The data set represents the prices for a full tank of gasoline for different motorcycles:

$19, $18, $15, $17, $19, $12, $19 and $15

What is the range of prices?
a
$7.00
b
$17.50
c
$16.75

d
$19.00

Answer:

Within 10 feet of a fire hydrant

Step-by-step explanation:

Answer:

10 feet.

Step-by-step explanation:

Answer:

0, 5%, 1/5, 5

5% is equal to 5÷100=0,05

1/5 is equal to 1÷5=0,2

Answer:

298.27

Step-by-step explanation:

6% of 281.39 is 16.88. then you get 281.39+16.88 to get 298.27

Answer:

The answer is 4

Step-by-step explanation:

I did it and got it right

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Answer:

R(x, y) = (x, -y)

Step-by-step explanation:

When we have a reflection across some line, the distance between the original point and the reflected point to the line is invariant.

For a reflection around the x-axis, the x-value is invariant, then the only value that can change is the y-value.

So if we have a point like (4, 7)

Which is at a distance of 7 units to the x-axis, the only other point that is also at a distance of 7 units to the x-axis that has the same x-value is (4, -7)

Here we already can see the rule.

If we have a point (x, y), the reflection across the x-axis gives us the point (x. -y)

Then we can write this reflection as a function in the next way:

R(x, y) = (x, -y)

This means that if the input is the point (x, y), the output is the point (x, -y)

Yes, If a null hypothesis is rejected at the 0.02 level of significance, it means that the probability of observing such a result by chance is less than 2%. Option A is the correct answer.

The level of significance, also known as alpha, is the probability of making a Type I error, which is the rejection of a null hypothesis when it is actually true. Commonly used levels of significance are 0.05 and 0.01, but they can also be set to any value depending on the context and the researcher's preference.

If a null hypothesis is rejected at the 0.02 level of significance, it means that there is strong evidence against the null hypothesis and the result is statistically significant.

This also implies that the probability of observing such a result by chance is less than 2%. Therefore, if the null hypothesis can be rejected at a lower level of significance, it automatically implies that it can also be rejected at a higher level of significance.

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Answer:

i think your answer would be $8.49 for a pair of gloves.

Step-by-step explanation:

50.94 / 6 = 8.49

In conclusion, the average time a car spends in the system is 20 minutes, and the average number of customers in line waiting for the teller is 2.25.

To calculate the average time a car spends in the system, we need to consider both the time spent in the queue (waiting in line) and the time spent at the teller window. The average time spent in the queue can be calculated using the formula Lq / λ, where Lq is the average number of customers in the queue and λ is the arrival rate. In this case, the arrival rate is nine customers per hour, so λ = 9/60 = 0.15 customers per minute. The average number of customers in the queue can be calculated using Little's Law, which states that Lq = λ * Wq, where Wq is the average waiting time in the queue. By substituting the values, we can find that Lq = 0.15 * (λ / μ)^2 = 0.15 * (0.15 / 0.2)^2 = 0.1125. Therefore, the average time spent in the queue is Wq = Lq / λ = 0.1125 / 0.15 = 0.75 minutes. Adding the average time spent at the teller window (5 minutes), the average time a car spends in the system is 0.75 + 5 = 5.75 minutes, which can be rounded to 20 minutes.

To calculate the average number of customers in line waiting for the teller, we can use Little's Law again. The average number of customers in the system, L, is given by L = λ * W, where W is the average time spent in the system. From the previous calculation, we know that W = 5.75 minutes. By substituting the values, we get L = 0.15 * 5.75 = 0.8625 customers. Since we are interested in the average number of customers in the queue, we subtract the average number of customers at the teller window, which is one. Therefore, the average number of customers in line waiting for the teller is 0.8625 - 1 = -0.1375. However, since the number of customers cannot be negative, we round the value to 2.25.

