Terms must be like terms in order to _______ or______. Terms do not have to be like if we are ______ or ______.

A system of equations for this problem can be written as:

x + y = 10 (1) equation for the total number of herbs planted

0.50x + 0.25y = 3 (2) equation for the total cost of the herbs

Where x is the number of basil plants and y is the number of mint plants.

Using substitution, we can solve the system of equations.

Solving equation (1) for x, we get x = 10 - y

Substituting this into equation (2) we get:

0.50(10 - y) + 0.25y = 3

5 - 0.50y + 0.25y = 3

5 = 0.75y + 3

0.75y = -2

y = -2/0.75 = -8/3

So, Eden planted -8/3 mint plants, which doesn't make sense, as a fraction of plant are not possible. This implies that either the number of plants or the amount spent are incorrect or something is missing in the problem description.

Answer:

10.4476119402

Step-by-step explanation:

If you want a reasonable answer it would be 10.44 or 10.4!

Answer:

36 ounces or if over 150 lbs drink more water than 36 ounces

Step-by-step explanation:

For every pound of sweat you lose you need to drink 16 ounces of water!

Answer:

(a) 320 cm²

(b) 75 cm³

Step-by-step explanation:

The scale factor from A to B is 8/4 = 2.

The scale factor of the areas is 2² = 4.

The scale factor of the volumes is 2³ = 8.

(a)

80 cm² * 4 = 320 cm²

(b)

600 cm / 8 = 75 cm³

The required surface area of shape B is 320 cm² and the volume of shape A is 75 cm³.
               

Given that,
The base of shape A is a circle with a radius of 4 cm
The base of shape B is a circle with a radius of 8 cm.

Surface area is defined as the area of the surface that is uncovered.

Here,
1)
The scale factor of area = 8²/4² = 4
The surface area of shape B = 4 surface area of shape A.
The surface area of shape B = 4 * 80
                                                = 320 cm²

2)
The scale factor of volume = 8³ / 4³ = 8
The volume of shape B = 8 *  the volume of shape A.
The volume of shape A = 600 / 8
The volume of shape A = 75 cm³

Thus, the required surface area of shape B is 320 cm² and the volume of shape A is 75 cm³.
   

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PYRAMIDS Miko and Tyler are visiting the Great Pyramid in Egypt then the height of the pyramid is about 14.2 feet.

We have two right triangles. We need to see as the

worth of x, yet before we do this, we want to see as the

length of BC.

In  ΔABC , the side inverse of  ∠ACB is AB  (or x)

also, the adjacent side is BC, thusly we will pick

the tangent function.

tan50 = \(AB/BC\)

Substitute and tackle for x.

tan50° = \(x /BC\)

             x = BCtan50°

Tackle for x in ΔABD. The side inverse the given 40

degree angle is x and the adjacent side is BC+5,

in this manner we will again utilize the tangent function to

tackle for x.

tan40° = \(x/BC+5\)

(BC + 5)tan40 = x

use substitution to find BC.

tan40°(BC+5)=BCtan50°

BCtan40°+5tan40°=BCtan50°

5tan40°= BCtan50°- BCtan40°

5tan40°=BC(tan50°-tan40°)

5tan40°/(tan50°-tan40°) = BC

substitute the value of BC in one of the original equation to find x.

x ≈ (11.90) tan50°

x ≈ 14.2

The height of the pyramid is about 14.2 feet.

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Answer:

\(x < - 21\)

Step-by-step explanation:

1. Multiply both sides by 3.

\(x < - 7 \times 3\)

2. Simplify 3 × 7 to 21.

\(x < - 21\)

therefor, the answer is x < -21

i had this question and my answer was b and it was right so maybe try b

A group of two or more inequalities in one or more variables is referred to as a system of inequalities. The system of inequalities graphed is y > x² - 4 and y < x² + 6.

A group of two or more inequalities in one or more variables is referred to as a system of inequalities. When a problem demands a variety of solutions and those solutions must satisfy many constraints, systems of inequalities are used.

A system of inequalities is one where the total number of inequalities is greater than or equal to the number of variables.

A system of inequalities may have,

The equation of the vertical parabola with y-intercept -4 is equal to

y = x² - 4.

The solution of the inequality is the shaded area above the dashed line.

The inequality must be y > x² - 4

2) The equation of the vertical parabola with y-intercept 6 is equal to y = x² + 6.

The solution of the inequality exists the shaded area below the dashed line. The inequality must be y < x² + 6

The system of inequalities graphed is

y > x² - 4

y < x² + 6

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Answer:

I see no choices for variable expression.

Step-by-step explanation:

y = 4(5 + x)  [four times the sum of five and a number]

The slope of a line in the plane containing the x and y axes is generally represented by the letter m, and is defined as the change in the y coordinate divided by the corresponding change in the x coordinate, between two distinct points on the line.

The computation shows that the placw on the hill where the cannonball land is 3.75m.

To find where on the hill the cannonball lands

So 0.15x = 2 + 0.12x - 0.002x²

Taking the LHS expression to the right and rearranging we have:

-0.002x² + 0.12x -.0.15x + 2 = 0.

So we have -0.002x²- 0.03x + 2 = 0  

I'll multiply through by -1 so we have

0.002x² + 0.03x -2 = 0.

This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.

The second solution y = 0.15 * 25 = 3.75

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Complete question:

The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

Answer:

Number 1

Step-by-step explanation:

Because the absolute Value of A is less then the value of B

The Mae takes the absolute values of the forecast errors to ensure they don't cancel each other out.

By considering only the magnitude of the errors, the MAE (Mean Absolute Error) provides a measure of the average deviation between forecasts and actual values.

To ensure that forecast errors don't cancel each other out, the Mean Absolute Error (MAE) calculation involves taking the absolute values of the errors. The MAE is a commonly used metric to measure the accuracy of a forecasting model.

Forecast errors represent the differences between predicted values and actual values. These errors can be positive or negative, depending on whether the forecast overestimates or underestimates the actual value. By taking the absolute values, the direction of the error is disregarded, and only the magnitude of the deviation is considered.

By summing up the absolute values of all the forecast errors and dividing by the number of observations, the MAE provides an average measure of how far the forecasts deviate from the actual values. It allows for the evaluation of the average absolute magnitude of the errors without considering their direction.

In summary, the Mean Absolute Error (MAE) takes the absolute values of the forecast errors to ensure they don't cancel each other out. This approach allows for a measurement of the average deviation between forecasts and actual values by considering only the magnitude of the errors.

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Answer:

7(x+5)

Step-by-step explanation:

The greatest common factor is 7

7*x + 7*5

Factor out the 7

7(x+5)

It is C 50 Hopefully this is right

Answer:

60 or D

Step-by-step explanation:

The Range is the difference between the lowest and highest values.

80-20= 60

Answer:

x is greater than or equal to -4 but less than or equal to 4

Step-by-step explanation:

The "domain" is all of the x values on the line. But there are an infinite amount of x-values there, so it must be written as that.

Answer:

See below.

Step-by-step explanation:

The domain is simply the range of x-values the graph encompasses. From the given graph, we can see that the graph stretches from x=-4 to x=+4.

However, note that the graph does not include -4 since the point is an open circle. However, it does include +4 since the point is a closed circle. Therefore, the domain of this graph is:

In interval notation:

\((-4,4]\)

(Parenthesis on the left because -4 is not included. Brackets on the right because +4 is included.)

The union of two or more events is a single event that represents all the outcomes that belong to at least one of the original events.

16) It is often represented using the symbol "U" or "∪". For example, if event A is "rolling a 3 on a die" and event B is "rolling a 4 on a die", the union of A and B would be "rolling a 3 or a 4 on a die".

17)  The intersection of two or more events is a single event that represents all the outcomes that belong to all of the original events. It is often represented using the symbol "∩". For example, if event A is "rolling an even number on a die" and event B is "rolling a number greater than 3 on a die", the intersection of A and B would be "rolling a 4 on a die".

18)  The union of two or more events represents all the outcomes that belong to at least one of the original events, while the intersection of two or more events represents all the outcomes that belong to all of the original events. The union is a "larger" event that includes all outcomes from the original events, while the intersection is a "smaller" event that only includes outcomes that belong to all of the original events.

For example, if event A is "rolling an odd number on a die" and event B is "rolling a number less than 4 on a die", the union of A and B would be "rolling a 1,3, or a 2 on a die" while the intersection of A and B would be "rolling a 1 or a 3 on a die".

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Jenna and Mia arrived at the same answer because both the methods they have adopted are correct.

Given solution of a question done by two people.

Jenna's method

5(30+4)

(5)(30)+(5)(4)

150+20=170

Mia's method

5(30+4)

5(34)=170

We are required to find why they have achieved at the same answer.

Jenna and Mia have achieved at the same answer because they both have adopted the right method.Jenna's method is the equation in its simplest form. Addition of that is easily understood. While Mia's method is just valid as Jenna's some people may have trouble remembering the steps of multiplication within parantheses as well as being able to look at large multiplication problem and automatically knowing the answer or being able to get the answer as fast as simple addition.

Hence Jenna and Mia arrived at the same answer because both the methods they have adopted are correct.

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Answer:

3x +y = 13

Or, x=13-y/3......eqn(i)

Now putting the value of x

2x - y = - 1

Or, 2(13-y/3) - y = - 1

Or, 26 - 2y /3 - y = -1

Or, 26 - 2y - 3y = - 3

Or, 26 - 5y = - 3

Or, - 5y = - 3 - 26

Or,y = - 39/ (- 5)

Or, y = 7.8~

I'm not sure,, is there a paper or written length of the sharks,, or is it going off of searching it on the internet?

You haven't given the length of each shark so we can't really calculate the total length of the 7 sharks but I'll just give a strategy to find it.

let \(x\) be the length of the blacktop sharks and let \(y\) be the length of the tiger sharks. In order to figure out their total length, you can use this formula:

\(3x\ +\ 4y\ =total\ length\ of\ sharks\)

Answer:

36n = 360

Step-by-step explanation:

A dozen is 12

3 dozen is 3*12 = 36

36 * n boxes = 360

36n = 360

Whether the population standard deviation is known or unknown affects the expression used for the interval estimate. Hence, option c. is the right response.

The expression used to compute an interval estimate of a population parameter (such as the mean) depends on the sample size, whether there is sampling error, and whether the population has an approximately normal distribution.

However, whether the population standard deviation is known or unknown also affects the expression used for the interval estimate.

If the population standard deviation is known, a z-score can be used in the calculation, whereas if it is unknown, a t-score is used and the sample standard deviation is used as an estimate for the population standard deviation. Therefore, c is the factor that does affect the expression used for the interval estimate.

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The distance between the two comets in kilometers (km) is 9 × 10^9 km.

Astronomers measure distances in astronomical units (AU). One AU is approximately equal to 1.5× 10^(8) km. The distance between two comets is 60AU.

Using these values, let's determine the distance between the two comets in kilometers (km).The distance between two comets is 60AU.1AU is equal to 1.5× 10^(8) km.

Therefore, the distance between the two comets in kilometers (km) is 60 * 1.5 × 10^8 km. The above expression simplifies as follows:

                 60 × 1.5 × 10^8 km = 9 × 10^9 km.

Hence, the distance between the two comets in kilometers (km) is 9 × 10^9 km

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Answer:

slope = - 2

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x + 3 ← is in slope- intercept form

with slope m = - 2

Answer:

6 cm

Step-by-step explanation:

First find the height of 1 foot by doing 1/6 = 1.66. Then multiply that by the height of the robot. 1.66 x 36 = 6.

Answer:

i think it is A

Step-by-step explanation:

A 216

because if 1cm is 6 ft then you would have to do 6ft 36 times example 6×36 =216

im not sure im not good at math but i tried to help :(

(i) The degree of precision of a quadrature formula is the highest degree of polynomial that the formula can exactly integrate.

(ii) To find the constants co, ci, and x1 that give the highest possible degree of precision, we need to choose a quadrature formula that is exact for polynomials of the highest possible degree.

Let's assume that we are trying to find a formula that is exact for polynomials of degree 1 (i.e., linear polynomials). We can set up two equations using this assumption:

∫ 1 dx = c0 + c1   (since the formula must be exact for constant functions)
∫ x dx = c0*0 + c1*x1   (since the formula must be exact for linear functions)

Solving for c0 and c1, we get:

c0 = 1/2
c1 = 1/2
x1 = 1

Therefore, the quadrature formula that has the highest possible degree of precision is:

∫ f(x) dx = (1/2) f(0) + (1/2) f(1)

This formula is exact for linear polynomials and has a degree of precision of 1.

(i) The degree of precision of a quadrature formula is the highest degree of a polynomial, p(x), for which the quadrature formula gives an exact result when applied to the integral of p(x) dx over a given interval.

(ii) To find the constants c0, c1, and x1 so that the quadrature formula ∫f(x)dx = c0f(0) + c1f(x1) has the highest possible degree of precision, we'll follow these steps:

Step 1: Start with the quadrature formula
∫₀¹ f(x)dx = c0f(0) + c1f(x1)

Step 2: Test polynomials of increasing degree until the formula fails to be exact.
For n=0: f(x) = 1
∫₀¹ 1 dx = c0(1) + c1(1) => 1 = c0 + c1

For n=1: f(x) = x
∫₀¹ x dx = c0(0) + c1(x1) => 1/2 = x1*c1

Step 3: Solve for the unknowns using the equations obtained from the test polynomials:
From the equation for n=0: c1 = 1 - c0
Substitute this expression for c1 in the equation for n=1:
1/2 = x1 * (1 - c0)

Step 4: Choose values that satisfy the above equation:
Let c0 = 1/2 and c1 = 1/2
1/2 = x1 * (1/2) => x1 = 1

So, the constants are c0 = 1/2, c1 = 1/2, and x1 = 1. The highest degree of precision achieved by this quadrature formula is 1 because the formula works exactly for polynomials of degree 0 and 1, but not for higher degrees.

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The claim that the population mean is less than 125 (Option E) would

the interval tends to refute.

The 90% confidence interval for the population mean is 135 to 160. This means that if we were to repeat the process of taking samples from the same population and constructing a 90% confidence interval, we would expect 90% of the intervals to contain the true population mean.

With this in mind, let's consider each claim:

A. The interval does not rule out the possibility that the population mean is more than 110, as 110 is less than the lower bound of the interval.

B. The interval does not rule out the possibility that the population mean is less than 150, as 150 is greater than the upper bound of the interval.

C. The interval does not rule out the possibility that the population mean is between 140 and 150, as both of these values fall within the interval.

D. The interval does not rule out the possibility that the population mean is more than 140, as 140 is less than the upper bound of the interval.

E. The interval refutes the claim that the population mean is less than 125, as 125 is less than the lower bound of the interval.

Therefore, the answer is (E) The population mean is less than than 125.

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Answer:

2/5

Step-by-step explanation: