Steve is driving at 35 mi/h when he makes an emergency stop. His brakes lock and his tires leave four skid marks of equal length. The drag factor for the road surface was 0.97 and his brakes were operating at 90% efficiency. How long might the skid marks be to the nearest foot?

Answer:13cm

Step-by-step explanation:

Answer:198.447

Step-by-step explanation:

just search 7 ounces to grams

Answer:

-14/15

Step-by-step explanation:

To add or subtract fractions, they have to have the same denominator

-3 /5 =  - 9/15      - 1/3 = - 5/15

-9/15 - 5/15   =  ( - 9 -5) / 15 = -14 /15

An equation that mode the relationship between thee two variable is y=2x+3 .

Let x represent the number of 6-month period worked

Let y represent the total number of paid vacation day

According to the question,

When he started work, he was given three paid day of vacation. For each six-month period he pay at the job, his vacation is increased by two day.

Each year has 2 six-month periods. After 4.4 years Roberto will have worked 8.8 six-month periods. He will have been given vacation days for each of the 8 whole working periods he has completed. x=8 y=2*8+3 y=19

An equation that mode the relationship between thee two variable is y=2x+3 (Total vacation time equals 2 days times x plus the 3 days he was given at the start).

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Answer:

see explanation

Step-by-step explanation:

the sum of the 3 angles in a triangle = 180°

sum the 3 angles and equate to 180

4x + 21 + x - 10 + 2x + 8 = 180

7x + 19 = 180 ( subtract 19 from both sides )

7x = 161 ( divide both sides by 7 )

x = 23

Then angles in triangle are

4x + 21 = 4(23) + 21 = 92 + 21 = 113°

x - 10 = 23 - 10 = 13°

7x + 8 = 7(23) + 8 = 161 + 8 = 169°

the only 2 possible angle measures are A and E

Luke's weight loss over the 3 weeks: 6 pounds + 4 pounds + (13/4)x - (1/2)

Liam's weight loss over the 3 weeks: (9/4)x - (9/2) + (21/4)x - (9/2) + 2 pounds

Luke's weight loss over the 3 weeks can be calculated by adding up the individual amounts he lost each week.

In the first week, he lost x pounds. In the second week, he lost pounds less than times the pounds he lost in the first week, which can be expressed as 4 pounds less than 9/4 times x, or (9/4)x - 4 pounds. In the third week, he lost 1 pound more than of the pounds he lost in the first week, which can be written as 1/2 times x plus 1 pound, or (1/2)x + 1 pound.

Adding these three amounts together, we get Luke's weight loss over the 3 weeks as 6 pounds + 4 pounds + (13/4)x - (1/2) pounds.

Similarly, Liam's weight loss over the 3 weeks can be calculated. In the first week, he lost 1 pound less than times the pounds Luke lost in the first week, which is expressed as (9/4)x - 1 pound.

In the second week, he lost 4 pounds less than times the pounds Luke lost in the first week, which is (21/4)x - 4 pounds. In the third week, he lost pound more than times the pounds Luke lost in the first week, or (1/2)x + 2 pounds.

Adding these amounts together, we get Liam's weight loss over the 3 weeks as (9/4)x - 1 pound + (21/4)x - 4 pounds + (1/2)x + 2 pounds.

The number of pounds Luke lost in the first week is simply x.

The number of pounds Luke and Liam each lost over the three weeks is the same, and it can be represented by the expression 6 pounds + 4 pounds + (13/4)x - (1/2) pounds, which is equal to (9/4)x - (9/2) + (21/4)x - (9/2) + 2 pounds.

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Answer:

Area = length x width

21 = (2w-1)w

21 = 2w^2 -w

2W^2 - w -21=0

(2w-7 )(W +3)=0

2W-7=0 or w+3=0

W=7/2 or w=-3

Width cannot be negative.

So width is 7/2=3.5

Then the length is 6

Step-by-step explanation:

It is not a scalene triangle

because the third angle is 69⁰

Explanation: 180-(69+42)

180-111

69

Answer: Yes.

Step-by-step explanation:

600 x 0.41 or 41% = 246, which yes is different from 0.41.

The solution for y in the expression is y = -53 and y = 63

From the question, the expression is given as

y = 5 ± 58

We start by expanding the expression

So, we have the following representation

y = 5 - 58 and y = 5 + 58

Evaluate the sum and the difference of the like terms in the above expression

So, we have the following representation

y = -53 and y = 63

Hence, the solution is

y = -53 and y = 63

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Answer:

B

Step-by-step explanation:

if its less than 1 it shrinks

The correct statement is; Pentagon M’N’P’Q’R is smaller than pentagon MNPQR because the scale factor is smaller than 1.

The ratio between comparable measurements of an item and a representation of that thing is known as a scale factor in arithmetic.

If a polygon is dilated by a scale factor = k

Rule to be followed as;

(x, y) → (kx, ky)

Here, k = Scale factor

If 0 < k < 1, size of the image will be reduced.

Similarly, k > 1, size of the image will be enlarged.

We are given that Pentagon MNPQR is dilated with the origin as the center of dilation to form an image M'N'P'Q'R'.

Rule used for the transformation,

(x, y) → (1/4x, 1/4y)

Here, the scale factor through which MNPQR has been dilated is 1/4.

Since, scale factor is between zero and 1/4, size of M'N'P'Q'R' will be reduced.

Therefore, the size of pentagon M'N'P'Q'R' will be 1/4 smaller than pentagon MNPQR.

Option (2) is the answer.

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Answer: first lowest: 1/3           second lowest:2/6

Step-by-step explanation:

3x-y=2....(i)

2x-y=3.....(ii)

now adding the eqn I and ii ,

3x-y=2

2x-y=3

+ + +

5x=5

x=1

Now substituting the value of x in eqn I

3×1-y=2

3-y=2

-y=-1

y=1

Answer:

14 blocks

Step-by-step explanation:

next time plz add a grid :(

The X-axis (horizontal axis) often represents a "class boundaries" of such an ogive, whereas the Y-axis (vertical axis) typically shows the frequency count.

A sort of frequency polygon that displays cumulative frequencies is an ogive, often known as a cumulative frequency polygon.

Thus, The X-axis (horizontal axis) often represents a class boundaries being measured of such an ogive.

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The probability for a data point is less than is 0.8413.

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

The mean(μ)=4

Standard deviation(σ)=1

(P<5)

From the figure, standard normal distribution curve probability which we have to find P<5

It is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

P(x=4)=x-μ/σ

=4-4/1=0

P(x=4)=50%

P(x<5)=P(x=4)+P(x=1)

=50%+34.13%

=0.8413

P(x<5)=0.8413

Therefore, the probability a data point is less than 5 is 0.8413.

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The speed of Ted is 08 mph  and the speed of Frank is 12 mph.

Given:

Ted runs 2/3 as fast as frank. In 2 hours frank runs 8 miles farther than ted.

Ted Data:

Distance = d;

Rate = (2/3)x;

Time = 2 hours

Candid Data:

Distance = d+8;

Rate = x;

Time = 2 hours

Formula: Distance = Speed*Time

Therefore,

Flank distance = ted distance + 8

2x = (4/3)x + 8

6x = 4x + 24

2x = 24

x = 12 mph

The speed of Flank is 12 mph.

Therefore, the speed of Ted is:

(2/3)x = 8 mph

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Step-by-step explanation:

Lidal : 9 rolls for £3.51

1 roll for 3.51/9 = £0.39

Oldi : 4 rolls for £1.52

1 roll for 1.52/4 = £0.38

so, Oldi has the best value for money when buying toilet rolls.

The solution to the system of equations is x = 3/2 and y = 6

The system of equations is given as:

1/2x = 3/4 and y = 6

The variables x and y in each of the above equations are independent

This is so because they only occur in one equation at a time

So, we have:

1/2x = 3/4

Multiply both sides by 2

x = 3/2

Hence, the solution to the system of equations is x = 3/2 and y = 6

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The formula for a complex formed between \(Cu^{2+}\) and oxalate \((C_2O_4^{2-})\)with a coordination number of 4 can be represented as follows: \([Cu(C_2O_4)2]^{2-}\)

In this complex, \(Cu^{2+}\)serves as the central metal ion, and it is coordinated to two oxalate ligands. The oxalate ligand, \(C_2O_4^{2-}\) consists of two carbon atoms and four oxygen atoms. Each oxalate ligand donates two oxygen atoms to the central copper ion. The coordination number of 4 indicates that there are four donor atoms involved in the complex formation.

The square brackets represent the complex ion, and the overall charge outside the brackets is 2-, indicating the charge of the complex. The formula \([Cu(C_2O_4)2]^{2-}\) succinctly represents the complex formed between \(Cu^{2+}\) and oxalate with a coordination number of 4, highlighting the number of donor atoms and the charge of the complex.

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Answer: 235

Step-by-step explanation: Just easy

Answer:

33 kids n 94 kids

Step-by-step explanation:

We are asked to prove the inequality L(f, S) ≤ L(f, P) ≤ U(f, P) ≤ U(f, S) for a bounded function f on an interval [a, b], where S and P are partitions of the interval.

To prove the inequality, we start by considering the lower sums. The lower sum L(f, S) is defined as the sum of the infimum values of f over each subinterval of the partition S. Since the partition P is a refinement of S, each subinterval of S is contained within a subinterval of P. Therefore, the infimum value of f over each subinterval in S will be less than or equal to the infimum value over the corresponding subinterval in P. This implies that L(f, S) ≤ L(f, P).

Next, we consider the upper sums. The upper sum U(f, S) is defined as the sum of the supremum values of f over each subinterval of the partition S. Again, since P is a refinement of S, each subinterval in S is contained within a subinterval in P. Thus, the supremum value of f over each subinterval in S will be greater than or equal to the supremum value over the corresponding subinterval in P. Therefore, U(f, S) ≥ U(f, P).

Combining the results, we have L(f, S) ≤ L(f, P) and U(f, P) ≤ U(f, S). This establishes the desired inequality L(f, S) ≤ L(f, P) ≤ U(f, P) ≤ U(f, S), proving the statement.

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Answer:

F type connector

Step-by-step explanation:

Use an F-type connector for broadband cable connections that use coaxial cable.

The F connector is a coaxial RF connector commonly used for "over the air" terrestrial television, cable television and universally for satellite television and cable modems,

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F type connector

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Answer:

35.92 m

Step-by-step explanation:

To have a better comprehension of the problem, we can draw it as in the image attached.

If we use the tangent relation in both triangles, we have:

tangent(35) = h/x

tangent(20) = h/(150-x)

From the first equation, we have:

x = h/tangent(35) = h/0.7

From the second equation, we have:

0.364 = h / (150 - h/0.7)

54.6 - 0.52h = h

1.52h = 54.6

h = 35.92 m

Answer:

x = 5

y = 34

Step-by-step explanation:

Sub y = 8x - 6 into second equation (y = 5x + 9)

8x - 6 = 5x + 9

Rearrange by collecting like terms

8x - 5x = 9 + 6

3x = 15

x = 5

Sub x = 5 into first equation (y = 8x - 6)  

y = (8*5) - 6

y = 40 - 6

y = 34

The remaining mass of the element after 19 minutes is approximately 110.7 grams, rounded to the nearest tenth of a gram.

The mass of the element is decreasing at a rate of 8.9% per minute. Let's call the remaining mass of the element after 19 minutes "x". Then, the mass of the element after 1 minute would be 0.911 times x, since 8.9% of the mass disintegrates per minute.

After 2 minutes, the mass would be 0.911 times 0.911 times x, or 0.911² times x. In general, after t minutes, the mass would be:

x = 310 × \(0.911^t\)

To find the remaining mass after 19 minutes, we plug in t = 19:

x = 310 × 0.911¹⁹ ≈ 110.7

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According to the question, there is approximately a 1.15% chance that none of the components meet specifications, a 14.69% chance that exactly one component meets specifications, a 48.77% chance that exactly two components meet specifications, and an 86.30% chance that all three components meet specifications.

