Answer:
Chemical change
Explanation:
Because a new substance is formed.
In reaction 1, if we had used 4 grams of NaOH instead of 2 grams, would the heat gained by the solution [#6] have been larger, smaller or the same? Explain Briefly!
If we had used 4 grams of NaOH instead of 2 grams, the heat gained by the solution would have been higher.
What is the enthalpy?The term enthalpy has to do with the heat that could be emitted or evolved in a given reaction. We know that in a neutralization reaction, there is an evolution of heat and as such the reaction vessel would feel warm at the end of the reaction.
Also, the enthalpy would depend on the amount of the limiting reactant. In this case, the limiting reactant would be the sodium hydroxide and as such the enthalpy would affected by a change in the amount of the sodium hydroxide.
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A shiny piece of metal has a volume of 315 cm3 and a mass of 851 g. what is the density of the metal?
The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition. The density of aluminum in g/cm³ is 2.70 g/cm³.
A substance's density is a measurement of how heavy it is in relation to its size. If an object is placed in water, it will float if it is less dense than the water, and it will sink if it is more dense. The density of a material is a distinguishing quality that is independent of the substance's volume.
The volume of the metal =315 cm³
Then density is:
Density = mass /volume
Density of metal = 851 g / 315cm³
D = 2.70 g / cm³
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Calculate the amount of heat needed to convert 230.0g of ice at -10C to water at 0C
Answer:
It would take approximately 81.65 kJ (or 81,650 J) of heat to convert 230.0g of ice at -10C to water at 0C.
Explanation:
To calculate the amount of heat needed to convert ice at -10°C to water at 0°C, we need to consider two steps:
1. Heating the ice from -10°C to 0°C (heat required to raise the temperature of ice)
2. Melting the ice into water at 0°C (heat required to change the state of ice)
Let's first calculate the heat required for step 1:
Q1 = m × c × ΔT
where Q1 is the heat required, m is the mass of the ice, c is the specific heat capacity of ice, and ΔT is the change in temperature.
The specific heat capacity of ice is 2.09 J/g°C, and ΔT is (0°C - (-10°C)) = 10°C.
So, Q1 = 230.0 g × 2.09 J/g°C × 10°C = 4827 J
Now, let's calculate the heat required for step 2:
Q2 = m × Lf
where Q2 is the heat required, m is the mass of the ice, and Lf is the latent heat of fusion of ice.
The latent heat of fusion of ice is 334 J/g.
So, Q2 = 230.0 g × 334 J/g = 76820 J
Therefore, the total amount of heat needed to convert 230.0g of ice at -10C to water at 0C is:
Qtotal = Q1 + Q2 = 4827 J + 76820 J = 81647 J
Therefore, it would take approximately 81.65 kJ (or 81,650 J) of heat to convert 230.0g of ice at -10C to water at 0C.
how does the addition of thermal energy relate to the molecules inna substance
Answer:
Its will particles move faster and its temperature will rises more.
Explanation:
Calculate the ph when 25.0 ml of 0.150 m hno₃ is mixed with 40.0 ml of 0.250 m lioh.
The pH of the solution is 7.00. First, we need to determine the number of moles of HNO₃ and LiOH:
moles HNO₃ = (0.150 mol/L) x (0.0250 L) = 0.00375 mol
moles LiOH = (0.250 mol/L) x (0.0400 L) = 0.0100 mol
Next, we need to determine which reactant is limiting. From the balanced chemical equation:
HNO₃ + LiOH → LiNO₃ + H₂O
We can see that the stoichiometric ratio of HNO₃ to LiOH is 1:1. Therefore, HNO₃ is the limiting reactant.
