid ounces contain 1920 milliliters.

Oz to Half Gallon Conversions

A half gallon is equal to 64 ounces in a gallon measurement.

A milliliter is equal to how many ounces. The conversion factor from fluid ounces to milliliter is 1 fluid ounce = 30 milliliter.

This equates to eight 8-ounce glasses or 2,000 ml (approximately 64 ounces) for a person who consumes 2,000 calories per day.

Given: She regularly drinks 64 fluid ounces of water.

       1 fluid = 30 milliliters

       => 30 × 64 = 1920 milliliters

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Answer:

f(-3)=4

Step-by-step explanation:

Substitute x=-3 into the function

f(-3)=(-3)^2-5

f(-3)=9-5

f(-3)=4

Answer:

f(-3) = 4

Step-by-step explanation:

f(x) = x² - 5

f(x) is a function with input x, meaning it is an expression which has terms involving x;

x is a variable and can be considered a space holder;

f(-3) is the function with input -3, this simply means replacing the space holder, i.e. x, with -3;

f(-3) = (-3)² - 5

f(-3) = 9 - 5

f(-3) = 4

Answer:

10

Step-by-step explanation:

its a tripple: 3,4,5 (except everything is multiplied by 2)

no need to thank me, just mark me brainliest plz ;)

Step-by-step explanation:

hyp² = opp²/adj²

\(x {}^{2} = 6 {}^{2} + 8 {}^{2} \\ x { }^{2} = 36 + 64 \\ x {}^{2} = 100 \\ x = \sqrt{100 } \\ x = 10\)

Answer:

hi

Step-by-step explanation:

Answer:

Step-by-step explanation:

2(x+3)

=(2)(x+3)

=(2)(x)+(2)(3)

=2x+6