The deflection on the manometer is h meters when the pressure in the tank is 150 kPa absolute. If the absolute pressure in the tank is doubled, what will be the deflection on the manometer be

Answer:

provides the Organization with accurate data analytics ,

provides/ensures strict compliance in the organization,

helps in lowering the cost of managing data in the organization and

provides the data scientists access to the exact data they require to work with

Explanation:

The adoption of a data platform by an organization for the purpose of  handling Data, helps to simplify data governance by :

i)provides the Organization with accurate data analytics ,

ii) provides/ensures strict compliance in the organization,

iii) It helps in lowering the cost of managing data in the organization and

iv) provides the data scientists access to the exact data they require to work with

The absolute pressure of air at which it deviates from the continuum concept can be calculated using the given information.

To calculate the absolute pressure, we need to determine the number of molecules per cubic millimeter. Given that a gas is considered rarefied when it contains less than 10^12 molecules per cubic millimeter, and Avogadro's number is\(6.023 × 10^23\) molecules per mole, we can use these values to find the absolute pressure.

To convert from molecules per cubic millimeter to moles per cubic millimeter, we divide the given value by Avogadro's number:

\(10^12 molecules/mm^3 / (6.023 × 10^23 molecules/mol) = 1.66 × 10^-12 mol/mm^3\)

Now, we can convert the number of moles per cubic millimeter to pressure in Pascals (Pa) using the ideal gas law equation:

PV = nRT

Assuming the gas is at a temperature of 20 degrees Celsius, which is 293.15 Kelvin, and using the ideal gas constant R = 8.314 J/(mol·K), we can rearrange the equation to solve for pressure:

P = (nRT) / V

Given that the volume is 1 mm^3, the number of moles per cubic millimeter is 1.66 × 10^-12 mol/mm^3, and the temperature is 293.15 K, we can calculate the absolute pressure as:

\(P = (1.66 × 10^-12 mol/mm^3) × (8.314 J/(mol·K)) × (293.15 K) / (1 mm^3)P ≈ 3.89 × 10^-6 Pa\)

Therefore, the absolute pressure for air when it deviates from the continuum concept is approximately 3.89 × 10^-6 Pa.

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Answer:

Past tense of hear = heard

Answer:

The answer is below

Explanation:

Given that:

\(k_t=torque\ constant=0.075\ Nm/A\\\\k_v=voltage\ constant=0.12\ V/(rad/sec)\\\\R_a=armature \ resistance=2.5 \Omega\\\\V_t=terminal\ voltage=24\ V\\\\a)The \ starting\ current\ I_a\ is\ given \ as:\\\\I_a=\frac{V_t}{R_a} =\frac{24}{2.5} =9.6\ A\\\\The \ starting\ torque(T)\ is:\\\\T=k_tI_a=0.075*9.6=0.72\ N.m\)

b) The maximum speed occurs when the terminal voltage and back emf are equal to each other i.e.

\(V_t=e_b=k_v\omega\\\\\omega=\frac{V_t}{k_v}=\frac{24}{0.12} =200\ rad/s\)

c) The load torque is given as:

\(T_L=0.0125\Omega\\\\The\ motor\ torque \ is:\\\\T=k_t(\frac{V_t-k_v\omega}{R_a} )\\\\but\ T = T_L,hence:\\\\0.0125\omega=0.075(\frac{24-0.12\omega}{2.5} )\\\\0.03125\omega=1.8-0.009\omega\\\\0.04025\omega=1.8\\\\\omega=44.72\ rad/sec\\\\N=\frac{60\omega}{2\pi} =\frac{60*44.72}{2\pi} =427\ rpm\)

Answer:

Motorcyclist Fatality and Injury Rates per Vehicle Miles Traveled, 1998-2008. 10. 9. Fatalities in School Transportation Related Crashes,. 1998-2008.

Explanation:

Answer:

350×305π{^ not sure my answer please follow me

The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.

