Suppose a plumbing subcontractor requires the mechanical engineer's assistance to resolve a problem discovered in the construction drawings. Which of the following scenarios describes the proper lines of communication?
Answers
The proper lines of communication would depend on the specific roles and responsibilities of the parties involved
Describing the proper line of communication
In this scenario, the proper lines of communication would depend on the specific roles and responsibilities of the parties involved, as well as the contract and project documents.
Generally, the following scenario would describe proper lines of communication:
If the mechanical engineer is contractually responsible for designing the plumbing system and ensuring its proper installation, then the proper line of communication would be for the engineer to review the problem identified by the subcontractor and propose a solution.
The engineer would be responsible for ensuring the proposed solution is implemented correctly by the subcontractor.
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Related Questions
A ball slowly starts to roll downhill, but its speed increases as it rolls. How are the ball's speed and energy related? - Why do you think the ball starts to roll faster? And the impact energy has on objects! (Write at least 2-3 complete sentence).
Answers
Answer:
the ball gains speed because of the force of the earth pulling on it and the kinetic energy coming ffrom the potental energy
Explanation:
A wind tunnel is used to study the flow around a car. The air is drawn at 60 mph into the tunnel. (a) Determine the pressure in the test section as determined by the manometer. (b) Determine the pre
Answers
Answer:
The answer is below
Explanation:
The complete question is attached.
a) Bernoulli equation is given as:
\(P+\frac{1}{2}\rho V^2+ \rho gz=constant\\\\\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\)
Where P = pressure, V = velocity, z = height, g = acceleration due to gravity and ρ = density.
\(\frac{P}{\rho g} +\frac{V^2}{2g} +z=constant\\\\\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_1}{\gamma} +\frac{V_1^2}{2g} +z_1=\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2\\\\but \ z_1=z_2,P_1=0,V_1=0,V_2=60\ mph=88\ ft/s. Hence:\\\\\frac{P_2}{\gamma} =-\frac{V_2^2}{2g} \\\\P_2=\gamma*-\frac{V_2^2}{2g} =\rho g*-\frac{V_2^2}{2g} \\\\P_2=-\frac{V_2^2}{2}*\rho=-\frac{(88.8\ ft/s)^2}{2} * 0.00238\ slug/ft^3=-9.22\ lb/ft^2\\\\P_2+\gamma_{H_2O}h-\gamma_{oil}(1/12 \ ft)=0\\\\\)
\(\gamma_{oil}=0.9\gamma_{H_2O}=0.9*62.4\ lb/ft^3=56.2\ lb/ft^3\\\\Therefore:\\\\-9.22\ lb/ft^2+62.4\ lb/ft^3(h)-56.2\ lb/ft^3(1/12\ ft)=0\\\\h=0.223\ ft\)
b)
\(\frac{P}{\gamma} +\frac{V^2}{2g} +z=constant\\\\\frac{P_2}{\gamma} +\frac{V_2^2}{2g} +z_2=\frac{P_3}{\gamma} +\frac{V_3^2}{2g} +z_3\\\\but \ z_3=z_2,V_3=0,V_2=60\ mph=88\ ft/s. \\\\\frac{P_2}{\gamma}+\frac{V_2^2}{2g} = \frac{P_3}{\gamma}\\\\\frac{P_3-P_2}{\gamma}=\frac{V_2^2}{2g} \\\\P_3-P_2=\frac{V_2}{2g}*\gamma=\frac{V_2^2}{2g}*\rho g\\\\P_3-P_2=\frac{V_2}{2}*\rho=\frac{(88\ ft/s^2)^2}{2}*0.00238\ slg\ft^3\\\\P_3-P_2=9.22\ lb/ft^2\)
This agency develops standards for pressure vessels and pressure relief valves, as well as the design, welding, and materials that may be used in pipeline construction.
Select one:
a. American Petroleum Institute
b. American Society of Mechanical Engineers
c. American Gas Association
d. National Fire Protection Association
Answers
Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
A passive instrument performs which of the following tasks?
sends transmissions to Earth
records echo results from signals
accepts transmissions from Earth
collects radiation reflected from Earth
Answers
Answer:
D. Collects radiation reflected from Earth.
Explanation:
You will be using the fictional manufacturing facility Acme Automotive Parts (AAP) throughout the course. AAP manufactures several support parts for new automobiles as a small supplier to Nissan, Honda, and Volkswagen facilities in the United States. Their processes include shipping/receiving, hydraulic presses, metal working lines, robotic welding stations, hand-welding stations in rework areas, two small paint booths, a quality assurance/quality control (QA/QC) laboratory, and a final inspection area.
For this unit please answer the following question:
Determine what information you would use to anticipate health hazards that might be present in each of the eight areas of the AAP plant. State where you might find the information you need.
Answers
To anticipate health hazards in each of the eight areas of the AAP plant, the following information could be used:
1. Shipping/Receiving:
Type of materials being received and shippedPossible exposure to hazardous chemicals, dust, and fumesPossible exposure to heavy machinery and equipmentInformation could be found in Material Safety Data Sheets (MSDS) for the materials, as well as through workplace observations and assessments.2. Hydraulic Presses:
Possible exposure to hydraulic fluids and associated fumesPossible exposure to high pressure and loud noise levelsInformation could be found in MSDS for hydraulic fluids and through workplace assessments and monitoring.3. Metal Working Lines:
Possible exposure to metal dust, fumes, and particlesPossible exposure to high noise levelsPossible exposure to sharp edges and hot surfacesInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the metal working process.4. Robotic Welding Stations:
Possible exposure to welding fumes, dust, and particlesPossible exposure to high noise levelsPossible exposure to high heat and bright lightInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the welding process.5. Hand-Welding Stations in Rework Areas:
Same hazards as in robotic welding stationsPossible exposure to sparks and hot surfacesInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the welding process.6. Small Paint Booths:
Possible exposure to paint fumes and particulate matterPossible exposure to high noise levelsInformation could be found through workplace assessments and monitoring, as well as through MSDS for the paint materials.7. QA/QC Laboratory:
Possible exposure to chemicals and hazardous materials used in testing and analysisPossible exposure to high noise levels from laboratory equipmentInformation could be found through workplace assessments and monitoring, as well as through MSDS for the chemicals and hazardous materials used in the laboratory.8. Final Inspection Area:
Possible exposure to dust and fumes from various manufacturing processesPossible exposure to high noise levelsInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the final inspection process.To anticipate health hazards in each area of Acme Automotive Parts (AAP) manufacturing facility, the following information would be relevant.
What are the information that are relevant in this case?1. Shipping/Receiving: Material Safety Data Sheets (MSDS) for chemicals received, potential for heavy lifting injuries, and risks associated with forklift operations.
2. Hydraulic Presses and Metal Working Lines: MSDS for lubricants and coolants, risks of crush injuries, and exposure to metal fumes.
3. Robotic and Hand-Welding Stations: MSDS for welding materials, welding fume exposure, and risk of burns.
4. Paint Booths: MSDS for paints and coatings, potential for volatile organic compounds (VOCs) exposure, and respiratory hazards.
5. QA/QC Laboratory: MSDS for chemicals used in testing, potential for chemical exposure, and ergonomic risks.
6. Final Inspection Area: Ergonomic risks associated with repetitive tasks, MSDS for any chemicals used, and general safety precautions.
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A "calorie" is a unit of energy, defined as the amount of energy needed to raise the temperature of one gram of water by one degree Celsius. The nutritional labels on food products typically tell you how many calories of digestible energy are in one serving of food, where "digestible" means that the energy stored in the chemical bonds of the molecules comprising the food can be extracted by your body. (Water for example has energy, but that energy is not chemically accessible via digestion.) To simplify understanding for typical consumers, the "calories" reported on nutritional labels actually represent kilocalories: a 170 calorie can of beer actually contains 170,000 calories of digestible energy.
i) If a student foolishly decides to binge drink 21 beers on their 21t birthday, how many gallons of water could they have heated from room temperature (24 °C) to boiling (100 C) using an equivalent amount of digestible energy in the beer? Recall that one gallon of water is roughly 8 pounds.
ii) What is this energy equivalent to in BTU? A "BTU" or British Thermal Unit is also a unit of energy, defined as the amount of energy needed to raise the temperature of one pound of water by one degree Fahrenheit
iii) If you had purchased an equivalent amount of electrical energy in kW-hr from the utility company, how much would you have to pay? Is this cheaper than buying beer?
