Answer: The first one
Step-by-step explanation: first you have to subtract 5 from both sides and then you have -6n < 6 . Then you have to divide both sides by -6 then you get n < -1.
Consider the below minimization LP problem we solve in lab class.
minz=
s.t t;
3×1+3×2−3×3≤6
−3×1+6×2+3×3≤4
x1,x2,x3≥0
3×1+6×2−12×3
3×1+3×2+6×3≤27
a) (10%) Write the LP in the standard form and solve it by using the simplex method (we solve the min problems directly in the lab class. Now, you should use the other method for minimization problem in which the objective function for the min problem is multiplied by −1 and the problem is solved as a maximization problem with the objective function -z. b) (10%) Solve the LP using Excel Solver, show your Excel spreadsheet and report your solutions.
(a) The given minimization LP problem is converted to the standard form by multiplying the objective function by -1, and then solved using the simplex method as a maximization problem with the objective function -z.
(b) The LP problem is also solved using Excel Solver, where the LP model is set up in a spreadsheet, constraints and objective function are defined, and Solver is used to find the optimal solution.
(a) To solve the minimization LP problem using the simplex method, we convert it to the standard form by multiplying the objective function by -1. The problem becomes:
maximize -z = -(3x1 + 6x2 - 12x3)
subject to:
3x1 + 3x2 - 3x3 ≤ 6
-3x1 + 6x2 + 3x3 ≤ 4
x1, x2, x3 ≥ 0
We solve this problem as a maximization problem with the objective function -z. Applying the simplex method, we perform the iterations to find the optimal solution. The detailed calculations are not provided here due to the text-based format limitations.
(b) To solve the LP problem using Excel Solver, we set up the LP model in an Excel spreadsheet. We define the constraints and objective function, specifying the range of decision variables and their coefficients. Then, we utilize the Solver add-in in Excel to find the optimal solution.
The Solver tool allows us to input the LP model, specify the objective function and constraints, and set the optimization parameters. After running the Solver, it finds the optimal values for the decision variables (x1, x2, x3) that minimize the objective function.
The Excel spreadsheet containing the LP model and Solver setup, including the decision variables, objective function, constraints, and Solver settings, is not available in the text-based format. However, by following the steps of setting up the LP model and utilizing Solver, the optimal solution for the LP problem can be obtained.
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high-low or least squares regression analysis should only be done it a(n) ____ plot depicts linear cost behavior.
High-low or least squares regression analysis should only be done if a scatter plot depicts linear cost behavior.
A scatter plot is a graphical representation of data points, with the x-axis representing the independent variable (such as the level of production) and the y-axis representing the dependent variable (such as the cost). Linear cost behavior means that the relationship between the independent and dependent variables can be approximated by a straight line. In other words, as the independent variable increases or decreases, the dependent variable changes proportionally.
To determine if a scatter plot depicts linear cost behavior, you need to visually examine the data points. If the points appear to align closely along a straight line, it indicates a linear relationship. However, if the points are scattered and do not follow a clear pattern, it suggests non-linear cost behavior.
High-low or least squares regression analysis are statistical techniques used to estimate and quantify the linear relationship between variables. These methods help determine the equation of the line that best fits the data points and can be used to predict future values. Therefore, performing these analyses is only meaningful when the scatter plot indicates linear cost behavior.
In summary, high-low or least squares regression analysis should only be done if a scatter plot depicts linear cost behavior.
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Find the median of the data. 43, 37, 49, 51, 56, 40, 44, 50, 36
Answer:
Median = 44
Step-by-step explanation:
Arrange the data in ascending order:
36, 37, 40, 43, 44, 49, 50 , 51, 56.
Choose the number in the middle.
Median = 44
Procter and Gamble (PG) paid an annual dividend of $2.95 in 2018. You expect PG to increase its dividends by 7.4% per year for the next five years (through 2023), and thereafter by 2.6% per year. If the appropriate equity cost of capital for Procter and Gamble is 8.6% per year, use the dividend-discount model to estimate its value per share at the end of 2018.
The dividend in 2018 was $2.95, and it is expected to grow at a rate of 7.4% for the next five years and 2.6% thereafter. With an equity cost of capital of 8.6%, the value per share at the end of 2018 can be calculated.
To calculate the value per share at the end of 2018, we need to discount the expected future dividends using the dividend-discount model. The model assumes that the value of a stock is equal to the present value of all its expected future dividends.
First, we need to calculate the dividends for each year from 2019 to 2023. We start with the dividend in 2018, which was $2.95. We then increase it by 7.4% each year for the next five years:
Dividend in 2019 = $2.95 * (1 + 7.4%) = $3.17
Dividend in 2020 = $3.17 * (1 + 7.4%) = $3.40
Dividend in 2021 = $3.40 * (1 + 7.4%) = $3.65
Dividend in 2022 = $3.65 * (1 + 7.4%) = $3.92
Dividend in 2023 = $3.92 * (1 + 7.4%) = $4.22
After 2023, the dividend is expected to grow at a rate of 2.6% per year. To find the value per share at the end of 2018, we discount the future dividends to their present value using the equity cost of capital of 8.6%.
The present value of the dividends can be calculated as follows:
PV = (D1 / (1 + r)) + (D2 / (1 + r)^2) + ... + (Dn / (1 + r)^n)
where PV is the present value, D1 to Dn are the dividends for each year, r is the equity cost of capital, and n is the number of years.
In this case, n = 5 because we are discounting the dividends for the next five years. Let's calculate the present value:
PV = ($3.17 / (1 + 8.6%)) + ($3.40 / (1 + 8.6%)^2) + ($3.65 / (1 + 8.6%)^3) + ($3.92 / (1 + 8.6%)^4) + ($4.22 / (1 + 8.6%)^5)
PV = $3.17 / 1.086 + $3.40 / 1.086^2 + $3.65 / 1.086^3 + $3.92 / 1.086^4 + $4.22 / 1.086^5
PV ≈ $2.91 + $3.07 + $3.24 + $3.41 + $3.59
PV ≈ $16.22
Therefore, the estimated value per share of Procter and Gamble at the end of 2018 using the dividend-discount model is approximately $16.22.
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The dividend in 2018 was $2.95, and it is expected to grow at a rate of 7.4% for the next five years and 2.6% thereafter. With an equity cost of capital of 8.6%, the value per share at the end of 2018 can be calculated.
To calculate the value per share at the end of 2018, we need to discount the expected future dividends using the dividend-discount model.
The model assumes that the value of a stock is equal to the present value of all its expected future dividends. First, we need to calculate the dividends for each year from 2019 to 2023. We start with the dividend in 2018, which was $2.95. We then increase it by 7.4% each year for the next five years:
Dividend in 2019 = $2.95 * (1 + 7.4%) = $3.17
Dividend in 2020 = $3.17 * (1 + 7.4%) = $3.40
Dividend in 2021 = $3.40 * (1 + 7.4%) = $3.65
Dividend in 2022 = $3.65 * (1 + 7.4%) = $3.92
Dividend in 2023 = $3.92 * (1 + 7.4%) = $4.22
After 2023, the dividend is expected to grow at a rate of 2.6% per year. To find the value per share at the end of 2018, we discount the future dividends to their present value using the equity cost of capital of 8.6%.
The present value of the dividends can be calculated as follows:
PV = (D1 / (1 + r)) + (D2 / (1 + r)^2) + ... + (Dn / (1 + r)^n) where PV is the present value, D1 to Dn are the dividends for each year, r is the equity cost of capital, and n is the number of years.