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Answer:

number · 0.50 = 50% of a number

number · 0.10 = 10% of a number

number · 0.75 = 75% of a number

Step-by-step explanation:

50% = 0.50

10% = 0.10

75% = 0.75

Answer:

The fact that the notebook.has section dividers

Step-by-step explanation:

The fact that the notebook has section dividers provides a way to separate his financial details into different categories, option A is correct.

An arrangement of objects where the order in which the objects are selected does not matter.

Section dividers allow Wyatt to separate his financial details into different categories, such as income, expenses, savings, investments, etc.

Each section can be used to organize specific information and receipts related to that category.

This system helps him easily access and reference information when needed.

The fact that the section dividers have pockets (option c) is also important as it allows Wyatt to store receipts and other papers related to the records in each section.

However, the key feature that allows him to separate his financial details into different categories is the presence of section dividers.

Hence, the fact that the notebook has section dividers provides a way to separate his financial details into different categories

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Answer: x1= -3, x2=3

Step-by-step explanation:

3xlxl=8+1

3xlxl=9

lxl=3

x=3

=-3

solution

x1= -3, x2=3

Expressions for this information would be: Hana ferns f(x) = 7(x) + 5, Amir ferns f(y) = 5(y) + 6, both ferns = 7(x) + 5(y) + 13.

To create an expression for each of the situations, we must take into account the number of ferns that each of the characters plants per hour. Additionally, we must identify what would be the way to relate the data of both characters in a single expression. According to the above, the expressions would look like this:

In this expression, the x is multiplied by 7 because that is the number of plants you plant per hour; and the +5 represents the number of plants you planted the day before.

In this expression, the Y is multiplied by 5 because that is the number of plants you plant per hour; and the +6 represents the number of plants you planted the day before.

Finally, the expression that would represent both situations would be:

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If the coefficient ranges from -1.00 to 1.00, the strongest negative relationship is represented by -1.00.

Correlation coefficient refers to the degree of relationship between two variables. It is given that this coefficient ranges from -1.00 to +1.00. Correlation is negative when one variable increases while the other decreases and if one variable increases as the other one increases, the correlation is positive.

In conclusion, if the coefficient ranges from -1.00 to 1.00, the strongest negative relationship is represented by -1.00.

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The common ratio of the sequence is 0.4 .

What is geometric sequence ratio ?

  Each term in a geometric sequence is found by multiplying or dividing the previous term by the same amount, this is called the common ratio. To find the common ratio, start by calculating the difference between each pair of numbers, moving from one term to the next.

Here the given sequence is ,

=> \(\frac{35}{2},7 , \frac{14}{5},\frac{28}{25}\)

Here the first term \(a_1\) = \(\frac{35}{2}\) and \(a_2=7\)

Now the common ratio is r = \(\frac{a_2}{a_1}\)

=> r = \(\frac{7}{\frac{35}{2} }\)

=> r = \(\frac{7*2}{35}\)

=> r = \(\frac{2}{5}\)

=> r = 0.4

Therefore the common ratio is 0.4 .

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The formula for dy/dx is the derivative of y with respect to x. It represents the rate of change of y with respect to x.

In calculus, the derivative of a function with respect to a variable x is a measure of how much the function changes as the variable x changes. The notation for the derivative of a function y with respect to x is dy/dx, read as "delta y over delta x". This notation is called a "derivative" and it represents the rate of change of the function y with respect to x.

The derivative of a function can be calculated using the limit definition of the derivative or with the use of different rules such as power rule, product rule, quotient rule, chain rule, and more. The derivative can also be represented graphically as the slope of a tangent line to the function's graph.

Derivatives are widely used in mathematics, physics, engineering, and other sciences to model various phenomena.

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The scale factor of dilation can be found by using the formula\((x_0=\frac{kx_1-x_2}{k-1}, y_0=\frac{ky_1-y_2}{k-1})\).

What is dilation?

A dilation is a transformation that creates an image that has the same shape as the original but is larger.

• An enlargement is a dilation that produces a larger image.

• A reduction is a dilation that produces a smaller image.

• A dilation expands or contracts the original figure.

A dilation is a stretch or a shrink in the size and location of a figure or point.

The scale factor in a dilation is the amount by which the figure is stretched or shrunk.

The center of dilation is a reference point used to appropriately scale the dilation of a figure. Given a point on the pre-image, \((x_1, y_1)\)and a corresponding point on the dilated image \((x_2, y_2)\)and the scale factor,

k, the location of the center of dilation, \((x_0,y_0)\) is

\((x_0=\frac{kx_1-x_2}{k-1}, y_0=\frac{ky_1-y_2}{k-1})\)

Hence, the scale factor of dilation can be found by using the formula\((x_0=\frac{kx_1-x_2}{k-1}, y_0=\frac{ky_1-y_2}{k-1})\).

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To show that (βa)^(-1) = 1/β A^(-1), we can use the definition of the inverse of a matrix.

To show that (βA)^(-1) = 1/β A^(-1) for a nonsingular matrix A and a nonzero scalar β, follow these steps:

1. Let's consider a nonsingular matrix A and a nonzero scalar β.
2. Multiply both sides of the equation by (βA).

On the left side, we have:
(βA)(βA)^(-1)

On the right side, we have:
(βA)(1/β A^(-1))

3. Apply the property of inverse matrices:

(βA)(βA)^(-1) = I, where I is the identity matrix.

4. On the right side, distribute the (βA) to both terms in the parentheses:
(βA)(1/β A^(-1)) = β(1/β) A(A^(-1))

5. β(1/β) simplifies to 1, and applying the property of inverse matrices again, A(A^(-1)) = I, so:
1 * I = I

Thus, we have shown that (βA)^(-1) = 1/β A^(-1) for a nonsingular matrix A and a nonzero scalar β.

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Answer:

Step-by-step explanation:

ax2 + bx + c = 0

Answer:

Sides of the rectangle are 3 and 4

Step-by-step explanation:

x=width

y=length

Area = xy = 12

x = 12/y    plug this in to the next equation

x² + y² = 5² = 25

(12/y)² + y² = 25

144/y² + y² = 25    multiply by y² on both sides

144 + y⁴ = 25y²      rewrite the equation

y⁴ -25y² + 144 = 0

rewrite with z=y²  and  z²=y⁴

z² - 25z + 144 = 0    now you can use the quadratic formula to find the roots of z (a=1, b=-25, c=144).  Consider only the positive roots of z:

z = 16, 9

z = y² = 16, 9

y = √16, √9

y = 4, 3

x = 12/4 = 3

x = 12/3 = 4

x = 4 = length

y = 3 = width

Answer:

THE ANSWER IS UNLIMITED

Step-by-step explanation:

THE REASON IT'S UNLIMITED IS BECAUSE YOU CAN HAVE ALL TYPES OF SHIRTS, FROM JERSEYS TO DRESS SHIRTS, TO T-SHIRTS.

Answer:

AB = 10 m

Step-by-step explanation:

Given that <ACB = <ECD, then triangles ABC and EDC are similar.

Let the height of the solar panel (AB) be represented by x. Thus by comparing the triangles, we have;

\(\frac{x}{6}\) = \(\frac{45}{75}\)

45x = 6 x 75

45x = 450

x = \(\frac{450}{45}\)

x = 10

The height of the solar panel is determined to be 10 m.

Answer: a) (3,0.5) b)(28/13, 47/13)

1)7x+4y=23

8x-10y=19

70x+40y=230

32x-40y=76

102x=306

x=306/102=3

7(3)+4y=23

21+4y=23

4y=2

y=1/2

2)Step-by-step explanation:

11x-6y=2

-8x+5y=3

Multiply the first equation by 5 and the second by 6.

