the american antelope (pronghorn) and the wildebeest are among the fastest mammals on the planet, particularly at running long distances. the maximum recorded speed for the antelope is 88.5\, \text{km/h}88.5km/h88, point, 5, start text, k, m, slash, h, end text, which it can sustain for nearly one kilometer. on the other hand, the distance, ddd, in kilometers that the wildebeest can run in ttt hours is given by the equation d

Answer:

Velocity of the car at the bottom of the slope: approximately \(20.3\; \rm m \cdot s^{-2}\).

It would take approximately \(3.9\; \rm s\) for the car to travel from the top of the slope to the bottom.

Explanation:

The time of the travel needs to be found. Hence, make use of the SUVAT equation that does not include time.

\(v^2 - u^2 = 2\, a\cdot x\).

Given:

Rearrange the equation \(v^2 - u^2 = 2\, a\cdot x\) and solve for \(v\):

\(\begin{aligned}v &= \sqrt{2\, a \cdot x + u^2} \\ &= \sqrt{2 \times 4.5\; \rm m \cdot s^{-2} \times 45\; \rm m + \left(3\; \rm m \cdot s^{-1}\right)^{2}} \\ &\approx 20.3\; \rm m \cdot s^{-1}\end{aligned}\).

Calculate the time required for reaching this speed from \(u = 3\; \rm m \cdot s^{-1}\) at \(a = 4.5\; \rm m \cdot s^{-2}\):

\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{20.3\; \rm m \cdot s^{-1} - 3\; \rm m \cdot s^{-1}}{4.5\; \rm m \cdot s^{-2}} \approx 3.9\; \rm m \cdot s^{-1}\end{aligned}\).

Answer:

true

Explanation:

Answer:

false

Explanation:

The total distance traveled by the mass after a time interval t is simply twice the time interval t.

In simple harmonic motion, the displacement of an object from its equilibrium position is given by:

x = A cos(ωt)

where x is the displacement of the object at time t, A is the amplitude of the motion, ω is the angular frequency of the motion, and t is the time.

The period T of the motion is the time required for one complete cycle, and is related to the angular frequency by:

T = 2π/ω

Solving for ω, we get:

ω = 2π/T

Substituting this expression for ω in the equation for x, we get:

x = A cos(2πt/T)

The total distance traveled by the mass after one period of oscillation is equal to the total distance traveled by the mass from the initial position to the position it reaches at time T.

This is equal to four times the amplitude of the motion:

Total distance = 4A

Therefore, the total distance traveled by the mass after a time interval t is given by:

Total distance = 4A × (t/T)

Substituting the expression for T in terms of t, we get:

Total distance = \(4A *(t/(2\pi /\omega))\)

Substituting the expression for ω in terms of T, we get:

Total distance = \(4A * (t/T) * (\omega/2\pi )\)

Substituting the expression for ω in terms of A and T, we get:

Total distance = \(4A * (t/T) * (1/T) * (2\pi /A)\)

Simplifying, we get:

Total distance = \(8\pi * (t/T^2) * A\)

Substituting the expression for T in terms of A, we get:

Total distance = \(8\pi * (t/(4\pi ^2A)) * A\)

Simplifying, we get:

Total distance = 2t

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The mechanical advantage that us provided due to lifting the rock is 4.

The term mechanical advantage has to do with the degree of ease that is introduced by the use of simple machines. We know that the entire purpose of a machine is to make work easier.

We also know that the mechanical advantage is the ratio of the load to the effort.

MA = Load/Effort

Load = 600 pounds

Effort = 150 pounds

MA = 600 pounds / 150 pounds

= 4

The lever offer Jeff a mechanical advantage of 4 as he lifts the rock.

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Answer:

The answer is "The location of the bird and time interval between pieces of information".

Explanation:

Please find the complete question in the attached file.

The Radar is the instrument used to gather data from birds by researchers. This would be the primary tool to study the flight behavior of migrating birds with the impact of environmental influences including the ecology of migratory movements, from the broad population group for both the distribution of land areas and geomorphology as well as meteorological systems to the shift in the behavior of airlines of particular birds, especially when responding to lead routes.

Based on the dependence of the electric force on distance, if the distance between the charged rod and the hanging sphere is doubled, the force on the hanging sphere would decrease by a factor of four.