Answers
A "calorie" is a unit of energy that is defined as the usually inform you of the number of calories of digestible energy present in one serving of food. 21 beers times 17 calories per beer equals 357 calories.
What is "calorie"?Calories are units of energy that a food or drink provides. You can usually find calorie counts listed on food items, and wearables like the best fitness trackers allow you monitor how many calories you're burning by doing different activities. Certain foods, such as fatty, fried, or processed foods, tend to have more calories. Other foods, such as fresh fruit and vegetables, tend to have fewer calories. However, some healthy fruits and vegetables can be high in calories, while low-calorie foods, such as diet soda, don’t provide any nutritional value. We need calories to give us enough energy to move around, stay warm, grow, work, think, and play. Even our blood circulation and digestion need the energy gained from calories in order to function well.To learn more about blood circulation refer to:
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1. Discuss how products incorporate aesthetic design and why this appeals to target markets 2. Discuss how the universal design process has impacted engineering design and the impact these expectations will have on the future of product design.
Answers
Explanation:
Remember, to say a product is incorporated with aesthetic design implies that its overall appearance is designed to look beautiful to the eyes of the user/buyer. For example, a clothing company whose target market is mainly focused on women's clothing would need to take into consideration that certain colors like pink, blue, etc are attractive to women more than men. So they'll have to ensure the colors of their clothing are suitable to the needs of their target market.
The Universal Design process involves building products that can be used by a wide range of users at ease. For example, you may ask yourself: Is my product/service easily accesible to those with disabilities?
Other processes include;
Defining who the users (or universe) are of the products. Involve consumers in the design.Follow the existing standards of product designEvaluate and review your universal design methods1.What is three phase? why it is needed?
2. What is the condition to be balanced? Write down voltage equation of a balanced 3 phase voltage source and draw their phasor diagram.
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1. We can see here that three phase refers to a type of electrical power transmission that uses three alternating current (AC) waveforms that are 120 degrees out of phase with each other. This is different from single-phase power transmission, which uses only one AC waveform.
What is voltage?Voltage, also known as electric potential difference, is a measure of the electrical potential energy per unit of charge in an electrical circuit. It is defined as the amount of work required to move a unit of electric charge between two points in a circuit, typically measured in volts (V).
Three-phase power is needed because it allows for more power to be transmitted over a given amount of wire or cable. With three-phase power, the power is delivered in a more consistent manner, which means that there is less voltage drop over long distances.
2. In order for a three-phase system to be balanced, the three phases must have the same amplitude and be 120 degrees out of phase with each other. The voltage equation of a balanced three-phase voltage source is given by:
Vph = Vline / √3
where Vph is the phase voltage and Vline is the line voltage. The phasor diagram for a balanced three-phase system shows three sinusoidal waveforms that are displaced by 120 degrees from each other.
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. (20 pts) A horizontal cylindrical pipe (k = 10 W/m·K) has an outer diameter of 15 cm and a wall thickness of 5 cm. The pipe is situated in a stationary air, where the air and surrounding temperature is 27°C. The outer surface temperature of the pipe is 127°C, and the pipe surface has an emissivity of 0.5. Determine the inner surface temperature of the pipe. Use the following air properties for the analysis: k = 0.03 W/m∙K, ν = 20.92 × 10−6 m2 /s, α = 29.90 × 10−6 m2 /s, Pr = 0.70
Answers
Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
three 20kva 24000/277 v distribution transformers are connected in delta y
Answers
If three 20kVA 24000/277V distribution transformers are connected in delta-y, this means that the transformers are arranged in a three-phase configuration.
The primary side of each transformer is connected in delta (Δ) configuration, while the secondary side is connected in wye (Y) configuration.
The transformers are designed to step down the voltage from 24000V to 277V, which is the standard voltage for residential and commercial buildings. The total capacity of the three transformers is 60kVA (20kVA x 3), which is sufficient to handle the electrical load of a medium-sized building.
It is important to note that the delta-y connection provides a neutral point on the secondary side, which can be used for grounding purposes. This configuration also allows for better voltage regulation and reduced harmonics in the electrical system.
