The decomposition of NI3 to form N2 and I2 releases ?290.0 kJ of energy. The reaction can be represented as 2NI3(s)?N2(g)+3I2(g), ?Hrxn=-290.0 kJ
Find the change in enthaply when 17.0 g of NI3 decomposes.
Express your answer to three significant figures and include the appropriate units

1-The acceleration of the center of mass of the cylinder is a = F/(m+1/2m), 2- the force of friction is f = 1/2F, and 3- the speed attained by the center of mass after the cylinder has rolled through a distance x is v = √(2Fx/(m+1/2m)).

Since the cylinder does not slip, the force of friction acting on it is given by f = 1/2F, where F is the applied force. The net force acting on the cylinder is then F - f = 1/2F. The torque acting on the cylinder about its center of mass is τ = Fr/2, where r is the radius of the cylinder. Using Newton's second law of motion and the rotational version of Newton's second law, we can write the following equations of motion:

F - f = (m + 1/2m)a, τ = (1/2mr²)a

Solving these equations simultaneously, we get the acceleration of the center of mass as a = F/(m+1/2m) and the force of friction as f = 1/2F.

3-We may use the work-energy concept to estimate the speed obtained by the centre of mass after the cylinder has rolled a distance x, which states that the work done by the net force on the cylinder is equal to the change in its kinetic energy. W = (F - f)x is the work done by the net force, and K = 1/2mv2 is the change in kinetic energy, where v is the speed of the centre of mass. When we combine these two, we get: (F - f)x = 1/2mv2.

Substituting f and a values yields: (F/2)x = 1/2m(m+1/2m)v²

Simplifying further, we get: v = (2Fx/(m+1/2m))

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Explanation:

Given:

Speed of sound = 1400 m/s

Total time taken = 0.4 seconds

To find:

The depth of water

Solution:

As it take 0.4 seconds for the burst to reach the seabed and return (both ways), we can deduce that it takes 0.2 seconds to reach the seabed (one way).

This is because the speed of sound is a constant.

Now, to find the depth, we use the equation

Speed = Distance/Time

Here, we know the values of speed (1400 m/s) and time (0.2 seconds). Distance is the depth of the water, which we need to find. Let the distance be x.

Therefore

1400 = x/0.2

x = 1400 * 0.2

x = 280 m

We get the depth as 280 metres.

Feel free to ask me if you didn't understand any part.

Hope this helps! :D

A substance that prevents free flow of electrical current is known as an electrical insulator. The electrons in the insulator's atoms are securely bonded and immobile.

Protons are in overabundance on an aluminium plate that is positively charged. A positively charged aluminium plate has a deficiency of electrons when viewed from the perspective of electrons. We might characterise each extra proton as being somewhat dissatisfied in terms of people.

The other plate develops an imposed positive charge as a result of the electron's electric field, which pulls on the electrons that are in that plate and repels other electrons.

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From the calculation;

1) Melting point of indium = 171.4°

2) The resistance is 52.9 ohm

3) The power dissipated is  834 W

The temperature coefficient of resistance is a measure of how much the resistance of a material changes with temperature. It quantifies the relationship between the change in resistance and the change in temperature.

We have that;

R1/R2 = (1 + αt1)/(1 + αt2)

50/76.8 = (1 + (3.92 * \(10^-3\) * 20))/(1 +  (3.92 *\(10^-3\) * t))

0.65 = 1.0784/1 + 0.00392t

0.65(1 + 0.00392t) =  1.0784

0.65 + 0.0025t = 1.0784

t = 171.4°

P = \(V^2\)/R

R = \(V^2\)/P

R = \(230^2\)/1000

R = 52.9 ohm

The new power is;

P =\(210^2\)/52.9

P = 834 W

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Answer:

They respond to the weak force but not to the electromagnetic force, which means they cannot emit light.

Explanation:

The energy of the high energy neutron is 940.51 MeV.

Speed is nothing but the distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity with the SI unit meter/second.

We know that mass of the neutron m₀ = 939.6 MeV/c²

A high energy neutron is travelling at a speed of 18 million m/s.

