The average bond dissociation energy of carbon-carbon bond is 410 kj/mol. 292 wavelength in nanometers of the ultraviolet radiation has an energy of 410 kj/mol.
What do you mean by wavelength?The distance between the two successive crests or troughs of wave is known as its wavelength. It is measured in wave's direction.
The distance wave travels between its crests or troughs is known as its wavelength (which may be an electromagnetic wave, a sound wave, or the any other wave). Wave's crest is its highest point, while its dip is the lowest. Since wavelength is a measure of both the distance and length, it is expressed in the length units such meters, centimeters, millimeters, and nanometers.
Wavelength of light varies with the colors, i.e., it is different for the every color. Red color has the longest wavelength while violet has least. The wavelength of the UV radiation is shorter than the violet light. Similarly, the wavelength of the infra red radiation is longer than the wavelength of red light.
To know more wavelength visit: https://brainly.com/question/13533093
#SPJ4
Using the letters for the seven colours and starting with R (Red), what is the correct order for the colours in a rainbow? Your answer should be in the form RXXXXXX Which of these seven colours has the shortest wavelength?
Answer:
Red
Orange
Yellow
Green
Blue
Indigo
Violet
shortest wavelength: violet (380 nanometers)
¯\(°_o)/¯
Answer:
Red Orange Yellow Green Blue Indigo Violet
violet has the shortest wavelength
happy to help :)
What is the acceleration of a rocket with 500N of thrust force and a mass 10kg?
Explanation:
F=ma
500N=10×a
a=500÷10=50m/s²
PLEASE GIVE BRAINLIEST
Answer:
50m^2
Explanation:
acceleration=f/m
what is the angular displacement formula?
Angular displacement is defined as “the angle in radians (degrees, revolutions) through which a point or line has been rotated in a specified sense about a specified axis”.
Formula:
S = rθ
∴ S = arc length
r = distance
θ = angular displacement
When compared to winds at the surface, winds at 2,000 feet areA. higher due to absence of frictionB. higher and go at right angles to the isobars due to frictionC. higher because they move from an area of higher pressure to lower pressure
When compared to winds at the surface, winds at 2,000 feet are typically higher due to the absence of friction.
At the surface, winds are affected by friction with the Earth's surface, which slows them down and causes them to move in a more turbulent and erratic fashion. However, as winds move up in altitude, they encounter less and less friction, allowing them to increase in speed and flow in a more uniform and predictable manner.
While friction may still have some influence on winds at 2,000 feet, it is not as significant as at the surface. Therefore, winds at this altitude tend to move more smoothly and follow a more consistent path, often perpendicular to the isobars (lines of equal pressure) on a weather map. This makes them useful for aviation purposes, as pilots can use this information to plan their flight paths and take advantage of favorable tailwinds or avoid dangerous crosswinds.
In contrast, winds at the surface are more affected by local topography, temperature gradients, and other factors that can cause them to vary widely in direction and speed. Overall, winds at 2,000 feet are an important component of the Earth's atmospheric circulation system, and understanding their behavior is essential for predicting weather patterns and ensuring safe air travel.
Learn more about friction :
https://brainly.com/question/13000653
#SPJ11
what is the weight of a 45kg box
____ N
The weight of a \(45 kg\) box is \(441.45 N\).
Weight refers to the measure of the force exerted on an object due to the gravitational pull of the Earth.
Given the mass of the box is \(m=45 kg\).
The weight of an object (\(W\)) can be found by multiplying the mass of the object (\(m\)) by the acceleration due to gravity (\(g\)).
So, \(W=mg\).
It is known that acceleration due to gravity, \(g=9.81 m/s^2\).
Hence, the weight of the box, \(W=(45kg)\times (9.81 m/s^2)\).
\(\Rightarrow W=441.45 (kg\cdot m/s^2)\\\Rightarrow W=441.45 N\)
Therefore, the weight of the box is \(441.45 N\).
Learn more about the weight here: brainly.com/question/86444
Ammeters must be connected in _____ with the circuit
A) parrellel
B) series
C) vertical
D) hortizontal
Ammeters must be connected in series with the circuit in order to accurately measure the current flowing through the circuit. When an ammeter is connected in parallel with a circuit, it creates a low-resistance path, which can alter the current in the circuit and give inaccurate readings.
When an ammeter is connected in series, it becomes a part of the circuit and allows the current to flow through it. This way, the ammeter measures the actual current in the circuit, without altering it.
