Answer:
not similar
Step-by-step explanation:
hope it help
line c and d are perpendicular. the slope of line c is -2/3. which equation is true?
Answer:
The slope of line d is 3/2 since the slopes of perpendicular lines are negative reciprocals of each other.
So the correct equation is
-2/3 × slope of d = -1
Answer:
3/2
Step-by-step explanation:
If a line is perpendicular to the other it's slope is the inverse reciprocal of the other slope
A sugar solution currently measures 250 degrees fahrenheit. the temperature of the solution increases 5 degrees per minute. the sugar solution will caramelize at temperatures greater than 310 and less than 338 degrees fahrenheit. which inequality can be used to find x, the number of minutes it will take for the solution to begin caramelizing?
The inequality which is used to find the number of minutes taken by the solution to begin caramelising is 310 < 250 + 5x <338. The correct answer is option A.
The complete question is given below:-
A sugar solution currently measures 250 degrees Fahrenheit. The temperature of the solution increases 5 degrees per minute. The sugar solution will caramelize at temperatures greater than 310 and less than 338 degrees Fahrenheit. Which inequality can be used to find x, the number of minutes it will take for the solution to begin caramelizing? 310 < 250 + 5x < 338 310 < 250 + 5x < 338 310 < 5(x + 250) < 338 310 < 5(x + 250) < 338
What is inequality?A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions is called an inequality.
According to the given question.
The current temperature of a sugar solution is 250 degrees Fahrenheit. Per minute the temperature of the solution increases by 5 degrees. Also, x is the number of minutes taken by the sugar to caramelize.
⇒ The total increase in the temperature in x minutes = 25 + 5x
Since the sugar solution caramelizes at a temperature greater than 310 and less than 338.
Inequality will be given as:-
310 < 250 + 5x < 338
Therefore, the inequality which is used to find the number of minutes taken by the solution to begin to caramelize is given by 310 < 250 + 5x < 338.
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Which expression is equivalent to 1/2(16x+2)+5?
A:8x+6
B:8x+7
C:14x
D:15x
Answer:
A is the answer!
3 (3 – 3) = 2 ( + 3) – 30
Answer:
0 = 2×3 - 30
= 6-30
= -24
is the right answer
This question has no solution, but If you want to to compare, then it's False because 0 doesn't equal -24
solve this if u can pls!
using the numbers 5, 7, and 8 only once each, fill in the boxes to make the statement true.
Answer:
its log 5 7/8
Step-by-step explanation:
if cosecA = 2 find the value of 1/tanA +sinA /1+cosA
The final answer is the same as given, which is cosecA= 2.....
hope it helped ☺️
17 points please help
Answer:
3% of the figure is shaded
Fraction: 3/10
Decimal: 0.3
Hope this helped
Can someone help me out on this
Answer:
Step-by-step explanation:
A person invested $8100 for 1 year, part 5%, part at 11%, and the remainder at 14%. The total annual income from these investments was $942. The amount of money invested at 14% was $500 more than the amounts invested at 5% and 11% combined. Find the amount invested at each rate.
The formula is
\(C=c(1+n\times i)\)Where C is the total, c initial capital, n the number of years and i interest percentage
We can modify the formula to express the total won
\(C=c_1(1+n\times i_1)+c_2(1+n\times i_2)+c_3(1+n\times i_3)\)Where c1 is the par 5%, C2 the par at 11% and c3 the par at 14%
i1,i2 and i3 the percentage of interest applied to each part
as a total you must use the total earned plus the initial capital
so replacing
\(\begin{gathered} 8100+942=c_1(1+1\times0.05)+c_2(1+1\times0.11)+c_3(1+1\times0.14) \\ 9042=c_1(1.05)+c_2(1.11)+c_3(1.14) \end{gathered}\)this was our first equation
the next comes from: the sum of all inverted parts is 8100
so
\(c_1+c_2+c_3=8100\)hitrd equation is from: The amount of money invested at 14% was $500 more than the amounts invested at 5% and 11% combined.