In this case, n = 5 because we are discounting the dividends for the next five years. Let's calculate the present value: PV = ($3.17 / (1 + 8.6%)) + ($3.40 / (1 + 8.6%)^2) + ($3.65 / (1 + 8.6%)^3) + ($3.92 / (1 + 8.6%)^4) + ($4.22 / (1 + 8.6%)^5)
PV = $3.17 / 1.086 + $3.40 / 1.086^2 + $3.65 / 1.086^3 + $3.92 / 1.086^4 + $4.22 / 1.086^5
PV ≈ $2.91 + $3.07 + $3.24 + $3.41 + $3.59
PV ≈ $16.22
Therefore, the estimated value per share of Procter and Gamble at the end of 2018 using the dividend-discount model is approximately $16.22.
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Pls help asapppp I dint know the answer and I’m running out of time
Step-by-step explanation:
I can barely see the questions
the volume of a large aquarium is 210 ft. it is 5 ft wide and 6 ft high. what is the length of the aquarium?
Answer:
7
Step-by-step explanation:
210=5×6×x
x is length of aquarium.
210÷(5×6)=7
$/sqrt{9}$
Johnathon spends two eights of his money on food, one fifth of his money on fuel, and two tenths of his money on clothes. Estimate what fraction of his money he has left
Answer:
7/20 of money left----------------------
Jonathan spends the fraction of total:
2/8 + 1/5 + 2/10 = 1/4 + 1/5 + 1/5 = 1/4 + 2/5 = 5/20 + 8/20 = 13/20The fraction of money left:
1 - 13/20 = 20/20 - 13/20 = 7/20Jonathan has 7/20 of money left.
What is the difference between 4 and -5?
Answer:
l-5l+l4l=9
l . l means total value from zero.
25 POINTS HELP NOWW
a curcle has a diameter of 14. What is the circumference of the circles exact value?
Answer:
i dont know math stinks
Step-by-step explanation:
Answer:
I guess the answers in the photo?
One pack of sliced cheese weighs 350 grams. How many packages would you need tobuy to have at least 1 kilogram of cheese?
Answer:
3
Step-by-step explanation:
Divide 1kg or 1000g by 350 and round up to the next integer. That's it.
Answer:
3 packages
Step-by-step explanation:
350+350=700
700+350=1100
1000 grams=1 kilograms
A thermometer is accurate to ± 5°F. Which absolute value equation can be used to find the greatest
and least possible temperatures if the thermometer reading is 29°F?
The absolute value equation can be used to find the greatest and least possible temperatures if the thermometer reading is 29°F is |t + 5| = 29.
What is absolute value function?An absolute value function is a function in algebra where the variable is inside the absolute value bars. This function is also known as the modulus function.
Now it is given that,
Accuracy of the thermometer = ± 5°F
Temperature reading of the thermometer = 29°F
Let t be the absolute temperature of the thermometer.
So, greatest possible temperatures-
Thermometer reading + thermometer accuracy
t + 5 = 29°F
And, least possible temperature
Thermometer reading - thermometer accuracy
t - 5 = 29°F
Thus, absolute value equation is given as,
t ± 5 = 29°F
⇒ |t + 5| = 29°F
Thus, the absolute value equation can be used to find the greatest and least possible temperatures if the thermometer reading is 29°F is |t + 5| = 29.
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Solve for the volume of the pyramid. Show your work and explain the steps you used to solve.
The volume of the pyramid is 3733.33 m³.
Having a square base and four lateral sides, a square pyramid is a type of pyramid in geometry. Having three or more triangular faces that intersect above its base, a pyramid is a particular kind of polyhedron (the apex).
The building is in the shape of a square pyramid.
The base of the building is 20 meters long.
The height of the building is 28 meters.
The volume of the right square pyramid is given as:
V = ( 1/3)a²h
Where a is the base and h is the height.
Now we have,
a = 20 m and h = 28 m
So,
V = ( 1/3 ) × 20 × 20 × 28
V = ( 1/3 ) × ( 20 )² × 28
V = 11200/3
V = 3733.33 m³
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a man builds a house with all 4 sides facing south. a bear walks past the house, what color is the bear
The color of the bear is White, since the house is directly built on north pole.
It is believed that this house was built directly on the northernmost point of the earth, the North Pole. In this scenario, if all four of his sides of the house face south, it means the house faces the equator. Since the North Pole is in an Arctic region where polar bears are common, any bear that passes in front of your house is likely a polar bear.
Polar bears are known for their distinctive white fur that blends in with their snowy surroundings. This adaptation is crucial for survival in arctic environments that rely on camouflage to hunt and evade predators.
Based on the assumption that the house is built in the North Pole and bears pass in front of it, the bear's color is probably white, matching the appearance of a polar bear.
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100 POINTS!
Factor completely.
(-a^2)+(ab)+(2b^2)
You have to use the box method.
(Algebra 1)
Step-by-step explanation:
I am not sure of the box method but here is an answer that maybe you can adapt
(-a+b)(a+b) = - a^2 - ab + ab + b^2 = - a^2 + b^2
now we need to add (b^2 and ab) to this to get the answer given
- a^2 + b^2 + b^2 + ab this will give the result needed ..factor it
( -a+b)(a+b) + b^2 + ab
( b-a)(a+b) + b ( b+a) this DOES equal -a^2 + ab + 2b^2
This can then be further reduced ( due to the common factor (b+a) to ( 2b-a)(a+b)
Answer:
(-a + 2b)(a + b)
Step-by-step explanation:
Given trinomial:
\((-a^2)+(ab)+(2b^2)\)
To factor using the box method, first create a 2x2 grid.
Place the first term of the trinomial in the upper left box, and the last term in the bottom right box of the 2x2 grid:
\(\begin{array}{|c|c|}\cline{1-2}\vphantom{\dfrac12}-a^2&\\\cline{1-2}\vphantom{\dfrac12}&2b^2\\\cline{1-2}\end{array}\)
Multiply these two terms together:
\(-a^2 \times 2b^2=-2a^2b^2\)
Look for factors of -2a²b² that will sum to the second term of the trinomial, ab.
Factors of -2a²b² that sum to ab are: -ab and 2ab.
Place -ab and 2ab in the empty boxes of the grid (the order doesn't matter):
\(\begin{array}{|c|c|}\cline{1-2}\vphantom{\dfrac12}-a^2&-ab\\\cline{1-2}\vphantom{\dfrac12}2ab&2b^2\\\cline{1-2}\end{array}\)
Find the greatest common factor of each row and write them down on the outside of the box.
\(\begin{array}{r|c|c|}\cline{2-3}\vphantom{\dfrac12}-a&-a^2&-ab\\\cline{2-3}\vphantom{\dfrac12}2b&2ab&2b^2\\\cline{2-3}\end{array}\)
Find the greatest common factor of each column and write them down on the outside of the box.
\(a\quad\;\;\;\;b\)
\(\begin{array}{r|c|c|}\cline{2-3}\vphantom{\dfrac12}-a&-a^2&-ab\\\cline{2-3}\vphantom{\dfrac12}2b&2ab&2b^2\\\cline{2-3}\end{array}\)
The factors of the trinomial are the sum of the external column numbers and the sum of the external row numbers: (-a + 2b) and (a + b).
Therefore, (-a²) + (ab) + (2b²) factored completely using the box method is:
(-a + 2b)(a + b)i will give brainliest.On every sale of goods worth N10,000.00, there is a commission of N550.00. If
an agent delivers N150,000.00, find his commission. pls helllp
Answer:
8250
Step-by-step explanation:
I think
The city of Anville is currently home to 21000 people, and the
population has been growing at a continuous rate of 7% per year. The
city of Brinker is currently home to 20000 people, and the population
has been growing at a continuous rate of 8% per year. In how many years
will the populations of the two towns be equal?
years
Give your answer accurate to at least 2 decimal places.
Edit:Not right answer
Answer:5 years
Step-by-step explanation:
21000x0.07=1400 people a year
20000x0.08=1600 people a year
1400x5=7000 people
1600x5=8000 people
21000+7000=28000 people
20000+8000=28000 people
Write a function PrintShampoolnstructions 0 . with int parameter numCycles, and void retum type. If numcycles is less than 1 , print "Too few". If more than 4. print "Too many." Else. print " N. Lather and rinse" numCycles times, where N is the cycle number, followed by 'Done:" End with a newline. Example output with input 2 1: Lather and rinse. 2: Lather and rinse. Done. Hint: Declare and use a loop variabie. 1 uinclude sstdio,hs Vo Your solution goes hene if int main(void) I int usercycles; scanf ( ndd
∗
, susercycles); Printsharepoornstructions(usercycles); return o;
In this code, the `PrintShampooInstructions` function takes an integer parameter `numCycles` and follows the logic you described:
- If `numCycles` is less than 1, it prints "Too few".
- If `numCycles` is more than 4, it prints "Too many"
```c
#include <stdio.h>
void PrintShampooInstructions(int numCycles) {
if (numCycles < 1) {
printf("Too few\n");
} else if (numCycles > 4) {
printf("Too many\n");
} else {
for (int i = 1; i <= numCycles; i++) {
printf("%d. Lather and rinse\n", i);
}
printf("Done.\n");
}
}
int main(void) {
int userCycles;
scanf("%d", &userCycles);
PrintShampooInstructions(userCycles);
return 0;
}
```
- Otherwise, it uses a loop to print "N. Lather and rinse" `numCycles` times, where N is the cycle number.
- Finally, it prints "Done." to indicate the completion of the instructions.
The `main` function demonstrates the usage of `PrintShampooInstructions`, taking user input for `numCycles` and calling the function with the provided value.
Please note that this code assumes the user will input a valid integer value for `numCycles`. Error checking for non-integer input is not included in this example.
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using your equation of f(x)= 5x + 8, evaluate f(5)
Answer:
33
Step-by-step explanation:
Answer:
33
Step-by-step explanation:
#carryonlearning :)Meadow is growing her hair out. The graph below shows how much her hair has grown over the last 8 months.
Which of the following shows the rate at which Meadow's hair is growing?
A.) 4 inches per month
B.) 0.50 inch per month
C.) 0.25 inch per month
D.) 2 inches per month
ANSWER QUICK!!! (Linear Equations)
Susan is required to buy pet food for her local pet shelter she buys food for both dogs and cats, but the dog food costs twice what the cat food costs. She needs to feed 150 cats and 30 dogs. Her budget is $3250. How much can Susan spend on dog food per dog
Given that Susan is required to buy food for dogs and cats. It is also given that dog food costs twice as much as cat food. Also, Susan needs to feed 150 cats and 30 dogs and her budget is $3250.
Let C be the cost of cat food. Then the cost of dog food will be 2C. Total cost of feeding 180 animals with cat food will be 150C. And the total cost of feeding 180 animals with dog food will be 30(2C) = 60C. Hence, the total amount of money Susan needs to spend is 150C + 60C = 210C. We know that Susan has $3250 to spend on food. Therefore:
210C = $3250 => C = $15 So, the cost of dog food is
2C = $30 per dog.
Therefore, Susan can spend $30 per dog on dog food. Given that Susan is required to buy food for dogs and cats. It is also given that dog food costs twice as much as cat food. Also, Susan needs to feed 150 cats and 30 dogs and her budget is $3250. Hence, the total amount of money Susan needs to spend is 150C + 60C = 210C.We know that Susan has $3250 to spend on food. Therefore:
210C = $3250 => C = $15 So, the cost of dog food is 2C = $30 per dog. Therefore, Susan can spend $30 per dog on dog food. In conclusion, Susan can spend $30 per dog on dog food.
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Hi, can you help me to solve this exercise, please!
Trigonometric Identities.
To solve this problem, we need to keep in mind the following:
* The tangent function is negative in the quadrant II
* The cosine (and therefore the secant) function is negative in the quadrant II
* The tangent and the secant of any angle are related by the equation:
\(\sec ^2\theta=\tan ^2\theta+1\)We are given:
\(\text{tan}\theta=-\frac{\sqrt[]{14}}{4}\)And θ lies in the quadrant Ii.
