The average birth weight of a new born baby is 7 pounds. However, this weight can vary as much as 4.5 pounds. What is an absolute value inequality to describe this situation?

An ice hockey puck glides across frictionless ice, the forces acting on it are: Weight, Gravity Fc, and Force of hockey stick Fho. Therefore, options B: Weight, E: Gravity Fc, and F: Force of hockey stick Fho are the correct answers.

The ice hockey puck is gliding across frictionless ice, so there is no kinetic friction acting on it. There is also no normal force acting on the puck since it is not in contact with any surface. However, there is a gravitational force acting on it due to the earth's gravity, and there could also be a force applied to the puck by a hockey stick.

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Option A. Supports this knowledge. Yes, The beverage will cool faster inside the freezer than the ordinary part of the refrigerator.

Newton's regulation of cooling states that the fee at which an object cools is proportional to the difference in temperature between the item and the item's environment. genuinely put, a pitcher of hot water will settle down faster in a cold room than in a hot room.

Newton's law of cooling explains the rate of cooling of a frame. The charge at which an item cools down is immediately proportional to the temperature difference between the object and its surroundings.

Newton's regulation of cooling applies to both warming and cooling. the heat loss with time is dependent on the distinction in temperature between the 2 our bodies.

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Disclaimer:- your question is incomplete, please see below for the complete question.

it is commonly thought that a can of beverage will cool faster in the coldest part of a refrigerator. knowledge of newton's law of cooling,

A. Supports this knowledge

B. Show this knowledge is false

C. May or may not support this knowledge

D. May or may not contradict this knowledge

Answer:

Changing nuclear energy to radiant energy

Explanation:

   Conversely, potential energy is a type of energy stored in an object, which can be converted to kinetic energy.

   Nuclear energy is a type of potential energy because this energy is stored in the atomic nucleus.

In conclusion, changing nuclear energy to radiant energy is an example of transforming potential energy into kinetic energy.

Answer:

if you stand still, that's potential energy, and if you move that's kinetic energy.

Explanation:

When standing still, you aren't moving, which the potential energy now is enact, but if you move a muscle, even the tiniest one, it will cause a transformation into kinetic energy.

Answer:

41895 J

Explanation:

GPE= mgh

m=95

g=9.8

h=45

95*9.8*45

The gravitational potential energy of the rock at the top of the cliff is 41895 Joules.

Gravitational potential energy is simply the potential energy an object possessse in relation to another object due to gravity.

It is expressed as;

U = mgh

Given the data in the question;

We substitute our values into the expression above.

U = mgh

U = 95kg × 9.8m/s² × 45m

U = 41895kgm²/s²

U = 41895J

Therefore, the gravitational potential energy of the rock at the top of the cliff is 41895 Joules.

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Considering the following function_ g(v) = 27v + 3

The derivative of the function g'(v) = 27.

There are no values of v that satisfy the condition g'(v) = 0, and we can write: DNE

There are no values of v in the domain of g(v) that would make the derivative undefined, and we can write:
DNE

There are no critical numbers of g(v), and we can write: DNE

To find the derivative of g(v) = 27v + 3, we need to use the power rule of derivatives, which states that the derivative of constant times a variable raised to a power is equal to the constant times the derivative of the variable raised to that power minus one. In this case, since the variable is just v raised to the power of 1, the derivative of g(v) is simply the coefficient of v, which is 27. Therefore, we have:
g'(v) = 27
To find the values of v such that g'(v) = 0, we simply set the derivative equal to zero and solve for v:
27 = 0
This is not possible, since there is no value of v that would make the derivative of g(v) equal to zero. Therefore, there are no values of v that satisfy this condition, and we can write:
DNE
To find the values of v in the domain of g(v) such that g'(v) does not exist, we need to look for values of v that would make the derivative undefined. Since the derivative of g(v) is a constant function, it is defined for all values of v. Therefore, there are no values of v in the domain of g(v) that would make the derivative undefined, and we can write:
DNE
To find the critical numbers of g(v), we need to look for values of v where the derivative is either zero or undefined. However, as we saw earlier, the derivative of g(v) is always equal to 27, which is a constant value. Therefore, there are no critical numbers of g(v), and we can write:
DNE

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Answer:

minerl in shells

Explanation:

Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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Longitudinal waves

Transverse waves

Electromagnetic Waves

Water waves

Rope waves

LIght Waves

Answer:

since the charges are of different nature it's a attractive force

Explanation:

magnitude of force=

9*10^9*5*10^-6*3*10^-6/0.04

= 3.375N answer

For a grating with 500.0 slits/mm, the angles for two wavelengths in second order are 31.08 degrees and 31.84 degrees, with an angular separation of 0.76 degrees.

