stopwords have both high term-frequency and low inverse-document frequency group of answer choices true false

The required work against gravity to construct a solid rectangular box with a height of 4m and square base with side lengths of 2m using lightweight material whose density is 700 kg/m³ can be determined through the following method:

work against gravity is 5.6 × 10³ J Formula: The weight of the object = m × g, where m = mass of the object and g = acceleration due to gravity.W = F × d, where W = work done, F = force applied, and d = distance traveled.A solid rectangular box has a height of 4m and a square base of 2m. Therefore, the volume of the box is V = 2m × 2m × 4m = 16 m³Given the density of the lightweight material is 700 kg/m³, then the mass of the box is:mass = density × volume = 700 kg/m³ × 16 m³ = 11200 kg

The weight of the box is:Weight = m × g = 11200 kg × 9.8 m/s² = 109760 NTo lift the box, a force equal to the weight of the box must be applied over a distance equal to the height of the box. Therefore, the work done is given by:W = F × d = Weight × height = 109760 N × 4 m = 439040 JHowever, the box is made of a lightweight material, therefore, the required work against gravity is less.

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Answer:

I think the answer is Decreases the time that the egg slows down.

Explanation:

If not try it starts slowing down

O Increases the time that the egg slows down.

Answer:

0.16 Hz

Explanation:

frequency = speed/wavelength

= 20/125 = 0.16 Hz

Answer:

An object is considered to be accelerating if the object is changing its rate in speed, decreases in speed, or changes the object's direction

Permissive parenting is characterized by low expectations and high responsiveness. Permissive parenting characteristic that lends itself to wanting to be more of a friend than a parent.

Permissive parenting is characterized by low expectations and high responsiveness. Permissive parents are usually very caring, but they don't have a lot of restrictions or boundaries.

Permissive parents are exceedingly loose and rarely develop or enforce any form of rules or structure, instead of handing over their children's every move.

Hence Permissive parenting characteristic lends itself to wanting to be more of a friend than a parent.

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Answer:

Explanation:

Permissive parenting is characterized by low expectations and high responsiveness. Permissive parenting characteristic that lends itself to wanting to be more of a friend than a parent.

What is permissive parenting?

Permissive parenting is characterized by low expectations and high responsiveness. Permissive parents are usually very caring, but they don't have a lot of restrictions or boundaries.

Permissive parents are exceedingly loose and rarely develop or enforce any form of rules or structure, instead of handing over their children's every move.

Hence Permissive parenting characteristic lends itself to wanting to be more of a friend than a parent.

At resonance, the reactance of the inductor (XL) and the capacitor (XC) in the RLC circuit are equal in magnitude and opposite in sign. Therefore, the total impedance of the circuit is equal to the resistance (R) only. Mathematically, this can be represented as:

Z = R + j(XL - XC)

At resonance, XL = -XC, so the imaginary part of the impedance cancels out, leaving only the real part (resistance) as the impedance of the circuit. Therefore, the correct answer is (c) R. At resonance, the circuit behaves purely resistive and the impedance is at its minimum value, making it easier to transfer power to the circuit.

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An atom with great electronegativity is able to attract electrons towards itself in a chemical bond. This means that it is able to form strong covalent bonds with other atoms, and can also participate in ionic bonding by attracting electrons away from other atoms.

Additionally, an atom with high electronegativity is able to exert a greater degree of control over the distribution of charge within a molecule, making it an important factor in determining the overall reactivity and behavior of the molecule.

Electronegativity is a measure of an atom's ability to attract electrons towards itself when it is part of a chemical bond. In other words, it is a measure of an atom's ability to pull electrons away from other atoms in a molecule. Electronegativity is an important concept in chemistry, as it helps predict how atoms will behave in chemical reactions.

Electronegativity is typically measured on a scale called the Pauling scale, named after the American chemist Linus Pauling. The scale ranges from 0.7 (for the least electronegative element, francium) to 4.0 (for the most electronegative element, fluorine). Elements towards the right side of the periodic table, such as the halogens and oxygen, are generally more electronegative than elements towards the left side, such as the alkali metals.

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Answer:

False.

Explanation:

A forearm pass is a volleyball movement that involves hitting off the forearms in an underhand manner. To create a forearm stance you'd have to clasp your palm together in an overlapping manner and keep them outstretched away from your torso.

Skilled players are more when to use the wrists, the hands, or the forearms as they wield different strengths in passing the ball and are meant to be used at different scenarios.

The forearm pass is best used when you want to position the ball near the net so the setter can set it.

Cheers

The testes are the primary male reproductive organs responsible for producing testosterone.

Vas Deferens: Also known as the ductus deferens, it is a muscular tube that carries mature sperm from the epididymis to the ejaculatory ducts.

