The acceleration due to gravity on Earth is 9. 8 m/s2. What is the weight of a 75 kg person on Earth? 9. 8 N 75 N 85 N 735 N.

Answers

Answer 1

The weight of a 75 kg person on Earth, which has an acceleration due to gravity of 9.8m/s², is 735N.

CALCULATE WEIGHT:

Weight is a force, hence, measured in Newton. It is a function of an object's mass in relation to gravity.

Weight of an object can be calculated using the following formula:

W = mg

Where;

W = weight (N)m = mass (kg)g = acceleration due to gravity (m/s²)

The weight of the person in this question can be calculated as follows:

W = 75 × 9.8

W = 735N

Therefore, the weight of a 75 kg person on Earth, which has an acceleration due to gravity of 9.8m/s², is 735N.

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Related Questions

write down an equation that relates the heat energy generated by one turn of the crank to the temperature increase of the cylinder in one turn

Answers

Answer:

Explanation:

Image result for write down an equation that relates the heat energy generated by one turn of the crank to the temperature increase of the cylinder in one turn

The quantitative relationship between heat transfer and temperature change contains all three factors: Q = mcΔT, where Q is the symbol for heat transfer, m is the mass of the substance, and ΔT is the change in temperature. The symbol c stands for specific heat and depends on the material and phase.

A turntable rotates counterclockwise at 78 rpm. A speck of dust on the turntable is at θ= 0.45 rad at t=0s. What is the angle of the speck at t=8.0s? Your answer should be between 0 and 2π rad.

Answers

A turntable rotates counterclockwise at 78 Rpm. The angle of the speck at 8.0 s is approximately 2.91 rad.

How to determine the angle of the speck

To find the angle of the speck at t = 8.0 s, we must first determine the angular displacement of the speck in 8 seconds. The angular displacement is given by:

θ = ωt

where

θ = angular displacement

ω = angular velocity

t = time

Substituting the given values,

ω = (78 rev/min) × (2π rad/rev) = 156π rad/min = (156/60) π rad/s

ω = 2.6 π rad/s

θ = ωt = (2.6 π rad/s)(8.0 s) = 20.8 π rad

Now, we can find the angle of the speck at t = 8.0 s by adding the angular displacement to the initial angle of the speck.

θf = θi + θθf = 0.45 rad + 20.8 π rad

θf ≈ 65.5 rad (rounded to one decimal place)

Since the answer should be between 0 and 2π rad, we need to convert the answer to this range by subtracting 2π rad until the answer is within the range.

θf = 65.5 rad - 2π rad = 2.91 rad

The angle of the speck at t = 8.0 s is approximately 2.91 rad.

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If the mass of the sun, the mass of earth, and the sun-earth distance all doubled, the force of gravity between the sun and earth would:________

Answers

If the mass of the sun, the mass of Earth, and the Sun-Earth distance all doubled, the force of gravity between the sun and Earth would quadruple.

The force of gravity between two objects is determined by the product of their masses and inversely proportional to the square of the distance between them, according to the law of universal gravitation.

When the masses of both the sun and Earth are doubled, the force of gravity between them will increase by a factor of 2×2 = 4. Doubling the distance would result in the force decreasing by a factor of (1/2)² = 1/4. However, since both the masses and the distance are doubled, the overall effect is an increase in the force of gravity by a factor of 4.

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What is the average horizontal speed of the grasshopper as it progresses down the road? Assume that the time A grasshopper hops down a level road. On each spent on the ground between hops is negligible. hop, the grasshopper launches itself at angle θ
0

= Express your answer using two significant figures. 35

and achieves a range R=1.1 m.

Answers

The average horizontal speed of the grasshopper as it progresses down the road is approximately 3.39 m/s.

To find the average horizontal speed of the grasshopper, we can use the range formula for projectile motion:

R = (v² * sin(2θ)) / g

where:

R is the range of the projectile

v is the initial velocity of the projectile

θ is the launch angle

g is the acceleration due to gravity (approximately 9.8 m/s²)

Rearranging the formula to solve for the initial velocity, v, we have:

v = √((R * g) / sin(2θ))

Substituting the given values:

R = 1.1 m

θ = 35°

g ≈ 9.8 m/s²

v = √((1.1 * 9.8) / sin(2 * 35°))

v ≈ √(10.78 / sin(70°))

v ≈ √(10.78 / 0.9397)

v ≈ √(11.47)

v ≈ 3.39 m/s

Therefore, the average horizontal speed of the grasshopper as it progresses down the road is approximately 3.39 m/s.

