starting with the following equation, fe₂o₃(s) al(s) → fe(l) al₂o₃(s) calculate the moles of fe₂o₃ that will be required to produce 645 grams of fe.

Answer:

sentence 2, sentence 2, sentence 1

Explanation:

it was right for me on edge 2020

Answer:

1. Fred visited Nick after his graduation.

2. After Nick's graduation, Fred visited him.

1. Marie told Sarah that she makes great spaghetti.

2. Marie told Sarah, "You make great spaghetti."

1. John broke the fence with his bike.

2. John's bike hit a fence and it broke.

A 20-liter sample of gas at STP would occupy 5.68 liters if the pressure was changed to 20 atm and the temperature was changed to 38°C.

To solve this problem, we can use combined gas law, which relates the pressure, volume, and temperature of a gas. The formula for the combined gas law is:

\((P_1 * V_1) / (T_1 * n_1) = (P_2 * V_2) / (T_2 * n_2)\)

where P1 and P2 are the initial and final pressures of the gas \(V_1\) and \(V_2\) are the initial and final volumes of the gas.

At STP, the conditions are 1 atmosphere of pressure and 0°C (273 K) of temperature.

Therefore, we can use these values as our initial conditions \((P_1 = 1\ atm, T_1 = 273 K)\) and solve for \(V_2\), the final volume of the gas:

\((P_1 * V_1) / T_1 = (P_2 * V_2) / T_2\\V_2 = (P_1 * V_1 * T_2) / (P_2 * T_1)\)

Substituting the given values, we get:

\(V_2 = (1 atm * 20 L * 311 K) / (20 atm * 273 K) \\V_2 = 5.68 L\)

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Answer:

I hope everything gets better

Explanation:

Answer:

I hope you are better now

Using the change of base rule to find the logarithm to four decimal places. the correct answer is 11.4235.

To find the logarithm of 143.2 using the change of base rule, we can choose any base we prefer. Let's use base 10 and natural logarithm (base e) for this calculation.

First, we'll use the change of base formula, which states that log(base b) x = log(base c) x / log(base c) b. In this case, we'll calculate log(base 10) 143.2.

We'll use the natural logarithm (ln) as our intermediary step. The natural logarithm of 143.2 can be calculated as ln(143.2).

Using a calculator, we find that ln(143.2) is approximately 4.9628.

Next, we need to calculate log(base 10) e, which is the logarithm of e with base 10. Using a calculator, we find log(base 10) e is approximately 0.4343.

Finally, we apply the change of base formula:

log(base 10) 143.2 ≈ ln(143.2) / log(base 10) e
                ≈ 4.9628 / 0.4343
                ≈ 11.4235

Rounding to four decimal places, the logarithm of 143.2 using base 10 is approximately 11.4235.

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16.77 grams of KClO3 must be decomposed to produce 3.45 L of oxygen at STP with a 75.3% yield.

To find out how many grams of KClO3 must be decomposed to produce 3.45 L of oxygen at STP with a 75.3% yield, we'll use the following steps:

1. Convert the volume of oxygen gas to moles using the molar volume of gas at STP (22.4 L/mol).
2. Adjust for the yield percentage.
3. Use the stoichiometry of the balanced equation to find the moles of KClO3.
4. Convert moles of KClO3 to grams using its molar mass.

1. Moles of O2 produced: (3.45 L) / (22.4 L/mol) = 0.154 moles O2
2. Adjust for yield: 0.154 moles / 0.753 = 0.205 moles O2 (theoretical yield)
3. Moles of KClO3: (0.205 moles O2) * (2 moles KClO3 / 3 moles O2) = 0.137 moles KClO3
4. Grams of KClO3: (0.137 moles KClO3) * (122.55 g/mol) = 16.77 g KClO3

So, 16.77 grams of KClO3 must be decomposed to produce 3.45 L of oxygen at STP with a 75.3% yield.

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Answer:

When endothermic reaction takes place, the system gains heat from the surroundings and so the temperature of the surroundings decreases ie. it gets colder

Explanation:

A chemical reaction is exothermic if heat is released by the system into the surroundings.

STUDY WELL!

The purpose of adding base in the aldol condensation reaction is to generate the enolate ion, which is a strong nucleophile and is critical for the reaction to take place. The enolate ion attacks the carbonyl group of another molecule, resulting in the formation of a carbon-carbon bond.