Seminal Vesicles: These glands produce a fluid rich in fructose and other nutrients, which helps nourish and provide energy to the sperm.

Prostate Gland: It is a walnut-sized gland that produces a milky fluid containing enzymes, proteins, and other substances that contribute to se men formation.

Cowper's Glands: These small glands secrete a clear, alkaline fluid that lubricates the urethra and neutralizes any acidic urine remnants, creating a favorable environment for sperm.

Urethra: This is a tube that runs  serves as a passage for both urine and semen, though not at the same time.

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Answers:

(a) a = -90 m/s² or 9.18g

(b) t = 0.00667 s

(c) a = -40 m/s² or 4.08g

Explanation:

When the acceleration is constant, we can use the following equation:

Where x is the distance, v0 is the initial velocity, vf is the final velocity and t is the time. So, replacing x by 2 mm (0.002 m), v0 by 0.6 m/s, and vf by 0 m/s, we can solve for t as:

Therefore, the stopping time is 0.00667 s.

With this time we can calculate the acceleration using the following equation:

Then, to know the acceleration as a multiple of g, we need to divide 90 m/s² by 9.8 m/s² to get:

So, 90 m/s² is equivalent to 9.18g

In the same way, we can calculate the acceleration when the distance is 4.5 mm (0.0045 m). So, the stopping time is equal to:

Then, the acceleration is equal to:

Since 40/9.8 = 4.08g, we can say that -40m/s² is equivalent to 4.08g.

Thus Kinetic energy of the object is 200J when mass is 25 kg and velocity is 4 m/s.

Answer:

A

Explanation:

Potential energy = m g h       unless h changes there is zero PE change

Answer:

showing the differences between states of matter.

Answer:

D

Explanation:

the kinetic theory of matter states that matter is made up of molecules that are in continuous motion.this in turn talks about the different states of matter

Explanation:

The object is not moving, because the distance is a constant value regardless of the time value.

Charged particles are fundamental to the behavior of electric currents, electric circuits, and resistance. An electric current is the flow of charged particles, typically electrons, through a conductor.

The flow of charged particles generates an electric field that induces a potential difference, or voltage, across the conductor.Electric circuits are constructed by connecting conductors and electrical components, such as resistors, capacitors, and inductors, in a specific configuration. The arrangement of the components determines how the current flows through the circuit.

The flow of current through the circuit depends on the resistance offered by the components in the circuit and the potential difference across the circuit.Resistance is the property of a conductor that opposes the flow of current. The resistance of a conductor is proportional to the number of charged particles in the conductor, the length of the conductor, and the cross-sectional area of the conductor. The resistance can also be affected by the temperature of the conductor and its material properties.

In summary, charged particles are responsible for generating electric currents that flow through electrical circuits. The behavior of the currents is determined by the arrangement of the components in the circuit and the resistance offered by the conductors and components. Resistance is a fundamental property of a conductor that opposes the flow of charged particles and can be affected by various factors.

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Answer:

T = 60°C

Explanation:

We are given;

Mass of water in both cases as 60g.

Thus; m1 = m2 = 60 g

Temperature of first water; T1 = 40°C

Temperature of 2nd water; T2 = 80°C

Let final temperature be T.

To solve for the final temperature, we will use the formula;

(m1 + m2)T = ((m1•T1) + (m2•T2))

(60 + 60)T = ((60 × 40) + (60 × 80))

120T = 7200

T = 7200/120

T = 60°C

The work done by the electric field on a charge is given by:

W = qΔV

where q is the charge and ΔV is the change in electric potential. The work done is the largest when the charge moves between the two points with the greatest potential difference.

Since the equipotential lines are equally spaced, the potential difference between adjacent lines is the same. Therefore, the path with the greatest potential difference will be the one that crosses the greatest number of equipotential lines.

In the given figure, we can see that path D crosses the greatest number of equipotential lines, and therefore corresponds to the largest work done on the charge by the electric field. Therefore, the answer is path D.

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\( \huge \boxed {\mathfrak{ \color{gold}Answer ࿐ }}\)

The wave having the lowest frequency is :

=》A. (a)

When considering the emf of each of the given circuits, the instantaneous value of the emf for Ea, Eb, and Ec can be expressed as:Ea= 80 V

The general formula for the instantaneous value of EMF is: E(t) = Emax × sin(ωt + φ) where: - E(t) is the instantaneous value of EMF at time t - Emax is the maximum value of EMF - ω is the angular velocity (in radians per second) - t is the time (in seconds) - φ is the phase angle (in radians)

(Since there is no other value given in the problem, we can assume that the emf is constant)Eb = 110sin(100πt)V (Since it is a sin wave, we take the maximum amplitude as the instantaneous value)Ec = 70 V (Since there is no other value given in the problem, we can assume that the emf is constant)Therefore, the instantaneous value of emf for Ea, Eb, and Ec is 80 V, 110 V, and 70 V respectively.

