Suppose that a woman weighing 130 lb and wearing high heeled shoes momentarily places all her weight on the heel of one foot. If the area of the heel is 0.50 in.2, calculate the pressure exerted on the underlying surface in (a) pounds per square inch, (b) kilopascals, and (c) atmospheres.

Answer:

1 - c

2 - a

Explanation:

1 - c

2 - a...............

Answer:

Slipher developed spectrographic methods that allowed researchers to see a Doppler effect in the distances of what were then called “spiral nebula,” what we today call galaxies. Simply put, by measuring the longer wavelength red shift (objects moving away) and shorter wavelength blue shift (objects moving closer), Slipher demonstrated that the universe was not static.

Explanation:

Answer:

5.99 m  = 6 m

Explanation:

PE = m*g*h

235.2 J = (4 kg)(9.81 m/s^2)(h)

h = (235.2 J)/(9.81*4)

h = 5.99 m

h = 6 m

Here, the slope of the graph is negative and constant.

Hence, acceleration is constant and is in opposite direction to its motion.

So, The object whose motion is represented by this graph is moving with constant acceleration.

Motion is defined in physics as the phenomenon through which an object changes its location with respect to time. Motion is mathematically characterized in terms of displacement, distance, velocity, acceleration, speed, and frame of reference to an observer, with the change in position of the body relative to that frame measured as time passes. Kinematics is the branch of physics that studies forces and their effects on motion, whereas dynamics is the branch that studies forces and their effects on motion.

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Answer:

Nuclear power plant.

Gas stove.

Dam.

Gas pump.

Geothermal heat pump.

Power lines.

Solar panels.

Windmills.

Explanation:

Hope this helps :))

Answer:

gasoline,solar panels,geothermal heat pump,windmills

Explanation:

Explanation:

Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.

Answer:

Personality or share the same interest similar in age or hobby

Explanation:

Answer:

Explanation:

People will form relationships with others who are similar in background, attitude and lifestyle.

0.02020 ohm is the resistance of a carbon rod at 25.8 ∘C if its resistance is 0.0200 Ω at 0.0 ∘C.

A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.

The temperature of the resistor varies based on the variation in the temperature. The equation that describes the relationship between the two of them is:

R = R0[1+ alpha(T-T0)]  where:

R is the new resistance we are looking for

alpha is the temperature coefficient of resistance. For carbon rod, alpha = ₋ 4.8 x \(10^{-4}\)(1/°c)

T0 is the standard temperature =25.8°C

R0 is the resistance at T0 = 0.0200 ohms

T is the temperature at which we want to get R = 0

Substitute in the equation to get R as follows:

R = 0.0200 [1+( ₋ 4.8 x \(10^{-4}\)) (0-25.8)] = 0.02020 ohm

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The voltage drop across R3 is 34.5 volts.

Voltage, also known as electric potential difference, is a measure of the difference in electric potential energy between two points in an electrical circuit, and it is measured in volts. It is the driving force that moves electric charges through a circuit, from a higher potential to a lower potential.

To determine the voltage drop across R3 in this circuit, we need to first find the equivalent resistance of R2, R3, and R4, since they are connected in parallel. We can then find the total resistance of the circuit by adding the equivalent resistance in series with R1, and finally use Ohm's Law to calculate the voltage drop across R3.

The equivalent resistance of R2, R3, and R4 in parallel can be calculated as:

1/R_parallel = 1/R2 + 1/R3 + 1/R4

1/R_parallel = 1/20 + 1/25 + 1/10

1/R_parallel = 0.15

R_parallel = 1/0.15

R_parallel = 6.67 ohm

The total resistance of the circuit can be found by adding R1 and the equivalent resistance in series:

R_total = R1 + R_parallel

R_total = 15 + 6.67

R_total = 21.67 ohm

Now we can use Ohm's Law to calculate the current flowing through the circuit:

I = ET / R_total

I = 30 / 21.67

I = 1.38 A

Finally, we can use Ohm's Law again to calculate the voltage drop across R3:

V_R3 = I * R3

V_R3 = 1.38 * 25

V_R3 = 34.5 V

Therefore, the voltage drop across R3 is 34.5 volts.

