The cost of a rework for a manufactured part is $85 per hour. The part has to be made to the following dimensions: 195 +/- 0.04mm. What is the cost if the average part size is 195.02mm?

Answer:

B SIR

Step-by-step explanation:

the table's depiction of the probability distribution for X And section an asks us to calculate the likelihood that X equals two. When X = 2, the chance of X = 2 is 0.15, and for B, we need to determine the likelihood of more than 3.

There are only two ways that X might be greater than three: X is equal to four, or X is equal to five, increasing the likelihood that X is greater than three. Therefore, the likelihood of being more than three is equal to the likelihood of being four. Additionally, the likelihood of being five, These probability are.03 and.02, which equals C. We are asked to determine the likelihood that X is equal to one. When X is, the probability that X will be one is.7, and we want to know the likelihood that X will be less than four. The options for X being one, two, or three or fewer than four. Therefore, these have odds of.1,.15, and.7.The chance is 95 percent. Since you were asked to determine the mean for X for discrete random variables like this one, the mean is equal to the total of all possible values of X multiplied by the probability associated with each one. Therefore, that is once. 2 times 7 plus. Three times 15 plus. 1 and onward. And this equals 1.52; to find f, we must determine the discrete random variable X's standard deviation. This formula, which also has this form for the standard deviation, can be used to represent the latter version of the standard deviation, which is the square root of one squared times. 7Thus, that is two times squared. 15 and onward. After completing the square root procedure, we deduct the principal squared, and the result is approximately 2.93–5. The goal of having X equal to at least two has not been achieved for G, as evidenced by the fact that the typical number of occupants for cars is 1.52.

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Answer:

$20 i think

Step-by-step explanation: have a good day bye bye yup yup

In a case whereby Malcolm is finding the solutions of this quadratic equation by factoring 3x²-24x=-45, the correctly factored equation that can be used to find the solutions is 3(x-3)(x-5)=0

The given equation is  3x²-24x=-45

The equation can be re written as;

3x²-24x=-45

3x²-24x+45 = 0

Then we can divide by 3 and have

x²-8x + 12= 0

thene if we factorize we have

x= 5, x= 3

Therefore, option B is correct.  which is 3(x-3)(x-5)=0

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The probability of any one undergraduate being selected in a random sample of 2550 undergraduates from a population of 25500 can be calculated using the formula:

Probability = Number of individuals in the sample / Total population

In this case, the probability would be:

Probability = 2550 / 25500 = 0.1 or 10%

Therefore, the probability of any one undergraduate being included in the random sample is 10%. This means that for every 10 undergraduates in the population, only one would be included in the sample. It is important to note that this probability assumes a truly random sampling process with no bias or influencing factors affecting the selection of individuals.

In conclusion, the probability of any undergraduate being in a random sample of 2550 undergraduates selected from a population of 25500 is 10%. This information can be useful in determining the representativeness of the sample and making inferences about the larger population based on the characteristics of the sample.

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Step-by-step explanation:

y+x-2-6x = y-5x-2

2x+3-x-4 = x-1

5xy+4x-5xy-3 = x

Answer:

1 does not represent a function, but 2 and 3 do

Step-by-step explanation:

1 is not a function because there are multiple points, with the same x value. 2 and 3 are functions because there are not multiple points with the same x value

Answer:

37.6%

Step-by-step explanation:

You can use find John's original earnings by taking 12% off of 5600. You can do this by doing 0.78 x 5600, and you get 4368.

Now, we can use John's orignal earning to find Musa's original earning. Knowing that their earning's correspond, you can use the proportion 5/3 = 5600/x. You can use cross products to solve:

4368 x 3 = 5x

13104 = 5x

2620.8 = x

Musa's original earnings was 2620.8.

If the sum of their new earnings is 9800, we can take of John's new earnings to find Musa's new earnings. 9800 - 5600= 4200. That means Musa's new earnings were 4200. To find the percentage, we can use the following equation, and then solve:

2620.8 = 4200x

.624 = x

That means that 2620.8 is 62.4% of 4200, and that it increased by 37.6%.

Okay, according with the identities of parallelograms we have: AE=CE and BE=DE.

Replacing we obtain:

AE=CE

2x=x+2

2x-x=2

x=2

BE=DE

y+10=4y−8

10+8=4y-y

18=3y

y=18/3

y=6

And considering that BD=BE+DE, we got:

BD=(y+10)+(4y-8)=(6+10)+(4*6-8)=(16)+(24-8)=16+16=32

So, finally we obtain that the length of BD is 32 units.

​(a) 9.3875 response represents the 94th ​percentile.

​(b)  6.2625 response represents the 62nd percentile.

(c) 3.8150 response represents the first quartile.

Given:

µ =     5.5

σ =    2.5

a) 94th percentile                                    

P(X < x) =    94%                                    

P(Z < z) =    0.94                                    

z =    1.555  [ from z-table or excel command: =NORM.S.INV(probability) ]                        

x = µ + z σ  = 5.5 + (1.555 × 2.5)  

                  = 9.3875    

b) 62nd percentile                                    

P(X < x) = 62%                                    

P(Z < z) = 0.62                                    

z = 0.305 [from z-table or excel command: = NORM.S.INV(probability) ]                        

x = µ + z σ = 5.5 + ( 0.305× 2.5 )

                 = 6.2625    

c) first quartile

25th percentile                                    

P(X < x) = 25%                                    

P(Z < z) = 0.25                                    

z = -0.674 [from z-table or excel command: = NORM.S.INV(probability) ]                        

x = µ + z σ = 5.5 + ( -0.674 × 2.5)

                 = 3.8150    

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Complete Question:

In a recent study on world​ happiness, participants were asked to evaluate their current lives on a scale from 0 to​ 10, where 0 represents the worst possible life and 10 represents the best possible life. The mean response was 5.5 with a standard deviation of 2.5.

​(a) What response represents the 94th ​percentile?

​(b) What response represents the 62nd percentile?

(c) What response represents the first quartile?

To find the response that represents a specific percentile or quartile, convert the percentage to a decimal, multiply it by the total number of responses, and use the result to locate the corresponding position in the data set.

(a) To find the response that represents the nth percentile, we need to determine the score below which n% of the responses fall. Let's say we want to find the response that represents the 75th percentile. We start by converting the percentile into a decimal, so 75% becomes 0.75.

Next, we calculate the position of the response in the data set. We multiply the decimal by the total number of responses. For example, if there were 100 participants, 0.75 x 100 = 75. This means that the response at position 75 would represent the 75th percentile.

(b) Similarly, if we want to find the response that represents the 90th percentile, we convert 90% to 0.90. Then we multiply it by the total number of responses to find the position of the response in the data set.

(c) To find the response that represents a specific quartile, we divide the data set into four equal parts.

The first quartile (Q1) represents the 25th percentile, the second quartile (Q2) represents the 50th percentile (also known as the median), and the third quartile (Q3) represents the 75th percentile. We can use the same method mentioned in part (a) to find the responses that represent these quartiles.

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Answer:

multiply the base number with the while number and add to the top number

Step-by-step explanation:

4 ×3+2 = 14/2 u can simplify

Answer:

Step-by-step explanation:

so for 3 2/4 you first multiply the whole number (the 3) with the bottom number of the fraction (the 4) that is 12. Then you add the top number (2) and get 14. That is the top number to your improper fractions. The bottom number is 4 because the bottom number will be the same as the original fraction. this is called the c method. Multiply the denominator by the whole number then add the numerator. Same method applies for 4 2/5                                                                                                                                                                                                                                    

Answer:

14=D

15=D

Step-by-step explanation:

Answer:

------------------

Let the angle be x.

Its complement is 90 - x and its supplement is 180 - x.

Set up an equation to reflect that its complement is 1/4 its supplement​:

It is difficult to determine whether the statement is true or false without additional information. However, more than 100 words will be used to explain the concept of welding and its types along with some additional information that may be useful in determining the accuracy of the statement.

Welding is a process of joining two or more metals to form a strong and permanent bond. In general, welding is used in almost all areas of life, from automobiles to medical equipment, from aircraft to computers, and so on. Welding is the process of heating the metal to a high temperature to melt it and add a filler material to the melted parts to join them together. Different types of welding are used depending on the metal, thickness, and intended use.There are various types of welding, some of which are mentioned below:

Shielded Metal Arc Welding (SMAW)Gas Tungsten Arc Welding (GTAW)Gas Metal Arc Welding (GMAW)Flux-Cored Arc Welding (FCAW)Plasma Arc Welding (PAW)Submerged Arc Welding (SAW)Electron Beam Welding (EBW)Laser Beam Welding (LBW)Resistance Welding (RW)The answer to your questionIt is difficult to determine whether the statement is true or false without additional information. As a result, it is impossible to determine whether a triangular plate of triangular shape is welded to rectangular plates. Thus, the statement is inconclusive.

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Answer:

A

Step-by-step explanation:

calculate 20% of $88

\(\frac{20}{100}\) × $88 = 0.2 × $88 = $17.60

The property of binomial distributions is that the sum of the probabilities of successes and failures is always 1.

The correct statement is: "The sum of the probabilities of successes and failures is always 1." In a binomial distribution, each trial has only two possible outcomes, typically labeled as success and failure. The sum of the probabilities of these two outcomes is always equal to 1. This property ensures that the probabilities are mutually exclusive and exhaustive, covering all possible outcomes for each trial.

The statement "All trials are dependent" is incorrect. In a binomial distribution, each trial is assumed to be independent of the others, meaning the outcome of one trial does not affect the outcomes of subsequent trials.

The statement "The expected value is equal to the number of successes in the experiment" is not necessarily true. The expected value of a binomial distribution is equal to the product of the number of trials and the probability of success.

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To approximate the solution and maximize the given objective function we need to find the steepest ascent direction and iteratively update the values of x₁ and x₂ to approach the maximum value of z.

The method of steepest ascent involves finding the direction that leads to the maximum increase in the objective function and updating the values of the decision variables accordingly. In this case, we aim to maximize the objective function z = -(x₁ - 3)² - (x₂ - 2)².

To find the steepest ascent direction, we can take the gradient of the objective function with respect to x₁ and x₂. The gradient represents the direction of the steepest increase in the objective function. In this case, the gradient is given by (∂z/∂x₁, ∂z/∂x₂) = (-2(x₁ - 3), -2(x₂ - 2)).

Starting with initial values for x₁ and x₂, we can update their values iteratively by adding a fraction of the gradient to each variable. The fraction determines the step size or learning rate and should be chosen carefully to ensure convergence to the maximum value of z.

By repeatedly updating the values of x₁ and x₂ in the direction of steepest ascent, we can approach the solution that maximizes the objective function z. The process continues until convergence is achieved or a predefined stopping criterion is met.

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Answer:

From greatest to least: AB, AC, BC

a. The efficiency of Expedition Everest is approximately 87.8%.

b. The utilization of Expedition Everest is approximately 94.7%.

c.  The demand is greater than the effective capacity, the operation is considered overcapacity. This means that the ride cannot accommodate all the riders who wish to ride, resulting in long waiting times for guests.

To calculate the efficiency and utilization of Expedition Everest, we need to compare the actual number of riders with the design capacity and effective capacity.

Given:

Demand = 3,000 riders/hour

Average riders = 1,800 riders/hour

Design capacity = 2,050 riders/hour

Effective capacity = 1,900 riders/hour

a. Efficiency:

Efficiency is calculated as the average riders divided by the design capacity, multiplied by 100%.

Efficiency = (Average riders / Design capacity) * 100%

= (1,800 / 2,050) * 100%

≈ 87.8%

Therefore, the efficiency of Expedition Everest is approximately 87.8%.

b. Utilization:

Utilization is calculated as the average riders divided by the effective capacity, multiplied by 100%.

Utilization = (Average riders / Effective capacity) * 100%

= (1,800 / 1,900) * 100%

≈ 94.7%

Therefore, the utilization of Expedition Everest is approximately 94.7%.

c. Capacity Analysis:

To determine if the operation is overcapacity or undercapacity, we compare the demand with the effective capacity.

Demand > Effective capacity

3,000 > 1,900

Since the demand is greater than the effective capacity, the operation is considered overcapacity. This means that the ride cannot accommodate all the riders who wish to ride, resulting in long waiting times for guests.

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Answer:

Normally distributed

hope this helps! bye:)

\((\stackrel{x_1}{2}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{-3}-\underset{x_1}{2}}}\implies \cfrac{-2}{-5}\implies \cfrac{2}{5}\)

A parabola's vertex form equation is as follows:

y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola.

To use a calculator to find the equation of a parabola in vertex form, you would typically need to know the coordinates of the vertex and at least one other point on the parabola.

Determine the vertex coordinates (h, k) of the parabola.

Identify at least one other point on the parabola (x, y).

Substitute the values of the vertex and the additional point into the equation y = a(x - h)^2 + k.

Solve the resulting equation for the value of 'a'.

Once you have the value of 'a', substitute it back into the equation to obtain the final equation of the parabola in vertex form.

Note: If you provide specific values for the vertex and an additional point, I can assist you in calculating the equation of the parabola in vertex form.

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The equation "ax2 = y," which has one solution unless a = 4, and none unless a = 4, has a solution. x = √(-4ay) / (2a) restricted by the condition that y be negative.

We may use the quadratic formula to determine the solutions to an equation for various values of an to construct a solution to the equation "ax² = y," which has no solution when a = 4 & just one solution in all other cases.

According to the quadratic formula, the answers to the problem "ax2 + bx + c = 0" are provided by

x = (-b +/- √(b² - 4ac)) / (2a)

In this formula, if we add "ax² = y," we obtain

x = (-0 +/- √(0² - 4ay)) / (2a)

which simplifies to

x = √(-4ay) / (2a)

If a = 4, the equation becomes

x = √(-16y) / 8

The equation has no solutions if y is positive because the value of (-16y) is fictitious. The value of (-16y) is real if y is negative, but the equation is still unsolvable since x cannot have a negative value. As a result, when a = 4, the problem has no solutions.

The equation has a single solution provided by any other value of a.

x = √(-4ay) / (2a)

For example, if a = 3, the equation becomes

x = √(-12y) / 6

Since √(-12y) is imaginary if y is positive, the problem has no solutions. If y is negative, √(-12y) has a real value, and there is only one solution to the problem.

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The number of cans required to paint an area of 2000 square units is equal to 5 cans.

As given in the question,

Total area to be painted is equal to 2000 square units.

Area covered by one can of paint is equal to 400 square units

400 square units = 1 can of paint

⇒ 1 square units = ( 1 / 400 ) cans of paint

⇒ 2000 square units =  ( 2000 / 400 ) cans of paint

⇒ 2000 square units = 5 cans of paint

Therefore, the number of cans required to paint an area of 2000 square units using given can is equal to 5 cans.

The above question is incomplete, the complete question is:

How many cans of paint are needed to cover an area of 2000 square units if one can of paint covers in area 400 square units?

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Answer:

i believe the last one would be 9 for the number of hours kevin works.

Step-by-step explanation:

Answer:

What is the question?

Step-by-step explanation:

I cannot see an attachment.

The time which both of take to deliver 51 papers is 3.4hours.

Since, we have time which Maria and Charlie are taking to deliver 45 papers.

Whenever some relation is given for any object with time and it is asking same relation at any other time, we need to use unitary methods.

So, we use unitary method.

45 papers are delivered in =3 hours

1 paper is delivered in =(3/45)hours

Therefore, 51 papers are delivered in :

=(3/45)×51hours

=(51/15)hours

=17/5hours

=3.4hours

Hence, 3.4 hours will be taken by both to deliver 51 papers.

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The question paper will be of  30 marks of questions divided between part A and part B based on the given syllabus. The total marks for this question paper is 40 marks.

Part A (15 marks):

1. Define Big-O notation and provide an example of a function and its corresponding Big-O notation. (3 marks)

2. What is the time complexity of the brute force method for finding the Longest Common Subsequence (LCS) of two sequences? Is there a more efficient algorithm for solving this problem? Explain. (6 marks)

3. State and explain Dijkstra's algorithm for finding the shortest path in a weighted graph. What is the time complexity of this algorithm? (6 marks)

Part B (15 marks):

1. Define a graph and provide examples of real-world problems that can be represented as graphs. (3 marks)

2. Explain Breadth-First Search (BFS) and Depth-First Search (DFS) algorithms for traversing a graph. What is the time complexity of these algorithms? (6 marks)

3. Compare and contrast the Prim's and Kruskal's algorithms for finding the Minimum Spanning Tree (MST) of a graph. What is the time complexity of these algorithms? (6 marks)

Note: The questions can be adjusted and rephrased based on the teacher's preference and the level of the course.

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This is a sample question paper with a total of 30 marks. The questions are distributed between Part A and Part B based on the syllabus provided.

Part A: Answer 20 Marks

1. Explain the concept of complexity analysis and asymptotic notation. (5 marks)

In this question, you need to provide an overview of complexity analysis and asymptotic notation. Describe the purpose of complexity analysis, the different types of complexities (such as time complexity and space complexity), and the importance of asymptotic notation in analyzing algorithmic efficiency.

2. Compare and contrast the time complexity of the following algorithms: (6 marks)

  a) Bubble Sort

  b) Merge Sort

  c) Quick Sort

For this question, provide a brief description of each algorithm and discuss their time complexities. Compare their best-case, average-case, and worst-case time complexities and explain the reasons behind the differences. Use big O notation to represent the time complexities.

3. Discuss the concept of Longest Common Subsequence (LCS) and explain how it can be computed using dynamic programming. (9 marks)

In this question, introduce the concept of the Longest Common Subsequence (LCS) problem and its significance in string matching. Describe the dynamic programming approach to solve the LCS problem and provide a step-by-step explanation of the algorithm. Include the time complexity analysis and illustrate with an example.

Part B: Answer 10 Marks

1. Define a graph and discuss its basic components. (4 marks)

In this question, define what a graph is and describe its fundamental components, such as vertices (nodes) and edges. Explain the difference between directed and undirected graphs and discuss the concept of weighted graphs.

2. Compare and contrast Breadth-First Search (BFS) and Depth-First Search (DFS) algorithms in terms of their applications and traversal strategies. (6 marks)

For this question, explain the Breadth-First Search (BFS) and Depth-First Search (DFS) algorithms. Compare their traversal strategies and provide examples to illustrate the differences. Discuss their applications in different scenarios, such as finding shortest paths, connectivity analysis, and topological sorting.

Note: This is a sample question paper with a total of 30 marks. The questions are distributed between Part A and Part B based on the syllabus provided.

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Here we have some given restrictions that affect the number of medals, using these, we want to find the maximum number of bronze medals that can be awarded.

We will find that:

The maximum number of bronze medals that can be awarded is 535

Now let's see how we can get that.

Let's define the variables:

G = number of gold medals.

S = number of silver medals.

B = number of bronze medals.

Now we can see what information we have.

There are 2021 participants.

The number of silver medals is at least twice the number of gold medals.

S ≥ 2*G

The number of bronze medals is at least twice the number of silver medals:

B ≥ 2*S.

The number of all medals is not more than 40% of the number of participants.

The total number of medals is (G + S + B)

40% of the total number of participants is:

(40%/100%)*2021 = 0.4*2021 = 808.4

Then we have:

G + S + B ≤ 808.4

We can rewrite the above inequality as:

G + S + B ≤ 808.

Then we have 3 inequalities:

S ≥ 2*G

B ≥ 2*S

G + S + B ≤ 808

Now we want to maximize the number of gold medals.

This means that the total number of medals should be exactly 808 (the maximum number of total medals) so we have:

G + S + B = 808.

Also, if we want to maximize the number of gold medals, then we need to minimize the number of silver medals and the number of bronze medals, such that we get:

S = 2*G

B = 2*S

Now we have 3 equations:

G + S + B = 808

S = 2*G

B = 2*S

Replacing the third equation in the first one, we get:

G + S + 2*S = 808

G + 3*S = 808

Now we can replace:

S = 2*G

in the above equation to get:

G + 3*(2*G) = 808

G + 6*G = 808

7*G = 808 =

G = 808/7 = 115.43

But we can have 0.43 of a gold medal, so we need to round down to the next whole number:

G = 115

Now, with this restriction, we want to find the maximum number of bronze medals.

This means that we need to minimize the number of silver medals, so we use:

S = 2*G = 2*115 = 230

And the number of bronze medals will be such that:

B + G + S  = 880

B + 115 + 230 = 880

B = 880 - 115 - 230 = 535

The maximum number of bronze medals that can be awarded is 535

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