(a) To determine the rejection region for the most powerful test of H0: θ = θ0 versus Ha: θ = θa, assuming θa > θ0, we can follow the Nyman-Pearson Lemma. The steps are as follows:
1. Define the likelihood ratio test (LRT) statistic:
\(LRT = f(y|θa) / f(y|θ0)\)
2. Substitute the given density function into LRT:
\(LRT = [(y^2 * e^(-y/θa)) / (2 * θa^3)] / [(y^2 * e^(-y/θ0)) / (2 * θ0^3)]\)
3. Simplify the LRT by canceling out common terms and rearranging:
\(LRT = (θ0^3 / θa^3) * (e^(-y/θ0 + y/θa))\)
4. Define the critical region:
Reject H0 if LRT > k, where k is a constant determined by the significance level.
(b) The test defined in part (a) is not uniformly most powerful for the alternative θ > θ0. The reason is that the Nyman-Pearson Lemma provides the most powerful test only for simple hypotheses, i.e., when both the null and alternative hypotheses specify a single value for the parameter.
In this case, the alternative hypothesis specifies a range of values (θ > θ0), so the test is not guaranteed to be uniformly most powerful for this alternative.
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. A man of mass 80 kg stands in a lift, what is the reaction from the floor of the lift if the lift;A. moves upwards with steady speed. moves upwards with acceleration 0.5m/sC. moves downward with acceleration 0.4m/s(g - 9.8m/s')
The reaction of the floor is as follows:
R = 784 NR = 816 NWhat is the reaction from the floor for a man in a lift?The reaction of the floor on the man is equal to the weight of the man and the upward force.
Reaction, R = mg + maA) When the lift moves upwards with steady speed.
R = 80 * 9.8 + * 80 * 0
R = 784 N
B) When the lift moves upwards with acceleration 0.4m/s
R = 80 * 9.8 + * 80 * 0.4
R = 816 N
In conclusion, the reaction of the floor changes as the body accelerates upwards.
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one joule of energy used each second is equal to ? of work.
Exactly, 1 Joule of energy per second is what is used to define a Watt. Joules and seconds, respectively, are the SI units for time and work. A power of 1 Joule per second was used to define a Watt.
A one newton (N) force applied over a one meter distance does one joule's worth of work (or energy) (m).. To put it simply, it requires approximately 1 joule of energy to raise a 3/4 pound weight 1 foot off the ground or to drag something 1 foot using a parallel pulling force of 3/4 pound. According to this definition from physics, 1 volt is the same as 1 joule of electric potential energy divided by 1 coulomb of charge. The power unit is the watt. According to this, 1 joule of labor is completed in 1 second. It is, in essence, the ability of an appliance to use energy at a rate of 1 joule per second.
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(a) Calculate the curl and divergence of a three dimensional flow field which is given
by v = i (y+z) + j zx + k xy .
(b) A table tennis ball of mass m = 0.0027 kg, with diameter D = 44 mm, is hit at a
velocity of U = 12 m/s in a horizontal direction with backspin of angular velocity ω
radians/sec. You may take the density of air to be 1.23 kg/m3. If the ball is to travel
on a horizontal path, not dropping due to the acceleration of gravity, explain why
mg = CLrhoU2A/2
where g is gravitational acceleration, CL is the coefficient of lift, rho is the density of
air and A is the projected area of the ball. Rearranging this expression write down
a formula for CL in terms of the other variables and evaluate this for the given
values.You are also told that the coefficient of lift is related to the angular velocity
by CL = 0.28(ωD/2U). Equating this formula with the formula you derived find the
value of ω in radians/sec that ensures the table tennis ball travels on a horizontal
path.
(c) An offshore wind turbine is supported on a vertical cylindrical pile. The diameter of
the pile is 5 m. The water depth at the site is 30 m and the maximum tidal current
at the surface is 1 m/s. Laboratory tests have indicated that the Strouhal number
is 0.3. Estimate the frequency of vortex shedding near the sea surface under peak
tidal flow conditions.
(d) The velocity potential for simple linear waves may be written as:
where H is the wave height, h is the still water depth, x is the horizontal distance,
z is vertical distance downward, t is time, k is the wave number and ω is the wave
frequency. Using the relationship u = ∂/∂x derive a formula for the horizontal
component of velocity, u. For a wave of height 2 m, period 7 s and wave length
100 m propagating in a water depth of 10m, determine the maximum horizontal
velocity at the seabed.
a) To calculate the curl and divergence of a three-dimensional flow field, we have the flow field given as
\(v = i(y + z) + j(zx) + k(xy).\)
The curl of v is defined as:
curl(v) = ∇ x vWhere ∇ is the vector differential operator.
The curl is evaluated as:
\(curl(v) = i[(∂vz/∂y) - (∂vy/∂z)] + j[(∂vx/∂z) - (∂vz/∂x)] + k[(∂vy/∂x) - (∂vx/∂y)]where vx = y, vy = x, and vz = 1.\)
The above equation can be rewritten as:
curl(v) = - i - j + kDivergence of v is defined as:
div(v) = ∇ . v
This can be written as:
\(div(v) = ∂vx/∂x + ∂vy/∂y + ∂vz/∂z\)
Given v, we can calculate div(v) as follows:
\(div(v) = ∂vx/∂x + ∂vy/∂y + ∂vz/∂z= ∂y(y+z)/∂x + ∂x(zx)/∂y + ∂(xy)/∂z= 0+0+0=0\)
div(v) = 0, and curl(v) = - i - j + k
(b) Given that mg = CLρU^2A/2 and CL = 0.28(ωD/2U)
where \(m = 0.0027 kg, D = 44 mm = 0.044 m, U = 12 m/s, g = 9.81 m/s^2, and ρ = 1.23 kg/m^3\)
We have to derive the formula for CL in terms of the given variables and evaluate for the given values.
substituting the given values in the equation, we get:
\(mg = CLρU^2A/2CL = 2mg/(ρU^2A) = 2*0.0027*9.81/(1.23*12^2*π(0.022)^2) ≈ 0.155\)
Given that CL = 0.28(ωD/2U)
we can equate this with the above formula to obtain:
\(0.155 = 0.28(ωD/2U)ω = 2*0.155*12/(0.28*0.044) ≈ 50.06 radians/s(c)\)
For an offshore wind turbine supported on a vertical cylindrical pile, the vortex shedding frequency can be estimated using the formula:
f = St*U/D
where St is the Strouhal number, U is the velocity of the tidal current, and D is the diameter of the pile. Given that D = 5 m, h = 30 m, H = U = 1 m/s,
St = 0.3 we can evaluate the frequency of vortex shedding as:
f = 0.3*1/5 = 0.06 Hz
(d) The horizontal component of velocity is given as
\(u = ∂ϕ/∂x\)
where ϕ is the velocity potential for simple linear waves given as:
\(ϕ = H cosh(k(z+h))/cosh(kh)cos(kx-ωt)\)
Given that H = 2 m, T = 7 s, λ = 100 m, h = 10 m and g = 9.81 m/s^2, we have:
\(T = 2π/ωλ = gT^2/2π = (9.81*7^2)/(2π) ≈ 193.13 m\)
To calculate k, we use the relation k = 2π/λ.
Therefore\(,k = 2π/λ = 2π/100 = 0.0628\)rad/mSubstituting the given values in the velocity potential, we have:
\(ϕ = 2 cosh(0.0628(z+10))/cosh(0.628)cos(0.0628x - ωt)\)
The horizontal component of velocity is given as:\(u = ∂ϕ/∂x = -0.0628*2 sinh(0.0628(z+10))/cosh(0.628)sin(0.0628x - ωt)At the seabed,\)
z = -10 m
t = 0
\(u = -0.0628*2 sinh(-0.628)/cosh(0.628)sin(0) ≈ 0 m/s\)
Therefore, the maximum horizontal velocity at the seabed is 0 m/s.
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How do you calculate the refractive index of a material using the critical angle? (GCSE Physics)
Answer:
µ = \(\frac{1}{sinC}\)
Explanation:
µ = 1/ sinC
µ -----> refractive index of medium
C ----> critical angle
Hope this helps!
Label the parts of the wave.
Answer:
A: Wavelength
B: Crest
C: Trough
D: Amplitude
Answer:
A:
✔ crest
B:
✔ amplitude
C:
✔ trough
D:
✔ wavelength
Explanation:
How much thermal energy does a 2 kg steel block (c = 450 J/kg°C) lose when it cools from 300°C to
20°C?
Answer:
see below
Explanation:
x J / (2 kg * (300-20 C) = 450 J / (kgC)
x = 450 * 2(280) = 252000 J = 252 kJ
Answer:
Thermal energy lost = 252,000 J
Explanation:
change in thermal energy = mass x specific heat capacity x change in temperature
ΔE = mcΔθ
ΔE = change in thermal energy (J)
m = mass (kg)
c = specific heat capacity (J/kg℃)
Δθ = change in temperature (℃)
ΔE = 2 x 450 x (300-20)
ΔE = 252,000 J
Thermal energy lost = 252,000 J
9. Which parts of the ear have a solid medium?
Middle part of the ear have a solid medium. The ossicles, which are bones that amplify sound waves, are located in the middle ear, therefore the medium is solid.
The outer ear is the first place that sound waves pass through, followed by the middle ear and lastly the inner ear. The first medium is gas because the external auditory canal, which is part of the outer ear, is filled with ambient air. The ossicles, which are bones that amplify sound waves, are located in the middle ear; therefore the second medium is solid. The last medium is liquid because the inner ear is loaded with fluids like endolymph and perilymph that vibrate when sound waves pass through them.
The middle ear amplifies sound after being directed toward it by the outer ear, which is in charge of catching it. Amplified sound waves are sent from the middle ear to the inner ear, where hair cells detect the sound waves and transmit the data to the brain.
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Which generalization can be made about the climate of these two areas? san antonio, texas, experiences more dramatic seasonal changes because land heats up and cools down more slowly than water. san antonio, texas, experiences milder seasonal changes because land heats up and cools down more slowly than water. palm coast, florida, experiences more dramatic seasonal changes because water heats up and cools down more slowly than land. palm coast, florida, experiences milder seasonal changes because water heats up and cools down more slowly than land.
The generalization can be made about the climate of these two areas which are-
because water warms and cools more slowly than land, Palm Coast, Florida, has much less seasonal changes.
in step with a generalisation about the weather of these locations, Palm Coast, Florida, has softer seasonal fluctuations than different components of the country because water warms and cools greater slowly than land.
what is Palm Coast, Florida?
normally speakme, Flagler County is wherein Palm Coast, Florida, is situated. In 2000, there had been 32,832 residents; as of the 2010 census, there had been seventy five,a hundred and eighty.
In conclusion, Palm Coast, Florida, has extra slow seasonal modifications than the alternative location due to the fact water warms and cools extra slowly than land.
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the body's electrochemical communication circuitry is known as the
The body's electrochemical communication circuitry is known as the nervous system. The nervous system enables communication between different parts of the body and coordinates various physiological processes
The nervous system is a complex network of specialized cells called neurons that transmit electrical signals, known as nerve impulses or action potentials, throughout the body. It consists of two main components: the central nervous system (CNS) and the peripheral nervous system (PNS). The CNS includes the brain and spinal cord, which are responsible for processing information, initiating responses, and coordinating bodily functions. The PNS consists of nerves that extend from the CNS to other parts of the body, transmitting signals to and from the CNS.
Within the nervous system, electrical signals are generated and propagated through the movement of charged ions across the cell membranes of neurons. These signals allow for the transmission of information, sensory perception, motor control, and the regulation of bodily functions. Overall, the nervous system serves as the body's electrochemical communication circuitry, enabling the transmission of electrical signals that facilitate coordination and control of various physiological processes.
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The classification of spiral galaxies is based on three properties:
Spiral galaxies are classified based on spiral arm tightness, bulge size, and amount of gas and dust present. This allows astronomers to categorize them into subtypes such as Sa, Sb, and Sc.
The classification of spiral galaxies is based on three properties:
1. Spiral arm tightness: This refers to how tightly wound the spiral arms are around the galaxy's center. Galaxies with more tightly wound arms are classified as "Sa," while those with more loosely wound arms are classified as "Sc."
2. Bulge size: The central bulge of a spiral galaxy can vary in size. Larger bulges are typically found in early-type spiral galaxies (such as Sa), while smaller bulges are found in late-type spiral galaxies (like Sc).
3. Amount of gas and dust: The presence and distribution of gas and dust within a spiral galaxy also play a role in its classification. Early-type spiral galaxies generally have less gas and dust compared to late-type spiral galaxies.
By considering these three properties, astronomers can classify spiral galaxies into various subtypes (such as Sa, Sb, and Sc) within the broader spiral galaxy category.
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ANSWER ASAPPP
What type of mountain would form from vertical movements along fault lines?
A) volcano
B) dome
C) fault-block
D) folded
C) fault-block mountain
The state of matter in which particles are arranged in the least organized manner is the
Answer:
gas
Explanation:
PLS MAKE ME AS BRAINLIST
A parallel plate capacitor of capacitance Co has plates of area A with separation d between them. When it is connected to a battery of voltage Vo, it has charge of magnitude Qo on its plates. It is then disconnected from the battery and the plates are pulled apart to a separation 2d without discharging them. After the plates are 2d apart, the new capacitance and the potential difference between the plates are: (Show all steps) [2 marks] a. ½ Co, ½ Vo b. ½ Co, 2Vo c. Co, Vo d. Co, 2Vo e. 2Co, 2Vo
Answer:
b. 1/2·C₀, 2·V₀
Explanation:
The capacitance on the parallel plate capacitor = C₀
The area of the plates = A
The voltage on the battery = V₀
The magnitude of the charge on the plate = Q₀
The new distance between the plates = 2·d
From an online physics source, we have;
\(C_0 = \epsilon_0 \times \dfrac{A}{d}\)
Where;
ε₀ = Constant
A = The area of the plates
With the new distance, 2·d, we get;
\(C_{new} = \epsilon_0 \times \dfrac{A}{2\cdot d} = \dfrac{1}{2} \times \epsilon_0 \times \dfrac{A}{d} = \dfrac{1}{2} \times C_0\)
Therefore;
\(The \ new \ capacitance \ C_{new} = \dfrac{1}{2} \times C_0\)
The potential difference, 'V', is given as follows;
\(C = \dfrac{Q}{V}\)
Therefore;
\(V = \dfrac{Q}{C}\)
Given that Q = Q₀, we get;
\(V = \dfrac{Q_0}{\dfrac{1}{2} \times C_0} = 2 \times \dfrac{Q_0}{C_0} = 2 \times V_0\)
∴ V = 2 × V₀
The new potential difference, V = 2·V₀
Therefore, after the plates are 2·d apart, the new capacitance and potential difference between the plates are;
1/2·C₀, 2·V₀.
At a distance of 2d, the potential difference will be twice the potential difference before while the capacitance will be half the value before.
Given to us
The capacitance on the parallel plate capacitor = C₀The area of the plate = AThe voltage on the battery = V₀The magnitude of the charge in the plate = Q₀The new distance between the plates = 2d What is Capacitance?We know capacitance can be written as,
\(C= \dfrac{\epsilon_0 A}{d}\)
where C is the capacitance,
A is the area,
d is the distance and
ε₀ is the electrostatic constant,
Capacitance before,\(C= \dfrac{\epsilon_0 A}{d}\)
Capacitance Afterwards,\(C= \dfrac{\epsilon_0 A}{2d}\)
\(C=\dfrac{1}{2} \times \dfrac{\epsilon_0 A}{d}\)
\(C=\dfrac{1}{2} \times C_0\)
What is Voltage(Potential difference)?We know that for the voltage we can write,
\(\rm Voltage = \dfrac{Charge}{Capacitance}\)
Voltage before\(V=\dfrac{Q_0}{C_0}\)
Voltage Afterwards\(V_{new} = \dfrac{Q_0}{C_{new}}\)
\(V_{new} = \dfrac{Q_0}{\dfrac{1}{2} \times C_0}\)
\(V_{new} = 2 \times\dfrac{Q_0}{C_0}\)
\(V_{new} = 2 \times V_0\)
Hence, At a distance of 2d, the potential difference will be twice the potential difference before while the capacitance will be half the value before.
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4. Coloca las partes en orden para formar una frase.
Se – La – se – transforma – sólo – no – ni – destruye – energía – crea – se
La energía no se crea ni se destruye solo se transforma
Explanation:
espero y te ayude
The phenomenon of pressure waves emanating from the bullet, causing damage remote from its path, is known as: A. capitation. B. cavitation. C. congruent.
The phenomenon of pressure waves emanating from the bullet, causing damage remote from its path, is known as B. cavitation.
Cavitation occurs when a bullet passes through a medium, like air or water, at high velocity, causing the medium to compress and expand rapidly. The rapid compression and expansion create a series of shock waves that can cause damage beyond the path of the bullet itself. Cavitation can cause damage to objects as well as tissue and organs, as the shock waves cause significant disruption. The effects of cavitation can be seen in other forms of high-velocity projectiles, such as missiles. Cavitation can also be used in underwater applications to create shock waves that can be used to clear debris or even kill marine life.
In summary, cavitation is the phenomenon of pressure waves emanating from a bullet, causing damage remote from its path. This phenomenon can cause considerable damage beyond the path of the bullet, as well as having practical applications in underwater engineering. Therefore the correct option is B
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If the force on a spring is 1 N and it stretched 0.5 m, what is the spring
constant?
A.4 N/m
B.0.2 N/m
C.2 N/m
D. 0.4 N/m
We know
\(\boxed{\sf Spring\:constant(K)=\dfrac{F}{x}}\)
\(\\ \sf\longmapsto K=\dfrac{1}{0.5}\)
\(\\ \sf\longmapsto K=2N/m\)
How do I solve this problem Determine the weight of the tram. The cable at left exerts a 30,000 N force. (The tram is attached to the cable so the tension in the left cable is not necessarily equal to the tension in the right cable.)
Free body diagram:
Here, T_1 is the tension in the left cable (T_1=30000 N; given), T_2 is the tension in the right cable, W is the weight of the tram.
The force equation in horizontal direction is given as,
\(T_1=T_2\sin (75\degree)\)Therefore, the tension in right cable T_2 is given as,
\(T_2=\frac{T_1}{\sin(75\degree)}\)Substituting all known values,
\(\begin{gathered} T_2=\frac{30000\text{ N}}{\sin (75\degree)} \\ \approx31058.28\text{ N} \end{gathered}\)The force equation in the vertical direction is given as,
\(W=T_2\cos (75\degree)\)Substituting all known values,
\(\begin{gathered} W=(31058.28\text{ N})\times\cos (75\degree) \\ \approx8038.47\text{ N} \end{gathered}\)Therefore, the weight of the tram is 8038.47 N.
derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
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A flasher generates 60° regular flashes in one minutes. Calculate (i) period of the flashes (ii) frequency of the flashing
(i) period of the flashes is, 1/60 minute/flash
(ii) frequency of the flashing is, 60 Hertz
What is frequency ?The frequency of a repeated event is the number of occurrences per unit of time. The common unit of expression is Hertz (Hz), which stands for cycles per second. For instance, a wave has a frequency of 1 Hz if it completes one cycle in one second. A wave moves faster and completes more cycles in a given period of time as its frequency increases.
Given that,
A flasher generates 60° regular flashes in one minutes
(i) The period of the flashes is the time it takes for one complete cycle of the flashing, or the time between two consecutive flashes. In this case, the flasher generates 60 flashes in one minute, so the period of each flash is given by:
Period = 1 minute / 60 flashes
= 1/60 minute
= 1/60 minute/flash
(ii) The frequency of the flashing is the number of flashes that occur in one unit of time, typically measured in Hertz (Hz), where 1 Hz = 1 cycle per second. To convert the period to frequency, we simply take the reciprocal of the period:
Frequency = 1 / Period
= 1 / (1/60 minute/flash)
= 60 flashes/minute
= 60 Hz
So the frequency of the flashing is 60 Hertz.
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A car starts from a spotlight and is traveling with a velocity of 10 m/s Ein
20 seconds. What is the acceleration of the car?
Answer:
ANSWER
Initial Velocity (u) = 10 m/sec
Acceleration (a) = 5 m/sec
2
Distance (s) = 30 m
Final velocity (v) = ??
Using Newton's Third law of Motion,
v
2
=u
2
+2as
v
2
=10
2
+2×5×30
v
2
=100+300
v
2
=400
v =
400
v = 20 m/sec
_____________________________
ANSWER =
FINAL VELOCITY = 20 m/sec
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Explanation:
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what is the kinetic energy in joules of a 1500kg car that is moving at a speed of 55 miles per hour (24.6m/s)
Answer:
453,870 J
Explanation:
KE = 1/2mv² = 1/2(1500 kg)(24.6 m/s)² = 453,870 J
the word medium is used to indicate a substance through which a force acts. What are some other meanings of medium that you use or hear in everyday life? Please I need help.
Push or pull are the word medium is used to indicate a substance through which a force acts other meanings of medium that you use or hear in everyday life.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.
f = Gmm/r²
Push or pull are the word medium is used to indicate a substance through which a force acts other meanings of medium that you use or hear in everyday life.
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30. The input force of a pulley system must move 8.0 m to lift a 3300-N engine a distance of 1.0 m. What is the
MA of the system? Show your work.
The MA or Mechanical Advantage of a pulley system can be calculated by dividing the output force (in this case, the weight of the engine, 3300 N) by the input force (the force needed to move the pulley system).
Which can be calculated by multiplying the distance moved by the force applied.
So, input force = distance moved x force applied = 8.0 m x F
Output force = weight of the engine = 3300 N
MA = output force / input force = 3300 N / (8.0 m x F)
We can simplify this by using the given information that the pulley system must move 8.0 m to lift the engine 1.0 m, which means the distance ratio is 8:1. Therefore, the force ratio must be the inverse, or 1:8.
So, input force = force applied = 3300 N / 8 = 412.5 N
MA = output force / input force = 3300 N / 412.5 N = 8
Therefore, the MA of the pulley system is 8. This means that for every 1 unit of force applied to the system, it can lift 8 units of weight.
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A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000 J of additional energy. If 3666.67 J of this energy must be used to overcome friction, what is the final speed of the car
The final speed of the car at the given conditions is 30.1 m/s.
The given parameters:
Mass of the car, m = 1700 kgVelocity of the car, v = 21 m/sTime of motion, t = 10 sAdditional energy provided by the engine, E₁ = 22,000 JEnergy used in overcoming friction, E₂ = 3,666.67 JThe change in the energy applied to the car is calculated as;
\(\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J\)
The final speed of the car is calculated as follows;
\(\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s\)
Thus, the final speed of the car at the given conditions is 30.1 m/s.
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(PLS ANSWER QUICKLY) Describe how a child is a combination of the traits of both parents. How does each parent contribute their traits? Will every trait from each parent appear in the child? What type of reproduction resulted in you? Write your response below in complete sentences.
Answer: The parents have recessive and dominant traits causing a child to be able to receive both a dominant and recessive trait.No the child won’t have the same trait from each parent, if one parent has blue eyes (recessive trait) and one parent has brown eyes (dominant trait) the child is more likely to receive the dominant trait.
Explanation:
Answer:
parents have recessive and dominant traits causing a child to be able to receive both a dominant and recessive trait.No the child won’t have the same trait from each parent, if one parent has blue eyes (recessive trait) and one parent has brown eyes (dominant trait) the child is more likely to receive the dominant trait.
Explanation:
There are 2 rocks sitting on 2 cliffs. One rock is sitting on a cliff that is 25 m high. The
other rock is sitting on a cliff that is 12 m high. Which rock has the greater gravitational
potential energy?
Explain.
The rock sitting on the cliff that is 25 m high has the gratest gravitational potential energy.
How do I determine the rock that has a greater potential energy?Potential energy is defined as the energy of an object by virtue of it's location. Mathematically, it is written as:
PE = mgh
Where
PE is the potential energym is the mass g is the acceleration due to gravityh is the heightTo determine the rock with the grater potential energy, we shall determine the potential energy of both rock assuming they have the same mass. Details below:
For rock sitting at 25 m high:
Mass (m) = 10 KgHeight (h) = 25 mAcceleration due to gravity (g) = 9.8 m/s² Potential energy (PE) = ?PE = mgh
PE = 10 × 9.8 × 25
PE = 2450 J
For rock sitting at 12 m high:
Mass (m) = 10 KgHeight (h) = 12 mAcceleration due to gravity (g) = 9.8 m/s² Potential energy (PE) = ?PE = mgh
PE = 10 × 9.8 × 12
PE = 1176 J
From the above calculation, we have:
Potential energy of rock at 25 m high = 2450 JPotential energy of rock at 12 m high = 1176 JThus, we can conclude that the rock sitting at 25 m high, has the gratest potential energy.
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explain why the vetcors can't be a closed diagram
Since they were viewing the movements of the vectors from various angles, the students discovered that the directions of the vectors didn't constantly point the same direction.
Vector addition is what?Combining two maybe more units to get a scalar sum is known as vector addition. By aligning the two nodes head to tail and dragging the wires from the nozzle exit to towards the free head, it is possible to determine the sum for two vectors.
What exactly does the word "vector" mean?A quantity or phenomena with independent attributes for size and direction is called a vector. Another meaning of the term is the mathematical or geometrical representation of a quantity. In nature, vector examples include force, weight, magnetic waves, and motion.
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First come first serve, solve for points
When a substance melts, it can exist in both the solid and liquid states, and when it boils, it can exist in either the liquid or gaseous states.
What are the Implications of Different Boiling Points?
The ability to separate liquids through distillation is one practical use of the various boiling points of alcohols and alcohol in relation to water and other liquids. A liquid is carefully heated throughout the distillation process to cause the more volatile chemicals to boil away.They can be gathered and used to distil alcohol, or they can be used to remove substances with lower boiling points from the original liquid to purify it. Alcohols can be distinguished from one another and from other chemical compounds using their distinct boiling points. Alcohol and water can be separated using distillation. Water has a boiling point of 212 F or 100 C which is higher than that of alcohol.To learn more about liquid states refer to:
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A jet flying north increases its velocity at a uniform rate from 138.5 m/s to 432.8 m/s in 47 seconds. Calculate the acceleration of the jet. a 12.16 m/s2 b 294.3 m/s c 6.26 m/s2 d 571.3 m/s
The acceleration of this jet is equal to: C. 6.26 m/s².
How to calculate the acceleration of this jet?In Physics, the acceleration of a physical object (jet) or body can be calculated by using this formula:
a = (V - U)/t
Where:
U represents the initial velocity.a represents the acceleration.V represents the final velocity.t represents the time measured in seconds.Substituting the given parameters into the formula, we have;
Acceleration, a = (432.8 m/s - 138.5 m/s)/47 seconds
Acceleration, a = 294.3/47
Acceleration, a = 6.26 m/s².
In conclusion, we can logically deduce that this jet has an acceleration of 6.26 meters per seconds square (m/s²).
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Two athletes are competing in upcoming competitions, a weightlifting meet and a marathon. which energy systems will each be primarily using, respectively?
Answer:
Explanation:
How did media attention affect Barack Obama's presidential performance?(A)(B)(C)(D)He made a concerted effort to listen to Congress' concerns about his policies.He decided to go on Fox News in an attempt to win over Republican voters.He started traveling the country to give speeches about his policy goals.He began meeting in private with Speaker of the House Nancy Pelosi.
Two athletes are competing in upcoming competitions, a weightlifting meet and a marathon. phosphagen and oxidative energy systems will each be primarily used, respectively.
As it is in charge of high-intensity, brief-duration activity, the phosphagen energy systems generate energy for jumping and sprinting. The quickest and most effective energy producer in muscle activity. Phosphagen metabolism is demonstrated by this system. It uses creatine phosphate to produce ATP (adenosine triphosphate, the chemical which provides energy for all body processes).
Energy is produced by the oxidative energy systems using 30% and 70% of carbs and lipids, respectively. When done for at least 150 minutes a week, aerobic exercise enables the body to experience physiological and health benefits.
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