\(c_3=c_1+c_2+500\)Solution of the equations
\(\begin{gathered} 9042=c_1(1.05)+c_2(1.11)+c_3(1.14) \\ c_1+c_2+c_3=8100 \\ c_3=c_1+c_2+500 \end{gathered}\)we replace the third equation on the second
\(\begin{gathered} c_1+c_2+(c_1+c_2+500)=8100 \\ 2c_1+2c_2=8100-500 \\ 2c_1=7600-2c_2 \\ \\ c_1=\frac{7600-2c_2}{2} \\ \\ c_1=3800-c_2 \end{gathered}\)now replace c3 and c1 on the first equation to find c2
\(9042=(3800-c_2)(1.05)+c_2(1.11)+(c_1+c_2+500)(1.14)\)now replace c1 again
\(9042=(3800-c_2)(1.05)+c_2(1.11)+(3800-c_2+c_2+500)(1.14)\)and find c2
\(\begin{gathered} 9042=3990-1.05c_2+1.11c_2+(4300)(1.14) \\ 9042-3990=0.06c_2+4902 \\ 5052-4902=0.06c_2 \\ 150=0.06c_2_{} \\ \\ c_2=\frac{150}{0.06}=2500 \end{gathered}\)the value of c2 or the part at 11% is $2,500
now we can replace c2 in one of the equations we solved, for example this
\(c_1=3800-c_2\)and find c1
\(\begin{gathered} c_1=3800-2500 \\ c_1=1300 \end{gathered}\)the value of c1 or the part at 5% is $1,300
now we can repalce c1 and c2 on the equation
\(c_1+c_2+c_3=8100\)and find c3
\(\begin{gathered} 1300+2500+c_3=8100 \\ c_3=8100-1300-2500 \\ c_3=4300 \end{gathered}\)the value of c3 or the part at 14% is $4,300
the total values are
part at 11% is $2,500
part at 5% is $1,300
part at 14% is $4,300
Can someone please help me out with this problem
Answer:
Step-by-step explanation:
Formula for the volume of a cone:
((r^2)(height)(pi)) / 3
Since we are finding the answer in terms of pi, we will use the pi symbol.
The radius is 18.
The height is 30.
18^2 is 324.
324 x 30 is 9720.
9720 / 3 is 3240.
Answer : 3240 pi.
A cow is tied with a rope of length 14 m at the corner of a rectangle field of dimension 20 m × 16 m, then the area of the field in which the cow can graze is:
A) 154 m²
B) 156 m²
C) 158 m²
D) 160 m²
unwanted answers will be reported...and the best will be marked as the brainliest...
View Policies Current Attempt in Progress Using the information provided in the table, the network diagram and the project completion time = 25 weeks, reduce the completion time of the project by 5 we
Strategies such as fast-tracking, crashing, prioritization, and resource optimization can be employed to reduce the project completion time by 5 weeks.
To reduce the completion time of the project by 5 weeks, we need to analyze the provided information and make appropriate adjustments. The initial completion time of the project is 25 weeks.
To achieve a reduction of 5 weeks, we can consider several strategies:
1. Fast-tracking: This involves overlapping or parallelizing certain project activities that were initially planned to be executed sequentially. By identifying tasks that can be performed concurrently, we can potentially save time. However, it's important to evaluate the impact on resource allocation and potential risks associated with fast-tracking.
2. Crashing: This strategy focuses on expediting critical activities by adding more resources or adopting alternative approaches to complete them faster. By compressing the schedule of critical tasks, we can reduce the overall project duration. However, this may come at an additional cost.
3. Prioritization: By reevaluating the project tasks and their priorities, we can allocate resources more efficiently. This ensures that critical activities receive higher attention and are completed earlier, resulting in an accelerated project timeline.
4. Resource optimization: Analyzing the resource allocation and identifying potential areas for optimization can lead to time savings. By ensuring that resources are utilized effectively and efficiently, we can streamline the project execution process.
It's important to note that implementing any of these strategies requires careful evaluation, considering factors such as project constraints, risks, cost implications, and stakeholder agreements. A comprehensive analysis of the project plan, resource availability, and critical path can guide the decision-making process for reducing the project completion time.
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and a positive constant binomial (x 5) is a factor of x2 8x 15. what is the other factor? (x 3)(x 7)(x 12)(x 13)
To find the other factor when (x-5) is a factor of the quadratic expression \(x^2 - 8x + 15\), we can use polynomial division or factoring techniques.
We can perform polynomial division as follows:
\(x - 5 | x^2 - 8x + 15\)
\(- (x^2 - 5x)\)
---------------
-3x + 15
- (-3x + 15)
---------------
0
The result of the division is 0, which means that (x-5) evenly divides \(x^2 - 8x + 15\). Therefore, the other factor is the quotient obtained during the division, which is x - 3.
So, the two factors of \(x^2 - 8x + 15\) are (x - 5) and (x - 3).
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PLEASE HELP WILL GIVE BRAINLIEST!
A dart board contains 20 equal sized sectors numbered 1 to 20. A dart is randomly tossed at the board 10 times. what is the probability that the dart lands in sector 20 exactly 5 times?
Answer:
it 20 chews 5 over 20 chews 10
= 20! / (20-5)! times 5! over 20! / (20-10)! times 10!
=15504/ 184756= .08 or 8%
Step-by-step explanation:
have a good day/night
may i please have a branllliest
sorry if wrong :(
a batch of 200 iron rods consists of 50 oversized rods, 50 undersized rods and 100 rods of the desired length. if two rods are drawn at random without replacement, what is the probability of obtaining (a) two rods of the desired length, (b) exactly one of the desired length, (c) none of the desired length? show all steps and clearly write out your formulas and assumptions
(a) The probability of obtaining two rods of the desired length is (100/200) * (99/199) = 0.495.
This can be found by using the formula for independent events:
P(A and B) = P(A) * P(B)
Since the two draws are of rods without replacement,
the probability of the first-rod being of the desired length = 100/200 (there are 100 desired-length rods out of a total of 200).
The probability of the second-rod being of the desired length = 99/199 (since one of the desired length rods has already been drawn). Multiplying these two probabilities gives us the answer.
(b)The probability of obtaining exactly one rod of the desired length
=(100/200) * (100/199) + (100/200) * (100/199)
= 0.990.
This can be found by using the formula for the union of two events: P(A or B) = P(A) + P(B).
Since the two draws are rods without replacement, the first draw has a probability of 100/200 of being of the desired length (there are 100 desired-length rods out of a total of 200).
The probability of the second draw being of the desired length is 100/199 (since one of the desired length rods has already been drawn). Adding these two probabilities gives us the answer.
(c) The probability of obtaining none of the desired length is (50/200) * (50/199) = 0.015.
This can be found by using the formula for independent events
: P(A and B) = P(A) * P(B).
Since the two draws are of rods without replacement, the probability of the first-rod being of the undersized length is 50/200 (there are 50 undersized rods out of a total of 200).
The probability of the second-rod being of the undersized length is 50/199 (since one of the undersized rods has already been drawn). Multiplying these two probabilities gives us the answer.
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the accompanying dataset provides data on monthly unemployment rates for a certain region over four years. compare​ 3- and​ 12-month moving average forecasts using the mad criterion. which of the two models yields better​ results? explain.
To compare the 3-month and 12-month moving average forecasts using the mean absolute deviation (MAD) criterion, we need to calculate the MAD for each model and then compare them. The MAD is a measure of the average magnitude of the forecast errors, and a lower MAD indicates a better forecast.
To calculate the MAD for the 3-month moving average model, we need to first calculate the forecasted values for each month by taking the average of the unemployment rates for the previous 3 months. For example, the forecasted value for April 2018 would be the average of the unemployment rates for January, February, and March 2018. We then calculate the absolute deviation between the forecasted value and the actual value for each month, and take the average of those deviations to get the MAD for the 3-month moving average model.