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A 0.4-W cylindrical electronic component with diameter 0.3 cm and length 1.8 cm and mounted on a circuit board is cooled by air flowing across it at a velocity of 240 m/min. If the air temperature is 358C, determine the surface temperature of the component. For air properties evaluations assume a film temperature of 508C. Is this a good assumption
Answers
The surface temperature of the component is found using the formula q=hA(Ts-T∞), where h is calculated using the Reynolds number correlation. The surface temperature is 58.4°C and assuming a film temperature of 50.8°C is reasonable.
Using the formula for convective heat transfer, q = hA(Ts - T∞), where q is the rate of heat transfer, h is the convective heat transfer coefficient, A is the surface area of the component, Ts is the surface temperature of the component, and T∞ is the air temperature, we can solve for Ts. First, we need to calculate the convective heat transfer coefficient, h. Using the Reynolds number correlation for flow over a cylinder, we can calculate the Nusselt number and then use it to calculate h. Assuming a film temperature of 50.8°C is reasonable because it is within the range of the air temperature and can provide a good approximation of the convective heat transfer coefficient. The calculated surface temperature of the component is 58.4°C.
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A plant might be emitting some dangerous pollutants that are environmentally harmful, but completely eliminating them would be so expensive that the plant would have to close, throwing many local inhabitants out of work. Assuming there is an obligation both to preserve jobs and to protect the environment. What is the best technique that should be used to resolve this problem?
Select one:
a. The convergence and divergence techniques
b. The Utilitarian approach
c. The creative middle way
d. The line drawing technique
Answers
Answer: c. The creative middle way
Explanation:
As there is both an obligation to preserve jobs and to protect the environment, a creative middle way which involves compromise would be most effective.
The company involved should process and remove the worst pollutants alone while leaving others so that the process will not be so expensive that they have to close down.
They will do this till a better and more environmentally beneficial solution can be found at which point they can then clean up the previous pollutants with the hope that they have not irrecoverably damaged the environment.
2. Discuss the reengineering process in your own words and provide an example.
Answers
Reengineering is the process of redesigning and improving business processes to achieve significant performance improvements. It involves challenging traditional methods and leveraging technology for transformative change.
Reengineering is the process of fundamentally redesigning and improving business processes to achieve significant improvements in performance, efficiency, and effectiveness. It involves a holistic approach that rethinks and restructures existing processes, often leveraging technology and innovation to drive transformative change. Reengineering aims to break away from traditional ways of operating and create new, streamlined processes that align with organizational goals and deliver value to customers.
Example: One example of reengineering is the transformation of a traditional paper-based invoicing process into an automated electronic invoicing system. In the traditional process, invoices would be generated manually, printed, and sent through the mail, resulting in delays, errors, and inefficiencies. Through reengineering, the process can be redesigned to leverage electronic invoicing software, where invoices are generated electronically, sent via email or a digital platform, and seamlessly integrated with the organization's accounting systems. This reengineering effort eliminates manual steps, reduces processing time, improves accuracy, and enhances customer satisfaction through faster invoice delivery and streamlined payment processes. The focus is on reimagining the entire invoicing process, identifying pain points, and implementing technological solutions to drive efficiency and effectiveness.
Reengineering projects can vary in scope and scale, but they all involve a critical examination of existing processes, identifying bottlenecks, and finding innovative ways to streamline operations. The goal is to achieve radical improvements in performance and outcomes by challenging traditional assumptions and embracing new approaches to work.
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Which of the following disaster recovery tests is The LEAST time-consuming for the disaster recovery team?
A. Tabletop
B. Parallel
C. Full interruption
D. Simulation
Answers
The Tabletop disaster recovery test is The LEAST time-consuming for the disaster recovery team. A Tabletop disaster recovery test is a process that enables organizations to evaluate their disaster response plans, ensuring that the plan is viable and effective.
It is a group brainstorming exercise in which participants explore various disaster scenarios and devise strategies to manage them effectively. This exercise is also known as a walk-through or tabletop exercise, and it helps companies to test their emergency response procedures and identify gaps in their disaster recovery plan.
It is the least time-consuming disaster recovery test for the disaster recovery team because it does not require the shutdown of critical systems, testing of backups, or other complex and resource-intensive activities. It is a low-cost and low-risk approach to assess an organization's readiness to respond to a disaster. Therefore, The Tabletop disaster recovery test is The LEAST time-consuming for the disaster recovery team.
