Sort the following forms of radiation into the appropriate area: onizing and nonionizing lonizing Nonionizing Gamma rays Microwaves Radio frequencies Infrared radiation from an electric heater or remote control X-Rays

The correct statement that explains the observation using Newton's laws is objects at rest tend to remain in their current state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion. Here option A is correct.

According to Newton's first law of motion, an object will continue moving at a constant velocity in a straight line unless acted upon by an external force. In this case, when the cannonball is shot horizontally from the cannon, it initially possesses a forward velocity due to the force applied by the cannon. However, once the cannonball is in motion, the only forces acting on it are gravity and friction.

Gravity acts vertically downward, causing the cannonball to accelerate downward. Friction acts horizontally in the opposite direction to the motion of the cannonball. As the cannonball moves forward, friction opposes its motion and gradually slows it down.

Since there is no force continuously propelling the cannonball forward, and the forces of friction and gravity act on it, the cannonball eventually comes to a stop and falls to the ground. Hence option A is correct.

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In order to explain the photoelectric effect, Albert Einstein applied quantization to the energy of photons. He proposed that light is made up of discrete packets of energy called photons, and each photon carries a specific amount of energy.

The photoelectric effect refers to the phenomenon where electrons are emitted from a material when it is exposed to light of a sufficiently high frequency. Albert Einstein provided a groundbreaking explanation for this effect by applying the concept of quantization to the energy of photons. According to Einstein's explanation, light consists of discrete packets of energy called photons. Each photon carries a specific amount of energy directly proportional to the frequency of the light wave. This meant that light energy could not be continuously varied but instead existed in discrete units.

This application of quantization to the energy of photons explained several key observations of the photoelectric effect that classical wave theory couldn't account for. It provided a satisfactory explanation for the immediate emission of electrons upon light exposure, the dependence of the emission on the frequency of light rather than its intensity, and the existence of a threshold frequency below which no emission occurs.

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Answer:

 α= 1.3 10-5 ºC⁻¹

Explanation:

La dilatación termica de los cuerpos esta dada por la relación  

      ΔL = L₀ α ( T -T₀)

en este caso nos piden el coeficiente de dilatación térmica

     α =DL/L₀ DT

calculemos

      α = (  100,13 -100)/[100 (100 – 0)]

       α = 1,3 10-5 ºC⁻¹

Traduction

The thermal expansion of bodies is given by the relationship

       ΔL = L₀ α (T -T₀)

in this case they ask us for the coefficient of thermal expansion

        α = ΔL / L₀ ΔT

    let's calculate

        α = (100,13 -100) / [100 (100 - 0)]

        α= 1.3 10-5 ºC⁻¹

The speed of the block immediately after the bullet becomes embedded in the block is (m1v1)/(m1 + m2).

Assuming that the collision between the bullet and block is elastic, we can use the law of conservation of momentum to find the speed of the block immediately after the bullet becomes embedded in the block. The law of conservation of momentum states that the total momentum of a system of objects remains constant if no external forces act on the system. In this case, the system consists of the bullet and the block.

Before the collision, the momentum of the bullet is given by:

P1 = m1v1

where m1 is the mass of the bullet and v1 is its velocity.

The momentum of the block before the collision is zero since it is initially at rest.

After the collision, the bullet becomes embedded in the block and they move together with a common velocity, say v2. By conservation of momentum:

P1 = P2

where P2 is the total momentum of the bullet and the block after the collision.

The total momentum after the collision is given by:

P2 = (m1 + m2) v2

where m2 is the mass of the block.

Setting P1 = P2, we get:

m1v1 = (m1 + m2) v2

Solving for v2, we get:

v2 = (m1v1)/(m1 + m2)

Therefore, the speed of the block immediately after the bullet becomes embedded in the block is (m1v1)/(m1 + m2).

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Answer:

geocentric- The geocentric model is an Earth-centered model that was first summarized by Ptolemy. In the model the Earth is motionless at the center of Universe.

The ship travels with a velocity of 15 km/h within 2 hours. The distance travelled is the velocity times the time taken that is 30 km to the north.

Velocity is a physical quantity measuring the distance travelled by an object per unit time. Velocity is the rate of speed and it is a vector quantity having both magnitude and direction. The unit of velocity can be m/s, km/h, ft/s etc.

Velocity is the ratio of the change in distance to the change in time. The change in distance is sometimes called the displacement.

then velocity  = displacement / time

Given that velocity = 15 km/h

time taken = 2 hours

then displacement = velocity × time

= 15 × 2 = 30 Km

Therefore, the displacement of the ship is 30 km to the north.

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The direct answer to your question is that electric engines can be more than 80% efficient and even up to 90% efficient while combustion engines are 30 to 45% efficient.

Electric motors make vehicles substantially more efficient than internal combustion engines. Electric motors convert over 85 percent of electrical energy into mechanical energy, or motion, compared to less than 30 to 40 percent for a gas combustion engine.

These efficiencies are even lower after considering losses as heat in the drivetrain, which is the collection of components that translate the power created in an electric motor or combustion engine.

• Motor efficiency: 85..90%

• Battery load efficiency: 80..90 %

• Battery discharge efficiency: 80..90 %

• Power generation efficiency at power: 30..40 %

• Transfer efficiency from the powerplant to the reloading station: 90..95 %

• Energy conversion efficiency AC to DC: 90..95 %

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To determine the fraction of the hose opening that was blocked, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant before and after blocking a fraction of the hose opening.

The mass flow rate of water is given by the equation:

Mass flow rate = density * cross-sectional area * velocity

Assuming the density of water remains constant, we can write:

Mass flow rate before blocking = Mass flow rate after blocking

The cross-sectional area of the hose opening is proportional to the square of its diameter. Let's assume that the fraction of the hose opening blocked is represented by 'x'.

Since the velocity of water before blocking is 'v' and after blocking is '4v', and the cross-sectional area is reduced by a fraction of 'x^2', we can write:

density * (1 - x^2) * v = density * 4^2 * v

Simplifying the equation, we get:

1 - x^2 = 16

x^2 = 1 - 16

x^2 = -15

Since we cannot have a negative value for 'x^2', it implies that the given scenario is not physically possible. The fraction of the hose opening blocked cannot be determined using the provided information

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Answer:

i think it is 20.5

Explanation:

Answer:

may be upside down alphabet :"T"

Explanation:

Answer: D

Explanation:

Answer:

B - 0.18N/cm

Explanation:

The spring formula:

      Force =  - (spring constant) · (distance stretched or squashed)

          6 N  =  - (spring constant) · (33 cm)

                  =  - (0.33 m) · (spring constant)

         Spring constant  =   - (6 N) / (0.33 m)

                                     =    - 18.18 N/meter .

The negative signs mean that the spring always wants to go in the

opposite direction from where you forced it, and return to its relaxed

length.  If you stretch it, it tries to get shorter, and if you compress it,

it tries to get longer.

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Answer:2.83 times greater than the average speed of oxygen molecules at the same temperature.

Explanation:The ratio of the average speed of helium molecules to the average speed of oxygen molecules can be calculated using the root mean square (rms) velocity formula:

ratio of rms velocity = sqrt(M2/M1)

where M1 and M2 are the molar masses of the gases.

In this case, the ratio of the molar masses is M2/M1 = 32/4 = 8.

So, the ratio of the rms velocity of helium to oxygen is:

ratio of rms velocity = sqrt(8) = 2.83

Therefore, the average speed of helium molecules is about 2.83 times greater than the average speed of oxygen molecules at the same temperature.

Answer:

It looks like its moving north.

Explanation:

Answer:

6.25 N

Explanation:

F = ma

F = 2.5 × 2.5

F = 6.25 Newtons

Newton's third rule of motion states that whenever air is forced backwards out of a balloon (out the end with the opening), there must be an equal and opposite reaction force pushing the balloon forward (out the end opposite the opening).

A balloon tends to fly around the room randomly when you just let it go on its own, making steering nearly impossible. On the other hand, you can use the balloon's energy to move the automobile forward if you attach it to a vehicle.

What is the ballon powered car model experiment?