Since HNO₃ is a strong acid and LiOH is a strong base, they will react completely to form water and LiNO₃. The moles of HNO₃ that reacted will be equal to the moles of H₃O⁺ formed.
moles H₃O⁺ = 0.00375 mol
To determine the concentration of H₃O⁺ in solution, we need to determine the total volume of the solution:
Vtotal = 25.0 mL + 40.0 mL = 65.0 mL = 0.0650 L
Now we can use the equation for the dissociation of water:
Kw = [H₃O⁺][OH⁻]
Assuming that the initial concentration of OH⁻ is negligible, we can simplify this to:
Kw = [H₃O⁺]²
Taking the negative logarithm of both sides:
-pKw = 2pH
where pKw = 14.00 at 25°C. Substituting in the values we have determined:
-14.00 = 2pH - > pH = -14.00/2 = -7.00
Therefore, the pH of the solution is 7.00.
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Where and how does most heat loss occur in a thermos bottle? _________
Answer:
neck
Explanation:
through the neck and opening of the thermos, where there is no vacuum.. hence heat is easily transmitted resulting into heat loss
In pulmonary ventilation, the movement of gases is between the ______ and the ______.
In pulmonary ventilation, the movement of gases is between the atmosphere and the alveoli of the lungs.
It is the process of inhalation and exhalation of air from the lungs. This happens because of the difference of pressure due to contraction and relaxation.
Inspiration occurs intrapleural cavity enlarges due to diaphragm's contraction which pulls it down. intrapleural cavity also occurs when ribs are elevated.
In pulmonary ventilation, three different pressures are included; Atmospheric pressure, Interalveolar pressure, Intrapleural pressure.
The pressure outside the body is known as atmospheric pressure. Pressure inside the alveoli of the lungs is known Interalveolar pressure. The pressure in the pleural cavity is known as Intrapleural pressure.
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Perform Calculatlons Using Ksp Question For the following equilibrium; HgBr2(s) ~= Hg?+(aq) + 2Br"(aq) If Ksp 6.2 x 10-20, what is the molar solubility of mercury (II) bromide (HgBrz)? Report your answer in scientific notation with the correct number of significant figures Provide your answer below:'
The molar solubility of mercury (II) bromide (HgBr2) is 7.00 × 10^-7 M. This is the long answer to the problem.
To perform calculations using Ksp for the given equilibrium HgBr2(s) ↔ Hg2+(aq) + 2Br-(aq) and find the molar solubility of mercury (II) bromide (HgBr2) we have to use the solubility product expression.Ksp for HgBr2 is 6.2 × 10^-20Ksp = [Hg2+][Br-]^2 Since the initial concentration of HgBr2 is given as s, and after dissociation, the concentration of Hg2+ becomes s, while the concentration of Br- becomes 2s.[Hg2+] = s M and [Br-] = 2s MThus,Ksp = [Hg2+][Br-]^2= s(2s)^2= 4s^3= 6.2 × 10^-20Molar solubility of HgBr2 is given as s, therefore;s = (6.2 × 10^-20/4)1/3s = 7.00 × 10^-7 M
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State the law of moment of force.
Explanation:
when in equilibrium condition the total sum of anti clockwise moment is equal to the sum of clock wise moment
Answer:
Newton's First Law of Motion states that in order for the motion of an object to change, a force must act upon it. This is a concept generally called inertia.
Newton's Second Law of Motion defines the relationship between acceleration, force, and mass.
Newton's Third Law of Motion states that any time a force acts from one object to another, there is an equal force acting back on the original object. If you pull on a rope, therefore, the rope is pulling back on you as well.
Explanation:
Differentiate between worldwide conservation and national conservation policy.
suppose that an atom has (i) 4, (ii) 5, electrons in different orbitals. what are the possible values of the total spin quantum number s? what is the multiplicity in each case?
The spin quantum number will be 2 and 2.5 and multiplicity in each case will be 5 and 6.
The angular momentum of such an electron is described by its spin quantum number (ms). An electron carries orbital angular momentum in addition to angular momentum around its axis of rotation. The Spin Quantum Number (s) really does have a magnitude (1/2) and a direction (+ or -) since angular momentum would be a vector.