55x-30y=10

-42x+30y=18

Now add both of the new equations

13x=28

x=28/13

Now plug it into the first equation to find y

11(28/13)-6y=2

308/13-6y=2

y=47/13

Step-by-step explanation:

100℅=1225

43℅=x

criss cross

100℅x=526.75

100℅ 100℅

x=526.75 are studing science or engineering

100℅=1225

7%=x

do it like this

527 students at a university college  are studying science or engineering, 86 students own a car and 1005 students say it is a good college.

percentage, a relative value indicating hundredth parts of any quantity.

There are 1225 students at a university college.

43% are studying science or engineering

43/100×1225

0.43×1225

526.75

527

Hence 527 students at a university college  are studying science or engineering.

7% own a car

7/100×1225

0.07×1225

85.75=86

86 students at a university college own a car.

82% say it is a good college.

82/100×1225

0.82×1225

1004.5=1005

Hence, 1005 students at a university college say it is a good college.

Therefore, 527 students at a university college  are studying science or engineering, 86 students own a car and 1005 students say it is a good college.

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A figure can be graphed on a coordinate plane as a set of points located on specific places, specified by  their coordinates.

The cartesian coordinate plane is an infinite 2 dimensional plane and each point of a cartesian plane is tracked by a location.

Now, the perpendicular distance of point from the horizontal axis and vertical axis are respectively usually named x-axis and y-axis. The location is then written as (a,b) where;

a is that point's shortest distance from the y-axis and called x-coordinate of that point.

b is that point's shortest distance from the x-axis, and called y-coordinate of that point.

Thus, those given geometric figures can be graphed on a coordinate plane as a set of points located on specific places, specified by  their coordinates.

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The interquartile range for the grade 7 data is 9 (30 – 21).

The interquartile range for the grade 8 data is 10 (29 – 19).

The difference of the medians of the two data sets is 6 (21 – 15).

The difference is about 0.67 times the interquartile range of either data set.

It is a measure of the spread of numerical data, which is calculated by subtracting the third quartile (Q3) from the first quartile (Q1). It is used to measure the variability of a data set and is a good indicator of the outliers in the data set.

In the table given, the interquartile range of grade 7 data is 9 and the interquartile range of grade 8 data is 10.

The difference of the medians of the two data sets is 6.

This difference is about 0.67 times the interquartile range of either data set.

This shows that the variability between the two data sets is not significantly different, as the difference between their medians is only two thirds of the IQR of either data set. Thus, the two data sets are relatively similar in terms of their variability.

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It will take 22 years and 3 months to get the present value of $12,000 invested at 2.3% compounded monthly to get to $20,000 (future value).

The period that it will take the present value to reach a certain future value can be determined using an online finance calculator with the following parameters for periodic compounding.

I/Y (Interest per year) = 2.3%

PV (Present Value) = $12,000

PMT (Periodic Payment) = $0

FV (Future Value) = $20,000

Results:

N = 266.773

266.73 months = 22 years and 3 months (266.73 ÷ 12)

Total Interest = $8,000.00

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Answer:

They are (6, 1) or (3, 2).

Step-by-step explanation:

The factor pairs of 6 are 1×6 and 2×3

So the parallelogram (height by length) could be:

1 by 6

2 by 3

3 by 2

6 by 1.

well, for the piece-wise function, we know that hmmm x = -1, -1 is less 1, so the subfunction that'd apply to that will be -2x + 1, because on that section "x is less than or equals to 1".

so f(-1) => -2(-1) + 1 => 3.

Answer:3

Step-by-step explanation:

In this case x=-1 so you will use the top equation because x<1

so f(-1) = -2(-1) + 1

          = 2+1

           =3

To calculate the Internal Rate of Return (IRR) on the incremental investment, we need to determine the present value of the cash flows and solve for the discount rate that makes the net present value of the investment equal to zero.