Steps to Take

1. Poke a hole through the centre of the pop bottle lid with the hammer and nail.

2. Attach the ballon to the straw using masking tape. By blowing into the straw, check the balloon for any holes.

3. Connect the tongue depressor to the two short straw pieces. These will serve as the wheels' axles.

4. Using the skewers, fasten the four wheels. This could be a little difficult! To prevent the bottle cap from rubbing on the side of the tongue depressor, you might need to adjust it.

5. Use masking tape to secure the balloon and straw to the car's top.In order to have enough space to blow into the straw, make sure it is over the edge.

6. Blow into the balloon, grip the straw, then release. Observe how the automobile moves off! ​

Students build a car in this exercise that is propelled by the elastic energy of a balloon. In contrast to family automobile, which transforms chemical energy into kinetic energy, this vehicle transforms potential energy into kinetic energy.

When inflated with air, balloons, which are elastic, can store potential energy. The potential energy, sometimes referred to as kinetic energy, is transformed into the energy of motion when the air is released. When the car is moving forward, you can perceive this energy.

When you release the automobile, it will have more kinetic energy the more potential energy it has saved.

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Answer:

connect two 9 ohms resistance in series now it becomes 18 ohm

Answer:

SF4 + 3H2O → H2SO3 + 4HF

Explanation:

I found it

The electric and magnetic fields associated with a plane wave in a lossless material medium (ε=ε0εr, µ=µ0µr) are governed by Maxwell's equations.

In such a medium, the electric field E and magnetic field H oscillate in phase and are mutually perpendicular to each other and the direction of wave propagation.

The material properties, relative permittivity (εr) and relative permeability (µr), determine the speed of the wave and its impedance. The speed of the wave (v) can be found using the equation v=1/√(ε0εrµ0µr).

The wave impedance (Z) is given by Z=√(µ0µr/ε0εr). Plane waves in lossless materials do not experience any attenuation, ensuring that the energy carried by the wave remains constant as it propagates through the medium.

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Answer:

I think its C

Explanation:

The hill must be at least 30 meters high for the riders to experience weightlessness at the top of the loop.

Let h be the height of the hill, and let v be the velocity of the roller coaster at the top of the loop. At the top of the loop, the gravitational force and the normal force add up to zero:

mg + N = 0

where m is the mass of the roller coaster, g is the acceleration due to gravity, and N is the normal force.

The centripetal force required to keep the roller coaster moving in a circle of radius R is, Fc = mv²/R, where Fc is the centripetal force.

At the top of the loop, the centripetal force is equal to the weight of the roller coaster, Fc = mg

Setting these two expressions for Fc equal to each other,

mv²/R = mg

Solving for v,

v = sqrt(gR)

Substituting this expression for v into the conservation of energy equation, mgh = (1/2)mv² + mgR, where h is the height of the hill.

Substituting the expression for v,

mgh = (1/2)mgR + mgR

Solving for h,

h = 3R/2

Substituting the given value of R = 20 m, h = 30 m.

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Answer:

Explanation:

a) work=Force times distance. given force is 888N and distance travelled is 22M

work= 888 x 22 = 19536J or 1.954x10^5J

b) work = 1111 x 22= 24442J or 2.444x10^5J

c) putting on a larger engine means that there are gonna be more force applied to the go cart. therefore the cart will travel the same distance faster

a. The amount of work done by the go cart engine is 19,536 Nm.

b. The amount of work done when a bigger engine is used is 24,442 Nm.

c. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

Given the following data:

a. To determine the amount of work done by the go cart engine:

Mathematically, the work done by an object is given by the formula;

\(Work\;done = Force \times distance\)

Substituting the given parameters into the formula, we have;

\(Work\;done = 888 \times 22\)

Work done = 19,536 Nm.

b. To determine the amount of work done when a bigger engine is used:

\(Work\;done = Force \times distance\)

\(Work\;done = 1111 \times 22\)

Work done = 24,442 Nm.

c. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

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Answer:

Cracking of an egg is a physical change since the egg and the stuff inside does not change but the shape or appearance of the shell changes.

Explanation:

Hope it helps

The change in momentum of the bowling ball of mass 8.11 kg is 159.152 kgm/s.