We have three independent mechanical components with the following probabilities of meeting specifications: \(\(P(X_1) = 0.94\)\), \(\(P(X_2) = 0.96\)\), and \(\(P(X_3) = 0.98\)\), where \(\(X_i\)\) represents the event that the \(\(i\)th\) component meets specifications.

Let \(\(X\)\) be the number of components that meet specifications. \(\(X\)\) can take on the values 0, 1, 2, or 3, representing the number of components that meet specifications out of the three.

To determine the probability mass function (PMF) of \(\(X\)\), we need to calculate the probability \(\(P(X = k)\)\) for each possible value of \(\(k\)\).

When \(\(X = 0\)\), it means none of the components meet specifications. Since the components are independent, the probability of all three components failing to meet specifications is \(\(P(X_1') \times P(X_2') \times P(X_3')\)\). Thus, \(\(P(X = 0) = (1 - 0.94) \times (1 - 0.96) \times (1 - 0.98)\)\).

\(Similarly, when \(X = 1\), we have three cases: one component meets specifications while the other two fail. So, \(P(X = 1) = P(X_1) \times (1 - P(X_2)) \times (1 - P(X_3)) + (1 - P(X_1)) \times P(X_2) \times (1 - P(X_3)) + (1 - P(X_1)) \times (1 - P(X_2)) \times P(X_3)\).\)

\(For \(X = 2\) and \(X = 3\), we have similar calculations: \(P(X = 2) = P(X_1) \times P(X_2) \times (1 - P(X_3)) + P(X_1) \times (1 - P(X_2)) \times P(X_3) + (1 - P(X_1)) \times P(X_2) \times P(X_3)\) and \(P(X = 3) = P(X_1) \times P(X_2) \times P(X_3)\).\)

Therefore, the probability mass function of \(\(X\)\) can be summarized as:

\(\[ P(X = k) = (1 - 0.94) \times (1 - 0.96) \times (1 - 0.98) & \text{if } k = 0 \\\\= P(X_1) \times (1 - P(X_2)) \times (1 - P(X_3)) + (1 - P(X_1)) \times P(X_2) \times (1 - P(X_3)) + (1 - P(X_1)) \times (1 - P(X_2)) \times P(X_3) & \text{if } k = 1 \\\)

\(=P(X_1) \times P(X_2) \times (1 - P(X_3)) + P(X_1) \times (1 - P(X_2)) \times P(X_3) + (1 - P(X_1)) \times P(X_2) \times P(X_3) & \text{if } k = 2 \\\\=P(X_1) \times P(X_2) \times P(X_3) & \text{if } k = 3 \\\\& \text{otherwise}\end{cases}\]\)

Let's calculate the probabilities for each value of \(\(X\)\) using the given probabilities:

\(\(P(X = 0) = (1 - 0.94) \times (1 - 0.96) \times (1 - 0.98) \\\\\approx 0.01152\)\)

\(\(P(X = 1) = (0.94 \times (1 - 0.96) \times (1 - 0.98)) + ((1 - 0.94) \times 0.96 \times (1 - 0.98)) + ((1 - 0.94) \times (1 - 0.96) \times 0.98) \\\\\approx 0.14688\)\)

\(\(P(X = 2) = (0.94 \times 0.96 \times (1 - 0.98)) + (0.94 \times (1 - 0.96) \times 0.98) + ((1 - 0.94) \times 0.96 \times 0.98) \\\\\approx 0.48768\)\)

\(\(P(X = 3) = 0.94 \times 0.96 \times 0.98 \\\\\approx 0.86304\)\)

Therefore, the probability mass function of \(\(X\)\) is:

\(\[P(X = k) = \begin{cases} 0.01152 & \text{if } k = 0 \\0.14688 & \text{if } k = 1 \\0.48768 & \text{if } k = 2 \\0.86304 & \text{if } k = 3 \\0 & \text{otherwise}\end{cases}\]\)

This means that there is approximately a 1.15% chance that none of the components meet specifications, a 14.69% chance that exactly one component meets specifications, a 48.77% chance that exactly two components meet specifications, and an 86.30% chance that all three components meet specifications.

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