Answer:
50µs
Explanation:
The conversion is that 1 second equals 1,000,000 micro seconds. Since we have 0.00005 seconds, we will multiply that to a million.
0.00005 * 1,000,000 = 50µs
Keep in mind that 50 only has 1 significant figure because any trailing zeroes before the decimal point do NOT count.
Best of Luck!
0.00005 seconds = 50 μs
Thank you
Which action will cause the induced current to decrease or remain constant?
A. Moving the magnet faster B. Increasing the strength of the magnet
C. Adding more turns to coil. D. Reversing polarity of the magnet.
Answer:
Its Reversing the polarity of the magnet :)
Explanation:
The action that cause the induced current for reduce or be same is when the polarity is reverse with respect to the magnet.
The following actions should not induced the current:
In the case when the magnet moved in the fastest way. When the magnet strength is increased. And, when the more turns to coil is added.Therefore we can conclude that the action that cause the induced current for reduce or be same is when the polarity is reverse with respect to the magnet.
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A 2.0 cm tall object is placed 25 cm in front of a converging lens. The image is found 64 cm on the other side of the lens.
The focal length of the lens is ________.
0.011 cm
0.024 cm
41 cm
0.056 cm
18 cm
15 cm
Since focal length cannot be negative for a converging lens, we take the positive value: f ≈ 41 cm Option C
To determine the focal length of the lens, we can use the lens formula, which relates the object distance (u), image distance (v), and focal length (f) of a lens. The lens formula is given by:
1/f = 1/v - 1/u
In this case, the object distance (u) is 25 cm and the image distance (v) is 64 cm. We can substitute these values into the lens formula to solve for the focal length:
1/f = 1/v - 1/u
1/f = 1/64 cm - 1/25 cm
To simplify the equation, we can find a common denominator:
1/f = (25 - 64) / (64 * 25)
1/f = -39 / (64 * 25)
Now, we can invert both sides of the equation to solve for the focal length:
f = (64 * 25) / -39
f ≈ -41.03 cm
Since focal length cannot be negative for a converging lens, we take the positive value:
f ≈ 41 cm
Therefore, the correct answer is option C) 41 cm.
It's important to note that in the lens formula, distances are measured with respect to the lens, with positive values indicating distances on the opposite side of the incident light. The negative value obtained for the focal length indicates that the lens is a converging lens, as expected. Option C
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A set of lights consists of 20 lamps connected in series to the 230 V mains electricity supply. 1. (a) When the lights are switched on and working correctly, the current through each lamp is 0.25 A. (i) What is the total current drawn from the mains supply?
The total current that is drawn from the mains supply is 5 A.
What is current?The term current has to do with the flow of charges in a circuit. Now we have been told that A set of lights consists of 20 lamps connected in series to the 230 V mains electricity supply. It was also said in the question that when the lights are switched on and working correctly, the current through each lamp is 0.25 A.
Now we have the following information;
Current passing through each lamp = 0.25 A
Number of lamps = 20 lamps
Hence;
Total current = 0.25 A * 20
= 5 A
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Iron metal is added to an aqueous solution of copper nitrate to create solid copper metal and
iron nitrate in solution. The equation is below. Use this equation to answer all the questions
in this warmup.
What are the products in this reaction?
(1 Point)
Fem) + Cu(NO3)2(aq) → Cue) + Fe(NO3)2(aq)
()
()
Answer:
When the metal is dropped in the solution it turns blue to green because this forms iron sulphate solution and turns the metal copper
Iron sulphate + copper
An experiment consists of throwing balls straight up with varying initial velocities. Which quantity will have the same value in all trials?a) initial momentum.
b) maximum height.
c) time of travel.
d) acceleration.
Answer:
the correct answer is D, acceleration of gravity
Explanation:
In a projectile launch problem it is described by the expressions
v = v₀ - g t
v² = v₀² - 2 g y
y = v₀ t - ½ g t²
By examining these equations we can see that acceleration is the magnitude that appears constant in all expressions.
This acceleration is the acceleration of gravity with a value of g = 9.8 m/s² and directed towards the center of the Earth
therefore the correct answer is D
What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?
The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².
What is the moment of inertia?
This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².
From the question:
Mass,M =4.2kg
Radius, R=32Cm
The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:
moment of inertia, I =1/2MR²
I =\(\frac{1}{2}\) * 4.2 * 32²
=2,150.4 kgm²
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Man-made climate change is an example
of...
Step 5: Measure the Speed of the Toy Car on the Higher Track
alculate the average time the car took to reach each
heckpoint. Record the average time in Table D of your
Student Guide.
The average time to the first quarter checkpoint is
seconds.
The average time to the second quarter checkpoint is
seconds.
The average time to the third quarter checkpoint is
seconds.
The average time to the finish line is ✓seconds
The average for each checkpoint is:
point 1 t_{avg} = 2.07 sec
point 2 t_{avg} = 3.16 sec
point 3 t_{avg} = 4.11 sec
point 4 t_{avg} = 4.92 sec
We have the graph for each interval.
The magnitude of the average is:
t_{avg} = Σ ( t_(i) / n)
where t_{avg} is the average time, t_(i) each time the magnitude is measured and n is the number of times the measurement is repeated for the same point.
The table for the times measured for each interval is:
Measurement times for each interval
1 2 3 4
1 2.02 3.17 4.12 4.93
2 2.05 3.07 3.98 4.81
3 2.15 3.25 4.23 5.01
Now, the average time to reach the get married checkpoint is:
For point 1:
t_{avg} = (2.02 + 2.05 + 2.15) / 3
t_{avg} = 2.07 s
For point 2:
t_{avg} = (3.17 +3.07 + 3.25) / 3
t_{avg} = 3.16 s
For point 3:
t_{avg} = (4.12 + 3.98 + 4.23) / 3
t_{avg} = 4.11 s
For checkpoint 4:
t_{avg} = (4.93 + 4.81 + 5.01) / 3
t_{avg} = 4.917 s
We employ the significant figures criterion for the sum, which is steady in that the result must be provided with the least amount of decimal places.
t_{avg} = 4.92 s
Therefore, the average times for each checkpoint are:
point 1: t_{avg} = 2.07 s
point 2: t_{avg} = 3.16 s
point 3: t_{avg} = 4.11 s
point 4: t_{avg} = 4.92 s
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The mass of a car is 625kg. Calculate the weight of the gravitational field strength is 10 N/kg.
Ans: 62.5
Explanation: \(F{net}\) = m x a
1N = 1kg x 1m/ \(s{2}\)
If a gas turned into a solid without going through the liquid state and how do you reverse it?
Answer:
put it in a volcano
Explanation:
On earth a 2.25 kg object is lifted a height of 5.22m. What is the gravitational potential energy
Answer:
117.45 JExplanation:
The gravitational potential energy of a body can be found by using the formula
GPE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
GPE = 2.25 × 10 × 5.22
We have the final answer as
117.45 JHope this helps you
An 50kg car travels at 2m/s. What is the car's Kinetic energy?
100J
200J
50J
Answer:
The answer is 100J.
Explanation:
In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. In this question, the mass is equals to 50kg and the velocity is 2m/s
Now,
25kg×4m/s^2 = 100kgm/s^2 or 100J
A particle travels between two parallel vertical walls separated by 23 m. It moves toward the opposing wall at a constant rate of 9.6 m/s. It hits the opposite wall at the same height. a=9.8. What will be its speed when it hits the opposing wall? At what angle with the wall will the particle strike?
The particle is moving toward the wall and is being deflected at the same time.
What is Vertical walls?The time to reach the wall will be 18.4/7.2 =2.56 sec. The direction of the acceleration is not specified but since the ask for how high we will assume it is upward. S=1/2 at^2 t= 2.56.
s = 0.5X 1.7 m/s 2 x 2.56*2.56 = 5.5 meters. Two velocities on x one way the up velocity is 1.7*2.56 = 4.3 m/s or the arctan of 4.3/7.2 =30.8 degrees.
Vertical gardens, sometimes known as "green walls," are large-scale plant arrangements that are affixed to wall-mounted structures. They serve as an effective ornamental element while also being quite practical because they improve the indoor air quality and the comfort level of the surrounding area.
Therefore, The particle is moving toward the wall and is being deflected at the same time.
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A 0.18 kg baseball moving at +21.80 m/s is slowed to a stop by a catcher who exerts a constant force of -360 N.
How long does it take this force to stop the ball?
___s
How far does the ball travel before stopping?
___m
Answer:
hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.
It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.
What is force?To find the time it takes for the catcher to stop the ball, you can use the equation:
time = distance / velocity
In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:
time = 0 / 21.80
time = 0 s
So, it takes 0 seconds for the catcher to stop the ball.
To find the distance the ball travels before stopping, you can use the equation:
distance = 1/2 * acceleration * time^2
In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:
distance = 1/2 * (-2000 m/s^2) * (0 s)^2
distance = 0 m
So, the ball travels 0 meters before stopping.
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Which describes a feature of the physical changes of all substances?
Answer:
A change in size, shape, or matter.