The electric force between two charged objects is inversely proportional to the square of the distance between them. This means that as the distance between the charged rod and the hanging sphere is doubled, the force acting on the hanging sphere decreases by a factor of (\(2^2\)) = 4.

The reason for this relationship is rooted in Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. When the distance is doubled, the denominator of the equation increases by a factor of 4, resulting in a force that is one-fourth of the original force.

Therefore, if the distance between the charged rod and the hanging sphere is doubled, the force on the hanging sphere will be reduced to one-fourth of its original value. This indicates that the electrostatic force between the two objects weakens as the distance between them increases.

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The magnitude of the kinetic frictional force acting on the box is approximately 9.8 N.

To calculate the magnitude of the kinetic frictional force, we can use the formula:

Frictional force = coefficient of kinetic friction * normal force,

where the normal force is equal to the weight of the box.

The weight of the box can be calculated using the formula:

Weight = mass * gravitational acceleration,

where the gravitational acceleration is approximately \(9.8 m/s^2\).

Substituting the given values, we have:

Weight = 5 kg * \(9.8 m/s^2\) = 49 N.

Now we can calculate the magnitude of the kinetic frictional force:

Frictional force = 0.2 * 49 N = 9.8 N.

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--The complete Question is, A box is being pulled to the right with a force of 100 N. The box experiences a kinetic frictional force. The mass of the box is 5 kg and the coefficient of kinetic friction between the box and the surface is 0.2. What is the magnitude of the kinetic frictional force acting on the box? --

In the given situation, as the ball is thrown upward, it gains gravitational potential energy (GPE) while losing kinetic energy (KE). The energy diagram and statement of conservation of energy can be represented as follows: The picture is given below.

Conservation of Energy Statement:

The total mechanical energy of the ball, which is the sum of its gravitational potential energy (GPE) and kinetic energy (KE), remains constant as long as no external forces (such as air resistance) are acting on the ball. Therefore, the decrease in kinetic energy as the ball rises is equal to the increase in gravitational potential energy.

Mathematically, the conservation of energy can be expressed as:

Initial Energy (at release) = Final Energy (at highest point)

KE(initial) + GPE(initial) = KE(final) + GPE(final)

Since the ball is rising upward and its speed is decreasing, the initial kinetic energy is higher than the final kinetic energy. At the same time, the initial gravitational potential energy is lower than the final gravitational potential energy. This conservation principle ensures that the total energy of the ball is conserved throughout its motion.

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Answer:

40 m

Explanation:

The area under v-t graph gives the distance travelled by the particle.

Distance = area of ΔOBC + area of ΔCDE + area of ΔEFG

\(=\dfrac{1}{2}\times 4\times 10+\dfrac{1}{2}\times 2\times 10+\dfrac{1}{2}\times 4\times 5\\\\=40\ m\)

So, the distance travelled by the particle in the time interval t = 0 and t= 10 s is equal to 40 m.

Answer:

Explanation:

im confused

Answer:. B

Explanation: how this helps sry if I'm wrong

The confidence interval for the given sample will be 15±1.711.

The confidence interval for the given sample will be 15±1.711.

To find the answer, we have to know about the confidence interval.

                           \(C= X+t (\frac{d}{\sqrt{n} } )\\ or \\C= X-t (\frac{d}{\sqrt{n} } )\)

t-value for the chosen confidence level, X is the sample mean, d is the standard deviation, and n is the sample size.

                        \(C=15+1.711(\frac{5}{\sqrt{25} } )=15+1.711\\or\\C=15-1.711\)

Thus, the confidence interval for the given sample will be 15±1.711.

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The mass of the truck is 12,974.4kg .

As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force.

Measures a substance's resistance to acceleration in physics. A measure of an object's mass is roughly equivalent to counting the atoms that make up the object. The kilogram serves as the fundamental mass unit. Mass multiplied by the gravitational acceleration equals weight.

50km/h =50×5/18 m/s= 13.88 = 13.9

momentum (p)=180,345 kg.m/s

P=mv

180,345= m X 13.9

m = 180345/13.9

m = 12,974.46

m = 12,974.4

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Einstein's famous formula, E = mc², describes the relationship between mass and energy. It states that energy (E) is equal to mass (m) times the speed of light (c) squared. This formula is actually relevant to the sun, as it helps to explain how the sun produces its energy.