We can repeat this process for the 12-month moving average model, but instead of taking the average of the previous 3 months, we take the average of the previous 12 months.
Once we have calculated the MAD for both models, we can compare them to determine which model yields better results. Generally, a lower MAD indicates a better forecast. However, it is important to note that the MAD criterion only considers the magnitude of the forecast errors and does not take into account the direction of the errors (i.e., overestimation versus underestimation).
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Full Question ;
The accompanying dataset provides data on monthly unemployment rates for a certain region over four years. Compare 3- and 12-month moving average forecasts using the MAD criterion. Which of the two models yields better results? Explain. Click the icon to view the unemployment rate data. Find the MAD for the 3-month moving average forecast. MAD = (Type an integer or decimal rounded to three decimal places as needed.) A1 fx Year D E F G H I 1 2 3 1 с Rate(%) 7.8 8.3 8.5 8.9 9.4 9.6 9.4 9.5 9.7 9.9 9.8 10.1 9.9 9.7 9.8 9.91 9.7 9.4 9.6 9.4 9.3 9.5 9.9 9.5 9.2 9.1 8.9 A B Year Month 2013 Jan 2013 Feb 2013 Mar 2013 Apr 2013 May 2013 Jun 2013 Jul 2013 Aug 2013 Sep 2013 Oct 2013 Nov 2013 Dec 2014 Jan 2014 Feb 2014 Mar 2014 Apr 2014 May 2014 Jun 2014 Jul 2014 Aug 2014 Sep 2014 Oct 2014 Nov 2014 Dec 2015 Jan 2015 Feb 2015 Mar 2015 Apr 2015 May 2015 Jun 2015 Jul 2015 Aug 2015 Sep 2015 Oct 5 7 3 ) 1 2 3 1 5 7 9.1 ) 9. 1 2 3 1 5 7 ) 9.1 8.9 8.9 8.9 8.9 8.7 8.4 8.3 8.3 8.4 8.1 8.1 8.4 8.2 8.3 7.7 7.9 7.9 7.8 1 2 2015 Dec 2016 Jan 2016 Feb 2016 Mar 2016 Apr 2016 May 2016 Jun 2016 Jul 2016 Aug 2016 Sep 2016 Oct 2016 Nov 2016 Dec 3 1 5 3 2 2
what is the LCM of 9,12,16
Answer: The Least Common Multiple (LCM) for 9, 12 and 16, notation LCM (9,12,16), is 144.
Answer:
its 144
Step-by-step explanation:
find the area enclosed by the curve x = t2 − 3t, y = t and the y-axis.
The area under the curve is \(\frac{6 \sqrt{3}}{5}\).
Consider the following parametric equations:\($$x=t^2-3 t \text { and } y=\sqrt{t} \text { and the } y \text {-axis. }$$\)
The objective is to find area enclosed by the curve using the formula.
The area under the curve is given by parametric equations x=f(t), y=g(t), and is traversed once as t increases from α to β, then the formula for calculating the area under the curve:
\($$A=\int_\alpha^\beta g(t) f^{\prime}(t) d t$$\)
The curve has intersects with y-axis. so x=0
\($$\begin{aligned}t^2-3 t & =0 \\t(t-3) & =0 \\t & =0 \text { or } t=3\end{aligned}$$\)
Now we have to draw the graph,
Let f(t)=\(t^2-3 t, g(t)=\sqrt{t}$\)
Differentiate the curve f(t) with respect to t.
\(f^{\prime}(t)=2 t-3\)
Now, find the area under the curve use the above formula.