(i) If an atom has 4 electrons then it will have total
Total spin quantum number = 1/2+1/2+1/2+1/2 = 4/2=2
Multiplicity = 2S+1= 2×2+1=5
(ii) If an atom has 5 electrons then it will have
Total spin quantum number = 1/2+1/2+1/2+1/2+1/2 = 5/2 = 2.5
Multiplicity = 2S+1= 2×2.5+1=6
Therefore, the spin quantum number will be 2 and 2.5
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Write the Formulas for these ionic compounds:
1) Tin(IV) oxide
2) Aluminum oxide
3) Silver sulfide
4) Copper (II) sulfate
5) Potassium carbonate
Answer:
1. Tin(IV) oxideTin(IV) oxide, also known as stannic oxide, is the inorganic compound with the formula SnO₂. The mineral form of SnO₂ is called cassiterite, and this is the main ore of tin. With many other names, this oxide of tin is an important material in tin chemistry. It is a colourless, diamagnetic, amphoteric solid.
Formula: SnO₂
Molar mass: 150.71 g/mol
Melting point: 1,630 °C
Density: 6.95 g/cm³
2. Aluminum oxideAluminium oxide is a chemical compound of aluminium and oxygen with the chemical formula Al₂O₃. It is the most commonly occurring of several aluminium oxides, and specifically identified as aluminium(III) oxide.
Formula: Al₂O₃
Molar mass: 101.96 g/mol
Melting point: 2,072 °C
Density: 3.95 g/cm³
Boiling point: 2,977 °C
ChemSpider ID: 14086
ChemSpider ID: 26988
3. Silver sulfideSilver sulfide is an inorganic compound with the formula Ag ₂S. A dense black solid, it is the only sulfide of silver. It is useful as a photosensitizer in photography. It constitutes the tarnish that forms over time on silverware and other silver objects.
Formula: Ag2S
Molar mass: 247.8 g/mol
Density: 7.23 g/cm³
ChemSpider ID: 145878
4. Copper (II) sulfateCopper(II) sulfate, also known as copper sulphate, are the inorganic compounds with the chemical formula CuSO₄ₓ, where x can range from 0 to 5. The pentahydrate is the most common form. Older names for this compound include blue vitriol, bluestone, vitriol of copper, and Roman vitriol.
Formula: CuSO4
IUPAC ID: Copper(II) sulfate
Molar mass: 159.609 g/mol
Density: 3.6 g/cm³
Melting point: 110 °C
Soluble in: Water
5. Potassium carbonatePotassium carbonate is the inorganic compound with the formula K₂CO₃. It is a white salt, which is soluble in water. It is deliquescent, often appearing as a damp or wet solid. Potassium carbonate is mainly used in the production of soap and glass.
Formula: K2CO3
Molar mass: 138.205 g/mol
IUPAC ID: Potassium carbonate
Density: 2.43 g/cm³
Melting point: 891 °C
Soluble in: Water
Explanation:
Hope it is helpful....
How do we know what parts make up the atom?
Answer:nucleus protons nuetrons electrons
Explanation:
The smallest partical into which an element can be divied and still be the smallest element
.( A basic unit o f matter)
Answer:
Nucleus, electrons, and protons
Explanation:
Multiple experiments and results accumulated over the years. Dalton is credited through his ray cathode tube experiments, and Rutherford's Gold Foil experiment led to the discovery of the positively charged nucleus and protons. His student Chadwick continued his studies and discovered the neutron.
3c reaction time =138.5 sec reation rate=
Answer:
Compute the reaction rate to the nearest whole number using the formula below,
mass of tablet/volume of water
Reaction Rate = mas
reaction time
3°C Reaction time = 138.5 sec
Reaction rate = mg/l/sec
24°C Reaction time = 34,2 sec
Reaction rate = mg/L/sec
40°C Reaction time = 26.3 sec
Reaction rate = mg/L/sec
65°C Reaction time = 14.2 sec
Reaction rate = mg/L/sec
Explanation:
I hope my answer help
Answer:
#1 is 36 (138.5 seconds)
#2 is 146 (34.2 seconds)
#3 is 190 (26.3 seconds)
#4 352 (14.2 seconds)
#5 is 145 (34.5 seconds)
#6 is 173 (28.9 seconds)
#7 is 216 (23.1 seconds)
Explanation:
Edge, we may have different orders.
rank the type of light each space telescope primarily uses, from shortest wavelength to longest. items (3 items) (drag and drop into the appropriate area) chandra hubble spitzer items in order shortest wavelength 1 2 3 longest wavelength
Type of light each space telescope primarily uses is Shortest wavelength: Chandra, Hubble, Spitzer and Longest wavelength: Spitzer, Hubble, Chandra.