In the aldol condensation reaction, the base serves two primary functions. Firstly, it generates the enolate ion, which is an essential intermediate for the reaction. Secondly, the base helps to remove the alpha hydrogen atom from the carbonyl compound, allowing it to become acidic and therefore more susceptible to the removal of the proton. When the base is added to the carbonyl compound, it accepts a proton to form an anion. This anion then attacks the carbonyl group of another molecule, resulting in the formation of a carbon-carbon bond. As a result, the aldol product is formed. The product can either be an α,β-unsaturated carbonyl compound or a β-hydroxy carbonyl compound depending on the reaction conditions.

In summary, the addition of base in the aldol condensation reaction serves to generate the enolate ion, which is a strong nucleophile and is essential for the reaction to occur. It also helps to remove the alpha hydrogen atom from the carbonyl compound, allowing it to become acidic and more reactive.

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Answer:

There is nothing attached to this question so I unfortunately cannot help you

Explanation:

True. 1-octanol is a combustible liquid with a flashpoint of 86°C and an auto-ignition temperature of 258°C, according to the provided SDS.

The SDS (Safety Data Sheet) for 1-octanol indicates that it is a combustible liquid. According to the SDS, 1-octanol has a flashpoint of 86°C (187°F) and an auto-ignition temperature of 258°C (496°F). These values suggest that 1-octanol can easily ignite in the presence of an ignition source and may burn at relatively low temperatures. Additionally, the SDS provides information on the fire and explosion hazards associated with 1-octanol and recommends appropriate handling procedures and precautions to minimize the risk of fire or explosion. Therefore, it is important to handle 1-octanol with care and follow appropriate safety protocols when working with this substance.

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The complete question is:

the SDS for 1-octanol is provided here. (links to an external site.) is 1-octanol a combustible liquid? True or False.

2H2O+O2--->2H2O2  

8.5 gm H2O2=0.25 mole  

hence H2O is also 0.25 mole i.e.4.5 gm  

O2is 0.125 mole i.e.4 gm

Answer:

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Answer:

As the garter snake can be found almost in any kind of habitat, what makes them be able to survive in any environment include:

1. They hibernate to increase their chances of survival in unfavorable weather conditions.

2. They can blend with the background of any environment especially grass to escape being eaten.

3. They produce an odor that is usually unpleasant especially when about to be attacked.

Explanation:

The garter snakes are distinguished by the three stripes running the length of their body and can often be found in forests, places that are even close to water bodies, and almost any place, even in holes.

Answer:

Because it'll live in the desert!

Explanation:

It probably won't survive on time!

Answer:

Same amount of liquid and take up same amount of liquid but they are in different containers

Explanation:

A non-spontaneous process is one in which the overall entropy change is negative.

Thermodynamic principles are used to optimize the performance of our houses' heating and cooling systems, other buildings' engines, and even the motor cars we drive.

The amount of thermal energy per unit of temperature in a system that is not accessible for doing beneficial work. The quantity of entropy is also a gauge of a system's molecular disorder, or unpredictability, since work is produced by organized molecular motion.

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Answer:

sorry we don't know the answer.

There are D) 9.51E23

Given

1.58 moles of LiOH

Required

The number of formula units

Solution

The mole is the number of particles(molecules, atoms, ions, formula units) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

So for 1.58 moles :

= 1.58 x 6.02 x 10²³

= 9.5116 x 10²³

The density of rhodium metal is approximately 4.755 g/cm³.

To calculate the density of rhodium metal, we need to use the formula:

Density = (mass of the unit cell) / (volume of the unit cell)

In a face-centered cubic (FCC) unit cell, each corner atom contributes 1/8th of its volume to the unit cell, while each face-centered atom contributes its entire volume.