Answer:

The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.

Explanation:

The range of force exerted at the end of the rope is; 285.7 N to 1,000 N.

The net horizontal force of the cylinder when it is at equilibrium position can be found by applying Newton's second law of motion. Thus;

∑F = 0

F - μF_n = 0

We are given;

F_n = 5 kN = 5000 N

μ = 0.2

Thus;

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force will be increasing as the number of turns of the rope increases. Thus;

Minimum force = Total force/number of turns of rope

Since rope is wrapped three and half times, then;

number of turns = 3.5

Thus;

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

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In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

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The answer of the following statistics course will be:

i. Mean: 64.7

Median: 67

Mode: 70

ii. Mean: 69.4

Median: 72

Mode: 76

What is statistics?

Statistics is the study of data gathering, organisation, analysis, interpretation, and presentation. It is customary to begin with a statistical population or a statistical model to be researched when applying statistics to a scientific, industrial, or social problem. Populations can refer to many groupings of people or objects, such as "all people in a country" or "every atom in a crystal." Statistics is concerned with all aspects of data, including data collection planning in the form of survey and experiment design.

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ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.

ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.

Answer:

The resulting pressure of the gas when its volume decreases is 300 kN/m².

Explanation:

Given;

initial volume of the gas, V₁ = 80 L

number of moles of the gas, n = 0.5 moles

initial pressure of the gas, P₁ = 150 kN/m² = 150 kPa

Determine the constant temperature of the gas using ideal gas equation;

PV = nRT

where;

R is ideal gas constant = 8.315 L.kPa/K.mol

T is the constant temperature

\(T = \frac{P_1V_1}{nR} \\\\T = \frac{150.kPa \ \times \ 80 .L}{0.5 .mol \ \times \ 8.315(L.kPa/mol.K)} \\\\T = 2,886.35 \ K\)

When the gas is compressed to half of its volume;

new volume of the gas, V₂ = ¹/₂ V₁

                                             = ¹/₂ x 80L = 40 L

The new pressure, P₂ is calculated as;

\(P_2V_2 = nRT\\\\P_2 = \frac{nRT}{V_2} \\\\P_2 = \frac{0.5 \times 8.315\times 2886.35}{40} \\\\P_2 = 300 \ kPa = 300 \ kN/m^2\)

Therefore, the resulting pressure of the gas when its volume decreases is 300 kN/m².

Answer:

A) condenser pressure = 9.73 kPa,

B) 10242 kw

C) 36.9%

Explanation:

given data

entrance pressure of steam = 12.5 MPa

temperature of steam = 550⁰c

flow rate of steam = 7.7 kg/s

outer pressure = 2 MPa

reheated steam temperature = 450⁰c

isentropic efficiency of turbine( nt ) = 85% = 0.85

isentropic efficiency of pump = 90% = 0.90

From steam tables

at 12.5 MPa and 550⁰c ; h3 = 3476.5 kJ/kg,  S3 = 6.6317 kJ/kgK

also for an Isentropic expansion

S4s = S3 .

therefore when S4s = 6.6317 kJ/kg and P4 = 2 MPa

h4s = 2948.1 kJ/kg

nt = 0.85

nt (0.85) = \(\frac{h3-h4}{h3-h4s}\) = \(\frac{3476.5 - h4}{3476.5 - 2948.1}\)

making h4 subject of the equation

h4 = 3476.5 - 0.85 (3476.5 - 2948.1)

h4 = 3027.3 kj/kg

at P5 = 2 MPa and T5 = 450⁰c

h5 = 3358.2 kj/kg,  s5 = 7.2815 kj/kgk

at P6 , x6 = 0.95  and s5 = s6

using nt = 0.85 we can calculate for h6 and h6s

from the chart attached below we can see that

p6 = 9.73 kPa, h6 = 2463.3 kj/kg

B) the net power output

solution is attached below

c) thermal efficiency

thermal efficiency = 1 - \(\frac{qout}{qin}\) = 1 - ( 2273.7/ 3603.8) = 36.9% ≈ 37%

Answer:

Explanation:

Step 0: Store the dataset across 4 partitions in HDFS.

Partition 1 (already done):

- Partition 1 contains a subset of the dataset.

Partition 2:

- Partition 2 contains another subset of the dataset, balancing the load across the partitions.

Partition 3:

- Partition 3 holds a portion of the dataset to distribute the data evenly.

Partition 4:

- Partition 4 stores the remaining part of the dataset, ensuring load balance across all partitions.

Step 1: Map the data.

In this step, we cluster similar keys together within each partition.

Partition 1:

- Map function clusters keys: squares, stars, circles, hearts, triangles.

Partition 2:

- Map function clusters keys: squares, stars, circles, hearts, triangles.

Partition 3:

- Map function clusters keys: squares, stars, circles, hearts, triangles.

Partition 4:

- Map function clusters keys: squares, stars, circles, hearts, triangles.

Step 2: Sort and Shuffle.

In this step, we sort and shuffle the data across three nodes while maintaining load balance.

Node 1:

- Receives and processes data from Partition 1, Partition 2, and Partition 3.

Node 2:

- Receives and processes data from Partition 1, Partition 2, and Partition 4.

Node 3:

- Receives and processes data from Partition 3 and Partition 4.

Step 3: Reduce to calculate the final counts.

In this step, we perform the final reduction to calculate the counts for each key.

Node 1:

- Reduce function calculates the count of squares: count_squares = _____.

- Reduce function calculates the count of stars: count_stars = _____.

Node 2:

- Reduce function calculates the count of circles: count_circles = _____.

- Reduce function calculates the count of hearts: count_hearts = _____.

Node 3:

- Reduce function calculates the count of triangles: count_triangles = _____.

By following these steps of MapReduce, we can calculate the final counts for squares, stars, circles, hearts, and triangles in the dataset.

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The weapon that would create cast-off patterns consisting of small droplets in a linear pattern is a knife. So the correct answer is b) knife.

Cast-off patterns are typically created by the force and direction of the weapon used in an attack. Small droplets in a linear pattern are indicative of a sharp-edged weapon, such as a knife, which produces a spray of blood in the direction of the blade's motion. A baseball bat or a wooden plank would likely produce different patterns, such as larger and more irregularly shaped droplets, as they are not sharp and would not cut through the skin and tissue as easily. In conclusion, the weapon that would create cast-off patterns consisting of small droplets in a linear pattern is a knife due to its sharp edge and the force and direction used in an attack. This is an important factor to consider in crime scene investigation to determine the type of weapon used in a violent crime.

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A PFAS anchorage point for a 6-foot lanyard must be able to hold a minimum static load of 5,000 pounds.

PFAS stands for Personal Fall Arrest System, which is a type of fall protection equipment that is designed to protect workers from falls.
The 5,000-pound minimum static load requirement is based on the assumption that the PFAS will experience a shock load of 2,500 pounds in the event of a fall.

This shock load is due to the force of the fall and the weight of the worker, and it puts a significant amount of stress on the anchorage point. The 5,000-pound minimum static load ensures that the anchorage point can withstand this shock load without failing.
It's important to note that the 5,000-pound minimum static load requirement is a general guideline, and the actual load capacity of the anchorage point will depend on a variety of factors, including the type of anchorage point, the material it's made from, and the conditions of use.