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A 1.96 in. diameter rod must be machined on a lathe to a smaller diameter for use as a specimen in a tension test. The rod material is expected to break at a normal stress of 68,787 psi. If the tensile testing machine can apply no more than 797 lb of force to the specimen, calculate the maximum rod diameter that should be used for the specimen.
Answers
Answer:
Explanation:
The maximum normal stress that can be applied to the specimen is given by the ratio of applied force to the area of the cross section of the specimen:
stress = force / area
The area of the cross section of a rod is given by the formula for the area of a circle:
area = πr^2
where r is the radius of the rod. We are given the diameter of the rod, which is 1.96 inches, so the radius is half of that, or 0.98 inches.
The maximum normal stress that the specimen can withstand is 68,787 psi, and the maximum force that can be applied is 797 lb. Substituting these values into the equation for stress gives:
68,787 psi = 797 lb / πr^2
Solving for the radius r gives:
r = √(797 lb / (68,787 psi × π))
Substituting in the value for π and calculating gives:
r ≈ 0.330 inches
The maximum diameter of the rod is twice the radius, so the maximum diameter is:
d = 2r ≈ 0.660 inches
Therefore, the maximum rod diameter that should be used for the specimen is approximately 0.660 inches.
Para un intercambiador de calor encargado de precalentar pulpa de fruta, se utiliza agua caliente que entra a 180°C y sale a 78°C, mientras que la pulpa de fruta entra a 3°C y sube su temperatura hasta 55°C. Realizar los esquemas de perfil de temperaturas para un intercambiador de calor que funcione en paralelo y en contracorriente. Además, calcular LMTD.
Answers
Answer:
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
Explanation:
De la teoría de Transferencia de Calor tenemos que un intercambiador de calor en paralelo presenta las siguientes dos características:
1) Tanto el fluido caliente como el fluido frío entran por el mismo lado.
2) Tanto el fluido caliente como el fluido frío salen por el mismo lado.
Mientras que el intercambiador de calor en contracorriente tiene que:
1) El fluido caliente y el fluido frío entran por lados opuestos.
2) El fluido caliente y el fluido frío salen por lados opuestos.
A continuación, anexamos los esquemas de perfil de cada intercambiador.
Ahora, la Diferencia Media Logarítimica de Temperatura (\(\Delta T_{lm}\)), medida en grados Celsius, queda definida como sigue:
\(\Delta T_{lm} = \frac{\Delta T_{1}-\Delta T_{2}}{\ln \frac{\Delta T_{1}}{\Delta T_{2}} }\) (Eq. 1)
Donde \(\Delta T_{1}\) y \(\Delta T_{2}\) son las diferencias de temperatura de los fluidos en cada extremo del intercambiador, medido en grados Celsius.
Procedemos a determinar esas diferencias y la Diferencia Media Logarítimica de Temperatura para cada configuración:
Intercambiador en paralelo
\(\Delta T_{1} = 180\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{1} = 177\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C - 55\,^{\circ}C\)
\(\Delta T_{2} = 23\,^{\circ}C\)
\(\Delta T_{lm} = \frac{177\,^{\circ}C-23\,^{\circ}C}{\ln \frac{177\,^{\circ}C}{23\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 75.466\,^{\circ}C\)
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
Intercambiador en contracorriente
\(\Delta T_{1} = 180\,^{\circ}C-55\,^{\circ}C\)
\(\Delta T_{1} = 125\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{2} = 75\,^{\circ}C\)
\(\Delta T_{lm} = \frac{125\,^{\circ}C-75\,^{\circ}C}{\ln \frac{125\,^{\circ}C}{75\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 97.881\,^{\circ}C\)
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
1. The term lefty loosey, righty tighty is used to prevent what?
Answers
Answer:
Used to recall the direction a standard screw
What is definition Forensic Science?
Answers
the use of scientific or technical methods to identify, gather, analyze, and evaluate evidence for matters of criminal and civil law or regulation
Which two terms best describe forensic science?The application of natural sciences to legal issues is known as forensic science. In actual practice, forensic science makes use of ideas and procedures from physics, chemistry, biology, and other branches of science. The appraisal of physical evidence includes its identification, individualization, and recognition by forensic scientists.
What makes it forensic science?The Roman term forensis, which means public, to the forum or public conversation; argumentative, rhetorical, belonging to dispute or discussion, is where the word "forensic" originates. The phrase "related to, employed in, or fit for a court of law" is a valid definition of forensic in today's society.
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A coastal engineer is to an oil platform as a structural engineer is to:
a freeway.
a skyscraper.
submarine pipelines.
an underground tunnel.
Answers
Answer:
I think the answer is d: underground tunnel
Explanation:
Hope this helps
Which type of design does not need special care for the placement of dimensions?
Answers
Answer:
cubes
Explanation:
Design for software engineering does not need special care for the placement of dimensions. Software engineering generally deals with arranging lines of coding.
What is Software Engineering Design?In order to achieve a software's goal by using lower-level, machine-understandable algorithms and a set of parameters based on project requirements or environmental constraints, software design is the process of outlining solutions, planning, and specifying a method of implementation based on the needs of the user.
Software engineering is the application of engineering principles, which are often employed in the design, development, testing, deployment, and management of physical systems to the design.
Therefore, the main focus of software engineering is organizing coded lines that are kept in a device's or computer's memory rather than in actual physical space.
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Alex loves to build things and wants to study robotics. He needs to get a job over the summer but the only one he can find is at a fast food restaurant. Does taking the job mean that Alex cannot pursue a career in robotics? Explain your answer.
Answers
Answer:
He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.
Which of the following is NOT a peripheral?
Input devices
Output devices
CPU devices
Input/Output devices
Answers
Answer:
I believe that cpu devices are not considered peripherals
Explanation:
From google: A peripheral or peripheral device is an ancillary device used to put information into and get information out of the computer.
A closed vessel of volume 80 litres contains 0.5 N of gas at a pressure of 150 kN/m2. If the gas is compressed isothermally to half its volume, determine the resulting pressure.
Answers
Answer:
The resulting pressure of the gas when its volume decreases is 300 kN/m².
Explanation:
Given;
initial volume of the gas, V₁ = 80 L
number of moles of the gas, n = 0.5 moles
initial pressure of the gas, P₁ = 150 kN/m² = 150 kPa
Determine the constant temperature of the gas using ideal gas equation;
PV = nRT
where;
R is ideal gas constant = 8.315 L.kPa/K.mol
T is the constant temperature
\(T = \frac{P_1V_1}{nR} \\\\T = \frac{150.kPa \ \times \ 80 .L}{0.5 .mol \ \times \ 8.315(L.kPa/mol.K)} \\\\T = 2,886.35 \ K\)
When the gas is compressed to half of its volume;
new volume of the gas, V₂ = ¹/₂ V₁
= ¹/₂ x 80L = 40 L
The new pressure, P₂ is calculated as;
\(P_2V_2 = nRT\\\\P_2 = \frac{nRT}{V_2} \\\\P_2 = \frac{0.5 \times 8.315\times 2886.35}{40} \\\\P_2 = 300 \ kPa = 300 \ kN/m^2\)
Therefore, the resulting pressure of the gas when its volume decreases is 300 kN/m².
The component has an exponentially distributed reliability with a mean of 2000 hours what is the probability that it will fail after 3000 hours?
Answers
Answer:
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Which one of the following answer options are your employers responsibility
Answers
Where are your answer options?
Answer:
Implement a hazard communication program
Explanation: i took the quiz
A one electron species, Xm, where m is the charge of the one electron species and X is the element symbol, loses its one electron from its ground state when it absorbs 7.84×10−17 J of energy. Using the prior information, the charge of the one electron species is?
Answers
Answer:
c +5
Explanation:
we have difference in energy =
2.18x10⁻¹⁸ x z² / n²
now n = 1
amount of energy absorbed Δdelta = 7.84×10−17 J
7.84×10⁻¹⁷ = 2.18x10⁻¹⁸ x z²
we divide through by 2.18x10⁻¹⁸
z² = 7.84×10⁻¹⁷ / 2.18x10⁻¹⁸
z² = 35.9633
z = √35.9633
z = 5.9969
≈ 6
charge = atomic number 6 - number of electrons available in the element 1
= 6-1 = 5
from the calculations above, the charge of the one electron specie would be c +5
Steam at 20 bars is in the saturated vapor state (call this state 1) and contained in a pistoncylinderdevice with a volume of 0.03 m3. Assume the steam is cooled at constantvolume (i.e. the piston is held fixed in place) until the temperature reaches 200 C (callthis state 2). Then the steam is expanded isothermally until its volume is three times theinitial value (state 3).
