The 300 gram billiard ball of 30 mm radius is struck by a cue stick that exerts an average force of 600 N horizontally over a 0.005 s interval. Immediately after being hit, the billiard ball rolls without slipping. Determine (a) the height h for the cue stick, and (b) the velocity of the ball after the impact.

Answer:86,400

Explanation:

Answer: its low

Explanation:

Answer:

18 meters

Explanation:

Answer:12

Explanation:

Answer:

Staples, Bestbuy, Maybe Homedepot

Explanation:

Answer:

find the mechanical pencil on amazon

Explanation:

amazon has everything!

HOPETHIS HELPS!

brailiest? please....

Yes, the presence of water on top of the glass block will affect the apparent position of the object.

Total apparent depth of the block and water is 8 cm.

This is because the light rays passing through the water will refract or bend as they enter the glass block, and then bend again as they exit the glass and enter the air above.

To determine the apparent position of the object, you will need to know the refractive indices of water and glass. The refractive index of water is 1.33, and the refractive index of glass is typically around 1.5.

Assuming the light rays are traveling perpendicular to the surfaces of the block, the apparent depth of the block as seen from above the water line will be:

apparent depth = actual depth / refractive index

For the water, the apparent depth is simply its actual depth, since the light rays are not refracted when passing from air to water.

So, for the glass block:

apparent depth = 6 cm / 1.5 = 4 cm

And for the water:

apparent depth = 4 cm

Therefore, the total apparent depth of the block and water is 4 + 4 = 8 cm. If an object is placed below the water line but above the top surface of the block, its apparent position will appear to be shifted upward by this amount.

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Answer:

I think its B bc I took the test and got D wrong

Explanation:

:)

the characteristics of continental tropical air masses They have warm, dry air. Hence option B is correct.

Tropical Air is a Tanzanian airline operating in Zanzibar. It was the first locally owned airline in Zanzibar, starting operations in 1999 with a single aircraft. Captain Omar Haji established it. It works in Pemba, Dar es Salaam, and other areas in Tanzania. They are no longer in use.

Throughout the year, the maritime Tropical (mT) air mass is the most important moisture-bearing and rain-producing air mass. It goes poleward in the winter and is cooled by the ground surface. As a result, it is distinguished by fog or low stratus or stratocumulus clouds, rain, and limited visibility.

Meteorology (the study and forecasting of weather), climatology (the study of long-term atmospheric patterns and their impacts), and aeronomy are the three classic thematic areas of the atmospheric sciences.

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Answer:

Yes you are right

Explanation:

hope this helps and I get the Brain thingy whatever it call

Answer:

Explanation:

compressions and rarefactions

Answer:

Compressions

-and-

Rarefactions

Explanation:

A star is moving directly toward earth at a large fraction of the speed of light. The light we observe from this star compared to the light received from the same star if it were at rest relative to earth will be blueshifted.

The amount of light emitted by a star coming towards earth would have a shorter wavelength as compared to other sources of light. This refers to the doppler shift principle. According to the doppler shift principle, if an observer is moving in relation to a source, then the change in frequency in the light waves would be relative to that observer.

In this case, we will observe that the star approaching earth will shift its spectral lines toward the blue end of the light series.

Since blue light has a shorter wavelength, therefore, the large fraction of the speed of light coming out from a star would correspond to the blue end of the light spectrum hence called blueshift.

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Answer:

Surface

Explanation:

Rayleigh Waves—surface waves that move in an elliptical motion, producing both a vertical and horizontal component of motion in the direction of wave propagation. Particle motion consists of elliptical motions (generally retrograde elliptical) in the vertical plane and parallel to the direction of propagation.

The speed of the mass as it passes through the central point b is 139 m/s. To find this, we need to use the concept of conservation of mechanical energy.

As the mass moves from a to b, it loses potential energy and gains kinetic energy. At point b, all the potential energy is converted into kinetic energy, so we can equate the potential energy at point a with the kinetic energy at point b.

Using the formula for potential energy of a spring (PE = 0.5 * k * x^2), where k is the force constant and x is the displacement, we can find the potential energy at point a. The potential energy at point b is zero because the spring is unstretched. Equating these two energies and solving for the speed at point b gives us a speed of 139 m/s.

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Answer:

Its called pollen. Pollen is a powdery substance consisting of pollen grains which are male microgametophytes of seed plants, which produce male gametes (sperm cells).

Hope this helps, have a great day/night and stay safe!

Answer:

a

Explanation:

Answer:

You're best answer to your question would be C!!!

The detection of quasars from such great distances is due to their extreme luminosity and the fact that they emit massive amounts of energy.

Quasars are the most energetic objects in the universe, and their bright emissions make them visible even at very large distances. On the other hand, even the biggest and most luminous galaxies cannot be seen from such distances because their emissions are not as powerful as those of quasars.

Quasars are actually supermassive black holes at the center of galaxies that are actively feeding on surrounding matter. As they consume matter, they emit large amounts of energy in the form of light, X-rays, and other types of radiation. This energy is what makes them visible from great distances, even beyond the limits of what other galaxies can achieve.

The fact that quasars can be detected from distances beyond the reach of other galaxies is a testament to their extreme power and luminosity. It also helps astronomers to study the universe at a deeper level and gain insight into the evolution of galaxies and supermassive black holes.

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The average velocity of the car for the entire trip is 0.018 km/h.

The velocity of the trip is determined from the ratio of change of displacement to total time of motion.

The total displacement of the motion = ( 30 m North -  30 m South) + 40 m est = 40 m west = 0.04 km west

The total time of motion = 2.22 hours

The average velocity of the car for the entire trip is calculated as follows;

v = ( 0.04 km ) / ( 2.22 hrs )

v = 0.018 km/h

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The average velocity is 25 mph north.

Average velocity = displacement/time

Displacement =

(400 mi north) + (275 mi south)

Displacement = 125 mi north

Average V = (125 mi north) / 5 hours.

Average V = 25 mph north

An engine moves a boat through the water at a constant speed of 15 m/s. The engine must exert a force of 6.0 kN to balance the force that the water exerts against the hull. Power is the measure of how fast work can be done. The unit of power is watts (W), which can be defined as the amount of work done in one second.

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The distance from the central maximum for violet light is 0.0152 meters.

To find the distances from the central maximum for red and violet light, we can use the formula for the position of the m-th order fringe in a double-slit interference pattern:

y = mλL / d

where y is the distance from the central maximum, λ is the wavelength of light, L is the distance from the slits to the screen, d is the distance between the slits.

For red light with a wavelength of 700 nm (700 x 10^-9 m), substituting the values into the formula:

y_red = (1)(700 x 10^-9 m)(0.95 m) / (25 x 10^-6 m)

     ≈ 0.0266 m

Therefore, the distance from the central maximum for red light is approximately 0.0266 meters.

For violet light with a wavelength of 400 nm (400 x 10^-9 m), using the same formula:

y_violet = (1)(400 x 10^-9 m)(0.95 m) / (25 x 10^-6 m)

        ≈ 0.0152 m

Hence, the distance from the central maximum for violet light is approximately 0.0152 meters.

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When Weight of 7294.3 N can be supported by boom if force 7800 is applied on the cable and there is no resultant rotation at point C.

Torque is defined as force times perpendicular distance from axis of rotation to the point at which force is applied. Torque is denoted by τ and its SI unit is Nm. i.e Torque is given by, τ = F×d sinθ. Torque is vector quantity.

Torque is analogous to force in rotational motion. like there angular velocity ω is analogous  linear velocity v. means Torque is a force in rotational motion.

Looking at the answered figure I have resolved forces, there will be no resultant rotation when opposite torques due to opposite horizontal forces gets balanced.

We get,

τ₁ = τ₂

F×d Cos40⁰ = W×d Sin55°

F Cos40° = W Sin55°

W = F×(Cos40°÷Sin55°)

W = F×0.93516

W = 7800 ×0.93516

W = 7294.3 N

Hence Weight that can be supported is 7294.3 N.

b) When we assume that there is no cable, Then

Torque τ = W×d Sin35°

τ = 7294.3×10 Sin35°

τ = 41838.3 Nm

bloom will rotate with 41838.3 Nm torque.

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Answer:

a. 4.99 × 10⁻⁴ N b. 1.46 × 10⁻³ N c. 4.83 nC

Explanation:

(a) Find the magnitude of the electric force acting on each ball.

The tension in the string, T is resolved into horizontal and vertical components Tsin20° and Tcos20° respectively, since the string makes an angle of 20° with the vertical.

Let F = electric force and W = mg be the weight of the ball where m = mass of ball = 0.14 g = 0.14 × 10⁻³ kg and g = acceleration due to gravity = 9.8 m/s²

The electric force acts in the opposite direction to the horizontal component of the tension in each string. Since the masses are in equilibrium,

Tsin20° = F (1)

Also, the weight of the ball acts downwards, opposite to the direction of the vertical component of the tension in the string. Since the masses are in equilibrium,

Tcos20° = W = mg

Tcos20° = mg (2)

Dividing (1) by (2), we have

Tsin20°/Tcos20° = F/mg

tan20° = F/mg

F = mgtan20°

So, F = 0.14 × 10⁻³ kg × 9.8 m/s²× tan20°

F = 0.4994 × 10⁻³ N

F = 4.994 × 10⁻⁴ N

F ≅ 4.99 × 10⁻⁴ N

(b) Find the tension in each of the threads.

Since  Tsin20° = F

T = F/sin20°

=  4.99 × 10⁻⁴ N/sin20°

= 4.99 × 10⁻⁴ N/0.3420

= 14.59 × 10⁻⁴ N

= 1.459 × 10⁻³ N

≅ 1.46 × 10⁻³ N

(c) Find the magnitude of the charge on the balls.

From Coulomb's law, the electric force between the masses of charge q and separated by a distance r = 2.05 cm = 2.05 × 10⁻² m

F = kq²/r² where k = 9.0 × 10⁹ Nm²/C²

q² = Fr²/k

q = √(Fr²/k)

q = [√(F/k)]r

Thus,  

q = [√(F/k)]r

q = [√( 4.99 × 10⁻⁴ N/9.0 × 10⁹ Nm²/C²)]2.05 × 10⁻² m

q = [√(0.5544 × 10⁻¹³ C²/m²)]2.05 × 10⁻² m

q = [√(5.544 × 10⁻¹⁴ C²/m²)]2.05 × 10⁻² m

q = [2.355 × 10⁻⁷ C/m]2.05 × 10⁻² m

q = 4.83 × 10⁻⁹ C

q = 4.83 nC

Answer:

The world would have been blown up by now.

Explanation:

Hypothetically, lets say that someone gave Kim Jong boi a cup of coffee.

He gets mad at the "public servant" since it didn't contain 3 posafa43asdunds of sugar which makes him "big".

The public servant claims they added jfoaj4su38093 units of sugar, which is equivalent to 3 posafa43asdunds.

He gets mad and launches big cannons at Trump since he blames Boe Jiden.

Answer:

Gold is metallic, with a yellow color when in a mass, but when finely divided it may be black, ruby, or purple. It is the most malleable and ductile metal; 1 ounce (28 g) of gold can be beaten out to 300 square feet. It is a soft metal and is usually alloyed to give it more strength.

Formula  --

Molecular Weight (lb/m o l)  28.96

Critical Temp. (°F)  N/A

Critical Pressure (p s i a)  N/A

Boiling Point (°F)  -317.8

Melting Point (°F)  N/A

Psat  70°F (p s i a)  (note 1)

Explanation:

The design that has the metal bar would increase the chances of an elastic collision and lead to an increase of the velocity of the car after collision.

We know that an elastic collision is one in which there is a conservation of the kinetic energy of the momentum. Recall that the colliding particles would have to constitute a closed system such that there is no loss in the momentum of the objects that are colliding.

We have two designs of the bumpers of the cars. We know that the balloon  design would have more tendency to have this car stick to the other car and create an inelastic Collison.

However, with the metal bar design, there is less tendency that the cars would stick together after collision and we would have an elastic collision. The effect of this is that velocity of the car 2 may increase after the collision.

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Answer:

10m/s

Explanation:

a = v- u/ t

=> v = at + u

= -2 × 5 + 20

= 10m/ s. ( 72 km/ h = 20 m/ s)

The potential energy of a 3 kg ball that is on the ground is zero.

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It would be necessary to conduct a calibration or compare the balances against a known reference mass to determine which one is more accurate when measuring a 12.1 g sample.

To determine which balance is more accurate when the mass of the sample is actually 12.1 g, we need to compare the balances' precision and accuracy.

Precision refers to the degree of reproducibility or consistency of measurements, while accuracy refers to the closeness of a measured value to the true or accepted value.

If the two balances have different precisions, we would compare their standard deviations or uncertainties. A balance with a smaller standard deviation or uncertainty would be considered more precise.

Percentage error = (|Measured value - True value| / True value) * 100

For Balance A:
Percentage error = (|12.0 g - 12.1 g| / 12.1 g) * 100 = (0.1 g / 12.1 g) * 100 ≈ 0.826%

For Balance B:
Percentage error = (|12.2 g - 12.1 g| / 12.1 g) * 100 = (0.1 g / 12.1 g) * 100 ≈ 0.826%

If both balances have the same precision, we would compare their systematic errors or biases. A balance with a smaller systematic error or bias would be considered more accurate.

Without specific information about the precision and accuracy of the balances, it is difficult to determine which one is more accurate. It is possible that one balance is more precise, while the other is more accurate, or they may have similar levels of precision and accuracy.

In practice, the accuracy and precision of a balance can be determined through calibration and comparison with known reference masses. The calibration process helps establish the accuracy of a balance by verifying its readings against a traceable standard.

Therefore, it would be necessary to conduct a calibration or compare the balances against a known reference mass to determine which one is more accurate when measuring a 12.1 g sample.

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Complete question is here

Adrian and Mark weighed the same sample on two different balances. The results were as follows:

Balance A

Balance B

12.11g

12.1324 g

12.09 g

12.1322 g

12.10 g

12.1323 g

a.

Which balance is more precise?

b.

If the mass of the sample is actually 12.1 g, which balance is more accurate?