The Chandra X-ray Observatory primarily uses X-rays, which have very short wavelengths in the electromagnetic spectrum.
The Hubble Space Telescope primarily uses visible light, which has a slightly longer wavelength than X-rays. The Spitzer Space Telescope primarily uses infrared light, which has the longest wavelengths of the three types of light.
Therefore, the order of telescopes from shortest to longest wavelength is Chandra, Hubble, and Spitzer. Conversely, the order of telescopes from longest to shortest wavelength is Spitzer, Hubble, and Chandra.
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a graduated cylinder contains 32.0 ml of water. what is the new water level after 33.7 g of silver metal is submerged in the water?
Answer: 35.2mL
Explanation:
Take the mass of this silver chunk, and divide it by the density of silver to get the volume of silver. Add it to the volume of the water to get the total volume.
33.7g /(10.5g/mL) = about 3.2mL
32.0mL + 3.2mL = 35.2mL
WILL MARK AS BRAINLIEST IF CORRECT
Answer:
I don't know what is the actual answer
A solution consists of 42. 00 g of CoSO4 dissolves in 200. 0 mL of water. The molar mass of Cu is 63. 55 g/mol, the molar mass of S is 32. 07 g/mol, and the molar mass of O is 16. 00 g/mol. What is the molarity of the solution?
Answer:
1.3155M
Explanation:
molar mass of CuSO4
=63.55+32.07+16(4)
=159.62g/mol
n=mass/molar mass
n=42.00/159.62
n=0.2631mol
volume=200mL=0.2L
molarity=mole (n)/volume (v)
molarity=0.2631mol/0.2L
molarity=1.3155M
which pollutant would you suggest the government try to limit in order to slow down the breakdown of the marble on the taj mahal
Answer:
SO2
Explanation:
SO2 causes acid rain which is leading to dissolving of the marble on the Taj Mahal
SO2 reacts with water to come down as sulfuric acid during acid rains
A mixture of oxygen( O2), dinitrogen monoxide (N2O), and argon (Ar) has a total pressure of 0.98 atm. What is the partial pressure of N2O, if the partial pressure of O2 is 0.48 atm and the partial pressure of Ar is 0.15 atm?
Answer: The partial pressure of \(N_{2}O\) is 0.35 atm.
Explanation:
Given: Total pressure = 0.98 atm
Partial pressure of \(O_{2}\) = 0.48 atm
Partial pressure of Ar = 0.15 atm
Partial pressure of \(N_{2}O\) = ?
Total pressure is the sum of partial pressure of each component present in a mixture of gases.
Hence, partial pressure of \(N_{2}O\) is calculated as follows.
Total pressure = \(P_{N_{2}O} + P_{O_{2}} + P_{Ar}\)
Substitute the values into above formula as follows.
\(Total pressure = P_{N_{2}O} + P_{O_{2}} + P_{Ar}\\0.98 atm = P_{N_{2}O} + 0.48 atm + 0.15 atm\\P_{N_{2}O} = 0.35 atm\)
Thus, we can conclude that the partial pressure of \(N_{2}O\) is 0.35 atm.
Newton's Laws (8.6 C):Question 3
An object at rest will stay at rest unless acted upon by an outside force.
Which activity is an example of this law?
Select one:
A.A football is kicked off a tee.
B.A floating stick is carried over a waterfall.
C.A bicycle travels faster as it
goes downhill.
D.A baseball player slides into second base.
Answer:A.