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From the analysis, it can be concluded that planet A has the strongest gravitational field, followed by planet C, and planets B and D have the same gravitational field strength.

The gravitational force acting on various masses is measured on different planets. The table shows the measured values for the forces acting on the corresponding masses:Planet Force (N) Mass (kg)A 8.0 0.50B 30 3.0C 45 3.0D 60 6.0

Method for comparing the gravitational field strengths on the different planets:First, we can use the formula for calculating gravitational force: \(`F = G (m_1m_2 / r^2)`\)where G is the universal gravitational constant `\(6.67 * 10^{-11 }Nm^2/kg^2\), m1 and m2 are the masses of the two objects in kg, and r is the distance between the centers of the objects in meters.

We know that the force is proportional to mass (F = ma). So we can calculate the acceleration due to gravity (g) on each planet by dividing the force by the mass. Therefore, we can use the formula: `g = F / m`.

Comparing the gravitational field strengths on the different planets:We will calculate the acceleration due to gravity (g) on each planet.

For planet A: `

g = F / m

= 8.0 N / 0.50 kg

= 16 \(m/s^2\)`

For planet B: `g = F / m

= 30 N / 3.0 kg

= 10 \(m/s^2\)

For planet C: `g = F / m

= 45 N / 3.0 kg

= 15 \(m/s^2\)

For planet D: `g = F / m

= 60 N / 6.0 kg

= 10 \(m/s^2\)

`So we see that planet A has the strongest gravitational field, followed by planet C, then planet B and planet D have the same gravitational field strength.

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Answer:

v_Object A = 3v_Object B

OR

1/3v_Object A = v_Object B

Explanation:

Let's see what variables we have in this problem.

Since the objects both start at rest, we have an initial velocity of 0 m/s.

The objects accelerate, so we will have acceleration.

Object A accelerates for 3x the time as Object B, so we have time.

The problem wants us to compare their final speeds, so we have final velocity.

Check what constant acceleration kinematic equation has these variables:

Let's create values for the unknown variables and compare the final velocities.

Since Object A accelerates for 3x the time as Object B, we can use t = 30 s for Object A.

Let's write the two equations:

Simplify these equations.

Let's use another set of values to compare the final velocities to see if the velocities differ by 100 m/s or Object A has 3x the final velocity of Object B.

Write the two equations:

Simplify these equations.

Now we can clearly see that the final velocities are differed by 3x. Object A has 3x the final speed compared to that of Object B.

Answer:

Δt=48 s

Explanation:

v: Barry's speed

v.: speed of the walkway

Δx=30 m

Δt1=30 s ,  Δt2=120 s

|Δx1|=|Δx2|

Δx=v*Δt

=> (v+v.)*30=(v-v.)*120

v=v.*5/3

30=(v+v.)*30

=> 30=(5v./3 +v.)*30

v.=3/8 m/s

v=5v./3 , v.=3/8

=> v=5/8 m/s

Δx=v*Δt

30=5/8 *Δt

Δt=48 s

Answer:

An online UPS.

Explanation:

An online UPS is a type of uninterruptible power supply uses AC power to continuously charge its battery, while also providing power to devices through the battery. It combines the inverter and rectifier to provide power to the alternating current (AC) load while supplying alternating current (AC) power during an outage to the load through the inverter.

Basically, an uninterruptible power supply unit is used to provide constant power supply to an electrical device, especially during a power outage.

Answer:

(I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)

(II). The Schwarzschild radius is 17.7 km.

(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)

(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)

Explanation:

Given that,

Mass of black hole \(m= 1\times10^{8} M_{sun}\)

(I). We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Where, G = gravitational constant

M = mass

c = speed of light

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times1\times10^{8}\times1.989\times10^{30}}{(3\times10^{8})^2}\)

\(R_{g}=2.94\times10^{8}\ km\)

(II). Mass of block hole \(m= 6 M_{sun}\)

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times6\times1.989\times10^{30}}{(3\times10^{8})^2}\)

\(R_{g}=17.7\ km\)

(III). Mass of block hole m= mass of moon

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times7.35\times10^{22}}{(3\times10^{8})^2}\)

\(R_{g}=1.1\times10^{-7}\ km\)

(IV). Mass = 50 kg

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times50}{(3\times10^{8})^2}\)

\(R_{g}=7.4\times10^{-29}\ km\)

Hence, (I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)

(II). The Schwarzschild radius is 17.7 km.

