Answer:
Explanation:
Fnet = ma
a.) (9N + F₂)(3.0 kg) = 5.0 m/s²
9N + F₂ = (5.0 m/s²) / (3.0 kg)
F₂ = 15 N - 9 N = 6 N →
b.) 9N + F₂ = (-5.0 m/s²) / (3.0 kg)
F₂ = -15 N - 9 N = -24 N ←
c.) 9N + F₂ = (0.0 m/s²) / (3.0 kg)
9N + F₂ = 0
F₂ = -9N ←
Part C Now, grab Tracker’s protractor tool (the green angle in the video frame) and measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below. Hints: To advance the video a frame at a time, use the step buttons on the right. Position the vertex of the protractor exactly at the origin of the coordinate axis. Move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.
In order to measure the angle of incidence and the angle of refraction using Tracker's protractor tool (the green angle in the video frame), the following steps should be followed:
Step 1: Open the video in Tracker software.
Step 2: Click on the "Measure" button on the toolbar at the top of the software.
Step 3: From the dropdown menu, select "Angle".
Step 4: Click on the "protractor tool" icon (the green angle in the video frame).
Step 5: Position the vertex of the protractor exactly at the origin of the coordinate axis and move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.
Step 6: Measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below by using the step buttons on the right to advance the video a frame at a time.
Step 7: Record the measured angles in the table below. Note that the angle of incidence should be measured on the incident ray (the ray that is coming from the left), and the angle of refraction should be measured on the refracted ray (the ray that is coming from the right).In conclusion, by following these steps, one can measure the angle of incidence and the angle of refraction using Tracker's protractor tool.
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A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?
The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and 6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.
4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.For more questions on speed
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Mona said, "I think that, when there is no lid, convection is the main way that
energy escapes from the water."
Has she drawn a good conclusion from her results? Explain your ideas
Mona's conclusion that convection is the main way that energy escapes from the water when there is no lid may or may not be a good conclusion, depending on the context and information provided.
Convection is a process of heat transfer that involves the movement of fluids (in this case, the water) due to differences in temperature. It occurs when warmer portions of the fluid rise and cooler portions sink, creating a circulating flow.
To determine if Mona's conclusion is valid, additional information is needed. Factors such as the presence of other heat transfer mechanisms (such as radiation or evaporation), the specific setup of the experiment, and the conditions under which the observations were made are essential.
If Mona's experiment only considered convection as the primary mechanism for energy escape and excluded other factors, her conclusion might be incomplete or inaccurate. To draw a more comprehensive conclusion, it is necessary to consider other potential heat transfer mechanisms and perform further investigations or provide additional supporting data.
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Father drove 176 km in 7 hours. For the first 92 km, he spent
for 4 hours. What was his average speed for the remaining
journey?
km/h
Answer:
28km/h
Explanation:
92km = 4 hours
176 - 92 = 84
84km = 3 hours
84/3 = 28
28km/h
Hopefully this helps you :)
pls mark brainlest ;)
If two such generic humans each carried 2.0 C coulomb of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 650 N weight?
Given :
Charge on human 1 , \(q_1=2\ C\) .
Charge on human 2 , \(q_2=-2\ C\) .
Force of attraction between them , F = 650 N .
To Find :
Force between them , F =- 650 N .( force between opposite charge is -ve )
Solution :
We know , electrostatics force between two charge is given by :
\(F=\dfrac{kq_1q_2}{r^2}\)
Here k is universal gravitational constant , \(k=6.67408 \times 10^{-11}\ m^3\ kg^{-1}\ s^{-2}\) .
Putting all given value in above equation we get :
\(-650=\dfrac{6.67408 \times 10^{-11}\times 2\times (-2)}{r^2}\\\\r=\sqrt{\dfrac{6.67\times 10^{-11}\times 2\times 2}{650}}\\\\r=6.40\times 10^{-7}\ m\)
Hence , this is the required solution .
Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!
Here is a function machine.
Input : multiply by 6. Subtract 80: output
The input is the same as the output. Find the input.
Also can you please show me an easy to work out these type of questions
Answer:
Explanation:
Sure, I'd be happy to help you with the question!
Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.
So, the function can be written as:
Output = (6 * x) - 80
Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:
x = (6 * x) - 80
Let's solve this equation to find the value of x:
x = 6x - 80
Subtracting 6x from both sides, we get:
x - 6x = -80
Combining like terms, we have:
-5x = -80
Dividing both sides by -5, we find:
x = (-80) / (-5)
Simplifying the expression, we have:
x = 16
Therefore, the input (x) that results in the input being the same as the output is 16.
To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.
Answer:
16
Explanation:
(x*6) - 80 = x
Multiply the parentheses
6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16
In the Skycoaster amusement park ride, riders are suspended from a tower by a long cable. A second cable then lifts them until they reach the starting position indicated in (Figure 1). The lifting cable is then released, and the riders swing down the circular arc shown. If the four riders have a total mass of 330 kg
, what is the tension in the left cable just before release?
Tension in the left cable is 4395.9 N.
What is meant by tension ?Tension is defined as a pulling force that acts along the length of a flexible medium like rope or cables.
Here,
The total mass of the riders is given, m = 330 kg
Let the tension in the left cable be T₁ and that in the right cable be T₂.
From the figure,
T₁ cos 15 = T₂ cos 26
T₁ = T₂ cos 26/cos 15
Also,
T₁ sin15 + T₂ sin 26 = mg
Substituting values,
(T₂ cos 26/cos 15) sin 15 + T₂ sin 26 = 330x 9.8
0.241 T₂ + 0.438 T₂ = 3234
0.679 T₂ = 3234
T₂ = 4762.8 N
Therefore, Tension in the left cable, T₁ = 0.930x 4762.8
T₁ = 4395.9 N
Hence, The tension in the left cable is 4395.9 N
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Your question was incomplete. Attaching the image here.
Where do you feel that you are traveling at the fastest speed when on the swing?
Answer:
C
Explanation:
I think it's C, because at that point, you are going fastest. Sorry if im wrong, hope this helps.
Answer:
In between and the middle one
Explanation:
The
is located 12 to 50 kilometers from Earth’s surface.
Both the
get colder as altitude increases.
The ozone in the
protects people from ultraviolet (UV) radiation.
The
has the highest temperature of any layer in Earth’s atmosphere.
The thermosphere has the highest temperature of any layer in Earth’s atmosphere.
What is the atmosphere?The term troposphere is the region that is found 12 to 50 kilometers from Earth’s surface. This region is found to be the region where you can find a lot of gases.
Both the Troposphere and the stratosphere get colder as altitude increases. However, the ozone in the stratosphere protects people from ultraviolet (UV) radiation.
The thermosphere has the highest temperature of any layer in Earth’s atmosphere.
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Explain why force, acceleration, and velocity are vectors.
Answer:
simply because they all have direction
Explanation:
vector quantities are quantities which have both magnitude and direction.Force,acceleration and velocity have both magnitude and direction.
Two points charge of 4\mu C and 2\mu C are placed at theopposite corners of a rectangle. What is the potential difference Va- Vb
Answer:
\(Va-Vb=168KV\)
Explanation:
From the question we are told that
Two points charge of 4\mu C and 2\mu C
Generally we find the Va and Vb individually to find there difference
Given a rectangle with two equal sides each,Assume lengths for bot sides
Length L=0.3
Breath B=0.4
Diagonal D=\(\sqrt{0.3^2+0.4^2} =0.5\)
at opposite sides
Mathematically Va can represented as
\(Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)
\(Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)
\(Va =9*10^9(0.00001333333-0.000004} )\)
\(Va =84000V\)
\(Va =84KV\)
Mathematically Vb is represented as
\(Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )\)
\(Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )\)
\(Va =9*10^9(-0.00001333333+0.000004} )\)
\(Va =-84000V\)
\(Va =-84KV\)
Therefore
\(Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV\)
A hovering mosquito is hit by a raindrop that is 45 times as massive and falling at 8.2 m/s , a typical raindrop speed. How fast is the raindrop, with the attached mosquito, falling immediately afterward if the collision is perfectly inelastic
Answer:
The speed of the raindrop and the mosquito is 8.02 m/s.