Explanation:
In this case, the object receives the action. Which lines up with newton's law " an object will stay at rest unless acted upon by an outside force." The football is being kicked, which means a direct outside force acted upon this.
Newton's first law states that An object at rest will stay at rest unless acted upon by an outside force. The example D a floating stick carried over the water fall depicts the first law of motion.
What are laws of motion ?Newton proposed three laws to describe the motion of an object. The first law states that, an object at rest will stay at rest unless acted upon by an outside force. The tendency to stay in its current state is called inertia of the object.
Newton's second law states that, the force acting on an object is the product of its mass and acceleration. Third law of motion states that, for every action, there is an equal and opposite reaction.
Among the given options, the example, of the baseball player sliding onto the second base is an illustrating first law of motion. The baseball player slide to avoid over running and to protect themselves.
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Succinic acid dissociates as follows: H₂C4H4O4+H₂O HC4H4O4 + H3O+ Ka1 = 6.2 × 10-5 HC4H4O4+H₂0 C4H4O42- + H3O+ Ka2 = 2.3 x 10-6 Calculate Kb1 and Kb2 for the following reactions (3 points): C4H4042 + H2O HC4H4O4 + OH- Kb1 = ? HC4H4O4+H₂O H2C4H4O4 + OH- Kb2 = ?
Kb1 = 1.61 × 10^-10 and Kb2 = 4.35 × 10^-9. The basicity constant, or Kb, is a measure of the strength of a base in a particular chemical reaction. The products of a reaction of a weak base and water with the corresponding acid determine the base constant.
For example, for a given acid and base, Kb1 and Kb2 are the basicity constants for the first and second base dissociations, respectively, of the base. The formulas and charges of the conjugate acid and base, as well as the acid dissociation constants, Ka1 and Ka2, are needed to calculate Kb1 and Kb2.
The following reactions are balanced chemical reactions that represent the dissociation of succinic acid:
Reaction 1: H2C4H4O4(aq) + H2O(l) ⇌ HC4H4O4(aq) + H3O+(aq) Ka1 = 6.2 × 10−5
Reaction 2: HC4H4O4(aq) + H2O(l) ⇌ C4H4O42-(aq) + H3O+(aq) Ka2 = 2.3 × 10−6
The values of Ka1 and Ka2 can be used to calculate Kb1 and Kb2, respectively, using the following equation:
Ka1 × Kb1 = Kw
where Kw is the ion-product constant for water, which is 1.0 × 10−14 at 25°C.
Kb1 can be calculated as follows:
Kw = Ka1 × Kb1
Kb1 = Kw / Ka1
Kw = 1.0 × 10^-14
Ka1 = 6.2 × 10^-5
Kb1 = Kw / Ka1
Kb1 = 1.0 × 10^-14 / 6.2 × 10^-5
Kb1 = 1.61 × 10^-10
Kb2 can be calculated using the same method:
Kw = Ka2 × Kb2
Kb2 = Kw / Ka2
Kw = 1.0 × 10^-14
Ka2 = 2.3 × 10^-6
Kb2 = Kw / Ka2
Kb2 = 1.0 × 10^-14 / 2.3 × 10^-6
Kb2 = 4.35 × 10^-9
Therefore, Kb1 = 1.61 × 10^-10 and Kb2 = 4.35 × 10^-9.
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what is the formula for sulfuric acid
Answer:
H₂SO₄
Explanation:
Hope this helps!
I NEED HELP ASAP
How do your experiments relate to the geologic processes that form soil?
Answer:
acting together to break down rocks and minerals to form soil.
Explanation:
There are a whole range of weathering processes at work near the surface of the soil, acting together to break down rocks and minerals to form soil. ... As rocks and sediments are eroded away, so more of the solid rock beneath becomes vulnerable in turn to weathering and breakdown.
how does the body and brain react when u are developing feelings for someobody?
Water circulates through Earth's water cycle by changing its _____.