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When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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Answer:

Stars are the light bulbs of the universe.

Answer:

Stars are the recycling centers of the universe

Explanation:

I just did on edge C

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Answer:

0.6

Explanation:

There are four forces on the box:

Weight force mg pulling down,

Normal force N pushing up,

Tension force T pulling 30° above the horizontal,

and friction force Nμ pushing to the left.

Sum of the forces in the y direction:

∑F = ma

N + T sin 30° − mg = 0

N = mg − T sin 30°

Sum of forces in the x direction:

∑F = ma

T cos 30° − Nμ = 0

Nμ = T cos 30°

μ = T cos 30° / N

μ = T cos 30° / (mg − T sin 30°)

Plug in values:

μ = (250 N) cos 30° / ((50 kg) (9.8 m/s²) − (250 N) sin 30°)

μ = 0.59

Rounded to one significant figure, the coefficient of friction is 0.6.

The coefficient of kinetic friction between the box and floor is :  0.6

Given data :

Mass of box = 50 kg

Angle = 30°

Force required on rope  ( T ) = 250 N

speed = 20 m/s

g = 9.81 m/s²

Calculate the value of the coefficient of kinetic friction

First step : determine sum of forces in the y-direction

∑ Fy = ma

N  +  T sin 30°  - mg = 0

∴ N = mg - Tsin 30° ----- ( 1 )

Next step : Determine the sum of forces in the x-direction

∑ Fx = ma

T cos 30° - Nμ = 0

∴ μ = T cos 30° / N  ----- ( 2 )

where ; N = mg - T sin 30°

Final step : Determine the coefficient of kinetic friction between the box and floor

Back to equation ( 2 )

μ = T cos 30° / ( mg - T sin 30° )

    = 250 cos 30° / ( ( 50 * 9.81 ) - 250 * sin 30° ))

    = 0.59 ≈ 0.6

Hence we can conclude that The coefficient of kinetic friction between the box and floor is :  0.6

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Answer: 7327 n

Explanation: Simple

a) Cart is speeding up ; b) cart is slowing down and c) cart is not moving.

Force of friction is a contact force whereas friction is the force that resists motion when surface of one object comes in contact with surface of another. Example is the force of friction between two stones rubbed with each other.

Static friction magnitude is directly proportional to normal force magnitude and the roughness between sliding surfaces. The ratio of magnitude of frictional force divided by normal force magnitude is called as coefficient of friction. Friction takes place at the point of contact between two bodies.

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Answer:

hello your question is incomplete below is the missing part

Ex = 0

Ey = \(\frac{-2kQ}{\pi a^2}\)

Explanation:

Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π

Ex = 0

Ey = \(\frac{-2kQ}{\pi a^2}\)

Answer:

920000

Explanation:

Each kg contains 1,000 grams

The momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s.

The momentum of the baseball is calculated by applying the following formula as shown below;

P = mv

where;

The momentum of the baseball is calculated as follows;

mass of the baseball = 0.14 kg

velocity of the baseball = 41.26 m/s

momentum, P = mv

P = 0.14 kg  x  41.26 m/s

P = 5.78 kgm/s.

Thus, the momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s by applying the formula for linear momentum.

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The complete question is below:

Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is pitched to the right with a velocity of 41.26 m/s. What is the momentum of the baseball?

Answer:

The answer is the Pluto.

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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The vector product of A and B is -3i - 5j - 9k.

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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Hi there!

\(\large\boxed{1560 kgm/s}\)

Recall that:

P = m · v, where:

P = momentum

m = mass (kg)

v = velocity (m/s)

Thus:

P = 156 · 10

P = 1560 kgm/s

Answer:

The value is   \(t =  14.129 \  minutes\)    

Explanation:

From the question we are told that

  The distance of planet Tatoone is  \(d =  1.7 \ AU  =  1.7 *1.496* 10^{11}=2.543*10^{11} \ m\)

   The  speed of light is  \(c =  3.0*10^{8} \  m/  s\)

Generally the time taken is mathematically represented as

     \(t =  \frac{d}{c}\)

=> \(t =  \frac{2.543*10^{11}}{3.0*10^{8} }\)

=>    \(t =  847.7 \  s\)

Now converting to minutes

       \(t =  \frac{847.7}{60}\)

   =>     \(t =  14.129 \  minutes\)    

Answer:

The value is  \(\lambda  = 214.3  \ nm \)

Explanation:

From the question we are told that

   The  slit separation is  \(d =  3.00 * 10^{-5} m\)

    The  distance of the screen is  \(D =   2.00\ m\)

    The  order of fringe is  n  =  7

    The path difference is  \(y =  10.0 \ cm  =  0.1 \  m\)

    Generally the path difference is mathematically represented as

      \(y =  \frac{n *  \lambda  *  D}{ d}\)

=>   \(0.1 =  \frac{7 *  \lambda  * 2.00 }{ 3.00 * 10^{-5}}\)

=>  \(\lambda  =  \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }\)

=>   \(\lambda  =  \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }\)

=>   \(\lambda  = 2.143 *10^{-7} \  m \)    

=>    \(\lambda  = 214.3  \ nm \)

Answer:

b

Explanation:

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

Answer:

Option A. 180000 Kgm/s.

Explanation:

From the question given above, the following data were obtained:

For Train Car A:

Mass of train car A = 45000 Kg

Velocity of train car A = 4 m/s

Momentum of train car A =?

For Train Car B:

Mass of train car B = 45000 Kg

Velocity of train car B = 0 m/s

Momentum is simply defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

With the above formula, the momentum of train car A before collision can be obtained as follow:

Mass of train car A = 45000 Kg

Velocity of train car A = 4 m/s

Momentum of train car A =?

Momentum = mass × velocity

Momentum = 45000 × 4

Momentum of train car A = 180000 Kgm/s

We can use the conservation of momentum principle to solve this problem. According to this principle, the total momentum of a system of objects remains constant if there are no external forces acting on the system. In this case, we can assume that there are no external forces acting on the two cars after they collide, so the total momentum of the system before the collision must be equal to the total momentum of the system after the collision.

The momentum of an object is defined as its mass multiplied by its velocity:

momentum = mass * velocity

Before the collision, the momentum of the first car (m1) is:

p1 = m1 * v1 = (0.1 kg) * (1.0 m/s) = 0.1 kg⋅m/s

Since the second car is stationary, its momentum before the collision is zero:

p2 = m2 * v2 = (0.15 kg) * (0 m/s) = 0 kg⋅m/s

The total momentum of the system before the collision is:

p1 + p2 = 0.1 kg⋅m/s + 0 kg⋅m/s = 0.1 kg⋅m/s

After the collision, the two cars move together with a common velocity (v), so the momentum of the system is:

p = (m1 + m2) * v

We can set the total momentum before the collision equal to the total momentum after the collision:

p1 + p2 = p

0.1 kg⋅m/s + 0 kg⋅m/s = (0.1 kg + 0.15 kg) * v

0.1 kg⋅m/s = 0.25 kg * v

v = 0.1 kg⋅m/s ÷ 0.25 kg

v = 0.4 m/s

Therefore, the two cars move off together at a speed of 0.4 m/s after the collision.

The power of the Carnot engine is 1.025 W.

Temperature of the hot reservoir, T₁ = 264°C = 537 K

Temperature of the cold reservoir, T₀ = 0°C = 273 K

Heat absorbed by the Carnot engine, Q₁ = 12.3 kJ

Efficiency of the Carnot engine,

η = 1 - (T₀/T₁)

η = 1 - 273/537

η = 0.5

We know that efficiency of Carnot engine,

η = 1 - Q₀/Q₁

Therefore, exhausted heat,

Q₀ = Q₁(1 - η)

Q₀ = 12.3(1 - 0.5)

Q₀ = 6.16 kJ

So, work done by the engine,

W = Q₁ - Q₀ = 12.3 - 6.15

W = 6.15 kJ

Therefore, power of the engine,

P = W/t = 6.15/6

P = 1.025 W

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Answer:

B.

Explanation:

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