Explanation:
A physical change does not produce new substances. A physical change may only change the physical properties of a substance. a change in size, shape, or phase of matter.
Answer: It does not change the identity of a substance
Explanation:
Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?
The height that will illustrate the distance will be d = 6.36m
How to calculate the height?Based on the information given, the length of the vine will be:
L = ✓(16² + 27.7)²
L = 32m
The velocity of Jane when she reaches position B will be:
V = ✓2gh
V = ✓(2 × 9.8 × 4.3)
V = 9.18m/s
We will apply the conversation of momentum. This will be:
50 × 9.18 = (50 + 80)V1
V1 = 3.53m/s
Therefore, the height that will illustrate the distance will be:
31.36² + d² = 32²
d² = 32² - 31.36²
d = 6.36m
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A 5.760 kg
block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is s=0.455
and the coefficient of kinetic friction is k=0.205.
At time =0,
a force =15.8 N
is applied horizontally to the block. State the force of friction applied to the block by the table at times =0
and >0.
A block of wood resting on a steel desk experiences a force of friction that opposes the applied force. The force of friction depends on the coefficients of friction and the normal force acting on the block.
At time t=0, the force applied on the block is 15.8 N. Since the block is at rest, the frictional force must be equal and opposite to the applied force to maintain static equilibrium. Therefore, the force of friction acting on the block at t=0 is:
Ffriction = Fapplied = 15.8 N
Now, when the applied force is greater than the maximum static frictional force (i.e., Fs > μsN), the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force is given by:
Ffriction = μkN
where μk is the coefficient of kinetic friction and N is the normal force acting on the block.
The normal force N acting on the block can be calculated using Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:
ΣF = ma
Since the block is moving horizontally, its acceleration in the vertical direction is zero, and the normal force N is equal to the weight of the block:
N = mg
where m is the mass of the block and g is the acceleration due to gravity.
Substituting the given values, we get:
N = 5.760 kg × 9.81 m/s^2 = 56.47 N
The maximum static frictional force Fs can be calculated using:
Fs = μsN
Substituting the given values, we get:
Fs = 0.455 × 56.47 N = 25.68 N
Since the applied force is greater than the maximum static frictional force, the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force can be calculated using:
Ffriction = μkN
Substituting the given values, we get:
Ffriction = 0.205 × 56.47 N = 11.56 N
Therefore, the force of friction acting on the block at t=0 is 15.8 N, and the force of friction acting on the block when it starts to move is 11.56 N.
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b) A child looking into a small, polished hemispherical metal bowl sees an erect image of himself 21cm from the bowl. He turns the bowl over and sees a further erect image of himself 7cm from the bowl. What is the radius of curvature of the bowl?
The radius of curvature of the bowl is 42 cm. It should be noted that this is a negative value, indicating that the mirror is concave (curved inward) rather than convex (curved outward).
The situation described can be modeled using the thin lens equation, which relates the object distance, image distance, and focal length of a lens or curved mirror. In this case, we can assume that the bowl acts as a concave mirror, with its reflecting surface forming a portion of a sphere.
We can also assume that the mirror is thin, meaning that the distance between the reflecting surface and the center of curvature is much greater than the radius of curvature.
Let us denote the radius of curvature of the mirror as R. When the child looks into the bowl, an erect image of himself is formed at a distance of 21 cm from the bowl. Using the thin lens equation, we can write:
\(1/f = 1/d_o + 1/d_i\)
where f is the focal length of the mirror, \(d_o\) is the object distance (i.e., the distance between the child and the mirror), and \(d_i\)is the image distance (i.e., the distance between the mirror and the image).
In this case, the object distance is negative (since the child is looking into the bowl from the same side as the object), and the image distance is positive (since the image is erect). Substituting the given values, we obtain:
\(1/f = -1/21 + 1/d_i\)
Next, when the child turns the bowl over, another erect image of himself is formed at a distance of 7 cm from the bowl. Using the same equation, we can write:
\(1/f = -1/d_o + 1/d_i'\)
where d_i' is the image distance for this case. In this case, the object distance is positive (since the child is looking at the bowl from the opposite side of the object), and the image distance is also positive (since the image is erect). Substituting the given values, we obtain:
\(1/f = 1/7 + 1/d_i'\)
Now we have two equations for f in terms of \(d_i\) and \(d_i\)', respectively. We can solve for \(d_i\)and \(d_i\)' by setting these two equations equal to each other and simplifying:
\(-1/21 + 1/d_i = 1/7 + 1/d_i'\\d_i' = 1/(1/7 - 1/21 + 1/d_i) = 28 cm\)
Now that we know both image distances, we can solve for the radius of curvature R using the mirror formula, which relates the focal length to the radius of curvature:
1/f = 2/R
Substituting the values of f and \(d_i\), we obtain:
\(1/R = 2/f = -1/21 + 1/d_i\)
Solving for R, we obtain:
R = -42 cm
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what an example of flat bone
Answer:
The Vomer Bone
Nasal Bone
Ribs
Explanation:
Those are some examples of flat bones.
