Answer:
the answer is lucid dreamers ..hope it helped you dear
What do the top of a zip line and the top of a bungee cord have in common
Answer:
They are both placed at high vantage points for an optimal experience.
Explanation:
Gravity works in your favor when participating in bungee jumping as well as ziplining
A massless rod is attached to the ceiling by a string. Two weights are hung from the rod: a 0.4-lb weight at its left end and a 1.2-lb weight at its right end. The length of the rod is L and a string is attached (3L/4 from its left end) so that the rod (with attached weights) is horizontal. What is the tension in the string supporting the rod and the attached weights
The tension in the string supporting the rod and the attached weights is 7.11 N.
Tension in the string supporting the rodThe tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.
T = (m1 + m2)g
where;
m1 and m2 are the two masses supported0.4lb + 1.2lb = 1.6lb = 0.725 kg
T = 0.725 x 9.8
T = 7.11 N
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An airplane from rest accelerates on a runway at 7.25 m/s² for 35 seconds until it finally takes off the ground. Solve the distance covered by the airplane.
G:
R:
E:
S:
A:
2.How long will it take for a car to travel from 37 m/s to 60 m/s that accelerates at 3.68m / s²
G:
R:
E:
S:
A::
It will take the car 6.25 seconds to travel from 37 m/s to 60 m/s with an acceleration of 3.68 m/s².
For the first question, we can use the equation:
distance = 0.5 x acceleration x time^2
We know the acceleration (7.25 m/s²) and the time (35 seconds), so we can plug those in:
distance = 0.5 x 7.25 m/s² x (35 s)^2
distance = 0.5 x 7.25 m/s² x 1225 s²
distance = 4448.125 meters
Therefore, the airplane covered a distance of 4448.125 meters before taking off the ground.
For the second question, we can use the equation:
final velocity = initial velocity + acceleration x time
We know the initial velocity (37 m/s), the final velocity (60 m/s), and the acceleration (3.68 m/s²), so we can rearrange the equation to solve for time:
time = (final velocity - initial velocity) / acceleration
time = (60 m/s - 37 m/s) / 3.68 m/s²
time = 6.25 seconds
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why water is optically denser than air
Answer: Speed of light in air is more than speed of light in water, which means water is optically denser than air.
Answer:
There
Explanation:
A medium is denser when the speed of light gets reduced when light travels through that medium. When water travels through water, its speed gets reduced. Hence, it is a optically denser medium. Speed of light in air is more than speed of light in water, which means water is optically denser than air.
Find the height of a cylinder with a volume of 220inand a radius of 3 inches. Round
your answer to the nearest hundredth.
07.78 inches
6.93 inches
5.00 inches
9.84 inches
\(\huge{ \mathcal{ \underline{ Answer} \: \: ✓ }}\)
Given :
volume = 220 in³radius = 3 inSolution :
\( \large\boxed{ \mathrm{volume = \pi {r}^{2}h }}\)
\(220 = \dfrac{22}{7} \times 3 \times 3 \times h\)\( \dfrac{220 \times 7}{22 \times 3 \times 3} = h\)\( \dfrac{10 \times 7}{3 \times 3} = h\)\(h = \dfrac{70}{9} \)\( \boxed{h \: = 7.78 \: \: in}\)_____________________________
\(\mathrm{ \#TeeNForeveR}\)
Answer:
0.078 inches
Explanation:
The volume of a cylinder is \(V=\pi r^{2} h\). \(r\) is the radius of the cylinder, \(h\) is the height of the cylinder, and \(V\) is the total volume.We can divide both sides by \(9\pi\) to isolate the height. We now have \(\frac{220}{9\pi }=h\).We can plug in \(220\) for the value of \(V\), and insert 3 as \(r\). Now, we have \(220 = \pi (3^2)(h)\).We can simplify the right side by finding the value of \(3^2\), which is \(3*3\), or \(9\). We now have \(220 = 9\pi h\).Divide both sides by \(9\pi\) so we can isolate the height! We now have \(\frac{220}{9\pi }=h\).It would be best to use a calculator at this point. Plug the above equation into a calculator; otherwise, replace \(\pi\) with \(3.14\) and simplify the fraction. You should get about \(07.7809...\) which we can round to the nearest hundredths (since this is Geometry, I am assuming you know how to round).Our final answer is \(07.78\) inches.Hopefully this was of use!
what is the work done by the force of gravity on the beachball during this process? give your answer with the correct sign (positive or negative).
The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.
