someone please answer!

Answer:

D. P(X=3)+P(X=4)+P(X=5)+ ...

Step-by-step explanation:

Given

\(n =60\)

\(pr = 70\%\) -- proportion of adults with pet

Required

Represent at least 3 adult with pet as a probability

At least 3 means 3 or more than.

So, the probability is represented as:

\(P(x \ge 3) = P(3) + P(4) + P(5) + ........\)

Hence;

(d) is correct

The perimeter of the given triangle with given lengths is; 78

The perimeter of a triangle is defined as the sum total of the 3 side lengths of the triangle.

Now, we are given the triangle as QRS.

We are given that;

A is the midpoint of QR

B is the midpoint of RS

C is the midpoint of SQ

Thus;

QA = RA = 10

BR = SB = 15

SQ = 28

Thus;

Perimeter of Triangle = 2(10) + 2(15) + 28 = 78

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Using a calculator, the trigonometric ratio of sin 98 is approximately 0.9848.

One of the trigonometric ratio we have in mathematics is the sine ratio. We can use calculator to find the sine of an angle without making use of tables. To do this on your calculator, enter the sine function followed by the degree of the angle you want to find its sine. You will get your answer.

Using a calculator, we can find the sine of 98 degrees as follows:

sin 98° ≈ 0.9848

Rounding this to four decimal places, we get:

sin 98° ≈ 0.9848

Therefore, sin 98° is approximately equal to 0.9848.

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The system of equations which this graph represent include the following:

A. y = x² + 2

   y = x + 4

In Geometry, the point-slope form of a straight line can be calculated by using this equation:

y - y₁ = m(x - x₁)

Where:

First, we would find the slope of this line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (6 - 3)/(2 + 1)

Slope (m) = 3/3

Slope (m) = 1.

At data point (-1, 3) and a slope of 1, an equation for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 3 = -1(x + 1)

y = -x + 4

For the quadratic equation, we have;

y = a(x - h)² + k

6 = a(-2 - 0)² + 2

4 = a4

a = 4/4

a = 1

Therefore, the required quadratic function is given by:

y = a(x - h)² + k

y = (x - 0)² + 2

y = x² + 2

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

0.58×0.90=0.522

Step-by-step explanation:

Im not really sure if it's right

The sum of the first four terms of the arithmetic sequence is 24.

From the information illustrated, the arithmetic sequence is given by 2n + 1.

The first term will be:

= 2n + 1

= 2(1) + 1 = 3

The second term will be:

= 2n + 1

= 2(2) + 1 = 5

The third term will be:

= 2n + 1

= 2(3) + 1

= 7

The fourth term will be:

= 2n + 1

= 2(4) + 1

= 9

The sum of the first four terms will be:

= 3 + 5 + 7 + 9

= 24

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An arithmetic sequence is given by 2n + 1. What is the sum of the first 4 terms of that arithmetic sequence?

Answer:

\(x = (-b + \sqrt{b^{2} - 4\, a\, c}) / (2\, a)\) or \(x = (-b - \sqrt{b^{2} - 4\, a\, c}) / (2\, a)\) assuming that \(b^{2} - 4\, a\, c \ge 0\).

Step-by-step explanation:

Let \(h\) and \(k\) be constants. Consider \(a\, (x + h)^{2} = k\). In this equation, \((x + h)^{2}\), the only term that includes \(x\), is a perfect square. If \(k \ge 0\), solving this equation is as simple as taking the square root of both sides of the equation:

\(x + h = \sqrt{k / a}\) or \(x + h = -\sqrt{k / a}\).

\(x = (-h) + \sqrt{k / a}\) or \(x = (-h) - \sqrt{k / a}\).

Assume that there are values for \(h\) and \(k\) such that  \(a\, x^{2} + b\, x + c = 0\) is equivalent to \(a\, (x + h)^{2} = k\). If \((k / a) \ge 0\), then \(x = (-h) + \sqrt{k / a}\) and \(x = (-h) - \sqrt{k / a}\) would be solutions to \(a\, x^{2} + b\, x + c = 0\!\).

Apply binomial expansion to \(a\, (x + h)^{2} = k\) and rewrite to find the values for \(h\) and \(k\):

\(a\, (x^{2} + 2\, h\, x + h^{2}) - k = 0\).

\(a\, x^{2} + 2\, a\, h\, x + (a\, h^{2} - k) = 0\).

Match the coefficients of this equation with those in \(a\, x^{2} + b\, x + c = 0\):

\(2\, a\, h = b\).

\(a\, h^{2} - k = c\).

Solve for \(h\) and \(k\) in terms of \(a\), \(b\), and \(c\):

\(h = (b / 2\, a)\).

\(\begin{aligned}k &= a\, h^{2} - c \\ &= \frac{a\, b^{2}}{4\, a^{2}} - c \\ &= \frac{b^{2}}{4\, a} - c \\ &= \frac{b^{2} - 4\, a\, c}{4\, a}\end{aligned}\).

Hence, as long as \((b^{2} - 4\, a\, c) \ge 0\), (such that \((k / a) \ge 0\),) solutions to \(a\, x^{2} + b\, x + c = 0\) would be:

\(\begin{aligned}x &= (-h) + \sqrt{\frac{k}{a}} \\ &= -\frac{b}{2\, a} + \sqrt{\frac{b^{2} - 4\, a\, c}{4\, a^{2}}} \\ &= -\frac{b}{2\, a} + \frac{\sqrt{b^{2} - 4\, a\, c}}{2\, a}\end{aligned}\), and

\(\begin{aligned}x &= (-h) - \sqrt{\frac{k}{a}} \\ &= -\frac{b}{2\, a} - \sqrt{\frac{b^{2} - 4\, a\, c}{4\, a^{2}}} \\ &= -\frac{b}{2\, a} - \frac{\sqrt{b^{2} - 4\, a\, c}}{2\, a}\end{aligned}\).

Using the it's formula, the total opportunity cost of three unit(s) of tanks is of 350 autos.

The opportunity cost formula is given by:

C = F - A.

In which:

For this problem, we have that:

Thus:

F = 1000 - 650 = 350.

The total opportunity cost of three unit(s) of tanks is of 350 autos.

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Answer:

A

Step-by-step explanation:

1 Factor out the common term ss.

\frac{s(25{s}^{2}+12)}{5s}

5s

s(25s

2

+12)

​

2 Cancel s.

\frac{25{s}^{2}+12}{5}

5

25s

2

+12

​

Using translation concepts, the cubing function after the translations is given as follows:

y = -0.56x³.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The cubing function is given by:

y = x³.

The function is vertically shrunk by applying a factor of 0.56 and reflected across the y​-axis, that is, it was multiplied by 0.56 and x -> -x, hence the translated function is:

y = 0.56(-x³) = -0.56x³.

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The final solution for the initial value problem: y = −e∫x dx√40 − ∫x2e∫x dx − ∫y2e∫x dx.

The given initial value problem is yy′+x=x2+y2 with y(3) = −√40. To solve this we make the substitution U = u' and u = y. This transforms the given equation into the linear differential equation in x, u, and u': u'+xu=x2+u2. To solve this, we can use the integrating factor method. Multiplying both sides by the integrating factor e∫x dx gives us u'e∫x dx + xue∫x dx = x2e∫x dx + u2e∫x dx. Taking the integral of both sides, we obtain ue∫x dx = ∫x2e∫x dx + ∫u2e∫x dx + c, where c is the constant of integration. Solving for u, we have u = c/e∫x dx − ∫x2e∫x dx − ∫u2e∫x dx. Using the fact that u = y, we can substitute this expression into the equation to obtain the solution in terms of x and y: y = (c/e∫x dx) − ∫x2e∫x dx − ∫y2e∫x dx. Using the initial condition y(3) = −√40, we can solve for c to get c = −e∫3 dx√40. Substituting this into the solution, we get the final solution for the initial value problem: y = −e∫x dx√40 − ∫x2e∫x dx − ∫y2e∫x dx.

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To find a particular solution of the non-homogeneous equation and the general solution of the equation, we can use the method of variation of parameters.

First, let's find the Wronskian of the homogeneous solutions y1(x) and y2(x):

W(y1, y2) = | y1 y2 |

| y1' y2' |

We have y1(x) = sin(x) / √x and y2(x) = cos(x) / √x. Differentiating these functions, we get:

y1'(x) = (cos(x) / √x - sin(x) / (2√x^3))

y2'(x) = (-sin(x) / √x - cos(x) / (2√x^3))

Substituting these values into the Wronskian:

W(y1, y2) = | sin(x) / √x cos(x) / √x |

| (cos(x) / √x - sin(x) / (2√x^3)) (-sin(x) / √x - cos(x) / (2√x^3)) |

Expanding the determinant:

W(y1, y2) = (sin(x) / √x) * (-sin(x) / √x - cos(x) / (2√x^3)) - (cos(x) / √x) * (cos(x) / √x - sin(x) / (2√x^3))

Simplifying:

W(y1, y2) = -1 / (2√x)

Now, we can find the particular solution using the variation of parameters formula:

y_p(x) = -y1(x) * ∫(y2(x) * g(x)) / W(y1, y2) dx + y2(x) * ∫(y1(x) * g(x)) / W(y1, y2) dx

Here, g(x) = 3x√xsin(x). Substituting the values:

y_p(x) = -((sin(x) / √x) * ∫((3x√xsin(x)) * (-1 / (2√x))) dx + (cos(x) / √x) * ∫((3x√xsin(x)) / (2√x)) dx

Simplifying the integrals:

y_p(x) = -(∫(-3sin^2(x)) dx) + (∫(3xcos(x)sin(x)) dx)

Integrating:

y_p(x) = 3/2 (xsin^2(x) - cos^2(x)) - 3/2 (xcos^2(x) + sin^2(x)) + C

Simplifying:

y_p(x) = 3x(sin^2(x) - cos^2(x)) + C

The general solution of the equation is given by the sum of the homogeneous solutions and the particular solution:

y(x) = C1 * (sin(x) / √x) + C2 * (cos(x) / √x) + 3x(sin^2(x) - cos^2(x)) + C

where C1, C2, and C are arbitrary constants.

The number of coupon codes that can be generated is given as follows:

247,808 coupon codes.

The Fundamental Counting Theorem states that if there are m ways to do one thing and n ways to do another, then there are m x n ways to do both.

This can be extended to more than two events, where the number of ways to do all the events is the product of the number of ways to do each individual event, according to the equation presented as follows:

\(N = n_1 \times n_2 \times \cdots \times n_n\)

The codes are composed as follows:

Thus the total number of codes is obtained as follows:

N = 22² x 8³

N = 247,808 coupon codes.

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The solution set for the inequality is x < 2. Among the given options, the value that is included in the solution set is 0.

To determine which value is included in the solution set for the inequality statement -3(x-4) > 6(x-1), we need to solve the inequality for x.

Starting with the given inequality:

-3(x - 4) > 6(x - 1)

First, distribute -3 and 6 to the terms inside the parentheses:

-3x + 12 > 6x - 6

Next, combine like terms by subtracting 6x from both sides and adding 6 to both sides:

-3x - 6x > -6 - 12

-9x > -18

To isolate x, divide both sides of the inequality by -9. Remember that when dividing by a negative number, we need to reverse the inequality sign:

x < (-18) / (-9)

x < 2

Therefore, the solution set for the inequality is x < 2. Among the given options, the value that is included in the solution set is 0.

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Answer: A

Step-by-step explanation:

Substitute the answers in the choices for x.

Answer:

14.2 ounce for $3.98 is more cheaper

Step-by-step explanation:

unit price formula; cost ÷ quantity

3.98 / 14.2 = 0.2802816901408

9.98 / 33.9 = 0.2943952802359

round answers to the nearest hundredth;

$0.28

$0.29

compare the answers

Answer:

\(\boxed {y = \frac{4}{3} + 1}\)

Step-by-step explanation:

Since you already have the slope and the y-intercept, use it to make a Slope-Intercept Form by using this formula:

\(y = mx + b\)

Slope: \(m\)

Y-intercept: \(b\)

-Substitute:

Slope: \(\frac{4}{3}\)

Y-intercept: \(1\)

\(\boxed {y = \frac{4}{3} + 1}\)

Let's denote the width of the printed material on the poster as "x" cm and the height as "y" cm.

According to the given information, the top and bottom margins are each 6 cm, and the side margins are each 8 cm. This means that the actual width of the entire poster, including the margins, is "x + 2(8)" cm, and the actual height, including the margins, is "y + 2(6)" cm.

Given that the area of the printed material on the poster is fixed at 380 square centimeters, we can set up the following equation:

Actual Area of Poster = Area of Printed Material on Poster

(x + 2(8))(y + 2(6)) = 380

(x + 16)(y + 12) = 380

To find the dimensions of the poster with the smallest area, we need to minimize the product (x + 16)(y + 12).

Since the given area of the printed material on the poster is fixed at 380 square centimeters, the actual area of the entire poster, including the margins, will be minimized when (x + 16)(y + 12) is minimized.

To minimize the product (x + 16)(y + 12), we need to minimize both x + 16 and y + 12, as they are both positive quantities.

Since x and y represent the width and height of the printed material on the poster, respectively, the smallest possible values for x + 16 and y + 12 would be 0, which means x = -16 and y = -12. However, since width and height cannot be negative, we need to find the next best option.

The smallest possible values for x + 16 and y + 12 that are greater than or equal to 0 would be when x = 0 and y = 0. This means that the width of the printed material on the poster should be 0 cm and the height should be 0 cm, which would make the dimensions of the poster with the smallest area:

Width = 0 cm

Height = 0 cm

However, please note that this would mean there is no printed material on the poster, as the width and height are both 0. If you want to have a non-zero width and height for the printed material on the poster, you would need to adjust the given area of the printed material on the poster accordingly.

3 answer :-

if the diameter=14cm

then radius =7cm

height=18.2cm

we know that

C. S. A=2πrh

=2×22/7×7×18.2

=36.4×22

the metal used for making can =796.4

hope this help you I apologize if the above answer is wrong

I am sorry but I know only one answer

Answer:

88 degrees

Step-by-step explanation:

Since x and z have the same angel their degrees is the same

Answer:

Step-by-step explanation:

x*y*z = 107

x y ≠ 0, z = 107/(x y)

x = -1, y = -107, z = 1

x = -107, y = 1, z = -1

x = -107, y = -1, z = 1

a) Y=38.6594-5.4198x; b) 39.1% explained variation; c) Y=44.9379-5.9522x1-1.2758x2-2.0102x3; d) 49.9% explained variation; e) Y=45.2478-6.1081x1-0.9945x2-2.5692x3+0.9963x4; f) 53.1% .

a) The estimated regression equation for predicting fuel efficiency for highway driving is Y = 38.6594 - 5.4198x, where x represents the engine's displacement in liters.

b) The estimated regression equation explains 39.1% of the variation in the sample values of HwyMPG.

c) The estimated regression equation that includes the dummy variables ClassMidsize and ClassLarge is Y = 44.9379 - 5.9522x1 - 1.2758x2 - 2.0102x3, where x1 represents engine's displacement, x2 represents variable ClassMidsize, and x3 represents variable ClassLarge.

d) The estimated regression equation with the added dummy variables explains 49.9% of the variation in the sample values of HwyMPG.

e) The estimated regression equation that includes the dummy variable FuelPremium is Y = 45.2478 - 6.1081x1 - 0.9945x2 - 2.5692x3 + 0.9963x4, where x1 represents engine's displacement, x2 represents variable ClassMidsize, x3 represents variable ClassLarge, and x4 represents variable FuelPremium.

f) The estimated regression equation with all three dummy variables explains 53.1% of the variation in the sample values of HwyMPG.

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Answer: 6:1

Step-by-step explanation:

The Halloween conical hat, with given height, circular base and brim

extension has the following calculated parameters;

Part a. The slant height is 18.2 inches

Part b. The volume of the cone is \(37\frac{1}{2} \cdot \pi\) in.³

Part c. The area of the brim, A = 36·π in.²

Part d. The area of the brim is found by subtracting the area of the base of the cone from the area covered by the perimeter of the brim

Reasons:

Known parameters;

Height of the conical portion, h = 18 inches

Base circumference, C = 5·π inches

Part a. Slant height of the conical portion; Required

Solution:

The circumference of a circle, C = 2·π·r

Therefore;

\(r = \dfrac{C}{2 \cdot \pi}\)

Which gives;

\(r = \dfrac{5 \cdot \pi}{2 \cdot \pi} = \dfrac{5}{2} = 2.5\)

Radius, r = 2.5 inches

According to Pythagoras's theorem, we have; s² = r² + h²

Where;

s = The slant height of the cone

s² = 2.5² + 18² = 330.25

s = √(330.25) ≈ 18.2

Part b. The measure in cubic inches of candy that exactly fills the conical portion of the hat is the volume of the cone.

\(Volume \ of \ a \ cone = \dfrac{1}{3} \cdot \pi \cdot r^2 \cdot h\)

Therefore;

\(V = \dfrac{1}{3} \times \pi \times 2.5^2 \times 18 = 37\frac{1}{2} \cdot \pi\)

Part c. The extension of the brim from the base of the cone = 4 inches

The radius of the brim, R = Radius of the base of the cone + 4 inches

∴ R = 2.5 inches + 4 inches = 6.5 inches

Area of the brim, A = Area of the 6.5 inch circle - Area of the circular base of the cone

∴ A = π × 6.5² - π × 2.5² = 36·π

Part d. The procedure for solving the question in part c, is described as follows;

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Answer and Step-by-step explanation:

To find out how many more yards of red fabric Reuben used, we need to subtract the amount of yellow fabric from the amount of red fabric. Since the two fractions have different denominators, we need to find a common denominator before subtracting them. The least common multiple of 8 and 4 is 8, so we can rewrite both fractions with a denominator of 8:

7/8 - 1/4 = 7/8 - (1/4) * (2/2) = 7/8 - 2/8 = (7 - 2)/8 = 5/8

So, Reuben used 5/8 yards more red fabric than yellow fabric.

a)  Z-score for Patrisse test grade is 0.7288

b) z-score for Makayla test grade is -0.7441

c) Patrisse did better.

A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values.

Z-score for Patrisse test grade.

X= 81.4, \(\mu\) = 72.8, \(\sigma\) = 11.8

Z= x-  \(\mu\) /  \(\sigma\)

Z= 81.4 - 72.8/ 11.8

Z= 0.7288

Now, z-score for Makayla test grade.

X= 60.6, \(\mu\) = 67, \(\sigma\) = 8.6

Z= x-  \(\mu\) /  \(\sigma\)

Z= 60.6 - 67/ 8.6

Z= -0.7441

Hence, Patrisse did better as she had better z- score.

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The Expression x^2 - 6x + 9 when x = 2 + i   is -2i

To evaluate the expression x^2 - 6x + 9 when x = 2 + i, we substitute the value of x into the expression:

(2 + i)^2 - 6(2 + i) + 9

Simplifying the first term, we get:

(2 + i)^2 = 2^2 + 2(2)(i) + i^2 = 4 + 4i + i^2

Since i^2 = -1, we can substitute that in and simplify further:

(2 + i)^2 = 4 + 4i - 1 = 3 + 4i

Now we substitute this into the original expression:

(2 + i)^2 - 6(2 + i) + 9 = (3 + 4i) - 6(2 + i) + 9

Simplifying further, we get:

= 3 + 4i - 12 - 6i + 9

= 0 - 2i

= -2i

Therefore, the value of x^2 - 6x + 9 when x = 2 + i is -2i.

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Therefore, the total mass of all bags of beads is 19.27 grams

Given masses of three bags of beads as

Mass of beads in bag1 = 10.3 grams

Mass of beads in bag2 = 5.23 grams

Mass of beads in bag3 = 3.74 grams

We have to calculate the total mass of all the beads as below

The total mass of all bags of beads = mass of bag1 + mass of bag2 + mass of bag3

                                                           = 10.3 + 5.23 + 3.74

                                                           = 19.27 grams

Therefore, the total mass of all bags of beads is 19.27 grams

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\((\sin^2 \theta + \cos^2 \theta)(\sin \theta + \cos \theta)\\\\=1 \cdot(\sin \theta + \cos \theta)\\\\=\sin \theta + \cos \theta\)

Answer:

D: cos^3(O)

Step-by-step explanation:

The  quotient of 302 ÷ (9.1 x \(10^4)\) in scientific notation is approximately 3.31868131868 x \(10^1\)

Dividing 302 by 9.1 gives:

302 ÷ 9.1 ≈ 33.1868131868

Now, to express this result in scientific notation, we need to move the decimal point to the appropriate position to create a number between 1 and 10. In this case, we move the decimal point two places to the left:

33.1868131868 ≈ 3.31868131868 x\(10^1\)

Therefore, the quotient of 302 ÷ (9.1 x \(10^4\)) in scientific notation is approximately 3.31868131868 x\(10^1\)

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