The compound mnco3 is an ionic compound. what are the ions of which it is composed?

Answer:

Dishwasher

Explanation:

Molarity= No of moles of solute * 1000 / vol solution in ml

No of moles= Given mass / Molar mass

Given Mass of solute (H2O2)= 10g

Molar mass of H2O2=34gmol^-1

No of moles= 10/34= 0.294 moles

Volume of solution=50ml

Molarity =   0.294*1000 / 50

Molarity = 5.8M

The elements can be sorted in order of increasing temperature at which they burn in a nuclear fusion reaction as: Hydrogen, Helium, Carbon, Neon/Magnesium/Oxygen, and Silicon/Sulfur.

In a high-mass star, fusion occurs in concentric shells resembling the layers of an onion. As you move closer to the core, the temperature increases.

The outermost layer contains hydrogen, which fuses into helium at the lowest temperature.

Moving inward, the next layer contains helium, which fuses into carbon at a higher temperature than hydrogen fusion.

The next layer contains carbon, which fuses into heavier elements like neon, magnesium, and oxygen at an even higher temperature.

Further inward, neon, magnesium, and oxygen can fuse into even heavier elements, such as silicon and sulfur, at a higher temperature.

Finally, the core contains silicon and sulfur, which can fuse into iron at the highest temperature.

So, the elements can be sorted in order of increasing temperature at which they burn in a nuclear fusion reaction as follows: Hydrogen, Helium, Carbon, Neon/Magnesium/Oxygen, and Silicon/Sulfur.

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Answer:

3.7

Explanation:

pH+pOH=14

10.3+pOH=14

pOH =14-10.3

3.7

The total amount of ATP generated from the complete oxidation of an unactivated polyunsaturated C22 fatty acid with 5 double bonds is approximately 140 ATP.

To calculate the amount of ATP generated from the total oxidation of a polyunsaturated C22 fatty acid with 5 double bonds, we need to consider the process of beta-oxidation.

Beta-oxidation is a metabolic pathway that breaks down fatty acids into acetyl-CoA units, which can then enter the citric acid cycle (also known as the Krebs cycle) to generate ATP.

Each round of beta-oxidation involves four steps:

Each round produces one molecule of acetyl-CoA, NADH, and FADH2.

The number of rounds of beta-oxidation required to completely oxidize a fatty acid depends on the length of the fatty acid chain. For a C22 fatty acid, it will undergo 10 rounds of beta-oxidation to generate 10 molecules of acetyl-CoA, NADH, and FADH2.

However, since the fatty acid in question is polyunsaturated and has 5 double bonds, there will be additional reactions required to deal with these double bonds.

For each double bond, two additional enzymes are needed:

These enzymes allow the fatty acid to undergo additional oxidation steps to break down the double bonds.

Since there are 5 double bonds, there will be 5 sets of additional reactions needed to fully oxidize the fatty acid.

Now, let's calculate the amount of ATP generated from the oxidation process:

1. Each round of beta-oxidation generates 1 NADH and 1 FADH2. Therefore, from the 10 rounds of beta-oxidation for a C22 fatty acid, we will have 10 NADH and 10 FADH2.

2. Each NADH can generate approximately 2.5 ATP molecules, while each FADH2 can generate approximately 1.5 ATP molecules through oxidative phosphorylation.

Therefore, the ATP generated from the NADH molecules would be 10 NADH * 2.5 ATP/NADH = 25 ATP.

And the ATP generated from the FADH2 molecules would be 10 FADH2 * 1.5 ATP/FADH2 = 15 ATP.

3. In addition to the ATP generated from NADH and FADH2, each round of beta-oxidation also produces 1 molecule of acetyl-CoA. Each molecule of acetyl-CoA can generate approximately 12 ATP molecules through the citric acid cycle.

Therefore, the ATP generated from the 10 molecules of acetyl-CoA would be 10 acetyl-CoA * 12 ATP/acetyl-CoA = 120 ATP.

4. Finally, we need to account for the ATP required to activate the fatty acid at the beginning of beta-oxidation. For each round of beta-oxidation, two ATP molecules are consumed for activation.

Since there are 10 rounds of beta-oxidation, the ATP required for activation would be 10 rounds * 2 ATP/round = 20 ATP.

Adding up the ATP generated and subtracting the ATP required for activation, the total ATP generated from the complete oxidation of the unactivated polyunsaturated C22 fatty acid with 5 double bonds would be:

ATP generated = 25 ATP (from NADH) + 15 ATP (from FADH2) + 120 ATP (from acetyl-CoA) - 20 ATP (for activation)

ATP generated = 140 ATP.