Required:
a. Determine the pressures at state 2 and 3. ans. 15.5 bar, ~10 bar
b. Determine the change in specific internal energy, u, for each of the two processes.
-389 kJ/kg, 410 kJ/kg
c. Make qualitatively correct sketches of the processes on a T-v plot.
Answers
Answer:
Explanation:
Given that:
At state 1:
Pressure P₁ = 20 bar
Volume V₁ = 0.03 \(\mathbf{m^{3}}\)
From the tables at saturated vapour;
Temperature T₁ = 212.4⁰ C ; \(v_1 = vg_1\) = 0.0996 \(\mathbf{m^{3}}\) / kg
The mass inside the cylinder is m = 0.3 kg, which is constant.
The specific internal energy u₁ = ug₁ = 2599.2 kJ/kg
At state 2:
Temperature T₂ = 200⁰ C
Since the 1 - 2 occurs in an isochoric process v₂ = v₁ = 0.099 \(\mathbf{m^{3}}\) / kg
From temperature T₂ = 200⁰ C
\(v_f_2 = 0.0016 \ m^3/kg\)
\(vg_2 = 0.127 \ m^3/kg\)
Since \(vf_2 < v_2<vg_2\) , the saturated pressure at state 2 i.e. P₂ = 15.5 bar
Mixture quality \(x_2 = \dfrac{v_2-vf_2}{vg_2 -vf_2}\)
\(x_2 = \dfrac{(0.099-0.0016)m^3/kg}{(0.127 -0.0016) m^3/kg}\)
\(x_2 = \dfrac{(0.0974)m^3/kg}{(0.1254) m^3/kg}\)
\(\mathsf{x_2 =0.78}\)
At temperature T₂, the specific internal energy \(u_f_2 = 850.6 \ kJ/kg\) , also \(ug_2 = 2594.3 \ kJ/kg\)
Thus,
\(u_2 = uf_2 + x_2 (ug_2 -uf_2)\)
\(u_2 =850.6 +0.78 (2594.3 -850.6)\)
\(u_2 =850.6 +1360.086\)
\(u_2 =2210.686 \ kJ/kg\)
At state 3:
Temperature \(T_3=T_2 = 200 ^0 C ,\)
\(V_3 = 2V_1 = 0.06 \ m^3\)
Specific volume \(v_3 = 0.2 \ m^3/kg\)
Thus; \(vg_3 =vg_2 = 0.127 \ m^3/kg\) ,
SInce \(v_3 > vg_3\), therefore, the phase is in a superheated vapour state.
From the tables of superheated vapour tables; at \(v_3 = 0.2 \ m^3/kg\) and T₃ = 200⁰ C
The pressure = 10 bar and v =0.206 \(\ m^3/kg\)
The specific internal energy \(u_3\) at the pressure of 10 bar = 2622.3 kJ/kg
The changes in the specific internal energy is:
\(u_2-u_1\)
= (2210.686 - 2599.2) kJ/kg
= -388.514 kJ/kg
≅ - 389 kJ/kg
\(u_3-u_2\)
= (2622.3 - 2210.686) kJ/kg
= 411.614 kJ/kg
≅ 410 kJ/kg
We can see the correct sketches of the T-v plot showing the diagrammatic expression in the image attached below.
In the circuit given below, R1 = 17 kΩ, R2 = 74 kΩ, and R3 = 5 MΩ. Calculate the gain 1formula58.mml when the switch is in position 1, position 2, and position 3.
A) The gain 1formula58.mml at the position 1 is _____.
B) The gain 1formula58.mml at the position 2 is _____.
C) The gain 1formula58.mml at the position 3 is _____.
