Synthesis of butyl-5-iodohexanoate

The chart used by moseley was more accurate at predicting where new elements would be placed, because Moseley's work chart based the atomic number which is definable property, measurable through experimentation not chemical properties or atomic mass as mendeleev do.

In his periodic table, Mendeleev left some notable gaps, such as the gaps just below aluminum and silicon, which covered elements as yet to be discovered. When these elements were later discovered, the properties of the new elements were found to match Mendeleev's predictions. The main difference between Mendeleev's and Moseley's arrangement of the elements on the periodic table is that Mendeleev arranged the elements in ascending order of atomic weight, whereas Moseley arranged them in ascending order of atomic number. Moseley diagrams were based on the use of atomic numbers rather than chemical properties of the elements. The similarity of products from the same period often caused problems when creating orders. Moseley's work made it possible to change atomic number from an arbitrary choice to a definable property that can be measured through experimentation.

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Answer:

The triple bonds are the strongest and hence the shortest. Then comes double bonds which are of intermediate strength between the triple and single bonds. And finally the single bonds are weaker than the other two.

This way, Triple bonds are the shortest. Then comes double bonds. Finally, single bonds are the longest among the three.

The order of bond lengths is given as,

Triple bond < Double bond < Single bond

According to the concept of significant figures,0.002  molecules of CO₂ per hundred molecules of air  are expressed as a concentration as 2 parts per thousand .

Significant figures are used for establishment  of a number which is presented in the form of digits. These digits give a meaningful representation  to the numbers.

The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:

1)All non-zero digits are significant .

2)All zeroes which occur between non-zero digits are significant.

3)All zeroes to the left and right of  a non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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Answer:

C

Explanation:

The order of increasing size are electron, neutron, nucleus and atom.

The size of electron is the smallest among the given particles which followed by neutron that is bigger in size from electron but smaller than nucleus. Proton and neutron are located in the nucleus of an atom so it is bigger in size than neutron.

Atom is the largest among the given substances in which nucleus is present at the center and electrons are revolving around the nucleus in fixed orbits so we can conclude that electron is the smallest and atom is the largest particle.

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Answer: C

Explanation:its on unit test

Answer:

C is  the correct answer

Explanation:

Answer:

Titrant and analyte is a pair of acid and base. ... Equivalence point: point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution. At the equivalence point in an acid-base titration, moles of base = moles of acid and the solution only contains salt and water.

Explanation:

Answer:

The reaction is nutride-cullic and sees all math about our lives.

Explanation:

The limiting component or reactant in a chemical process is the one that controls how much product is created. Because metals and compounds respond in a balanced chemical equation according to their mole ratios, a limiting reactant is necessary.

When a chemical reaction is complete, the limiting reagent—also known as the limiting reactant or limiting agent—is the component that has been completely consumed.  Since the process cannot proceed without this reagent, the quantity of product that can be produced is constrained.

Excess reagents or surplus reactants are any chemicals that are present in amounts greater than those necessary to cause a reaction with the limiting reagent (sometimes abbreviated as "xs").

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The complete Lewis structure of lactic acid is:
H      H
|      |
H-C-C-OH
|      |
H-C-C=O
|      |
H      OH

When lactic acid reacts with water, one of the OH groups will dissociate and form H+ ions. The complete Lewis structure of the product, H3O+, is:
      H
      |
H      O-H
|      ||
H-C-C=O
|      |
H      OH

(b)
To prepare 100.00 mL of a 1.00 M aqueous solution of NH4Cl, we need to dissolve 5.33 g of NH4Cl in distilled water. Here are the steps:

(1) Use the balance to weigh out 5.33 g of NH4Cl(s).

(2) Carefully transfer the solid into a 100 mL volumetric flask.

(3) Add distilled water up to the etched line.

(4) Mix the solution thoroughly until all the solid is dissolved.
You can use a stirring rod to help dissolve the NH4Cl.
The 50 mL buret, 100 mL graduated cylinder, and 100 mL pipet are not needed for this procedure.

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Sodium phosphate and calcium chloride reacts to form sodium chloride and calcium phosphate. If we have 379.4 grams of calcium chloride and an excess of sodium phosphate, we can make 353.3g of calcium phosphate.

The balanced chemical equation of sodium phosphate and calcium chloride to form sodium chloride and calcium phosphate is given as

2Na₃PO₄ + 3CaCl₂ → 6NaCl + Ca₃(PO₄)₂

We will convert given grams of calcium chloride into moles.

Using mol ratio, the moles of calcium phosphate are calculated and converted to grams as:

we know that,

Molar mass of calcium chloride is 110.98 gram /mol

And molar mass of calcium phosphate is 310 gram/mol.