The sun's core is incredibly hot and dense, with temperatures reaching up to 15 million degrees Celsius. This high temperature and pressure cause nuclear reactions to occur, which release enormous amounts of energy.

The nuclear reactions involve the conversion of mass into energy, in accordance with Einstein's formula. Specifically, the sun's core converts hydrogen nuclei (protons) into helium nuclei (alpha particles) and releases energy in the process.

This energy then travels through the sun's layers, eventually reaching the surface and radiating out into space as light and heat.

So, in short, Einstein's formula explains how the sun's core converts mass into energy, which is crucial to the sun's ability to produce light and heat.

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Answer:

a)

Weight in Air = 0.3N

Weight in Water = 0.25N

Weight in Liquid = 0.24N.

Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)

= 0.3 – 0.25

= 0.5N.

b) R.D of Body = Density of Body/Density of Standard Fluid(Water).

There's a Derived Formula for RD.

I'm gonna Apply it here.

Ask me for the derivation in the Comment section if you need it.

RD = α/ρ = (Weight in Air) / (Upthrust Force)

Where

α = density of the Body(or reference substance)

ρ = density of standard fluid (water)

= 0.3/0.05 = 6.

c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)

Or we just go by that formula

RD of Liquid = Weight in Air/Upthrust(In Liquid)

We'll be using the Upthrust in that Liquid now.

= 0.3 – 0.24 = 0.06

RD = 0.3/0.06 = 5.

Therefore, the velocity of the ball just before it hits the ground is approximately 22.1 m/s. Therefore, the closest value to this option is 21.0 m/s.

When a ball of mass 0.25 kg falls from a height of 50 m, we can calculate its velocity using the principle of conservation of energy. According to this principle, the sum of the potential and kinetic energy of an object remains constant.

Therefore, we can equate the potential energy at the initial height to the kinetic energy at the final velocity.Let's calculate the potential energy of the ball at the initial height

:Eg = mghEg = 0.25 kg × 9.81 m/s² × 50 m

Eg = 122.625 J

This is the energy that the ball has due to its position. As it falls, this energy is transformed into kinetic energy. At the moment the ball reaches the ground, all the potential energy has been transformed into kinetic energy

.Ek = 1/2mv²Ek = Egv² = 2Ek/mv = √(2Ek/m)

Let's plug in the values we obtained:Eg = 122.625 Jm = 0.25 kgv = √(2Ek/m)

We obtain:v = √(2 × 122.625 J / 0.25 kg)v = √(245.25 J/kg)v = 22.116 m/s

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Answer:

30 m/s

Explanation:

A boat moves initially at 10 m/s

The boat accelerates at 2 m/s^2 for 10 seconds

We are required to calculate the final velocity (v)

Therefore the velocity of the boat can be calculated as follows

v = u + at

u= 10 m/s

a= 2 m/s^2

t= 10 seconds

v= 10 + 2(10)

v= 10 + 20

= 30 m/s

Hence the velocity of the boat after 10 seconds is 30 m/s

Answer:

negative charge

Explanation:

A specialized part of a cell which has a specific location is called an organelle.

Overall, organelles are specialized parts of a cell that have a specific location and job. They are responsible for carrying out the various functions of the cell, and each type of organelle has a specific role.

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The  planet velocity and position;

a) The change in velocity during the time interval is 1.3 x 10-2 m/s.

b)  The change in the planet's position is 11.4 x 107 m.

Mass is a measure of the amount of matter in an object, and force is the influence that one body exerts on another. Velocity is the speed and direction of an object's motion.

The first step is to calculate the change in velocity. This can be found using the equation F = ma, where F is the force, m is the mass, and a is the acceleration.

The force on the planet comes from the star, and can be calculated using the equation F = GMm/r2,

where G is the gravitational constant, M is the mass of the star, m is the mass of the planet, and r is the distance between the star and the planet.

We can find that the acceleration of the planet is 0.0013 m/s2. To find the change in velocity, we must multiply this acceleration by the time interval.

Therefore, the change in velocity during the time interval is 1.3 x 10-2 m/s.

The next step is to calculate the change in the planet's position. This can be found using the equation Δr = vΔt, where Δr is the change in position, v is the velocity, and Δt is the time interval.

We can find that the change in the planet's position is 11.4 x 107 m.

Using a time interval of 1 x 109 seconds would not produce usable results, as this is much longer than the time it would take for the planet to travel significantly in its orbit around the star.

In such a long time, the force and velocity would change significantly due to the relativistic effects of gravity, and so our equations would not hold.

The distance moved in this long time interval would be significant compared to the distance from the star to the planet, and so the force would no longer be nearly constant.

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Answer:

No, a liter is equal to 1000 milliliters

ITS FALSE DUDE ......

HOPE THIS HELPS

The following mixtures as homogeneous or heterogeneous A. Orange juice without pulp, B. Sweat and C. Cinnamon sugar  is Homogeneous mixture. D. Dirt - Heterogeneous mixture

A mixture is defined as a combination of two or more substances in which the substances retain their unique properties.

There are two types of mixtures: homogeneous and heterogeneous.A homogeneous mixture is a mixture in which the composition of the mixture is uniform throughout, with no visible boundaries between the components.

Homogeneous mixtures are often referred to as solutions, such as saltwater or sugar water, because they have the same chemical and physical properties throughout.

A heterogeneous mixture, on the other hand, is a mixture in which the composition of the mixture is not uniform throughout.

In other words, there are visible boundaries between the components.

Examples of heterogeneous mixtures include sand and water, oil and vinegar salad dressing, and gravel.

Having this in mind, we can classify the following mixtures as homogeneous or heterogeneous: a. Orange juice without pulp - Homogeneous mixture

b. Sweat - Homogeneous mixture c. Cinnamon sugar - Homogeneous mixtured. Dirt - Heterogeneous mixture

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Answer:

The tennis ball.

Explanation:

Because the baseball is heavier, it requires more force to move it, whereas the tennis ball requires less force, so it will move more. Hope that makes sense!

If we apply the same amount of force to a 0.1-kilogram baseball and a 0.05-kilogram tennis ball, then the 0.05-kilogram tennis ball will accelerate more because the force is the product of the mass and acceleration.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem statement If you apply the same amount of force to a 0.1-kilogram baseball and a 0.05-kilogram tennis ball,

force on any object = acceleration × mass of the object

As given the same amount of force is applied to both the objects then the object having less mass would experience a greater amount of acceleration.

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a. The change in potential energy is 30,000,000 Joules

b. The direction of the  electrostatic force exerted on this charge is upward

c. the direction of the electric field between the plates is upward

d. The magnitude of the electric field is 38461.5

The formula is

PE = qΔv

where PE = potential energy

q = charge of 6 x 10⁴

Δv = 500

The potential energy is given as

PE =  500 x  6 x 10⁴

= 30,000,000 Joules

The higher potential plate (bottom) exerts force on the positive charge in the opposite direction to the lower potential plate (up). Thus, the electrostatic force acting on the charge when it is sandwiched between the plates is directed upward.

(c) The electric field is moving upward because it is moving from a higher to a lower potential.

d. E = v / d

= 500 / 0.013

= 38461.5

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A projectile is fired from a tank with initial speed 400 m/s,the two angles of elevation that can be used to hit the target 3000 m away are approximately 0.144 radians (or 8.26 degrees) and 2.997 radians (or 171.74 degrees).

To find the two angles of elevation that can be used to hit a target 3000 m away, we can use the equations of projectile motion. The angles of elevation correspond to the launch angles at which the projectile will reach the target.

Let's denote the initial speed of the projectile as v0 = 400 m/s and the horizontal distance to the target as R = 3000 m.

The horizontal and vertical components of the projectile's velocity are given by:

Vx = v0 * cos(theta)

Vy = v0 * sin(theta)

where theta is the launch angle.

The time of flight, T, is determined by the vertical motion of the projectile and can be calculated using the equation:

T = (2 * Vy) / g

where g is the acceleration due to gravity (approximately 9.8 m/s²).

The horizontal range, R, is determined by the horizontal motion of the projectile and can be calculated using the equation:

R = Vx * T

Substituting the expressions for Vx and T, we have:

R = v0 * cos(theta) * [(2 * v0 * sin(theta)) / g]

Simplifying the equation, we get:

R = (2 * v0^2 * sin(theta) * cos(theta)) / g

Now we can solve this equation to find the launch angles theta that satisfy the given range R.

Rearranging the equation, we have:

sin(2 * theta) = (R * g) / (2 * v0^2)

Taking the inverse sine of both sides, we get:

2 * theta = arc sin((R * g) / (2 * v0^2))

theta = (1/2) * arc sin((R * g) / (2 * v0^2))

Now we can substitute the given values to calculate the two angles of elevation:

theta₁ = (1/2) * arc sin((R * g) / (2 * v0^2))

theta₂ = π - theta₁

where π is the value of pi (approximately 3.14159).

Substituting the values, we have:

theta₁ = (1/2) * arc sin((3000 * 9.8) / (2 * 400^2))

theta₂ = π - theta₁

Calculating the values, we find:

theta₁ ≈ 0.144 radians (or approximately 8.26 degrees)

theta₂ ≈ 3.141 - 0.144 ≈ 2.997 radians (or approximately 171.74 degrees)

Therefore, the two angles of elevation that can be used to hit the target 3000 m away are approximately 0.144 radians (or 8.26 degrees) and 2.997 radians (or 171.74 degrees).

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The shape of the graph will be linear and the average acceleration is -0.278 m/s².

The average acceleration of an object is the rate of change of velocity of the object with time.

Mathematically it is given as;

a = Δv/Δt

a = (v2 - v1)/(t2 - t1)

where;

Substitute the given parameters and solve for the average acceleration.

a = (8.33 - 13.89) / (40 - 20)

a = -0.278 m/s²

Thus, the shape of the graph will be linear and the average acceleration is -0.278 m/s².

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When a  plane flies horizontally at an altitude of 5 km and passes directly over tracking telescope on the ground, then the plane is traveling at the speed of 8.69 km/min.

The angle of elevation is widely used for height and distance in trigonometry. It is defined as the angle between horizontal plane and oblique line from the observer's eye to any object above his eye.

tan(θ) = opposite / adjacent

tan(θ) = y/x

x tan(θ) = y

x = y/tan(θ)

x = 5/tan( π/3)

dx/dt * tan(θ) + x * sec²(θ) * dθ/dt = d y /dt

As altitude remains the same, d y/dt = 0

dx/dt * tan(π/3) + 3/tan(π/3) * sec²(π/6) * -π/6 = 0

dx/dt = [5/tan(π/3) * sec²(π/3) * π/6} / tan(π/3)]

= 5/0.018* 3413.6 * 0.52/ 0.018

= 8.69 km/min

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: A plane flies horizontally at an altitude of 3 km and passes directly over a tracking telescope on the ground. when the angle of elevation is π/6, this angle is decreasing at a rate of π/4 rad/min. how fast is the plane traveling at that time?

In comparison to Earth, Mars will have more extreme weather/climatic conditions

Axial tilt is the angular measure between the axis of rotation and the axis of revolution. it affects the extents of varying climatic conditions in a direct proportional relationship. This means that the more the axial tilt the more the difference in extremes of the climatic condition.

Therefore comparing the two axial tilts one can arrive at. Mars having more axial tilt will have more extreme seasonal conditions than Earth.

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Answer:

F= 1800N

Explanation:

the equation for force is F= ma

so plug in the numbers: F= (120)(15)

solve this to get F= 1800N

tip: don't forget to add the units when writing your answer :)

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

so

\((m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1\)

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

When the ice skater pulls in her arms, she decreases her moment of inertia by a factor of two. Moment of inertia is the measure of an object's resistance to rotational motion, and it is directly proportional to the object's mass and the distribution of that mass around the axis of rotation. So, by pulling in her arms, the ice skater is reducing the mass that is farther away from the axis of rotation (her body), thus decreasing the moment of inertia.

Now, according to the law of conservation of angular momentum, the product of an object's moment of inertia and angular speed must remain constant as long as no external forces act on the object. This means that when the ice skater decreases her moment of inertia by a factor of two, her angular speed must increase by a factor of two in order to maintain the same angular momentum.

Therefore, the correct answer is that her angular speed increases by a factor of two. It is important to note that this increase in angular speed is not due to an external force acting on the skater, but rather a result of the conservation of angular momentum.

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