Answers
Answer:a
a) Vo/Vi = - 3.4
b) Vo/Vi = - 14.8
c) Vo/Vi = - 1000
Explanation:
a)
R1 = 17kΩ
for ideal op-amp
Va≈Vb=0 so Va=0
(Va - Vi)/5kΩ + (Va -Vo)/17kΩ = 0
sin we know Va≈Vb=0
so
-Vi/5kΩ + -Vo/17kΩ = 0
Vo/Vi = - 17k/5k
Vo/Vi = -3.4
║Vo/Vi ║ = 3.4 ( negative sign phase inversion)
b)
R2 = 74kΩ
for ideal op-amp
Va≈Vb=0 so Va=0
so
(Va-Vi)/5kΩ + (Va-Vo)74kΩ = 0
-Vi/5kΩ + -Vo/74kΩ = 0
Vo/Vi = - 74kΩ/5kΩ
Vo/Vi = - 14.8
║Vo/Vi ║ = 14.8 ( negative sign phase inversion)
c)
Also for ideal op-amp
Va≈Vb=0 so Va=0
Now for position 3 we apply nodal analysis we got at position 1
(Va - Vi)/5kΩ + (Va - Vo)/5000kΩ = 0 ( 5MΩ = 5000kΩ )
so
-Vi/5kΩ + -Vo/5000kΩ = 0
Vo/Vi = - 5000kΩ/5kΩ
Vo/Vi = - 1000
║Vo/Vi ║ = 1000 ( negative sign phase inversion)
Segments AB and CD of the assembly are solid circular rods, and segment BC is a tube. If the assembly is made of 6061-T6 aluminum, determine the displacement of end D with respect to end A. Take b = 455 mm and E = 68.9 GPa. Express your answer to three significant figures and include the appropriate units.
Answers
The displacement of end D with respect to end A is 6.04 micrometers, if assembly is made of 6061-T6 aluminum.
To calculate the displacement we can use the formula for the deformation of a bar under axial load:
δ = P L / (A E)
where delta is the deformation (displacement) of the bar,
P is the axial load applied to the bar,
L is the length of the bar,
A is the cross-sectional area of the bar, and
E is the modulus of elasticity of the material.
For segment AB, the axial load is given by:
P = F = (2/3) W = (2/3) (9.81 m/s²) (4 kg) = 26.16 N
The length and cross-sectional area of segment AB are:
L = b = 455 mm = 0.455 m
A = (pi/4) d² = (pi/4) (20 mm)² = 314.16 mm² = 0.00031416 m²
The modulus of elasticity of 6061-T6 aluminum is given as E = 68.9 GPa = 68.9 x 10⁹ Pa.
Therefore, the deformation of segment AB is:
δ_{AB} = P L / (A E)
= (26.16 N) (0.455 m) / (0.00031416 m²) (68.9 x 10⁹ Pa)
= 1.83 x 10⁻⁶ m = 1.83 micrometers.
For segment BC, we can assume that there is no deformation since it is a tube and is not subject to axial load.
For segment CD, the axial load is given by:
P = F = (1/3) W = (1/3) (9.81 m/s²) (4 kg) = 13.88 N
The length and cross-sectional area of segment CD are:
L = b = 455 mm = 0.455 m
A = (pi/4) d² = (pi/4) (30 mm)² = 706.86 mm² = 0.00070686 m²
Therefore, the deformation of segment CD is:
δ_{CD} = P L / (A E) = (13.88 N) (0.455 m) / (0.00070686 m²) (68.9 x 10⁹ Pa)
= 4.21 x 10⁻⁶ m = 4.21 micrometers.
To find the displacement of end D with respect to end A, we can sum up the deformations of segments AB and CD, since they are in series:
δ_{D} = δ_{AB} + δ_{CD}
= (1.83 + 4.21) x 10⁻⁶ m = 6.04 micrometers
Therefore, the displacement of end D with respect to end A is 6.04 micrometers.
To practice more questions about displacement:
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A vibration system consists of a mass 50 kg, a spring of stiffness 30 kN/m and a damper. The
damping provided is only 20% of the critical value. Determine (a) the damping factor, (b) the
critical damping coefficient, (c) the natural frequency of the damped vibrations, (d) the
logarithmic decrement and (e) the ratio of two consecutive amplitudes.
Answers
Answer:
20% of the critical value. Determine (a) the damping factor, (b) the
Explanation: