State 'True' or 'False'. Rewrite the false statements correctly.

1.The body at terminal velocity will have less weight than the drag force.

2.The line of gravity is always within the base of support of the body in stable equilibrium

3.The force that accelerates a falling body is the force of friction. ​

a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.

(c) The position of the object at 5.0 seconds is 0.5 m.

(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is calculated as;

average velocity = total displacement / total time

average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s

(c) The position of the object at 5.0 seconds is calculated as follows;

at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.

(d) The motion of the object between 30 and 40 seconds is calculated as;

velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s

Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

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The behaviour that has just been displayed by the girl is an example of a learned behavior.

The term learned behaviour has to do with those behaviour that the individual acquires by practise and are not innate in the organism. The ability to drink a large amount of water without breathing is not inate in man.

Hence, the behaviour that has just been displayed by the girl is an example of a learned behavior.

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According to Kepler's first law of planetary motion, planets revolve around the sun such that the sun is always at one of its foci. This law is also known as the law of orbits.

According to Kepler's Second Law of planetary motion, a planet will cover equal amounts of area in an equal period of time if a line is drawn from the sun to the planet. This implies that the planet moves more slowly away from the sun and faster towards it.

According to Kepler's third Law of Planetary Motion, the squares of the orbital periods of the planets are directly proportional to the cubes of their semi-major axes.

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A spiral spring is compressed by 0.5 cm. The energy stored in the spring can be calculated using the formula \(E=1/2*k*x^2\). Given that the force constant is 200 N/m, we can calculate the energy stored in the spring to be 0.00025 J.

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B

Explanation:

I not sure try to solve I am sorry

The moment of inertia of the cylinder about the horizontal axis parallel and tangent to the cylinder is 3MR²/2.

The moment of inertia (Icm) of the cylinder about its symmetrical axis is calculated using the formula MR^2/2, where M represents the mass of the cylinder and R represents its radius.

To find the moment of inertia of the cylinder about the axis parallel and tangent to the cylinder, we can use the parallel axis theorem. According to the parallel axis theorem, the moment of inertia about an axis parallel to and at a distance 'd' from the axis passing through the center of mass is given by:

I = Icm + Md^2

In this case, the axis of rotation is parallel and tangent to the cylinder, so the distance 'd' from the axis passing through the center of mass is equal to the radius 'R'. Substituting the values into the equation:

I = Icm + MR^2

I = MR^2/2 + MR^2

I = (1/2 + 1)MR^2

I = (3/2)MR^2

Therefore, the moment of inertia of the cylinder about the given axis is (3/2)MR^2.

The correct answer is (D) 3MR^2/2.

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The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?

Answer:

The answer is "4".

Explanation:

The luminaire would be recessed inside a wall, so that, dependent on the surface mountings, its top-level is flush with the ceiling. It is the hanging under the primary structural, in which the drop was an area of the above falling ceiling, that referred to its full space, because it will be generally used for the HVAC air return and the total space is also used to obfuscate piping, cabling, and ducts, that's why the middle-to-middle spacing of curved lighting systems would have to be in incremental increases of 4 ft.

Minimum kinetic energy needed to escape is calculated as:(5) Kmin = (1/2)m g R.

The form of energy that it possesses due to its motion is referred as kinetic energy.

As U = -GMm/R

G is gravitational constant, M is mass of the Earth, m is mass of molecule, and R is radius of the Earth.

Kinetic energy of the molecule is given by: K = (1/2)mv²

v is velocity of molecule.

At the surface of the Earth, velocity of the molecule needed to escape  Earth's gravitation is given by: v = √(2GM/R)

Kmin = (1/2)mv² = (1/2)m(2GM/R) = GMm/R

So, minimum kinetic energy needed to escape in terms of mass of molecule m, free-fall acceleration at surface g and radius of Earth R is calculated as: Kmin = GMm/R = (6.6743 × 10⁻¹¹ m³/kg/s²)(M/R)(m) = (9.81 m/s²)(R)(m)

Answer is (5) Kmin = (1/2)m g R.

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The three workers that use technologies that apply the Doppler effect are;

The term Doppler effect has to do with an increase or decrease in the frequency of sound as the observer moves towards or away from the source of the sound.

We know that;

fo = (v + vo/v + vs) fs

fo = frequency of the observer

v = velocity of sound

vs = velocity of source of sound

vo = velocity of observer

fs = true velocity of sound

The three workers that use technologies that apply the Doppler effect are;

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Answer:

always accelerating

Explanation:

Answer:

B. Always accelerating

Explanation:

I recently did a review with an identical flashcard!