Therefore, the total amount of ATP generated would be 140 ATP.

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Answer:

;l ok

Explanation:

Null hypοthesis (H0): The prοpοrtiοn οf ball bearings with diameter values less than 2.20 cm in the existing manufacturing prοcess is the same as the prοpοrtiοn in the new prοcess.

A null hypοthesis is a type οf statistical hypοthesis that prοpοses that nο statistical significance exists in a set οf given οbservatiοns. Hypοthesis testing is used tο assess the credibility οf a hypοthesis by using sample data. Sοmetimes referred tο simply as the "null," it is represented as H₀.

Alternative hypοthesis (HA): The prοpοrtiοn οf ball bearings with diameter values less than 2.20 cm in the existing manufacturing prοcess is different frοm the prοpοrtiοn in the new prοcess.

Level οf significance: α = 0.05

Test statistic: -1.29

P-value (twο-tailed): 0.1984

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The addition of sodium hydroxide to the salicylic acid coupling agent in the scheme is crucial in neutralizing the carboxylic acid group, creating a more reactive acylating agent that can react with the amine group of the amino acid to form the desired amide product.

Conducting the coupling step under acidic conditions would result in a slower reaction rate due to protonation of the amine group and lack of activation of the carboxylic acid group, leading to the formation of an ester instead of an amide bond as the major product.

a. The addition of sodium hydroxide to the salicylic acid coupling agent in the scheme is important because it acts as a base to neutralize the acidic carboxylic acid group of the coupling agent. This results in the formation of a more reactive acylating agent, which is necessary for the acylation of the amine group in the amino acid.

b. i. If the coupling step was conducted under acidic conditions, the reaction rate would be slower because the amine group in the amino acid would be less nucleophilic due to protonation. The coupling agent's carboxylic acid group would also not be activated, leading to a decrease in reaction rate.

ii. No, the major product under acidic conditions would be an ester instead of an amide. This is because the carboxylic acid group of the coupling agent would react with the alcohol group in the amino acid instead of the amine group, leading to the formation of an ester bond.

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Answer:

2H2+ 02-->2H20

So 4H2 + 202-->4H20

so the answer is 4 water molecules.

The given statement " William Aston created the mass spectrograph to analyze and separated them, found 218 and found mass and percent abundance of each atoms" is false.

The mass spectrograph was not invented by William Aston. It was actually invented by J.J. Thomson in the early 20th century.

J.J. Thomson's work with the mass spectrograph led to the discovery of isotopes, which are different forms of an element with the same number of protons but different numbers of neutrons. Isotopes have different masses, and the mass spectrograph allowed scientists to separate and analyze them based on their mass-to-charge ratio.

The process of using a mass spectrograph to determine the mass and percent abundance of isotopes is known as mass spectrometry. It involves ionizing a sample, separating the ions based on their mass-to-charge ratio, and detecting the ions to determine their abundance.

The completed question is given as,

State true or false

William Aston created the mass spectrograph to analyze and separated them, found 218 and found mass and percent abundance of each atoms.

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Answer:

0.694 cents per second

Explanation:

25x100=2500 cents per hour, 2500/60 = 41.67 per minute and 41.67/60=0.694 cents per second

Answer:

4. 125°C

Explanation:

I hope this helps you :D

Answer:

Explanation:can you take a pic of it a little up so i can see the h please??

Answer:

Organic Molecule.

Explanation:

Any molecule with C atoms and H atoms are organic molecules in chemistry.

Examples could be C₄H₅, C₉H₁₈O₆, C₅H₁₂N.

Fuel shortages in the 1980s started the interest in fuel efficiency  best describes a society’s desire for fuel-efficient vehicles because of Iran- Iraq war.

The Iran-Iraq War in 1980 is the main cause of shortage of oil production. Iraq's and Iran's oil production dropped significantly which triggering economic recessions worldwide.

So that's why society’s desire for fuel-efficient vehicles in order to reduce consumption as well as reduce pollution.

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Answer:

At 70∘C , ammonium chloride has a solubility of about 62 g / 100 g H2O . This tells you that can only hope to dissolve 62 g of ammonium chloride for every 100 g of water before the solution becomes saturated.

The higher the concentration of OH- ions, the more basic the solution becomes.Finally, a solution is considered to be neutral if the concentration of H+ ions and OH- ions are equal. In this case, the pH value of the solution is 7.