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The dynamic viscosity of the oil in poise is 13.625 pois

The kinematic viscosity of the oil in strokes is 14.34

F viscous is given as n*  ΔFr / Δy

where n = F * Δy / A * ΔVn

We have to define the terms of the formula

Δy = 12.5 x 10⁻³

ΔVr = 2.5m /s

A = 60 x 60 cm² = 0.36m

F = 98.1 n

We have to put the values in the formula

98.1 n *  12.5 x 10⁻³ /  0.36m * 2.5m /s

n = 1.3625  ns / m²

The kinematic viscosity of the oil in strokes if the specific gravity of the oil is 0.95

y = n / e

n =  1.3625  

e = 0.95 x 10³

y = 1.3625  / 0.95 x 10³

= 1.434 x 10⁻³

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When subjected to an internal moment of M = 75 kN·m, the maximum tensile and compressive stress acting in the beam are 125 MPa and -125 MPa respectively.

These stresses are located at the top and bottom surfaces of the beam respectively.Let's find out how to solve the problem statement.A built-up beam is a composite beam that is constructed by bolting or welding together two or more individual beams side by side.

The bending stress formula for a beam subjected to a moment M is given by the following equation:σ = Mc / Iwhereσ is the bending stressM is the internal momentc is the distance from the neutral axis to the point of interestI is the moment of inertia of the beamWe need to determine the maximum tensile and compressive stress acting in the beam. To do so, we'll need to calculate the maximum bending stress that the beam experiences.

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Answer:

The thickness of the walls of each hollow lump of "iron ore" is 2.2 cm

Explanation:

Here we have that the density of solid gold = 19.3 g/cm³

Density of real iron ore = 5.15 g/cm³

Diameter of sphere of gold = 4 cm

Therefore, volume of sphere = 4/3·π·r³ = 4/3×π×2³ = 33.5 cm³

Mass of equivalent iron = Density of iron × Volume of iron = 5.15 × 33.5

Mass of equivalent iron = 172.6 cm³

∴ Mass of gold per lump = Mass of equivalent iron = 172.6 cm³

Volume of gold per lump = Mass of gold per lump/(Density of the gold)

Volume of gold per lump = 172.6/19.3 = 8.94 cm³

Since the gold is formed into hollow spheres, we have;

Let the radius of the hollow sphere = a

Therefore;

Total volume of the hollow gold sphere = Volume of gold per lump - void sphere of radius, a

Therefore;

\(33.5 = 8.94 - \frac{4}{3} \times \pi \times a^3\)

\(\frac{4}{3} \times \pi \times a^3 = 33.5 - 8.94\)

\(a^3 = \frac{24.6}{\frac{3}{4} \pi } = 5.9\)

a = ∛5.9 = 1.8

The thickness of the walls of each hollow lump of "iron ore" = r - a = 4 - 1.8 = 2.2 cm.

Explanation:

Elevator controller

An Elevator controller is a system to control the elevators, either manual or automatic. The controller usually tune down the voltage between 12V to 24V to the controlling system, Only the motor needs 3-phase power supply.

https://elevation.fandom.com › wiki

Elevator control system | Elevator Wiki | Fandom

Answer:

If Reynolds number increases the extent of the region around the object that is affected by viscosity decreases.

Explanation:

Reynolds number is an important dimensionless parameter in fluid mechanics.

It is calculated as;

\(R_e__N} = \frac{\rho vd}{\mu}\)

where;

ρ is density

v is velocity

d is diameter

μ is viscosity

All these parameters are important in calculating Reynolds number and understanding of fluid flow over an object.

In aerodynamics, the higher the Reynolds number, the lesser the viscosity plays a role in the flow around the airfoil. As Reynolds number increases, the boundary layer gets thinner, which results in a lower drag. Or simply put, if Reynolds number increases the extent of the region around the object that is affected by viscosity decreases.

When making a force (FD) and momentum diagram (MD) to et up the equations for momentum equation problem, Pressure force caused by a fluid flowing across a control surface boundary should be in the momentum diagram (MD) while the rest of the elements should be in the force diagram (FD).

Explanation:Force diagram (FD) shows all the forces that are acting on the system. Momentum diagram (MD) shows the momenta entering and leaving the system. The momentum equation expresses the balance of linear momentum in the control volume, while the force equation expresses the balance of forces in the control volume. The control volume can be a fixed or a moving one and can encompass a single point or a finite volume of space.The correct answer is E) Pressure force caused by a fluid flowing across a control surface boundary.