Answer:

Point A

Explanation:

Because it reaches maximum height

Answer:

B) 4 m/s²

Explanation:

\( \boxed{ \sf{ F= m \times a}}\)

Here,

Substituting the respective values for F and m:

==> 220 = 55 × a

==> 220 = 55 × a

dividing the equation by 55:

==> 4 = a

Therefore, an object of 55 kg when pulled across a frictionless surface by a force of 220 N accelerates at 4 (m/s)/s

The problem of determining the minimum spacing between two objects on the Earth's surface that can be resolved by a spy satellite's telescope involves the field of optical astronomy. The question asks us to calculate the telescope's resolution, which is the smallest distance between two objects that can be distinguished as separate by the telescope.To solve this problem, we can use the diffraction limit, which is a fundamental limit on the resolution of any optical system. The diffraction limit is determined by the diameter of the telescope's mirror, as well as the wavelength of the light being observed. The smaller the diameter of the mirror and the shorter the wavelength of the light, the better the resolution of the telescope.Using the given diameter of the mirror and the wavelength of the light being observed, we can calculate the telescope's diffraction limit and thus determine the minimum spacing between two objects that can be resolved by the telescope.Overall, this problem demonstrates the application of optical astronomy principles to solve a real-world problem involving the resolution of a satellite telescope. By understanding the fundamental limits of optical systems, we can design and optimize telescopes for a wide range of applications in astronomy, remote sensing, and other fields.

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The minimum spacing between two objects on the Earth's surface that can be resolved as distinct objects by this telescope is approximately 21.4 meters.

The minimum resolvable angle of the telescope is given by the Rayleigh criterion, which states that two objects can be resolved if the peak of the diffraction pattern of one object falls on the first minimum of the diffraction pattern of the other object. The angular size of the first minimum is given by:

θ = 1.22 λ / D

where θ is the angle, λ is the wavelength of light, and D is the diameter of the telescope's mirror.

At a height of 240 km, the satellite is in a circular orbit with a radius of:

r = R + h

where R is the radius of the Earth (6371 km) and h is the height of the orbit (240 km). Thus,

r = 6611 km

The angular size of an object on the surface of the Earth can be calculated using:

θ = s / r

where s is the size of the object. To resolve two objects as distinct, their angular separation must be greater than or equal to the minimum resolvable angle, so we have:

θ ≥ 1.22 λ / D

Combining the above equations, we get:

s / r ≥ 1.22 λ / D

Solving for s, we get:

s ≥ 1.22 λ r / D

Plugging in the given values, we get:

s ≥ 1.22 × 500 nm × 6611 km / 1.9 m

s ≥ 21.4 meters

Therefore, the minimum spacing between two objects on the Earth's surface that can be resolved as distinct objects by this telescope is approximately 21.4 meters.

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The collapse depth of a submarine is the depth at which the surrounding water pressure becomes great enough to cause the submarine's hull to collapse. At this depth, the pressure is sufficient to cause the submarine's material to reach its crush strength.

Given that the collapse depth of modern submarines is around a kilometer, and assuming seawater to be incompressible, the crush depth pressure can be calculated as follows:

Pressure = density of seawater * depth * gravitational acceleration

Density of seawater = 1025 kg/m^3

Gravitational acceleration = 9.8 m/s^2

Crush depth = 1000 m

So the pressure at crush depth would be:

Pressure = 1025 kg/m^3 * 1000 m * 9.8 m/s^2 = 10,250,000 N/m^2 = 10.25 MPa

The pressure you computed is an absolute pressure. It is the force per unit area exerted by the water on the submarine's hull. It is measured relative to a perfect vacuum and it is independent of any other external pressure.

The amount of water displaced by a liter-sized block of ordinary wood floating in water is less than 1L of water.

Buoyant force is the net upward force on any object in any fluid. If the buoyant force is greater than the object's weight, the object will rise to the surface and float. If the buoyant force is less than the object's weight, the object will sink. The block is made up of wood and has density less than water and has pores in it n which air is placed and the density of air is less than that of water. Hence the wooden block floats over water and unable to displace water more than or equal to its mass because of buoyant force acting on it. Hence, the amount of water displaced by a liter-sized block of ordinary wood floating in water is less than 1L of water.

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1. Force  necessary to stretch an ideal spring with a spring constant of 125 N/m by 35 cm is 437.5 N.