The concentration of hydrogen ions (H+) and hydroxide ions (OH-) determine whether a solution is acidic, basic or neutral. The pH scale ranges from 0 to 14. If the pH value of a solution is less than 7, it is acidic. If the pH value is greater than 7, it is basic. If the pH value is equal to 7, it is neutral.A solution is considered to be acidic if it has a higher concentration of H+ ions and a lower concentration of OH- ions. In an acidic solution, the concentration of H+ ions is greater than the concentration of OH- ions. The higher the concentration of H+ ions, the more acidic the solution becomes.On the other hand, a solution is considered to be basic if it has a lower concentration of H+ ions and a higher concentration of OH- ions. In a basic solution, the concentration of OH- ions is greater than the concentration of H+ ions. The higher the concentration of OH- ions, the more basic the solution becomes.Finally, a solution is considered to be neutral if the concentration of H+ ions and OH- ions are equal. In this case, the pH value of the solution is 7.
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(a) The speed of light in the unknown substance is determined 1.82 x 10⁸ m/s.

(b) The light will bend away from the normal since speed of light in air is not equal to speed of light in the substance.

The speed of light passing from air into the substance is calculated as follows;

refractive index = speed of light in air / speed of light in the substance

speed of light in the substance = speed of light in air/refractive index

speed of light in the substance = (3 x 10⁸) / (1.65)

speed of light in the substance = 1.82 x 10⁸ m/s

Thus, the light will bend away from the normal since speed of light in air is not equal to speed of light in the substance.

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Answer:

The answer is 1.834 * 10

Explanation:

Answer: 2 The Proximity toward the ocean

Explanation:

May i plz have brainiest  

When NH3 reacts with BF3, the nitrogen lone pair donates a pair of electrons to the boron atom. This forms a new bond between the nitrogen and boron atoms, and the boron atom gains a full octet of electrons:

 F                 H         H

/ \                /         /

B   F  +      N       /

\ /                \   /

 F                   H

NH3 acts as the Lewis base because it donates a pair of electrons to BF3, which acts as the Lewis acid. The electron pair being donated is the lone pair on the nitrogen atom in NH3.

The reaction between NH3 and BF3 can be modeled using electron dot structures.

First, let's draw the Lewis structure for each molecule:

NH3:

H         H

\        /

 N

/        \

H         H

BF3:

 F

/ \

B   F

\ /

 F

In NH3, nitrogen has five valence electrons and each hydrogen has one valence electron. The electrons are shared to form three covalent bonds between the nitrogen and hydrogen atoms, and there is one lone pair of electrons on the nitrogen atom.

In BF3, boron has three valence electrons, and each fluorine has seven valence electrons. The electrons are shared to form three covalent bonds between the boron and fluorine atoms.

In this reaction, NH3 acts as the Lewis base because it donates a pair of electrons to BF3, which acts as the Lewis acid. The electron pair being donated is the lone pair on the nitrogen atom in NH3.

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Answer:

A one mL per minute rate (or slower) is recommended for best results in a fractional distillation; simple can go faster. Slow, gradual distillation essentially allows the best equilibration and heat transfer. If you heat too fast, vapors may not condense as quickly as desired, and may waste some of the column.

Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

brainlest?

Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

Answer:

0.04838J

Explanation:

Heat is a form of energy that is transferred from one body to another as the result of a difference in temperature between the bodies , here heat is added to the water as a result of temperature change of 0.364 degreesC

Given:change in temperature=0.364

Mass of water=0.0318g

But we need specific heat capacity of water which is

4.2 J/g°C

Then we can calculate How much heat is added by using below formula

Energy = Mass * specific heat capacity *(change in temperature)

energy =0.0318g* 4.18g*0.364

=0.04838J

Answer: They have 8 valence electrons except for helium. Helium has 2 valence electrons.

Hope this helps!

The answer to the question is that the rate of the reaction can be calculated using the formula:

rate = Δ[I2] / Δt

where Δ[I2] is the change in concentration of iodine over time (in this case, 5 minutes), and Δt is the time interval.

To calculate Δ[I2], we need to first determine the initial concentration of iodine. This can be done using the equation:

n = C x V

where n is the number of moles, C is the concentration in moles per liter, and V is the volume in liters.