I hope it helps! Have a great day!
JellyBeanie~
An average person is 175 cm tall. How
many people could you stack one on top of
another to reach the top of the CN Tower
(553 m)?
The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people
Hor to convert 175 centimeters to metersWe'll begin by converting 175 cm to m. This can be obtained as illustrated below:
100 cm = 1 m
Therefore,
175 cm = (175 cm × 1 m) / 100 cm
175 cm = 1.75 m
Thus, 175 cm is equivalent to 1.75 m
How to determine the number of people neededThe number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:
Height of tower = 553 mHeight of a person = 1.75 mNumber of people needed =?Number of people needed = Height of tower / height of a person
Number of people needed = 553 / 1.75
Number of people needed = 316 people
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8. Before leaving the ground an airplane traveling with constant acceleration makes a run on the
runway of 1800 meters in 12 seconds. Determine:
a. Acceleration
b. Speed at which it leaves the ground
c. Distance traveled during the first and twelfth seconds
Answer:
\(\color{Blue}\huge\boxed{Answer} \)
B. Speed at which it leaves the groundWhat is the potential difference across the source?
60 V
220 V
440 V
120 V
Answer:
120 v
Explanation:
The two resistors have an equivalent of 20 * 30 /(20+30) = 12 ohms
10 amps of current in the circuit
v = ir
= 10 * 12 = 120 volts
Here is another way:
The two resistors are in prallel so the voltae across both is the same
use the one on the right v = ir = 4 x 30 = 120 v
Weather hazards and natural disasters such as tsunamis, earthquakes, and flooding are considered which type of migration factor?
A. Pull factor
B. Both push and pull factors
C. Neither push or pull factor
D. Push factor
Answer:
D. Push Factor
Explanation:
Pull factors are known as positive aspects of a place that make people want to stay/remain in that area.Push factors are known as negative aspects of a place that make people want to leave/depart from that area.Weather hazards and natural disasters are horrendously negative things that people actively seek to avoid; they make people want to leave or depart from an area in order to escape them. As such, they are considered push factors.
(Weather hazards and natural disasters are not pull factors because when discussing push vs pull we are specifically describing the mentioned factor. This aspect is not considered both because the migration factor mentioned in this question actively makes people want to move to any area that avoids their issue. Remember that pull factors make people want to move to a specific place for a unique advantage, while push factors make people want to move to any general place for a common advantage.)
A 15 kg block rest on a surface of a smooth plane incline at an angle 30 degree to the horizontal. A light in extensible string passing over a small Smooth Pulley at the top of the plane connect to the block to another 13/kg block hanging freely. find the acceleration of the resulting motion and the tension in the string.
If the coeficient of kinetic friction between the plane and the 15kg mass is 0.25. find the acceleration of the resulting motion
The acceleration of the system is 2.77 m/s² and the tension in the string is 127.4 N, given the provided values.
Given: Mass of the first block (m1) = 15 kgMass of the second block (m2) = 13 kgAngle of the plane (θ) = 30°Coefficient of kinetic friction (μk) = 0.25, Acceleration of the resulting motion (a) = ? Tension in the string (T) = ?First, we need to resolve the weight of the first block into its components perpendicular to and along the plane. Then we can use the component parallel to the plane to find the force of friction acting on the first block. We can then use the net force acting on the first block to find its acceleration. Finally, we can use the acceleration of the first block to find the tension in the string.Resolving the weight of the first block into components parallel to the plane: m1gsinθ = 15 x 9.8 x sin30° = 73.5 N. Perpendicular to the plane: m1gcosθ = 15 x 9.8 x cos30° = 127.5 N. Finding the force of friction acting on the first block: μk = coefficient of kinetic friction = 0.25f = force of friction acting on the first block N = normal force acting on the first block N = perpendicular force acting on the first block = 127.5 Nf = μkN = 0.25 x 127.5 = 31.88 NThe net force acting on the first block:F = maF = m1aF = m1g sinθ - fF = 15 x 9.8 x sin30° - 31.88F = 73.5 - 31.88F = 41.62 N. Acceleration of the first block: a = F/m1a = 41.62/15a = 2.77 m/s². Finding the tension in the string: The tension in the string is the force acting on the second block. We can use the weight of the second block and the acceleration of the first block to find the tension.T - m2g = m1aT = m2g + m1aT = 13 x 9.8 + 15 x 2.77T = 127.4 NTherefore, the acceleration of the resulting motion is 2.77 m/s² and the tension in the string is 127.4 N.For more questions on acceleration
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determine energy of absorbed photon.
The energy of an absorbed photon is \(2.998 * 10^8\) and the resulting unit for energy is Joules (J).
To determine the energy of an absorbed photon in electronvolts (eV), we can use the equation E = hv, where E represents energy, h is Planck's constant, and v is the frequency of the photon. By substituting the values and units correctly, we can calculate the energy in electronvolts.
To determine the energy of an absorbed photon, one can use the following formula:
energy of absorbed photon = Planck's constant x frequency of radiation
Where Planck's constant is equal to \(6.626 * 10^{-34\) Joule seconds and frequency of radiation is measured in Hertz (Hz).
The energy of an absorbed photon can also be expressed using the wavelength of the radiation instead of its frequency.
The formula for this is:energy of absorbed photon = Planck's constant x speed of light / wavelength of radiation
Where the speed of light is equal to \(2.998 * 10^8\) m/s.In both cases,
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what is 9/14 times 2 1/3? (i have more questions)
Given data
*The given equation is
\(\begin{gathered} x=\frac{9}{14}\times2\frac{1}{3} \\ =\frac{9}{14}\times\frac{7}{3} \\ =\frac{3}{2} \end{gathered}\)find the rms speed of a sample of oxygen at 30° C and having a molar mass of 16 g/mol.
At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.
The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:
vrms = √(3kT/m)
Where:
vrms is the rms speed
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
m is the molar mass of the gas in kilograms
To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:
m = 16 g/mol = 0.016 kg/mol
Substituting the values into the formula, we have:
vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))
Calculating this expression yields the rms speed of the oxygen sample:
vrms ≈ 482.34 m/s
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You carry a fire hose up a ladder to a height of 10 m above ground level and aim the nozzle at a burning roof that is 9 m high. You hold the hose horizontally and notice that the water strikes the roof at a horizontal distance of 7 m from where it exits the nozzle. The hose is connected to a large pressurized chamber in the fire truck 0.5 m above ground level. What is the pressure in the chamber
Answer:
The value is \(P_1 = 314645 \ Pa \)
Explanation:
From the question we are told that
The height is \(h_2 = 10 m\)
The height of the burning roof is \(k = 9 m\)
The horizontal distance is \(d = 7 \ m\)
The height of the truck is \(h_1 = 0.5 \ m\)
Generally the time for the water to hit the roof from the hose is mathematically represented as
\(t = \sqrt{\frac{2 * (h_2 - k)}{g} }\)
=> \(t = \sqrt{\frac{2 * (10 - 9)}{9.8} }\)
=> \(t = 0.4518 \ s \)
Generally the velocity of the water is mathematically evaluated as
\(v_2 = \frac{d}{t}\)
\(v_2 = \frac{ 7}{0.4518}\)
\(v_2 = 15.5 \ m/s \)
Generally from Bernoulli's Equation we have that
\(P_1 + \frac{1}{2} v_1^2 * \rho + \rho *g *h_1 = P_2 + \frac{1}{2} v_2^2 * \rho + \rho *g *h_2\)
Here \(P_1 [\tex] is pressure in the chamber which we are to calculate , \(P_2 [\tex] is the atmospheric pressure with value \(P_2 = 101325 \ Pa [\tex] , \(v_1 [\tex] is the velocity of the water before it starts flowing with value \(v_1 = 0 m/s [\tex] , \(\rho [\tex] is the density of water with value \(\rho = 1000 \ kg/m^3 [\tex]
So
\(P_1 + \frac{1}{2} 0^2 * 1000 + 1000 *9.81 *0.5 = 101325 + \frac{1}{2}* 15.5^2* 1000 + 1000 *9.81 *10\)
\(P_1 = 314645 \ Pa \)
Compared to a 1-kg block of solid iron, a 2-kg block of solid iron has the same:
A. Density
B. Mass
C. Volume
D. Inertia
The Correct choice is :
Densitythe mass of the velociraptor and cage together is 175 kg. What is the gravitational potential energy added when when the velociraptor and cage is lifted from the ground to a height of 9 m?
The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.
What is Potential Energy?
Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.
The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:
GPE = mgh
Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.
Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:
GPE = mgh
GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)
GPE = 15,998.95 J (joules)
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