Explanation:
mass of mosquito = m
mass of drop = 45 m
initial velocity of mosquito, u = 0 m/s
initial velocity of drop, u' = 8.2 m/s
During the inelastic collision, the momentum of the system is conserved.
Let the speed of rain drop and the mosquito is v.
Use the conservation of momentum
m x u + 45 m x u' = (m + 45 m) v
m x 0 + 45 m x 8.2 = 46 m x v
v = 8.02 m/s
The rabbit flea Spilopsyllus has a mass of 0.45 mg. It can jump vertically to aheight of about 3.5 cm. Biologists have hypothesized that the energy for the jump is most likely derived from the elastic potential energy stored in the resilin pads ofthe two rear legs of the flea. Each pad is estimated to have a volume of about and its strain typically reaches a value of 100%. The elastic modulus of resilience is about . Is the hypothesis plausible
Answer:
Therefore The hypothesis is not plausible Because
\(P.E \geq P.E_e\)
\(P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J\)
Explanation:
From the question we are told that:
Mass \(M=0.45mg\)
Jump height \(h=3.5cm \approx 0.03m\)
Percentage strain \(\mu =100\%\)
Generally the equation for potential energy is mathematically given by
\(P.E=mgh\)
\(P.E=0.45*10^{-3}*9.8*0.03\)
\(P.E=12.435*10^{-5}J\)
Generally the equation for Elastic potential energy is mathematically given by
\(P.E_e=0.5*stress*strain *volume\)
\(P.E_e=0.5*1*2*10^6*1*1.4*10^{-4*(10^-3)^3}\)
\(P.E_e=1.4*10^{-7}J\)
The hypothesis is only plausible at conditions where
\(P.E\leq P.E_e\)
Therefore The hypothesis is not plausible Because
\(P.E \geq P.E_e\)
\(P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J\)
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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A student's backpack has a mass of 9.6 kg. The student applies a force of 94.08 N [up] while walking through 1.4 km [E] to get to school. Calculate the work done by the student on the backpack
The student does zero work on the backpack because the upward force applied by the student is acting perpendicular to the backpack's displacement parallel to the ground.
Conservation of Energy Roller Coaster A roller coaster cart of mass 100kg travels on a track with one loop. Fill in blanks A-H. А. KE=OJ PE=120000J h= А. V= B B KE=___CE PE=60000J h= _D V= E KE=__F PE=40000J h=__G_ V= KE= PE= h=Om v= K D E F G H K
(a) The height of the roller coaster at 120,000 potential energy is 122.45 m.
(b) The velocity of the roller coaster at 0 J kinetic energy is 0.
(c) The height of the roller coaster at 60,000 potential energy is 61.23 m.
(d) The velocity of the roller coaster at 60,000 J kinetic energy is 34.64 m/s.
(e) The height of the roller coaster at 40,000 potential energy is 40.82 m.
(f) The velocity of the roller coaster at 80,000 J kinetic energy is 40 m/s.
The given parameters:
mass of the roller coaster, m = 100 kgWhen the kinetic energy = 0 and potential energy = 120,000 J
The height of the roller coaster is calculated as follows;
P.E = mgh
\(h = \frac{P.E}{mg}\\\\h = \frac{120,000}{100 \times 9.8} \\\\h = 122.45 \ m\)
Since the kinetic energy = 0, the velocity of the roller coaster = 0
When the potential energy, P.E = 60,000 J, the kinetic energy, K.E is calculated as;
P.E + K.E = M.A
P.E + K.E = 120,000
60,000 + K.E = 120,000
K.E = 120,000 - 60,000
K.E = 60,000 J
The height of the roller coaster at 60,000 potential energy is calculated as follows;
\(h = \frac{P.E}{mg} \\\\h = \frac{60,000}{100 \times 9.8} \\\\h =61.23 \ m\)
The velocity of the roller coaster at 60,000 J kinetic energy is calculated as follows;
\(K.E = \frac{1}{2} mv^2\\\\v^2 = \frac{2K.E}{m} \\\\v = \sqrt{ \frac{2K.E}{m}} \\\\v = \sqrt{ \frac{2\times 60,000}{100}}\\\\v = 34.64 \ m/s\)
When the potential energy, P.E = 40,000 J, the kinetic energy, K.E is calculated as;
P.E + K.E = M.A
40,000 + K.E = 120,000
K.E = 120,000 - 40,000
K.E = 80,000
The height of the roller coaster at 40,000 potential energy is calculated as follows;
\(h = \frac{P.E}{mg} \\\\h = \frac{40,000}{100 \times 9.8} \\\\h = 40.82 \ m\)
The velocity of the roller coaster at 80,000 J kinetic energy is calculated as follows;
\(v = \sqrt{\frac{2K.E}{m} } \\\\v = \sqrt{\frac{2\times 80,000}{100} } \\\\v = 40 \ m/s\)
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A bald eagle is flying to the left with a speed of 34 meters
per second when a gust of wind blows back against the
eagle causing it to slow down with a constant acceleration
of a magnitude 8 meters per second squared.
What will the speed of the bald eagle be after the wind has
blown for 3 seconds?
Answer:
the speed after 3 seconds is 10 m/s
Explanation:
The computation of the speed is shown below:
As we know that
V = U + at
Here,
U = 34 m/s
a = - 8 m/s²
t = 3 Sec
V = velocity after 3 sec
V = 34 + (-8)3
= 34 - 24
V = 10 m/s
Hence, the speed after 3 seconds is 10 m/s
The critical period is a special time of development in humans. True False
Answer:
True
Explanation:
Without proper development during the critical period, the growth of some life skills may be severely delayed or stunted.
what happened on march 21 every year in the northern hemisphere
Answer:
B. The Spring equinox
Explanation:
The vernal equinox marks the moment the sun crosses the celestial equator. The vernal equinox happens on March 19, 20, or 21 every year in the Northern Hemisphere. In the Southern Hemisphere, this same event marks the beginning of fall. (Source: What Exactly Is The Spring Equinox? - Dictionary.com)
Hopefully this helps.
if a girl is running along a straight road with a uniform velocity 1.5m/s find her acceleration
Answer:
Dear user,
Answer to your query is provided below
Acceleration is zero because of no change in velocity.
Explanation:
Remember that velocity is a vector quantity and a vector can change in 3 ways
•Magnitude only
•Direction only
•Both magnitude and direction.
Now the magnitude of velocity (speed) can stay constant while the direction is changing. This is the case in circular motion.
In the question above, it is mentioned that the girl is moving along a straight road. Therefore no change in direction of velocity.
A wave reflects off a certain boundary. The reflected wave has the same amplitude
and orientation as the incident wave. What is this the result of?
A. The wave experienced destructive interference.
B. The wave experienced constructive interference.
C. The wave reflected off of a free boundary.
D. The wave reflected off of a fixed boundary.
If the reflected wave has the same amplitude and orientation as the incident wave, it is because the wave experienced destructive interference.
option A.
What is destructive interference?
Destructive interference occurs when waves come together so that they completely cancel each other out. When two waves destructively interfere, they must have the same amplitude in opposite directions.
So when a wave reflects off a certain boundary and the reflected wave has the same amplitude and orientation as the incident wave, it is because both waves interfere destructively.
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Someone who snorts and stop breathing during sleep may be suffering from: a. Catoplexy b. Narcolepsy c. Sleep Apnea d. Insomnia
Answer:
C. Sleep Apnea
Explanation:
Sleep Apnea is when someone who snores and stops breathing while sleeping
Someone who snorts and stop breathing during sleep may be suffering from Sleep Apnea. Hence, option (c) is correct.
What is Sleep Apnea?Breathing repeatedly stops and begins while you sleep, which is a frequent symptom of sleep apnea. Your body may not receive enough oxygen as a result.
There are two different forms of sleep apnea.
When your upper airway is repeatedly closed while you sleep, airflow is reduced or entirely stopped, which is known as obstructive sleep apnea. This kind of sleep apnea is the most prevalent.When your brain fails to deliver the necessary signals for breathing, central sleep apnea develops. Central sleep apnea can be brought on by medical problems that alter how your brain regulates the muscles in your chest and airway.Learn more about sleep apnea here:
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Ô tô chuyển động trên đường cong có bán kính R = 300(m). Nếu vận tốc ôtô tăng đều từ v1 =
20(m/s) đến v2 = 35(m/s) trong thời gian t = 5(s). Xác định độ lớn gia tốc của ôtô khi vận tốc của ôtô là
v3 = 30(m/s)
Answer:
Mc ,12,4
Explanation:
Suppose we are told that the position of an object (x) moving with an acceleration a is proportional to some power of a, say an and some power of t, say tm. Determine the values of n and m and write the simplest form of an equation for the position.
(a) The value of n is 1 and the value of m is 2
(b) The simplest form of an equation for the position is \(at^2\)
The given expression:
\(x = a^nt^m\)
To find:
the values of a values of n and msimplest form of the equationThe values of n and m will be calculated using the dimensions of accelerations, position and time.
The dimension of acceleration, \(a = LT^{-2}\)The dimension of position, x = LThe dimension of time, t = T(a) the values of n and m are calculated as follows:
\(x = a^n t^m\\\\ L = [LT^{-2}]^n [T]^m\\\\L = [L]^n [T^{-2n}][T]^m\\\\L = [L]^n[T^{m-2n}]\\\\L^1T^0 = [L]^n[T^{m-2n}]\\\\L^1 = L^n\\\\n = 1\\\\T^0 = T^{m-2n}\\\\0 = m - 2n\\\\0 = m- 2(1)\\\\0 = m- 2\\\\m = 2\)
(b) The simplest form of an equation for the position can be written as;
\(x = a^n t^m\\\\x = a^1 t^2\\\\x = at^2\)
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two coherent sources of light of equal strength produce near parallel beams that intersect at a point p. compared to the intensity from just one of the sources, the intensity of the light due to both sources at point p will be select all that apply 1. four times that of a single source. 2. not enough information given. 3. twice that of a single source. 4. in a range from zero to four times that of a single source. 5. in a range from zero to two times that of a single source. I thought the intensity will be twice that of a single point due to the superposition principle. But, apparently I am wrong.
The intensity of the light due to both sources at point P will be four times that of a single source.
According to the superposition principle, the total intensity of light at a point is equal to the sum of the intensities due to each individual source. Since the two sources are of equal strength, the intensity of the combined light at point P will be twice that of a single source.
However, the light from each source will interfere with each other, resulting in constructive and destructive interference. As two beams are coherent, meaning they have the same frequency and phase, the light waves will add together constructively at certain points, increasing the intensity. So, at point P, the intensity of the light due to both sources will be four times that of a single source.
Hence option 1 is correct.
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Why was the geocentric model of our solar system widely accepted until the 16th century?
A.
The model was considered to work in tandem with the ancient Aztec calendar.
B.
Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
C.
The star catalogue matched the movement of constellations.
D.
No one had yet sailed entirely around Earth to disprove the geocentric model.
The correct answer is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
The geocentric model, which placed Earth at the center of the universe with the Sun, Moon, and stars revolving around it, was widely accepted until the 16th century for several reasons. One of the primary reasons was that observations seemed to support this view. For example, it was observed that the stars appeared to move across the sky in a circular path, and it was assumed that this was due to their motion around Earth. Similarly, the Sun and Moon appeared to rise and set each day, which was consistent with their motion around Earth.
The geocentric model was consistent with the prevailing philosophical and religious beliefs of the time, which held that Earth was a special and unique place at the center of the universe. It was not until the development of the heliocentric model, which placed the Sun at the center of the solar system, and the refinement of astronomical observations, that the geocentric model was gradually abandoned.
The correct option is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.
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A block of mass 10.0 kg is pulled to the right along a rough horizontal surface with a constant horizontal force of 20.0 N. The friction force is known to be 5.00 N. What is the magnitude of the acceleration of the block
Answer:
the magnitude of acceleration will be 1.50m/s^2
Explanation:
To calculate your acceleration, you can use your formula that states that the net force on an object is equal to the mass of the object multiplied by the acceleration of the object. Fnet=ma
if you draw out this situation and label the forces you will have your vector towards the right with a magnitude of 20.0N and then your friction vector will be pointing to the left (in other words, in the negative direction) (opposing the direction of movement) with a magnitude of 5.00N, with the 10.0 kg box in the middle.
The net force will be calculated using F1+F2=Fnet where your F1=20.0N and F2= -5.00N (since it is towards the negative direction).
you will find that Fnet=15.0N
With that, plug in the values you know to calculate the acceleration of the block:
Fnet=ma
(15.0N)=(10.0kg)a from her you can divide both sides by 10 to isolate a:
1.50=a (and now make sure to label the units of your answer)
a=1.50m/s^2 (which is the typical unit for acceleration)
what is hookies law of elasticity
Hooke's law of elasticity is a principle in physics that states that the force required to extend or compress a spring by some distance is proportional to that distance. It is named after the English physicist Robert Hooke, who first stated the law in 1678. Hooke's law is often written as F = -kx, where F is the force applied to the spring, x is the distance it is stretched or compressed, and k is the spring constant, a measure of the stiffness of the spring.
engaging in physical activities like agawang base helps me become
Explanation:
Agawang base is sport mainly played among children in eastern countries like Philippines. It is a game usually played using local props or instrument. Participants are divided into two teams with equal number of team members.
It becomes source of exercise for the players and improves their agility and endurance in the long run. It has also become tool of socializing and learning teamwork.
Question 16 of 17
Figure (a) shows a wire that forms a rectangle (W = 23.0cm, H = 31.0cm) and has a resistance of 4.00 mOhm. Its interior is split into three equal areas, with magnetic fields B₁, B₂, and B. The fields are uniform within each region and directly out of or into the page as indicated. Figure (b) gives the change in the z components B, of the three fields with time t; the vertical axis scale is set by B, = 3.00 μT
and B-2.50B, What are the
(a) the magnitude and
(b) direction of the current induced in the wire?
For the magnetic fields:
(a) 53.8 A(b) The induced current will flow counterclockwise.How to determine magnitude and direction?From Faraday's law of electromagnetic induction, the emf induced in the wire is given by:
emf = -dΦ/dt
where Φ is the magnetic flux through the wire. The negative sign indicates that the induced emf opposes the change in magnetic flux.
The magnetic flux through each of the three regions can be calculated as follows:
Φ₁ = B₁WH/3
Φ₂ = B₂WH/3
Φ₃ = BWH/3
The total magnetic flux through the wire is:
Φ = Φ₁ + Φ₂ + Φ₃ = (B₁ + B₂ + B)WH/3
Taking the time derivative of the magnetic flux:
dΦ/dt = (B₁ + B₂ + B)(WH/3)(dB/dt)
Substituting the given values:
dΦ/dt = (3.00 μT + 2.50(3.00 μT))(0.23 m)(0.31 m)(1.00 m)/(3)(0.010 s) = 0.215 V
The induced emf is equal to the product of the current and the resistance of the wire:
emf = IR
Solving for I:
I = emf/R = 0.215 V / 4.00 mΩ = 53.8 A
The direction of the induced current can be determined using Lenz's law, which states that the direction of the induced current is such that it opposes the change in magnetic flux that produced it. In this case, the induced current will produce a magnetic field that opposes the change in the magnetic field through the wire.
As the magnetic field increases in the downward direction, the induced current will produce a magnetic field in the upward direction to oppose the increase. As the magnetic field decreases in the downward direction, the induced current will produce a magnetic field in the downward direction to oppose the decrease.
Therefore, the direction of the induced current will be counterclockwise.
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