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please teach me step by step​

please teach me step by step

Answers

The velocity of the load right after the brake of the lorry is suddenly applied at t = 6 s, is 16.9 m/s.

What is the velocity of the load?

The velocity of the load is determined from the ratio of the load displacement and time taken.

Mathematically, the formula for displacement is given as;

Displacement = change in displacement / change in time

The displacement of the load at 6 seconds is calculated as;

D = area under the curve

D = (15 s - 6 s ) x (20 m/s - 0 m/s)  +  ¹/₂ (19 s - 15 s ) x (20 m/s - 0 m/s)

D = 180 m  + 40 m

D = 220 m

The velocity of the load;

v = ( 220 m ) / (19 s - 6 s )

v = 16.9 m/s

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The speed limit sign in indiana reads 60 miles per hour. convert these units to meters per second

Answers

Answer:

26.822 m/s

Explanation:

60 mi/hr  *  5280 ft/mile *  1 hr / 3600 sec  *  12 in / foot * 1 meter / 39.37 in = 26.822 m/s

The speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. 60 miles per hour in m/s is 26.82 m/s.

Speed is a scalar quantity that describes "how fast an object is moving." The rate at which an object travels a distance can be thought of as its speed. A fast-moving object travels at a high speed and completes a significant distance in a brief period of time.

60 miles per hour is converted into meters per second is:

1 miles / hr = 0.44704 m/s

60 miles / hr = 60 × 0.44704

60 miles /hr = 26.82 m/s

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A hydraulic lift is used to raise an automobile of mass 1520 kg. The radius of the shaft of the lift is 8.00 cm and that of the piston is 1.00 cm. How much force must be applied to the piston to raise the automobile?

Answers

To raise the automobile with a hydraulic lift, a force of approximately 19,000 N must be applied to the piston.

In a hydraulic lift, the principle of Pascal's law is applied, which states that pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and the walls of its container. By utilizing this principle, a smaller force applied to a smaller piston can generate a larger force on a larger piston.

In this scenario, the force needed to lift the automobile can be calculated using the formula:

\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)

where \(F_{1}\) is the force applied to the piston, \(A_{1}\) is the area of the piston, \(F_{2}\) is the force generated on the larger piston (required to lift the automobile), and \(A_{2}\) is the area of the larger piston.

Given the radius of the shaft (small piston) as 0.08 m and the radius of the piston as 0.01 m, we can calculate the forces applied and generated as follows:

\(A_{1} = \pi (0.08)^2\\A_{2}= \pi (0.01)^2\)

\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)

Simplifying the equation and substituting the values, we can solve for \(F_{2}\):

\(F_{2}=\frac{F_{1}A_{2}}{A_{1}}\)

Plugging in the values, we find:

\(F_{2}=\frac{F_{1} \pi (0.01)^2 }{ \pi (0.08)^2} \\F_{2}= \frac{F_{1}\times 0.0001}{0.0064} \\F_{2}= 0.015625 \times F_{1}\)

Given that the mass of the automobile is 1520 kg and the acceleration due to gravity is \(9.8 \hspace m/s^{2}\), we can equate \(F_{2}\) to the weight of the automobile:

\(F_{2}= mg\\0.015625\times F_{1}= 1520\times 9.8\)

Solving for \(F_{1}\), we find:

\(F_{1}\approx \frac{1520\times 9.8}{0.015624} \\F_{1} \approx 19072 \hspace N\)

Therefore, a force of approximately 19,000 N must be applied to the piston in order to raise the automobile using the hydraulic lift.

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What is the heat energy produce within 4s with the rate of transfer energy 50 J/s?​

Answers

Okay, let's think this through step-by-step:

* The rate of energy transfer is 50 J/s

* We need to calculate the energy transferred in 4 seconds

* So we would calculate:

Energy in 4 seconds = Rate x Time

= 50 J/s x 4 s

= 200 J

So the heat energy produced within 4 seconds with an energy transfer rate of 50 J/s is 200 J.

Let me know if you have any other questions!

The heat energy produced within 4 seconds with a rate of transfer energy of 50 J/s can be calculated using the formula:

Heat energy = Rate of transfer energy x Time

Substituting the given values, we get:

Heat energy = 50 J/s x 4 s
Heat energy = 200 J

Therefore, the heat energy produced within 4 seconds with a rate of transfer energy of 50 J/s is 200 J.



A bird flies 200 km in 4.5 hours. What is the birds average speed?

900 km/hr
0.0225 km/hr
44.44 km/hr
245 km/hr

Answers

900km just multiple

ntally Check for Understanding
POSSIBLE POINTS: 5
In a football game, the kicker kicks the football a horizontal distance of 39 m. If the ball lands 3.9 s later, what is the football's horizontal velocity just before
it lands?
0 10 m/s
41 m/s
0 34 m/s
O 14 m/s

Answers

Answer: 34

Explanation:

34

a running back with a mass of 70 kg and a speed of 9 m/s collides with, and is held by, a 105-kg defensive tackle going in the opposite direction. how fast must the tackle be going before the collision for their speed afterward to be zero?

Answers

If a  running back with a mass of 70 kg and a speed of 9 m/s collides , then speed of tackle before the collision is 6 m/s .

Let the speed of the defensive tackle before the collision be = v .

The momentum of the system before the collision is given by the momentum of the running back,

⇒ that is ; 70 × 9 = 630 Kgm/s , and

the momentum of the tackle is , (-105 kg) × (v m/s)  ;

After the collision, the momentum of the system must be zero, so the momentum before the collision must equal the momentum after the collision ;

⇒ (70 × 9) + (-105 × v) = 0  ;

Solving for v, we get ;

⇒ v = 630/105 = 6 m/s

Therefore , the defensive tackle must be going 6 m/s in the opposite direction before the collision for the two players to come to a stop after the collision.

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The diagram shows how Earth is tilted on its axis as it revolves around the Sun. What is the season in the United States when Earth is in position C

Answers

Winter

It is winter because the Northern Hemisphere is not facing the sun.

outlet and at the reactor inlet are of 14.4 m s−1 and 10.7 m s−1, respectively. What is the change of rate of kinetic energy (in W )? a. 102.68 b. −698.78 c. −696.53 d. 696.60 e. −102.68

Answers

We find that the change in kinetic energy is positive and equal to 696.60 W, option d. The formula for kinetic energy is given by KE = 1/2 * mv^2, where m is the mass of the fluid and v is its velocity.

In this case, we are given the velocities at the outlet and the reactor inlet, which are 14.4 m/s and 10.7 m/s, respectively. Since the mass of the fluid is not provided, we can assume it to be constant.

The change in kinetic energy is given by the difference in kinetic energies at the outlet and the reactor inlet, which can be calculated using the formula:

ΔKE = (1/2 * m * v_outlet^2) - (1/2 * m * v_inlet^2)

Simplifying this expression, we get:

ΔKE = 1/2 * m * (v_outlet^2 - v_inlet^2)

Plugging in the given values, we have:

ΔKE = 1/2 * m * (14.4^2 - 10.7^2)

Calculating this expression, we find the answer to be approximately 696.60 W. Therefore, the correct option is d. 696.60.

In summary, the change in the rate of kinetic energy is approximately 696.60 W. This is calculated by taking the difference between the kinetic energy at the outlet and the kinetic energy at the reactor inlet using the formula ΔKE = 1/2 * m * (v_outlet^2 - v_inlet^2). Plugging in the given velocities of 14.4 m/s and 10.7 m/s, we find that the change in kinetic energy is positive and equal to 696.60 W.

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When calcium oxalate dissolves in water, what will happen to the temperature of the water?.

Answers

(CaC₂)O₄. H₂O decomposes under heat in three distinct steps, as the total reaction equation is depicted below. To create anhydrous calcium oxalate,

step 1 includes the loss of water through crystallization. In step 2, calcium oxalate thermally breaks down to calcium carbonate while losing carbon monoxide.If they are insoluble in acetic acid and caustic alkali, soluble in hydrochloric and sulfuric acid without effervescence, and display a progressive separation of needle-like calcium sulphate crystal when mixed in a 50% sulfuric acid solution, they can be classified as calcium oxalate.It burns in air or pure oxygen to form the oxide and reacts rapidly with warm water (and more slowly with cold water) to produce hydrogen gas and calcium hydroxide. On heating, calcium reacts with hydrogen, halogens, boron, sulfur, carbon, and phosphorus.

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What is true of a match burned in a closed system?

Answers

Answer:

The match is made of wood or paper, mainly cellulose, a carbohydrate. When it burns, carbon and hydrogen combine with oxygen in the air and go off into the atmosphere. The match loses mass, but the mass goes somewhere else—in this case, the atmosphere. When a match burns, its mass decreases

Explanation:

PLEASE GIVE ME BRAINLIEST IF NEW IT SHOULD SAY NEAR MY ANSWER MARK AS BRAINLIEST IF NOT YOULL HAVE TO WAIT A DAY AND BRAINLY WILL REMIND YOU

Two solid spheres, both of radius 5 cm, carry identical total charges of 2 μC. Sphere A is a good conductor. Sphere B is an insulator, and its charge is distributed uniformly throughout its volume. How do the magnitudes of the electric fields they separately create at radius 4 cm compare? a. EA=EB>0
b. EA>EB=0
c. EB>EA=0
d. 0 e. EA>EB>0

Answers

Two solid spheres with identical charge imbalance of 2 C have radii of 5 cm each. A is an excellent conductor, or sphere A. As an insulator, sphere B's charge is dispersed evenly throughout its volume.

A charge is what?

the sum of money required to purchase something, particularly a service: levy/impose/experience a fee You will be charged if you don't cancel the reservation within the allotted time. the cost of sb/sth Do kids pay anything or are they admitted free minimal or modest charge For this service, we charge a small fee.

What does charge mean in physics and chemistry?

August 8, 2017 update. Charge often refers to electric charge in chemistry and physics, which is a conserved feature of some subatomic particles that governs their electromagnetic interaction. An electromagnetic field exerts a force on matter as a result of the physical attribute of charge.

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Which of the following is an example of thermal energy?
O Lightning
O Food
O Nuclear power
O Melting ice cream

Answers

Nuclear power
because thermal energy is obtained via the nuclear fuel.

Answer:

melting ice cream

Explanation:

in order for the ice cream to melt, thermal energy (heat) must be applied to it.

Segregation of alleles happens during the sex cell formation called ___.

A. translation
B. meiosis
C. sexual reproduction
D. transcription

Answers

Answer:

The answer to your question is sexual reproduction

Explanation:

Mark me brainliest (WHY?) cause my answer is correct

What is the force on a 1025 kg elevator that is falling freely at 9.8 m/sec 2?


Answers

Answer:

Given :-Mass = 1025 kgAcceleration = 9.8 m/s²To Find :-

Force

Solution :-

We know that

F = mg

F = 1025 × 9.8

F = 10,045 N

Or,

10045/1000 = 10.045 Kilo Newton

\( \\ \)

Help me please in the Next Question i will give all points to the first to arive 500 on the line

Help me please in the Next Question i will give all points to the first to arive 500 on the line

Answers

Answer: Newton's third law of motion is naturally applied to collisions between two objects. In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction.

Explanation: So it is #2

The color of light emitted during a flame test depends on

A) the location of electrons only

B) the size of the atom only

C) the size of the atom and the location of protons

D) the location of electrons and size of the atom

the answer is D

Answers

D hope this helps :))))

PLEASE HELP ME SOLVE ASAP​

PLEASE HELP ME SOLVE ASAP

Answers

Answer:

a) The distance after 1 minute will be x = 600 m.

b) The distance of vertical drop from A to B is  \(\Delta y=17658\: m\).

Explanation:

Let's use the parabolic motion equations. Here we have a horizontal initial velocity, and knowing that the horizontal velocity is a constant we have:

a)

\(v_{x}=\frac{\Delta x}{\Delta t}\)    (1)

Where:

v(x) is the horizontal velocity (v(x) = 36 km/h = 10 m/s)Δx is the displacement Δt is the time (Δt = 1 min = 60 s)

Usinf (1) we find Δx:

\(\Delta x=v_{x}\Delta t\)    

\(\Delta x=10*60=600 m\)      

Therefore, the distance after 1 minute will be x = 600 m

b)

Here we need to find Δy = y(A)-y(B), this is the distance of vertical drop from A to B.

Using the following equation we will get it:

\(y_{B}=y_{A}+v_{iy}t-\frac{1}{2}gt^{2}\)

Let's recall that the initial velocity in the y-direction is 0.

\(y_{A}-y_{B}=0t+\frac{1}{2}gt^{2}\)

\(\Delta y=\frac{1}{2}gt^{2}\)

\(\Delta y=\frac{1}{2}(9.81)(60)^{2}\)  

\(\Delta y=17658\: m\)  

Therefore, the distance of vertical drop from A to B is  \(\Delta y=17658\: m\).

I hope it helps you!

     

Which of the following is a pure
substance?
A. Heterogenous mixture
B. Homogenous mixture
C. Solution
D. Element

Answers

Answer:

B. Homogenous mixture

Explanation:

........

A mass hanging from a pendulum at the end of a string of negligible mass. The string has a length of 0.84 m. With the string hanging vertically, the object is given an initial velocity of 1.4 m/s parallel to the ground and swings upward on a circular arc. Eventually, the object comes to a momentary halt at a point where the string makes an angle θ with its initial vertical orientation and then swings back downward. Find the angle θ.

Answers

Explanation:

tan(theta)=(v^2)/(length of string × g)

=(1.4^2)/(0.84 × 9.8m/s )

=1.96/(8.232)

=0.2380952381

theta=arctan(0.2380952381)

=13.4°

ILL GIVE BRAINLIEST IF UR CORRECT

ILL GIVE BRAINLIEST IF UR CORRECT

Answers

Answer:

B is the answer.

Explanation:

can someone please help me? i don’t wanna fail :(

can someone please help me? i dont wanna fail :(

Answers

Answer:

All of the above

Explanation:

The larger truck has greater mass than the car thus allowing it to build up momentum faster.

Answer:

The answer is momentum

Explanation:

I have done that question before, And I got it right.

If I have a series circuit with 3 resistors on it and each resistor has a resistance of 500
Ohms, what is my total resistance?

If I have a series circuit with 3 resistors on it and each resistor has a resistance of 500Ohms, what

Answers

Answer:

1,500 ohms is the total resistance

a device that converts mechanical energy into electricity is a

Answers

Answer:

An electric generator is a device that converts a form of energy into electricity.

Explanation:

You are trying to push a 70kg crate out the back door. The force of friction between the crate and the floor is 275 N, and you push horizontally. How hard must you push to move the crate with a constant speed? If you push with a force of 380 N, what will be the crates acceleration? If her crates moved from rest, what will be the crate’s final velocity if you push with a force of 380 N for 6s?

Answers

(a) The acceleration of the crate  is  1.5 m/s^2

(b) The crate’s final velocity is 9 m/s.

What will be the crates acceleration?

To move the crate with a constant velocity, the force you apply must equal the force of friction. So, to move the crate, you must push with a force of 275 N.

If you push with a force of 380 N, the net force on the crate will be;

F (net)  380 N - 275 N = 105 N.

The acceleration of the crate will be given by Newton's second law of motion:

a = F / m

where;

a is the acceleration, F is the net force, and m is the mass of the crate.

So, substituting in the known values, we get:

a = 105 N / 70 kg = 1.5 m/s^2

Finally, if the crate started from rest, its final velocity after 6 seconds can be found using the equation:

v = at

v = 1.5 m/s^2  x  6s = 9 m/s

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9. What is NOT true about the Body Composition Assessment?
It can be measured using skin calipers, a water test, and body composition scales.
OBMI is an indirect body composition measuring method using your weight and height.
ОО
Your weight alone can determine the percentages of your body's composition.
OBMI can be a reliable indicator of body composition.

Answers

Answer: Your weight alone can determine the percentages of your body's composition

Explanation:

C. Your weight alone can determine the percentages of your body's composition.

What is Body Composition Assessment?

Body composition analysis is the assessment of the proportion of fat to fat-free mass in your body.

Performing Body Composition Assessment will tell you your own body's unique makeup and help you identify areas to work on to improve your overall health and wellness.

Thus, the statement that is NOT true about the Body Composition Assessment is your weight alone can determine the percentages of your body's composition.

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