Given that rhodium has a face-centered cubic unit cell, the relationship between the atomic radius (r) and the edge length (a) of the unit cell can be expressed as;

a = 4r / √2

Let's calculate the edge length of the unit cell;

a = 4(134 pm) / √2

a ≈ 377.98 pm

Now, let's calculate the volume of unit cell;

Volume of the unit cell = a³

Volume of the unit cell = (377.98 pm)³

Volume of the unit cell ≈ 21,663,803.7 pm³

Next, we need to convert the volume from picometers cubed (pm³) to cubic centimeters (cm³);

1 cm³ = 10²⁴ pm³

Volume of the unit cell ≈ 21,663,803.7 pm³ × (1 cm³ / 10²⁴ pm³)

Volume of the unit cell ≈ 2.16638037 × 10⁻¹¹ cm³

The atomic mass of rhodium (Rh) is approximately 102.91 g/mol. Since there is only one rhodium atom in the unit cell, the mass of the unit cell is equal to the molar mass of rhodium (102.91 g/mol).

Now, let's calculate the density;

Density = mass of the unit cell/volume of the unit cell

Density = 102.91 g/mol / (2.16638037 × 10⁻¹¹ cm³)

Density ≈ 4.755 g/cm³

Therefore, the density of rhodium metal is approximately 4.755 g/cm³.

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Answer: blowing a balloon is a physical change as when you blow a balloon the balloon expands but the balloon remains a balloon .there is change in Blowing a balloon is a physical change because only the size of the balloon changes , no change in chemical properties of the balloon occurs (no new substance is formed).

Explanation:

Answer:

releases energy from the food for us to use

Explanation:

87.56% is the percentage of the original s2o82– in solution 1 that should have been consumed after the fourth time interval.

The initial concentration of s2o82– in solution 1 was 0.025 M. The rate constant of the reaction at this temperature is 6.20 x 10-4 s-1. The reaction is first-order, hence the rate law can be represented by rate = k[s2o82–].To calculate the percentage of original s2o82– in solution 1 that should have been consumed after the fourth time interval, we will use the following formula:  

t1/2 = ln(2)/k where t1/2 is the half-life of the reaction. Since the reaction is first-order, we can use the half-life formula to find out the concentration of s2o82– remaining after the fourth time interval.

half-life (t1/2) = ln(2)/k = ln(2)/6.20 x 10-4 s-1 = 1118.5 s

Converting 15 minutes to seconds: 15 minutes x 60 seconds/minute = 900 seconds

After four time intervals (4 x 900 seconds), the time elapsed is 3600 seconds. Hence, the fraction of s2o82– remaining is: fraction remaining = 1/2nwhere n is the number of half-lives. In this case, n is equal to 3600 seconds (the total time elapsed) divided by the half-life (1118.5 seconds), or n = 3.22 (rounded to two decimal places).fraction remaining = 1/2n = 1/23.22 = 0.1244

Consequently, the percentage of s2o82– consumed is: percent consumed = (1 - 0.1244) x 100% = 87.56%

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When the author states that "on a molecular level, no one compound is grosser than any other," he is suggesting that at the smallest level of matter, which is the molecular level, there is no inherent difference between different compounds.

All compounds are made up of molecules, which are simply collections of atoms. The atoms themselves are made up of protons, neutrons, and electrons, which are all subatomic particles.

Thus, the author is saying that on a molecular level, all compounds are made of the same basic building blocks, and therefore, no one compound is fundamentally different or "grosser" than any other. It could be that the author is trying to make a point about the subjective nature of describing something as "gross" or not, and how this is not a scientifically valid way to measure the properties of a compound.

In summary, the author is pointing out that at the molecular level, all compounds are made up of the same building blocks, and therefore, one compound is not inherently "better" or "worse" than another.

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Moles of HNO_3

\(\\ \rm\hookrightarrow Given\:mass/Molar\:mass\)

\(\\ \rm\hookrightarrow 18.71/63.01=0.29mol\)

Moles of water:-

The difference in kinetic energy if a 6 kg bowling ball rolling at 16 mph and when it is rolling at 14 mph is 180J.

Kinetic energy of an object can be calculated using the following formula;

K.E = ½mv²

Where;

According to this question, a 6 kg bowling ball is rolling at 16 mph and 14 mph respectively.

K.E = (½ × 6 × 16²) - (½ × 6 × 14²)

K.E = 768 - 588

∆K.E = 180J

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Answer:

selenium, fluorine and neon

Explanation:

the less valence electrons an element has, the more reactive.

selenium has 6 valence electrons

fluorine has 7 valence electrons

neon has 8 valence electrons

So, it is ordered from the least number of valence electrons to the most

Tetrodotoxin (TTX) specifically affects voltage-gated sodium channels.

These channels are responsible for the generation and propagation of action potentials in excitable cells, including neurons and muscle cells. TTX binds tightly to a specific site on the outside of the sodium channel, blocking the movement of sodium ions through the channel pore.

By blocking sodium channels, TTX prevents the influx of sodium ions into cells during depolarization, effectively inhibiting the generation and propagation of action potentials. This leads to the disruption of normal electrical signaling in excitable tissues, resulting in various physiological effects depending on the affected tissues.

Due to its potent inhibitory effects on sodium channels, TTX is known for its use as a toxin, primarily found in pufferfish and certain other marine organisms. Ingesting TTX-contaminated seafood can lead to severe poisoning, characterized by paralysis, respiratory failure, and potentially fatal consequences.

Research on TTX and its interactions with sodium channels has also provided valuable insights into the function and structure of these channels, contributing to our understanding of electrical signaling in cells and the development of drugs targeting sodium channels for therapeutic purposes.

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The reaction between nitrous acid (HNO2) and sodium hydroxide (NaOH) can be represented as:

HNO2 + NaOH → NaNO2 + H2O

This is a neutralization reaction, in which a strong base (NaOH) reacts with a weak acid (HNO2) to produce a neutral salt (NaNO2) and water.

To calculate the pH of the solution after the addition of NaOH, we need to determine the amount of nitrous acid that has been neutralized by the NaOH. The initial moles of nitrous acid in the solution can be calculated as follows:

Initial moles of HNO2 = 1.000 M x 122.1 mL / 1000 mL/L = 0.12210 moles

The moles of NaOH added to the solution can be calculated as follows:

Moles of NaOH added = 0.4000 M x 344.5 mL / 1000 mL/L = 0.1378 moles

Since the reaction is 1:1, the moles of HNO2 that have been neutralized by the NaOH is equal to the moles of NaOH added:

Moles of HNO2 neutralized = 0.1378 moles

The remaining moles of HNO2 in the solution can be calculated as follows:

Remaining moles of HNO2 = 0.12210 moles - 0.1378 moles = -0.0157 moles

Since the solution is at equilibrium, the concentration of HNO2 can be calculated using the equation for the dissociation of nitrous acid:

[HNO2] = K_a x [HNO2]^2 / (1 + [HNO2])^2

Where K_a is the acid dissociation constant of nitrous acid, which can be found in a table of acid dissociation constants.

Since K_a = 10^-pK_a, where pK_a is the negative logarithm of the acid dissociation constant, we can calculate K_a as follows:

K_a = 10^-3.35 = 2.74 x 10^-4

Substituting the remaining moles of HNO2 into the equation, we can calculate the concentration of HNO2:

2.74 x 10^-4 = 2.74 x 10^-4 x [HNO2]^2 / (1 + [HNO2])^2

[HNO2]^2 / (1 + [HNO2])^2 = 1

[HNO2]^2 = (1 + [HNO2])^2

[HNO2]^2 = 1 + 2[HNO2] + [HNO2]^2

0 = 1 + 2[HNO2] + [HNO2]^2

[HNO2]^2 + 2[HNO2] + 1 = 0

Using the quadratic formula, the solution for [HNO2] is:

[HNO2] = (-2 ± √(4 - 4(1)(1))) / 2(2)

[HNO2] = (-2 ± √(0)) / 2(2)

[HNO2] = -1

Since [HNO2] is negative, it is not possible to have a negative concentration of HNO2. We must therefore reject this solution.

[HNO2] = (-2 -

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Answer:

The answer is C for sure!

Explanation:

In the picture we have the electrons given, so we have to determine the nucleons and protons.

Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

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Answer:

A

Explanation:

The Maxwell-Boltzmann equation, is the basis for discussion of the kinetic theory of gases. From it we can understand how gases are distributed at a particular temperature.

Let us remember that the kinetic energy of all gases is the same at the same temperature. However, the distribution of gases depends on their molecular weight at that particular temperature.

Heavier molecules are known to move slowly compared to lighter molecules. Heavier molecules generally have a smaller distribution while lighter molecules spread out.

For this reason, oxygen which is heavier than nitrogen has a smaller distribution as shown in the diagram (molar mass of oxygen = 32g/mol) while nitrogen (molar mass 28 g/mol) has a distribution that is more spread out being a lighter molecule. Hence the option chosen.