2. The mass of a fish that would stretch the spring by 7.55 cm from its normal length is 5.10 kg.

3. Spring constant is 267.94 N/m.

4. Spring constant is 285.71 N/m.

5. Distance will be 0.115 m.

6. Distance will be 1.986 m.

7. Spring constant is calculated to be 183.38 N/m.

8. Original length becomes 80 cm.

9. Distance covers to be 0.1924 m.

10. Equivalent spring constant becomes 150 N/m

1. The force necessary to stretch the spring can be calculated using Hooke's law, which states that F = kx, where F is the force applied, k is the spring constant, and x is the displacement from the equilibrium position.

Thus, F = kx

F = (125 N/m)(0.35 m)

F = 43.75 N.

2. Using Hooke's law again, we have

F = kx

F = (650 N/m)(0.0755 m)

F = 49.98 N.

This force is equal to the weight of the fish, so we can find its mass by dividing by the acceleration due to gravity:

m = F/g

m = 5.10 kg.

3. We can use Hooke's law once more to find the spring constant:

k = F/x

k = (43 kg)(9.81 m/s²)/(0.16 m)

k = 267.94 N/m.

4. Hooke's law gives us k = F/x

k = (80 N)/(0.28 m)

k = 285.71 N/m.

5. We can use Hooke's law to set up a proportion: F1/x1 = F2/x2, where F1 and x1 are the initial force and displacement, and F2 and x2 are the new force and displacement. Solving for x2, we get

x2 = (F2/F1)x1

x2 = (23 N/16 N)(0.08 m)

x2 = 0.115 m.

6. Hooke's law gives us F = kx = (36 N/cm)(0.073 m) = 2.628 N. This is the force required to stretch the spring by 1 cm, so the total displacement is

x = (7.3 kg)(9.81 m/s²)/(36 N/cm)

= 1.986 m.

7. We can use Hooke's law to set up an equation: mg = kx, where m is the mass, g is the acceleration due to gravity, and x is the displacement from the equilibrium position. Solving for k, we get

k = mg/x

k = (15 kg)(9.81 m/s²)/(0.80 m)

k = 183.38 N/m.

8. The original length of the cord is simply the length when no mass is attached, so it is 80 cm.

9. The total force on the bottom spring is the sum of the weights of the two springs and the mass, so

F = (0.58 kg)(9.81 m/s²) + (50 N/m + 100 N/m)(x), where x is the displacement of the two springs together. Using Hooke's law, we can write this as F = 19.24 N + 150 x.

Setting this equal to kx and solving for x, we get

x = F/(k1 + k2)

x = (19.24 N)/(50 N/m + 100 N/m)

x = 0.1924 m.

10. The spring constant of the system of springs is simply the sum of the individual spring constants, so

k = k1 + k2

k = 50 N/m + 100 N/m

k = 150 N/m.

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The wavelength of the standing wave pattern on the 9.0 m long string is 18.0 m.

To determine the wavelength of the standing wave pattern on the 9.0 m long string, we need to analyze the diagram carefully. In a standing wave, nodes and antinodes are formed. Nodes are the points on the string where the displacement is zero, while antinodes are the points of maximum displacement.

In the diagram, we can observe that there are two nodes formed, one at each end of the string. This implies that the string is fixed at both ends, creating a situation known as the fundamental mode or the first harmonic. In this mode, half of a wavelength is equal to the length of the string.

Therefore, the wavelength can be calculated by multiplying the length of the string by 2, since there are two halves in a full wavelength. Thus, the wavelength is 2 times the length of the string: 2 * 9.0 m = 18.0 m.

In conclusion, the wavelength of the standing wave pattern on the 9.0 m long string is 18.0 m.

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Answer:

15 μF

Explanation:

If two capacitors are in parallel, the equivalent capacitance is equal to the sum of the capacitances, so for the first two capacitors, we get:

C = 10 μF + 20 μF

C = 30 μF

Then, this capacitor C is in series with another capacitor of 30μF. For capacitor in series, we can find the equivalent as follows

Therefore, the answer is 15μF

Answer:

15 meters/second

Explanation:

When astronomers talk about the seeing conditions at a potential observatory site, they are referring to the atmospheric turbulence and how it affects the quality of images obtained from telescopes at that location.The seeing conditions can have a significant impact on the image quality as well as the scientific output of an observatory.

Turbulent air creates a blurring effect on the images which is known as atmospheric distortion. This limits the telescope’s ability to resolve fine details in the observed objects.The quality of the seeing conditions at a potential observatory site depends on various factors such as the altitude, climate, and topography.

Astronomers evaluate the seeing conditions by monitoring the atmospheric turbulence at the site. They use a device called a seeing monitor that measures the fluctuations in the air density and temperature.The seeing conditions are critical for the success of an observatory.

