Suppose two parallel-plate capacitors have the same charge Q, but the area of capacitor 1 is A and the area of capacitor 2 is 2 A.If the spacing between the plates, d, is the same in both capacitors, and the voltage across capacitor 1 is V, what is the voltage across capacitor 2?Express your answer in terms of V but do not type in the symbol "V"

All these people perform similar duties due to their similar profession.

All these People are the astronomers so they used various instruments that are present at their time in order to study the heavenly bodies such as stars and planets present in the sky. They also analyze their findings with the help of researches and experiments. They also develop theories that are based on personal observations and tested the theories of other astronomers in order to verify their theories.

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Answer:

3ft/s²

Explanation:

\(a = \frac{60 - 45}{5} = 3ft \div {s}^{2} \)

Answer:

it is no darker than any other part of the moon surface

Explanation:

Answer:

this stuff hard no cap

Explanation:stop cheating cuhhh

Answer:

To solve this problem, we can use the formula:

d = (v^2)/(2μg)

d = distance traveled

v = speed of the car

μ = coefficient of kinetic friction

g = acceleration due to gravity

First, let's calculate the distance traveled when the car is traveling at 23 m/s:

d = (23^2)/(2*0.7*9.81) ≈ 67.97 meters

Now, let's calculate the distance traveled when the car is going twice as fast (46 m/s):

d = (46^2)/(2*0.7*9.81) ≈ 271.88 meters

Therefore, the car would travel approximately 271.88 meters if it were going twice as fast.

Answer:

V2 = (V1 - u) / (1 - V1 u / c^2)

V1 = speed of ship in observer frame = .99 c    to right

u = speed of frame 2 = -.99 c   to left relative to observer

V2 = speed of V1 relative to V2

V2 = (.99 - (-.99 ) / (1 - .99 (-.99)) c

V2 = 1.98 / (1 + .99^2) c = .99995 c

Answer:

The following explanatory section gives an explanation of this question.

Explanation:

Answer:

the answer is 3,888.7

Explanation:

Hope this answer helped!:)

Answer:

Significant figures have a few rules about 0s and you should research but simply, for example say round 27.879 to 3 significant figures you round up until you have 3 numbers that aren't 0s so it would be 27.9.

SI units are the international system of units.

Answer:

SI units refer to the International System of Units. These are the standard units that measurements are typically given in. For example, the SI unit for time is seconds, meters for distance, kg for mass, etc.

Significant figures are the number of notable digits given for a measurement. For example, let's say you measured a piece of metal to be exactly 3.00 meters long. The value 3.00 has three significant figures, where as 3 only has one significant figure. Larger amounts of significant figures indicate a more precise measurement. In this case, by writing 3.00 instead of 3, you're telling me that you measured that piece of metal to be precisely 3.00 meters long.

( a ) The magnitude of the impulse given to the meteor is 2,480,000 kg.m/s at 22⁰ from original position.

( b ) The magnitude of the force applied to the meteor is 55,111.1 N.

The magnitude of the impulse given to the meteor is calculated from the change in momentum of the meteor.

Mathematically, the formula for Impulse is given as;

J = ΔP

J = m (vf - vi )

where;

The magnitude of the impulse given to the meteor is calculated as follows;

J = ( 310, 000 kg ) ( 27 m/s - 35 m/s )

J = ( 310, 000 kg ) ( -8 m/s )

J = -2,480,000 kg.m/s

| J | = 2,480,000 kg.m/s

The magnitude of the force applied to the meteor is calculated as follows;

F = ma = J / t

where;

F = ( 2,480,000 kg.m/s ) / ( 45 s )

F = 55,111.1 N

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Answer:

A) ≥ 325Kpa

B) ( 265 < Pe < 325 ) Kpa

C) (94 < Pe < 265 )Kpa

D)  Pe < 94 Kpa

Explanation:

Given data :

A large Tank : Pressures are at 400kPa and 450 K

Throat area = 4cm^2 ,  exit area = 5cm^2

a) Determine the range of back pressures that the flow will be entirely subsonic

The range of flow of back pressures that will make the flow entirely subsonic

will be ≥ 325Kpa

attached below is the detailed solution

B) Have a shock wave

The range of back pressures for there to be shock wave inside the nozzle

= ( 265 < Pe < 325 ) Kpa

attached below is a detailed solution

C) Have oblique shocks outside the exit

= (94 < Pe < 265 )Kpa

D) Have supersonic expansion waves outside the exit

= Pe < 94 Kpa

Answer:

The second chart seems to be correct

Explanation:

Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

Answer:

F = m a = G m M / R^2      gravitational force between objects of mass M and m

a = G M / R^2         gravitational acceleration due to planet of mass M

a2 / a1 = M2 R1^2 / (M1 R2^2)

given M2 = 1/4 M1      and  R2 = 1/4 R1

a2 / at = (M2 / M1) * (R1 / R2)^2 = 1/4 * 4*2 = 4

a2 the acceleration on planet x would be 4 times  that on earth

Answer:

the answer is equal to non zero

The tension T₁ on the left side of the rope is 698 N.

Equilibrium is a State of balance in which opposing forces are balanced, of when there is no net change in system. It is a State of rest or balance due to the equal action of opposing forces.

\($$From equilibrium along $x$ direction$$\begin{aligned}T_1 \sin 15 & =T_2 \cos 10 \\\frac{T_1}{T_2} & =\frac{\cos 10}{\sin 15} \\T_1 & =3.8 T_2\end{aligned}\)

\($$From equilibrium along y direction$$\begin{aligned}T_1 \cos 15+T_2 \sin 10 & =m g \\\left(3.8 T_2\right) \cos 15+T_2 \sin 10 & =(72)(9.8) \\T_2 & =\frac{(72)(9.8)}{(3.8) \cos 15+\sin 10} \\& =183.55 \mathrm{~N} \\& =184 \mathrm{~N}\end{aligned}\)

\($$From equation,$$\begin{aligned}T_1 & =3.8 T_2 \\& =3.8(183.55 \mathrm{~N}) \\& =698 \mathrm{~N}\end{aligned}$$\)

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Complete question:

A 72 Kg Man Is Being Pulled Away From A Burning Building As Shown In The Figure. T1= 15 Degrees On The "Y" Access T2= 10....

Calculate the tension T1 on the left side of the rope, in newtons, if the man is in static equilibrium.

Calculate the tension T2 on the right side of the rope, in newtons, if the man is in static equilibrium.

The perceived frequency when the fire truck is moving toward you and away from you will be 370 Hz and 329.59 Hz respectively.

A sudden change in the frequency due to the distance between the objects and source is explained by the doppler effect.

As the source and observer travel toward each other, the frequency of sound, light, or other waves increases or decreases.

The perceived frequency when the fire truck is moving toward you;

\(\rm r' = (\frac{v+v_0}{v}) V \\\\ \rm r' = (\frac{343+20}{343}) 350 \\\\ r' =370.4 \ Hz\)

The perceived frequency when the fire truck is moving away from you;

\(\rm r' = (\frac{v-v_0}{v}) V \\\\ \rm r' = (\frac{343-20}{343}) 343 \\\\ r' =329.59 \ Hz\)

Hence, the perceived frequency when the fire truck in cases 1 and 2 will be 370 Hz and 329.59 Hz.

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Humans would need a breathable environment like that on Earth in the living section of a colony on Venus in order to survive. Nitrogen, oxygen, and trace amounts of other gases, such as carbon dioxide, make up the majority of the atmosphere on Earth.

The clouds are made of sulfuric acid, and the atmosphere is primarily carbon dioxide, the same gas that causes the greenhouse effect on Venus and Earth. And the heated, high-pressure carbon dioxide acts corrosively at the surface.

For instance, compared to Earth, which has 99% nitrogen and oxygen in its atmosphere, Venus and Mars both contain more than 98% carbon dioxide and nitrogen.

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The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:

k = Q / (A * ΔT * L) = Rth * (A * ΔT)

Reorganizing this equation gives:

Rth = k / (A * ΔT)

The given information in the problem is:

Rate of heat flow (Q) = 14.0 watts

Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C

Temperature difference (ΔT) = 28°C

Substituting these values into the equation, we have:

k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK

So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.