By using dimensional analysis we get:

=379.4 g CaCl₂ (1 mol CaCl₂/ 110.98gCaCl₂)(1 molCa₃(PO₄)₂/3 molCaCl₂ )(310gCa₃(PO₄)₂/1 mol Ca₃(PO₄)₂)

=353.3 g Ca₃(PO₄)₂

Thus, 353.3 grams of calcium phosphate can be formed from the reaction

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The complete question should be:

Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium chloride and an excess of sodium phosphate, how much calcium phosphate can you make?

The presence of electron-withdrawing or electron-donating substituents on the aromatic ring affects an aldehyde's reactivity in a reaction as an electrophile. In the contrast provided, 4-cyanobenzaldehyde is probably a greater electrophile than 4-methoxy benzaldehyde.

This is so because the methoxy group \((-OCH_3)\) in 4-methoxy benzaldehyde is less effective at pulling electrons than the cyano group (-CN) in 4-cyanobenzaldehyde. By withdrawing electron density, the cyano group is predicted to make the aldehyde carbonyl group more electrophilic and hence more vulnerable to nucleophilic assault.

In contrast, the methoxy group in 4-methoxy benzaldehyde is a weaker electron-donating group. As a result, it might lessen the electrophilicity of the aldehyde carbonyl group by providing it with electron density, making it less reactive toward nucleophiles.

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The mass number is the atomic mass rounded to a whole number, i.e., which is a value that rounds the atomic weight to a near number.

The expression mass number is used in chemistry to denote the total amount of subatomic particles i.e. atomic protons and neutrons, which are present in a given atom (for example hydrogen has only one proton and one neutron).

Therefore, with this data, we can see that mass number denotes the overall amount of protons and neutrons present in a given atom, which is equal to one in the hydrogen atom

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assuming all of the xenon has reacted, The formula of the product is XFe2

In this situation, xenon and fluorine are reacting to form a binary compound. The reaction can be viewed by the below balanced chemical equation:

Xe + 2F2 -> XeF2

The reactants, xenon and fluorine, are initially present at partial pressures of 1.24 atm and 10.10 atm, respectively.Since the reactants are initially present at a total partial pressure of 1.24 atm + 10.10 atm = 11.34 atm, and the final partial pressure of fluorine is 7.62 atm, the partial pressure of the xenon fluoride compound must be 11.34 atm - 7.62 atm = 3.72 atm.

we can set up the following equation:1.24 atm + 10.10 atm = 3.72 atm + 7.62 atm

Solving for the number of moles of fluorine gives:

10.10 atm - 3.72 atm = 7.62 atm

= 6.38 atm

Since the pressure of a gas is directly proportional to the number of moles of the gas present,

n = P / (R * T

= 6.38 atm / (0.08206 Latm/molK * 298 K / 100 mL)

= 0.5 molThe number of moles of xenon present can be calculated in a similar way:

n = P / (R * T

= 1.24 atm / (0.08206 Latm/molK * 298 K / 100 mL)

= 0.05 mol

Since the ratio of moles of xenon to moles of fluorine in the product is 1:2, the formula of the product must be XeF2.

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Answer:

0.02 m

Explanation:

∆U = q + w

w = ∆U - q = (1380 - 2040) J = -660 J

w = -p∆V = -pA∆h

∆h = -w/(pA)

p = 1 bar × (100000 Pa/1 bar) = 100000 Pa

∆h = -(-660 J)/(100000 Pa×0.33 m²) = 0.02 m

A gas is contained in a horizontal cylinder with a moveable piston of cross-sectional area 0.33\text{ m}^20.33 m 2. The distance through which the piston moves is 0.02 m.

Among other related systems, pistons are found in reciprocating engines, reciprocating pumps, gas compressors, hydraulic cylinders, and pneumatic cylinders. It is the moving part that is enclosed in a cylinder and sealed off from the gas by piston rings.

The piston, which is a part of combustion engines, transforms the energy released during combustion into a mechanical action and sends it, via the piston pin and connecting rod, to the crankshaft as a torsional force. The piston in the cylinder goes up and down when the engine is running.

The equation given by

∆ U = q + w

w = ∆ U - q

= ( 1380 - 2040 )

J = -660 J

w = -p∆V

= -pA∆h

∆h = -w / (pA)

p = 1 bar × ( 100000 Pa / 1 bar )

= 100000 Pa

∆h = - ( -660 J) / ( 100000 Pa × 0.33 m² )

= 0.02 m

Thus, The distance through which the piston moves is 0.02 m.

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The given reaction involves an SN1 reaction, where the alkyl halide reacts with water to form an alcohol and hydroxyalkyl radical. SN1 reactions are known to be relatively slow and can lead to the inversion of configuration if the substrate is chiral. Therefore, the best option is (C) SN1 with inversion of configuration.  

In the given reaction, an alkyl halide reacts with water to form an alcohol and hydroxyalkyl radical. This is an example of an SN1 reaction, where the alkyl halide acts as a nucleophile and attacks the carbon atom of the alkyl group. The resulting bond between the alcohol and the hydroxyalkyl radical is a single bond.

Given the information provided, the reaction can be described as follows:The major product of this reaction is an alcohol, so it is likely an SN1 reaction. However, since the reaction involves the formation of a hydroxyalkyl radical, the reaction cannot lead to racemization. Therefore, the best option is (C) SN1 with inversion of configuration.  

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Answer: 144 inches

Explanation: 4 yards is 12 feet, so multiply 12 inches by 12 feet and you get 144 inches

Answer:

True

Explanation:

Answer:

Only when a podaj is connected with equal terms with a wjonie.( .. / 2 p.a)a) S

Explanation:

hope this helps :)

The volume of water that must be add is 20 mL. Volume of water that must add is new volume after dilution minus initial volume.

As per data given:

Initial volume (V1) = 40 mL = 0.040 L

Initial molarity(C1) = 9.0 M

New molarity (C2)= 6.0 M

As we want to know to the new volume of water(V2). We have to use dilution formula where the formula is C1 x V1 = C2 x V2. So, the calculation would be:

9.0 x 0.040 = 6.0 x V2

V2 = 0.06 L

V2 = 60 mL

Since the addition water is the difference between V2 and V1:

Volume add = V2 -V1

Volume add = 60 - 40

Volume add = 20 mL

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Answer:

Helium

Explanation:

I believe helium is what your are looking for, you didn't quite make it clear what you wanted but hope this can be of some use.

Helium has the smallest atomic radius. This is due to trends in the periodic table, and the effective nuclear charge that holds the valence electrons close to the nucleus.

Could I have branliest, heart with 5 stars

Thanks.

A half cell is one of the two electrodes in a galvanic cell or simple battery.

Find the value of the complete cell electrode potential (E°)?

Look up the standard reduction potentials for Br and Mg.  I find the following:

Mg2+ + 2e- ==> Mg(s)  Eº = -2.38 V

Br2(l) + 2e- ==> 2Br-(aq)  Eº = 1.07 V

Accordingly, Br2 will be reduced and Mg(s) will be oxidized in order to have a positive potential.

Br2 + 2e- ==> 2Br-

Mg ==> Mg2+ + 2e-

------------------------------------

Br2 + Mg ==> Mg2+ + 2Br-  Eº = 1.07 + 2.38 = 3.45 V

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Answer:

An equal number of atoms must be on both sides of the equation.

Explanation:

Answer:

Those types of notations indicate isotopes of an element germanium. so Ge 72 and Ge 73 are called isotopes.

they are different with their number of neutrons while having the same atomic number.

and so - Difference - Neutron Number

- Similarity - Atomic Number.

Answer:

The weight of 3.45 moles of carbon dioxide has been 151.8 grams.

Moles can be calculated as the mass of solute present with respect to the molecular mass of the solute.

Moles can be expressed as:

Moles = \rm \dfrac{weight}{molecular\;weight}

molecularweight

weight

The molecular weight of carbon dioxide has been 44 grams/mol.

The given moles of carbon dioxide = 3.45 moles.

3.45 mol = \rm \dfrac{weight}{44\;g/mol}

44g/mol

weight

Weight of carbon dioxide = 3.45 \times× 44 grams

Weight of carbon dioxide = 151.8 grams.

The weight of 3.45 moles of carbon dioxide has been 151.8 grams.

Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.

To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:

moles = concentration × volume

Given:

Concentration of AgNO3 solution = 0.500 M

Volume of AgNO3 solution = 150 mL

First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).

1 L = 1000 mL

Therefore, the volume of the AgNO3 solution in liters is:

150 mL × (1 L / 1000 mL) = 0.150 L

Now we can calculate the moles of AgNO3 using the formula:

moles = concentration × volume

moles = 0.500 M × 0.150 L

moles = 0.075 mol

So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.

Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).

From the balanced chemical equation:

2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)

We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.

Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:

moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol

To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:

Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol

mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4

mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g

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Answer:

In the world? I would say no, but at the same time there are a lot of variables to consider in this. But I'd say no. Just my opinion.

Explanation

Answer:

False the amount of water on earth has decreased over the years

Explanation:

Answer:

pOH = 3.18

Explanation:

The equilibrium of a weak base as NX3 is:

NX3(aq) + H2O(l) ⇄ HNX3⁺(aq) + OH-(aq)

Where the equilibrium constant, Kb, is:

Kb = 2.5x10⁻⁶ = [HNX3⁺] [OH-] / [NX3]

As both HNX3⁺ and OH- ions comes from the same equilibrium, their concentrations are the same, that is:

[HNX3⁺] = X

[OH-] = X

And: [NX3] = 0.175M:

2.5x10⁻⁶ = [X] [X] / [0.175M]

4.375x10⁻⁷ = X²

X = 6.61x10⁻⁴M = [OH-]

As pOH = -log [OH-]

Answer:

;,knbbbknnbkhbln bhbj k; b; m j

Explanation: