The ages and grades of some of the 19 girls on a club soccer team are
shown in the table.
O A.
15 years old
2
9th grade
10th grade
Which two-way frequency table correctly shows the marginal frequencies?
9th grade
10th grade
16 years old
0
10
15 years 16 years
old
old
2
0
7
10
Total
2
17

Answer: False

Step-by-step explanation:

If \(y=0.5\), then \(y^2=0.25\), whereas \(y=0.5\).

Therefore, this is a counterexample. Hence, the statement is false.

c

you need to find the slope and then y intercept

m=y2-y1/x2-x1

so m=2

now y intercept

3=2(4)+b

solve for b

u get -5

therefore

y=2x-5

Answer:

a

Step-by-step explanation:

Move 6 to the right by subtracting 6 to both sides of <

7x<4x+18

Now move 4x to the left by subtracting 4x to both sides of <

3x<18

Now divide 3 by both sides of < to solve for x

x<6

Answer:

84 cm 2 :)

Step-by-step explanation:

a cube has 6 faces

14 x 6 = 84!

Given, Area of each face = 14 cm^2

So, surface area = 6 × Area of each face

= 6 × 14 cm^2 = 84 cm^2

Hope this helps :)

Not enough information to answer the question, need the graph to solve it

40 millimeters; the ocean will have risen each year for the next 25 years.

ocean’s level is currently rising at about 1.6 millimeters per year.

create an application that displays the number of millimeters that the ocean will have risen each year for the next 25 years.

IN, 1 year  —>   1.6 millimeters;

25 years  —> 25*1.6 millimeters;

= 40 millimeters;

40 millimeters; the ocean will have risen each year for the next 25 years.

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Identify the coordinates of the points A and B on the graph:

The attached graph will be used to identify the cordinates

Each point can be identified by an ordered pair of numbers; that is, a number on the x-axis called an x-coordinate, and a number on the y-axis called a y-coordinate. Ordered pairs are written in parentheses (x-coordinate, y-coordinate)

points A = (x,y)

points B = (x,y)

Therefore the coordinates of point A and B are

Answer:

Step-by-step explanation:

Dilation about the origin multiplies each coordinate value by the dilation factor.

For dilation factor k, the new coordinates are ...

  (x, y) ⇒ (kx, ky)

Your dilation factor is 3, so the transformation is ...

  (x, y) ⇒ (3x, 3y)

  A(-1, 4) ⇒ A'(-3, 12)

  B(3, 2) ⇒ B'(9, 6)

  C(-2, -2) ⇒ C'(-6, -6)

Answer:

1981.6

Step-by-step explanation: :))

Answer:

Step-by-step explanation:

Move the decimal point one side to the right when multiplied by 10

198.16 X 10 = 1981.6

(a)the body temperature of the 1601 lb man will increase by approximately 3.0 °C.(b)the body temperature of the 160 lb man will increase by approximately 2.4 °C.

The specific heat of a human is given as 3.47 J/°C. Using this information, we can calculate the increase in body temperature when a certain number of calories are converted into heat energy. In the first scenario, a 1601 lb man consumes a candy bar containing 287 Cal. In the second scenario, a 160 lb man consumes a roll of candy containing 41.9 Cal. We will calculate the increase in body temperature for each case.

(a) To calculate the increase in body temperature for a 1601 lb man who consumes a candy bar containing 287 Cal, we need to convert calories to joules. Since 1 Calorie (Cal) is equal to 4184 joules, we have:
Energy = 287 Cal × 4184 J/Cal = 1.2 × \(10^6\) J
Now, using the specific heat formula Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat, and ΔT is the change in temperature, we can rearrange the formula to solve for ΔT:
ΔT = Q / (mc)
Assuming the mass of the man is converted to kilograms, we have:
ΔT = (1.2 × \(10^6\) J) / (1601 lb × 0.4536 kg/lb × 3.47 J/°C) ≈ 3.0 °C
Therefore, the body temperature of the 1601 lb man will increase by approximately 3.0 °C.
(b) For a 160 lb man who consumes a roll of candy containing 41.9 Cal, we repeat the same calculation:
Energy = 41.9 Cal × 4184 J/Cal = 1.75 × \(10^5\) J
ΔT = (1.75 × \(10^5\) J) / (160 lb × 0.4536 kg/lb × 3.47 J/°C) ≈ 2.4 °C
Thus, the body temperature of the 160 lb man will increase by approximately 2.4 °C.

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The statement that best describes the depth of the fish, given this equation, is this: C. From a starting position of 3 meters below sea level, the fish is descending 7 meters per second.

The first description of this statement should indicate the depth from which the fish descends. From the equation, y is equal to -7x -3. The minus in this case is indicative of descent.

7 is the rate at which the fish travels with respect to time and 3 is indicative of the distance from sea level and the starting point from which the fish moves.

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Answer:

59/130

Step-by-step explanation:

The solutions for differential equations of converge to the function:

y = (t/6) + (1/24)\(e^{-4t}\)

The given differential equation is:

y' + 6y = t + \(e^{-4t}\)

This is a first-order linear differential equation in standard form:

y' + p(t)y = q(t)

where p(t) = 6 and q(t) = t + e^(-4t). To solve this differential equation, we first find the integrating factor, which is given by:

μ(t) = e^(∫p(t) dt) = e^(∫6 dt) = \(e^{6t}\)

Multiplying both sides of the differential equation by μ(t), we get:

\(e^{6t}\) y' + 6\(e^{6t}\) y = t\(e^{6t}\) + \(e^{2t}\)

The left-hand side is the product rule of the derivative of e^(6t) y:

(\(e^{6t}\) y)' = t\(e^{6t}\) +\(e^{2t}\)

Integrating both sides with respect to t, we get:

\(e^{6t}\)y = ∫(t\(e^{6t}\) + \(e^{2t}\)) dt = (t/6)\(e^{6t}\) + (1/24)\(e^{2t}\) + C

where C is an arbitrary constant of integration. Rearranging, we get the general solution:

y = (t/6) + (1/24)\(e^{-4t}\)+ C\(e^{6t}\)

where C is the constant of integration.

To determine how the solutions behave as t approaches infinity, we can examine the term containing the exponential function \(e^{6t}\) in the general solution. As t approaches infinity, the term \(e^{6t}\)approaches zero, so the solutions converge to the function:

y = (t/6) + (1/24)\(e^{-4t}\)

This means that the solutions approach a straight line with slope 1/6 as t gets very large. The exponential term becomes negligible in comparison to the linear term, so the behavior of the solutions is dominated by the linear term.

Differential equations are mathematical equations that involve derivatives of unknown functions. The general solution of a differential equation is a family of functions that satisfies the equation, with one or more parameters that can be determined using initial or boundary conditions.

In this problem, we are asked to find the general solution of a first-order linear differential equation and analyze the behavior of its solutions as t approaches infinity.

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Answer:

4-(-3)=7

-8-(-5)=-3

Step-by-step explanation:

4-(-3)=7

4+3

=7

——

-8-(-5)=-3

-8+5

=-3

A negative times a negative makes a positive

Answer:

(-6,4)

Step-by-step explanation:

add the x coordinates of point A and B(take x coordinate of B as X),then divide the sum of 2 and equal it to 2 which is the x coordinate of the midpoint.

then repeat the same procedure for the y coordinates ,take the sum of y corrdinates divide by 2 and equal to 8.

then u can obtain the coordinates of B.

Let's write the likelihood of a promotion as P(promotion) and the likelihood of a rise as P(raise). The following details are sent to us:

P (promotion) = 0,40 P (promotion or raise) 0,72 P (promotion and raise) 0,25The inclusion-exclusion concept can be used to calculate the likelihood of receiving a rise. This rule states that the probability of two events (A or B) coming together is equal to the sum of each event's individual probabilities less the likelihood that A and B will come together.

P(promotion or raise) equals P(promotion) + P(raise) – P(promotion andraise).

By substituting the specified values, we obtain:

0.7 = 0.40 + P (b) - 0.25

We can rewrite the equation to isolate P(raise) as follows:P(raise) = 0.72-0.40+0.25

P(rise) = 0.57

The likelihood of receiving a rise is therefore 0.57, or 57%.

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The correct answer is the minimal cover of F is:F = {AB→C, AB→S, AB→E, ES→S}

Given, relation schema R(ABC,DE) with functional dependencies F:AB→SCDE→ABAB→SEES→C.

The candidate key of a relation R is a minimal set of attributes that can uniquely identify each tuple in R. To find the candidate key, we can compute the closure of each subset of attributes in R. Let's begin by finding the closure of AB, the subset of R. We can use the functional dependency AB→SC to compute the closure of AB as follows: AB+ = ABSC (by AB→SC)

Next, let's compute the closure of DE, the other subset of R. We can use the functional dependency DE→AB to compute the closure of DE as follows: DE+ = DEABSE (by DE→AB and AB→SE)

Now we have two potential candidate keys, AB and DEABSE. However, we need to check if they are minimal. To do this, we check if any subset of these candidate keys can also function as a candidate key. We can see that neither AB nor DEABSE has any proper subset that can function as a candidate key.

Therefore, both AB and DEABSE are candidate keys for the relation R. Next, let's compute the minimal cover of F. The minimal cover of a set of functional dependencies F is a minimal set of functional dependencies that is equivalent to F.

To find the minimal cover of F, we can use the following steps:

Step 1: Eliminate redundant dependencies. We can eliminate the dependency AB→SC since it is implied by AB→C.

Step 2: Decompose dependencies. We can decompose the dependency AB→SE into two dependencies, AB→S and AB→E, since S and E are not a subset of any other attribute set in F.

Step 3: Eliminate extraneous attributes. We can eliminate the attribute C from the dependency ES→C since C is already determined by AB→C.

Therefore, the minimal cover of F is:F = {AB→C, AB→S, AB→E, ES→S}

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Therefore, In the figure, a∥b  angle m∠7 = 34° .

An angle is a figure in Euclidean geometry made up of two rays that share a vertex, or common terminus, and are referred to as the sides of the angle. Angles of two rays lie in the plane containing the rays. Angles can also result from the intersection of two planes. Dihedral angles are the name given to them.

Here,

Given that a and b are parallel lines,

∠3 and ∠7  are corresponding angles and congruent

m∠3 = 34°

thus ,m∠7 =m∠3 = 34°

so, m∠7 = 34°

Therefore, In the figure, a∥b  m∠7 = 34° .

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Hello!

Five times x increased by three times y is  5x + 3y

To construct a 99% confidence interval for the mean amount spent per owner for an obedience class, we can use the formula: CI = X± Z * (σ / √n).

Where : CI is the confidence interval. X is the sample mean ($109.33). Z is the critical value (corresponding to the desired confidence level of 99%) σ is the population standard deviation ($28.17) n is the sample size (50). First, we need to find the critical value Z. Since the confidence level is 99%, we want to find the Z-value that leaves 0.5% in the tails (0.5% on each side). Looking up this value in a standard normal distribution table, the Z-value is approximately 2.576. Now we can calculate the confidence interval: CI = 109.33 ± 2.576 * (28.17 / √50). Calculating this expression, we get: CI ≈ 109.33 ± 7.865.  The confidence interval is approximately (101.465, 117.195).

Interpretation: We are 99% confident that the true mean amount spent per owner for an obedience class falls within the range of $101.465 and $117.195. This means that if we were to take multiple random samples and construct confidence intervals, 99% of those intervals would contain the true population mean.

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Answer:

Answer: C.Fraction 11 and 1 over 4 cubic inches

Step-by-step explanation:

The volume of a rectangular prism of length L, width W, and height H is given by:

V=LWH

The prism is packed with cubes of a side length of a=1/2 inch. The volume of each cube is:

\(V_c=a^3=\left(\frac{1}{2}\right)^3=\frac{1}{8}\ in^3\)

The prism is packed with L=5, W=3, and H=6, thus the volume (in cubes) is:

V=5*3*6=90\ cubes

Since each cube has a volume of \(\frac{1}{8} in^3\):

\(V=90\cdot\frac{1}{8}=\frac{45}{4}\)

Expressing as a mixed fraction:

\(V=\frac{45}{4}=\frac{44+1}{4}=11\frac{1}{4}\)

Answer: C.Fraction 11 and 1 over 4 cubic inches

The solution for the absolute value equation is x = 10 and x = -14

In this question,

Two thirds times the absolute value of the quantity x plus 2 end quantity minus 8 equals 0. The equation for this statement is 2/3 lx + 2l -8 =0.

The solution for the equation is

\(\frac{2}{3}\) lx + 2l -8 =0

\(\frac{2}{3}\) lx + 2l = 8

Multiply by 3/2 on both sides,

\(\frac{2}{3}\) lx + 2l = 8

\(\frac{2}{3}\) ×\(\frac{3}{2}\)lx + 2l =8×\(\frac{3}{2}\)

=> x +2 = 12

Case 1: Take as positive value

=> x + 2 = 12

=> x = 12 - 2

=> x = 10

Case 2: Take as negative value

=> -(x +2) = 12

=> -x - 2 = 12

=> -x = 12 + 2

=> -x = 14

=> x = -14

Hence, we can conclude that the solution for the absolute value equation is x = 10 and x = -14 is the correct answer

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Answer: She bought 6 $5 magazines and 5 $4 magazines

Step-by-step explanation:

Answer:

uhhh ok

Step-by-step explanation:

Answer:

An atom of sodium has 11 proton, 11 electrons, and 12 neutrons.

Answer

\(12\)

Step by step explanation

\(protons = electrons \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 12 = 12\)

hope this helps

brainliest appreciated

good luck! have a nice day!

The appropriate simulation applet to calculate an approximate p-value is 0.0077.

The strong evidence that a short delay hinders the memorization process is strong data suggests that a brief delay impairs memorization.

Delay or no delay, answer: the number of words remembered

The mean distance between words remembered with and without delay over time is null, or zero.

Alt: The mean distance in words remembered over the long term (with no delay minus with delay) is higher than 0.

Yes, the majority of the lines do skew to the right. The mean for no delay is 10.55 whereas that for with delay is 8.7.

The mean distance in words remembered is 1.85.

1)0.0077 as the p-value

2)Strong data suggests that a brief delay impairs memorization.

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Answer:

I think option 3 but not sure

Step-by-step explanation:

Theoretical probability is what we expect to happen, where experimental probability is what actually happens when we try it out. The probability is still calculated the same way, using the number of possible ways an outcome can occur divided by the total number of outcomes.