The machine that can turn 1000J of heat directly into 1000J of electricity goes against the second law of thermodynamics. The correct option is 2.

The laws of thermodynamics

The three laws of thermodynamics can be defined as follow:

First Law: The first law of thermodynamics, also known as the law of conservation of energy, asserts that energy cannot be created or destroyed, only transferred or converted from one form to another. This law forms the foundation of energy conservation and the concept of internal energy.

Second Law: The second law of thermodynamics asserts that the total entropy of a system and its surroundings always increases over time. It describes the concept of irreversibility in nature, meaning that some processes cannot be reversed.

The third law of thermodynamics postulates that the entropy of a perfect crystal at absolute zero temperature is zero. This law serves as a benchmark for entropy calculations, allowing scientists to determine the entropy of a substance at any temperature above absolute zero.The machine mentioned in the question, which can turn 1000J of heat directly into 1000J of electricity, violates the second law of thermodynamics. According to the second law of thermodynamics, it is not possible to convert heat into electricity with 100% efficiency. Some heat must be lost to the surroundings as waste heat during the conversion process. Therefore, the machine that can turn 1000J of heat directly into 1000J of electricity is not allowed.

Option 2 is correct answer

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Answer:

the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

Explanation:

We can analyze this exercise from several points of view, if we use Newton's second law

Bowling ball

           F = M a₁

pingpongg ball

           F = m a₂

as the forces the same

          M a₁ = m a₂

          a₂ = \(\frac{M}{m}\) a₁

Since the mass of the bowling ball is much greater than the ping pong ball,

          a₂ »a₁

so the acceleration of the ping pong ball is much greater than the acceleration of the bowling ball.

If we use the relationship of momentum and momentum, assuming that the time for the two cases is the same and that both start from rest

Bowling ball

           I = F t = Δp

           I = M (v₁ - v₀)

Ping pong ball

           I = F t = Δp

           I = m (v₂ -v₀)

the impulse itself

          M v₁ = m v₂

          v₂ = \(\frac{M }{ m}\) v₁

so we conclude that the speed of the ping pong ball is much greater than the speed of the bowling ball.

In conclusion the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Answer:

sorry I don't know the answer

If the engine of a boat on a river is turned off while the boat is moving with a steady speed, several things would happen Loss of propulsion,Drifting,Loss of steering control and Potential hazards.

Loss of propulsion: Without the engine running, the boat would lose its power source for propulsion. The boat would gradually slow down and eventually come to a stop unless other external forces, such as currents or wind, continue to move it.

Drifting: Once the boat comes to a stop, it would start to drift with the current of the river or be affected by wind forces. The direction and speed of the drift would depend on the strength and direction of the current or wind.

Loss of steering control: When the engine is turned off, the boat's steering mechanism, such as a rudder, would also lose power. Without the ability to steer, the boat would follow the course determined by the river's current or the wind direction.

Potential hazards: Depending on the surroundings and the current conditions, there could be potential hazards for a boat that is no longer under power. These hazards might include other vessels, obstacles, shallow areas, or strong currents. The boat's crew would need to take appropriate actions to ensure the safety of the boat and its occupants.

It's important to note that the specific behavior of the boat after the engine is turned off can vary depending on factors such as the size and design of the boat, the strength and direction of the current, and the presence of wind or other external forces.
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This question involves the concepts of the equation of motion and elastic collision.

The velocity of the ball as it rebounds from the floor will be "14 m/s".

The elastic collision is the one during which the momentum and kinetic energy of a body remain conserved. Hence, the velocity of the body also remains constant. Therefore, the rebound velocity of the ball will be the same as the striking velocity of the ball. This can be calculated using the third equation of motion.

\(2gh=v_f^2-v_i^2\)

where,

Therefore,

\((2)(9.81\ m/s^2)(10\ m)=v_f^2-(0\ m/s)^2\\v_f=\sqrt{196.2\ m^2/s^2}\\\\v_f=14\ m/s\)

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An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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Answer: Patsy is eager to learn how to bake a cake but does not know how to do it.

Explanation: i picked this and it is correct, you’re welcome:)