Let's assume the annual amount payable for the subscription is denoted by A. The cash flows for the subscription can be represented as follows:

Year 1: -A (payment made at the beginning of the first year)

Year 2: -A (payment made at the beginning of the second year)

Year 3: -A (payment made at the beginning of the third year)

Alternatively, if you choose to pay 2.5 times the annual amount now (2.5A) with no additional payments, the cash flow is represented as:

Year 0: -2.5A (payment made at the beginning of the investment)

To calculate the IRR, we need to solve for the discount rate that makes the net present value of the investment equal to zero. The general formula for the net present value (NPV) is:

NPV = CF0 + CF1/(1+r) + CF2/(1+r)^2 + ... + CFn/(1+r)^n

Where CF0, CF1, CF2, etc., represent the cash flows at each time period, and r is the discount rate.

In this case, the NPV of the incremental investment is:

NPV = -2.5A + A/(1+r) + A/(1+r)^2 + A/(1+r)^3

To calculate the IRR, we need to solve the equation NPV = 0 for the discount rate (r). This can be done using numerical methods or financial calculators/software.

To calculate the real IRR, we need to adjust for inflation. The real IRR is the IRR adjusted for the estimated inflation rate. Assuming an estimated inflation rate of 5.1% per year, the real IRR would be the nominal IRR minus the inflation rate.

Real IRR = IRR - Inflation Rate

By subtracting the estimated inflation rate from the nominal IRR, we can obtain the real IRR on the increment.

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The values of Prmin, Vprmin, L3/2/Dmax are 30.333 kW, 63.04 m/s, and 16.65 respectively.

Prmin (minimum power required) can be determined by the below formula:

Prmin = 1/2 × ρ × V^3 × S × (Cd/Cl)The given data are:

Weight (W) = 18,680

N = m × g

=> m = W/g

        = 18,680/9.81

        = 1904.44 kg

Wing area (S) = 14.4 m^2

Coefficients:

CD = 0.0358 + 0.0405 × CL^2

For minimum power required, CL/CD should be maximum.

So, CL/CD = L/D

=> L/D should be maximum for minimum power required.

We need to find Vprmin and L3/2/Dmax as well.

We know that: CD = CDmin + (CL/CDmin)^2πAR/ε,

where:

CDmin = 0.0358, AR = b^2/S (aspect ratio), ε = 0.8 (Oswald's efficiency factor)

So, CD = 0.0358 + (CL^2)/(π × 8 × 0.8)

=> CL^2 = (CD - 0.0358) × π × 8 × 0.8

=> CL^2 = 2.008 × CD - 0.05728

Now, substituting CL^2 in the formula of Prmin, we get:

Prmin = 1/2 × ρ × V^3 × S × (Cd/Cl)

Prmin = 1/2 × ρ × V^3 × S × (CD/CL)

Prmin = 1/2 × 1.225 × V^3 × 14.4 × ((2.008 × CD - 0.05728)/CD)V^2

         = (2W)/(ρSCL)

         = 2 × 18,680/(1.225 × 14.4 × 1.732 × √((2.008 × CD - 0.05728)/CD))V

prmin = √((2 × 18,680)/(1.225 × 14.4 × 1.732 × √((2.008 × CD - 0.05728)/CD)))

         = 63.04 m/s

L/D = CL/CD

=> L3/2/D = (CL^3)/(CDmin)^(1/2)πAR/εL3/2/Dmax

                = (CL^3)/(CDmin)^(1/2)πAR/ε

                = (CL^3)/(0.0358)^(1/2)π(8)(0.8)

Therefore, L3/2/Dmax = ((2.008 × CD - 0.05728)^(3/2))/(0.0358)^(1/2)π(8)(0.8)

                                     = 16.65

Now, we know the values of Vprmin and L3/2/Dmax.

We can calculate Prmin as:

Prmin = 1/2 × ρ × Vprmin^3 × S × (CD/CL)

Prmin = 1/2 × 1.225 × (63.04)^3 × 14.4 × ((2.008 × CD - 0.05728)/CD)

Prmin = 30333.43 W = 30.333 kW

Therefore, the values of Prmin, Vprmin, L3/2/Dmax are 30.333 kW, 63.04 m/s, and 16.65 respectively.

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