Given that, v = 1.8 * 10⁷ m/s

The energy of neutron is calculated with the formula, m₀* c²/√(1 - v²/c²)

⇒ 939.6 * (3* 10⁸)²/√[1 - (1.8 * 10⁷)²/(3* 10⁸)²]

⇒ 940.51 MeV

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The 49 N of force is needed to give 196 m/s² acceleration to a 0.25 kg arrow. Option D is correct.

It can be defined as the product of the mass of the object and the acceleration of the object.

\(F = ma\)

Where,

\(F\) - force

\(m\) - mass = 0.25 kg

\( a \) - acceleration = 196 m/s²

Now, put the values in the formula,

\(F = 0.25 \times 196 \\\\ F = 49\rm \ N \)

Therefore, the 49 N of force is needed to give 196 m/s² acceleration to a 0.25 kg arrow.

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The depth below the surface of the glycerine at which the pressure is 2470 Pa greater than atmospheric pressure is 0.2 m.

Let us consider that the height of the container as h₀. The difference in pressure Δp = 2470 Pa. The density of glycerine is ρ = 1.26 × 10³ kg/m³. Let the depth below the surface of the glycerine be h. Let us use the formula of pressure and substitute the given values in it.

pressure = ρ × g × h + atmospheric pressure

The atmospheric pressure is constant and hence can be taken as a reference. We are looking for the depth of glycerine at which the pressure is greater than atmospheric pressure by 2470 Pa. Hence, we can write the above equation as follows.

Δp = ρ × g × h

The acceleration due to gravity is 9.8 m/s².

Substituting the values, we get:

Δp = ρ × g × h⇒ 2470 = 1.26 × 10³ × 9.8 × h⇒ h = 2470 / (1.26 × 10³ × 9.8)⇒ h = 0.2 m

Therefore, the depth below the surface of the glycerine at which the pressure is 2470 Pa greater than atmospheric pressure is 0.2 m.

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The strength of the magnetic force is inversely proportional to the square of distance between the magnets. Thus, as the distance increases, force between the magnets decreases.

Magnetic force, is the force generated by magnetic flux lines arised from a magnetic field.  A magnet have a south pole and north pole. There will be repulsive force between two like poles and attractive force between two unlike pole.

The force between two objects is always in inverse proportion with the distance and this is well explained by Coulomb's law of forces.

Thus, F ∝ 1/r² where, r is the distance.

Therefore, as the distance between two magnets increases the magnetic force between them decreases.

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Answer:

Final coordinates in meters : (2.17, -8.6)

Explanation:

We have the equation

displacement  Δd = average velocity x time

In this case there are two components of displacement corresponding to the two components of average velocity

\(v_{avg}(x) = 1.70 \; m/s\)

\(v_{avg}(y) = -1.50 \; m/s\)

Time traveled is t = 2.60s

So the x component is toward east (+x) axis and y component is due south(-y axis)

\(\sf{x \;displacement \;} \Delta_x = v_{avg}(x) x t= 1.70m/s \; \times \; 2.60 = 4.42 m\\\\\)

Since the original x-coordinate was at -2.25m, the end x coordinate is

x =  -2.25 + 4.2 = 2.17

The y-displacement
\(\sf{y \;displacement \;} \Delta_y = v_{avg}(y) x t\\\\ = - 1.50m/s \; \times \; 2.60 = - 3.9 m\\\\\\\\\)

The starting y-coordinate was at y = -4.70m

So final y-coordinate = -4.7 - 3.9 = -8.6m

Final coordinates in meters : (2.17, -8.6)

Answer:

it is 1 / square root of the change in distance

Explanation:

since the equation of the gravitational force is

\(F=G{\frac{m_1m_2}{r^2}}\)

then F and r are inversely related, by the equation

\(F \alpha \frac{1}{r^2}\)

this means when F is multiplied by 2 then r^2 is multiplied by half

so when r is multiples by half we first square the number (0.5) ^ 2 = 0.25

so

\(F \alpha \frac{1}{(0.25)r^2}\)

which means F is multiples by 1/0.25 or 4 when the radius is halfed

Answer:

neutron.

Explanation:

subatomic particles include,

neutron.

proton.

electron.

hope it helps. :)

Answer:

I think it's true,,

Explanation:

maybeee truee

the solenoid should carry a current of 1.43 A to produce a field of 4.45 mT at its center.

The magnetic field inside a solenoid can be calculated using the formula:

B = μ_0 * n * I

where B is the magnetic field, μ_0 is the permeability of free space (4π x 10^-7 T m/A), n is the number of turns per unit length (in this case, N/L where N is the total number of turns and L is the length of the solenoid), and I is the current.

We can rearrange this formula to solve for the current I:

I = B / (μ_0 * n)

Substituting the given values, we get:

I = (4.45 x 10^-3 T) / (4π x 10^-7 T m/A * 930 turns/0.34 m)

I = 1.43 A

Therefore, the solenoid should carry a current of 1.43 A to produce a field of 4.45 mT at its center.
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a) The number of turns in the solenoid is approximately 206.

To determine the number of turns in the solenoid, we can use the formula for the magnetic field inside a solenoid, which is given by B = μ₀nI, where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current.

Rearranging the formula, we have n = B / (μ₀I). Substituting the given values of B = 9.00 T and I = 75.0 A, and using the value of μ₀, we can calculate the number of turns per unit length. Multiplying it by the length of the solenoid (0.500 m) gives us the total number of turns in the solenoid, which is approximately 206.

A solenoid is a coil of wire wound in a helical shape. When a current flows through the coils, it creates a magnetic field along the axis of the solenoid. The strength of the magnetic field depends on factors such as the number of turns per unit length and the current flowing through the solenoid.

In this case, we are given the magnetic field and current, and we use the formula for the magnetic field inside a solenoid to calculate the number of turns. The higher the number of turns, the stronger the magnetic field generated by the solenoid.

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According to the given statement Thousands of times have been used to test and validate Einstein's theory of relativity.

The Global Positioning System, or GPS, is a system of orbiting satellites that is developed with Einstein's Relativity in mind. We apply the Relativity Principle of Einstein every time they use the GPS. Disturbances move across space-time as gravitational waves, according to General Relativity.

Once more, Newton's theory violated relativity by predicting an instantaneous force. General Relativity is a brand-new alternative gravity theory that Albert Einstein proposed in 1915. Waiting for a complete solar eclipse was the only way to compare it to Newton's hypothesis. Today, 100 years ago, Einstein was shown to be correct.

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Answer:

a10

Explanation:

The magnitude of the initial acceleration of a proton in a 5.5 × 106 N/C electric field is 5.27 × 10^14 m/s^2.

To calculate it in an electric field, we need to use the formula F = qE, where F is the force acting on the proton, q is the charge of the proton, and E is the electric field.

Given that the electric field E is 5.5 × 106 N/C and the charge of a proton q is 1.6 × 10^-19 C, we can plug these values into the formula to find the force F:

F = qE
F = (1.6 × 10^-19 C)(5.5 × 106 N/C)
F = 8.8 × 10^-13 N

Now that we have the force, we can use Newton's second law of motion to find the acceleration a:

F = ma
a = F/m

Where m is the mass of the proton, which is 1.67 × 10^-27 kg. Plugging in the values for F and m, we get:

a = (8.8 × 10^-13 N)/(1.67 × 10^-27 kg)
a = 5.27 × 10^14 m/s^2

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Answer: True

If you increase the pressure on a gas sample by decreasing the volume, the particles will speed up.

Answer:

The answer is "a, c and b"

Explanation:

The bullet's speed just before impact was 29.17 m/s.

The given information is:

Length of the rod, L = 0.17 m

Mass of the rod, M = 4.1 kg

Mass of the bullet, m = 4.9 g = 0.0049 kg

Initial velocity of the bullet, u = ?

Angle between the path of the bullet and the rod, θ = 60° = 60 x π/180 rad = π/3 rad

Angular velocity of the rod after the collision, ω = 11.0 rad/s

By conservation of angular momentum, we have:MV0L/2 + mV0L cos θ/2 = (ML2ω)/12 + (1/2)(m+M)R2ω

Where,R is the distance of the point of collision from the center of mass of the rod.R = L/2

Since the bullet lodges in the rod, final velocity of the bullet is zero. Therefore,MV0L/2 + mV0L cos θ/2 = (ML2ω)/12 + (1/2)(m+M)R2ω=> V0 = (6ωL)/(m+M+3Mcosθ)

Putting the values of L, ω, m, M and θ, we getV0 = (6 x 11.0 x 0.17)/(0.0049+4.1+3 x 4.1 x cos(π/3))= 29.17 m/s

Therefore, the speed of the bullet just before the impact is 29.17 m/s.