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Based on  the data given, the regression equation y on-x is y = 3/4x + 1.

y = (3/4)x + 100

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Z≤ -4.852 ft, Maximum efficiency is η≅ 0.88 ≅ 88% is the maximum discharge possible

Solution

Given Data:-

D = 14.62in, N = 2134 rc/min, T=20°C. At T= 20°C ɣ=ρg= 62.35 lb/ft³, vapor pressure. Pv = 49.2 lb/ft².

The efficienies at each flow rate is computal by using formula

η = ρgθH / (550) (bhp)

→ As we can See the maximum efficiency point is at θ = 6ft³/s (close to 6ft³/s)

Maximum efficiency is η≅ 0.88 ≅ 88%

b) Given NPSHR = 16 ft,hg=22ft. Zactual. = 9ft  (below the sea surface)

To avoid cavitation NPSH < Pa - Pv/ρg - Z - hf

Z < Pa - Pv/ρg - hf

Z < 2116 - 49.2/62.35 - 16 - 22 [1 atm = 2116 lb/ft2]

Z≤ -4.852 ft

-> Keeping the pump 9 ft below the surface gives 4.148 ft of marign against cavitation.

Hence it is Sufficient to avoid cavitation.

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Answer:

Wind energy is converted to Mechanical energy  which is then converted in to  electrical energy

Explanation:

In a wind mill the following energy conversions take place

a) Wind energy is converted into Mechanical energy (rotation of rotor blades)

b) Mechanical energy is converted into electrical energy (by using electric motor)

This electrical energy is then used for transmission through electric lines.

Answer:

When a system is produced using the evolutionary development model, features tend to be added without regard to an overriding design. With each modification, the software becomes increasingly disorganized. System maintenance hampered by these problems, as it is harder identifying the source of bugs in poorly designed systems. Also, keeping the documentation up to date over successive "evolution" is uncommon. Poor documentation also makes maintenance more difficult.

Explanation:

・It leads to implementing and then repairing way of building systems.

・Practically, this methodology may increase the complexity of the system as scope of the system may expand beyond original plans.

・Incomplete application may cause application not to be used as the full system was designed.

・Their results have incomplete or inadequate problem analysis.

The heat transfer rate with insulation is significantly higher than the heat transfer rate without insulation, as can be shown by comparing the two heat transfer rates.

The table shows that solids (s) generally conduct heat at rates that are significantly higher than those of liquids (l) and gases (g).

The following equation can be used to determine the heat transfer rate without insulation under the conditions of steady-state heat transmission and little heat generation in the wire:

A = pidL A = pi0.0831 = 0.26 square inches. Q = hA(T wire - T inf).

Q = 2.50.26(90 - 50) = 26 Btu/h without insulation R = 0.02 / (0.075×0.26) = 0.98 hrft2°F/Btu

Copper, which is frequently used for electrical cables, has a thermal conductivity of roughly 223 Btu/hft°F. Inputting the values provided yields:

R total = 1 / (2230.26pi×0.0832 / 4) = 0.14 hours/feet/degrees Fahrenheit/Btu

We obtain the following by substituting the above values: q with insulation = (90 - 50) / 0.14 = 286 Btu/h

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The program that takes in a line of text as input, and outputs that line of text in reverse is as follows:

list1 = []

x = input("input your text for it to be reverse: ")

while x != "done" and "d" and "Done":

    list1.append(x)

    x = input("input your text for it to be reverse: ")

for i in list1:

    print(i[::-1])

The code is written in python

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Answer:

For most applications, it is simple, dependable, efficient, and straightforward to apply - a simple trigger signal may be provided, with appropriate processing if necessary. This implies that an appropriate trigger signal may be generated using other electrical circuits and then applied to the SCR.

Explanation: