How do you label a bar graph of work compared with power?
Answer:
You must label the horizontal axis with the names of the airlines and the vertical axis with the number of flights. The title must clearly state what data the bar chart is showing. With larger numbers, your scale may not go up by one.
Answer:
You must label the horizontal axis with the names of the airlines and the vertical axis with the number of flights. The title must clearly state what data the bar chart is showing. With larger numbers, your scale may not go up by one.
Explanation:
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B6. [9 Marks] 30⁰ 20140X20 DE Ofe OTO A stainless-steel orthodontic wire is applied to a tooth as shown in the diagram below. The wire has an unstretched length of 3.1 cm and a diameter of 0.22 mm. If the wire is stretched by 0.10 mm during the procedure, find the magnitude and direction of the force on the tooth. Disregard the width of the tooth and assume Young's modulus for stainless-steel is 18 × 10¹0 Nm-².
The magnitude of the force on the tooth is approximately 0.022 N.
To find the magnitude and direction of the force on the tooth, we can use Hooke's Law, which states that the force exerted on an object is directly proportional to the change in length of a material when it is stretched or compressed.
First, we need to calculate the strain (ε) of the stainless-steel wire.
Strain is defined as the change in length divided by the original length:
ε = ΔL / L₀
Given that the change in length (ΔL) is 0.10 mm \((0.10 \times 10^{-3} m)\) and the unstretched length (L₀) is 3.1 cm \((3.1 \times 10^{-2} m)\), we can calculate the strain:
\(\epsilon=(0.10 \times 10^{-3} m)/(3.1 \times 10^{-2} m)=0.003225\)
Next, we can use Young's modulus (E) to calculate the stress (σ) in the wire.
Stress is defined as the force per unit area:
σ = E * ε
Given that Young's modulus (E) for stainless-steel is 18 × 10¹⁰ N/m², we can calculate the stress:
σ = (18 × 10¹⁰ N/m²) * 0.003225 = 5.805 × 10⁸ N/m²
Now, we can find the force (F) on the tooth by multiplying the stress by the cross-sectional area (A) of the wire:
F = σ * A
The cross-sectional area (A) can be calculated using the formula for the area of a circle:
A = π * (d/2)²
Given that the diameter (d) of the wire is 0.22 mm\((0.22 \times 10^{-3} m)\), we can calculate the cross-sectional area:
\(A = \pi * (0.22 \times 10^-3 m / 2)^{2} = 3.802 \times 10^{-8} m^2\)
Finally, we can calculate the force:
\(F = (5.805 \times 10^{8} N/m^{2}) * (3.802 \times 10^-8 m^{2}) \approx 2.206 \times 10^{-2} N\)
Therefore, the magnitude of the force on the tooth is approximately 0.022 N.
Since the wire is stretched, the force is pulling the tooth in the direction opposite to the stretching.
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If 20J of heat is extracted from a system change in energy of the system will be
when 82.5 calories of heat are given to a metallic rod of mass 150g its temperature raises from 20 degree celcius to 25 degree Celsius. what is the specific heat of the metal.
A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.
What is specific heat?It is the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).
A metallic rod of mass 150 g (m) absorbs 82.5 cal of heat (Q) and its temperature raises from 20 °C to 25 °C. We can calculate the specific heat (c) of the metal using the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 82.5 cal / 150 g × (25 °C - 20 °C) = 0.11 cal/g.°C
A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.
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Which of the following represents an example of thermal energy?
O a
Saxophone
Ob
Oven
с
Powerlines
Od
Windmill
Answer:
The answer of this question is windmill
Which option is part of designing a set of experimental procedures?
A. Submitting conclusions to the peer-review process
B. Developing a hypothesis
C. Beginning to take measurements
D. Determining how data will be gathered
Answer:d for apex
Explanation:
In an experiment similar to the one you performed in Week 3, an experimenter measures the count rate of a radioactive element 100 times, calculates the mean and standard deviation of the data, and organizes the data into four bins:
Interval Number of Occurrences
n < n 15
< n < n 50 - 15
n < n < + 38
n > n + 12
The experimenter expects a Gaussian distribution. (For simplicity, assume 68 % of the counts fall within one standard deviation of the mean rather than the more exact value of 68.27 \%.) What is x?
Answer:
The answer is "1.5625".
Explanation:
Please find the complete question with its solution file in the attachment.
Fern life begins as _____.
a spore
a sperm
an egg
If a baseball travels a distance of 4 meters in 5 seconds, what is its average speed
Answer:
speed=d/t.
s=4/5=0.8m/s.
A hummingbird averages a speed of about 45 km/hour (Cool facts: They visit up to 1000 flowers per day, and reach maximum speed, while diving, up to 160 km/hour!). Ruby-throated hummingbirds take a non-stop trip across Gulf of Mexico in which they fly for 18 hours straight! How far is the trip across the Gulf of Mexico at their average speed?
answer choices
810 km
2.5 km
3.6 km
360 km
It would take 18 hours to travel 18 x 45 = 810 km across the Gulf of Mexico.
What is average speed?Average speed is the measure of an object's overall rate of motion in a given direction. It is calculated by dividing the total distance traveled by the total time taken. Average speed can be calculated over a certain period of time, or it can be calculated over the entire duration of a journey.
At an average speed of 45 km/hour, a hummingbird would travel 45 km in one hour.
Therefore, it would take 18 hours to travel 18 x 45 = 810 km across the Gulf of Mexico.
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A roller coaster designer wants their coaster to go from 0 m/s to 30 m/s in 6.6 seconds. What is the length of the track needed to accommodate this?
The length of the track needed would be 78.8 meters.
Designing a roller coasterUsing the kinematic equation:
v_f = v_i + a*t
where v_f is the final velocity, v_i is the initial velocity (which is 0 m/s in this case), a is the acceleration, and t is the time interval.
We are given that v_f = 30 m/s and t = 6.6 s. We need to solve for a, which will allow us to calculate the length of the track needed to accommodate the acceleration.
v_f = v_i + a*t
30 m/s = 0 m/s + a*6.6 s
a = 30 m/s / 6.6 s
a = 4.545 m/\(s^2\)
Now, we can use the kinematic equation:
d = v_it + 1/2a*\(t^2\)
where d is the distance (length of track) needed to accelerate from 0 m/s to 30 m/s.
We plug in the values we know:
d = 0 m/s * 6.6 s + 1/2 * 4.545 m/s^2 * \((6.6 s)^2\)
d = 78.8 meters
Therefore, the length of the track needed to accommodate the acceleration from 0 m/s to 30 m/s in 6.6 seconds is 78.8 meters.
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What is the ostrich’s average acceleration from 9.0 to 18s
Answer:
Explanation:
10.00 5
The earth rotates on its axis with a period of 24 hours. What is the frequency in Hertz?
Answer:
The answer is 0.042 Hz (rounded)
or 0.0417 Hz
Explanation:
Hope it helps
Answer:
The answer is 0.041Hz
Explanation:
The answer is 0.041Hz
I guess
AcellusVector E is 0.111 m long in a90.0.º direction. Vector Fis0.234 m long in a300° direction.Find the magnitude of theirvector sum.magnitude (m)
The magnitude of the vector sum = 0.149 m
The direction = 321.8 degrees
Explanation:Find the x and y components of vector E
\(\begin{gathered} E_x=\text{ 0.111}\cos 90 \\ E_x=\text{ }0 \\ E_y=\text{ 0.111sin90} \\ E_y=\text{ }0.111 \\ E=E_xi+E_yj \\ E\text{ = 0.111j} \end{gathered}\)Find the x and y components of vector F
\(\begin{gathered} F_x=\text{ 0.234}\cos 300 \\ F_x=\text{ }0.117 \\ F_y=\text{ 0.234}\sin 300 \\ F_y=\text{ }-0.203 \\ F=F_xi+F_yj \\ F\text{ = 0.117i-0.203j} \end{gathered}\)The vector sum of E and F is:
\(\begin{gathered} E+F\text{ = 0.111j+(0.117i-0.203j)} \\ E+F=0.117i-0.092j \end{gathered}\)The magnitude of the vector sum is given as:
\(\begin{gathered} |E+F|=\sqrt[]{0.117^2+(-0.092)^2} \\ |E+F|\text{ = }\sqrt[]{0.022153} \\ |E+F|=\text{ }0.149 \end{gathered}\)The magnitude of the vector sum = 0.149 m
The direction is given as:
\(\begin{gathered} \theta\text{ = }\tan ^{-1}(\frac{-0.092}{0.117}) \\ \theta\text{ = }\tan ^{-1}(-0.786) \\ \theta\text{ = }-38.2^0 \\ \theta\text{ = -38.2+360} \\ \theta\text{ = }321.8^0 \end{gathered}\)A 2.8 kg block slides along a frictionless surface at 1.1 m/s . A second block, sliding at a faster 4.8 m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.3 m/s.
What was the mass of the second block?
Conservation of momentum is a major law of physics which states that the momentum of a system is constant if no external forces are acting on the system. It is embodied in Newton’s First Law or The Law of Inertia.the mass of the second block is 1.1Kg.
principle of momentum conservation
M1u1 plus M2u2 equals M1v1 and M2V2.
As all collisions were elastic in nature and no energy loss through friction, heat, etc. was taken into account, theoretic calculations alone cannot guarantee that there was a complete transfer of energy.
Consider the scenario where a football with mass M2 is lying on the ground and a bowling ball with mass M1 is hurled at the football at a velocity of
The formula is: (2.8 kg * 1.1 m/s) + (m2 * 4.8 m/s) = (2.3 kg + m2). 2.3 m/s
The formula is 2.8 J + (4.8 m/s m2) = 4.8 J + (2.3 m/s m2).
4.8 m/s m2 = 2.8 J plus (2.3 m/s m2)
4.8 m2 = 2.8 + 2.3 m2
2.3 m2 on each side of the equation
2.5 m = 2.8 m = 2.8 / 2.5\sm = 1.1kg
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Nova, who’s mass is 75.0 kg, stays out skiing for too long and her body temperature drops by 3 K. What is the amount of heat lost from Nova’s body? (specific heat of the human body is 3470 J/kg K)
The amount of heat loss from the body is given as 780750 J
How to solve for the heat lossThe amount of heat lost by Nova's body can be calculated using the following formula:
Q = m * c * ΔT
where Q is the amount of heat lost, m is the mass of Nova's body, c is the specific heat of the human body, and ΔT is the change in temperature (in kelvins).
Substituting the given values, we get:
Q = 75.0 kg * 3470 J/(kg K) * 3 K
= 780750 J while skiing
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What is the frequency of a wave with a wavelength of 36 m and a speed of 12 m/s?
3Hz
O .33HZ
O 432HZ
O 312HZ
Answer:
312hz
Explanation:
thanks me later
03.03 LC)
The refraction of a sound wave occurs when the sound wave
stops at a boundary between media
bounces off the boundary between media
bends as it passes through the boundary between media
changes frequency after it passes through the boundary between media
The refraction of a sound wave occurs when the sound wave bends as it passes through the boundary between media. Refraction occurs when there is a difference in the speed of sound waves in two different media.
The bending of the sound wave occurs because the speed of sound changes as it passes from one medium to another. The amount of bending depends on the angle of incidence and the difference in speed between the two media. If the speed of sound is higher in the second medium than the first, then the wave bends away from the normal. If the speed of sound is lower in the second medium than the first, then the wave bends towards the normal. If the sound wave is incident perpendicular to the boundary, then there is no bending of the wave and no refraction occurs. Refraction of sound waves is an important phenomenon in our daily lives. It is the reason why we can hear sound around corners or why we can hear someone talking in another room even if the door is closed. The refraction of sound waves is also used in medical imaging, such as in ultrasound, where the sound waves are refracted as they pass through different tissues in the body.For more such questions on sound wave, click on:
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c = speed of light = 3.00 × 108 m/s
A gamma ray has a very high frequency of about 1019 s−1. What is the wavelength of the gamma ray?
A.
3.00 × 10−11 m
B.
3.00 × 1027 m
C.
3.33 × 1010 m
D.
3.33 × 10−12 m
URGENT!!!!!!!!!!
Answer:
The correct answer is option A: 3.00 × 10^(-11) m.
Explanation:
To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:
wavelength = speed of light / frequency
Given:
Speed of light (c) = 3.00 × 10^8 m/s
Frequency (f) = 10^19 s^(-1)
Substituting the values into the equation:
wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))
To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:
wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s
To divide by a fraction, we multiply by its reciprocal:
wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)
Applying the properties of exponents, we can add the exponents when multiplying with the same base:
wavelength = 3.00 × 10^(-11) m
Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.
true/false. Article 130, Work Involving Electrical Hazards, by definition, covers work involving four hazards caused by either proximity or equipment failure.
This statement is False, Article 130, Work Involving Electrical Hazards, by definition, covers work involving four hazards caused by either proximity or equipment failure.
Electrical hazards refer to the potential risks associated with the use of electricity, which can cause injury or even death. These hazards can arise from a variety of sources, including electrical systems, appliances, tools, and wiring.
Electrical hazards can include electrical shock, burns, and electrocution. Electrical shock occurs when a person comes into contact with an electrical current and can cause muscle contractions, respiratory failure, and cardiac arrest. Burns can result from direct contact with an electrical current or from an arc flash, which is a sudden release of electrical energy. Electrocution is a severe form of electrical shock that can result in death. It is essential to receive proper training and education on electrical safety and to always be aware of potential electrical hazards in the environment.
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A 4.0-kg ball with a velocity of in the collides head-on elastically with a stationary 2.0-kg ball. What are the velocities of the balls after the collision
Complete question:
4.0 kg ball with a velocity of 4 m/s in the +x-direction collides head-on elastically with a stationary 2.0-kg ball. What are the velocities of the balls after the collision.
Answer:
The final velocity of the first is 1.33 m/s
The final velocity of the second ball is 5.33 m/s
Explanation:
Given;
mass of the first ball, m₁ = 4.0 kg
mass of the second ball, m₂ = 2.0 kg
initial velocity of the first ball, u₁ = 4 m/s
initial velocity of the second ball, u₂ = 0
let the final velocity of the first ball after collision = v₁
also, let the final velocity of the second ball after collision = v₂
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
4(4) + 0 = 4v₁ + 2v₂
16 = 4v₁ + 2v₂
8 = 2v₁ + v₂ -------- equation (1)
Apply one-directional velocity;
u₁ + v₁ = u₂ + v₂
4 + v₁ = 0 + v₂
4 + v₁ = v₂ --------- equation (2)
Substitute in equation (2) into equation (1)
8 = 2v₁ + v₂
8 = 2v₁ + (4 + v₁)
8 = 2v₁ + 4 + v₁
8 - 4 = 2v₁ + v₁
4 = 3v₁
v₁ = 4 / 3
v₁ = 1.33 m/s
Then, v₂ = 4 + v₁
v₂ = 4 + 1.33
v₂ = 5.33 m/s
An unhappy 0.300-kg rodent, moving on the end of a spring with force constant k = 2.50 N/m, is acted on by a damping force F = -bv. (A) If the constant b has the value 0.900 kg/s, what is the frequency of oscillation of the rodent? (B) For what value of the constant b will the motion be critically damped?
If the rodent oscillates at a frequency of 0.950 kg/s, the motion will be critically dampened at a value of 1.732 kg/s for constant b. to highlight how different from angular frequency ordinary frequency is.
The frequency of an event is its repetitions per unit of time. When contrasting it with spatial frequency, it is also sometimes referred to as temporal frequency.
given damping force: mass = 0.3 kg, k = 2.5 N/m Fx=-bvx+b = 0.950 kg/s
This oscillator is underdamped since the equation of motion for it is mx" + bx' + kx = 0, which results in b2 - 4mk = 0. W = square root(k/m - b2/4m2) yields the angular frequency of oscillation.
For critically damped motion, b2 = 4mk b = 1.732 kg/s, where w = 2.41379 rad/s.
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Fill in the blank with the correct response.
Light striking a mirror at a 45° angle will be reflected at a
3. Who among the composers was born to musical parents and died on September 26, 1945 in New York City? a) Bela Bartok b) Sergei Prokofieff c) Igor Stravinsky d) George Gershwin
Answer:
A) Bela Bartok
Explanation:
Béla Bartók died at age 64 in a hospital in New York City from complications of leukemia (specifically, of secondary polycythemia) on September 26, 1945. His funeral was attended by only ten people. Among them were his wife Ditta, their son Péter, and his pianist friend György Sándor.
Which water on earth is the largest,second to the largest,3rd to the largest,fourth to the largest and 5th to the largest?
Answer:
Explanation:
There are a total of 5 differen classification for the types of bodies of water that exist on Earth. These 5 would be the following: Oceans, seas, lakes, rivers, and canals. Oceans are the biggest bodies of water on Earth. If we ranked them by their size the ranking would be the following...
Pacific Ocean - being 155,556,651 sq km. in size
Atlantic Ocean - being 76,761,938 sq km. in size
Indian Ocean - being 68,555,923 sq km. in size
Antarctic / Southern Ocean - being 20,327,001 sq km. in size
Arctic Ocean - being 14,055,930 sq km. in size
How are magnetic fields like vectors?
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
A 15 year old boy requires eyeglasses with lenses of 2 diopters power in order to read a book at 25 cm. Five years later he finds that while wearing the same glasses, he must hold a book 40 cm from his eyes. What power of lenses does he require at 20 years in order to read a book at 25 cm?
At 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.
How to solve for the power of lenses1/f1 = 1/v - 1/u1
1/f1 = 1/∞ - 1/0.25 (converting 25 cm to meters)
1/f1 = 0 - 4
1/f1 = -4
f1 = -1/4
f1 = -0.25 meters
The initial lens power (P1) is the reciprocal of the focal length:
P1 = 1/f1
P1 = 1/-0.25
P1 = -4 diopters
Now let's calculate the final focal length (f2) using the final distance (v2) of 40 cm:
1/f2 = 1/v2 - 1/u1
1/f2 = 1/0.40 - 1/0.25
1/f2 = 2.5 - 4
1/f2 = -1.5
f2 = -1/1.5
f2 = -0.67 meters
The final lens power (P2) is the reciprocal of the focal length:
P2 = 1/f2
P2 = 1/-0.67
P2 ≈ -1.49 diopters
Therefore, at 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.
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Match each Sun-Earth-Moon alignment diagram to the corresponding eclipse image, as seen from Earth.
Answer:
Explanation:
Here ya go
I've also corrected the moon position relative to the penumbra. It's much more representative to the actual geometry but still not very accurate because of the vast distances between moon, earth and sun. Could not do much with the quarter moon with realism because of scales.
The girl in the diagram is accelerating down the hill. What is the girl's acceleration?
m = 50kg
f net = 150 N right
(Hint: Use the formula a=\frac{F}{m}a= m F.)
A. a = 3 m/s2 A. is correct.
B. a = 5 m/s2
C. a = 150 m/s2
D. a = 6 m/s2
Answer:
150÷50=3 and the answer is letter AStudents in an acting class watch instructors demonstrate stage combat techniques. These students must be able to execute the behavior (i.e., the stage combat techniques) they are trying to learn. Which part of Bandura's observational learning process does this represent?
Initiation is the part of Bandura's observational learning process which is
represented.
Bandura's observational learning processThis is the process in which Bandura describes as how people learn
something by observing the behavior of other people and applying it. The
third part of this observational learning is referred to as Initiation.
This involves the learner being able to execute or initiate the learned
behavior and it depicts students being able to execute the stage combat
techniques.
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