\(\begin{aligned}A & =\int_0^3(\sqrt{t})(2 t-3) d t \\& =\int_0^3(2 t \sqrt{t}-3 \sqrt{t}) d t \\& =\int_0^3\left(2 t^{\frac{3}{2}}-3 t^{\frac{1}{2}}\right) d t \\& =\left[2 \frac{t^{\frac{5}{2}}}{\frac{5}{2}}-3 \frac{t^{\frac{3}{2}}}{\frac{3}{2}}\right]_0^3 \\& \left.\left.=\left[\frac{4 t^{\frac{5}{2}}}{5}-2 t^{\frac{3}{2}}\right]_0^3\right]^{\frac{5}{2}}\right] \\\\\end{aligned}$$\)
\(& =\left[\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}\right]-\left[\frac{4(0)^{\frac{5}{2}}}{5}-2(0)^{\frac{3}{2}}\right]\)
\($\begin{aligned}& =\left[\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}\right]-\left[\frac{4(0)^{\frac{5}{2}}}{5}-2(0)^{\frac{3}{2}}\right] \\& =\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}-0 \\& =\frac{6 \sqrt{3}}{5}\end{aligned}\)
Therefore, the area of the curve is \(\frac{6 \sqrt{3}}{5}\).
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Which is the quotient of 1.54 + 0.44 ?
O A. 0.35
0
B. 0.36
O C. 3.5
O D. 3.6
Help meee
Answer
1.98
Step-by-step explanation:
1.54 + 0.44 = 1.98
hope it helps.
Hello I need help../ Why was madame cj walker was proud of her daughter?
I need help
plzzz
URGENT DUE IN 10 MINS Suppose that the function f(x) = 5.32 + 0.80x represents the cost of mailing an object that weighs x pounds. How much would it cost mail an object that weighs 36 pounds?
Answer:
$34.12
Step-by-step explanation:
substitute 36 into the equation where x is and simplify
Solve the system by substitution. 5x+2y=5 y=(-2x+3
Answer:
(x, y) = (-1, 5)
Step-by-step explanation:
You want to solve this system of equations by substitution.
5x +2y = 5y = -2x +3SubstitutionThe idea of substitution means we want to replace an expression in one equation for an equivalent expression based on the other equation.
Here, the second equation gives an expression equivalent to "y", so we can use that expression in place of y in the first equation:
5x +2(-2x +3) = 5 . . . . . . . . (-2x+3) substitutes for y
x +6 = 5 . . . . . . . . . . simplify
x = -1 . . . . . . . . . subtract 6
y = -2(-1) +3 = 5 . . . . . use the second equation to find y
The solution is (x, y) = (-1, 5).
__
Additional comment
Choosing substitution as the solution method often works well if one of the equations gives an expression for one of the variables, or if it can be solved easily for one of the variables. The "y=" equation is a good candidate for providing an expression that can be substituted for y.
Any equation that has one of the variables with a coefficient of +1 or -1 is also a good candidate for providing a substitution expression.
4x -y = 3 ⇒ y = 4x -3 . . . . . for example
The attached graph confirms the solution above.
PLS HELP WILL GIVE BRAINLIEST IF CORRECT
Answer:
4-1
Step-by-step explanation:
Answer:
4/1
MARK ME BRAINLIEST PLEASE
Here is a rectangle with length 5 units and width 2 units.
1. What is the area of the rectangle?
2. Dilate rectangle ABCD from point A by a scale factor of 2. Calculate the area of the image.
3. Dilate rectangle ABCD from point A by a scale factor of 3. Calculate the area of the image.
This refers to the ratio between the scale of a given original object and a new object. It is its representation but of a different size (bigger or smaller). For example, if we have a rectangle of sides 2 cm and 4 cm, we can enlarge it by multiplying each side by a number, say 2.
Solving for the area and scale factor we have:
L= 5 units
W = 2 units
The area of the rectangle =L * WA = (5 x 2)
A = 10 square units.
If the rectangle is dilated from point A by a scale factor of 2, the area of the image:A= (Scale factor of L * W)* L * W
= (2 x 2 x 5 x 2)
A = 40 square units.
