The average of a sample of high daily temperature in a desert is 114 degrees F. a sample standard deviation or 5 degrees F, and 26 days were sampled. What is the 90% confidence interval for the average temperature? Please state your answer in a complete sentence, using language relevant to this question.

Step-by-step explanation:

(b + 3)(b + 7) = ...

= b² + (3 + 7)b + (3•7)

= b² + 10b + 21

In the given parallelogram vwxy: x = 3; m∠Y = 65° and ∠YVX = 61° by (alternate interior angle).

A quadrilateral with the opposing sides parallel is called a parallelogram (and thus opposite angles equal).

In the given parallelogram vwxy:

Parallel sides are equal.

So, 2x = 6

x = 6/2 = 3

Opposite pair of angles are also equal.

So,

∠W = ∠Y = 65°

Now,

∠YVX = 61° (alternate interior angle).

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Answer: y=18

Explanation:

We see "varies directly", we use:

y=kx

To find k, we use y=9 when x=8:

We plug in what we know.

y=kx

9=k(8)

Simplify

k=9/8

So, our equation is:

Now, to find y, we use x=16. So,

Therefore, the value of y is 18.

Answer:

The cost of the small package because...

Step-by-step explanation:

Cost of 1 postcards = $0.25

Cost of 4 postcards = 0.25 x 4 = 1

Cost of 1 letter = $0.44

Cost of 5 letters = 0.44 x 5 = 2.2

Cost of 1 large envelope = $0.80

Cost of 2 large envelopes = 0.80 x 2 - 1.6

Cost of 1 small package =$5.10

Since the cost of small package is highest

So, It will increase the mean

So,  the cost of the small package will skew the mean

Answer:

3/10

Step-by-step explanation:

3/25 / 2/5

The domain of a functio f(x) is the set of vlues for which the function is defined (all the values of x for which the function is defined).

Range: the values that f(x) takes.

Find the values of x when f(x) is greather than or equal to 4 and less than or equal to 5

When f(x)≥4

When f(x)≤5

Then. the domain in that interval of range is:

Answer:

$2.09

Step-by-step explanation:

3.8 x .55 = 2.09

Answer:

a. The probability that a particular student arrives by car is \(\frac{1}{20}\) = 0.05, which equals 5%.

b. The probability that a particular student walks to school is \(\frac{3}{10}\) = 0.3, which equals 30%.

c. The probability that a particular student does not walk to school is \(\frac{7}{10}\) = 0.7, which equals 70%.

d. The probability that a particular student does not walk or come by car is \(\frac{13}{20}\) = 0.65, which equals 65%.

Step-by-step explanation:

Probability is the greater or lesser possibility of a certain event occurring. In other words, probability establishes a relationship between the number of favorable events and the total number of possible events. Then, the probability of any event A is defined as the quotient between the number of favorable cases (number of cases in which event A may or may not occur) and the total number of possible cases. This is called Laplace's Law.

\(P(A)=\frac{number of favorable cases}{number of possible cases}\)

In this case, the number of possible cases is always the same, which is equal to the total number of students. So the number of possible cases is 320 students. The number of favorable cases varies as follows:

a. Number of favorable cases= number of students that arrive by car= 16

So: \(P(A)=\frac{16}{320}\)

P(A)=\(\frac{1}{20}\) = 0.05, which equals 5%

The probability that a particular student arrives by car is \(\frac{1}{20}\) = 0.05, which equals 5%.

b. Number of favorable cases= number of students that walk to school= 96

So: \(P(A)=\frac{96}{320}\)

P(A)=\(\frac{3}{10}\) = 0.3, which equals 30%

The probability that a particular student walks to school is \(\frac{3}{10}\) = 0.3, which equals 30%.

c. Number of favorable cases= number of students that do not walk to school = 320 students - number of students that walk to school= 320 students - 96 students= 224 students

So: \(P(A)=\frac{224}{320}\)

P(A)=\(\frac{7}{10}\) = 0.7, which equals 70%

The probability that a particular student does not walk to school is \(\frac{7}{10}\) = 0.7, which equals 70%.

d. Number of favorable cases= number of students that do not walk or come by car= 320 students - number of students that walk to school - number of students that arrive by car= 320 students - 96 students - 16 students= 208 students

So: \(P(A)=\frac{208}{320}\)

P(A)=\(\frac{13}{20}\) = 0.65, which equals 65%

The probability that a particular student does not walk or come by car is \(\frac{13}{20}\) = 0.65, which equals 65%.

Answer:

hii

Step-by-step explanation:

follow me please gugs

Answer:

For sure, A and C. However, I cannot fully read the last one.

Step-by-step explanation:

Be sure to mark me Brainliest!

John and his three passengers travel a total of 20.25 miles on the toll lane.

To solve this problem, we can use the fact that each person pays about $0.81, which includes their contribution to the toll lane entry fee. This means that the total amount of money paid by John and his three passengers is 4 times $0.81, or $3.24.

We can then use this information to find the cost per mile of the toll lane. If they traveled a total of x miles on the toll lane, then the cost per mile would be:

$3.24 / x

We can set this equal to the given cost of 16 cents per mile:

$0.16 = $3.24 / x

Multiplying both sides by x, we get:

x * $0.16 = $3.24

Dividing both sides by $0.16, we get:

x = $3.24 / $0.16

x = 20.25 miles

In summary, to find the distance they traveled on the toll lane, we used the fact that they split the cost of the toll, and that each person paid about $0.81. We then set the cost per mile equal to the given cost of 16 cents per mile, and solved for the distance traveled on the toll lane, which turned out to be 20.25 miles.

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9. Answer:

30

10. Answer:

2

11. Answer:

4

12. Answer:

4

13. Answer:

-1

Tip:

Use photomath, its an app

Answer: -1.8 and 11.4

Step-by-step explanation:

Trust me or don’t lol

Answer:

D. 2.6 and 7

Step-by-step explanation:

Plato course, did the test

The truth value of an argument's premises cannot be determined solely by the fact that the argument has a false conclusion, as the premises could be true, false, or partly true and partly false.

If an argument has a false conclusion, it means that the conclusion is not true or accurate. However, the truth value of the argument's premises is not necessarily determined by the truth value of the conclusion. The premises could be true, false, or partly true and partly false.

A valid argument is one where the conclusion follows logically from the premises. This means that if the premises are true, then the conclusion must also be true. However, if the conclusion is false, it could mean that either one or more of the premises are false, or that there is a flaw in the logical reasoning process used to derive the conclusion from the premises.

Therefore, having a valid argument with a false conclusion does not necessarily tell us anything about the truth value of the argument's premises. Additional information is needed to determine whether the premises are true, false, or partly true and partly false. The validity of the argument only tells us that if the premises are true, then the conclusion must also be true, but it does not guarantee the truth value of the premises or the conclusion on their own.

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Answer:

\(\boxed{x^4+4x^3y+6x^2y^2+4xy^3+y^4\\}\)

Step-by-step explanation:

Pascal’s triangle defines the coefficients which appear in binomial expansions. That means the nth row of Pascal’s triangle comprises the coefficients of the expanded expression of the polynomial (a + b)ⁿ

To create Pascal's triangle for any n in (a + b)ⁿ ,

Here is Pascal's triangle for the first 5 rows. The first row is row 0

Row #                                      

0                  1              

1               1    1            

2            1    2    1        

3         1    3    3    1      

4      1    4    6    4    1

\(\textrm{ Here row 0 represents $(a + b)^0$ }\) =   \(\boxed{\textbf{1}}\)

\(\textrm{Row 1 corresponds to $(a + b)^1$} =\)  \(\boxed{1}\;a + \boxed{1}\;b\)

\(\textrm{Row 2 corresponds to $(a + b)^2$} = \boxed{1}\;a^2 + \boxed{2} \;ab +\boxed{1}\;b^2\)

\(\textrm{Row 3 corresponds to $(a + b)^3$} = \boxed{1}\;a^3 + \boxed{3}\;a^2b + \boxed{3}\;ab^2 + \boxed{1}\;b^3\)

\(\textrm{Row 4 corresponds to $(a + b)^4$} = \boxed{1}\;b^4 + \boxed{4} \;a^3b +\boxed{6}\;a^2b^2 + \boxed{4} \;ab^3 + \boxed{1} \;b^4\)

For the specific problem, (4x + 3y)³ use coefficients of row 3 and use 4x instead of a and 3y instead of b

\(\mbox{\normal(4x + 3y)^3= \boxed{1}\;(4x)^3 + \boxed{3}\;(4x)^2(3y) + \boxed{3}\;4x(3y)^2 + \boxed{1}\;(3y)^3}\)

\(= \boxed{x^4+4x^3y+6x^2y^2+4xy^3+y^4\\} \;\;\; \textrm{ANSWER}\)

Step-by-step explanation:

l don't know how to solve

it

Answer:

35%

Step-by-step explanation:

Total made: (15)(1.80) = £27

\(\frac{27-20}{20} \times 100=35\%\)

Answer:

the answer is (n+2) (n+5)

Step-by-step explanation:

Factor n^2 + 7n + 10 using the AC method.

The good estimate, as well as the actual measurement for the given angle, is 110° and 109°.

In construction, a good estimate is an approximate value of a number that makes it faster to make cognitive deductions.

On the other hand, the actual measurement is the exact measurement of an angle or shape when the appropriate measuring tools are being used.

From the diagram, the angle is an obtuse angle because it is more than 90° since it extends more than its perpendicular axis(90°), but it is less than 180°.

Therefore, we can conclude that the good estimate, as well as the actual measurement for the given angle, is 110° and 109°.  

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Answer: A 110 and 109

Step-by-step explanation:

The x-coordinate and y-coordinate of the centroid is approximately 0.323 and 1.244 respectively.

To determine the x- and y-coordinates of the centroid of the shaded area,

Calculate the centroid coordinates for each individual shape

and then find the weighted average of those coordinates based on the area of each shape.

Let's break down the shaded area into two shapes: a rectangle and a semicircle.

Rectangle,

The width of the rectangle is 'a' and the height is 'c'

The centroid of a rectangle is located at the midpoint of its height and width.

x-coordinate of rectangle centroid

= a/2

= 1.30/2

= 0.65

y-coordinate of rectangle centroid

= c/2

= 5/2

= 2.50

Semicircle,

The radius of the semicircle is 'b'

The centroid of a semicircle is located at a distance of 4/3πr from the base of the semicircle.

x-coordinate of semicircle centroid = 0

y-coordinate of semicircle centroid

= (4/3πb)/2

= (4/3π × 2.25)/2

≈ 3.77

Now, find the weighted average of the centroids based on the area of each shape.

Total area of the shaded region = area of rectangle + area of semicircle

Total area = a × c + (1/2 × π × b²)/2

Total area = 1.30 × 5 + (1/2 × π ×2.25²)/2

Total area ≈ 9.09 + 3.98

Total area ≈ 13.07

Now ,calculate the weighted centroid coordinates,

x-coordinate of centroid = (area of rectangle × x-coordinate of rectangle centroid + area of semicircle × x-coordinate of semicircle centroid) / total area

x-coordinate of centroid = (1.30 × 5 × 0.65 + (1/2 × π × 2.25²)/2 × 0) / 13.07

x-coordinate of centroid ≈ 4.225 / 13.07

x-coordinate of centroid ≈ 0.323

y-coordinate of centroid

= (area of rectangle × y-coordinate of rectangle centroid + area of semicircle × y-coordinate of semicircle centroid) / total area

= (1.30 × 5 × 2.50 + (1/2 × π × 2.25²)/2× 3.77) / 13.07

≈ 16.25 / 13.07

≈ 1.244

Therefore, the x-coordinate of the centroid is approximately 0.323 and the y-coordinate of the centroid is approximately 1.244.

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The information provided is insufficient to determine the coordinates of the centroid of the shaded area. The specific shape of the shaded area and its orientation in the coordinate plane are necessary information to solve this problem.

The original question involves determining the x- and y-coordinates of the centroid of the shaded area for given values of c = 5, a = 1.30, and b = 2.25. However, the question is missing information about the specific shape of the shaded area, which is crucial to calculate its centroid coordinates. Typically, for basic geometric shapes, the formula used to calculate the centroid is different for each type of shape.

For instance, if the shaded area is a triangle, its centroid coordinates (x, y) can be determined as follows:

Where a, b, and c represent the x-coordinates of the vertices of the triangle. However, without information about the shape, an accurate calculation of the centroid cannot be made.

It's also important to note that the provided references do not apply directly to this problem, as they concern different mathematical contexts and principles.

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Answer:

answer is rs 192100ra 395500

Answer:

18

Step-by-step explanation:

The median of a set of data is the value that separates the lower and upper halves of the data. To find the median, the data must be arranged in numerical order.

The data, arranged in numerical order, is:

5, 5, 6, 7, 8, 9, 10, 10, 12, 14, 15, 17, 18, 18, 18, 20

Since the number of data points is an odd number (17), the median is simply the middle value, which is:

18

So the correct answer is A) 18.

Answer: C

Step-by-step explanation:

To find the median, arrange the numbers in sequential order.

5, 5, 6, 7, 8, 9, 10, 10, 12, 14, 15, 17, 18, 18, 18, 20

When there are an odd number of data in the set, choose the middle number in the set. For example, see the following data set.

2, 4, 6, 8, 9

The middle number in the data set is 6, so it is the median.

When there is an even number of data in the set, choose the middle two numbers, add them together, and then divide them by 2.

There are 16 numbers in this data set. We need to find the two middle numbers in the set.

5, 5, 6, 7, 8, 9, 10, 10, 12, 14, 15, 17, 18, 18, 18, 20

10 and 12 are the two middle numbers in the set.

10 + 12 = 22

22/2 = 11

Median = 11

To solve this we must be knowing each and every concept related to month. Therefore,  today's date is June 21st. It is also summer time in Canada.

A month is a measure of time used with calendars that is about the length of the Moon's natural orbital period; the phrases moon and Month are cognates. The conventional definition evolved from the lunar phase cycle; such lunar month ("lunations") comprise synodic months that last around 29.53 days.

In fifteen days it will be the first of the month. Fifteen days ago it was the first of the month. It is also summer time in Canada, then today's date is June 21st.