The change in the momentum is equal to the product of the mass and the change in the velocity.

To calculate the change in momentum of the bowling ball, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the change in momentum of the ball is 159.152 kgm/s.

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Complete question: A force of 203 N is exerted on 8.11 -kg bowling ball over time span of 0.784 seconds. Calculate the change in momentum of the bowling ball

We can find Kirkwood gaps at average distances of approximately 2.53 AU and 2.17 AU from the Sun, where the orbital periods of asteroids are three-eighths and one-third of Jupiter's orbital period, respectively.

To find the average distances (in AU) from the Sun where you would expect to find Kirkwood gaps with orbital periods of asteroids that are three-eighths and one-third of Jupiter's orbital period, you can use Kepler's Third Law of Planetary Motion. The law states that the ratio of the squares of the periods of any two planets is equal to the ratio of the cubes of the semi-major axes of their orbits.


1. Determine the orbital periods for the asteroids:
  Jupiter's orbital period is approximately 11.86 Earth years.
  - For the first asteroid: 3/8 * 11.86 ≈ 4.45 years
  - For the second asteroid: 1/3 * 11.86 ≈ 3.95 years

2. Use Kepler's Third Law:
  (P₁/P₂)² = (a₁/a₂)³

3. For the first asteroid (three-eighths of Jupiter's orbital period):
  (4.45/11.86)² = (a₁/5.20)³
  Solve for a₁ (Jupiter's semi-major axis is approximately 5.20 AU):
  a₁ ≈ 2.53 AU

4. For the second asteroid (one-third of Jupiter's orbital period):
  (3.95/11.86)² = (a₂/5.20)³
  Solve for a₂:
  a₂ ≈ 2.17 AU

In summary, you would expect to find Kirkwood gaps at average distances of approximately 2.53 AU and 2.17 AU from the Sun, where the orbital periods of asteroids are three-eighths and one-third of Jupiter's orbital period, respectively.

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Therefore, the total charge on the sphere is 0.040716 C or 40.716 mC (milli-coulombs).

The given information regarding the sphere is:

Radius of the sphere, r = 0.06 m, Charge per unit area on the surface of the sphere, σ = 0.9 mc/m² (milli-coulomb/meter²)

The total charge on a sphere can be calculated by multiplying the charge density (charge per unit area) with the total surface area of the sphere.

The total surface area of the sphere is given by:

A = 4πr².

On substituting the given values of r and σ, we get:

A = 4 × π × (0.06)² = 0.04524 m²

Charge on the sphere,

q = σ × A = 0.9 × 0.04524

q= 0.040716 C (coulombs).

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The ball which is thrown with a speed of 21 m/s, travels a distance of 129.99 m in the horizontal direction.

Therefore, the vertical component of the ball's motion will be determined by the force of gravity and the initial vertical speed of the balloon.

We can use the following kinematic equation to determine how long it takes for the ball to fall to the ground:

h = ut + 1/2 * g * t^2

where h is the initial height of the ball (equal to the height of the balloon which is 210 m).

u is the initial velocity of the ball in the vertical direction which is 3.5 m/s.

g is the acceleration due to gravity (approximately 9.8 m/s^2),

and t is the time it takes for the ball to fall to the ground.

Plugging in the values we know, we get:

210 = 3.5 * t + 1/2 * 9.8 * t^2

4.9 t^2 + 3.5 t - 210 = 0

t = 6.19 seconds

Now we can use the time it takes for the ball to fall to the ground to determine how far it travels horizontally, given its initial horizontal velocity of 21 m/s. We can use the following equation:

d = v * t

where d is the horizontal distance traveled by the ball, v is its initial horizontal velocity, and t is the time it takes to fall to the ground (which we just calculated).

Plugging in the values we know, we get:

d = 21 * 6.19

d ≈ 129.99 meters

Therefore, the girl will find the ball approximately at a distance of 129.99 meters away from her when she lands after throwing the ball horizontally.

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Answer:

Inertia.

Explanation:

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

For example, the inertia of an object such as a shopping cart is greatly dependent or influenced by its mass; the higher quantity of matter in a shopping cart, the greater will be its tendency to continuously remain at rest.