T/F: Carbide tools come in a variety of grades. Grade is based on the carbide wear resistance and toughness.

The given code snippet is a loop that iterates over each element in the "list" array. It compares each element to the value stored in the variable "temp". If the element is greater than "temp", it increments the counter variable "c" by 1.

Therefore, the code is counting the number of elements in the "list" array that are greater than the value of "temp".

To elaborate, the loop initializes an index variable "j" to 0 and iterates as long as "j" is less than the length of the "list" array. For each iteration, it checks if the element at index "j" in the "list" array is greater than the value of "temp". If it is, it increments the counter variable "c" by 1.

At the end of the loop, the variable "c" will hold the count of elements in the "list" array that are greater than "temp".

Learn more about code snippet here:

https://brainly.com/question/30467825

#SPJ11

The value of the site is $10,472,000.

The total construction costs are:

$6,000/m2 * 10,000m2 + $400,000 = $64,000,000

The professional fees are:

$64,000,000 * 0.13 = $8,320,000

The total development costs are:

$64,000,000 + $8,320,000 = $72,320,000

The developer's return for risk and profit is:

$72,320,000 * 0.20 = $14,464,000

The total cost of the development is:

$72,320,000 + $14,464,000 = $86,784,000

The expected rent is:

$3,000/m2 * 8,000m2 * 12 months = $28,800,000

The initial yield is:

$28,800,000 * 0.07 = $2,016,000

The value of the site is:

$86,784,000 - $2,016,000 = $10,472,000

Read more about initial yield here:

https://brainly.com/question/14714924

#SPJ1

Answer: d consequences

Explanation:

Answer:

Relative roughness = 0.04

Explanation:

Given that:

Diameter = 5 cm

roughness = 2 mm

At inlet:

Minor coefficient loss \(k_{L1} = 0.4\)

At exit:

Minor coefficient loss \(k_{L2} = 1\)

Height h = 4m

Length = 5 m

To find the relative roughness:

Relative roughness is a term that is used to describe the set of irregularities that exist inside commercial pipes that transport fluids. The relative roughness can be evaluated by knowing the diameter of the pipe made with the absolute roughness in question. If we denote the absolute roughness as e and the diameter as D, the relative roughness is expressed as:

\(e_r = \dfrac{e}{D}\)

\(e_r = \dfrac{0.2 }{5}\)

\(\mathbf{e_r = 0.04}\)

Answer:

  Av = -800

Explanation:

The gain to the output of the first op-amp is ...

  A1 = -R2/R1 = -1000/10 = -100

The gain of the voltage divider R3/R4 is ...

  A2 = R4/(R3+R4) = 10/(10+10) = 1/2

The gain of the second op-amp circuit from the positive terminal to the output is ...

  A3 = 1+ R5/R6 = 1 + 150/10 = 16

Then the total circuit gain is ...

  Av = A1×A2×A3 = (-100)(1/2)(16)

  Av = -800

_____

Additional comment

In the above, we have assumed ideal op-amps, with infinite gain and infinite input impedance. The resistor values used in the calculations are all Kohms, so we can avoid writing unnecessary zeros.

In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.

To learn more about Ideal capacitor refer to:

https://brainly.com/question/24302087

#SPJ1

Answer:

True

Explanation:

The two materials being considered for the piping system are Austenitic stainless steel and Brass (70Cu-30Zn). Austenitic stainless steel is a type of stainless steel that contains high levels of chromium and nickel. These materials are used in piping systems because they are resistant to corrosion.

However, they are susceptible to certain types of corrosion, which can occur in hot aerated seawater used to cool steam in a new power plant. There are several types of corrosion that can occur in Austenitic stainless steel, including pitting corrosion, stress corrosion cracking, and crevice corrosion. Pitting corrosion occurs when small holes or pits develop on the surface of the material. Stress corrosion cracking occurs when the material is exposed to high levels of stress, which can cause cracks to form. Crevice corrosion occurs in areas where the material is in contact with stagnant water. Brass (70Cu-30Zn) is an alloy of copper and zinc that is commonly used in piping systems.

Brass is also susceptible to several types of corrosion, including dezincification and stress corrosion cracking. Dezincification occurs when the zinc in the alloy is leached out of the material, leaving behind a porous copper structure that is prone to cracking. Stress corrosion cracking occurs when the material is exposed to high levels of stress, which can cause cracks to form. In summary, Austenitic stainless steel and Brass (70Cu-30Zn) are both susceptible to several types of corrosion, including pitting corrosion, stress corrosion cracking, and crevice corrosion.

To know more about corrosion visit:

https://brainly.com/question/31313074

#SPJ11

The given problem involves a 200 kg object sliding down a 10-meter-long ramp inclined at an angle of 40 degrees from the horizontal. As air resistance and friction are negligible, we can use the conservation of mechanical energy to solve for the object's velocity at the bottom of the ramp.

Initially, the object has only potential energy due to its height, which can be calculated as h = 10 * sin(40°). The potential energy (PE) is given by the formula PE = mgh, where m = 200 kg, g = 9.81 m/s², and h is the height.
When the object reaches the bottom of the ramp, all its potential energy is converted into kinetic energy (KE), which is given by the formula KE = (1/2)mv², where m = 200 kg and v is the final velocity in m/s.
Using conservation of mechanical energy, we equate the potential energy and kinetic energy: mgh = (1/2)mv². We can cancel the mass (m) from both sides of the equation and solve for the final velocity (v).
After calculating the height and solving the equation for v, you will find the object's velocity at the bottom of the ramp in m/s. Remember to maintain accuracy and professionalism when presenting your final answer.

Learn more about mechanical here

https://brainly.com/question/30403434

#SPJ11

Answer:

I think it's 23 ohms.

Explanation:

Not entirely sure about it.

hope this helps

Answer:

There are a few key benefits to a pre-construction and design specialist taking an interdisciplinary approach:

To maximize employability options. Having exposure to different fields and skills makes a specialist a more versatile and attractive job candidate. They can work across multiple areas of design, planning, architecture and construction.

To draw on a varied creative tool set. Exposure to fields like architecture, engineering, economics, sustainability and more provides many perspectives and solutions to tapping into. This leads to more innovative and well-rounded design thinking.

To integrate well with other team members. Understanding the methods, priorities, constraints and languages of fields like architecture, engineering, planning, and construction allows a specialist to collaborate more effectively. They can translate across disciplines and facilitate joined-up thinking.

To understand constraints and optimally balance priorities. No design or pre-construction problem has limitless options. An interdisciplinary approach helps gain insights into the constraints each field operates under and how to optimize solutions across ecological, economic, functional and other priorities.

To consider impacts holistically. Many impacts, like environmental sustainability, cost efficiency and user experience, span multiple disciplines. An interdisciplinary mindset is needed to evaluate options based on overall impact, not just impacts within one area of focus.

Of these options, I believe "To integrate well with other team members" is the strongest summary of why an interdisciplinary approach is so valuable for this type of specialist role. Understanding other fields in depth helps in collaborating, communicating clearly, addressing concerns proactively and finding optimal compromise - all of which are key to successfully interweaving different areas of expertise on a team.

Explanation:

Answer:

98 x 100=9,00

Explanation:

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

C++ requires that a copy constructor's parameter be a reference parameter. It is essential to have a parameter in the copy constructor, where we pass an object of a class that is being copied.

This parameter can either be passed by value or reference, but it's always better to use the reference parameter in copy constructor than using the value parameter.2. Tree operator = (const Tree &right) is the correct prototype for a member function of Tree that overloads the = operator. We generally use the overloading operator = (assignment operator) to copy one object to another.

oak.operator=(elm); is equivalent to oak = elm. The assignment operator is an operator that takes two operands, where the right operand is the value that gets assigned to the left operand. Here oak is the left operand that gets assigned the value of the elm.4. Overloading the = operator requires the use of a dummy parameter.

In the overloading operator, we use a dummy parameter, where the left-hand side (LHS) is the name of the function, and the right-hand side (RHS) is the parameter, which is also the argument.

To know more about constructor's visit:

https://brainly.com/question/13267120

#SPJ11

To estimate the hydraulic conductivity of the unconfined aquifer, we can use the equation:

Q = 2πKhdwhere Q is the flow rate, h is the rise in water level, d is the diameter of the well, and K is the hydraulic conductivitySubstituting the given values, we have:

100 gpm = 2πK(15 ft)(2 ft)

K ≈ 1.32 ft/dayb) To calculate the height the water table will be mounded above the original water level, we can use the Theis equation:

S = Q/4πT * W(u)

where S is the drawdown, Q is the flow rate, T is the transmissivity, W(u) is the well function, and u is a dimensionless parameter that depends on the aquifer properties and pumping ratI this case, we want to find the height of the groundwater mound, which is equal to the drawdown. We can assume that the groundwater mound is symmetric and therefore the drawdown at the center of the mound is half of the total drawdown.

To learn more about  hydraulic click on the link below:

brainly.com/question/29673023

#SPJ11

Answer:

True!! took the test

Explanation:

The impulse response of a sample-and-hold (S/H) circuit, when viewed as a linear filter, is given by option (c): h(t) = δ(t) * 1,0. In this expression, δ(t) represents the Dirac delta function, which is zero everywhere except at t = 0, where it is infinite. The asterisk (*) denotes convolution.

A sample-and-hold circuit is commonly used in analog-to-digital conversion and signal processing applications. It consists of a switch that samples the input signal periodically and holds the sampled value until the next sampling instant. When analyzing the S/H circuit as a linear filter, we are interested in its response to an impulse input.

An impulse input can be represented by the Dirac delta function δ(t). Convoluting this impulse input with the impulse response of the S/H circuit will yield the output of the system. In this case, the impulse response h(t) is given by 1,0, indicating that the output of the S/H circuit will be constant and equal to the most recent sampled value until the next sampling instant.

So, the correct answer is option (c): h(t) = 1,0, which represents the impulse response of an S/H circuit when viewed as a linear filter.

Learn more about Circuit:

brainly.com/question/29508163

#SPJ11

This question is incomplete, the complete question is;

For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.

Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.

Answer:

the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Explanation:

Given the data in the question;

treatment time t₁ = 11.3 hours

Carbon concentration = 0.444 wt%

thickness at surface x₁ = 1.8 mm = 0.0018 m

thickness at identical steel x₂ = 4.9 mm = 0.0049 m

Now, Using Fick's second law inform of diffusion

\(x^2\) / Dt = constant

where D is constant

then

\(x^2\) / t = constant

\(x^2_1\) / t₁ = \(x^2_2\) / t₂

\(x^2_1\) t₂ = t₁\(x^2_2\)

t₂ = t₁\(x^2_2\) / \(x^2_1\)

t₂ = (\(x^2_2\) / \(x^2_1\))t₁

t₂ = \((\) \(x_2\) / \(x_1\) \()^2\) × t₁

so we substitute

t₂ = \((\) 0.0049  / 0.0018  \()^2\) × 11.3 hrs

t₂ = 7.41 × 11.3 hrs

t₂ = 83.733 hrs

Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Answer:

I don't know the question but so do I. I analyze a problem very carefully before I answer it. Just like this one, I analyzed the problem(no question), then answered it to the best of my abilities.

Answer:

Explanation:

a) Present worth of the system:

First step :

Calculation of bank installment:

We are given:

·nitial costs = $32,000

Borrow amount = ½ of purchase price

Payment of borrow amount = EOY 2 to EOY 4 (3 Equal installments)

Bank loan interest = 8.5% = 8.5/100 = 0.085

Assume the installment amount is F. They will be paid at end of year 2 to end of year 4. Their present value must be equal to borrow amount.

Present value of cost to be incurred in future can be calculated by below formula:

F P (1 + i)

F= Future cost

i = Rate of interest

n = time (in years)

Therefore,

F F $32,000 2 F (1 +0.085)2 (1 +0.085) 3 (1 +0.085) + +

.: 2.35394F = 16,000 or F = 16,000 2.35394 - $6,797.11

Step 2: Present worth of the system:

Given Data:

Initial costs = $32,000

Expected life = 7 years

Salvage value = $5,000

O&M Costs = $2,000 per year

MARR = 12.5%

= 12.5/100

= 0.125

Present value of uniform recurring payments is given by below formula:

P=A (1 + i) - 1 i(1+i)n 72

Where,

P = Present Value

A = Recurring payments per annum

i = rate of interest

n = time (in years)

Hence present value of O&M costs,

P1 = -2,000 x (1 + 0.125) 7-1 0.125 x (1 + 0.125) 7 -$8,984.60

Present worth of the system calculated in below table:

Description

F ($)

MARR (i)

per year

n (years)

P ($)

Initial investment (1/2 of purchase price)

-16,000.00

0.125

0

-16,000.00

Bank installment EOY2

-6,797.11

0.125

2

-5,370.56

Bank installment EOY3

-6,797.11

0.125

3

-4,773.83

Bank installment EOY4

-6,797.11

0.125

4

-4,243.40

Salvage value

5,000.00

0.125

7

2,192.31

O&M Costs

-8,984.60

0.125

0

-8,984.60

The current worth of the new system

-37,180.07

Part b) Decision rule of judgment:

Assuming current value of costs is lower than current value of benefit, an alternative is known to be economic to use based on current worth analysis.

Part c) Decision for the water filtration system:

Given Data:

· Annual savings from filtration system (A) = $13,000 per year

· Expected life (n) = 7 years

· MARR = 12.5%

= 12.5/100

= 0.125

Present value of benefits = 13,000 X (1 + 0.125)7 - 1 0.125 x (1 + 0.125) 7 $58,399.91

Since current value of costs is less than current value of benefit, this is an worthwhile system and has to be be purchased.

The total work done by the wind turbine's blades after 10 revolutions in a wind of speed v_1 = 8.80 m/s is U_1 = 5.344e4 J.

A turbine is a rotary engine that converts the energy of a moving fluid (such as water or steam) into mechanical energy. A turbine is made up of a rotor, or a series of blades, and a stator, or a stationary part. The fluid enters the rotor, which is set in motion by its pressure and kinetic energy, and is directed towards the stator. The stator is designed to capture the energy from the fluid and convert it into mechanical energy, which can then be used to drive a generator, a compressor, or other machinery. Turbines are widely used in industry for power generation and for other applications such as water pumps.

U_1 = F * r_1 * 10 revolutions
U_1 = (40.0 kg/s)v_1 * 13.8 mm * 10 revolutions
U_1 = 5.344e4 J

The total work done by the wind turbine's blades after 10 revolutions in a wind of speed v_1 = 8.80 m/s is U_1 = 5.344e4 J. This calculation is based on the magnitude of the force produced by each blade (F=(40.0 kg/s)v) and the center of mass of each blade (r_1 = 13.8 mm). The force F is multiplied by the distance r_1 and then multiplied by the number of revolutions (10) to calculate the total work done by the blades.

To learn more about turbine's
https://brainly.com/question/15241334
#SPJ4

4 netherite scrap and 4 gold

in a crafting table

Many chips encased in one chip working together is known as a System on a Chip (SoC). An SoC combines multiple components of a computer into a single integrated circuit, allowing for the smaller size, lower power consumption, and increased performance of devices that use it.

A chip that contains many chips working together is known as an integrated circuit or a microchip. Integrated circuits are used in a wide range of electronic devices, including computers, smartphones, and other digital appliances. These chips are designed to perform a specific function, such as processing data, controlling a device, or amplifying a signal. By combining multiple chips into a single integrated circuit, manufacturers can reduce the size and cost of electronic devices, while also improving their performance and reliability.

Learn more about chips encased: https://brainly.com/question/30423461

#SPJ11

Answer:dimples

Explanation:

The option that is not designed to absorb collision energy is Reinforcements.

Thus option D (reinforcements)  is correct.

Here,

Reinforcements are designed to strengthen and support the structure of the vehicle, and not to absorb collision energy.

Automobiles have several safety features designed to protect drivers and passengers in the event of a collision. These safety features include airbags, seat belts, crumple zones, and several other components.

Among these safety features, the ones designed to absorb collision energy are dimples, slots, and crush zones. They are made to absorb the force of the impact during a collision and help prevent serious injuries to the occupants of the vehicle.

Therefore, the correct answer is D, reinforcements, which are not designed to absorb collision energy.

Know more about reinforcements,

https://brainly.com/question/33736020

#SPJ6

The statement that "Contractors who receive positive interest in a VECP may want to prepare a preliminary VECP to describe the change" is TRUE.

What is a VECP? VECP is the abbreviated form of Value Engineering Change Proposal. The VECP is a formal recommendation, submitted by a contractor or subcontractor, which identifies a specific project component that should be modified to achieve specific cost savings while maintaining or enhancing performance, reliability, and safety standards. A VECP is a written proposal that proposes a change to the contract requirements, specifications, or any other design characteristic. It usually involves a modification to the work statement, materials, components, construction techniques, or any other aspect of the project that has the potential to generate cost savings.

A Preliminary VECP is an informal version of a VECP and is submitted to the government before a formal VECP. It is an initial assessment of the project that identifies the changes required to meet the criteria. A preliminary VECP is developed to provide an outline of the proposed change so that the government can review it and provide feedback before a formal VECP is submitted.

Conclusion: So, it can be concluded that contractors who receive positive interest in a VECP may want to prepare a preliminary VECP to describe the change.

Learn more about Value Engineering at:

brainly.com/question/29663853

#SPJ11

Fritz Roethlisberger is famously known for conducting the Relay Assembly Test Room experiments at the Hawthorne Electric Plant.

The Hawthorne experiments marked the beginning of human relations research.

The experiments were aimed at investigating the connection between the productivity of workers and their physical working conditions.

The researchers hypothesized that by improving the working conditions, worker productivity would be improved.

What made the Hawthorne experiment unique was that the researchers didn't only examine the impact of physical working conditions on productivity,

but also how factors such as social and psychological elements could affect productivity.

The researchers found out that productivity was not just about providing the optimal working conditions.

Rather, the productivity of workers was also affected by the interactions and social relationships among workers and with their supervisors.

This led to the development of the Hawthorne effect theory,

which states that when people know they are being observed,

they tend to change their behavior and work more productively.

In conclusion,

Fritz Roethlisberger is known for conducting the Relay Assembly Test Room experiments at the Hawthorne Electric Plant.

These experiments marked the beginning of human relations research and led to the development of the Hawthorne effect theory.

To know more about experiments visit:

https://brainly.com/question/15088897

#SPJ11

The two most common sequential circuits used as memory devices are flip-flops and latches.

Flip-flops store one bit of data and have two stable states, while latches are similar to flip-flops but can store multiple bits of data. Both circuits are commonly used in digital electronics for a variety of applications,

such as storing program instructions and data in microprocessors, digital signal processing, and communication systems. Flip-flops and latches are often used in combination with other digital logic gates to create more complex circuits, such as counters and registers.

These memory devices play an important role in the operation of many electronic devices and systems, from computers and smartphones to digital cameras and gaming consoles.

To learn more about : sequential circuits

https://brainly.com/question/15244265

#SPJ11