Therefore,  today's date is June 2st.

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Answer: There are 196 different five-person teams that can be formed from the given group of 12 people, with at most one man in each team.

Step-by-step explanation:

We need to find the number of five-person teams that can be formed out of the given group of 12 people, such that at most one man is included.

We can approach this problem by counting the number of teams that have zero men, one man, and four women.

Number of teams with zero men = (number of ways to choose 5 women from 7) = 21

Number of teams with one man = (number of ways to choose 1 man from 5) × (number of ways to choose 4 women from 7) = 5 × 35 = 175

Therefore, the total number of five-person teams that can be formed with at most one man is:

Number of teams = Number of teams with zero men + Number of teams with one man = 21 + 175 = 196

Therefore, there are 196 different five-person teams that can be formed from the given group of 12 people, with at most one man in each team.

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The number of each type of coins are as follows:

q = 15 quarters.

d = 30 dimes.

n = 25 nickels.

In order to solve this word problem, we would assign a variables to the unknown numbers and then translate the word problem into algebraic equation as follows:

Let d represent the number of dimes.

Let q represent number of quarters.

Let n represent number of nickels.

Let T represent total number of coins.

Note: 1 quarter is equal to 0.25 dollar, 1 nickel is equal to 0.5 dollar, and 1 dime is equal to 0.1 dollar.

Translating the word problem into an algebraic equation, we have;

Dimes; d = 2q     .....equation 1.

Nickels; (70 - (q + 2q)) = (70 - 3q)     .....equation 2.

Total coins; T = n + d + q

0.5(70 - 3q) + 2q(0.1) + q(0.25) = 8.00

Multiplying all through by 100, we have:

5(70 - 3q) + 2q(10) + q(25) = 800

350 - 15q + 20q + 25q = 800

350 + 30q = 800

30q = 800 - 350

30q = 450

q = 450/30

q = 15 quarters.

For the number of dimes, we have:

Dimes, d = 2q

Dimes, d = 2(15)

Dimes, d = 30 dimes.

For the number of nickels, we have:

Nickels, n = (70 - 3q)

Nickels, n = (70 - 3(15))

Nickels, n = (70 - 45)

Nickels, n = 25 nickels.

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a)  P(X=330) is approximately 0.0002. b)P(X>340) is approximately 0.0294. c) P(335≤X≤345) is approximately 0.6415. d) P(X=300) is approximately 0.0004 of given probabilities

To find the probabilities using Excel's function options, we can use the binomial distribution function, which is provided as BINOM.DIST in Excel.

a) P(X=330):

=BINOM.DIST(330, 400, 0.8, FALSE)

The first argument is the specific value (330), the second argument is the total number of trials (400), the third argument is the probability of success (0.8), and the fourth argument FALSE indicates that we want the probability for a specific value.

The result is approximately 0.0002.

Therefore, P(X=330) is approximately 0.0002.

b) P(X>340):

=1 - BINOM.DIST(340, 400, 0.8, TRUE)

Since we want the probability of X being greater than 340, we can subtract the cumulative probability of X up to 340 from 1. We use the TRUE argument to indicate that we want the cumulative probability.

The result is approximately 0.0294.

Therefore, P(X>340) is approximately 0.0294.

c) P(335≤X≤345):

=BINOM.DIST(345, 400, 0.8, TRUE) - BINOM.DIST(334, 400, 0.8, TRUE)

To find the probability of X being between 335 and 345 (inclusive), we subtract the cumulative probability of X up to 334 from the cumulative probability of X up to 345.

The result is approximately 0.6415.

Therefore, P(335≤X≤345) is approximately 0.6415.

d) P(X=300):

=BINOM.DIST(300, 400, 0.8, FALSE)

The first argument is the specific value (300), the second argument is the total number of trials (400), the third argument is the probability of success (0.8), and the fourth argument FALSE indicates that we want the probability for a specific value.

The result is approximately 0.0004.

Therefore, P(X=300) is approximately 0.0004.

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There are 60 possible outcomes for this experiment.

The problem asks to determine the total number of outcomes for an experiment consisting of three steps with different numbers of possible outcomes at each step.

To solve this problem, we need to apply the multiplication principle, which states that the total number of outcomes for a sequence of events is equal to the product of the number of outcomes at each event.

In this case, there are two possible outcomes for the first step, six possible outcomes for the second step, and five possible outcomes for the third step.

Therefore, the total number of outcomes possible is:

2 * 6 * 5 = 60

Therefore, there are 60 possible sequences of events that can occur in this experiment.

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Answer:

she can fill 10 boxes of 12 cookies and the the left over will be 2 cookies.

Step-by-step explanation:

first we have to find out what multiple of 12 is closest to 122 which is 12 x 10=120.

then minus 120 from 122 which gives 2 remaining cookies