The equation for calculating the angle for a diffraction grating is given by nλ = d(sinθ), where n is the order of diffraction, λ is the wavelength of light, d is the grating spacing, and θ is the angle of diffraction.

For the given grating with 500.0 slits/mm, the grating spacing is 2.00 μm.

In the second order (n=2), we can solve for the angles of diffraction for two wavelengths: 400 nm and 600 nm.

Plugging in the values, we get angles of 31.08 degrees and 31.84 degrees, respectively.

The angular separation between these two wavelengths is found by taking the difference between the angles, which is 0.76 degrees.

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Larry Page, real name Lawrence Edward Page, is a computer scientist and entrepreneur from the United States who co-founded Goo-gle, one of the most well-known websites on the Internet, with Sergey Brin on March 26, 1973 in East Lansing, Michigan.

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It's important to remember that not all individuals will experience the same physical changes at the same rate, and some may experience different changes due to genetics, lifestyle, and other factors.

Yes, there are differences in the physical appearance of an individual in each stage of their development. Here are some of the physical differences that typically occur at different stages:

It's important to remember that not all individuals will experience the same physical changes at the same rate, and some may experience different changes due to genetics, lifestyle, and other factors.

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Given:

Original distance between the planets, d1 = 5 x 10¹⁰ km

Distance after the planets moved, d2 = 2 x 10¹⁰ km.

Let's determine what would happpen to the gravitational force between the planets.

Apply the formula:

Let F1 be the gravitational force before the movement.

Let F2 be the gravitational force after the movement.

Equate both equations

Now, for the two gravitational forces, we have the equations:

The relationship between the gravitational force between planets and the distance is:

The gravitational force is inversely proportional to the square of the distance between the planets.

Thus, we have:

We can see the force after the movement F2 is greater than the force before the movement F1.

Therefore, the gravitational force will increase.

ANSWER:

Increase.

The refractive index (n) of a medium is defined as the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v). Therefore, n = c/v. In this case, the speed of light in the medium is given as 1.2×10^8 m/s.

The speed of light in vacuum is approximately 3×10^8 m/s. Therefore, the refractive index of the medium can be calculated as follows:   n = c/v = 3×10^8 m/s / 1.2×10^8 m/s = 2.5
Hence, the refractive index of the medium is 2.5.

Light bends away from the normal (a line perpendicular to the surface of the medium) as it moves from a media with a higher index of refraction to a medium with a lower index of refraction. On the other hand, light bends towards the normal as it moves from a medium with a lower index of refraction to a medium with a higher index of refraction. When a surface is concave, light rays arriving from an object are bent towards the normal, and then they are bent away from the normal as they leave the object.

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Light waves are bent more easily than sound waves is refereed to as a false statement.

This is referred to as the propagation of disturbances from one place to another in a regular and organized way. There is always the transfer of energy during this process however the matter doesn't move and there are different types such as sound and light waves.

Sound waves is a type of wave which has a lower wavelength and are slowed more which is therefore the reason why it is bent more easily than light waves who has a higher wavelength.

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The statement is True, The MPC for a country will likely be measured as less than 1.

MPC in physics stands for "Multipurpose Ceramic". However, it's unclear what specific context you are referring to as MPC could stand for many different things in physics, depending on the field and application. For example, in particle physics, MPC could stand for "Minimum Projected Calorimeter", which is a type of calorimeter used to measure the energy of particles.

In astrophysics, MPC could refer to "Minor Planet Center", which is an organization responsible for collecting and disseminating information about minor planets, comets, and natural satellites. In materials science, MPC could refer to "Metal-Plastic Composite", which is a type of material made by combining metal and plastic components. In optics, MPC could refer to "Micro-structured Polymer Composite", which is a material used for making diffractive optical elements.

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A. Mid-ocean ridges.Mid-ocean ridges often occur at divergent plate boundaries.

These undersea mountain ranges are formed by the upwelling of magma from the Earth's mantle, creating new oceanic crust. As tectonic plates move apart, molten material rises to fill the gap, solidifies, and forms a new section of ocean floor. This process of seafloor spreading results in the formation of mid-ocean ridges.