It is important to note that ammeters should only be connected in series with a circuit that is properly designed and has the necessary safety measures in place. Incorrectly connecting an ammeter can create a hazard and damage the equipment. Therefore, it is important to follow proper procedures and safety guidelines when using ammeters to measure electrical current.
learn more about ammeter Refer: https://brainly.com/question/27206933
#SPJ11
u-shaped Tube of uniform cross-sectional area, the length of each branch is 33 cm and its area is 2cm² contains an amount of mercury of height 6.8cm. find the volume of the largest amount of water that can be poured in one of the two branches knowing that the density of water is 1 g/cm³, the density of mercury is 13.6 g/cm³
The maximum volume of water that can be poured into one of the branches is 2 cm² x 3.4 cm = 6.8 cm³.
Let's first find the volume of the mercury in the tube.
The height of the mercury in the tube is 6.8 cm. Since the cross-sectional area of the tube is uniform, the volume of the mercury is given by:
Volume of mercury = area of cross-section x height of mercury
= 2 cm² x 6.8 cm
= 13.6 cm³
Now, let's find the maximum volume of water that can be poured into one of the branches. We'll assume that all the mercury in that branch is pushed up to the top of the branch, and that the water is poured in until it reaches the same height.
Let's call the height of the water in the branch "h".
The volume of water in the branch is then given by:
The volume of water = area of cross-section x height of water
= 2 cm² x h
For the water to reach the same height as the mercury in the other branch, we need:
Volume of water = Volume of mercury
2 cm² x h = 13.6 cm³
Solving for h, we get:
h = 6.8 cm³ / 2 cm²
h = 3.4 cm
Therefore, the maximum volume of water that can be poured into one of the branches is 2 cm² x 3.4 cm = 6.8 cm³.
learn more about density here
https://brainly.com/question/1354972
#SPJ9
show that pv=nrt has the same unit with energy
Answer:
The unit of the equation P·V = n·R·T is the Joules which is the same as the unit of energy
Explanation:
The unit of energy is Joules, with symbol J
The given equation for an ideal gas is P·V = n·R·T
Where;
P = The pressure of the gas with units Pascals, Pa
V = The volume of the gas, with units m³
n = The number of moles with unit moles
R = The universal gas constant = 8.314 J/(mol·K)
T = The temperature, with units, Kelvin, K
Therefore, we get;
P·V has unit 1 Pa × 1 m³ = 1 N/m² × 1 m³ = 1 N·m = 1 Joule
Similarly, we get
n·R·T with units n mole × 8.314 J/(mol·K) × 1 K = 8.314·n Joules
Therefore, P·V = n·R·T, has the unit of Joules which is the same unit with energy.
Which factors are used to calculate the kinetic energy of an object? Check all that apply. gravity velocity volume mass heig
Answer:
mass , velocity
Explanation:
K.E= 1/2 X mv2
True or False. Friction can be reduced by lubricating or changing the shape of objects.
O True
OFalse
Answer: true
Explanation:
Answer:
true
Explanation:
Using lubricants such as oil or grease can reduce the friction between the surfaces
Suppose that the ultrasound source placed on the mother's abdomen produces sound at a frequency 2 MHz (a megahertz is 10^610 6 Hz). Sound travels through tissue at roughly the same speed as in water (v\approx 1500v≈1500m/s). Find the maximum change in frequency between the sound that is emitted by the device and the sound that is observed at the wall of the baby's heart. Treat the heart wall as a moving observer. Hint: you will need to use your answer from part (a). Give your answer as a positive number in Hz.
Answer:
the maximum frequency observed is 2.0044 10⁶ Hz
Explanation:
This is a Doppler effect exercise. Where the emitter is still and the receiver is mobile, therefore the expression that describes the process is
f ’= \(f_o \ ( \frac{v \pm v_o}{v} )\)
the + sign is used when the observer approaches the source
typical speeds of a baby's heart stop are around 200 m / min
let's reduce to SI units
v₀ = 200 m / min (1 min / 60 s) = 3.33 m / s
let's calculate
f ’= 2 10⁶ (\(\frac{1500 \ \pm 3.33}{1500}\))
f ’= 2.0044 10⁶ Hz
f ’= 1,9956 10⁶ Hz
therefore the maximum frequency observed is 2.0044 10⁶ Hz
two identical spheres of mass 1 kg are plafed near each other. to keep the spheres apart, a light spring is placed between them. the spring has a natural length of 1.0 m. if equilibrium is a chived when the spheres are 0.2 m apart, what is the spring constant of the spring
The spring constant of the spring is 25 N/m.
We can use Hooke's law, which states that the force exerted by a spring is proportional to its displacement from its equilibrium position, to solve for the spring constant.
In this problem, the spring is compressed by a distance of 0.8 m (from its natural length of 1.0 m to a length of 0.2 m) to keep the spheres apart.
Therefore, the force exerted by the spring can be calculated as:
F = kx
where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.
Plugging in the given values:
F = k(0.8 m)
We know that the equilibrium is achieved when the net force on the spheres is zero. Therefore, the force exerted by the spring must be equal in magnitude and opposite in direction to the force of gravity pulling the spheres together.
The force of gravity can be calculated as:
Fg = Gm^2/r^2
where Fg is the force of gravity, G is the gravitational constant, m is the mass of each sphere (1 kg in this case), and r is the distance between the centers of the spheres (0.2 m + 0.5 m + 0.2 m = 0.9 m).
Plugging in the given values:
Fg = (6.67 x 10^-11 N m^2/kg^2)(1 kg)^2/(0.9 m)^2
Fg = 8.27 x 10^-8 N
Since the force of gravity and the force exerted by the spring must be equal in magnitude and opposite in direction at equilibrium, we can set them equal to each other:
F = Fg
k(0.8 m) = 8.27 x 10^-8 N
Solving for k:
k = (8.27 x 10^-8 N)/(0.8 m)
k = 25 N/m
Therefore, the spring constant of the spring is 25 N/m.
Learn more about Hooke's law: https://brainly.com/question/30379950
#SPJ11
A mass-spring system consists of an ideal spring that can compress and stretch equally well. The spring has spring constant k and un-stretched length L. The spring is connected to a cart of mass M which can roll freely on a horizontal surface. If the cart is pulled to one side a small distance and released, it will oscillate back and forth with amplitude A and frequency f.
Increasing the mass will,
decrease the frequency of the system
As the Mass is increased, the frequency and hence the pitch decrease. This is quite familiar to most of us. For example, the thick strings on a piano or a guitar produce the lower tones.
Masses in vibrational systems undergoing simple harmonic motion will have a certain time period for their oscillation.
The frequency is the inverse of the time period and is equal to the number of oscillations completed per unit time.
Hence, the greater is the mass, lesser is the frequency and vice versa
https://brainly.com/question/21667239
#SPJ4
Jessie and Jaime complete a 5.0 km race. Each has a mass of 68 kg. Jessie runs the race at 15 km/h; Jaime walks it at 5 km/h. How much metabolic energy does each use to complete the course
The total metabolic energy used by each to complete the course is determined as 656.91 J.
Kinetic energy of Jessie and JaimeThe kinetic energy of Jessie and Jaime is calculated as follows;
K.E = ¹/₂mv²
where;
m is mass of Jaimev is speed15 km/h = 4.17 m/s
5 km/h = 1.39 m/s
K.E = ¹/₂(68)(4.17)² + ¹/₂(68)(1.39)²
K.E = 656.91 J
Thus, the total metabolic energy used by each to complete the course is determined as 656.91 J.
Learn more about kinetic energy here: https://brainly.com/question/25959744
#SPJ1
The frequency of a certain sound is 440 Mz. What is the wavelength of this sound when the temperature of the air is (a) 20°C; (b) 30°C
Answer:
Explanation:
We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for
λ
:
λ
=
v
f
Let's plug in our given values and see what we get!
λ
=
340
m
s
440
s
−
1
λ
=
0.773
m
What are the possible magnetic quantum numbers (me) associated with each indicated value of £? When l = 2, me = O 0,1,2 O-2, -1,1,2 0 -2,2 O-2, -1,0,1,2 When l = 4, m = O -4.-3.-2, -1.1,2,3,4 0 -4,-3, -2,-1,0,1,2,3,4 O 0,1,2,3,4 O -4,4
(a) When l = 2, the possible magnetic quantum numbers (mₑ) are -2, -1, 0, 1, and 2.(b) When l = 4, the possible magnetic quantum numbers (mₑ) are -4, -3, -2, -1, 0, 1, 2, 3, and 4.
(a) The magnetic quantum number (mₑ) represents the projection of the orbital angular momentum along a chosen axis. It takes on integer values ranging from -l to +l, including zero. When l = 2, the possible values for mₑ are -2, -1, 0, 1, and 2. These values represent the five different orientations of the orbital angular momentum corresponding to the d orbital.
(b) Similarly, when l = 4, the possible values for mₑ are -4, -3, -2, -1, 0, 1, 2, 3, and 4. These values represent the nine different orientations of the orbital angular momentum corresponding to the f orbital. The range of values for mₑ is determined by the value of l and follows the pattern of -l to +l, including zero.Therefore, when l = 2, the possible magnetic quantum numbers (mₑ) are -2, -1, 0, 1, and 2. And when l = 4, the possible magnetic quantum numbers (mₑ) are -4, -3, -2, -1, 0, 1, 2, 3, and 4.
Learn more about quantum numbers here:
https://brainly.com/question/14288557
#SPJ11
What is the energy of a photon with a frequency of 2.2 x 1016 Hz? Planck's constant is 6.63 x 10-34 Jos.
O 1.5 x 10-17
8.8 x 10-17
O 1.5 10-16
O 8.8 10-16
Answer: 1.5 × 10^-17
Explanation:
Given the following :
Frequency(f) = 2.2 × 10^16 Hz
Planck's constant(h) = 6.63 × 10^-34
The energy of a photon 'E' is given as the product of frequency and the planck's constant
E = hf
E = (6.63 × 10^-34) × (2.2 × 10^16)
E = 6.63 × 2.2 × 10^(-34 +16)
E = 14.586 × 10^-18
E = 1.4586 × 10^-17
E = 1.5 × 10-17 (2 S. F)
Answer:
C. 1.5 × 10–16 J
Explanation:
a common problem with the eye is incorrect curvature of the cornea, causing light rays to come to a focus someplace other than on the retina. in a person who is nearsighted, the focal point of light rays from a distant object is in front of the retina. what type of corrective lens would allow objects to properly focus onto the retina?
A corrective lens that would allow objects to properly focus onto the retina for a person who is nearsighted is a concave lens. This type of lens is thinner in the centre and thicker at the edges, which causes light rays to spread out and focus properly on the retina, correcting the refractive error caused by the incorrect curvature of the cornea.
In a person who is nearsighted, the focal point of light rays from a distant object is in front of the retina. To properly focus objects onto the retina, a nearsighted person would need a concave (diverging) lens for their corrective eyewear. This type of lens spreads out the light rays, allowing them to focus correctly on the retina, improving the person's distance vision.
To know more about retina here:
brainly.com/question/13993307
#SPJ11
what instrument would you use to measure the volume of a box
A graduated cylinder, buret, or pipette are a few of the tools scientists employ to measure precise volumes. You must look at the meniscus's base to calculate volume.
What is Volume?
Measuring is the most important scientific concept. Many different types of quantifiable quantities can be measured using base or physical fundamental units. One such quantifiable quantity is speed, which computes the proportion of a moving object's The area that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.
Cubic units are used to quantify a solid's volume. For instance, the volume will be given in cubic metres if the dimensions are given in metres. The International System of Units uses this as the reference unit for volume (SI). Cubic metres, cubic feet, cubic inches, etc. are additional volume units.
Learn more about Volume from given link
https://brainly.com/question/463363
#SPJ1
a swan on a lake gets airborne by flapping its wings and running on top of the water. if the swan must reach a velocity of 6.00 m/s to take off and it accelerates from rest at a constant rate of 0.350 m/s2, how far will it travel before becoming airborne?
By using uniform motion, the distance traveled by the swan is 51.43 meters.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 0 m/s
vt = 6 m/s
a = 0.35 m/s²
By using second equation, we can find the distance traveled by swan
vt² = vo² + 2a . s
6² = 0² + 2 . 0.35 . s
36 = 0.7 s
s = 36 / 0.7
s = 51.43 m
Find more on uniform motion at: https://brainly.com/question/28040370
#SPJ4
Which of the following is occurring while a satellite is in orbit around Earth? O It is continuously pulling away from Earth It is continuously falling toward the surface of Earth. It stays in a constant speed orbit where it was oriented from the start. It stays in the same orbit orientation traveling at variable speeds.
AnswerIt is continuously falling towards the surface of the earth
Explanation:
since gravity from earth is the thing that keeps it constantly in orbit
All waves that travel through matter are called
The height of the 500-mb pressure level plotted at North Platte (LBF) in western Nebraska was ______ m above sea level (denoted 555).
The height of the 500-mb pressure level plotted at North Platte (LBF) in western Nebraska was 5,570 meters m above sea level.
What is pressure?
Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
Pressure level plotted at North PlatteRecalling that the heights plotted at individual stations on 500-mb maps are in tens of meters (place a 0 to the right of the three plotted digits).
The coded height at North Platte, in west-central Nebraska, ("557") indicated 500 mb occurred at 5,570 meters above sea level.
Thus, The height of the 500-mb pressure level plotted at North Platte (LBF) in western Nebraska was 5,570 meters m above sea level.
Learn more about pressure here: https://brainly.com/question/25736513
#SPJ1
if an object weighs 700 n in air and 500 n in water, a. calculate the buoyant force it experiences in water b. what is the density of the object?
a. The object having weight 700N in air, experiences buoyancy force of 200N in water.
b. The density of the object is 3.5g/cm3
a. Archimedes Principle:
When a body is partially or fully immersed in a fluid, its weight appears to decrease and apparent decrease in its weight is equal to weight of the fluid displaced by the body.
The object weight in air is 700N and it's weight in water is 500N.
Buoyancy force = Apparent loss of weight
= 700N - 500N
= 200N
b. Density of the object:
Buoyancy force = Vdg ( where v is volume of the object, d is the density of liquid and g is gravity of earth)
200 = Vdg
200 = V × 1000 × 10 (density of water= 1000kg/m3)
V = 2/100
m/d = 2/100 (V = m/d ,where d is density of solid)
(mg = 700N given in question)
(m = 70)
d = 70× 100/2
d = 3500kg/m3
= 3.5g/cm3
hence density of the object is 3.5g/cm3
learn more about Archimedes Principle:
https://brainly.com/question/13106989
#SPJ4
why do we believe a world with a density of 3.4 g/cm3 composed of mostly rock with a little iron?
Density of a planet is a fundamental property that can be used to infer its composition. The belief that a planet with a density of 3.4 g/cm3 is composed mostly of rock with a little iron is based on scientific observations and measurements.
By studying the properties of objects in our solar system, scientists have determined that rocky planets like Earth have densities that are generally in the range of 3 to 5 g/cm3. Iron, which is denser than rock, will increase the overall density of a planet. Therefore, a density of 3.4 g/cm3 is consistent with a composition that is mostly rock with a small amount of iron.
Additionally, scientists use spectroscopic techniques to study the light that is reflected off a planet's surface. By analyzing the light, they can determine the types of minerals present on the surface. On the basis of these observations, it has been concluded that planets with densities around 3.4 g/cm3 are composed of silicate rocks and possibly a small amount of metal.
To learn more about Density visit:
https://brainly.com/question/29775886#
#SPJ11
how to convert g/cm^3 to kg/m^3
To convert g/cm³ to kg/m³, multiply the value in g/cm³ by 1000. For example, 2.5 g/cm³ is equivalent to 2500 kg/m³.
How to convert g/cm³ to kg/m³?
To convert grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³), you can use the following conversion factor:
1 g/cm³ = 1000 kg/m³
To convert from g/cm³ to kg/m³, simply multiply the value in g/cm³ by 1000.
For example, let's say you have a density of 2.5 g/cm³. To convert it to kg/m³, you would do the following calculation:
2.5 g/cm³ * 1000 = 2500 kg/m³
So, 2.5 g/cm³ is equivalent to 2500 kg/m³.
Certainly! Density is a measure of how much mass is contained in a given volume. It is typically expressed in units such as grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).
The conversion from g/cm³ to kg/m³ involves scaling the density by a factor of 1000. This is because there are 1000 grams in a kilogram and 1 cubic meter is equivalent to 1,000,000 cubic centimeters.
When you convert from g/cm³ to kg/m³, you are essentially converting from a smaller unit (gram) to a larger unit (kilogram) and from a smaller volume (cubic centimeter) to a larger volume (cubic meter). This means that the resulting value in kg/m³ will be larger than the original value in g/cm³.
For example, if you have a material with a density of 0.75 g/cm³, to convert it to kg/m³, you would multiply by 1000:
0.75 g/cm³ * 1000 = 750 kg/m³
So, the density of the material is 750 kg/m³.
It's important to remember that when converting units, you need to consider the relationship between the units and the appropriate conversion factors. In this case, the conversion factor is based on the relationship between grams and kilograms (1000 grams = 1 kilogram) and the relationship between cubic centimeters and cubic meters (1,000,000 cubic centimeters = 1 cubic meter).
Learn more about: convert
brainly.com/question/15743041
#SPJ11
a 30 kg cart is travelling in a zero friction environment at a constant velocity of 5m/s. It's about to go up a very steep hill. How high will the cart be when the velocity changes to zero? PLEASE HELP
Answer:
1.27551m
Explanation:
This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.
Thus, we get:
\(KE_{initial} + PE_{initial} = KE_{final} + PE_{final}\)
We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using \(\frac{1}{2}mv^2\)
One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.
\(KE_{initial} = PE_{final}\)
Plugging in:
\(\frac{1}{2}*30*5^2 = 30*9.8*h\)
Solving for h, we get 1.27551m
Is acceleration directly proportional to mass, or is it inversely proportional to mass?
Will give brainliest
Answer:
The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object
Answer:
It’s actually A) Inversely
Explanation:
a sphere moves in simple harmonic motion with a frequency of 1.20 hz and an amplitude of 5.90 cm. (a) through what total distance (in cm) does the sphere move during one cycle of its motion? cm (b) what is its maximum speed (in cm/s)? cm/s where does this maximum speed occur? as the sphere passes through equilibrium at maximum excursion from equilibrium exactly halfway between equilibrium and maximum excursion none of these (c) what is the maximum magnitude of acceleration (in m/s2) of the sphere? m/s2 where in the motion does the maximum acceleration occur? as the sphere passes through equilibrium at maximum excursion from equilibrium exactly halfway between equilibrium and maximum excursion none of these
(a) The distance traveled by the sphere during one cycle is equal to 2π times the amplitude.
Total distance covered by the sphere in one cycle of motion is equal to the circumference of the circle with radius equal to the amplitude of the motion.
Given:
Frequency of simple harmonic motion, f = 1.20 Hz
Amplitude, A = 5.90 cm
Therefore, total distance = 2πA
= 2π(5.90 cm)
= 37.08 cm
The distance traveled by the sphere during one cycle of its motion is equal to the circumference of the circle whose radius is the amplitude of the motion. Therefore, the distance traveled by the sphere during one cycle is equal to 2π times the amplitude.
(b) The maximum speed of the sphere is 44cm/s occurs when it passes through equilibrium, and its speed is given by the product of its amplitude and frequency
Given:
Frequency of simple harmonic motion, f = 1.20 Hz
Amplitude, A = 5.90 cm
\($v_{max} = 2\pi fA\)
= 2π(1.20 Hz)(5.90 cm)
= 44.55 cm/s
This maximum speed occurs at the equilibrium position. The maximum speed of the sphere occurs at the points where it passes through the equilibrium position. At these points, the acceleration is zero and the velocity is at its maximum. The maximum speed of the sphere is equal to the amplitude times the angular frequency.
(c) The maximum magnitude of acceleration occurs at the maximum excursion from equilibrium, and its value i.e 62.55m/s²
Given:
Frequency of simple harmonic motion, f = 1.20 Hz
Amplitude, A = 5.90 cm
\($a_{max} = 4\pi^2f^2A\)
= 4π²(1.20 Hz)²(5.90 cm)
= 62.55 m/s²
This maximum acceleration occurs at the maximum excursion from equilibrium. The maximum magnitude of acceleration of the sphere is equal to the product of the amplitude and the square of the angular frequency. The maximum acceleration occurs at the maximum excursion from equilibrium, where the acceleration is directed towards the equilibrium position.
Learn more about amplitude here:
https://brainly.com/question/23567551
#SPJ11
what is the typical speed of a helium atom in a child's balloon at a room temperature of 20∘c?
The typical speed of a helium atom in a child's balloon at room temperature is 1352 m/s.
Given:
Temperature, t = 20⁰ C
From the Maxwell-Boltzmann distribution and the root-mean-square (rms) speed formula.
v= √(3kT/m)
Here, (v) is the root-mean-square speed, (k) is the Boltzmann constant, (T) is the temperature in Kelvin, and (m) is the molar mass of the gas.
Convert temperature into kelvin:
T = 20 °C + 273.15 = 293.15 K
To convert the molar mass to kilograms:
m = (4.00 g/mol) / (6.022 × 10²³ particles/mol) ≈ 6.646 × 10⁻²⁶ kg
The rms speed using the formula is:
v= √(3kT/m)
v = √[(3 ×1.38 × 10⁻²³) J/K × 293.15 K) / (6.646 × 10⁻²⁶ kg)]
v = 1352 m/s
Hence, the speed is, 1352 m/s.
To learn more about Speed, here:
https://brainly.com/question/17661499
#SPJ12