If the rectangle is dilated from point A by a scale factor of 3, the area of the image is:A= (Scale factor of L * W)* L * W
= (3 x 3 x 5 x 2)
A= 90 square units
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PLEASE HELP ME IS FOR TOMMOROW
Answer:
65°
Step-by-step explanation:
The missing angle is x°
tan x° = \(\frac{opposite }{adjacent}\)
tan x° = \(\frac{850}{400\\}\)
tan x° = 2.125
Using a calculator insert
tan^(-1)(2.125) ≈ 65° (after rouding the the nearest unit)
A utility company charges $25 for basic
service plus $1 for every 100 kilowatts
of electricity used.
What would be the cost of service if you
used 400 kilowatts of electricity?
The graph shows the bacteria population on a petri dish as a function f the days d since an antibiotic is introduced.
What is the approximate value of f(3.5)?
Approximately what is d when f(d) = 500,000?
Does anyone have answers 3 and 4 for 4. 4. 3 Practice: Modeling: Solids?
Extremely lost and help with be appreciated :)
Answer:
search them up it should give you the answers
Step-by-step explanation:
A local coupon mailer charges $11 for each of the first three lines of an ad, and $5 for each additional line. What is the price of a 5-line ad?
Answer:
$43
Step-by-step explanation:
There are 5 lines in the ad in total.
It costs $11 for each of the first three lines which gives us:
3 x 11 = $33
There are now 2 lines left. Each additional line apart from the first three costs $5 extra. This gives us:
2 x 5 = $10
If we add the original $33 with the extra $10, we get a grand total of $43.
In a recent tennis tournament, women playing singles matches used challenges on 135 calls made by the line judges. Among those challenges, 36 were found to be successful with the call overturned.
a. Construct a 95% confidence interval for the percentage of successful challenges.
b. Compare the results from part (a) to this 95% confidence interval for the percentage of successful challenges made by the men playing singles matches: 23.6%
a) The 95% confidence interval is 18.95% to 34.49%. b) The confidence interval for women (18.95% to 34.49%) does not include the value of 23.6%.
To construct a 95% confidence interval for the percentage of successful challenges made by women playing singles matches, we can use the formula for the confidence interval for a proportion. The formula is:
Confidence Interval = p ± Z * \(\sqrt{p(1-p)/n}\)
Where:
p is the sample proportion (successful challenges / total challenges)
Z is the z-score corresponding to the desired confidence level
n is the sample size
a. Let's calculate the confidence interval for the percentage of successful challenges made by women:
Sample size (n) = 135
Number of successful challenges (x) = 36
Sample proportion (p) = x/n
p = 36/135 ≈ 0.2667
To find the z-score corresponding to a 95% confidence level, we need to calculate the critical value. Since the sample size is large enough (n > 30), we can approximate the critical value using the standard normal distribution.
The z-score corresponding to a 95% confidence level (two-tailed test) is approximately 1.96.
Confidence Interval = 0.2667 ± 1.96 * \(\sqrt{0.2667(1-0.2667)/135}\)
Calculating the confidence interval:
Confidence Interval = 0.2667 ± 1.96 * \(\sqrt{0.2667*0.7333/135}\)
= 0.2667 ± 1.96 * \(\sqrt{0.19511/135}\)
= 0.2667 ± 1.96 * 0.03943
≈ 0.2667 ± 0.07723
The lower bound of the confidence interval is:
0.2667 - 0.07723 ≈ 0.1895
The upper bound of the confidence interval is:
0.2667 + 0.07723 ≈ 0.3449
Therefore, the 95% confidence interval for the percentage of successful challenges made by women is approximately 18.95% to 34.49%.
b. To compare the results with the 95% confidence interval for the percentage of successful challenges made by men (23.6%), we can observe that the confidence interval for women does not overlap with the value for men.
The confidence interval for women (18.95% to 34.49%) does not include the value of 23.6%. This suggests that there may be a significant difference in the percentage of successful challenges made by women compared to men.
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