For the solution containing iodine, we have:

n = 0.005 mol/L x 0.002 L = 0.00001 mol

Since the ratio of acetone to HCl is 4:1, we can assume that the concentration of HCl is also 4 M. This means that the number of moles of HCl in the solution is:

n = 4 mol/L x 0.002 L = 0.008 mol

Since HCl is in excess, we can assume that all of the iodine reacts with acetone. The balanced chemical equation for the reaction is:

I2 + CH3COCH3 + H2O → CH3COCH2I + 2H+ + 2I-

This shows that 1 mole of iodine reacts with 1 mole of acetone. Therefore, the number of moles of iodine that react with the acetone is also 0.00001 mol.

After the reaction is complete, all of the iodine has been consumed, so the final concentration is 0 mol/L. Therefore, the change in concentration is:

Δ[I2] = 0 mol/L - 0.005 mol/L = -0.005 mol/L

Substituting this into the formula for the rate gives:

rate = (-0.005 mol/L) / (5 min) = -0.001 mol/L/min

The negative sign indicates that the concentration of iodine is decreasing over time, as expected for a reaction.

The rate of the reaction was calculated using the change in concentration of iodine over time. The initial concentration of iodine was determined from the volume and concentration of the solution. Since iodine is the limiting reactant, all of it is consumed in the reaction, and the change in concentration is equal to the initial concentration. The rate is expressed in units of mol/L/min.

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The compound B is 3,3-dimethyl-1-butyne, and the compound C is 4,4-dimethyl-2-pentyne.

Alkynes are hydrocarbons that have triple bonds between carbon atoms. CₙH₍₂ₙ₋₂₎ is the typical formula for molecules with one triple bond. Alkynes undergo many of the same reactions as alkenes, but because a triple bond contains two p-bonds, they can react twice.

Here, compound B with the molecular formula C₆H₁₀ is 3,3-dimethyl-1-butyne and compound C is 4,4-dimethyl-2-pentyne. The compound B reacts with sodium amide (NaNH₂) and methyl iodide (CH₃I), giving the compound C. This reaction explains the acidity of non-terminal alkynes.

In this reaction, sodium amide first abstracts the protons from carbon atoms near the triple bond. The resulting carbanions undergo rapid proton transfer equilibria to form a stable terminal alkyne conjugate base.

The reaction is attached.

The complete question is -

Identify the compounds B and C. Compound B has molecular formula C₆H₁₀ and gives (CH₃)₂CHCH₂CH₂CH₃ when treated with excess H₂ in the presence of Pd. B reacts with NaNH₂ and CH₃I to form compound C (molecular formula C₇H₁₂).

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The theoretical oxygen demand associated with the complete aerobic degradation of 1 mg/L of benzene is 0.0128 mmol/L * 15 = 0.192 mmol/L.

The theoretical oxygen demand associated with the complete aerobic degradation of 1 mg/L of benzene (C₆H₆) can be calculated using the stoichiometry of the reaction.

The balanced equation for the complete aerobic degradation of benzene is:

C₆H₆ + 15O₂ -> 6CO₂ + 3H₂O

From the equation, we can see that for every 1 mole of benzene, 15 moles of oxygen are required to completely degrade it.

To calculate the theoretical oxygen demand, we need to convert 1 mg/L of benzene to moles. The molar mass of benzene (C₆H₆) is approximately 78.11 g/mol.

1 mg/L is equivalent to 1 mg/L * (1 g/1000 mg) * (1 mol/78.11 g) = 0.0128 mmol/L. Using the stoichiometry, for every 1 mmol of benzene, 15 mmol of oxygen are required.

Therefore, the theoretical oxygen demand associated with the complete aerobic degradation of 1 mg/L of benzene is 0.0128 mmol/L * 15 = 0.192 mmol/L.

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Answer:

A motor (device that converts electrical energy into kinetic energy) runs by using the magnetic field formed by a flowing current formed into a loop.

The 20 amino acids  are:

Alanine (Ala)  Arginine (Arg) Asparagine  (Asn) Aspartic acid (Asp) Cysteine (Cys) Glutamic acid  (Glu) Glutamine (Gln ) Glycine (Gly) Histidine (His) Isoleucine (Ile) Leucine (Leu) Lysine (Lys) Methionine (Met) Phenylalanine (Phe)  Proline (Pro)  Serine (Ser)  Threonine (Thr)  Tryptophan (Trp)  Tyrosine (Tyr) Valine (Val)

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Answer:

1. B

2.C

3.D

4.Sorry don't this one :(

5.A

Explanation:

please give me at least 20 points ❤