The correct feature that often occurs at divergent plate boundaries is A. Mid-ocean ridges.

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In conclusion, when conducting bars slide frictionless on conducting rails that have resistance, and the setups are placed in a region with a uniform magnetic field, it gives rise to electromagnetic induction and the Lorentz force.

When conducting bars slide frictionless on conducting rails that have resistance, and the setups are placed in a region with a uniform magnetic field, it gives rise to the phenomenon of electromagnetic induction.

Electromagnetic induction is the process of generating an electromotive force (EMF) across a conductor in a changing magnetic field. It is due to this process that we have electric generators, electric motors, and other similar devices that are widely used today.

According to Faraday’s law of electromagnetic induction, the EMF induced in a circuit is directly proportional to the rate of change of magnetic flux linkage with the circuit. Magnetic flux linkage is the product of magnetic flux and the number of turns of wire.

Magnetic flux, in turn, is the product of the magnetic field and the area of the circuit.

A changing magnetic field causes a changing flux, which in turn leads to an induced EMF and a current in the circuit.

The conducting bars slide on the rails, and since they are in a region with a uniform magnetic field, a force is generated on the bars due to the interaction between the magnetic field and the current flowing through them.

This phenomenon is known as the Lorentz force. The force generated can be calculated using the equation:

F = BILsinθ,

where F is the force, B is the magnetic field, I is the current, L is the length of the conductor, and θ is the angle between the magnetic field and the conductor.

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Answer: How would you use a number linee to determine the sum of two negative integers?

Explanation:

Answer:

The tangential acceleration is 0 m/s².

Explanation:

Answer:

The tangential acceleration is 0 m/s².

Explanation:

A shadow zone occurs for P-waves because P-waves refract as they go through the outer core, following a curved path through the mantle, and they do not travel through the outer core.

In more detail, P-waves are generated during earthquakes and propagate through Earth's layers. When they reach the outer core, which is liquid, their speed decreases, causing them to refract or bend.

This refraction creates a curved path through the mantle, leading to an area on Earth's surface where P-waves are not detected, known as the shadow zone. The shadow zone occurs between approximately 103 and 142 degrees from the earthquake's epicenter.

P-waves can still be detected beyond this range because they refract again as they exit the outer core, returning to a more direct path. The fact that P-waves do not travel through the outer core contributes to the formation of the shadow zone, as their energy is not transmitted through this layer.

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Answer:

The time it takes the ball to fall 3.8 meters to friend below is approximately 0.88 seconds

Explanation:

The height from which the student tosses the ball to a friend, h = 3.8 meters above the friend

The direction in which the student tosses the ball = The horizontal direction

Given that the ball is tossed in the horizontal direction, and not the vertical direction, the initial vertical component of the velocity of the ball = 0

The equation of the vertical motion of the ball can therefore, be represented by the free fall equation as follows;

h = 1/2 × g × t²

Where;

g = The acceleration due gravity of the ball = 9.81 m/s²

t = The time of motion to cover height, h

Then height is already given as h = 3.8 m

Substituting gives;

3.8 = 1/2 × 9.81 × t²

t² = 3.8/(1/2 × 9.81) ≈ 0.775 s²

∴ t = √0.775 ≈ 0.88 seconds

The time it takes the ball to fall 3.8 meters to friend below is t ≈ 0.88 seconds.

Jon had a flat tire on his car. He used a hydraulic jack to lift the car up so that he could change the tire. If Jon knows the amount of force used to lift the car 0.25 meter off of the ground, he is able to calculate the work done by the jack (option d).

Explanation:

In physics, work is defined as the amount of energy transferred when a force acting on an object causes it to move a certain distance.

Work (W) is defined as

W = F × d,

where F is the force exerted on an object and d is the distance the object moves in the direction of the force.

In the given scenario, Jon used a hydraulic jack to lift the car, which means he applied a force to the jack to lift the car up. The amount of force Jon applied to the jack is given in the question.

Therefore, if he knows the distance the car was lifted, he can calculate the work done by the jack using the formula

W = F × d.

As Jon lifted the car 0.25 meter off of the ground, he can use this distance value in the formula along with the force value he knows to calculate the work done by the jack.

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The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,

F = kx

Therefore,

k = F/x

We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,

K = 50.174/0.25 N/m

K = 200.696 N/m

Therefore, The Spring Constant is 200.696 N/m

On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:

h = \(1/2 kx^{2}\)

We know that k=200.696 N/m and x=0.25 m. Therefore the height is:

h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)

h = 2.5087 m

Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

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10.2 cm separates the hubcap from the face. The magnitude of the hubcap's radius of curvature is 0.318 cm.

To determine the distance between the enthusiast's face and the hubcap, use the concept of mirror images formed by curved surfaces.

In the first scenario, when the enthusiast sees an image of his face 10.2 cm behind the hubcap, we can assume that the hubcap acts as a concave mirror.

The distance between the face and the hubcap is equal to the focal length of the mirror.

Therefore, the face is 10.2 cm away from the hubcap.

In the second scenario, when the hubcap is turned over, it now acts as a convex mirror.

The distance between the face and the hubcap remains the same.

From the given information, the image of the face appears 29.4 cm behind the hubcap.

This distance corresponds to the focal length of the convex mirror, which is negative. So, the focal length is -29.4 cm.

To find the magnitude of the radius of curvature, we can use the mirror equation:

1/f = 1/v - 1/u,

where f is the focal length, v is the image distance, and u is the object distance.

Plugging in the values:

1/-29.4 = 1/29.4 - 1/10.2.

Simplifying the equation:

\(1/-29.4 = (10.2 - 29.4)/(29.4 * 10.2).\)

Solving for the left-hand side:

-29.4 = -0.318.

Taking the reciprocal of both sides:

-1/29.4 = -1/0.318.

Thus, the magnitude of the radius of curvature is approximately 0.318 cm.

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Answer:

When two objects collide, the forces that are exerted on each other are determined by their masses and speeds. If the mass of one of the objects is increased, the force that it exerts on the other object during the collision will also increase. Similarly, if the speed of one of the objects is increased, the force that it exerts on the other object during the collision will also increase. In general, the greater the mass and speed of an object, the greater the force that it will exert on another object during a collision. However, it is important to note that the direction of the forces will remain the same, regardless of the masses or speeds of the objects involved.

Answer:

B. Chemical energy -> Thermal energy

Explanation:

the candle burning is a chemical reaction where the fire is using the oxygen in the air and the chemicals in the wick and it ends with giving off thermal energy. thermal energy is heat energy.

(this might not be right, i'm 95% sure it is though)

The given photo is showing the transformation of chemical energy into thermal energy. Therefore, option (B) is correct.

Chemical energy can be explained as the energy emitted by chemical substances in a chemical reaction. Chemical energy is stored in batteries,  gasoline, and food. The energy is absorbed by or released in a chemical system when the chemical bonds form or break.

Chemical energy is stored in the chemical bonds of chemical compounds and the reaction produces heat energy as a side product in an exothermic reaction.

The stored in biomass, natural gas, batteries, petroleum, and coal is chemical energy. When this energy is emitted by a substance, it is converted into a new substance.

Therefore, the chemical energy in the burning of candles is converted into thermal energy as the candle and the oxygen in the air burm and produce heat energy.

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Answer:

True

Explanation:

We have that the statement is

True

Kinesiology

Kinesiology  is the study of human movement,and functions by inducing other sciences of like exercise psychology , exercise sociology and other science that studies human movement and performance

Therefore

The Statement is True

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Answer:

A single-called organism must perform all cellular functions on its own

Explanation:

i took the test

Therefore, the uncertainty in the estimate of the sound velocity in the air at T = 300 ± 0.4 K is approximately ±0.232 m/s.  A. To estimate Velocity.

We can substitute T = 300 K into the given equation: v = 20.04√T; v = 20.04√300. v ≈ 346.54 m/s

Therefore, the estimated velocity of sound in air at T = 300 K is approximately 346.54 m/s. B. To find the uncertainty in the estimate, we can use the formula for propagation of uncertainties: Δv = |∂v/∂T| ΔT. where Δv is the uncertainty in v, ΔT is the uncertainty in T, and |∂v/∂T| is the absolute value of the partial derivative of v with respect to T. Taking the partial derivative of the given equation: ∂v/∂T = 20.04/(2√T)

Substituting T = 300 K: ∂v/∂T = 20.04/(2√300) ≈ 0.5792 m/(s·K)

Substituting the given uncertainty ΔT = 0.4 K:

Δv = |∂v/∂T| ΔT

Δv = 0.5792 × 0.4

Δv ≈ 0.232 m/s

Therefore, the uncertainty in the estimate of the velocity of sound in air at T = 300 ± 0.4 K is approximately ±0.232 m/s.

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