Is work done by gravity positive or negative?Work done by a force is defined as the sum of an object's or particle's displacement and the component of the force acting in the direction of the object's motion.The product of an object's displacement and the component of the applied force that is directed in the direction of the object's displacement is known as the work done by a force.Depending on which way an object is going, the amount of work done to overcome gravity can either be negative or positive.The work done by gravity will be negative if the object goes upward since gravity pulls in the opposite direction from the displacement. The work done by gravity will be positive if an object moves downward since both gravity and displacement are moving in the same direction.To Learn more About gravity refer to :
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a binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure? (a) true (b) false
The given statement '' A binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure '' is True.
A binary phase diagram is a graphical representation that shows the phases of two elements, at least one of which is metallic, as a function of composition and temperature at a specific pressure, typically atmospheric pressure.
The diagram displays different regions representing the stability of different phases (such as solid, liquid, and gas) as the composition and temperature of the system are varied. It is a valuable tool in understanding the behavior and phase transitions in binary systems.
Hence, The given statement '' A binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure '' is True.
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When the energy of a wave increases, what happens to the amplitude?
Answer:
The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.
Explanation:
When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.
What is the amplitude of a wave?The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.
It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.
Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.
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a round asteroid has a surface gravity of 0.0288
If the mass of the asteroid is 1.10x10^18 kg, what is its radius??
Answer:
50473.45
Explanation:
(6.67×10^-11)(1.10×10^18)/(x)^2=0.0288.
answer: 5.047345 × 10^4 (50473.45)
George rides his bike to his friend’s house that is 5 kilometers from his house. If he rides his bike at an average speed of 15 km/h, how long will it take him to get to his friend’s house?
Answer:
The answer is 0.33 H!
Explanation:
Use the list to answer the question.
potassium, Group 1
calcium, Group 2
iodine, Group 17
neon, Group 18
Which two elements in the list would bond together based on their ionic charges?(1 point)
potassium and neon
potassium and iodine
calcium and neon
calcium and potassium
Answer: Potassium and Iodine
Explanation:
I took the quick check and it’s right.
What do all elements in a column in the periodic table have in common? (2 points)
Answer:
Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.
Explanation:
A projectile is fired from a gun near the surface of Earth. The initial velocity of the projectile has a vertical component of 148 meters per second and a horizontal component of 149 meters per second. How long will it take the projectile to reach the highest point in its path
A projectile is fired from a gun near the surface of Earth. The initial velocity of the projectile has a vertical component of 148 meters per second and a horizontal component of 149 meters per second. It will 15 second take the projectile to reach the highest point in its path
There are numerous formulas available for computing time, final velocity, initial velocity, etc.
But in this case, the simplest formula to use would be:
v = u + at (where v is the final velocity, u is the beginning velocity, an is the acceleration, and t is the duration)
Since the bullet won't have any vertical velocity at its highest point and we're trying to calculate how long it takes to get there, we assume that the end velocity will be zero.
In the vertical direction, the initial velocity was stated as 148 m/s.
Gravitational acceleration is -9,8 m/s2 (negative due to taking the up direction as positive).
Inserting the values:
t = (v-u) / a
t = (0-148 m/s) / -9,8 m/s²
t = 15seconds
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A beaver runs at a speed of 2.0\,\dfrac{\text m}{\text s}2.0 s m 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction with 45\,\text J45J45, start text, J, end text of kinetic energy.
Answer:
22.5kg
Explanation:
Since we not told wat to find, we can as well find the mass of the beaver.
Kinetic energy formula is expressed as;
KE = 1/2mv²
m is the mass
v is the speed
Given
KE = 45Joules
v = 2.0m/s
Substitute into the formula and get the mass
45 = 1/2m(2)²
45 = 2m
m =45/2
m = 22.5kg
Hence the mass of the beaver is 22.5kg
What was the runoff from precipitation on the property for areas with vegetation and roofed or paved areas over the past four months? What percent of total precipitation ran off of the property? Include data tables in your answer. Would you expect this percentage to be the same for the properties of other students in the class? Why or why not? What factors decide the percentage of runoff?
Answer:
Higher percentage of runoff water is absorbed by the vegetation whereas 100 % of water runoff on the roofed area.
Explanation:
Higher percentage of runoff water is absorbed by the vegetation and very little amount of runoff water is received on the end of vegetative cover while on the other hand, 100 percent of precipitation water runoff on the surface of roofed or paved area because no water is absorbed by the roof due to its solid surface. The percentage of runoff depends on the factors such as rainfall intensity, slope, soil water storage capacity, and infiltration rate.
you throw a rock straight up into the air with a speed of 11.5ms how long does it take to reach its highest point
The time taken for the rock to reach its highest point is 1.2 seconds.
What is time of motion?
The time of motion of an object is the time taken for the object to travel from its initial position to the final position.
The time taken for the rock to reach its maximum or highest point is calculated as follows;
v = u - gt
where;
v is the final velocity of the rock at the highest pointu is the initial velocity of the rockg is acceleration due to gravityt is time of motionAt the maximum height, the final velocity of the object is zero.
0 = u - gt
]gt = u
t = u/g
t = (11.5 m/s) / (9.8 m/s²)
t = 1.2 seconds
Thus, we can conclude that time from the initial position of the rock to the highest position of the rock is 1.2 seconds.
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What do psychologists used to assist them in diagnosing abnormal behavior?
Ok so it usually includes the evaluation of symptom and disorder severity, patterns of symptoms over time number, frequency, and duration of episodes, and the patient's strengths and weaknesses.
Question 1 Review
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A projectile is launched horizontally from a height of 65 meters with an initial horizontal speed of 35 meters per second. What is the projectile's horizontal
speed after it has fallen 25 meters? [Neglect friction.]
Answer: 35 m/s
Explanation: Gravitational acceleration only affects the vertical component of motion meaning the horizontal component never changes. This means 35 m/s is the correct answer.
A projectile is fired horizontally at an initial horizontal speed of 35 meters per second from a height of 65 meters, after falling 25 meters, the projectile's horizontal speed is 35 m/s.
What is speed?
The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar number.
Speed is calculated using the formula s=d/t, where s is the speed in m.s⁻¹, d is the distance in m, and t is the time in s.
Variable speed is when an object travels a different distance at the same time intervals, whereas uniform speed is when an item travels the same distance at the same time intervals.
Therefore, after falling 25 meters, the projectile's horizontal speed is 35 m/s.
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An object of mass m is hanging by a string from the ceiling of an elevator. The elevator is moving up at constant speed. What is the tension in the string?.
The tension in the string, when the elevator is moving with constant speed is equal to the product of mass and gravitational force.
Tension is the pulling force carried by the flexible mediums like ropes, cables and string.
The tension in the body caused by the weight of the hanging body is the net force acting on the body.
For a body of mass (m) suspended on a string, the tension force of the string can be entered in three ways,
The tension in the string when the body is at rest or moving at a constant speed. At rest, the tension will be the product of the gravitational force times time. It can be given as, T = mg.Tension in the string when the body is moving upwards. When the body is moving upwards, both gravitational force and acceleration force are acting on it and the magnitude of the tension will be due to the sum of the two forces. This can be written as, T = m(g + a).Tension in the string as the body moves down. As the body moves down, differentiate the gravitational and acceleration forces acting on it. It can be given as, T = m(g - a)Because the object is hanging by a string from the ceiling of the elevator and the elevator is moving upward at a constant speed.
As the elevator moves at a constant speed. Thus, the magnitude of the tension in the string, T = mg.
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5. An airplane must reach a velocity of 71 m/s for takeoff. If the runway is 1.0 km long, what
must the constant acceleration be?
Answer:
final velocity 'v' = 71m/s distance 's' = 1000m intial velocity 'u' =0 therefore,using third equation of motion v^2- u^2=2*a*s 71*71=2*a*1000 a=71*71/(2*1000 a= 2.52m/s^2
Explanation:
Explain why teens are especially weak at impulse control
Answer:
One explanation may be that as a group, teenagers react more impulsively to threatening situations than do children or adults, likely because their brains have to work harder to rein in their behavior, a research team reported here yesterday at the Society for Neuroscience meeting
Calculate the momentum for the 5 kg bowling ball moving at 6 m/s.
Answer:
Given
mass (m) =5kg
velocity (v) =6m/s
momentum (p) =?
Form
p=mv
5kgx6m/s
p=30kg.m/s
momentum =30kg.m/s
Which one of the following is normally not a characteristic of a simple two-lens refracting astronomical telescope?A) The angular size of the final image is larger than that of the object.B) The final image is virtual.C) The objective forms a virtual image.D) The final image is inverted.
Option C, "The objective forms a virtual image," is normally not a characteristic of a simple two-lens refracting astronomical telescope.
A simple two-lens refracting astronomical telescope typically consists of an objective lens and an eyepiece lens. The objective lens forms a real image at its focal point, and the eyepiece lens magnifies and focuses this image for the observer.
Option A states that the angular size of the final image is larger than that of the object. This is typically true for telescopes as they are designed to magnify distant objects and make them appear larger.
Option B states that the final image is virtual. In a refracting telescope, the final image is virtual, meaning it appears to be formed behind the eyepiece. This is a characteristic of such telescopes.
Option C states that the objective forms a virtual image. However, in a simple two-lens refracting astronomical telescope, the objective lens forms a real image at its focal point. The eyepiece then magnifies this real image to create the final virtual image.
Option D states that the final image is inverted. This is generally true for refracting telescopes, as the light rays undergo refraction at both the objective and eyepiece lenses, resulting in an inverted image. Therefore, the characteristic that is normally not associated with a simple two-lens refracting astronomical telescope is option C, which states that the objective forms a virtual image.
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an object accelerated at 6.00m/s^2 starting at a velocity of 15.2m/s for 12.4 seconds. what is the objects final velocity?
the drawing shows an exaggerated view of a rifle that has been"sighted in" for a 91.4-meter target. If the muzzle speed of thebullet is v0 = 427 m/s, what are the two possible anglesθ1 and θ2 between the rifle barreland the horizontal such that the bullet will hit the target? One ofthese angles is so large that it is never used in target shooting.(HInt: the following trigonometric identity may be useful: 2 sinθ cos θ = sin 2 θ.)
The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.
Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.
It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).
Here, t is the time of flight of the bullet and g is the acceleration due to gravity.
As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.
On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.
Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.
Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.
Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.
Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.
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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.
Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.
It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).
Here, t is the time of flight of the bullet and g is the acceleration due to gravity.
As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.
On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.
Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.
Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.
Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.
Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.
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Two protons enter a region of the transverse magnetic field. What will be the ratio of the time period of revolution if the ratio of energy is 2√2 : √3 ?
Given:
ratio of energy is 2√2 : √3
Apply:
\(T=2\pi\sqrt[\frac{}{}]{\frac{mr}{qBv}}\)Where:
q = charge of proton
v= speed of proton
r= radius of circular path
T= time period of revolution
Kinetic energy (K)
K= 1/2mv^2
From both equations:
Tα1/k
K1:K2 = 2√2 : √3
T1:T2 = √3:2√2
Answer: √3:2√2
When a bug hits a windshield of a car, the force of the car on the bug equals the force of the bug on the car.
O True
O False
True. The force of the car on the bug will be equal to the force of the bug on the car.
Newton's third lawThis statement is true according to Newton's third law of motion.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction.
In this case, the action is the force of the car on the bug, and the reaction is the force of the bug on the car.
Therefore, the force of the car on the bug is equal in magnitude and opposite in direction to the force of the bug on the car.
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microscopes briefly explain
Answer:
Microscopes are just plainly a form of a high tech magnifying glass and helping us see what we can't see with our naked eye
Explanation:
the current in a 100 watt lightbulb is 0.85 a. the filament inside the bulb is 0.25 mm in diameter. a. what is the current density in the filament? b. what is the electron current in the filament?
a) current density in the filament = 0.85/ (0.0025)2
=136000 A/m2
b) electron current in the filament = 1/0.85
=1.17Current in bulb = 0.85A
Power of bulb= 100 watt
diameter of filament =0.25 mm = 0.0025m
So, current density in the filament = 0.85/ (0.0025)2 =136000 A/m2
And, electron current in the filament = 1/0.85 =1.17
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calculate how long tt takes for tennis ball to reach the ground and the tennis ball is droped height 3m and bounce book to a height of 7m
Answer:
0.59 seconds
Explanation:
To find the time it takes for a tennis ball to reach the ground and bounce back to a height of 7 meters, we need to use the formula for the time it takes an object to fall to the ground.
The formula for the time it takes an object to fall to the ground is given by:
t = sqrt(2 * d / g)
where t is the time it takes the object to fall, d is the distance the object falls, and g is the acceleration due to gravity.
In this case, we are given that the height from which the tennis ball is dropped is 3 meters, the height to which the ball bounces is 7 meters, and the acceleration due to gravity is 9.8 m/s^2. We can use these values to solve for the time it takes for the ball to reach the ground and bounce back to a height of 7 meters.
First, we need to calculate the distance the ball falls. The distance the ball falls is equal to the difference between the height from which the ball is dropped and the height to which the ball bounces:
d = H1 - H2
d = 3 - 7
d = -4
Next, we can use the formula for the time it takes an object to fall to the ground to solve for the time it takes for the ball to reach the ground and bounce back to a height of 7 meters:
t = sqrt(2 * d / g)
t = sqrt(2 * -4 / 9.8)
t = 0.59 seconds
Therefore, it takes 0.59 seconds for the tennis ball to reach the ground and bounce back to a height of 7 meters.