:Hence, the bullet's speed just before impact was 29.17 m/s.

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Answer:

100 newton

Explanation:

newton third law of motion says to every action there is an always an equal and opposite reaction so the magnitude will stay equal but opposite direction

Answer:

- 100N is the answer of this question

Given the speed of light in the medium as 1.3 x 10^8 m/s, we can calculate the index of refraction which is approximately 2.31.

The index of refraction (n) of a medium is defined as the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v). Mathematically, it can be expressed as:

n = c/v

In this case, we are given the speed of light in the medium as 1.3 x 10^8 m/s. The speed of light in vacuum is a constant value of approximately 3.0 x 10^8 m/s.

Substituting the given values into the formula, we have:

n = (3.0 x 10^8 m/s) / (1.3 x 10^8 m/s)

Simplifying the expression, we find:

n = 2.31

Therefore, the index of refraction of the transparent medium is approximately 2.31.

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Given :-

To Find :-

Solution :-

See attachment .

Firstly break the velocity of A , into it's vertical components . That will be ,

\( v_A = v_A cos60^o + v_A sin60^o \)

Now the component , \(v_A cos60^o \) coincides on side AC and is directed from A to C . Along CA, the velocity of particle C is directed . So both are in opposite directions.

So , the relative velocity of C with respect to A will be ,

\( v_{CA}= v_C - v_A \)

Substitute ,

\( v_{CA}= v - ( - v cos 60^o) \)

Value of cos 60° is 1/2 ,

\( v_{CA}= v + v\bigg(\dfrac{1}{2}\bigg)=v +\dfrac{v}{2}\)

Add the terms,

\( v_{CA}= \dfrac{2v + v}{2}=\dfrac{3v}{2}\)

Hence , now we can find the time taken by A and C ,to meet each other will be ,

\(s = v t \)

Substitute ,

\(d = \dfrac{3v}{2} t \)

Multiplying both sides by 2 ,

\( 2d = 3vt \)

Dividing both sides by 3v ,

\( t = \dfrac{2d}{3v} \)

Similarly , taking any two particles you will get the same time .

Hence the particles meet after 2d/3v time .

I hope this helps .

Answer:

  never

Explanation:

Particles moving on paths that don't meet at a point will be particles that never meet. Even if the paths meet at a point, which these don't, the particles may not meet if they arrive at different times.

__

Consider the diagrams in the attachments. In order, they show the positions of the particles shortly after takeoff, midway along the line, and after they have gone farther than the length of the line. The point of closest approach is shown in the second attachment, when the particles are halfway along the line.

Consider particles A and C. Their north/south direction is 'north' for each of them. They both have the same velocity in the 'north' direction, but have started at different points, so can never meet. Those two particles have opposite velocities in the east/west direction, so can pass each other (which they do in the second attachment), but cannot meet.

Answer:

yes 5 is greater

Explanation:

Answer: 5 grams is greater than 508 milligrams. Even though the number '508' is larger than '5,' you need to look at the units.

Answer:

Draw line perpendicular to mirror

Angle of incidence = angle between incident ray and perpendicular

Angle of reflection = angle between reflected ray and perpendicular

32 + 32 = 64

Angle of incidence = angle of reflection = 32 deg

The horizontal distance traveled by the football is determined as 25.33 m.

The horizontal distance traveled by the football is calculated as follows;

X = u²sin(2θ)/g

where;

X = (18² x sin(2 x 65))/9.8

X = 25.33 m

Thus, the horizontal distance traveled by the football is determined as 25.33 m.

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Answer:

Cold temps. . .

Explanation:

Hope it helps!

Answer:

Hi! These graphs I'm providing below are the answer to this problem, as well as the free response sections. I'll attach them below for you.

Hope this helps! :)

EDIT: I didn't realize that I had solved the problem wrong, so I deleted my answer. The other answer to this question is really good so look at that one, not this. I'm so sorry!