A. state
B. acidity
C. turbidity
D. composition
PLsss I need answers T-T
P O R F A V O R
4. Expresa las siguientes magnitudes en unidades del Sistema
Internacional. (1 punto)
a. 45 m3
b. 1250 cm3
c. 63 días
d. 97 cm/min2
e. 927 g∙cm/min2
f. 97 km/h2
g. 2500 g/cm2
h. 36 km/h
Answer:
a. 45×10³ kg
b. 1.25 kg
c. 5443200 s
d. 2.69×10⁻⁴ m/s²
e. 2.57×10⁻⁶N
f. 7.48×10⁻³ m /s²
g. 2.45 Pa
h. 10 m/s
Explanation:
The SI units are: kg, m, s, N, K, A, Pa, J and cd
a. 1 g is the mass for 1 cm³. We convert the m³ to cm³
45 m³. 1×10⁶ cm³ / 1 m³ = 45×10⁶ cm³
By the way, 45×10⁶ cm³ = 45×10⁶ g
We convert the g to kg → 45×10⁶ g . 1 kg / 1000 g = 45×10³ kg
b. As 1 g = 1 cm³, we convert the cm³ to g and then, the g to kg
1250 cm³ = 1250 g → 1250 g . 1kg / 1000 g = 1.25 kg
c. 1 day has 24 hours; 1 hour has 60 minutes; 1 minute has 60 seconds
1 hour has 3600 s. Then 24 h . 3600 s / 1 h = 86400 s
86400 s/d. 63 d = 5443200 s
d. 1 min² = 3600 s²
97 cm / 3600 s² = 0.0269 cm/s² / 100 = 2.69×10⁻⁴ m/s²
e. 927 g.cm / min² / 3600 s² = 0.2575 g.cm/s² → dyn
We need to convert dyn to N
1 dyn = 10⁻⁵N → 0.2575 dyn . 10⁻⁵N / 1dyn = 2.57×10⁻⁶N
f. 1 m/s² = 12960 km/h²
12960 km/h² . 1 m/s² / 97 km/h² = 7.48×10⁻³ m /s²
g. 2500 g/cm² . 1kg / 1000 g = 2.5 kg/cm²
1 Pa = 1.02kg/cm²
2.5 kg/cm² . 1 Pa / 1.02 kg/cm² = 2.45 Pa
h. 1 h = 3600 s
36 km / 3600 s = 0.01 km /s → 0.01 km . 1000 m / 1 km = 10
= 10 m/s
In the reaction, HCO3−+H2O→OH−+H2CO3, the conjugate acid - base pair is:A H2CO3,HCO3−B H2O,H3O+C OH−,H3O+D H2CO3,CO32−
In the given chemical equation, HCO3−+H2O→OH−+H2CO3, the acid-base pair is formed between HCO3− and H2CO3.
HCO3− is the base and H2CO3 is the conjugate acid. When HCO3− accepts a proton (H+) from H2O, it forms its conjugate acid, H2CO3.
Similarly, when H2CO3 donates a proton (H+) to OH−, it forms its conjugate base, HCO3−.
A conjugate acid-base pair is formed when an acid donates a proton to a base and forms its conjugate base, and the base accepts a proton and forms its conjugate acid.
In this reaction, HCO3− accepts a proton from H2O and forms its conjugate acid, H2CO3, and H2CO3 donates a proton to OH− and forms its conjugate base, HCO3−. Thus, the conjugate acid-base pair in this reaction is H2CO3 and HCO3−.
To summarize, the conjugate acid-base pair in the given reaction is H2CO3 and HCO3−, where H2CO3 is the conjugate acid and HCO3− is the conjugate base.
Understanding the concept of conjugate acid-base pairs is important in many areas of chemistry, including acid-base equilibria, buffer solutions, and chemical reactions.
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The observed brightness of a star depends on which factors?
a
the star's shape, distance, and size
b
the star's brightness, size, and distance
c
the star's temperature, size, and, composition
d
the star's composition, shape, and temperature
Answer:
b..............
Explanation:
......
hi can someone pls help me it’s important i’m studying for my finals
Answer:
i think the answer is D)
but u should ask the another person too:)