Substituting in the identity:
\(\begin{gathered} \sec ^2\theta=(-\frac{\sqrt[]{14}}{4})^2+1 \\ \text{Operating:} \\ \sec ^2\theta=\frac{14}{16}+1 \\ \sec ^2\theta=\frac{14+16}{16} \\ \sec ^2\theta=\frac{30}{16} \end{gathered}\)Taking the square root and writing the negative sign for the secant:
\(\begin{gathered} \sec ^{}\theta=\sqrt{\frac{30}{16}} \\ \sec ^{}\theta=-\frac{\sqrt[]{30}}{4} \end{gathered}\)The value of a car that depreciates over time can be modeled by the function M(t)=10000(0.9)^3t+2. Write an equivalent function of the form M(t)=ab^t
The equivalent exponential decay function is given as m(t) = 10000\((0.729)^{t}\)
What is an exponential function?
Calculating the exponential growth or decay of a given collection of data is done using an exponential function, which is a mathematical function. Mathematical functions with exponents include exponential functions. f(x) = bx, where b > 0 and b 1, is a fundamental exponential function.
Here, we have
Given: The value of a car that depreciates over time can be modeled by the function M(t) = 10000\((0.9)^{3t}\)
An exponential function is in the form
y = abˣ
where y and x are variables, a is the initial value of y, and b is the multiplier.
Let m(t) represent the value of the car after t years, hence the exponential decay is given by:
m(t) = \(10000(0.9)^{3t}\)
m(t) = 10000\((0.9)^{3(t)}\)
m(t) = 10000\((0.729)^{t}\)
Hence, The equivalent exponential decay function is given as m(t) = 10000\((0.729)^{t}\)
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A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 38 centimeters, and the length of the other leg is 21 centimeters. The student incorrectly says that the length of the hypotenuse is 7.7 centimeters
a. Find the length of the hypotenuse of the right triangle to the nearest tenth of a centimeter.
adam graded ten standardized tests with the following scores: 48, 65, 72, 86, 84, 52, 93, 97, 81, 80 which standardized test score represents the 70th percentile?
Standardized test score that represents 70th percentile is 86.
Percentile is a comparison score between someone's score and the scores of the rest of the group. It tells the percentage of surpassed scores.
Data set = 48, 65, 72, 86, 84, 52, 93, 97, 81, 80
Sample size, n = 10
Now, arrange numbers in ascending order.
48, 52, 65, 72, 80, 81, 84, 86, 93, 97
Formula for percentile is,
Percentile = ( Number of Scores below 86 / Sample size ) x 100
Percentile = ( 7 /10 ) x 100
= (0.7) x 100
= 70%
Therefore, we can conclude that 70th percentile is = 86.
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The five values for a data set are: minimum = 0 lower quartile = 2 median = 3. 5 upper quartile = 5 maximum = 10 Bruno created the box plot using the five values. What error did he make? The right whisker should go from 3. 5 to 10. The left whisker should go from 0 to 2. The box should go from 2 to 3. 5. The box should go from 3. 5 to 5
The five values for a data set are: minimum = 0 lower quartile = 2 median = 3. 5 upper quartile = 5 maximum = 10 Bruno created the box plot using the five values. Bruno made error. The left whisker should go from 0 to 2.
About quartileQuartiles is a type of quartile that divides data into four parts with approximately the same number. The first quartile or lower quartile (Q1) is the middle value between the smallest value and the median of the data group. The first quartile is a marker that the data in that quartile is 25% below the data group.
The second quartile (Q2) is the median data which marks 50% of the data (dividing the data in half). The third or upper quartile (Q3) is the middle value between the median and the highest value of the data set. The third quartile is a marker that the data in that quartile is 75% below the data group. Quartiles are a form of an ordered statistic because to determine quartiles, data needs to be sorted from smallest to largest value first.
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The library sponsors a chess club for members of all ages and skill levels. Currently, the ages of the members are 7, 9, 10, 11, 13, 14, 15, 16, 18, 19, 20, 21, and 22. The librarian uses a histogram to track the number of members in different age groups. For this situation, which is the appropriate way to label the age intervals on the x-axis?
Answer:
B. 7−10; 11−14; 15−18; 19−22
Step-by-step explanation:
If w = ln(2x^2 + y^2 - z^2) + ln(2y^2 – z^2) + In (x^2), then Wzxy(1, 1, 1) =
Given f(x,y,z) = ln(2x² + y² - z²) + ln(2y² - z²) + In(x²) then Wzxy(1,1,1) will be -3/2 using the partial-derivative of the function
Now,Let's find the first derivative of the function f with respect to zfz(x,y,z) = ∂f/∂z
= 1/(2x² + y² - z²) * (-2z) + 1/(2y² - z²) * (-2z) + 0
= -2z/(2x² + y² - z²) - 2z/(2y² - z²)
Now,evaluate the partial derivative of fz with respect to xfzx(x,y,z)
= ∂fz/∂x
= ∂/∂x(-2z/(2x² + y² - z²) - 2z/(2y² - z²))
= 4xz/(2x² + y² - z²)²
Now, let's find the derivative of fzx with respect to yfzxy(x,y,z)
= ∂²f/∂z∂x∂y
= ∂/∂y(4xz/(2x² + y² - z²)²)
= -8xyz/(2x² + y² - z²)³
Now, Wzxy(1,1,1) = ∂³f/∂z∂x∂y (1, 1, 1)
= -24/16= -3/2
Therefore, Wzxy(1, 1, 1) = -3/2
Thus, the correct option is (d).
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Solve:
x-1
——— < 0
x²-4
Answer: x≠±2, x<±2, x>1, x<1, and x>±2
explanation:
for this equation to be true
Case 1
either (x-1) should be a negative while (x²-4) should be positive
which gives:-
x-1<0
so, x<1
also, x²-4>0
so, x²>4
⇒x>±2
Case 2:-
x-1>0 and x²-4<0
which gives
x>1 and x²-4<0
so, x>1 or x<±2
Case 3:-
either way, the denominator can't be 0
so, x²-4≠0
which gives,
x≠±2
compiling all, we have,
x≠±2, x<±2, x>1, x<1, and x>±2
These solutions can be pointed to as points on a number line and the behavior shows their discontinuity.
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Compare the function f(x)=3x-1/2 to the function shown in the graph. Which statements are correct?
Answer: B
Step-by-step explanation:
For \(f(x)=3x-\frac{1}{2}\), comparing it with slope-intercept form yields that the slope is \(3\) and the \(y\)-intercept is \(-1/2\).
For the graphed function, the slope is \(\frac{-4-0}{-2-6}=\frac{1}{2}\) and the \(y\)-intercept is about \(-3\).
Since the absolute value of the slope of the graphed function is less than that of \(f(x)\), option B is correct.
calculate the volume of this solid if the base is a regular pentagon of area 27, and the altitude of the pyramid is 7
The volume of the solid is 63 cubic units.
To calculate the volume of a pyramid, you can use the formula:
Volume = (1/3) * Base Area * Height
In this case, the base is a regular pentagon with an area of 27 and the altitude (height) of the pyramid is 7.
First, let's find the side length of the pentagon. Since a regular pentagon has all sides and angles equal, we can use the following formulas:
Area = (5/4) * side^2 * cot(pi/5)
27 = (5/4) * side^2 * cot(pi/5)
Now we solve for side:
side^2 = (27 * 4) / ((5/4) * cot(pi/5))
side^2 = 108 / ((5/4) * cot(pi/5))
side^2 = 108 * (4/5) * tan(pi/5)
side^2 = 86.4
side ≈ √86.4
side ≈ 9.306
Now we can calculate the volume using the formula:
Volume = (1/3) * Base Area * Height
Volume = (1/3) * 27 * 7
Volume = 63 cubic units
Therefore, the volume of the solid is 63 cubic units.
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