Astronomers prefer sites with stable atmospheric conditions, low turbulence, and dry climate. These conditions help to minimize the effects of atmospheric distortion on the images and enable astronomers to study celestial objects in greater detail.

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Thermal system is used on some electric and hybrid vehicles to cool the power electronics and charger modules.

What is thermal system?

An isolated system has no interaction with the rest of the physical universe, a closed system can only exchange heat and work, and an open system can also exchange mass. In thermodynamics, a system is the portion of the physical universe that the observer chooses to analyse separately from the rest.

A thermal system, on the other hand, is a complex assembly of coupled components, some of which are thermal, that exhibits a common structured behavior  for instance, a refrigerator consists of pipes, a compressor, an electric motor, heat exchangers, valves, insulation, a casing, doors, a lamp, and other components that interact to achieve the internal goal of producing cold.

The interior space or the refrigerant are thermodynamic systems, whereas a refrigerator is a thermal system. While large thermal systems, like a refrigerated store, are constructed on the job site, small thermal systems, like a refrigerator, typically come fully installed from the manufacturer (although a straightforward split-air-conditioning system needs installation). Thermal systems often require services such as fuel supply, flue stack, water intake and exit, air intake and exit, and electrical supply (for power or at least for control).

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Answer:

a, 4

b, 3

c, 6

d, 3

e, 3

f, 3

g, ambiguous

h,

The velocity of the projectile is 13.86 m/s (approx) to the leave the barrel of the cannon.

The mass of the rubber ball, m = 5.34 g = 0.00534 kg

The force constant of the spring, k = 8.05 N/m

The displacement of the spring, x = 5.05 cm = 0.0505 m

The distance travelled by the ball, d = 15.9 cm = 0.159 m

The force of friction acting on the ball, f = 0.0326 N

To find: The velocity of the projectile, v

The potential energy of the compressed spring is given as,

U = 1/2 k x²= 1/2 × 8.05 × 0.0505²= 0.0102 J

When the ball is fired, the potential energy of the spring is converted into the kinetic energy of the ball and the work done against the friction force.

W = U - f × d= 0.0102 - 0.0326 × 0.159= 0.00512 J

The kinetic energy of the ball is given as,

K.E = 1/2 m v²

Here, m = 0.00534 kg

Substituting the given values of kinetic energy and mass,

0.00512 = 1/2 × 0.00534 × v²

v² = 0.00512 / (0.5 × 0.00534)

v² = 191.7

v = √191.7 = 13.86 m/s (approx)

Therefore, the velocity of the projectile is 13.86 m/s (approx).

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Answer:

Setting short-term and long-term goals is very important to stay on track and motivated to improve fitness levels. You can keep track of your progress by weighing yourself every day to track weight loss, and by steadily increasing the difficulty of the exercises to track your strength improvement. It is very important to reflect on progress, so you can evaluate what you need to do in the future to remain on track, as well as seeing how much you've improved.

Answer:

this is a little late, but for the people who are just now doing the question the answer is

Explanation:

it is important to set short-term and long-term goals cause certain exercises can be dangerous if you set it as a long term goal. But an exercise such as jogging, really has no down downside if you set it as a long term goal.

The work done by gravity (\(W_g\)) and the work (\(W_t\))done by the tension in the cable for lowering a girder into place at constant speed is same in magnitude. So, \(W_g = W_t\).

The amount of force multiplied by the distance the thing travelled in the direction of the applied force is how much work is done on an object.

Work done is equal to force times distance. joule is the unit of work.

In the case of a crane lowers a girder into place at constant speed. gravitational force and tension of the cable acts in opposite direction with equal magnitude. So, the work done by gravity (\(W_g\)) and the work (\(W_t\))done by the tension in the cable for lowering a girder into place at constant speed is same in magnitude. So, \(W_g = W_t\).

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I'm going to assume that this gripping drama takes place on planet Earth, where the acceleration of gravity is 9.8 m/s².  The solutions would be completely different if the same scenario were to play out in other places.

A ball is thrown upward with a speed of 40 m/s.  Gravity decreases its upward speed (increases its downward speed) by 9.8 m/s every second.

So, the ball reaches its highest point after (40 m/s)/(9.8 m/s²) = 4.08 seconds. At that point, it runs out of upward gas, and begins falling.

Just like so many other aspects of life, the downward fall is an exact "mirror image" of the upward trip.  After another 4.08 seconds, the ball has returned to the height of the hand which flung it.  In total, the ball is in the air for 8.16 seconds up and down.