(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)

(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)

The energy conservation allows to find the Schwarschild radius for several bodies of different masses are:

  1)  Black hole quasar is:  r = 2.9 10⁸ km

  2) Blsck hole supernove is:  r = 17.7 km

  3)  Mini black hole is:   r = 1.1 10⁻⁷ km

  4) Human body is:  r=  7 10⁻²⁹ km

The schwarschild radius is defined as the distance from a black hole center at radius  which the escape velocity is equal to the light speed, in some cases it is also called the event horizon.

Let's use Newton's second law where force is the universal law of attraction and acceleration is centripetal.

        F = ma

        F = \(G \frac{Mm}{r^2}\)        

Where F is the force, M the mass of the black hole, m the handle of the body, r the radius and v the speed of the body.

The energy of the gravitational field is

        F = \(- \frac{dU}{dr }\)  

         U = \(-G \frac{Mm}{r}\)  

Let's use conservation of energy

        Em₀ = K + U = ½ m v² -  \(G \frac{Mm}{r}\)  

In infinity the energy

        Em_f = 0

energy is conserved

       Em₀ = Em_f  

       ½ m v² - \(G \frac{Mm }{r}\)  = 0

       r = \(\frac{2GM}{v^2}\)

From the definition of the Schwarschild radius this speed is equal to the light speed

        v = c

        r = \(\frac{2GM}{c^2 }\)  

They ask to calculate the radius for several cases of different mass, claculate the constant value

      V = \(\frac{2 \ 6.67 \ 10^{-11} }{(3 \ 10^8) ^2 }\)  

      V =  1.482 10⁻²⁷

1) A black hole of mass M = 1 10⁸ \(M_{sum}\)

The tabulated mass of the sun is \(M_{sum}\) = 1.989 10³⁰ kg

Let's  substitute

        r =  1.482 10⁻²⁷   1 10⁸ 1.989 10³⁰

        r = 2.94 10⁸ km

With two significant figures

        r = 2.9 10⁸ km

2) A black hole of mass M = 6 \(M_{sum}\)

        r =  1.482 10⁻²⁷ 6 1.989 10-30

        r = 17.7 km

3) a mini black hole with the mass of the moon

    Tabulated mass of the moon M = 7.35 10²² kg

       r =  1.482 10⁻²⁷  7.35 10²²    

       r = 1.1 10⁻⁷ km

4) A person of M = 50 kg

    r =  1.482 10⁻²⁷ 50

    r=  7 10-29 km

In conclusion using the conservation of energy we can find the Schwarschild radius for several bodies of different masses are:

  1)  Black hole quasar is:  r = 2.9 10⁸ km

  2) Blsck hole supernove is:  r = 17.7 km

  3)  Mini black hole is:   r = 1.1 10⁻⁷ km

  4) Human body is:  r=  7 10⁻²⁹ km

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Answer:

V = f * λ           velocity equals frequency * wavelength

If f is increased then λ must decrease for the velocity to remain constant.

Using the dot and cross product, we find that the angle between vectors A and B is 90°.

The angle between two vectors can be determined using the dot and cross product. In this case, if the dot product of vectors A and B is zero, it means that the vectors are orthogonal, and the angle between them is 90°.

The dot product of two vectors, A and B, can be calculated using the equation:

A · B = |A| |B| cos(θ)

where |A| and |B| represent the magnitudes of vectors A and B, respectively, and θ is the angle between them.

Given that the dot product A · B is zero, we have:

0 = |A| |B| cos(θ)

Since the magnitudes of vectors A and B are both non-zero, we can conclude that cos(θ) must be zero. The cosine of an angle is zero when the angle is 90° or 270°. However, we are only interested in the angle between 0° and 180°.

Therefore, the angle between vectors A and B is 90°.

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Asbestos would most likely be found around pipes in a house.

Asbestos is nan organic naturally occurring mineral.

Its composition is similar to thin fibers like crystals of of silicate mineral.

The fibers of Asbestos are so thin and microscopic that they liberate into the atmosphere due to erosion and other processes.

These tiny particles are considered harmful for health as they are carcinogenic in nature and causes mesothelioma.

Its melting point is between 400 to 1,040 °C and is available in blue, green, grey white and yellow color.

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The total work (in Joules) that must be done on the object to increase its speed to 10.7 m/s is 349J.

ΔK.E = W

ΔK.E = K.Ef - K.Ei

⇒ ΔK.E = 1/2m(Vf² - Vi²)

⇒ ΔK.E = 1/2×9.5(10.7² - 6.4²)

⇒ ΔK.E = 349J

Hence, the total work is 349J

Work = Force Distance is the formula for calculating work. The joule (J), sometimes known as the Newton meter (N m), is the SI unit for work. When an object is moved across a distance of 1 m by 1 N of force, the work done is equal to 1 joule.

Between KE and W relationship: An object's change in kinetic energy equals the work performed on it by a net force: W = KEi - KEf. The work-energy theorem is the name given to this relationship.

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